Mark Watney (Matt Damon in the Martian movie) and Marvin the Martian (Looney Tunes cartoon character) are having an argument on the surface of Mars (negligible air resistance). They are testing out their new potato launcher that fires projectiles at a constant speed. Mark launches his potato at an angle of 60◦ and Marvin launches his identical potato at an angle of 30◦ . Without any calculations try to answer the following questions, and justify each answer.

(A) Which potato lands farther away from the launcher (potatoes are launched from ground level)?

(B) Which potato spends more time in the air before hitting the ground

(C) Which potato has a greater speed just before it hits the ground?

Answers

Answer 1

Answer:

A) The two potatoes cover the same horizontal distance from the launcher.

B) Mark's potato spends more time in the air than Marvin's potato before hitting the ground.

C) Marvin's potato hits the ground with a greater speed than Mark's potato

Explanation:

A) For projectile motion, the final horizontal distance of the projectile from where it was initially launched (its range) is given as

R = (u² sin 2θ)/g

where

u = initial velocity of the projectile

θ = angle above the horizontal at which the projectile was launched = 30°, 60°

g = acceleration due to gravity on Mars

Since, u and g are the same for Mark and Marvin, sin 2θ would determine which range is higher.

Sin (2×60°) = sin 120°

Sin (2×30°) = sin 60°

Sin 120° = Sin 60°

Hence, the two potatoes cover the same horizontal distance from the launcher.

B) Time spent in the air for a projectile is given as

T = (2u sin θ)/g

Again, since u and g are the same for Mark and Marvin on Mars, sin θ will give the required idea of whose potato spends more time in the air.

Sin 60° = 0.866

Sin 30° = 0.50

Sin 60° > Sin 30°

Hence, Mark's potato spends more time in the air than Marvin's potato.

C) The horizontal velocity for projectile motion is constant all through the motion and is equal to u cos θ

u cos 60° < u cos 30°

And the initial vertical velocity is u sin θ

Final vertical velocity

= (initial vertical velocity) - gt

g = acceleration due to gravity on Mars

T = time of flight

For Mark,

initial vertical velocity = u sin 60°, greater than Marvin's u sin 30°

And Mark's potato's time of flight is greater as established in (B) above.

But for Marvin

initial vertical velocity = u sin 30°, less than Mark's u sin 60°

And Marvin's potato's time of flight is lesser as established in (B) above

So, at the end of the day, the final vertical velocity is almost the same for both Mark's and Marvin's potatoes.

Hence, the horizontal component of the final velocity edges the final speed of the potatoes just before hitting the ground in Marvin's favour.

Hope this Helps!!!


Related Questions

Within the living area of the colony, what atmospheric gases must be present on Venus?

Answers

Humans would need a breathable environment like that on Earth in the living section of a colony on Venus in order to survive. Nitrogen, oxygen, and trace amounts of other gases, such as carbon dioxide, make up the majority of the atmosphere on Earth.

What gases are present in Venus' atmosphere?

The clouds are made of sulfuric acid, and the atmosphere is primarily carbon dioxide, the same gas that causes the greenhouse effect on Venus and Earth. And the heated, high-pressure carbon dioxide acts corrosively at the surface.

What gases are found in Mars' and Venus' atmospheres?

For instance, compared to Earth, which has 99% nitrogen and oxygen in its atmosphere, Venus and Mars both contain more than 98% carbon dioxide and nitrogen.

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QUESTION ❗️❗️❗️❗️❗️❗️
How could you measure the flow rate of various liquid
a.Place each one on a scale and measure its weight versus its volumes
b.Place them in a beaker and se which one floats to the top
c.Pour them down an incline and time how long it takes each one to reach the bottom
d.Burn each sample to create a deposit than can be analyzed

Answers

We can measure the flow rate of various liquid by pouring the liquid down an incline and time how long it takes each one to reach the bottom.

option C.

What is the flow rate of a liquid?

The flow rate of a liquid is how much fluid passes through an area in a particular time.

Flow rate can be articulated in either in terms of velocity and cross-sectional area, or time and volume. As liquids are incompressible, the rate of flow into an area must be equivalent to the rate of flow out of an area.

Generally, the best equipment to measure the flow rate of a liquid is flow meters. In the absence of flow meters, we can other methods such as the one given in the options.

We can pour the various liquid down an incline and time how long it takes each one to reach the bottom.

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someone is pushing a shopping cart and maintaining the same applied force. another person keeps adding items into the cart increasing the mass of cart. what would happen to the acceleration?

Answers

Answer:

The rate of acceleration slow

Explanation:

Force (N) = mass (kg) × acceleration (m/s²) , because acceleration multiply by mass it a inverse relationship

Suppose that you wanted to travel to the next closest star to Earth. Proxima Centauri is the closest star to our solar system at a distance of 4.3 light years (40,208,000,000,000 km). Knowing that the space shuttle’s typical speed is 28,000 km/hr, how long would it take you to get there?

Answers

Answer:

1 436 000 000 hrs     163 814 .7 years

Explanation:

40208000000000 km  / 28000 km/hr  =

The Space shuttle's speed is 28,000 km/hr, and the time it will take to get you there is 1436000000 hours or 163814.7 years.

What is Proxima Centauri?

Although Proxima Centauri cannot be seen normally with eyes, it is one of the most famous stars in the sky. This is because it is a member of the Alpha Centauri star system, which is the nearest stellar system to our sun and is home to three known stars.

Proxima, with a distance of 4.22 light-years from our sun, is thought to be the star in Alpha Centauri that is nearest to our sun of the three. For Proxima, astronomers have so far found two planets. It also produces large solar flares, and a strange radio signal may come from it.

According to the question :

The given distance is 4.3 light-years or,

Distance = 40,208,000,000,000 km

Given speed is 28,000 km/hr.

So the time it will take to get you up there is:  Distance/speed

Time = 40,208,000,000,000 km/28,000 km/hr

Time = 1436000000 hours or,

Time = 163814.7 years

Hence, the time taken to get you there will be 163814.7 years.

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De que esta hecho el sol? plisss ayuda.no necesito un texto de 100 reglones, puede ser resumido en solo 2 renglones

Answers

El sol es una bola de gas así como las estrellas:)

A light elastic string, of natural length g metres and modulus mg N, has one end attached to a fed point O, and the other end attached to a particle of mass m kg. If the particle hangs in equilibrium vertically below O, what will the extension in the string be? Give your answer in metres to 1 decimal place.

The particle from the previous question is dropped from a point § metres directly below O and enters into simple harmonic motion centred on the equilibrium point once the string is under tension. If the equation of motion when under tension is › = -n?, where x is the displacement from the
equilibrium position, then find the constant n.

In the previous question, how long after it is dropped does the particle enter simple harmonic motion? Give your answer in seconds.

What is the amplitude of the simple harmonic motion in the previous two questions? Give your answer in metres to 2 decimal places.

How long does it take the particle in the previous three questions to come to instanteous rest for the first time? Give your answer in seconds to 2 decimal places.

A light elastic string, of natural length g metres and modulus mg N, has one end attached to a fed point

Answers

The extension in the string when the particle hangs in equilibrium is e = mg/k. The constant n in the equation of motion is n = (2π/T)²m. The time it takes for the particle to enter simple harmonic motion is t = √(2§/g).

To find the extension in the string when the particle hangs in equilibrium, we need to consider the forces acting on the particle. The weight of the particle is mg, acting vertically downward. The tension in the string exerts an equal and opposite force, mg, to balance the weight. Since the particle is in equilibrium, the total force acting on it is zero.When the particle is dropped from a point below O, it will stretch the string due to its weight. Let's denote the extension of the string as e. The tension in the string will now be greater than mg because it needs to support the weight of the particle and provide the necessary centripetal force for the simple harmonic motion.The extension in the string is given by Hooke's law: F = kx, where F is the force, k is the modulus of the string, and x is the extension. In this case, the force is the tension in the string, and the extension is e. Thus, we have mg = ke. Rearranging the equation, we get e = mg/k.

To find the constant n in the equation of motion, › = -n?, we can use the fact that the period of simple harmonic motion is given by T = 2π√(m/k), where m is the mass of the particle and k is the spring constant. Comparing this with the equation of motion, we see that ω² = n/m. Since ω = 2π/T, we can substitute ω in terms of T and solve for n: n = (2π/T)²m.

To determine when the particle enters simple harmonic motion, we need to find the time it takes for the string to reach its equilibrium position. Since the particle is dropped from a point § meters below O, it will accelerate towards the equilibrium position due to the tension in the string. The time taken for this free-fall motion can be calculated using the equation of motion for constant acceleration: § = ½gt². Solving for t, we get t = √(2§/g).The amplitude of the simple harmonic motion is equal to the maximum displacement from the equilibrium position. In this case, the maximum displacement is equal to the initial dropped distance, § meters.To determine the time it takes for the particle to come to instantaneous rest for the first time, we need to find the time period of the simple harmonic motion. The time period, T, is given by T = 2π√(m/k). To find the time it takes to come to rest, we need to consider half of the time period, T/2.The amplitude of the simple harmonic motion is equal to the initial dropped distance, § meters. The time it takes for the particle to come to instantaneous rest for the first time is T/2, where T is the time period of the simple harmonic motion.

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A force F is applied to a cylindrical steel cable of diameter 3.5 mm and length 10.0 m. Determine the value of F if the change in length of the cable is 7.8 mm.
Ysteel = 20 x 10^10 N/m2

Answers

Explanation:

Mathematicians seek and use patterns[8][9] to formulate new conjectures; they resolve the truth or falsity of such by mathematical proof. When mathematical structures are good models of real phenomena, mathematical reasoning can be used to provide insight or predictions about nature. Through the use of abstraction and logic, mathematics developed from counting, calculation, measurement, and the systematic study of the shapes and motions of physical objects. Practical mathematics has been a human activity from as far back as written records exist. The research required to solve mathematical problems can take years or even centuries of sustained inquiry.

Rigorous arguments first appeared in Greek mathematics, most notably in Euclid's Elements.[10] Since the pioneering work of Giuseppe Peano (1858–1932), David Hilbert (1862–1943), and others on axiomatic systems in the late 19th century, it has become customary to view mathematical research as establishing truth by rigorous deduction from appropriately chosen axioms and definitions. Mathematics developed at a relatively slow pace until the Renaissance, when mathematical innovations interacting with new scientific discoveries led to a rapid increase in the rate of mathematical discovery that has continued to the present day.[11]

Mathematics is essential in many fields, including natural science, engineering, medicine, finance, and the social sciences.

The value of force (F) if the change in length of the cable is 7.8 mm is 1500.89 N

The value of the force can be determined by using the young modulus equation that shows the relation between the tensile of the steel cable when the force is applied.

\(\mathbf{\gamma = \dfrac{F/A}{\Delta L/L}}\)

\(\mathbf{\gamma = \dfrac{F} {A }\times \dfrac{L}{\Delta L} }\)

Making the force the subject of the formula and replacing the values, we have:

\(\mathbf{F =\dfrac{A \times \gamma \times \Delta L }{L} }\)

\(\mathbf{F =\dfrac{ \pi \times (3.5 \times 10^{-3}) \times ( 20 \times 10^{10} \ N/m^2 ) \times (7.8 \times 10^{-3}) }{4 \times 10} }\)

\(\mathbf{F =1500.89 \ N }\)

Therefore, we can conclude that the value of force (F) if the change in length of the cable is 7.8 mm is 1500.89 N

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Cheri has a new Dodge Charger with a Hemi engine and has challenged Vince, who owns a tuned VW GTI, to a race at a local track. Vince knows that Cheri’s Charger is rated to go from 0 to 60 mph in 5.3 s, whereas his VW needs 7 s. Vince asks for a head start and Cheri agrees to give him exactly 1 s. (a) How far down the track is Vince before Cheri gets to start the race? (b) At what time does Cheri catch Vince? (c) How far away from the start are they when this happens? (Assume constant acceleration for each car during the race.)

Answers

Answer:

a) 1.915 s

b) 7 s

c) 122.5 m

Explanation:

1 mph = 0.44704 m/s

60 mph = (0.44704 * 60) m/s = 26.8 m/s

a) The VW acceleration = \(a_1\) = (26.8 m/s - 0 m/s) / 7 s =  3.83 m/s²

Cheri's acceleration = \(a_2\) = (26.8 m/s - 0 m/s) / 5.3 s = 5 m/s²

The distance traveled is given as:

\(S=ut+\frac{1}{2}at^2\\ \\For\ Vince\ VW\ which\ has\ traveled\ for\ 1\ s:\\\\S=0(1)+\frac{1}{2}(3.83)(1)^2=1.915\ m\)

b) The distance traveled by Vince VW with a 1s head start is given as:

\(S_1=ut+\frac{1}{2}a_1(t+1)^2\\ \\S_1=\frac{1}{2}(3.83)(t+1)^2\\\\S_1=1.915(t+1)^2\\\\S_1=1.915(t^2+2t+1)\\\\S_1=1.915t^2+3.83t+1.915\)

The distance traveled by Cheri is given as:

\(S_2=ut+\frac{1}{2}a_2(t)^2\\ \\S_2=\frac{1}{2}(5)(t)^2\\\\S_2=2.5t^2\\\\S_1=S_2\\\\2.5t^2=1.915t^2+3.83t+1.915\\\\0.585t^2-3.83t-1.915=0\\\\t=7s\ or\ t=-0.5\ s\\\\t=7s\)

c) \(S_1=2.5t^2\\\\S_1=2.5(7)^2=122.5\ m\)

Callisto is a moon of Jupiter
(mass= 1.90 x 1027 kg), which orbits
the planet with a period of 16.9 days.
What is the radius of its orbit?
[?] x 10¹ m
Coefficient (green)
Exponent (yellow)
Enter

Answers

8.27 x 1013 meres is the orbital radius.

Additional details:-

Jupiter's mass, 1.9 x 1027 kg, and the time interval, 16.9 days, are equal to 1.46 x 106 seconds. The radius is needed, thus r. Solution

The moon must be held in its orbit by a gravitational force equal to the centripetal force between Jupiter and the moon.

6.67 x 10⁻¹¹ N/m²kg

2 x 1.9 x 10/27 x 1.46 x 10'6 / 4 r = 6.85 x 102'7 G = 6.67 x 10'11 N/m2kg2 r = 8.27 x 10'7

What distinguishes Callisto, a huge moon orbiting Jupiter, from all other large moons in the solar system?

The second-largest moon in Jupiter's orbit and the third-largest moon in the solar system is called Callisto. Of all the objects in our solar system, its surface has the most craters.

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Calculate current and voltage and power if the circuit below

Calculate current and voltage and power if the circuit below

Answers

Answer:

Explanation:

Equivalent resistance

Re = 100 + (1/( 1/270 + 1/(150 + 240)))

Re = 100 + (1/( 1/270 + 1/390))

Re = 100 + 159.5

Re = 259.5 Ω

Power drawn from battery = V²/R

P = 12²/259.5

P = 0.554816...

P = 0.55 W

circuit current

I = V/Re

I = 12 / 259.5

I = 0.04623...A

I = 46 mA

100 Ω resistor

V = IR = 0.04623(100) = 4.6 V

I = 46 mA

P = VA = 4.6(0.046) = 0.21376...

P = 0.21 W

270 Ω resistor

V = 12 - 4.6 = 7.4 V

I = V/R = 7.4/270 = 0.02732... = 27 mA

P = VA = 7.4(0.027) = 0.2015... = 0.20 W

150 Ω resistor

V = 7.4(150 / (150 + 240)) = 2.8 V

I = 7.4/390 = 0.01891... = 19 mA

P = I²R = 0.01891²(150) = 0.053661... = 0.05 W

240 Ω resistor

V = 7.4(240 / (150 + 240)) = 4.5394 = 4.5 V

I = 7.4/390 = 0.01891... = 19 mA

P = I²R = 0.01891²(240) = 0.08585... = 0.09 W

verify power consumption

0.55 = 0.21 + 0.20 + 0.05 + 0.09

0.55 = 0.55         **check**

current check through parallel circuits

46 = 27 + 19

46 = 46                **check**

If a longitudinal wave passes a specific point seven times per second, and the distance between wave rarefaction points is 2 meters, what is the speed of the wave? 14 m/s 3. 5 m/s 0. 29 m/s 9 m/s.

Answers

The speed of the wave from the calculation that we have done is 14 m/s

What is the wave speed and how do we find it?

To find the wave speed, we need to know the frequency and wavelength of the wave. These values can be measured experimentally or calculated based on the properties of the medium through which the wave is traveling.

For example, the wavelength of a sound wave can be determined by measuring the distance between two consecutive points of maximum compression or rarefaction, while the frequency can be measured using a frequency meter or calculated based on the properties of the sound source.

We know that;

Frequency = 7 cycles/s

Wavelength = 2 m

Wave speed = λf

= 7 cycles/s * 2 m

= 14 m/s

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plzzz help will give brainlist

Below are views related to education.

---------------------------

Civics should be taught in public schools.
Good citizenship is learned in communities.
---------------------------

Which conclusion can be drawn from these views?

A. Civic involvement is important to building strong societies.

B. Civic participation should be learned at home.

C. Political conflict is a threat to strong societies.

D. Political conflict should be reduced through legislation.

Answers

Answer:

A.

Explanation:

this would make sense but it seems to be more like they both sound different

4.2 Determine the reactions of the loads L and R. ↓ 5m
↓ 7 kN 6m 3 kN 4m R (8)​

Answers

The reaction of load L is 0 (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).

How to find reaction?

To determine the reactions of the loads L and R, consider the equilibrium of the forces acting on the structure.

First, analyze the vertical equilibrium. The sum of the vertical forces must be zero:

ΣFy = R − 7 kN − 3 kN

ΣFy = 0

This gives:

R = 10kN

Next, analyze the horizontal equilibrium. The sum of the horizontal forces must be zero:

ΣFx = L

ΣFx = 0

This indicates that there is no horizontal force acting on the structure.

Therefore, the reaction of load L is zero (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).

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Find the total translational kinetic energy of
1 L of oxygen gas held at a temperature of
6°C and a pressure of 2.5 atm.
Answer in units of J.

Answers

The total translational kinetic energy of 1 L of oxygen gas at 6°C and 2.5 atm is 833.7 J.

To find the total translational kinetic energy of 1 L of oxygen gas at 6°C and 2.5 atm, we can use the following formula:

KE = (3/2) * n * R * T

where KE is the total translational kinetic energy, n is the number of moles of gas, R is the gas constant (8.314 J/(mol*K)), and T is the temperature in Kelvin.

First, we need to find the number of moles of gas in 1 L at 2.5 atm and 6°C. We can use the ideal gas law to do this:

PV = nRT

where P is the pressure, V is the volume, and T is the temperature in Kelvin.

Converting 6°C to Kelvin, we get:

T = 6°C + 273.15 = 279.15 K

Substituting the given values into the ideal gas law, we get:

(2.5 atm) * (1 L) = n * (0.08206 Latm/(molK)) * (279.15 K)

Solving for n, we get:

n = (2.5 atm * 1 L) / (0.08206 Latm/(molK) * 279.15 K) = 0.108 mol

Now we can use the formula for KE:

KE = (3/2) * n * R * T = (3/2) * (0.108 mol) * (8.314 J/(mol*K)) * (279.15 K)

Solving for KE, we get:

KE = 833.7 J.

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A gas is contained in a chamber such as that in Figure 15.4. Suppose that the region outside the chamber is evacuated and the total mass of the block and the movable piston is 135 kg. When 2050 J of heat fl ows into the gas, the internal energy of the gas increases by 1730 J. What is the distance s through which the piston rises?

Answers

0.24 m  distance  through which the piston rises.

we have given the mass of piston+block = 135kg

2050 joule of heat flows into the gas

now;

According to first law thermodynamics,

dQ=du+dw

we have

2050=1730+MgS

Here M is mass, g is gravity, S is distance

now puttin gthe formula

MgS=320

S=320/1323

S= 0.24m

The link between the heat and work produced and the system's internal energy is explained by the first law of thermodynamics. The whole amount of energy present in a system, including the kinetic energy of molecules and the energy held inside their chemical bonds, is referred to as internal energy. The first law of thermodynamics states that the heat transferred into the system less the work done by the system equals the change in internal energy of the system. The law explains how energy is conserved when thermodynamic processes take place between two or more equilibrium states.

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Find the vector whose magnitude is 5 and which is in the direction of the vector 4i -3j +k

Answers

The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

To solve this problem

The given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:

The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:

Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26

Normalize the vector by dividing each component by the magnitude:

Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k

Multiply the normalized vector by the desired magnitude:

To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:

Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)

Simplifying the expression gives:

Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k

So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

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An object is placed 10.0 cm in front of a thin concave lens with a focal length of 18 cm. Calculate the imageposition

Answers

The focal length of a concave lens is expressed as,

\(\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\)

Here, f is the focal length, u is the distance of object and v is the distance of image.

Plug in the known values,

\(\begin{gathered} \frac{1}{18\text{ cm}}=\frac{1}{10.0\text{ cm}}+\frac{1}{v} \\ \frac{1}{v}=\frac{1}{18\text{ cm}}-\frac{1}{10.0\text{ cm}} \\ v=\frac{(18\text{ cm)(10.0 cm)}}{10.0\text{ cm-18 cm}} \\ =-22.5\text{ cm} \end{gathered}\)

Thus, the distance of image is -22.5 cm where negative sign indicates that the image will be at the same side of object.

What is the difference between special relativity and general relativity? Briefly describe each theory and cite one piece of evidence supporting each theory.

Answers

Special relativity and general relativity are both theories proposed by Albert Einstein. Special relativity deals with the laws of physics in the absence of gravity, while general relativity extends special relativity to include gravity and explains the curvature of spacetime caused by mass and energy.

Special relativity, proposed in 1905, deals with the laws of physics in the absence of gravitational fields. It introduces the concepts of time dilation and length contraction, stating that the laws of physics are the same for all observers moving at constant speeds relative to each other.

One piece of evidence supporting special relativity is the famous Michelson-Morley experiment, which failed to detect the existence of the hypothetical luminiferous aether.

On the other hand, general relativity, formulated in 1915, is an extension of special relativity that incorporates gravity. It postulates that gravity arises from the curvature of spacetime caused by mass and energy. General relativity explains the motion of celestial bodies, the bending of light in the presence of massive objects, and phenomena like black holes.

One piece of evidence supporting general relativity is the observed gravitational redshift, where light emitted from a source in a strong gravitational field is shifted to longer wavelengths.

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Use the information from the article to answer the question.

Asteroids and Comets

Which statement best explains the location of the asteroid belt?

Most asteroids can be found between Mars and Jupiter.
The formation of the solar system produced planets as well as asteroids orbiting the Sun.
The gravitational pull of the Sun brought all asteroids in the solar system together in one area.
The size of asteroids caused them to orbit the Sun at a similar distance.

Answers

Answer:

Most asteroids can be found between Mars and Jupiter.

Explanation:

Most asteroids can be found between Mars and Jupiter.

What are the asteroids and comets?Asteroid: A rocky object that orbits the sun and has an average size between a meteoroid and a planet. Comet: An object made mostly of ice and dust, often with a gas halo and tail, that sometimes orbits the sun.What is asteroid belt?

The asteroid belt is a torus-shaped region in the Solar System, located roughly between the orbits of the planets Jupiter and Mars.

In the solar system asteroids are orbiting around the sunThe gravitational pull of the Sun brought all asteroids in the solar system together in one area.

Thus the statement which best explains the location of the asteroid belt is "Most asteroids can be found between Mars and Jupiter."

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Microwave ovens rotate at a rate of about 5 revolutions per minute (rpm). This is equal to 0.08 revolutions per second (rps). What is the angular velocity in radians per second? 2π rad = 1 revolution.

Answers

The angular velocity in radians per second, given that Microwave ovens rotate at a rate of about 5 revolutions per minute (rpm) is 0.50 radians per second

How do I determine the angular velocity in radians per second?

The angular velocity (in radians per second) can be obtained by simply converting 0.08 revolution per second to radians per second. This is obtained as illustrated below:

Angular velocity (in revolution per second) = 0.08 revolution per secondAngular velocity (in radians per second) =?

1 revolution per second = 2π radians per second

Therefore,

0.08 revolution per second = 0.08 × 2π

Recall

Pi (π) = 3.14

Thus,

0.08 revolution per second = 0.08 × 2 × 3.14

0.08 revolution per second = 0.50 radians per second

Thus, we can conclude that the angular velocity (in radians per second) is 0.50 radians per second

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Draw two lowest-order Feynman diagrams for scattering of an electron neutrino by an electron​

Answers

A fundamental particle with no electric charge and a spin of one-half is called an electron neutrino (v).

Explain about the electron neutrino?

The subatomic particle known as a neutrino resembles an electron in many ways, but it differs in that it lacks an electrical charge and has a very small mass that may even be zero. One of the cosmological particles with the highest density is the neutrino. However, they are exceedingly difficult to find because they barely interact with matter.

Small, almost massless particles known as neutrinos move at speeds close to light. They are phenomenally common in the universe and can move through lead as readily as we do through air. They are the product of intense astronomical events like exploding stars and gamma ray bursts.

A flat recoil energy spectrum is the result of monoenergetic electron neutrinos scattering from electrons.

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PLEASE HELP!! 50 points. The answer is not 2.6 m/s.

PLEASE HELP!! 50 points. The answer is not 2.6 m/s.

Answers

Answer:

A

Explanation:

5.2mm/s

hope this helps

A copper telephone wire has essentially no sag between poles 36.0 m apart on a winter day when the temperature is −20.0°C. How much longer is the wire on a summer day when the temperature is 34.0°C?

Answers

Answer:

The extension is  \(\Delta L = 0.033 \ m\)

Explanation:

From the question we are told that  

     The length of the wire on a winter day is    \(L_w = 36.0 \ m\)

      The temperature on the winter day is  \(T_w = -20.0 ^o C\)

      The temperature on a summer day is  \(T_s = 34.0 ^0 C\)

The the extension of the wire on a summer day is mathematically represented as

          \(\Delta L = \alpha L_w [T_s - T_w]\)

Where  

      \(\alpha\) is the  coefficient of linear expansion of copper with a values \(\alpha = 17 *10^{-6}\)

substituting value  

      \(\Delta L = 17 *10^{-6} * 36.0 [34 - [-20]]\)

      \(\Delta L = 0.033 \ m\)

Which pair of factors affects the force of gravity between objects?

direction and distance

mass and distance

mass and shape

shape and time

Answers

Answer:

mass and distance

Explanation:

dont need to summary this

Answer:

B. mass and distance

Explanation:

A person is hauling their taco stand and it takes 3,500 Joules of work to stop the taco stand. What force was exerted on the taco stand if it took 1.5 meters to stop the motion?

A person is hauling their taco stand and it takes 3,500 Joules of work to stop the taco stand. What force

Answers

Given the work done, the force exerted on the taco stand through the given distance is 2.3 × 10³ Newtons.

What is Work done?

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

W = f × d

Where f is force applied and d is distance travelled.

Given that;

Work done W = 3500J = 3500kgm²/s²Distance covered d = 1.5mForce applied F = ?

W = f × d

3500kgm²/s² = f × 1.5m

f = 3500kgm²/s² ÷ 1.5m

f = 2.3 × 10³ kgm/s²

f = 2.3 × 10³ N

Given the work done, the force exerted on the taco stand through the given distance is 2.3 × 10³ Newtons.

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If 600 J of energy of chemical energy is contained inside the gasoline in a gas tank, how much work can the engine perform on the car? What kinetic energy can be achieved?

Answers

Kinetic energy will be 600J. According to law of conservation energy: All the energy in a system will simply change the state, and no more nor less energy will be created or lost during the operation of the system. In this case, then all 600J of energy will be transformed during the operation of car.

This chemical energy, what is it?

kinetic energy, Chemical compounds' bonds contain energy. Chemical reactions have the potential to release chemical energy, frequently in the form of heat; these kinds of reactions are referred to as exothermic. Some of the energy from reactions that need heat input to continue may be stored as chemical energy in newly formed bonds.

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What is the force required to accelerate a 500 kg object at a rate of 10 m/s^2?

Answers

Answer:

Therefore, the force required to accelerate a 500 kg object at a rate of 10 m/s^2 is 5000 Newtons (N).

Explanation:

The force required to accelerate an object can be calculated using the formula:

force = mass x acceleration

where "mass" is the mass of the object being accelerated, and "acceleration" is the rate at which the object's velocity is changing.

In this case, the mass of the object is 500 kg, and the acceleration is 10 m/s^2. Plugging these values into the formula gives:

force = mass x acceleration

force = 500 kg x 10 m/s^2

force = 5000 N

Therefore, the force required to accelerate a 500 kg object at a rate of 10 m/s^2 is 5000 Newtons (N).

A ceramic capacitor has an effective plate area of 4 cm2 separated by 0.1 mm of ceramic of relative
permittivity 100.
a) Calculate the capacitance of the capacitor in picofarads.
b) If the capacitor in part (a) is given a charge of 1.2 μC what will be the pd between the plates?

Answers

a) The capacitance of the ceramic capacitor is approximately 354.16 pF.

b) The potential difference between the plates of the capacitor will be approximately 3.39 x 10^6 volts.

To calculate the capacitance of the ceramic capacitor, we can use the formula:

C = (ε₀ * εᵣ * A) / d

where:

C is the capacitance,

ε₀ is the vacuum permittivity (approximately 8.854 x 10^(-12) F/m),

εᵣ is the relative permittivity of the ceramic (given as 100),

A is the effective plate area (given as 4 cm², which is equal to 4 x 10^(-4) m²),

d is the separation between the plates (given as 0.1 mm, which is equal to 0.1 x 10^(-3) m).

Let's calculate the capacitance in picofarads (pF):

a) Calculation of capacitance (C):

C = (ε₀ * εᵣ * A) / d

= (8.854 x 10^(-12) F/m * 100 * 4 x 10^(-4) m²) / (0.1 x 10^(-3) m)

= (8.854 x 100 x 4) / 0.1

= 354.16 pF

Therefore, the capacitance of the ceramic capacitor is approximately 354.16 pF.

b) To find the potential difference (PD) between the plates when the capacitor is given a charge of 1.2 μC (microcoulombs), we can use the formula:

PD = Q / C

where:

PD is the potential difference,

Q is the charge (given as 1.2 μC, which is equal to 1.2 x 10^(-6) C),

C is the capacitance (calculated in part a) as 354.16 pF, which is equal to 354.16 x 10^(-12) F).

Let's calculate the potential difference (PD):

b) Calculation of potential difference (PD):

PD = Q / C

= (1.2 x 10^(-6) C) / (354.16 x 10^(-12) F)

= 3.39 x 10^6 V

Therefore, the potential difference between the plates of the capacitor will be approximately 3.39 x 10^6 volts.

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consider the interference resulting from sending coherent visible light perpendicularly through this pair of openings. calculate the angle between adjacent zones of constructive interference, assuming the width of your middle finger to be 2.5 cm and the wavelength of the light to be 690 nm.

Answers

The angle as the constructive interference is 1.485×\(10^{-3}\)

Calculate the angle as follows:

For constructive interference,

∅ = \(sin^{-1} \frac{n}{d}\)λ

   = \(sin^{-1} \frac{1*700*10^{-9}m}{0.027m}\) = \(1.485* 10^{-3}degrees.\)

In physics, the wavelength is the spatial length of a periodic wave—the distance over which the wave's form repeats. it is the space between consecutive corresponding factors of the same section on the wave, consisting of adjoining crests, troughs, or 0 crossings, and is a characteristic of both visiting waves and standing waves, in addition to other spatial wave patterns. The inverse of the wavelength is known as the spatial frequency. Wavelength is generally particular via the Greek letter lambda (λ). The time period wavelength is likewise once in a while applied to modulated waves, and to the sinusoidal envelopes of modulated waves or waves shaped by means of interference of several sinusoids.

Assuming a sinusoidal wave transferring at a hard and fast wave velocity, the wavelength is inversely proportional to the frequency of the wave: waves with better frequencies have shorter wavelengths, and lower frequencies have longer wavelengths.

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Complete Question:

Consider the interference resulting from sending coherent visible light perpendicularly through this pair of openings. Calculate the angle between adjacent zones of constructive interference, assuming the width of your middle finger to be 2.7 cm and the wavelength of the light to be 700 nm.

A 0.0400 kg meter stick is placed on a thin rod at the 30.0 cm mark. What is the minimum mass required to be placed on the 0.00 cm mark on the stick to maintain equilibrium?

Answer in kg

Answers

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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