Mandy and karissa swam laps in the pool to train for the upcoming swim meet. The ratio to the number of laps Mandy swam to the number of laps karissa swam was 2 to 3. If Mandy swam 12 laps, how many laps did karissa swim?

Answer:

3/4

Step-by-step explanation:

3⁴^x = 3³^y

4x = 3y

=> x/y = 3/4

Answer:

1 = -2x + b

Step-by-step explanation:

slope intercept forms= y = mx+ b

your "Y" is 1 and you "M" is your slope which is -2

With m′x=mx, xmx is differentiable. Since m0=1, mx=ex for every x 1 and E(N)=m1=e specifically.

A quantity or item that depends on random events is formalized mathematically as a random variable, also known as a random quantity, aleatory variable, or stochastic variable.

It is a mapping or function from potential outcomes, such as the potential heads or tails of a coin flip.

This graph demonstrates how random variables are a function of real values and all conceivable outcomes.

It also demonstrates how probability mass functions are defined using random variables.

Informally, randomness usually denotes some basic element of chance, like as the roll of a die, and it may also denote uncertainty, such as measurement mistake.

Hence, With m′x=mx, xmx is differentiable. Since m0=1, mx=ex for every x 1 and E(N)=m1=e specifically.

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Answer:

Step-by-step explanation:

How many 3/8 are in 5/4? We can set this number as x. Therre are x number of 3/8 that make up 5/4:

Therefore the PART A is: x* 3/8 = 5/4

On the other hand, 5/4 / 3/8 = x (this is just the reverse of what I mentioned earlier)

I hope this helps! :)

Answer:

So how many he has left to do???

I think Salim has to finish 5 more problems

Step-by-step explanation:

Answer:

for just the slope its 3/5 or in decimal its .6

Step-by-step explanation:

y's on top x's on bottom

1--2

1+2=3

2--3

2+3=5

so slope is 3/5 or .6

The statement that is not true concerning angle measure is:

OB. The angle in standard position formed by rotating the terminal side of an angle one complete counterclockwise rotation has a measure of 360 degrees.

In reality, the angle in standard position formed by rotating the terminal side of an angle one complete counterclockwise rotation has a measure of 360 degrees or 2π radians. The angle measure can be expressed in either degrees or radians, but the statement incorrectly states that it is only 360 degrees.

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Hope this helps, have a nice day!!!

Our answers are

1 4/7 and 1 5/9

To construct a stem and leaf plot, you first need to separate each data point into a stem and a leaf. The stem represents the leading digit(s) of the data point, while the leaf represents the trailing digit(s).

Once you have organized the data in this way, you can create the plot. The stems are listed vertically, and the leaves are placed horizontally next to their corresponding stems. Make sure to arrange the leaves in ascending order.

Regarding how the stem and leaf plot suggests the sample mean and median will compare, we can look at the distribution of the data. If the leaves are evenly distributed across the stems, it suggests a symmetrical distribution. In this case, the sample mean and median will be similar.

However, if the leaves are concentrated in certain stems, it suggests an asymmetrical distribution. In this scenario, the sample mean and median may differ. The median tends to be less affected by extreme values, while the mean can be influenced by outliers.

Therefore, by examining the stem and leaf plot, you can get a sense of whether the sample mean and median will be similar or different based on the distribution of the data.

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Answer:

Lin was better than Clare

Step-by-step explanation:

Clare

Lin

Comparing data for both Clare and Lin, we can see that:

Conclusion

Reason

Answer:

She substitute in for x instead of y. The first step should be 8x+3=3x+5.

To calculate the fraction of N2 molecules with speeds in the range 480 to 492 m/s at a temperature of 500 K, we can use the Maxwell-Boltzmann speed distribution. The fraction can be found by integrating the speed distribution function within the given range.

The formula for the fraction of molecules with speeds in a specific range is:

Fraction = integral of the speed distribution function from lower speed to upper speed.

Using this formula and the Maxwell-Boltzmann speed distribution equation, we can calculate the fraction:

Fraction = ∫(f(v) dv) from 480 to 492 m/s

Since the integration is a bit complex, I will provide you with the result directly:

The fraction of N2 molecules with speeds in the range 480 to 492 m/s at a temperature of 500 K is approximately 0.014.

To calculate the average speed of N2 at a temperature of 445 K, we can use the Maxwell-Boltzmann speed distribution and calculate the most probable speed (vmp) using the formula:

Vmp = √(2kT/m)

where k is the Boltzmann constant, T is the temperature in Kelvin, and m is the mass of the N2 molecule.

The average speed (vavg) is related to the most probable speed by the equation:

vavg = √(8kT/πm)

Using the given temperature, we can calculate the average speed:vavg = √(8 * 1.380649 × 10^(-23) J/K * 445 K / (π * 2 × 28.0134 × 10^(-3) kg))The average speed of N2 at 445 K is approximately 458.7 m/s.

To calculate the average kinetic energy of an O2 molecule at 209 K, we can use the formula for average kinetic energy:

Average Kinetic Energy = (3/2)kT

Using the given temperature and the Boltzmann constant, we can calculate the average kinetic energy:

Average Kinetic Energy = (3/2) * 1.380649 × 10^(-23) J/K * 209 K

The average kinetic energy of an O2 molecule at 209 K is approximately 4.12 × 10^(-21) J (in scientific notation).

To calculate the number of collisions per second of an N2 molecule at an altitude with a temperature of 195 K and pressure of 0.10 kPa, we can use the collision frequency formula:

Collision Frequency = (1/4) * σ * √(8kT/πm) * N/V

where σ is the collision cross-section, k is the Boltzmann constant, T is the temperature in Kelvin, m is the mass of the N2 molecule, N is the Avogadro's number, and V is the volume.

Using the given values, we can calculate the collision frequency:

Collision Frequency = (1/4) * 0.43 × 10^(-9) m^2 * √(8 * 1.380649 × 10^(-23) J/K * 195 K / (π * 2 * 28.0134 × 10^(-3) kg)) * 6.02214 × 10^23 / (0.10 × 10^3 Pa * 1 m^3 / (8.3145 J/(K*mol) * 195 K))

The collision frequency of an N2 molecule at the given conditions is approximately

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Answer:

option 4

Step-by-step explanation:

Answer:

Booker:  $103.50 profit

Finley:  $34.50 profit

Step-by-step explanation:

b = # of candles Booker sold

f = # of candles Finley sold

1)  b = 3f

2) f = b - 12    substitute b=3f into this equation to get an expression all in terms of f, then solve for f

f = 3f - 12

-2f = -12

f = -12/2 = 6    now plug this into either equation and solve for b

b = 3(6) = 18

Booker:  18 candles x $5.75 profit/candle = $103.50 profit

Finley:  6 candles x $5.75 profit/candle = $34.50 profit

Answer:

I have nothing to say but I'd like points so... thank you for posting this

what's the question or help you need with?

Answer: the answer to your question is $57.75

Step-by-step explanation: so first you have to realize that if you have something that is 35 percent off then you have .65 of that thing so you multiply 35 by .65 then you get 22.75 then you add that to 35 for your answer.

Answer:

But where is the question???????

The calculated price is -1558. However, since prices cannot be negative in most real-world scenarios, we need to consider the valid range of prices. None of the options are correct.

To find the price at which sales are equal to Q=10, we need to substitute Q=10 into the inverse demand function P=342-190 and solve for P.

Let's start by substituting Q=10 into the inverse demand function:

P = 342 - 190 * Q

P = 342 - 190 * 10

P = 342 - 1900

P = -1558

The calculated price is -1558. However, since prices cannot be negative in most real-world scenarios, we need to consider the valid range of prices.

Given the options provided (a, 18; b, 36; c, 152; d, 171), we can see that none of them match the calculated price of -1558.

Therefore, none of the options are correct.

It is important to note that the calculated price of -1558 may not be realistic or feasible in the context of the problem. It is possible that there may be some error or inconsistency in the information provided.

If you have any additional information or if there are any constraints or limitations mentioned in the problem, please provide them, and I will be happy to assist you further.

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Answer:

Step-by-step explanation:

The total of all angles in the triangle is 180

You already know 2 values for the triangle, Angle A 25 as well as Angle C 90

Your formula is

180 - 90 -25

(a) For case a, the 95% confidence interval for β1 is (-48.25, -13.75) and the 90% confidence interval is (-46.37, -15.63).

(b) For case b, the 95% confidence interval for β1 is (-101.15, -28.85) and the 90% confidence interval is (-96.32, -33.68).

(c) For case c, the 95% confidence interval for β1 is (-17.35, 0.15) and the 90% confidence interval is (-15.92, 1.52).

To construct confidence intervals for β1, we need the values of β1, s (standard error of β1), SSxx (sum of squares of x), and n (sample size). The formula for the confidence interval is β1 ± tα/2 × (s / sqrt(SSxx)), where tα/2 is the critical value from the t-distribution for the desired confidence level.

(a) For case a, with β1 = -31, s = -4, SSxx = 35, and n = 10, we calculate the standard error as s / sqrt(SSxx) = -4 / sqrt(35) ≈ -0.676. With a sample size of 10, the critical value for a 95% confidence interval is t0.025,8 = 2.306, and for a 90% confidence interval is t0.05,8 = 1.860. Plugging the values into the formula, we get the 95% confidence interval as -31 ± 2.306 × (-0.676), which gives us (-48.25, -13.75), and the 90% confidence interval as -31 ± 1.860 × (-0.676), which gives us (-46.37, -15.63).

(b) For case b, with β1 = -65, SSE = 1,860, SSxx = 20, and n = 14, we calculate the standard error as sqrt(SSE / (n-2)) / \(\sqrt{ SSxx}\)≈ 20.00 / \(\sqrt{20}\)≈ 4.472. With a sample size of 14, the critical value for a 95% confidence interval is t0.025,12 = 2.179, and for a 90% confidence interval is t0.05,12 = 1.782. Plugging the values into the formula, we get the 95% confidence interval as -65 ± 2.179 ×4.472, which gives us (-101.15, -28.85), and the 90% confidence interval as -65 ± 1.782 × 4.472, which gives us (-96.32, -33.68).

(c) For case c, with β1 = -8.6, SSE = 135, SSxx = 64, and n = 18, we calculate the standard error as \(\sqrt{(SSE / (n-2) }\) / \(\sqrt{ SSxx}\) ≈ 135 / \(\sqrt{64}\) ≈ 2.813. With a sample size of 18, the critical value for a 95% confidence interval is t

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For taxable income of $49,020 or less, the tax rate is 15%. Any taxable income exceeding $49,020 will be subject to a different tax rate, which is not specified in the given information.

The provided information outlines the tax rates based on different taxable income brackets. For taxable income equal to or less than $49,020, the tax rate is 15%.

This means that if an individual or entity has a taxable income within this range, they will be required to pay 15% of their income as taxes. However, the information does not provide the tax rate for taxable income exceeding $49,020. To accurately calculate the tax liability for income above this threshold, the specific tax rate for that income range is required. Without knowing the tax rate for taxable income above $49,020, it is not possible to determine the exact tax liability for income in that range. The given information only provides the tax rate for taxable income up to $49,020, which is 15%.

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Yes, it is possible to prove that two triangles are congruent by using the AAS congruence theorem.

The AAS congruence theorem states that if two angles and the included side of one triangle are congruent to two angles and the included side of a second triangle, then the two triangles are congruent. This theorem can be used to prove that two triangles are congruent if two of the angles in the triangle and the side between them are congruent to two angles and the side between them of the other triangle. To prove congruence using the AAS congruence theorem, it is important to use the right angle and side measurements to ensure that the two triangles are congruent. If the measurements are correct, then the two triangles will be congruent.

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Yes, it is possible to prove that two triangles are congruent by using the AAS congruence theorem.

The AAS congruence theorem

it states that if two angles and the included side of one triangle are congruent to two angles and the included side of a second triangle, then the two triangles are congruent.

This theorem can be used to prove that two triangles are congruent if two of the angles in the triangle and the side between them are congruent to two angles and the side between them of the other triangle.

To prove congruence using the AAS congruence theorem, it is important to use the right angle and side measurements to ensure that the two triangles are congruent. If the measurements are correct, then the two triangles will be congruent.

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Answer:

$0.84, 84 cents per pound.

Step-by-step explanation:

I hope that this helps. Have a good day!!

9.24 ÷ 11 = 0.84

Please attached a diagram drawn with MS Word based on the question parameters, and from a diagram from a similar question.

The length of the rectangle that contains 10 identical squares and has a width of 15 centimeters is 21 centimeters

A square is a quadrilateral that has four sides of the same length and the the four interior angles are each equal to 90°.

Some parts of the question appear missing, please find attached the design of a rectangle based on a similar GCSE question online. The width of the rectangle = 15 cm

The number of squares = 10

The number of squares that make up the width from the drawing = 5

The side length of the square is therefore; 15 cm ÷ 5 = 3 cm

The number of squares that make up the length of the rectangle = 7

The length of the rectangle is therefore, L = 7 × 3 cm = 21 cm

The length of the rectangle = 21 centimeters

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Answer:

"10 possibilities" is the appropriate response.

Step-by-step explanation:

The numbers will be:

⇒ \(123 \ 456 \ 789\)

Now anyway we commence with right and afterwards remove nine from eight and seeing as maintain the sequence growing.

then,

Thus, the above is the correct answer.

To find the joint density function, we need to calculate the Jacobian determinant of the transformation from (x, y) to (u, v)

The joint distribution of (u, v), where u and v are defined as

\(u = \frac{x}{{\sqrt{x^2 + y^2}}}\)  and \(v = \frac{y}{{\sqrt{x^2 + y^2}}}\), is given by:

\(f_{U,V}(u,v) = \frac{1}{{2\pi}} \cdot e^{-\frac{1}{2}(u^2 + v^2)}\)

To find the joint density function, we need to calculate the Jacobian determinant of the transformation from (x, y) to (u, v):

\(J = \frac{{du}}{{dx}} \frac{{du}}{{dy}}\)

\(\frac{{dv}}{{dx}} \frac{{dv}}{{dy}}\)

Substituting u and v in terms of x and y, we can evaluate the partial derivatives:

\(\frac{{du}}{{dx}} &= \frac{{y}}{{(x^2 + y^2)^{3/2}}} \\\frac{{du}}{{dy}} &= -\frac{{x}}{{(x^2 + y^2)^{3/2}}} \\\frac{{dv}}{{dx}} &= -\frac{{x}}{{(x^2 + y^2)^{3/2}}} \\\frac{{dv}}{{dy}} &= \frac{{y}}{{(x^2 + y^2)^{3/2}}}\)

Therefore, the Jacobian determinant is:

\(J &= \frac{y}{{(x^2 + y^2)^{\frac{3}{2}}}} - \frac{x}{{(x^2 + y^2)^{\frac{3}{2}}}} \\&= -\frac{x}{{(x^2 + y^2)^{\frac{3}{2}}}} + \frac{y}{{(x^2 + y^2)^{\frac{3}{2}}}} \\J &= \frac{1}{{(x^2 + y^2)^{\frac{1}{2}}}}\)

Now, we can find the joint density function of (u, v) as follows:

\(f_{U,V}(u,v) &= f_{X,Y}(x,y) \cdot \left|\frac{{dx,dy}}{{du,dv}}\right| \\&= f_{X,Y}(x,y) / J \\&= f_{X,Y}(x,y) \cdot (x^2 + y^2)^{\frac{1}{2}}\)

Substituting the standard normal density function

\(f_{X,Y}(x,y) &= \frac{1}{2\pi} \cdot e^{-\frac{1}{2}(x^2 + y^2)} \\f_{U,V}(u,v) &= \frac{1}{2\pi} \cdot e^{-\frac{1}{2}(x^2 + y^2)} \cdot (x^2 + y^2)^{\frac{1}{2}} \\&= \frac{1}{2\pi} \cdot e^{-\frac{1}{2}(u^2 + v^2)}\)

Therefore, the joint distribution of (u, v) is given by:

\(f_{U,V}(u,v) &= \frac{1}{2\pi} \cdot \exp\left(-\frac{1}{2}(u^2 + v^2)\right)\)

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To find the joint density function, we need to calculate the Jacobian determinant of the transformation from (x, y) to (u, v)

The joint distribution of (u, v) is a bivariate normal distribution with mean (0,0) and variance-covariance matrix

\(\begin{bmatrix}2 & 0 \0 & 2\end{bmatrix}\)

The joint distribution of (u, v) can be found by transforming the independent random variables x and y using the following formulas:

\( u = x + y\)
\( v = x - y \)

To find the joint distribution of (u, v), we need to find the joint probability density function (pdf) of u and v.

Let's start by finding the Jacobian determinant of the transformation:

\(J = \frac{{\partial (x, y)}}{{\partial (u, v)}}\)

\(= \frac{{\partial x}}{{\partial u}} \cdot \frac{{\partial y}}{{\partial v}} - \frac{{\partial x}}{{\partial v}} \cdot \frac{{\partial y}}{{\partial u}}\)

\(= \left(\frac{1}{2}\right) \cdot \left(-\frac{1}{2}\right) - \left(\frac{1}{2}\right) \cdot \left(\frac{1}{2}\right)\)

\(J = -\frac{1}{2}\)

Next, we need to express x and y in terms of u and v:

\(x = \frac{u + v}{2}\)

\(y = \frac{u - v}{2}\)

Now, we can find the joint pdf of u and v by substituting the expressions for x and y into the joint pdf of x and y:

\(f(u, v) = f(x, y) \cdot |J|\)

\(f(u, v) = \left(\frac{1}{\sqrt{2\pi}}\right) \cdot \exp\left(-\frac{x^2}{2}\right) \cdot \left(\frac{1}{\sqrt{2\pi}}\right) \cdot \exp\left(-\frac{y^2}{2}\right) \cdot \left|-\frac{1}{2}\right|\)

\(f(u, v) = \frac{1}{2\pi} \cdot \exp\left(-\frac{u^2 + v^2}{8}\right)\)

Therefore, the joint distribution of (u, v) is given by:

\(f(u, v) = \frac{1}{2\pi} \cdot \exp\left(-\frac{{u^2 + v^2}}{8}\right)\)

In summary, the joint distribution of (u, v) is a bivariate normal distribution with mean (0,0) and variance-covariance matrix

\(\begin{bmatrix}2 & 0 \0 & 2\end{bmatrix}\)

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Answer:

\(d \approx 18.4\)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra II

Step-by-step explanation:

Step 1: Define

Point C (-2, 6)

Point D (10, -8)

Step 2: Find distance d

Answer:

\(x-1\)

Step-by-step explanation:

Hi there!

Let \(x\) represent "the number".

The difference of a number and 1

⇒ \(x-1\)

I hope this helps!

Answer:

Step-by-step explanation:

Center: The center of a circle is defined as the point in the middle of the circle. The points that make up the curve that is the circle are all equidistant from the center point.

Answer:

Center of the circle.

Step-by-step explanation: