Mark thinks the equation y= 4+6x will match the red solid graph. Mia thinks it will match the blue dotted graph.

who's right? explain your thinking​

I runner is running at the speed of 6.8 miles/hr and he wants to run 10.1 km then he runner must run for 9.3 minutes.

To calculate this, we first need to convert the given speed from miles per hour to kilometers per hour. 6.8 mi/hr is equal to 10.9 km/hr.

Then, we need to divide the total distance (10.1 km) by the speed (10.9 km/hr) to get the total time it will take for the runner to complete the 10.1 km run.

10.1 km/10.9 km/hr = 0.922 hr = 9.3 minutes.

Therefore, the runner must run for 9.3 minutes in order to complete the 10.1 km run.
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Answer:

7.9m

Step-by-step explanation:

Area of square = length^2

62.41 = L^2

L= √62.41

so, L= 7.9m

Step-by-step explanation:

100% = 33,000 ft

1% = 100%/100 = 33000/100 = 330 ft

6% = 1% × 6 = 330 × 6 = 1980 ft

that means the plane has to go down 1980 ft to

33,000 - 1980 = 31,020 ft

and then it goes up by 5000 ft :

31,020 + 5000 = 36,020 ft

that is the final altitude.

Answer:

The final altitude of the airplane is 36,020

Step-by-step explanation:

I took the test

Answer:

g° 37

Step by step

angle AB = 180°

angle AD = 90°

angle DE = 53°

angle g = 180 - (90 + 53)

angle g = 37°

Answer:

259.5

Step-by-step explanation:

8.1*12=97.2
Area of trapiezium = 1/2(b+a)h
(2.8+8.1)=10.9
10.9*3/2=16.35
16.35*2=32.7
2.8*12=33.6
33.6+32.7+97.2=163.5
4*12*2=96
163.5+96=259.5

The one that is a step used in the construction of an equilateral triangle inscribed in a circle  is:

B. draw two line segments connecting the points where the arc intersects the circle and an endpoint of the diameter

The steps to construct an equilateral triangle inscribed in a circle are:

1. Draw a point that will be the center of the circle. Label this "point O". Technically, it doesn't matter which character you use to represent a point.

2. Draw a perfect circle centered at point O using a compass.

3. Use a ruler to draw a straight vertical line through point O. Extend this line beyond the boundaries of the circle. 4) Draw a point where the line and the circle intersect. Label the bottom point "Point W" and the top point "Point X".

5) Draw a second circle. The center of this circle is point W and the radius extends to point O.

6) Mark both places where the two circles intersect. Label the left point "Point Y" and the right point "Point Z".

7) Connect the points X, Y and Z with a ruler or straightedge. 

Looking at the options, the only correct step is:

B. draw two line segments connecting the points where the arc intersects the circle and an endpoint of the diameter

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Its slope is m = 1 on the right side of the vertex, and m = - 1 on the left side of the vertex.

Absolute Value Function:

An absolute value function is a function that contains an algebraic expression within the absolute value sign. Remember that the absolute value of a number is its distance from 0 on the number line. To graph the absolute value function, select some values ​​of x and find some ordered pairs.

In mathematics, the absolute value or modulus of the real number x, represented as.

|x| is the non-negative value of x, regardless of sign.

x is positive and |xI =-x}.  For example, the absolute value of 3 is 3, and the absolute value of -3 is also 3. The absolute value of a number can be thought of as the distance from zero.

Generalizations of the absolute value of real numbers are made in a variety of mathematical contexts. For example, absolute value is also defined for complex numbers, quaternions, ordinal rings, fields, and vector spaces. Absolute value is closely related to the concepts of magnitude, distance, and norm in various mathematical and physical contexts.

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The hypothesis test results show that there is sufficient evidence to conclude that the population represented by Sample 1 has a higher mean than the population represented by Sample 2. The p-value is less than 0.05, so we can reject the null hypothesis.

The null hypothesis is that the population mean of matched-pair differences is equal to 0. The alternative hypothesis is that the population mean of matched-pair differences is greater than 0. The test statistic is t = 2.78, which has 9 degrees of freedom. The p-value for this test statistic is 0.008, which is less than 0.05. Therefore, we can reject the null hypothesis and conclude that there is a significant difference between the two populations.

The assumptions that need to be made in order to perform this procedure are that the matched pairs are independent and that the differences are normally distributed.

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a. There are no real solutions to the equation. Therefore, there is no value of α for which P(-1 < X < 2) = 0.75.

b. The value of parameter α for  P(|X| < 1) = P(|X| > 2) is 4

a. We know that for a uniform distribution over (−α,α), the probability density function is given by f(x) = 1/(2α) for −α ≤ x ≤ α and zero otherwise. Thus, the probability of the event (-1 < X < 2) can be computed as:

P(-1 < X < 2) = ∫(-1)²/(2α) dx + ∫2²/(2α) dx

= (1/2α) ∫(-1)² dx + (1/2α) ∫2² dx

= (1/2α) [x]₋₁¹ + (1/2α) [x]²₂

= (1/2α) (2α - 1) + (1/2α) (4 - α²)

= (3 + α²)/(4α)

We want this probability to be 0.75. So, we solve the equation (3 + α²)/(4α) = 0.75 for α:

(3 + α²)/(4α) = 0.75

=> 3 + α² = 3α

=> α² - 3α + 3 = 0

This is a quadratic equation in α with discriminant:

Δ = b² - 4ac

= (-3)² - 4(1)(3)

= 9 - 12

= -3

Since Δ is negative, there are no real solutions to the equation. Therefore, there is no value of α for which P(-1 < X < 2) = 0.75.

b. The pdf of a uniform distribution is given by:

f(x) = 1/(b-a), for a ≤ x ≤ b

In this case, a = -α and b = α. Therefore,

f(x) = 1/(2α), for -α ≤ x ≤ α

Now we can calculate the probabilities as follows:

P(|X| < 1) = P(-1 < X < 1) = ∫(-1 to 1) f(x) dx = ∫(-1 to 1) 1/(2α) dx = 1/(2α) * [x]_(-1 to 1) = 1/α

P(|X| > 2) = P(X < -2 or X > 2) = P(X > 2) + P(X < -2) = ∫(2 to α) f(x) dx + ∫(-α to -2) f(x) dx = ∫(2 to α) 1/(2α) dx + ∫(-α to -2) 1/(2α) dx = 1/4

Therefore, we need to find α such that P(|X| < 1) = P(|X| > 2) = 1/4.

From P(|X| < 1) = 1/α, we get α = 1/P(|X| < 1) = 1/(1/4) = 4.

From P(|X| > 2) = 1/4, we get the same value of α = 4.

Hence, α = 4 satisfies both conditions.

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Answer:

\(\Huge \fbox{72 mph}\)

Step-by-step explanation:

Step 1:

Convert \(\bold{32 m/s}\) to \(\bold{km/h}\) by multiplying by 3.6 (since \(\bold{1 m/s}\) = \(\bold{3.6 km/h}\))

\(\large \text{32 m/s $\times$ 3.6 = 115.2 km/h}\)

Step 2:

Convert \(\bold{115.2 km/h}\) to \(\bold{mph}\) using the given conversion factor of \(\bold{8 km/h = 5 mph}\)

\(\large \text{115.2 km/h $\div$ 8 km/h = 14.4}\\\text{14.4 $\times$ 5 mph = 72 mph}\)

Therefore, \(\bold{32 m/s}\) is equivalent to \(\bold{72 mph}\).

----------------------------------------------------------------------------------------------------------

In the standard conversion unit, 32 m/s equals 72 mph in mph

The conversion equation is given as

\(\sf 8 \ km/h = 5 \ mph\)

Convert 8 km to meters

So, we have the following equation

\(\sf 8 \times 1000 \ m/h = 5 \ mph\)

Evaluate the products

So, we have the following equation

\(\sf 8000 \ m/h = 5 \ mph\)

Convert 1 hour to seconds

So, we have the following equation

\(\sf 8000 \ m/3600 s = 5\ mph\)

Evaluate the quotient

So, we have the following equation

\(\sf \dfrac{20}{9} \ m/s = 5 \ mph\)

Multiply both sides by 9/20

\(\sf 1 \ m/s = \dfrac{9}{20} \times 5 \ mph\)

Multiply both sides by 32

\(\sf 32 \times 1 \ m/s = 32 \times \dfrac{9}{20} \times 5 \ mph\)

Evaluate the products

\(\sf 32 \ m/s = 72 \ mph\)

Hence, the equivalent of 32 m/s in mph is 72 mph

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Answer:

$12.90

Step-by-step explanation:

To solve, multiply the cost before tax with tax, and then add the number gotten to the original amount.

12 x 7.5% = 12 x 0.075 = 0.9

12 + 0.9 = 12.9

$12.90 is your answer.

~

Answer:

After tax, the price should be $12.90

Step-by-step explanation:

multiply 12 by 1.075

Answer:

12 carrots

Step-by-step explanation:

If there is 3 times as much cabbages as there is carrots, and there is 36 cabbages then you would do 36/3 because of the 3 times as much.  The answer would be 12 carrots.

36/3=12

True. a continuous random variable x assumes an (infinitely) uncountable number of distinct values.

A continuous random variable is one that can take on any value within a specified range, and it is defined over an interval of real numbers. Since the real numbers are uncountably infinite, a continuous random variable can assume an uncountable number of distinct values. In contrast, a discrete random variable can only take on a countable number of distinct values, since its possible values are restricted to a finite or countably infinite set of numbers.

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Answer:

2

Step-by-step explanation:

Answer:

the area is 144

Step-by-step explanation:

48 ÷ 4 (which is how many sides a square has) is 12

SO 12 × 12 bc l×w and all sides of a square are equal

the answer is 144

Answer:

Degrees = Radians x 180/π

or

Degrees = 57.2958  x radians

Step-by-step explanation:

1 radian = 180/π degrees

1 radian = 57.2958 degrees

Multiply radians by this factor of 57.2958  to get the equivalent measure in degrees

π radians = 180°

2π radians = 360° which is the number of degrees in a circle

For anything greater than 2π radians you will have to subtract 360°

For example, 7 radians using the formula is 7 x (57.2958  ) ≈ 401.07°

But this still falls in the first quadrant, so relative to the x-axis it is
401.07 - 360 = 41.07°

The higher the standard deviation of an arrival process with an average interarrival time of 6 minutes, the more variability or dispersion there is in the arrival times.

Standard deviation measures the dispersion or spread of data points around the mean. In the context of an arrival process, it represents the degree of variability in the time intervals between arrivals. A higher standard deviation indicates that the arrival times are more scattered or deviate more from the average interarrival time of 6 minutes.

When the standard deviation is high, it suggests that the arrival process is less predictable or more random. The actual interarrival times may vary significantly from the expected average of 6 minutes. This can lead to less efficient scheduling or planning as the arrival times become less predictable.

In contrast, when the standard deviation is low, the arrival times tend to be more consistent and closely clustered around the average interarrival time. This indicates a more predictable and reliable arrival process.

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Answer:

2. metaphor

3. hyperbole

4. personification

5. simile

Answer:

a) 70 degrees

b) 110 degrees

Step-by-step explanation:

Freezing point of water is 32 degrees.

Boiling point of water is 212 degrees.

Hope this helped :)

A basis for Col A is (-2,2,0,0) and (4,-6,0,0). A basis for Nul A is (2,1,0,0), (-1,0,1,1/2), and (-2,0,0,1). These bases were found using the row reduced form of A.

Since A is row equivalent to B, they have the same row space, null space, and column space. Thus, we can find the bases for Nul A and Col A using the row reduced form of A, which is

\(\left[\begin{array}{cccc}1&-2&1&2\\0&1&1/2&-1\\0&0&0&0\\0&0&0&0\end{array}\right]\)

To find a basis for Col A, we can take the columns of A that correspond to the pivot columns in the row reduced form. In this case, the pivot columns are the first and second columns. Therefore, a basis for Col A is

(-2, 2, 0, 0), (4, -6, 0, 0)

To find a basis for Nul A, we need to solve the system of homogeneous linear equations Ax = 0, which is equivalent to solving the system of equations corresponding to the row reduced form. Letting the free variable be t, we have

x¹ - 2x² + x³ + 2x⁴ = 0

x² + (1/2)x³ - x⁴ = 0

Expressing x¹ and x⁴ in terms of x² and x³, we get

x¹ = 2x² - x³ - 2x⁴

x⁴ = (1/2)x³ - x²

Thus, any solution to Ax = 0 can be written as

x = (2x² - x³ - 2x⁴, x², x³, (1/2)x³ - x²) = x²(2, 1, 0, 0) + x³(-1, 0, 1, 1/2) + x⁴(-2, 0, 0, 1)

Therefore, a basis for Nul A is

(2, 1, 0, 0), (-1, 0, 1, 1/2), (-2, 0, 0, 1)

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Answer:

$32.00

Step-by-step explanation:

Interest = Principal x Rate x Time

I = 200(.04)(4)

I = 32

Given that,

Height of the cone, h = 315 cm

Radius of the cone, r = 65 cm

To find,

The volume of the container.

Solution,

The container is in the shape of a cone. The volume of a cone is given by :

\(V=\dfrac{1}{3}\pi r^2 h\\\\=\dfrac{1}{3}\times (65)^2\times 315\\\\=443625\ cm^3\)

So, \(443625\ cm^3\) is filled in the container.

Answer:

-12

Step-by-step explanation:

Farenheit is on the x-axis (horizontal) so you go to 10, then find the celsius which is on the y-axis (vertical) and the line is around -12. Hope this helps!

At a discount rate of 4.5%, the present value of the perpetuity would be approximately $155,555.56.

To calculate the present value of a perpetual payment of $7000 per year at a discount rate of 9%, we can use the formula for the present value of a perpetuity:

PV = Payment / Discount Rate

Using the given values:

PV = $7000 / 0.09

PV ≈ $77,778.78

Therefore, at a discount rate of 9%, the present value of the perpetuity is approximately $77,778.78.

If the discount rate were lowered to 4.5%, we can calculate the new present value using the same formula:

PV = Payment / Discount Rate

PV = $7000 / 0.045

PV ≈ $155,555.56

Therefore, at a discount rate of 4.5%, the present value of the perpetuity would be approximately $155,555.56.

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The clock minutes rotate 270 degrees in 45 minutes.

While rotating, the clock's hands are seen to move at a speed of six degrees per minute.

The number of degrees for a clock minute is solved by

60 minutes  = 360 degrees

1 minute = ?

cross multiplying

60 * ? = 360

? = 360 / 60

? = 6

hence 1 minute is 6 degrees

The formula to use to get the calculation is multiplying the number of minutes by 6

Number of degrees in 45 minutes = 45 * 6

Number of degrees in 45 minutes = 270 degrees

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The correct answer is D. f(x) = 11x - 4 and g(x) = (x + 4)/11

To determine which pair of functions are inverses of each other, we need to check if the composition of the functions results in the identity function, which is f(g(x)) = x and g(f(x)) = x.

Let's test each option:

Option A:

f(x) = x/2 + 15

g(x) = 12x - 15

f(g(x)) = (12x - 15)/2 + 15 = 6x - 7.5 + 15 = 6x + 7.5 ≠ x

g(f(x)) = 12(x/2 + 15) - 15 = 6x + 180 - 15 = 6x + 165 ≠ x

Option B:

f(x) = ∛3x

g(x) = (x/3)^3 = x^3/27

f(g(x)) = ∛3(x^3/27) = ∛(x^3/9) = x/∛9 ≠ x

g(f(x)) = (∛3x/3)^3 = (x/3)^3 = x^3/27 = x/27 ≠ x

Option C:

f(x) = 3/x - 10

g(x) = (x + 10)/3

f(g(x)) = 3/((x + 10)/3) - 10 = 9/(x + 10) - 10 = 9/(x + 10) - 10(x + 10)/(x + 10) = (9 - 10(x + 10))/(x + 10) ≠ x

g(f(x)) = (3/x - 10 + 10)/3 = 3/x ≠ x

Option D:

f(x) = 11x - 4

g(x) = (x + 4)/11

f(g(x)) = 11((x + 4)/11) - 4 = x + 4 - 4 = x ≠ x

g(f(x)) = ((11x - 4) + 4)/11 = 11x/11 = x

Based on the calculations, only Option D, where f(x) = 11x - 4 and g(x) = (x + 4)/11, satisfies the condition for being inverses of each other. Therefore, the correct answer is:

D. f(x) = 11x - 4 and g(x) = (x + 4)/11

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The equation of the tangent line to the parabola at the point (1,5) is y = 4x + 1.

To find the slope of the tangent line to the parabola at the point (1,5), we need to find the derivative of the equation y = 6x - x² and evaluate it at x = 1.

Taking the derivative of y with respect to x:

dy/dx = d(6x - x²)/dx

= 6 - 2x

Now, we can substitute x = 1 into the derivative to find the slope at that point:

slope = 6 - 2(1)

= 6 - 2

= 4

So, the slope of the tangent line to the parabola at the point (1,5) is 4.

To find the equation of the tangent line, we need to use the point-slope form of a line.

The equation is given by:

y - y₁ = m(x - x₁)

Substituting the values we have:

y - 5 = 4(x - 1)

Expanding and simplifying:

y - 5 = 4x - 4

Moving the constant term to the other side:

y = 4x + 1

Therefore, the equation of the tangent line to the parabola at the point (1,5) is y = 4x + 1.

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Complete question =

Find the slope of the tangent line to the parabola at the point (1,5). y = 6x-x². find an equation of the tangent line.

A relation R from set X to a set Y is defined as a subset of the cartesian product X × Y. Relations can be reflexive, symmetric, antisymmetric,or transitive.

(a) Relation R is reflexive and symmetric but not transitive.(b) Relation R is reflexive, symmetric, and transitive.(c) Relation R is reflexive, symmetric, and not transitive.(d) Relation R is reflexive, symmetric, and transitive.(e) Relation R is reflexive, antisymmetric, and transitive but not symmetric.

(a) {(1,1),(1,2),(1,3)}:

The matrix representation of this relation is:

\(\left[\begin{array}{ccc}1&1&1\\0&0&0\\0&0&0\end{array}\right]\)

(b) {(1,2),(2,1),(2,2),(3,3)}:

The matrix representation of this relation is:

\(\left[\begin{array}{ccc}0&1&0\\1&1&0\\0&0&1\end{array}\right]\)

(c) {(1,1),(1,2),(1,3),(2,2),(2,3),(3,3)}:

The matrix representation of this relation is:

\(\left[\begin{array}{ccc}1&1&1\\0&1&1\\0&0&1\end{array}\right]\)

(d) {(1,3),(3,1)}:

The matrix representation of this relation is:

\(\left[\begin{array}{ccc}0&0&1\\0&0&0\\1&0&0\end{array}\right]\)

Note: In each matrix, the element in the i-th row and j-th column represents the relation between the i-th and j-th elements of the set {1, 2, 3}. If the relation holds, the corresponding matrix element is 1; otherwise, it is 0.

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Answer:

900,000

Step-by-step explanation: