List a value of b that will cause 4x2 + bx + 25 = 0 to have one real solution

Based on the results of the hypothesis test, we can say that a batch containing 1.80% zinc phosphide indicates that there is too little zinc phosphide in this production.

Based on the information provided, the chemical company produces a substance that contains 2% zinc phosphide for controlling rat populations in sugarcane fields. The production must be carefully controlled to ensure that the substance contains exactly 2% zinc phosphide. Records from past production indicate that the actual percentage of zinc phosphide present in the substance is approximately mound-shaped with a mean of 2.0% and a standard deviation of .08%.
Suppose one batch chosen randomly actually contains 1.80% zinc phosphide. This may or may not indicate that there is too little zinc phosphide in this production. To determine whether the batch contains too little zinc phosphide, we can perform a hypothesis test.
The null hypothesis in this case is that the batch contains exactly 2% zinc phosphide, and the alternative hypothesis is that the batch contains less than 2% zinc phosphide. We can use a one-tailed z-test to test this hypothesis.
Calculating the z-score for a batch with 1.80% zinc phosphide, we get:
z = (1.80 - 2.00) / 0.08 = -2.5

Using a standard normal distribution table, we can find that the probability of getting a z-score of -2.5 or lower is approximately 0.006. This means that if the batch truly contains 2% zinc phosphide, there is only a 0.006 probability of getting a sample with 1.80% zinc phosphide or less. Assuming a significance level of 0.05, we reject the null hypothesis if the p-value is less than 0.05. Since the p-value in this case is less than 0.05, we can reject the null hypothesis and conclude that there is evidence that the batch contains less than 2% zinc phosphide.

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3/8 is smaller than 3/5.

3/8 is smaller than 3/5

Find the LCD of both fractions:

Multiples of 8:

8, 16, 24, 32, 40, 48, 56, 64, 72, …

Multiples of 5:

5, 10, 15, 20, 25, 30, 35, 40, 45, …

40 is the LCD of denominators 5 and 8.

Multiply both denominators by a number that makes it 40, multiply that same number by each numerator:

3/8:

3 x 5 = 15

8 x 5 = 40

15/40

3/5:

3 x 8 = 24

5 x 8 = 40

24/40

15/40 < 24/40

Hope this helps

Answer: It's the first one

Also could you mark my answer as brainliest? It helps and doesnt hurt

The equation for the hyperbola with foci (0,±5) and asymptotes y=± 3/4 x is:

y^2 / 25 - x^2 / a^2 = 1

where a is the distance from the center to a vertex and is related to the slope of the asymptotes by a = 5 / (3/4) = 20/3.

Thus, the equation for the hyperbola is:

y^2 / 25 - x^2 / (400/9) = 1

or

9y^2 - 400x^2 = 900

The center of the hyperbola is at the origin, since the foci have y-coordinates of ±5 and the asymptotes have y-intercepts of 0.

To graph the hyperbola, we can plot the foci at (0,±5) and draw the asymptotes y=± 3/4 x. Then, we can sketch the branches of the hyperbola by drawing a rectangle with sides of length 2a and centered at the origin. The vertices of the hyperbola will lie on the corners of this rectangle. Finally, we can sketch the hyperbola by drawing the two branches that pass through the vertices and are tangent to the asymptotes.

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The risk premium of a given stock by the mathematical expression "rm - rf," where "rm" represents the expected return of the market and "rf" represents the risk-free rate. The correct option would be A. rm - rf.

The risk premium of a stock refers to the additional return that an investor expects to earn above the risk-free rate in order to compensate for the higher risk associated with investing in the stock market. This risk premium reflects the extra return that investors demand for taking on the additional risk of investing in stocks rather than risk-free assets like government bonds.

In the provided expression, "rm - rf," the term "rm" represents the expected return of the overall market, and "rf" represents the risk-free rate. By subtracting the risk-free rate from the expected market return, we obtain the difference between the two, which represents the compensation for bearing the additional risk of investing in stocks.

Essentially, "rm - rf" captures the excess return that investors anticipate from investing in the stock market compared to the guaranteed return of a risk-free asset. This difference, or premium, serves as a measure of the compensation for taking on the higher risk associated with stock investments.

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(a) Complex zeros of a polynomial come in pairs.

If a + bi is a zero of a polynomial then its conjugate a - bi is also a zero of the polynomial.

The given complex zeros of R(x) are 1 + 3i and -2i.

1 - 3i is the conjugate of 1 + 3i.

Hence, another zero of R(x) is 1 - 3i

b)

Since the polynomial R(x) is of order 13 then R(x) must have 13 zeros.

The given complex zeros of R(x) are 1 + 3i and -2i. We also know that the conjugates of 1 + 3i and -2i are zeros of R(x). Hence, R(x) has at least 4 complex roots

Hence, the maximum number of real zeros of R(x) is (13 -4).

The maximum number of real zeros of R(x) is 9

c) Let the maximum number of nonreal zeros (complex roots) be n

Complex roots come in pairs. Therefore, n must be even.

Hence, n ≤ 13 - 1 = 12

n ≤ 10

We have been given a real zero of R(x), 3 ( With the multiplicity of 4).

12 - 4 = 8

Therefore,

n ≤ 8.

Hence the maximum number of nonreal zeros of R(x) is 8

The volume of gasoline in the cylindrical tank is increasing at 23.56 ft.³/sec when the depth of the gasoline in the tank is 6 feet. Computed using differentiation.

Since the tank is cylindrical in shape, its volume can be written as:

V = πr²d,

where V is its volume, r is the radius, and d is the depth.

The radius is constant, given r = 5ft.

Thus the volume can be shown as:

V = π(5)²d,

or, V = 25πd.

Differentiating this with respect to time, we get:

δV/δt = 25πδd/δt ... (i),

where δV/δt, represents the rate of change of volume with respect to time, and δd/δt represents the rate of change of depth with respect to time.

Now, we are given that when the depth increases at 0.3 ft./sec when the depth of the gasoline is 6 feet.

Thus, we can take δd/δt = 0.3 ft./sec, in (i) to get:

δV/δt = 25πδd/δt = 25π(0.3) ft.³/sec = 23.56 ft.³/sec.

Thus, the volume of gasoline in the cylindrical tank is increasing at 23.56 ft.³/sec when the depth of the gasoline in the tank is 6 feet. Computed using differentiation.

The question written correctly is:

"Gasoline is pouring into a vertical cylindrical tank of radius 5 feet. When the depth of the gasoline is 6 feet, the depth is increasing at 0.3 ft./sec. How fast is the volume of gasoline changing at that instant?"

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Answer: 37.5 or 0.375

Step-by-step explanation:

to write 45/120 as a decimal you have to divide the numerator by the denominator of the fraction. we divide now 45 by 120 what we write down as 45/120 and get 0.375

Hope this helped!

Answer:

The final answer is "$2387.85 and $2594.85".

Step-by-step explanation:

Given values:

The bank statement balance= $2,253.18

The checkbook balance = $2,324.34

outstanding check amounts= $105.50 and $158.10

transit amount= $605.27

account earnin(credits)= $68.51

service charge= $5.00

Adjusted Checkbook Balance =?

Adjusted  Statement Balance=?

Adjusted the Checkbook Balance:

checkbook balance = $2,324.34

\(\text{total checkbook balance = checkbook balance+ credits}\\\)

                                      \(= \$ 2,324.34+ \$ 68.51\\\\= \$ 2392.85\)

\(\text{ Adjust check book balance= total checkbook balance - servicec charge}\)

                                         \(= \$2392.85 - \$5.00\\\\= \$ 2387.85\)

Adjusted the Statement Balance:

bank statement balance= $2,253.18

\(\text{total Statement balance = bank Statement balance+ transit amount}\\\)

                                      \(= \$ 2,253.18+ \$ 605.27\\\\= $ 2,858.45\)

\(\text{outstanding check amounts = $105.50+ $158.10}\)

                                           \(= \$263.60\)

\(\text{ Adjust statement balance= total statement balance - outstanding check amount }\)                                        \(= \$ 2,858.45 - \$263.60\\\\= $ 2,594.85\)

Answer:

700

Step-by-step explanation:

Answer:

the answer is 900 students

Step-by-step explanation:

if there are 5 parts to the ratio then take that and divide it by the total number of learners and then multply it by the ratio for the boys

Answer:

No

Step-by-step explanation:

No, it is not because the 3 dollars is a steady price. A expression will look like 7n+3. Since the 3 dollars is a steady price you can never have a unit rate.

Answer:

It's proportional

Step-by-step explanation:

10-3=7  7/1 = 7

17 - 3= 14 1 4/2 = 7

31 - 3 = 28 28/4 = 7

38 -3 = 35 35/5 = 7

73 - 3 = 70 70/10 = 7

A firm experiences increasing returns to scale if inputs are doubled and output more than doubles.

When the firm's output grows at a faster rate than the growth in inputs, increasing returns to scale result. In this case, the company experiences economies of scale, which makes it more effective as it grows its production.

The firm is able to boost productivity and efficiency as it expands its scale of operations if inputs are doubled and output more than doubles.

This can be ascribed to a number of things, including specialisation, labour division, the use of capital-intensive technology, discounts for bulk purchases, and spreading fixed costs over a higher output. Lower average costs per unit of output result in higher profitability and competitiveness for the company.

The firm gains a number of benefits from growing returns to scale. First off, it lets the company to benefit from cost savings brought about by economies of scale, allowing it to manufacture goods or services for less money per unit. This may enable more competitive pricing on the market or result in larger profit margins.

Second, raising returns to scale can result in better operational effectiveness and resource utilisation. As the company grows in size, it will be able to use resources more wisely and profit from production volume-related synergies.market prices that are competitive.

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Answer:

B.

Step-by-step explanation:

Since 6 = 5r + 1, r = 1

As for s, if s is 2, then you can do

4 x 2 + 5 = 13 & 6 x 2 + 1 = 13

13 = 13

So B!

Hope that helps!

Answer: 1/9

Step-by-step explanation:

The probability of rolling a 2 on the first cube is 1/6.

The probability of rolling a number greater than 2 on the second cube is 2/3.

Multiplying these probabilities yields a final answer of 1/9.

The domain of this function is the set of all nonnegative integers

So, the correct answer is C.

The domain of a function is the set of all possible input values that the function can take.

In this case, the function X + 3f(x) = 30 represents the number of school buses needed to transport students on a field trip, where x represents the number of students going on the trip.

Since the number of students going on the trip can be any nonnegative integer (i.e., 0, 1, 2, 3, ...), the domain of this function is the set of all nonnegative integers.

This is because it wouldn't make sense to have a negative number of students going on the trip, nor would it make sense to have a fraction of a student.

Therefore, the answer to the question is: x is the set of all nonnegative integers. Hence the answer is C.

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The area of the tile which is trapezoid is  70 cm².

A trapezoid is a four-sided geometric shape with one pair of parallel sides.

The two non-parallel sides are usually referred to as the "legs" and the other two sides are the "bases".

A trapezoid can be either isosceles or non-isosceles depending on the angles of the legs.

A trapezoid can also be equilateral if all four sides have equal lengths.

The formula for the area of a trapezoid is (base 1 + base 2) x height/2.

In this case, the base 1 is 3 cm and the base 2 is 6 cm and the height is 4 cm.

Plugging these values into the equation

we get (3 cm + 6 cm) x 4 cm/2 = 70 cm².

Therefore, the area of the tile shown is 70 cm².

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Based on the given information, we can conclude that TUVW is a rhombus.

A rhombus is a quadrilateral with all four sides of equal length. Given that TU = UV = VW = WT, we can confirm that all sides of TUVW are equal. Additionally, the fact that the diagonals intersect at right angles (UV IVW, and VW IWT) tells us that TUVW is not just any rhombus, but a special kind of rhombus known as a square.

Therefore, TUVW is a square, which is a special type of rhombus, so it also has all the properties of a rhombus. In addition, it is also a parallelogram and a rectangle, since it has all the properties of those shapes. However, it is not a trapezoid, as a trapezoid has at least one pair of parallel sides, which TUVW does not have.

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The distance between the center and the point is equal to the radius, the point (−15, −4) is on the circle.

To solve this problem, we need to use the distance formula to find the distance between the center of the circle and the point on the circle. If this distance is equal to the radius of the circle, then we know that the point is on the circle.

The distance formula is:

\(d = \sqrt{((x2 - x1)^2 + (y2 - y1)^2)}\)

where (x1, y1) is the center of the circle, (x2, y2) is the point on the circle, and d is the distance between them.

Plugging in the values we have:

\(d = \sqrt{((-15 - (-9))^2 + (-4 - 0)^2)} \\d = \sqrt{((-6)^2 + (-4)^2)} \\d = \sqrt{(36 + 16)} \\d = \sqrt{(52)}\)

Now we need to find the radius of the circle. Since we know the center of the circle, we can use the distance formula to find the distance between the center and any point on the circle. We already found the distance between the center and the given point, so we can use that:

\(radius = \sqrt{(52)}\)

Now we can check if the point (−15, −4) is on the circle by comparing its distance to the center with the radius:

\(d = \sqrt{((-15 - (-9))^2 + (-4 - 0)^2)} \\d = \sqrt{((-6)^2 + (-4)^2)} \\d = \sqrt{(36 + 16)} \\d = \sqrt{(52)}\)

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The center of a circle is located at the point ( − 9 , 0 ) . the point ( − 15 , − 4 ) is located on the circle.Given a circle with its center at point (-9, 0), we need to find the circle's equation, knowing that point (-15, -4) lies on the circle.

Step 1: Find the radius
To find the radius, we need to calculate the distance between the center and the point on the circle:

Distance formula: √((x2 - x1)² + (y2 - y1)²)
Center: (-9, 0)
Point on circle: (-15, -4)

Radius = √((-15 - (-9))² + (-4 - 0)²) = √(6² + 4²) = √(36 + 16) = √52

Step 2: Write the equation of the circle
The general equation of a circle is (x - a)² + (y - b)² = r², where (a, b) is the center, and r is the radius.

Equation: (x - (-9))² + (y - 0)² = (√52)²
Simplified equation: (x + 9)² + y² = 52

So, the equation of the circle with center (-9, 0) and a point (-15, -4) on the circle is (x + 9)² + y² = 52.

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A triangle's opposite side is split in half by an angle bisector into two segments that are proportional to the other two sides.

We can solve this problem by using the formula explained in the angle bisector theorem below.

Angle Bisector theorem :

            In the below image, PS is the angle bisector of ∠P in ΔPQR.

As a result, we can state that by using the angle bisector theorem as

PQ/PR = QS/SR

or

a/b = x/y.

By this, we can solve the angle bisector theorem.

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Answer:

10

Step-by-step explanation:

5 outside the star 5 inside the star

As the consumption rate of 1997  estimated 2,000 billion barrels of oil last in 74.34 approx 75 year .

As here the rate of 1997 is not given which will be find in the below link which is 73.7000 millions barrels per day was the consumption of oil. here we have awalible the data of per days and we have to calculate for year so in year 1997 there was 365 days  so comsumption of oil yearly was .

1997 consumption = 73.700 million barrels per day

so for 1 year 73.700 million *365 =26,900.5 million barrels per day

her we find the rate of yearly so by this rate we will calculate the consumption of 2000 billion barrels of oil

2000 billion = 2,000,000 millions

here we are calculation this in million

so for 2,000,000 million will be

2,000,000 million /26,900.5 million =74.34 year

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Answer:

1- 50

2-49

3-22

Step-by-step explanation:

just add the sides that you have and then subtract the sum by 90 becasue theu are right triangles

1) To find the optimum quantities of X and Y that the consumer will purchase, we need to consider two conditions: the budget constraint and the utility maximization. The budget constraint can be expressed as Px*X + Py*Y = Income. Given that Px = 1, Py = 2, and Income = 300, the budget constraint becomes X + 2Y = 300. To maximize utility, we need to find the combination of X and Y that maximizes the utility function U = X*Y^2  Taking the derivative of U with respect to X and Y, we get dU/dX = Y^2 and dU/dY = 2XY. Setting dU/dX equal to the marginal rate of substitution (MRS), which is the ratio of prices (MRS = Px/Py), we have Y^2 = 1/2. Rearranging, we get Y = 1/sqrt(2). Setting dU/dY equal to the MRS, we have 2XY = 1/2. Substituting Y = 1/sqrt(2), we get X*(1/sqrt(2)) = 1/2. Solving for X, we find X = sqrt(2)/2. Therefore, the optimum quantities of X and Y that the consumer will purchase are X = sqrt(2)/2 and Y = 1/sqrt(2). 2) This combination of X and Y is an equilibrium in the sense that it maximizes the consumer's utility given the budget constraint and the prices of the goods. It represents the point where the consumer allocates their income between X and Y in a way that maximizes their overall satisfaction, taking into account the relative prices of the goods.

3) To find the maximum satisfaction, we substitute the optimum quantities of X and Y into the utility function. The maximum satisfaction is given by U = X*Y^2 = (sqrt(2)/2) * (1/sqrt(2))^2 = 1/2. Therefore, the maximum satisfaction that this utility-maximizing consumer can achieve is 1/2. 4) On the diagram, we can plot X on the x-axis and Y on the y-axis. The budget constraint can be represented by the line X + 2Y = 300. The optimum combination of X and Y, given by X = sqrt(2)/2 and Y = 1/sqrt(2), can be shown as a point on the diagram. Note: Unfortunately, as a text-based AI, I am unable to provide a visual diagram.

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To set up the artificial variable LP (Phase I LP) for the given problem, we introduce an artificial variable, LP, to the objective function with a coefficient of 1. The artificial variable is used to identify infeasible solutions.

To set up the artificial variable LP (Phase I LP), we modify the objective function as follows:

Maximize Z = 4x1 + 7x2 + x3 + LP

The artificial variable LP is introduced to the objective function with a coefficient of 1. This allows us to track its value during the iterations.

The initial constraints remain the same:

2x1 + 3x2 + x3 = 20

3x1 + 4x2 + x3 + x4 = 40

8x1 + 5x2 + 2x3 - x5 = 70

The initial basic variables (BV) are the slack variables corresponding to the equality and inequality constraints, namely, x3 and x4. The artificial variable LP is initially a non-basic variable.

The initial artificial variables' basic variable (BVB) values are set to the right-hand side values of the constraints:

x3 = 20

x4 = 40

The initial artificial variable LP's value is set to 0.

Next, the artificial variable LP is selected as the entering variable, as it has a positive coefficient in the objective function. To determine the leaving variable, we perform the ratio test using the ratios of the right-hand side values and the entering column values (coefficients of LP) for the respective constraints.

The leaving variable is determined based on the minimum ratio, ensuring that the corresponding row represents a valid pivot element. If no valid pivot element is found, the problem is infeasible.

This completes the setup of the artificial variable LP (Phase I LP) without performing a complete pivot. Further steps would involve applying the simplex method and iteratively pivoting to find the optimal solution or identify infeasibility.

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First pump can fill the tank in 4 hours. So, In 1 hour it fill 1/4 of the tank.

Second pump 1/3

Third one, 1/4

If three pumps are used at the same time, then in 1 hour they will fill

1/4 + 1/3 + 1/4 = 5/6

Therefore tank will be full = 1 ÷ 5/6 = 1.2 hours or 1 hour and 12 minutes

Answer: 60 inches

Step-by-step explanation:

The general formula for the lateral surface area of a regular pyramid is L.S.A.=1/2pl

where p represents the perimeter of the base and l the slant height.

Find the lateral surface area of a regular pyramid with a triangular base if each edge of the base measures 8 inches and the slant height is 5  inches.

The perimeter of the base is the sum of the sides.  p =3(8) = 24  inches

L.S.A.= 1/2( 24) (5 )= 60  inches^2

Answer:

224 hr

Step-by-step explanation:

Answer:

9/5

Step-by-step explanation:

because I know I pass the test

Answer:

If I am doing this correctly it should be 58

Step-by-step explanation:

VF=36 so VN/FN = 13

EI = 42 so EN/IN = 21

EF = 24 so VI = 24 (Parallel)

13 + 21 + 24 = 58

By the pigeonhole principle, there must be at least two people at the party.

What is pigeonhole principle?

The pigeonhole principle is a fundamental concept in mathematics that states that if there are n items and k containers, and n > k, then at least one of the containers must contain more than one item.

This is an example of the pigeonhole principle. The pigeonhole principle states that if you have n pigeons and fewer than n pigeonholes, then there must be at least one pigeonhole with more than one pigeon in it.

In this case, we have 19 people and only 18 possible pigeonholes (since you cannot put two people in the same spot).

Therefore, by the pigeonhole principle, there must be at least one pigeonhole (i.e., a spot at the party) with more than one pigeon (i.e., more than one person). In other words, there must be at least two people at the party.

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