Maria claims that any fraction located between 1/4 and 1/8 on a number line must have a denominator of 12. Enter a fraction that shows Maria's claim is incorrect.
Answers
Answer:
LCM is 16
Step-by-step explanation:
2/3 - 1/2
There's something called whole fraction whereby the fractions should be multiplied to get the LCM 6
Here We Go!
2/2*2/3 - 3/3*1/2
The denominators are 2 and 3 and when multiplied. The above fraction will still give you the LCM to be 6
Related Questions
can someone please help me find the value of X?
Answers
The given diagram is a right angled triangle with an angle 34 degrees, whose opposite side is 'x', and adjacent side is 16 units.
Since it is right triangle, the triagonometric ratios are applicable.
Apply the tangent ratio as,
\(\tan \theta=\frac{OppositeSide}{Adjacent}\)Substitute the values and simplify,
\(\begin{gathered} \sin 34^{\circ}=\frac{x}{16} \\ 0.559=\frac{x}{16} \\ x=0.559\times16 \\ x\approx8.947 \end{gathered}\)Thus, the value of 'x' is 8.947 approximately.
The angle of a triangle are in ratio 4:5:6.what is the angle of the triangle?
Answers
Answer:
48, 60 and 72
Step-by-step explanation:
Given;
The ratios of the angle in the triangle = 4:5:6;
Unknown:
The angle of the triangle = ?
Solution:
We must understand that the sum of angles in a triangle is 180°
So as ratios; 4:5:6 denotes some certain multiples that sums up to 180°
Let the multiple number = x; so
4x : 5x : 6x
4x + 5x + 6x = 180
15x = 180
= 12
The angles in the triangles are:
4(12) : 5(12) : 6(12)
48 : 60 : 72
These angles are 48, 60 and 72
Help me plz plz help me with this question
Answers
Answer:
6 97/100 bags
Step-by-step explanation:
4 1/10 ⋅ 1 7/10 = ?
41/10 ⋅ 17/10 = 697/100
697/100 = 6 97/100
6 97/100 bags
Answer:
697/100 bags
or
6 97/100 bags
Step-by-step explanation:
it is fractions. just plain and simple.
when you eat a pizza slice, it is usually one of 8 slices that make the whole pizza. 1/8 or one 8th. meaning that the whole thing is 8/8 or eight 8ths.
the same for 10ths or any other fractions.
4 1/10 bags = 41/10 bags
1 7/10 times = 17/10 times
and now we multiply fractions, as 17/10 times is similar to 2 times or 3 times something - we multiply by this factor.
41/10 × 17/10
as we learned in early elementary school : numerators (top part of the fraction) are multiplied with each other, and denominators (bottom part) are multiplied with each other. and then we simplify the result as much as possible.
41/10 × 17/10 = (41×17) / (10×10) = 697/100
no simplification is possible, sadly.
but that means he used almost 7 bags of hot dog buns.
exactly 6 full bags and 97/100 of the 7th bag.
so, either
697/100 bags
or
6 97/100 bags
or as alternative (not wanted here in this example but just FYI)
6.97 bags
What does x equal? A. 4 B. 2 C. -2
Answers
Answer:
i.d.k
Step-by-step explanation:
(p^2n^1/2)^0
√ p^5n^4 equivalent to p^18n^6 √p?
Answers
The two expressions are not equivalent.
To simplify the expression (p^2n^1/2)^0 √ p^5n^4, we first need to understand the properties of exponents and radicals.
Recall that any number raised to the power of zero is equal to 1, so (p^2n^1/2)^0 = 1.
Next, we can simplify the radical term by multiplying the exponents inside and outside the radical:
√ p^5n^4 =
(p^5n^4)^(1/2)
= p^(5/2)n^(4/2)
= p^(5/2)n^2
Combining this result with the previous step, we have:
(p^2n^1/2)^0 √ p^5n^4
= 1 * p^(5/2)n^2
= p^(5/2)n^2
This is not equivalent to p^18n^6 √p. In fact, p^(5/2)n^2 cannot be simplified any further without additional information about the expression. ,
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(a) There are European cities that Betty would eventually like to visit. On her next vacation, though, she only has time to visit of the cities: one on Monday, one on Tuesday, and one on Wednesday. She is now trying to make a schedule of which city she'll visit on which day. How many different schedules are possible
Answers
Answer:
The number of different schedules possible is given by:
\(P_{(n,3)} = \frac{n!}{(n-3)!}\)
In which n is the number of European cities that Betty would eventually like to visit.
Step-by-step explanation:
The order in which the cities are visited is important, for example, visiting Paris on Monday and London on Tuesday is a different schedule than London on Monday and Paris on Tuesday. This means that the permutations formula is used to solve this question.
Permutations formula:
The number of possible permutations of x elements from a set of n elements is given by the following formula:
\(P_{(n,x)} = \frac{n!}{(n-x)!}\)
She wants to visit n cities on 3 days:
So the number of different schedules possible is given by:
\(P_{(n,3)} = \frac{n!}{(n-3)!}\)
In which n is the number of European cities that Betty would eventually like to visit.
#3 Preimage point B is
located at (5,-4).
B' is located at (20, -16).
Write the algebraic rule for
the transformation.
Answers
The algebraic rule for the transformation is B' = (Bx + 15, By - 12)
Given data ,
To determine the algebraic rule for the transformation from point B to point B', we need to find the equations that relate the coordinates of the preimage point B to the image point B'.
Let's denote the translation amounts in the x-direction and y-direction as (dx, dy). The coordinates of B' can be obtained by adding these translation amounts to the coordinates of B:
B' = (Bx + dx, By + dy)
Given that B is located at (5, -4) and B' is located at (20, -16), we can calculate the translation amounts:
dx = 20 - 5 = 15
dy = -16 - (-4) = -12
Hence , the algebraic rule for the transformation is B' = (Bx + 15, By - 12)
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Bean Seed Growth Temp 25 20 15 10 Days S 7 9 If the trend continues, how many days will it take at 10 degrees?
Answers
The needed number of days at 10 degrees is given as follows:
11 days.
How to define a linear function?The slope-intercept equation for a linear function is presented as follows:
y = mx + b
In which:
m is the slope.b is the intercept.For this problem, we have that when x decreases by 5, y increases by 2, hence the slope m is given as follows:
m = -2/5
m = -0.4.
Hence the time needed for a temperature of 10 degrees is given as follows:
9 + 2 = 11 days.
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6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
Answers
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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susan has collection of 50 nickels and dimes . if the number of nickels is four times the number of dimes how many nickels and dimes does she have
Answers
Answer:
10dimes and 40nickels
Step-by-step explanation:
We know that the amount of nickels is four times that of dimes, so think about the total 50 in 5parts; if we divide 50 by 5 we are going to get 10. The nickels get 4/5s of the total, and the dimes get 1/5 of it.
Find the area of the square.10 cm^225 cm^220 cm^25 cm^2
Answers
Answer:
25 cm^2
Explanation:
Given:
To find:
Area of the square
The area(A) of a square can be determined using the below formula;
\(A=s^2\)where s = side length = 5 cm
So the area of the given is;
\(A=5^2=25\text{ cm}^2\)Area of the given square is 25 cm^2
I need help asap!!!
Answers
Carina records the height of a candle after x hours burning. Her data are shown in the graph below. Burning Candle A graph has time burned (hours) on the x-axis and candle height (centimeters) on the y-axis. A line goes through points (2, 6), and (1, 8). Which is the best estimate for the height of the candle after 1 hour? 4 cm 5 cm 8 cm 9 cm
Answers
Answer:
8 cm
Step-by-step explanation:
Calculate the slope that intersects points (2,6) and (1,8), m=(6-8)/(1-2), m=-2.
Use the point-slope formula to determine the equation of the line that intersects both given points, y-8=-2(x-1), f(x)=-2x+10. Calculate f(1), -2(1)+10=8. Alternatively, you could just look at the given coordinates and see that inputting one hour (1,8) gives the output eight, (1,8).
Answer8CM
Step-by-step explanation:
Divide the polynomials. Your answer should be a polynomial. 2x^3 − 5x^2 + x /x
Answers
2x^3-5x^2+1
9
Dusty found out that each grain of sand weighs 40000 or .000025 of a pound. He decides to write this
number in scientific notation.
2.5 x 10
What value should Dusty record in the box?
Record your answer and fill in the bubbles on your answer
document. Be sure to use the correct place value.
Answers
Answer:
\(n = -5\)
Step-by-step explanation:
Given
\(Digit = 0.000025\)
Required
Rewrite using scientific notation, then find n
\(Digit = 0.000025\)
Express as fraction
\(Digit =\frac{25}{1000000}\)
This can be splitted to
\(Digit = 25 * 10^{-6}\)
The first number must be between 1 and 10; hence, 25 can be expressed as 2..5 * 10
\(Digit = 2.5 * 10* 10^{-6}\)
Apply law of indices
\(Digit = 2.5 * 10^{1-6}\)
\(Digit = 2.5 * 10^{-5}\)
Comparing n, the given options
\(n = -5\)
the see turtle population is modeled by equation p=400 x 5/4 power y
Answers
The value of p is 781.25.
What is a population growth?
Population Growth is defined as the increase in the number of individuals in a population is called population growth.
What is a common growth factor?
The growth factor is the ratio between the old price and the new price, once sales tax is included.
We want to know the population when y = 0, or when the number of years is zero.
Substitute the same in the equation
p = (400).\((\frac{5}{4} )^{y}\)
When y = 1 or at the 1st year, the population will be p = (400)(\(\frac{5}{4}\) ) = 500
This means that the population is increasing by a common growth factor of \((\frac{5}{4})\) .
When y = 3, or at year 3 we get the population as p = 400 \((\frac{5}{4} )^{3}\)
= 781.25
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Divide x cubed minus 3 x squared minus 10 x + 24 by x minus 2. Step 1 - Fill in the missing number: A vertical line and horizontal line combine to make a L shape. There is one row of entries in the shape including 1, negative 3, negative 10, 24. On the outside to the left of the L shape is k. k = -3 ⇒ 2 Step 2 - Fill in the missing number: A vertical line and horizontal line combine to make a L shape. There is one row of entries in the shape including 1, negative 3, negative 10, 24. On the outside to the left of the L shape is 2 and to the outside below 1 is a. a = 24 ⇒ 1 Step 3 - Fill in the missing numbers: A vertical line and horizontal line combine to make a L shape. There are two rows of entries in the shape. The first row includes 1, negative 3, negative 10, 24. The second row includes blank, b, d, blank. On the outside to the left of the L shape beside row 1 is 2. On the outside below the L shape in the first column is 1 and in the second column is c. b = c = d =
Answers
The value of k is 2 if the polynomial x³ - 3x² - 10x + 24 is divided by the expression (x - 2).
What is synthetic division?In the case of dividing by a linear factor, the synthetic division is a shorthand, or quicker, a technique of polynomial division.
The question is attached to the picture please refer to the picture.
We have a polynomial:
x³ - 3x² - 10x + 24
Which is divided by (x - 2)
We can divide using the synthetic division:
The first row: 1 -3 -10 24
The entry outside the row: 2
The missing value which is 2
k = 2
Thus, the value of k is 2 if the polynomial x³ - 3x² - 10x + 24 is divided by the expression (x - 2).
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Answer:
K= 2
A= 1
B= 2
C= -1
D= -2
Complete the division. The remainder is 0.
The quotient is
x² - x - 12
Step-by-step explanation:
f(x) = 4x -1 find f(-2)
g(x) = 3x^2 - 2 find g(6)
Answers
Answer:
f(-2) = -9
g(6) = 106
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
FunctionsFunction NotationStep-by-step explanation:
Step 1: Define
Identify
f(x) = 4x - 1
f(-2) is x = -2 for function f(x)
g(x) = 3x² - 2
g(6) is x = 6 for function g(x)
Step 2: Evaluate
f(-2)
Substitute in x [Function f(x)]: f(-2) = 4(-2) - 1Multiply: f(-2) = -8 - 1Subtract: f(-2) = -9g(6)
Substitute in x [Function g(x)]: g(6) = 3(6)² - 2Exponents: g(6) = 3(36) - 2Multiply: g(6) = 108 - 2Subtract: g(6) = 106please
\(2x {}^{2} + 2y {}^{2} - 6y - 12y = 3 \)
I need help
Answers
![please [tex]2x {}^{2} + 2y {}^{2} - 6y - 12y = 3 [/tex]I need help](https://i5t5.c14.e2-1.dev/h-images-qa/answers/attachments/0X88LdBuMwIAUWxByc8exEH7JSTCTQBj.png)
Find the complete factored form of the
polynomial :
-8m²n-7m² nª
Enter the correct answer.
Answers
The polynomial -8m²n - 7m²n can be factored using the common factor -m²n. The complete factored form of the polynomial is (-m²n) (8 + 7a).
To find the complete factored form of the polynomial -8m²n - 7m²n, we can factor out common terms from both the terms. The common factor in the terms -8m²n and -7m²n is -m²n. We can write the polynomial as:
-8m²n - 7m²n = (-m²n) (8 + 7a)
Therefore, the complete factored form of the polynomial -8m²n - 7m²n is (-m²n) (8 + 7a). This expression represents the original polynomial in a multiplied form. We can expand this expression using distributive law to verify that it is equivalent to the original polynomial.
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Determine the value of the expression –56–8+(−3) .
Answers
\(=56-8-3\\=(56-8)-3\\=48-3\\=45\)
GOODLUCK!!!
Student Enrollment
The enrollment at a local college has been decreasing linearly. In 2004, there where 975 students enrolled. By
2009, there were only 730 students enrolled. Determine the average rate of change of the school's enrollment
during this time period, and write a sentence explaining its meaning.
The average rate of change=
The enrollment at the college has been [Select an answer at a rate of
Select an answer v
Answers
The average rate of change of the school's enrollment during this time period is -49 students per year. This means that on average, the enrollment at the college has been decreasing by 49 students per year.
To determine the average rate of change of the school's enrollment during the given time period, we can use the formula:
Average rate of change = (Change in enrollment) / (Change in time)
The change in enrollment is calculated by subtracting the initial enrollment from the final enrollment, while the change in time is calculated by subtracting the initial year from the final year.
Given that in 2004 there were 975 students enrolled and in 2009 there were 730 students enrolled, we can calculate the change in enrollment:
Change in enrollment = 730 - 975 = -245 students
The change in time can be calculated as:
Change in time = 2009 - 2004 = 5 years
Now we can calculate the average rate of change:
Average rate of change = (-245 students) / (5 years) = -49 students per year
Therefore, the average rate of change of the school's enrollment during this time period is -49 students per year. This means that on average, the enrollment at the college has been decreasing by 49 students per year.
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Rosie sells her laptop to John and makes a 15% profit. John then sells the laptop to
Michael for £391. John makes a 15% loss. How much did John pay for the laptop?
Answers
Answer:
John pay:449.65
Step-by-step explanation:
(391×15)÷100=58,65
391+58,65=449,65
When adding 32.6 to a certain number, the sum is 36.14, as seen below. What number should go in the box to complete the addition problem? 3
Answers
The unknown number which is added to the number 32.6 will be 3.54.
What is an expression?The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.
Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.
Given that when adding 32.6 to a certain number, the sum is 36.14. The unknown number will be calculated as,
32.6 + N = 36.14
N = 36.14 - 32.6
N = 3.54
Therefore, the unknown number which is added to the number 32.6 will be 3.54.
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what is the answer to this equation 21 x ___=7
Answers
Answer:
the answer is 3
Step-by-step explanation:
21 x 3 =7
hope it helps
Answer:
21/7
Step-by-step explanation:
Move 7 to next side with opposite process it is multiple after move it will be divided so 21x (21/7) it will be 7 although (21/7)equivalent to 1/3
Help please I have to answer these questions using the graph.
Answers
Using the graph the problem is soled as follows
a. The concentration of the drug in 8 hours is 24 mg/L
b. The concentration of the drug is increasing from 0 to 2 hours and the concentration of the drug is decreasing from 2 to 20 hours
When does the drug have maximum concentrationc. The maximum concentration occurred in 2 hours and the maximum concentration at this time is 64 mg/L
d. The time required for the drug concentration to reduce to 16 mg/L is 8 hours.
at maximum it was at 2 hours while at 16 mg/L it was at 10 hours. by subtraction we have
10 - 2 = 8 hours
e. The graph will predict values close to zero but not equal to zero
f. The concentration of the drug is summarized as follows
The concentration rise to its peak which is 64 mg/L at 2 hours and after this time, the concentration is on a steady decline. at 20 hours it is at about 2 mg/L and continued decreasing
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wich expression is equivalent to 0.5 * 0.6?
Answers
Answer:
0.3
Step-by-step explanation:
Answer:
0.3
Step-by-step explanation:
I hope this is what you where asking for?
Find m<6. SHOW WORK!!!
Answers
Step-by-step explanation:
1 = 138 since they are opposite each other.
2 = 138 as well because of the 'Z'
5 is equal to 138 as it is opposite 2
5+6 = 180
6 = 180 -5
6= 180 -138
6= 42
Select all the equations that describe each situation and then find the solution.
Kiran’s backpack weighs 3 pounds less than Clare’s backpack. Clare’s backpack weighs 14 pounds. How much does Kiran’s backpack weigh?
Answers
Answer:
Its 11
Step-by-step explanation:
Please help (easy economics question)!!!
Answers
The dollar value of total revenue at each price is $\(0\), $\(10\), $\(12\), $\(12\), $\(10\), and $\(6\). Total revenue will be the greatest at a price of $\(4\), with \(3\) units sold.
To find the dollar value of total revenue at each price, we can multiply the price by the corresponding quantity in the demand schedule:
Price: $\(6\)
Quantity: \(0\)
Total Revenue: $\(6 \times 0\) = $\(0\)
Price: $\(5\)
Quantity: \(2\)
Total Revenue: $\(5 \times 2\) = $\(10\)
Price: $\(4\)
Quantity: \(3\)
Total Revenue: $\(4 \times 3\) = $\(12\)
Price: $\(3\)
Quantity: \(4\)
Total Revenue: $\(3 \times 4\) = $\(12\)
Price: $\(2\)
Quantity: \(5\)
Total Revenue: $\(2 \times 5\) = $\(10\)
Price: $\(1\)
Quantity: \(6\)
Total Revenue: $\(1 \times 6\) = $\(6\)
To determine at which price the total revenue will be the greatest, we observe that the highest total revenue occurs at the price with the highest quantity sold. In this case, the price with the highest quantity is $\(3\), and the corresponding quantity sold is \(4\) units.
Therefore, at a price of $\(3\), the total revenue will be the greatest, with \(4\) units sold.
For more such questions on revenue:
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