List Three units commonly used to measure volume

Answers

Answer 1

Answer:

Three common units of volume are:

cubic centimeters.

liters.

gallons.

Explanation:


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the diagram shows a basic hydraulic system which has a small piston and a large piston with cross-sectional areas of 0.005m² and 0.1m² respectively. A force of 20 N is applied to the small piston. Determine (a) the pressure transmitted in the hydraulic fluid (b) the mass of the load​

Answers

The pressure transmitted in the hydraulic fluid is 4000 Pa and the mass of the load is 40.82 kg.

To determine the pressure transmitted in the hydraulic fluid, we can use the formula:

Pressure = Force / Area

Given that a force of 20 N is applied to the small piston and the cross-sectional area of the small piston is 0.005 m², we can calculate the pressure as follows:

Pressure = 20 N / 0.005 m²

Pressure = 4000 Pa

Therefore, the pressure transmitted in the hydraulic fluid is 4000 Pa.

To determine the mass of the load, we need to consider the equilibrium of forces in the hydraulic system. The force applied to the small piston is transmitted to the larger piston. Since the system is in equilibrium, the force exerted by the larger piston must balance the force applied to the small piston.

Using the formula:

Force = Pressure × Area

The force exerted by the larger piston can be calculated as follows:

Force = Pressure × Area (large piston)

Force = 4000 Pa × 0.1 m²

Force = 400 N

Therefore, the force exerted by the larger piston is 400 N.

Since force is equal to mass multiplied by acceleration (F = m × a), and the acceleration due to gravity is approximately 9.8 m/s², we can calculate the mass of the load:

400 N = mass × 9.8 m/s²

Solving for the mass:

mass = 400 N / 9.8 m/s²

mass ≈ 40.82 kg

Therefore, the mass of the load is approximately 40.82 kg.

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The diagram shows a basic hydraulic system which has a small piston and a large piston with cross-sectional areas of 0.005m² and 0.1m² respectively. A force of 20 N is applied to the small piston. Determine (a) the pressure transmitted in the hydraulic fluid (b) the mass of the load​

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the diagram shows a basic hydraulic system which has a small piston and a large piston with cross-sectional

Match the correct definition for:
1. Fundamental band
2. Band of combination
3. Undertone Band
Choices:
A band resulting from a transition from a excited state (n > 0) and for which delta n > 3.
A band resulting from a transition from the state shallow (n = 0) to a final state (n = nf) and for which Delta n> 1
A band resulting from a transition from a excited state (n > 0) and for which Delta n > 1
A band resulting from simultaneous transitions in two vibrational modes.
A band resulting from a transition from the state flat (n = 0) to a final state (n = nf) and for which Delta n = 1.

Answers

A band resulting from a transition from the state shallow (n = 0) to a final state (n = nf) and for which Delta n> 1 is the correct definition for Band of combination. A band resulting from a transition from a excited state (n > 0) and for which Delta n > 3 is the correct definition for Fundamental band.

A band resulting from a transition from a excited state (n > 0) and for which Delta n > 1 is the correct definition for Overtone band.A band resulting from simultaneous transitions in two vibrational modes is the correct definition for Hot band.A band resulting from a transition from the state flat (n = 0) to a final state (n = nf) and for which Delta n = 1 is the correct definition for Undertone Band.

In the spectra of diatomic and polyatomic molecules, the absorption bands correspond to transitions between electronic, vibrational, and rotational energy levels. When the molecule absorbs energy and passes from one state to another, a broad range of frequencies are absorbed or emitted, giving rise to a band of absorption or emission rather than a single line.

The intensity and location of the bands are highly dependent on the molecular composition, electronic structure, and molecular environment. For polyatomic molecules, there are five primary types of vibration-rotation bands, which are: the fundamental band, the overtone band, the combination band, the hot band, and the Fermi resonance band.

The fundamental band refers to the band resulting from a transition from the state shallow (n = 0) to a final state (n = nf) and for which Delta n> 1. The overtone band refers to the band resulting from a transition from a excited state (n > 0) and for which Delta n > 3. The combination band refers to a band resulting from a transition from a excited state (n > 0) and for which Delta n > 1. The hot band refers to a band resulting from simultaneous transitions in two vibrational modes.

The Fermi resonance band is the result of a vibration in which two or more vibrational modes of similar frequencies interact. They're related to the harmonic and anharmonic nature of vibrations in molecules and are therefore highly sensitive to the molecule's structure and the environment.

This study could be used to analyze the vibrational properties of molecules, which are important in a variety of chemical and physical processes, such as spectroscopy, crystallography, and photochemistry.

In summary, the absorption bands correspond to transitions between electronic, vibrational, and rotational energy levels. The intensity and location of the bands are highly dependent on the molecular composition, electronic structure, and molecular environment. There are five primary types of vibration-rotation bands:

the fundamental band, the overtone band, the combination band, the hot band, and the Fermi resonance band. These bands are related to the harmonic and anharmonic nature of vibrations in molecules and are therefore highly sensitive to the molecule's structure and the environment.

This study is important in a variety of chemical and physical processes, such as spectroscopy, crystallography, and photochemistry.

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A supersonic flow at m1 = 1.58 and p1 = 1 atm expands around a sharp corner. if the pressure downstream of the corner is 0.1306 atm, calculate the deflection angle of the corner

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The process involves using the Mach angle formula and the Prandtl-Meyer function, along with the isentropic relation for supersonic flow.

To calculate the deflection angle of the corner in a supersonic flow, we can use the Prandtl-Meyer expansion theory.
Given the initial Mach number (m1) of 1.58 and the initial pressure (p1) of 1 atm, we need to find the deflection angle.
First, we can use the Mach angle formula:
Mach angle (θM) = arcsin(1/m1)
Substituting the given Mach number, we have:
θM = arcsin(1/1.58)
Using a calculator, we find that θM is approximately 37.1 degrees.
Next, we can use the Prandtl-Meyer function to find the Mach angle downstream of the corner (θ2). The Prandtl-Meyer function relates the Mach angles before and after the expansion.
The Prandtl-Meyer function is defined as:
ν(M) = √((γ+1)/(γ-1)) * arctan(√((γ-1)/(γ+1)*(M²-1))) - arctan(√(M²-1))
where γ is the ratio of specific heats and M is the Mach number.
To find θ2, we can rearrange the equation and solve for M2 (Mach number downstream of the corner):
M2 = √(1 + (ν2/√((γ+1)/(γ-1))))
Since ν1 = θM and ν2 = θ2, we can rewrite the equation as:
M2 = √(1 + (θ2/√((γ+1)/(γ-1))))
Now, we can find the Mach number downstream of the corner using the given pressure downstream (p2 = 0.1306 atm) and the ratio of specific heats (γ).
Using the isentropic relation for supersonic flow:
(p2/p1) = (1 + ((γ-1)/2)*M2²)^(γ/(γ-1))
Substituting the given values, we have:
(0.1306/1) = (1 + ((γ-1)/2)*M2²)^(γ/(γ-1))
Solving this equation will give us the Mach number downstream of the corner (M2).
Finally, using the equation:
θ2 = ν2 - ν1
we can find the deflection angle (θ2) by subtracting the Mach angle before the corner (θM) from the Mach angle downstream of the corner (θ2).
In conclusion, to calculate the deflection angle of the corner in a supersonic flow, we can use the Prandtl-Meyer expansion theory. By finding the Mach angle before and after the corner, and subtracting them, we can determine the deflection angle. The process involves using the Mach angle formula and the Prandtl-Meyer function, along with the isentropic relation for supersonic flow. By substituting the given values, we can find the Mach number downstream of the corner and calculate the deflection angle.

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Christmas is the best holiday true or false

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True. Definitely. What other holiday could match Christmas (I ran out of things to say)

a car’s bumper is designed to withstand a 3.00–km/h (0.833–m/s) collision with an immovable object without damage to the body of the car. the bumper cushions the shock by absorbing the force over a distance. calculate the magnitude of the average force on a bumper that collapses 0.200 m while bringing a 1050–kg car to rest from an initial speed of 0.833 m/s.

Answers

The average force on the bumper is 1821.455 Newtons.

Assuming there is no friction from the ground on the car that leads us to think the only restrictive force that acts on the car is the force on the bumper, we can think of the energy conversion during the collision.The car's kinetic energy just before it undergoes the collision is expended against the work done on the car through the bumper by the force that acts upon the bumper that takes the car to rest eventually.The kinetic energy the car had can be calculated as follows,

                     \(\begin{aligned}\\\text{kinetic energy} &= \small \frac{1}{2}mv^2\\\\&=\small \frac{1050\,kg\times (0.833\,m/s)^2}{2}\\\\&=\small 364.291\,kg\,m^2/s^2\end{aligned}\)

Note that the answer is kept in 3 decimals.The work done on the car by the force on it is as follows,

                     \(\begin{aligned}\\\text{work on the car} &= \small Fs\\\\&=\small F\times 0.200\,m\\\\&=\small 0.200F\, m\end{aligned}\)

These 2 quantities are equal as per the explanation and therefore,

                               \(\begin{aligned}\\\small 0.200F \,m &=\small 364.291\,kg\,m^2/s^2\\\\\small F &=\small 1821.455\, N\end{aligned}\)

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According to the giant impact hypothesis about the formation of the moon. Why did the earth not break apart into many pieces when the giant impact happened?

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The earth could not be broken apart by the impactor since it was formed of such light material (mostly gas and liquid).

What are the basic features of the theory of the enormous impact ?

According to the Giant Impact Hypothesis, which is the most widely accepted theory for how the moon formed, the Earth and a Mars-sized object called Theia collided with each other as they were forming as protoplanets. The moon was created from a large amount of debris. According to this theory, the Moon was created after the Earth collided with a smaller planet that was around Mars' size. The Moon was created when the impact's leftover debris gathered in an orbit around Earth.

The larger body may have caught the iron core of the striking object.

The key to this theory is understanding how consciousness works and harnessing its power for good. By doing so, we can help to manifest positive changes in our world collectively.

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Find the density, dry density, void ratio, water content, porosity, and degree of saturation: (a) Total mass=89.3 g, mass of water=21.4 g, total volume=49.3 cm^3, RD=2.66 (b) Total volume=1.00 cm^3, mass of water=0.49 g, mass of soil solids=1.32 g, RD=2.70V(air+water)= ?Vair = ?Vwater = ?Vsolids = ?Msolids

Answers

The density, dry density, void ratio, water content, porosity, and degree of saturation are 1.81 g/cm^3, 1.37 g/cm^3, 0.32, 0.31, 0.43, 1.00 and for b part 1.81 g/cm^3,  1.32 g/cm^3, 0.37, 0.37,  0.49 and 1.00 respectively.

To find the density, dry density, void ratio, water content, porosity, and degree of saturation for part (a) and (b), use the following formulas:

Density (part a) = Mass (89.3 g)/Volume (49.3 cm^3) = 1.81 g/cm^3

Dry Density (part a) = Mass of Soil Solids (67.9 g)/Volume (49.3 cm^3) = 1.37 g/cm^3

Void Ratio (part a) = Volume of Voids (21.4 g)/Volume of Soil Solids (67.9 g) = 0.32

Water Content (part a) = Mass of Water (21.4 g)/Mass of Soil Solids (67.9 g) = 0.31

Porosity (part a) = Volume of Voids (21.4 g)/Total Volume (49.3 cm^3) = 0.43

Degree of Saturation (part a) = Volume of Water (21.4 g)/Volume of Voids (21.4 g) = 1.00

For part (b):

Density = Mass (1.81 g)/Volume (1.00 cm^3) = 1.81 g/cm^3

Dry Density = Mass of Soil Solids (1.32 g)/Volume (1.00 cm^3) = 1.32 g/cm^3

Void Ratio = Volume of Voids (0.49 g)/Volume of Soil Solids (1.32 g) = 0.37

Water Content = Mass of Water (0.49 g)/Mass of Soil Solids (1.32 g) = 0.37

Porosity = Volume of Voids (0.49 g)/Total Volume (1.00 cm^3) = 0.49

Degree of Saturation = Volume of Water (0.49 g)/Volume of Voids (0.49 g) = 1.00


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The purest way to do un inverse square law experiment would Be to take sound intensiry level measurements in an anechoic chamber where mom reflections wont talloet die rosults. Suppose you stand 3 incluss Gor a speaker playing a sound und my dB
meter reads 62 dis. ( (5) What is the intensity of this sound in Wit?
(10) Find the intensity and dB level at a distance of 1 m from the same speaker.

Answers

5. At 3 inches from the speaker: Intensity ≈ 1.59 x 10^(-6) watts.

10. At 1 meter from the speaker: Intensity ≈ 9.25 x 10^(-9) watts, dB level ≈ 37.58 dB.

To calculate the intensity of the sound in watts and the dB level at different distances from the speaker, we can use the inverse square law for sound propagation. The inverse square law states that the intensity of sound decreases with the square of the distance from the source.

Given:

Distance from the speaker (D1) = 3 inches (0.0762 meters)dB reading at D1 = 62 dB

First, let's calculate the intensity (I1) in watts at a distance of 3 inches (0.0762 meters) from the speaker:

I1 = 10^((dB - 120) / 10)

= 10^((62 - 120) / 10)

= 10^(-5.8)

≈ 1.59 x 10^(-6) watts

Now, let's proceed to the next part of the question:

Distance from the speaker (D2) = 1 meter

We need to find the intensity (I2) and the dB level at this distance.

Using the inverse square law, we can calculate the intensity (I2) at a distance of 1 meter:

I2 = I1 * (D1 / D2)^2

= (1.59 x 10^(-6) watts) * ((0.0762 meters / 1 meter)^2)

= (1.59 x 10^(-6)) * (0.0762^2)

≈ 9.25 x 10^(-9) watts

To find the dB level at a distance of 1 meter, we can use the formula:

dB = 10 * log10(I / I0)

where I is the intensity and I0 is the reference intensity (usually taken as 10^(-12) watts).

dB2 = 10 * log10(I2 / I0)

= 10 * log10((9.25 x 10^(-9)) / (10^(-12)))

= 10 * log10(9.25 x 10^3)

≈ 37.58 dB

Therefore, the answers to the given questions are:

(5) The intensity of the sound at a distance of 3 inches from the speaker is approximately 1.59 x 10^(-6) watts.

(10) The intensity of the sound at a distance of 1 meter from the speaker is approximately 9.25 x 10^(-9) watts, and the corresponding dB level is approximately 37.58 dB.

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You have a potential difference of 7 V. How much work is done to transfer 0.15 C of charge through it

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The amount of work done to transfer 0.15 C of charge through a potential difference of 7 V is 1.05 J.

The electrical potential difference is the energy required to move a unit charge between two points.

As a result, the work done in transferring charge across a potential difference is

W = qV where: W = work done q = quantity of charge V = potential difference In the situation above, the potential difference is 7 V, and 0.15 C of charge are being transferred.

To calculate the amount of work done, plug in the values:

W = (0.15 C)(7 V)W = 1.05 J

Therefore, 1.05 J of effort is required to transfer 0.15 C of charge over a 7 V potential difference.

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if a beam of 11 kev x rays illuminates a sample, what angles will give diffraction maxima of the first, second and third order?

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When a beam of 11 keV X-rays illuminates a sample, the angles that will produce diffraction maxima of the first, second, and third order can be calculated using Bragg's law, which states that nλ = 2d sin(θ), where n is the order of diffraction, λ is the wavelength of the X-rays, d is the spacing between crystal lattice planes, and θ is the angle of incidence.

Bragg's law can be used to calculate the angles for diffraction maxima. For the first-order maximum (n = 1), we have λ = 2d sin(θ₁). Rearranging the equation, we get sin(θ₁) = λ / (2d). Substituting the values, with λ representing the wavelength of 11 keV X-rays (which can be converted to the corresponding wavelength), and the known spacing between lattice planes, we can solve for θ₁.

For the second-order maximum (n = 2), the equation becomes λ = 2d sin(θ₂). Solving for sin(θ₂) and substituting the values, we can find θ₂.

Similarly, for the third-order maximum (n = 3), we use λ = 2d sin(θ₃) to determine sin(θ₃) and find θ₃ by substituting the values.

By calculating these angles using Bragg's law, we can determine the angles that will produce diffraction maxima of the first, second, and third order for the given beam of 11 keV X-rays illuminating the sample.

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An object appears red when viewed with white light. What color would it appear when viewed with blue light?

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Answer:

Colour of any object is by the colour of light it reflects i.e if white light is incident on the object,it will reflect blue color.so it will appear blue.But if red light is incident on it,it will not reflect that and absorb it.so as it will not reflect any light it will appear black.

Explanation:

The colour of an object depends upon the light reflected and absorbed, so if you the object appears blue to you that means that the object reflects blue light and absorbs rest of the spectrum. That's why in black colour all light is absorbed and no light is emitted, thus absorbing all the radiation heat. Now, coming to the point, the red light incident on the object will contain light composed of many wavelength, some of which will be reflected by the body, so the body should reflected light of wavelength near to blue light thus giving a darkish red, with blueish tint. The resultant should be somewhat dark maroon.

A car has a momentum of 30kg m/s and it hits a car that has a momentum of 20kg m/s. If after the first car has a momentum of 15 kg m/s, what is the second cars momentum

Answers

The momentum of the second car is 40 kg.m/s with the initial momentum and final momentum before and after the collision.

Momentum equals the product of mass and velocity. The velocity is defined as the rate of change of displacement and measures the speed with respect to direction. Velocity is the vector quantity and hence, momentum is the vector quantity.

From the given,

Initial momentum before collision (C₁) = 30 kg.m/s

Initial momentum before collision(C₂) = 20 kg.m/s

Final momentum after collision (C₁) = 15 kg.m/s

Final momentum after collision(C₂) =?

Initial momentum of C₁, C₂ = final momentum of C₁, C₂

30×20 = 15× X

X = 30×20 / 15

  = 40 m/s.

The final momentum of the car is 40 kg.m/s.

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What is the source of protons that are pumped out of the mitochondrial matrix in Stage 1 of oxidative phosphorylation?​a.​NADH​b.​H2O​c.​FADH​d.​H2S

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The source of protons that are pumped out of the mitochondrial matrix in Stage 1 of oxidative phosphorylation is NADH (A).

During Stage 1, electrons from NADH are passed through the electron transport chain (ETC) and this process results in the pumping of protons across the inner mitochondrial membrane from the matrix to the intermembrane space. This proton gradient is then used by ATP synthase to generate ATP during Stage 2 of oxidative phosphorylation.

FADH can also donate electrons to the ETC, but it does not contribute as many protons to the gradient as NADH. H₂O and H₂S are not involved in the electron transport chain or the proton pumping process during oxidative phosphorylation. Understanding the role of NADH and FADH in the electron transport chain is crucial to understanding how cells generate ATP, the primary energy currency of the cell. Hence, the correct answer is Option A.

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As a freely falling object picks up downward speed, what happens to the power supplied by the gravitational force?.

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The power supplied by the gravitational force will increase because (Power=work/time).

What happens to a freely falling object's speed as it descends?

A falling object gains momentum as it descends.

An increase in air resistance is caused by a speed increase.

At some point, the force of air resistance grows strong enough to counteract the pull of gravity.

Since there is no net force at this point, the object will stop accelerating.

Although the direction and magnitude of velocity fluctuate, the acceleration caused by gravity remains constant and downward.

The ball has zero velocity at the highest point in its trajectory, and it picks up speed as it descends back toward the earth.

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The indirect method is used to determine total power in a parallel circuit when that power is determined from the total current, total resistance, and source voltage.

Answers

The indirect method is used to determine total power in a parallel circuit through the following:

Total currentTotal resistanceSource voltage

What is a Parallel circuit?

This involves the circuit which has branches and a portion of the total current flows through it as a result.

In determining the total power in a parallel circuit, the indirect method is used only if the parameters mentioned above are available.

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Which characteristics can be used to differentiate star systems? Select three options.
the number of stars in the system
O the level of dust and gas
the age of the stars in the system
the way stars are organized in the system
the color of stars in the system

Answers

Answer:

1,3and4 just did and got correct

Explanation:

Which characteristics can be used to differentiate star systems? Select three options.the number of stars

A bullet of mass M1 is fired towards a block of mass m2 initially at rest at the edge of a frictionless table of height h as in the figure. The initial speed of the bullet is vi . Consider two cases, a completely inelastic one and an elastic one,where the bullet bounces off the block. inelastic case elastic case a bullet inside no bullet inside A B A' B' What is the ratio of the flight time; i.e., tAB tA′B′ ?

Answers

The ratio of time of flight for inelastic collision to elastic collision is 1:2

The given parameters;

mass of the bullet, = m₁mass of the block, = m₂initial velocity of the bullet, = u₁initial velocity of the block, = u₂

Considering inelastic collision, the final velocity of the system is calculated as;

\(m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\m_1u_1 + 0 = v(m_1 + m_2)\\\\v= \frac{m_1u_1}{m_1 + m_2} \ -- (1)\\\\\)

The time of motion of the system form top of the table is calculated as;

\(v = u + gt\\\\v = 0 + gt\\\\v = gt\\\\t= \frac{v}{g} \\\\t_A = \frac{m_1u_1}{g(m_1 + m_2)} \ \ ---(2)\)

Considering elastic collision, the final velocity of the system is calculated as;

\(m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\m_1u_1 + 0 = m_1v_1 + m_2v_2\\\\m_1 u_1 = m_1v_1 + m_2v_2\)

Apply one-directional velocity

\(u_1 + (-v_1) = u_2 + v_2\\\\u_1 -v_1 = 0 + v_2\\\\v_1 = v_2 -u_1\)

Substitute the value of \(v_1\) into the above equation;

\(m_1u_1 = m_1(v_2 - u_1) + m_2 v_2\\\\m_1u_1 = m_1v_2 -m_1u_1 + m_2v_2\\\\2m_1u_1 = m_1v_2 + m_2v_2\\\\2m_1u_1= v_2(m_1 + m_2)\\\\v_2 = \frac{2m_1u_1}{m_1+ m_2} \ --(3)\)

where;

\(v_2\) is the final velocity of the block after collision

Since the bullet bounces off, we assume that only the block fell to the ground from the table.

The time of motion of the block is calculated as follows;

\(v_2 = v_0 + gt\\\\v_2 = 0 + gt\\\\t = \frac{v_2}{g} \\\\t_B = \frac{v_2}{g} \\\\ t_B = \frac{2m_1u_1}{g(m_1 + m_2)} \ \ ---(4)\)

The ratio of time of flight for inelastic collision to elastic collision is calculated as follows;

\(\frac{t_A}{t_B} = \frac{m_1u_1}{g(m_1 + m_2)} \times \frac{g(m_1 + m_2)}{2m_1u_1} \\\\\frac{t_A}{t_B} = \frac{1}{2} \\\\t_A:t_B = 1: 2\)

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1 =
Q=240c
t=300s

Please explain Im so confused

Answers

Answer:

Answer:

0.8 A

Explanation:

Given: Q = 240 C

t = 300 s

Required: I

Equation: I = Q / t

Solution: I = 240 C / 300 s

Answer: I = 0.8 A

Which of these best describes the relationship between the incident ray, the reflected ray, and the normal for a curved mirror?(1 point)
Responses

The angle that the incident ray makes with the normal is the same as the angle that the reflected ray makes with the normal. All points on a curved mirror have the same normal.
The angle that the incident ray makes with the normal is the same as the angle that the reflected ray makes with the normal. All points on a curved mirror have the same normal.

The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. All points on a curved mirror have the same normal.
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. All points on a curved mirror have the same normal.

The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.

The angle that the incident ray makes with the normal is the same as the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.
The angle that the incident ray makes with the normal is the same as the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.

Answers

For curved mirror, all points have same normal and angle of incidence is also equal to angle of reflection.

What is curved mirror?

A curved mirror is a mirror with curved reflecting surface and the surface may be convex or concave. Most of the curved mirrors have surfaces that are shaped like part of sphere but other shapes are sometimes used in the optical devices.

For a curved mirror, all points have same normal and the angle of incidence is also equal to angle of reflection. According to the laws of reflection, incident ray, reflected ray and normal all lie on same plane. For  curved mirror, normal remains the same at all points along the curved mirror.

Angle made between the incident ray and normal is the same as the angle made between reflected ray and the normal. Therefore, angle of reflection is equal to the angle of incidence.

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a monochromatic light beam is incident on a barium target that has a work function of 2.50 ev. if a potential difference of 1.00 v is required to turn back all the ejected electrons, what is the wavelength of the light beam? 355 nm 497 nm 744 nm 1.42 pm none of those answers

Answers

The wavelength of the light has beam 355 nm.

What is a wavelength?
A wavelength is the measure of a wave's distance from one peak to the next. It is the physical distance between two successive wave crests or troughs, and is usually measured in meters, nanometers, or micrometers. Wavelengths are an important aspect of light, sound, and other types of waves. Wavelengths are often used to describe the properties of these waves such as their color, pitch, and intensity. Wavelengths are also related to the frequency of a wave, with shorter wavelengths associated with higher frequencies and longer wavelengths associated with lower frequencies.

The wavelength of the light beam can be calculated using the equation λ = h/eV, where h is Planck's constant, e is the charge of an electron, and V is the potential difference in volts.
For this question, the wavelength of the light beam is therefore λ = (6.626 x 10-34 Js)/(1.602 x 10-19 C x 1 V) = 4.13 x 10-7 m or 355 nm.

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Friction is a ____________ force
a. Artificial
b. Natural
c. Pessimistic
d. Negative

Answers

Answer:

natural is the answer

Friction is a natural force which exist

Now, let's look at how the distance from the charge affects the magnitude of the electric field. Select Values on the menu, and then click and drag one of the yellow E-Field Sensors. You will see the magnitude of the electric field given in units of V/m (volts per meter, which is the same as newtons per coulomb). Place the E-Field Sensor 1 m away from the positive charge (1 m is two bold grid lines away if going in a horizontal or vertical direction), and look at the resulting field strength. Consider the locations to the right, left, above, and below the positive charge, all 1 m away. For these four locations, the magnitude of the electric field is________________. the same. greatest to the left of the charge. greatest below the charge. greatest to the right of the charge. greatest above the charge.

Answers

Electric field strength decreases as the distance from the source increases.

How the distance from the charge affects the magnitude of the electric field?

The strength of an electric field is inversely related to square of the distance from the source. This means that the electric field strength decreases when the distance from the source increases.

So we can conclude that Electric field strength decreases as the distance from the source increases.

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Wings produce a downward force .Why would this be useful to a race car?​

Answers

Answer:

it increases drag

Explanation:

Question 6 of 10
Which two changes would decrease the electric force between two charged
particles?
A. Increase the distance between the particles.
B. Increase the charge of both particles.
C. Increase the charge of one of the particles.
D. Decrease the charge of one of the particles.
E. Decrease the distance between the particles.

Answers

The electric force between two charged particles is decreased by increasing the distance and decreasing the charge of one of the particles. Thus, options A and D are correct.

The electric force or Coloumbic force between two charged particles is directly proportional to the product of charges and inversely proportional to the square of the distance between them. F = k (q₁×q₂) / r². The unit of force is Netwon.

From the Coloumbic force, the electric force is decreased by decreasing the number of charges, and the electric force is decreased by increasing the distance between the charges.

Hence, the ideal solution is options A and D.

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what is the importance of natural resources ?write 5 points ​

Answers

Hey there!

Natural Resource:

The resources, for example, sunshine, air, water, soil, plants, animals, minerals, rivers etc. which after natural formation remain distributed on the earth, are known as natural resource. The natural resources are found in solid, liquid or gaseous states, and in metallic or non metallic form.

Hope it help you

49. A 6.1-kg bowling ball is liſted 2.1 m to a shell. Find
the increase in the ball-Farth system's energy.

Answers

Answer:

125.5J

Explanation:

Given parameters:

Mass of the bowling ball  = 6.1kg

Height of lifting  = 2.1m

Unknown:

Increase in the ball energy  = ?

Solution:

The ball has changed position by moving it from one point to another. So, it has acquired more potential energy.

 Potential energy  = mgh

     m is the mass

     g is the gravity  

     h is the height

Now insert the given parameters and solve;

       Potential energy  = 6.1 x 9.8 x 2.1  = 125.5J

a rocket moves with a velocity of 0.862c to the right with respect to

Answers

The rocket's velocity is 0.862c relative to the observer.

In this scenario, the rocket is moving at a velocity of 0.862c to the right. The term "c" represents the speed of light, which is approximately 299,792,458 meters per second. To calculate the rocket's velocity, simply multiply 0.862 by the speed of light.

The velocity of the rocket is relative to an observer or a reference frame. This means that the rocket's speed is being measured compared to the position of an observer, which could be a person, a device, or another object. In this case, the rocket is moving at a velocity of 0.862 times the speed of light, which is a significant fraction of the speed of light and would cause relativistic effects, such as time dilation and length contraction, to become noticeable.

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Explain the advantages and disadvantages of having a racecar with a large mass in reference to Newton’s 1st law of motion. Use the term inertia in your answer.

Answers

Answer:

read the explanation

Explanation:

My answer to research question one is a car with a higher mass has more inertia than a car with a lower mass. A car with a higher mass needs more force to move than a car with a lower mass. The advantage of a car with greater mass is that it takes less impact when crash happens and has more protection.

The advantage of a race car with large mass is that it will continue moving without stopping once it is already in motion.

The disadvantage of a race car with large mass is that it will be difficult to get it start moving.

The Newton's first law of motion states that, an object in a state of rest or uniform motion in a straight line will continue in that form unless it is acted upon by an external force.

This first law is also known as law of inertia because it depends on mass of the object.

Inertia is reluctance of an object to move or stop moving once it is in motion.

Thus, the advantage of a race car with large mass is that it will continue moving without stopping once it is already in motion.

The disadvantage of a race car with large mass is that it will be difficult to get it start moving.

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what is the name used for the series of interacting circular surface currents in the ocean? multiple choice question. cyclones gyres orbits circuits

Answers

The name used for the series of interacting circular surface currents in the ocean is gyres. These currents play a significant role in the distribution of heat, nutrients, and marine life across the ocean basins.

Gyres are large systems of rotating ocean currents, particularly those involved with large wind movements. These currents form circular patterns, moving clockwise in the northern hemisphere and counterclockwise in the southern hemisphere due to the Coriolis effect. There are five major gyres in the world's oceans: the North Atlantic gyre, the South Atlantic gyre, the North Pacific gyre, the South Pacific gyre, and the Indian Ocean gyre. Gyres are important for several reasons.

First, they play a crucial role in the ocean's circulation, helping to distribute heat and nutrients around the planet. Second, they are also responsible for transporting large amounts of plastic and other debris across the ocean, leading to the formation of oceanic garbage patches.

Finally, gyres can have a significant impact on regional weather patterns, influencing both temperature and precipitation. Gyres are the name used for the series of interacting circular surface currents in the ocean. They are complex systems of oceanic circulation that are crucial for regulating the planet's climate and weather patterns.

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Which is an example of why impuise is so important?
Elevators being hoisted up by a pulley
Using nylon ropes in rock climbing
Running a race around a track
Plane taking off from a runway

Answers

Impulse is important because it is the force that changes an object's momentum.

What is momentum?

Momentum is a physical concept that describes the movement of an object due to the product of its mass and velocity. Momentum is a vector quantity, meaning it has both a magnitude and a direction. In classical mechanics, momentum is conserved, meaning that the total momentum of a system remains constant over time.

In the examples given, impulse is what allows the elevator to be hoisted up, the nylon ropes to hold a climber's weight, the runner to move around the track, and the plane to take off from the runway. Without impulse, none of these activities would be possible.

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