Look at the picture and answer but I also need the value for each image

Answer:so the answer is 1,9,7,3,5,2

Step-by-step explanation:

The set of all possible outcomes is S = {A, C, G, T}. The set of all possible outcomes is also called the sample space. Events of interest might be E1 = an A

Step-by-step explanation:

-2a4 - 3a2 + 7a + 6 - 6a3 + a4 + 7a2 - 6

Solving like terms

-a4 - 6a3 + 4a2 + 7a

Option A is the correct answer

The value of x that makes the line containing (1,2) and (5,3) perpendicular to the line containing (x,4) and (3,0) is x = 2.

To determine the value of x such that the line containing (1,2) and (5,3) is perpendicular to the line containing (x,4) and (3,0), we need to find the slope of both lines and apply the concept of perpendicular lines.

The slope of a line can be found using the formula:

slope = (change in y) / (change in x)

For the line containing (1,2) and (5,3), the slope is:

slope1 = (3 - 2) / (5 - 1) = 1 / 4

To find the slope of the line containing (x,4) and (3,0), we use the same formula:

slope2 = (0 - 4) / (3 - x) = -4 / (3 - x)

Perpendicular lines have slopes that are negative reciprocals of each other. In other words, if the slope of one line is m, then the slope of a line perpendicular to it is -1/m.

So, we can set up the equation:

-1 / (1/4) = -4 / (3 - x)

Simplifying this equation:

-4 = -4 / (3 - x)

To remove the fraction, we can multiply both sides by (3 - x):

-4(3 - x) = -4

Expanding and simplifying:

-12 + 4x = -4

Adding 12 to both sides:

4x = 8

Dividing both sides by 4:

x = 2

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Answer:

Do you mean "Riley has a farm on a rectangular piece of land that is  200   meters wide. This area is divided into two parts: A square area where she grows avocados (whose side is the same as the length of the farm), and the remaining area where she lives.  

Every week, Riley spends  $3  per square meter on the area where she lives, and earns  $7  per square meter from the area where she grows avocados. That way, she manages to save some money every week." ?

The answer is 7L^2>3l(200-l)

Answer:

The commission rate is 15%

Step-by-step explanation:

commission = commission rate x sales

where the commission rate is expressed as a decimal.

In this case, the salesperson earned a commission of $345 for selling $2,300 in merchandise. Therefore, we have:

345 = commission rate x 2300

To solve for the commission rate, we can divide both sides by 2300:

commission rate = 345/2300

Simplifying this expression, we get:

commission rate = 0.15

So, the commission rate is 15%

Answer:

75%

Step-by-step explanation:

in order to find the percentage of something like this, all you need to do is divide the part by the whole, thus 240/320 to make 75%

Answer:

$28.00

Step-by-step explanation:

Set up an equation:

$22.40 = y(1 - 0.20)

Solve the contents of the parentheses first:

$22.40 = y(0.80)

Divide by 0.80 on both sides to isolate y:

($22.40)/0.80 = y

Solve:

$22.40 / 0.80 = $28.00

Answer:

Step-by-step explanation:

A) To find the area covered by two-way radio A, we need to calculate the area of a circle with a radius of 8 miles:

Area = πr² = 3.14 x 8² = 200.96 square miles

Rounding to the nearest whole number, two-way radio A covers 201 square miles.

B) To find the area covered by two-way radio B, we need to convert the radius from kilometers to miles and then calculate the area of a circle with that radius:

Radius in miles = 11.27 / 1.61 = 6.9988 miles (rounded to 4 decimal places)

Area = πr² = 3.14 x (6.9988)² = 153.94 square miles

Rounding to the nearest whole number, two-way radio B covers 154 square miles.

C) Two-way radio A covers a larger area than two-way radio B (201 square miles vs 154 square miles).

D) The scale factor relationship between the radio coverages can be found by dividing the radius of radio A by the radius of radio B:

Scale factor = radius of A / radius of B = 8 miles / (11.27 km / 1.61 km/mile) = 4.97

This means that the coverage of two-way radio A is almost 5 times larger than that of two-way radio B.

To solve this problem, we need to find the lengths of the two pieces when the wire is cut into two parts. Let's denote the length of each leg of the triangle as\(\(x\).\)

The perimeter of the triangle is the sum of the lengths of its three sides. Since the two legs are equal in length, the perimeter can be expressed as \(\(2x + x = 3x\).\)

The length of the wire is given as 71 cm, so we have the equation \(\(3x = 71\).\)

Solving for\(\(x\),\) we divide both sides of the equation by 3:

\(\(x = \frac{71}{3}\).\)

Now that we know the length of each leg of the triangle, we can proceed to the next part of the problem.

The circumference of a circle is given by the formula \(\(C = 2\pi r\)\), where\(\(C\)\)is the circumference and r is the radius. In this case, the wire of length xis bent into the shape of a circle, so we can set the circumference equal to x and solve for the radius r:

\(\(x = 2\pi r\).\)

Substituting the value of x we found earlier, we have:

\(\(\frac{71}{3} = 2\pi r\).\)

Solving for r, we divide both sides of the equation by \(\(2\pi\):\)

\(\(r = \frac{71}{6\pi}\).\)

Therefore, the two pieces of wire will have lengths\(\(\frac{71}{3}\)\)cm and the radius of the circle will be\(\(\frac{71}{6\pi}\)\) cm.

In summary, when the 71 cm wire is cut into two pieces, one piece will have a length o\(\(\frac{71}{3}\)\)cm, which can be bent into the shape of an equilateral triangle with legs of equal length, and the other piece can be bent into the shape of a circle with a radius of \(\(\frac{71}{6\pi}\)\) cm.

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Answer:

40%

Step-by-step explanation:

middle of 35 and 45

   35                 40      45

fail by 20      pass  extra 20

and the total marks are

400

that means

every 1% is equivalent to 4 marks

Step-by-step explanation:

=4(x)+4(-7)-2(x)-2(1) = -10

= 4x-28-2x-2= -10

therefore the third equation is equivalent to the given equation..all you need is to simplify.

Hope this Helps!!!

Answer:

Step-by-step explanation:

\(x=r cos \theta=7 cos150=7cos(180-30)=-7cos ~30=-\frac{7\sqrt{3} }{2} \\y=r~sin~\theta=7~sin ~150=7~sin~(180-30)=7~sin~30=\frac{7}{2} \\so ~coordinates ~are~(-\frac{7\sqrt{3}}{2} ,\frac{7}{2} )\\C\)

Let x = 2y. Then we want to show

sin(6y) + sin(4y) - sin(2y) = 4 sin(2y) cos(y) cos(3y)

Recall the angle sum identities,

sin(x ± y) = sin(x) cos(y) ± cos(x) sin(y)

cos(x ± y) = cos(x) cos(y) ∓ sin(x) sin(y)

which lets us write

sin(6y) = sin(4y + 2y) = sin(4y) cos(2y) + cos(4y) sin(2y)

sin(4y) = sin(2y + 2y) = 2 sin(2y) cos(2y)

cos(4y) = cos(2y + 2y) = cos²(2y) - sin²(2y)

Ultimately, we use these identities to rewrite the left side as

sin(6y) + sin(4y) - sin(2y)

= 2 (sin(4y) cos(2y) + cos(4y) sin(2y)) + 2 sin(2y) cos(2y) - sin(2y)

= 2 sin(2y) cos²(2y) + (cos²(2y) - sin²(2y)) sin(2y) + 2 sin(2y) cos(2y) - sin(2y)

Notice the underlined common factor of sin(2y). If we remove this from both sides of the identity we want to prove, then it remains to show that

2 cos²(2y) + (cos²(2y) - sin²(2y)) + 2 cos(2y) - 1 = 4 cos(y) cos(3y)

or

3 cos²(2y) - sin²(2y) + 2 cos(2y) - 1 = 4 cos(y) cos(3y)

Recall the Pythagorean identity,

cos²(x) + sin²(x) = 1

which lets us write

3 cos²(2y) - sin²(2y) + 2 cos(2y) - 1

= 3 cos²(2y) - (1 - cos²(2y)) + 2 cos(2y) - 1

= 4 cos²(2y) + 2 cos(2y) - 2

= 2 (2 cos²(2y) + cos(2y) - 1)

= 2 (2 cos(2y) - 1) (cos(2y) + 1)

Recall the half-angle identity for cosine,

cos²(x/2) = 1/2 (1 + cos(x))

which means

cos(2y) + 1 = 2 • 1/2 (1 + cos(2y)) = 2 cos²(y)

and so

2 (2 cos(2y) - 1) (cos(2y) + 1)

= 4 (2 cos(2y) - 1) cos²(y)

= 4 cos(y) (2 cos(2y) - 1) cos(y)

Now notice the underlined factor of 4 cos(y), which also appears in the right side of the identity we want to prove. Eliminate this term and all that's left is to show that

(2 cos(2y) - 1) cos(y) = cos(3y)

which follows from a combination of the identities I mentioned above:

(2 cos(2y) - 1) cos(y)

= 2 cos(2y) cos(y) - cos(y)

= 2 • 1/2 (cos(2y + y) + cos(2y - y)) - cos(y)

= (cos(3y) + cos(y)) - cos(y)

= cos(3y)

as required.

Trigonometric identities involve equations that use the trigonometric functions that are true for all variables in the equation

The identity is given as:

\(\sin(3x) + \sin(2x) - \sin(x) = 4\sin(x)\cos(\frac x2)\cos(\frac{3x}{2})\)

Let x = 2y.

So, we have:

\(\sin(6y) + \sin(4y) - \sin(2y) = 4\sin(2y)\cos(y)\cos(3y)\)

Expand

\(\sin(4y + 2y) + \sin(2y + 2y) - \sin(2y) = 4\sin(2y)\cos(y)\cos(3y)\)

Expand the identities using the angle sum identities,

\(\sin(4y)\cos(2y) + \cos(4y)\sin(2y) + 2\sin(2y)\cos(2y) - \sin(2y) = 4\sin(2y)\cos(y)\cos(3y)\)

Expand cos(4y) and sin(4y)

\(2\sin(2y)\cos^2(2y) + [\cos^2(2y) - \sin^2(2y)]\sin(2y) + 2\sin(2y)\cos(2y) - \sin(2y) = 4\sin(2y)\cos(y)\cos(3y)\)

Factor out sin(2y)

\(\sin(2y)[2\cos^2(2y) + \cos^2(2y) - \sin^2(2y) + 2\cos(2y) - 1] = 4\sin(2y)\cos(y)\cos(3y)\)

Evaluate the like terms

\(\sin(2y)[3\cos^2(2y) - \sin^2(2y) + 2\cos(2y) - 1] = 4\sin(2y)\cos(y)\cos(3y)\)

Substitute

\(\sin^2(2y) = 1 - \cos^2(2y)\)

\(\sin(2y)[3\cos^2(2y) - 1 + \cos^2(2y) + 2\cos(2y) - 1] = 4\sin(2y)\cos(y)\cos(3y)\)

Evaluate the like terms

\(\sin(2y)[4\cos^2(2y) - 1 + 2\cos(2y) - 1] = 4\sin(2y)\cos(y)\cos(3y)\)

\(\sin(2y)[4\cos^2(2y) + 2\cos(2y) - 2] = 4\sin(2y)\cos(y)\cos(3y)\)

Factor out 2

\(2\sin(2y)[2\cos^2(2y) + \cos(2y) - 1] = 4\sin(2y)\cos(y)\cos(3y)\)

Expand

\(2\sin(2y)[2\cos^2(2y) +2\cos(2y) - \cos(2y) - 1] = 4\sin(2y)\cos(y)\cos(3y)\)

Factorize

\(2\sin(2y)[2\cos(2y)( \cos(2y) + 1) -1( \cos(2y) + 1)] = 4\sin(2y)\cos(y)\cos(3y)\)

Factor out cos(2y) + 1

\(2\sin(2y)[( 2\cos(2y) - 1)( \cos(2y) + 1)] = 4\sin(2y)\cos(y)\cos(3y)\)

By half identity, we have:

\(\cos\²(\frac x2) = \frac 12 (1 + \cos(x))\)

Multiply both sides by 2

\(2\cos\²(\frac x2) = (1 + \cos(x))\)

Replace x with 2y

\(2\cos\²(y) = 1 + \cos(2y)\)

So, we have:

\(2\sin(2y)[( 2\cos(2y) - 1)( 2\cos^2(y))] = 4\sin(2y)\cos(y)\cos(3y)\)

\(4\sin(2y)(2 \cos(2y) - 1)(\cos^2(y)) = 4\sin(2y)\cos(y)\cos(3y)\)

Factor out cos(y)

\(4\sin(2y)(\cos(y)(2 \cos(2y) - 1)(\cos(y)) = 4\sin(2y)\cos(y)\cos(3y)\)

Expand

\(4\sin(2y)(\cos(y)(2 \cos(2y)\cos(y) - \cos(y)) = 4\sin(2y)\cos(y)\cos(3y)\)

Using the half identity, we have:

\(4\sin(2y)(\cos(y)(2 * \frac 12 *\cos(2y + y) + \cos(2y - y) - \cos(y)) = 4\sin(2y)\cos(y)\cos(3y)\)

\(4\sin(2y)(\cos(y)(\cos(3y) + \cos(y) - \cos(y)) = 4\sin(2y)\cos(y)\cos(3y)\)

\(4\sin(2y)\cos(y)\cos(3y) = 4\sin(2y)\cos(y)\cos(3y)\)

Recall that:

x = 2y

So, we have:

\(4\sin(x)\cos(\frac x2)\cos(\frac {3x}2) = 4\sin(x)\cos(\frac x2)\cos(\frac {3x}2)\)

Both sides of the equations are the same.

Hence, the identity \(\sin(3x) + \sin(2x) - \sin(x) = 4\sin(x)\cos(\frac x2)\cos(\frac{3x}{2})\) has been proved

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Answer:

x=30

Step-by-step explanation:

x/5 = 6

Multiply each side by 5

x/5 *5 = 6*5

x=30

Answer:

30

Step-by-step explanation:

x/5 times 5/1 = x

6 times 5 = 30

i.  The position vector of X is 2b - a.

ii.  The position vector of Y is (3b + c)/4.

iii.  The ratio XY : Y Z is \(|(2b - a) - ((3b + c)/4)|/|((3b + c)/4) - (a + c)/2|\). Simplifying this expression will give us the final ratio.

i. To find the position vector x of point X, we can use the concept of vector addition. Since AB : BX = 2 : 1, we can express AB as a vector from A to B, which is given by (b - a). To find BX, we can use the fact that BX is twice as long as AB, so BX = 2 * (b - a). Adding this to the vector AB will give us the position vector of X: x = a + 2 * (b - a) = 2b - a.

ii. Similar to the previous part, we can express BC as a vector from B to C, which is given by (c - b). Since BY : YC = 1 : 3, we can find BY by dividing the vector BC into four equal parts and taking one part, so BY = (1/4) * (c - b). Adding this to the vector BY will give us the position vector of Y: y = b + (1/4) * (c - b) = (3b + c)/4.

iii. Z is the midpoint of AC, so we can find Z by taking the average of the vectors a and c: z = (a + c)/2. The ratio XY : YZ can be calculated by finding the lengths of the vectors XY and YZ and taking their ratio. Since XY = |x - y| and YZ = |y - z|, we have XY : YZ = |x - y|/|y - z|. Plugging in the values of x, y, and z we found earlier, we get XY : YZ =\(|(2b - a) - ((3b + c)/4)|/|((3b + c)/4) - (a + c)/2|\).

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The actual consumer spending at a price of $27 per unit is $268.26.

Substitute the given price into the supply equation to get the corresponding quantity supplied:

p = q + 10

27 = q + 10

q = 17

Substitute q = 17 into the demand equation to get the corresponding price:

4q² + p² = 1405

4(17)² + p² = 1405

p² = 1405 - 1156

p² = 249

p = 15.78

The actual consumer spending can be calculated by multiplying the quantity demanded by the price:

Actual consumer spending = quantity demanded x price per unit

= 17 x 15.78

= $268.26

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The demand and supply equations for a certain product are given by space 4 q squared plus p squared equals 1405 and p equals q plus 10 where p is in dollars per unit and q is in units. For a price of $27 per unit, determine the actual consumer spending.

Answer:

  61.03°

Step-by-step explanation:

You want the angle opposite the side of length 7 in the triangle with other sides of lengths 4 and 8.

The law of cosines relates the angles of a triangle to the side lengths. For triangle ABC with opposite sides a, b, c, the relation is ...

  c² = a² +b² -2ab·cos(C)

Solving for angle C, we have ...

  cos(C) = (a² +b² -c²)/(2ab)

  C = arccos((a² +b² -c²)/(2ab))

In this triangle, that means ...

  C = arccos((4² +8² -7²)/(2·4·8)) = arccos(31/64)

  C ≈ 61.03°

The angle of interest is about 61.03°.

__

Additional comment

We get the same result from a triangle solver. See the second attachment. (The angle we want is angle B in that attachment.)

<95141404393>

Answer:

d) 1/12

Step-by-step explanation:

$0.09 will he have left after buying the greatest number of sunglasses and beach balls.

Mathematical expressions with inequalities are those in which the two sides are not equal. Contrary to equations, we compare two values in inequality. Less than (or less than or equal to), greater than (or greater than or equal to), or not equal to signs are used in place of the equal sign.

Given:

Model Inequality:  4x + 2.5x ≥  45.

Now, solving for inequality

4x + 2.5x ≥  45.

(4 + 2.5)x ≥ 45

6.5x ≥ 45

x ≥ 45/ 6.5

x≥ 6.92

x≥ 7 (approx)

So, the max price for sunglasses and beach balls = 4(6.92)+ 2.5(6.92)

                                                                                   = $44.91

Thus, the left money is = 45- 44.91 = $ 0.09

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Answer:

y≥1 is the answer :)

The Time taken for David and Amy to be exactly 23 miles apart is 1.014 Hours.

Let \(t\) be the time taken to reach 23 miles apart from a single point.

David and Amy start at same point and move towards different directions, making them move at perpendicular to each other.

According to Pythagoras theorem, and distance = Speed x time.

\((17t)^2 + (15t)^2 = 23^2\)

\(289t^2 + 225t^2 = 529\)

\(\therefore 514t^2 = 529\)

\(t^2 = \frac{529}{514}\)

\(t^2 = 1.029\)

\(\therefore t = \sqrt{1.029} = 1.014 \text{ hours}\)

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Answer:

The distributive property tells us how to solve expressions in the form of a(b + c). The distributive property is sometimes called the distributive law of multiplication and division. ... Then we need to remember to multiply first, before doing the addition!

Step-by-step explanation:

Greetings! Hope this helps!

Answer

240 emails in 6 hours

Explanation

160/4 = 40 emails per hour

40 x 6 = 240 emails in 6 hours

Have a good day!

_______________

A brainliest would help tons! :D

The theorem that justifies the similarity of the two triangles is given as follows:

A: AA.

The Angle-Angle (AA) Congruence Theorem states that if two pairs of corresponding angles are congruent, then the triangles are similar.

In other words, if two angles of one triangle are equal in measure to two angles of another triangle, then the third angle in each triangle must also be equal in measure, and the two triangles are therefore congruent.

The two pairs of corresponding angles that are congruent in this problem are given as follows:

Hence the third angle will also have the same measure for both triangles.

Hence the AA theorem can be used and the correct option is given by option A.

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Answer:A topic sentence is used to bring

to a paragraph.

Step-by-step explanation:

A topic sentence is used to bring

to a paragraph.

Answer:

۴۶-(-۳۵)=۸۱

Step-by-step explanation:

We can use the formul

Answer:

7x−3=7k,x=7k+3,k∈ℤ

Step-by-step explanation:

3x ≡ 2 (mod 7)

3 is a solution, since 3×3−2=7.

All solutions are 3+7ℤ

y=3x−2/7=3(x−3)+7/7=3(x−3)/7+1

7x−3=7k,x=7k+3,k∈ℤ

The simplified value of the given expression (2x^3 + 3x + 7) / (x^2 + x + 10) is: the quotient will be 2x - 2 and the remainder will be -15x + 27.

Let us solve the given algebraic expression by the long division method:

We are given the expression:

(2x^3 + 3x + 7) / (x^2 + x + 10)

We need to perform the division of the given algebraic expression:

x^2 + x + 10  ) 2x^3 + 3x + 7 ( 2x - 2

                       2x^3 + 2x^2 + 20x

                     -         -            -        

                         -2x^2 - 17x + 7

                         -2x^2 - 2x  - 20

                         +        +       +          

                                  -15x + 27

So,

quotient = 2x - 2

remainder =  -15x + 27

Thus, the simplified value of the given expression (2x^3 + 3x + 7) / (x^2 + x + 10) is: the quotient will be 2x - 2 and the remainder will be -15x + 27.

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Answer:

= 59 - (59*0.07)

= 59 - 4.13

= 54.87

Answer:

The result would be 54.87