location of inhibitors bound to group iva phospholipase a2 determined by molecular dynamics and deuterium exchange mass spectrometry. t/f

The force on an electron would be upwards. To achieve this force, the velocity of the proton should be oriented parallel to the magnetic field, as shown below:

A magnetic field with north and south poles, similar to a bar magnet, is created as current flows through the coil. The magnetic field inside the solenoid has a parallel, linear pattern. A solenoid's magnetic field moves from its north pole to its south pole in one direction only.

a) To find the magnitude of the force on the proton, we use the formula:

F = qvBsinθ

where F is the force, q is the charge of the proton, v is its velocity, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field. Plugging in the values given, we get:

\(F = (1.602 * 10^-^1^9 C) * (3.60 m/s) * (0.750 T) * sin(55) = 2.06 * 10^-^1^7 N\)

To find the direction of the force, we use the right-hand rule, which states that if you point your thumb in the direction of the velocity, and your fingers in the direction of the magnetic field, then the force on a positive charge will be perpendicular to both your thumb and your fingers, in a direction given by the palm of your hand. In this case, the force will be pointing downwards, as shown below:

b) The maximum force will be achieved when the velocity of the proton is perpendicular to the magnetic field, since sin(90°) = 1, and the force is proportional to sinθ. In this case, the force will be:

\(F_m_a_x = (1.602 * 10^-^1^9 C) * (3.60 m/s) * (0.750 T) x sin(90) = 3.22 * 10^-^1^7 N\)

To achieve this force, the velocity of the proton should be oriented at a right angle to the magnetic field, as shown below:

The minimum force will be achieved when the velocity of the proton is parallel to the magnetic field, since sin(0°) = 0, and the force is proportional to sinθ. In this case, the force will be zero:

\(F_m_i_n = (1.602 * 10^-^1^9 C) * (3.60 m/s) x (0.750 T) * sin(0) = 0 N\)

To achieve this force, the velocity of the proton should be oriented parallel to the magnetic field, as shown below:

c) For an electron traveling in the same way as the proton, the magnitude of the force would be the same as in part (a), since the only difference between a proton and an electron is their charge (protons are positive, while electrons are negative). However, the direction of the force would be opposite, since electrons have a negative charge. Therefore, the force on an electron would be upwards.

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The rocket landed 92.45m below when it hit the ground.

When a  body is dropped from a height, its initial velocity is 0. A body executing free fall moves with constant acceleration i.e., acceleration due to gravity

Given data -

By using 2nd equation of motion:

\(s = ut + \frac{1}{2} at^2\)

Equation of motion under gravity:

\(s = ut + \frac{1}{2} gt^2\)

  \(= 0 \times 4.3 \sec + \frac{1}{2} \times 10 \times (4.3)^{2}\) ( assuming g = 10 m/s²)

  \(= \frac{1}{2} \times 10 \times 18.49\)

  = 5 × 18.49

  =  92.45 m

Thus we can conclude that the rocket landed 92.45m below when it hit the ground.

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After 42 minutes, there are 203 x \(10^{20\) atoms remaining of the radioactive substance.

To determine the number of atoms remaining after a certain amount of time has passed, we can use the formula for radioactive decay:

N(t) = N0 * \((1/2)^{(t / T)\),

where:

N(t) = number of atoms remaining at time t,

N0 = initial number of atoms (812 x  \(10^{20\) atoms),

T = half-life of the substance (21 minutes), and

t = time that has passed.

Let's calculate the number of atoms remaining after a given time.

Suppose the time passed is t = 42 minutes (twice the half-life).

N(t) = 812 x  \(10^{20\) * \((1/2)^{(42 / 21)\)

N(t) = 812 x  \(10^{20\) * \((1/2)^2\)

N(t) = 812 x  \(10^{20\) * 1/4

N(t) = 203 x  \(10^{20\) atoms.

So, after 42 minutes, there are approximately 203 x \(10^{20\) atoms remaining of the radioactive substance.

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Explanation:

The answer is:

A squirrel runs up the trunk of a tree.

Answer:

its b

Explanation:

the one with the squirrel :p

Explanation:

a boy walks at 2m/s for 30sec and run at 5m/s for 20sec. what is his average speed

Answer:

consuming contaminated foods or beverages

Answer:

Podemos decir que la presión que se aplica sobre un liquido encerrado en un tanque es de 5000 Pa.

Explanation:

Answer:

Podemos decir que la presión que se aplica sobre un liquido encerrado en un tanque es de 5000 Pa.

Explanation:

The mass spectrometer separates ions of different masses by utilizing the relationship between the strength of the magnetic field, the accelerating voltage, the charge-to-mass ratio of the ions, and the resulting radius of the circular path

From the formula in the question;

B is a symbol for the magnetic field's intensity as it is applied to the mass spectrometer.

The accelerating voltage used to move the ions is called Vaccelm.

The charge of the ion, specifically its charge-to-mass ratio (q/m), is represented by the letter q.

The mass spectrometer may selectively alter the radius of the circular route for various ions by varying the magnetic field's intensity (B). This makes it possible to spatially segregate ions with various masses based on their various radii. The ions' locations and masses can then be measured using detectors placed along the journey.

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Angle of incidence=angle of refraction

\(\\ \sf\longmapsto sin\:i=sin\:r\)

\(\\ \sf\longmapsto sin\:r=30°\)

Answer: A

Explanation:

Answer:

The answer is A. It detects any current in the wire.

Explanation:

I took the quiz.

The amount of charge that will pass through the cross-sectional area of the conductor in 1 min is 192 C.

We can use the formula Q = I * t,

where;

Given that a charge of 6.4 C passes through a cross-sectional area of the conductor in 2 s, we can find the current using the formula:

I = Q / t = 6.4 C / 2 s = 3.2 A

So, the current through the conductor is 3.2 A.

To find the amount of charge that will pass through the cross-sectional area of the conductor in 1 min (60 s), we can use the same formula:

Q = I * t = 3.2 A * 60 s = 192 C

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Since you wanted to use some brain-mapping techniques to identify anatomical functioning, the method that would be the best choice is option A. MRI.

In PET scans, the breakdown of option B:  radioactive materials in the body and the release of gamma rays produce a functional view of the brain.

FDG, which stands for "fluorodeoxyglucose," is a simple sugar (like glucose) that is frequently employed in PET scanning. It is injected into the bloodstream and builds up inside the body, where it emits gamma rays as energy.

Note that without injecting any kind of dye or tracer, brain mapping techniques like magnetoencephalography (MEG) and functional magnetic resonance imaging (fMRI) scans can be used to detect the anatomical functioning of the brain. The diagnosis and treatment of neurodegenerative illnesses can both benefit greatly from these techniques.

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a) The image is attached to this answer

b) The kinetic friction force affects the forward force of the ball.

The force that opposes a rolling ball's motion is called rolling friction. It slows the ball down by acting in the opposite direction to that of the ball's motion. The weight of the ball and the type of the surface are two variables that affect rolling friction.

The force that a surface uses to maintain the weight of an object that is resting on it is known as the normal force. When a ball is rolling, the normal force exerts itself perpendicular to the surface the ball is moving on. It maintains the ball's weight balance and offers the required reaction force for rolling motion.

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The wavelength of light that should be used to obtain fringes that are 0.0045 m wide after reducing the distance between the screen and the slit by half is 2.25 * 10^7 Å.

Huygens's Principle states that every point on a wavefront can be considered as a source of secondary spherical wavelets that spread out in all directions with the same speed as the original wave. The new wavefront is formed by the envelope of these secondary wavelets at a later time.

Now, let's consider a Young's double-slit experiment. In this experiment, when light passes through two narrow slits, it creates an interference pattern on a screen behind the slits. The fringe width is the distance between two consecutive bright or dark fringes in the pattern.

Given that the fringe width obtained is 0.6 cm and the wavelength of light used is 4500 Å (Angstroms), we can calculate the wavelength of light required to obtain fringes that are 0.0045 m wide.

We can use the formula for fringe width in Young's double-slit experiment:

w = (λ * D) / d

Where:

w is the fringe width,

λ is the wavelength of light,

D is the distance between the screen and the double slits, and

d is the distance between the two slits.

Let's calculate the value of D/d using the given information:

D/d = w / λ

= 0.006 m / 4500 Å (1 m = 10^10 Å)

= 0.006 * 10^10 / 4500 m^-1

Now, if the distance between the screen and the slit is reduced by half, the new value of D/d would be:

(D'/d) = (0.006/2) * 10^10 / 4500 m^-1

Now, we can rearrange the equation to solve for the new wavelength (λ'):

(λ' * D') / d = (D/d)

λ' = (D/d) * d / D

= [(0.006/2) * 10^10 / 4500] * (4500 / 0.006) Å

= 0.0045 m * 10^10 / 2 Å

= \(0.00225 * 10^{10\) Å

=\(2.25 * 10^7\)Å

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Answer: B

G v = 60 cm/s λ = 15 cm E f = V / λ S f = 4 Hz U f = ? S f = (60 cm/s) / 15 cm 5.

Explanation:

The correct equation for the x-axis of object A is F-T = mga, where F is the force acting on object A, T is the tension in the rope, m is the mass of object A, g is the acceleration due to gravity, and a is the acceleration of object A.

From NA - WA = 0, we know that the normal force acting on object A is equal to its weight, NA = WA = mg = 75 kg * 9.81 m/\(s^2\) = 735.75 N.

From Ng - WB = 0, we know that the weight of object B is equal to the weight of the hanging mass, WB = mg = 75 kg * 9.81 m/\(s^2\) = 735.75 N.

The tension in the rope is equal to the weight of the hanging mass, T = WB = 735.75 N.

From F - T = mga, we can solve for the acceleration of object A, a = (F - T) / m = (mA * g - T) / mA = (mA * g - 735.75 N) / mA.

Substituting the given values of mA = 50 kg and g = 9.81 m/\(s^2\), we get a = (50 kg * 9.81 m/\(s^2\) - 735.75 N) / 50 kg = 4.549 m/\(s^2\).

Therefore, the correct equation for the x-axis of object A is F-T = mga = 50 kg * 4.549 m\(s^2\) = 227.45 N.

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To set an object in motion on a surface, it usually requires overcoming several factors. The primary requirement is to overcome the force of static friction between the object and the surface.

Static friction is the force that resists the motion of an object when it is at rest. The magnitude of static friction depends on the nature of the surfaces in contact and the normal force acting perpendicular to the surface. In order to overcome static friction and initiate motion, an external force must be applied to the object.

The minimum amount of force required to overcome static friction is known as the threshold force. This force must exceed the maximum static frictional force. Once the threshold force is applied, the object transitions from rest to motion, and the static friction changes to kinetic friction, which is typically lower than static friction.

The exact amount of force required to initiate motion varies depending on factors such as the weight of the object, the roughness of the surfaces, and any other external forces acting on the object. Smooth surfaces and lighter objects generally require less force to set them in motion compared to rough surfaces and heavier objects.

To overcome the force of static friction and set an object in motion, one can apply a force in the direction of desired motion, either by pushing, pulling, or applying a torque. Once the object is in motion, it continues to move with a constant velocity unless acted upon by external forces such as friction or gravity.

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Answer:

False

Explanation:

A contact force is any force that requires contact to occur. Contact forces are ubiquitous and are responsible for most visible interactions between macroscopic collections of matter. Pushing a car up a hill or kicking a ball across a room are some of the everyday examples where contact forces are at work. 

Answer:

false

Explanation:

Answer:Sir haymo knows

Explanation:

he gave as homework

The acceleration of the Saturn is - (2πf)²x(t).

A motion in which the restoring force is directly proportional to the body's displacement from its mean position is known as a simple harmonic motion, or SHM. This restoring force always moves in the direction of the mean position. A particle moving in simple harmonic motion accelerates as a(t) = - ω² x (t). Here, ω denotes the particle's angular velocity.

The acceleration of the particle at any position is directly proportional to the displacement from the mean position in simple harmonic motion, which is an oscillatory motion.

Given that:

at any time, the angular position of Saturn is (2πf)t.

the displacement in SHM at that time t is given by x(t)=R cos(2πf)t.

Hence, speed  in SHM at that time t is given by

\(v(t) = \frac{dx(t)}{dt} =R \frac{d }{dt} cos(2\pi f)t = -(2\pi f) sin(2\pi f)t\)

it's acceleration is

\(a(t) = \frac{dv(t)}{dt} =-(2\pi f) R \frac{d }{dt} sin(2\pi f)t = -(2\pi f)^2 Rcos(2\pi f)t = -(2\pi f)^2 x(t)\)

hence, at any time t, the acceleration of the Saturn is - (2πf)²x(t).

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Answer:

You have to compare the densities,

Explanation:

To find density:

1. Measure the object's weight

2. Divide the mass by the volume

Answer:

Acidity

Explanation:

pH measures how acidic or basic a substance is.

Answer:

a) Acidity

From the calculations, the Pd across the capacitors are 360V and 240V respectively.

The capacitor is a device used to store charges. Since the charge for capacitors in series is the same;

1/C = 1/20 + 1/30 = 0.05 + 0.033

C = 12 * 10^-3 F

Q = 12 * 10^-3 F * 600 V

Q = 7.2  C

Voltage across the 20mf  capacitor = 7.2  C/20 * 10^-3

= 360 V

Voltage across the 30mf capacitor =  7.2  C/30 * 10^-3

=240 V

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Answer:

PE = (|accepted value – experimental value| \ accepted value) x 100%

Explanation:

The word 'scientist' was first coined by William Whewell in the early 19th century. He proposed the term as a replacement for the previous term 'natural philosopher.

The four men who met at Cambridge in 1812 were Charles Babbage, John Herschel, George Peacock, and Richard Jones. They were all highly accomplished scientists and mathematicians, and they formed a close friendship and intellectual partnership. They discussed a wide range of scientific and philosophical topics, including the nature of knowledge, the role of mathematics in science, and the principles of inductive reasoning. Their meetings laid the foundation for the development of the modern scientific method and helped to establish the field of mathematics as a central component of scientific inquiry.

The inductive scientific method involves making observations and collecting data in order to draw general conclusions or make predictions about a particular phenomenon. It is based on the idea that knowledge can be built up gradually through the accumulation of empirical evidence. The debate surrounding this scientific method focused on the question of whether it was truly objective and reliable, or whether it was inherently biased by the particular observations and assumptions of the scientist conducting the research.

Women first began to make significant contributions to science in the 19th century, largely through the efforts of pioneers such as Mary Somerville and Caroline Herschel. These women often had to overcome significant social and institutional barriers in order to pursue scientific research, but their accomplishments helped to pave the way for future generations of female scientists.

The heroic part of the Philosophical Breakfast Clubs story is the way in which these four men collaborated and supported each other in pursuit of scientific knowledge. They were willing to challenge established ideas and take risks in order to advance their field. However, the flip side of this story is that their exclusive, male-dominated intellectual circle reinforced existing power structures and excluded women and other marginalized groups from participating in the scientific enterprise.

Darwin's statement that "science is not only for scientists" emphasizes the idea that scientific knowledge should be accessible and understandable to everyone, not just those who have specialized training or expertise. In order to fully participate in a democratic society, it is important for individuals to have at least a basic understanding of scientific concepts and methods. Whether or not one considers oneself to have a basic scientific literacy depends on individual experiences and education.

Therefore, It is important that forensics is categorized as a science because it involves the application of scientific principles and methods to the investigation of crimes and other legal matters. By using evidence-based techniques, forensic scientists can provide accurate and reliable information that can be used to make informed decisions in legal proceedings.

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Answer:

rbOH

Explanation:

The gauge pressure in the balloon as indicated by a difference of 0.0171 m in the heights of the water columns is 167.58 Pa.

The gauge pressure in the balloon is the pressure inside the balloon due to the water columns relative to the atmospheric pressure.

The gauge pressure in the balloon as indicated by a difference of 0.0171 m in the heights of the water columns is calculated as follows;

P = ρgΔh

P = (1,000)(9.8)(0.0171)

P = 167.58 Pa

Thus, the gauge pressure in the balloon as indicated by a difference of 0.0171 m in the heights of the water columns is 167.58 Pa.

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Answer:

F = 17170.16 N = 17.17 KN

Explanation:

First we need to find the mass of helicopter by using its weight:

Weight = mg

2.75 x 10⁵ N = m(9.8 m/s²)

m = (2.75 x 10⁵ N)/(9.8 m/s²)

m = 28061.22 kg

Now, we find acceleration. We have position vector as:

r = (0.02 m/s³)(t³)i + (2.2 m/s)(t)j - (0.06 m/s²)(t²)k

taking its derivative twice, we can find acceleration:

a = (3)(2)(0.02 m/s³)(t)i + (0)j - (2)(1)(0.06 m/s²)k

a = (0.12 m/s³)(t)i - (0.12 m/s²)k

at, t = 5 sec

a = (0.12 m/s³)(5 s)i - (0.12 m/s²)k

a = (0.6 m/s²) i - (0.12 m/s²) k

Now, the magnitude of acceleration will be:

a = √[(0.6)² + (-0.12)²]

a = 0.61 m/s²

So, from Newton's Second Law, the net force on helicopter is given as:

F = ma

F = (28061.22 kg)(0.61 m/s²)

F = 17170.16 N = 17.17 KN

Answer:

Option D

Explanation:

11,890

Hope this helps

Information technology has greatly impacted the economy, leading to increased productivity, efficiency, and innovation across industries.

The widespread adoption of information technology in the business world has led to a significant transformation in the way companies operate. Through the use of computers, software, and other digital tools, businesses are now able to streamline their operations, automate processes, and access vast amounts of data that can inform decision-making.

This has resulted in increased productivity, efficiency, and cost savings for companies. Additionally, information technology has facilitated the rise of new industries, such as e-commerce and digital marketing, while also enabling existing industries to adapt and innovate in response to changing market conditions.

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--The complete question is, How has information technology impacted the economy?--

The force between these charges, according to Coulomb's law would be -54 N.

We can solve this problem applying "Coulomb's Law" which states-

\(\qquad\:\sf \underline{F_{(air)} = K\times \dfrac{ q_1 q_2}{r^2}} \\ \)

\( \qquad\sf\underline{F_{(air)} = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ \)

Where-

According to the given parameters -

Now that required values are given, so we can plug the values into the formula and solve for Force -

\(\qquad\qquad \:\sf\underline{Force = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ \)

\( \longrightarrow \sf Force = 9\times 10^9 \times \dfrac{ 3\times 10^{-6}\times -5 \times 10^{-6}}{\bigg(5\times 10^{-2}\bigg)^2}\\ \)

\( \longrightarrow \sf Force = -\dfrac{9\times 5\times 3\times 10^{9} \times 10^{-12}}{25\times 10^{-4}}\\ \)

\( \qquad\longrightarrow \sf Force =- \dfrac{135 \times 10^{9-12+4}}{25}\\ \)

\( \qquad\longrightarrow \sf Force = - \dfrac{\cancel{135}}{\cancel{25}}\times 10\\ \)

\( \qquad\longrightarrow \sf Force = -5.4 \times 10\\ \)

\( \qquad\qquad\longrightarrow \sf \underline{Force = \boxed{\sf{-54 N}}} \\ \)