Lisa invested $2500 in a bank account. The account has an annual interest rate of 3.5%. How much money will be in the account after 15 years? Use the formula A(t) = P*e^rt to solve the problem. (round to the nearest hundredth)​

Answer:

The answer would be 4+0.15d.

Step-by-step explanation:

I hope this helps! :) I am so sorry if this is not right!

The required  cost of each shirt is $21.28.

A mathematical statement known as an equation is made up of two expressions joined together by the equal symbol. A formula would be 3x - 5 = 16, for instance. When this equation is solved, we discover that the value of the quantity x is 7.

The total cost of 3 identical shirts, including shipping, is $71.83. So we can write the equation as:

3s + 7.99 = 71.83

To solve for the cost of each shirt, we need to isolate the variable "s" on one side of the equation. We can start by subtracting 7.99 from both sides:

3s = 63.84

Then, we can divide both sides by 3:

s = 21.28

Therefore, the cost of each shirt is $21.28.

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Answer:

f(x)=|1/2x|

Step-by-step explanation:

Answer:

y=l(1/4)x + (1/2)l

Step-by-step explanation:

When shifting non-linear functions to the left or right, you must put the opposite operation inside the parenthesis. This means when you move to the left, your number must be positive. If you move to the right, your number must be negative. In this scenario, we want to shift the graph to the left 2 units. However, because our m value is a fraction, the shifting vale must also be a fraction. So instead of 2, the value becomes (1/2). Putting this all together, your answer is y=l(1/4)x + (1/2)l

The value of x1 and x2 in the given triangle is 11.28 and 3.70 respectively.

The first six functions are trigonometric, with the domain value being the angle of a right triangle and the range being a number. The angle, expressed in degrees or radians, serves as the domain and the range of the trigonometric function (sometimes known as the "trig function") of f(x) = sin. The domain and range of the other functions are similar. In calculus, geometry, and algebra, trigonometric functions are often utilised.

The value of x1 and x2 can be determined using the trigonometric identity that relates the adjacent side and hypotenuse.

Cos (a) = adjacent side / Hypotenuse

Cos (27.3) = x1/ 12.7

0.88(12.7) = x1

x1 = 11.28

Now, the trigonometric identity that relates the opposite side and hypotenuse is sine function.

Thus,

sin (19.2) = x2 / 11.28

0.32(11.28) = x2

x2 = 3.70

Hence, the value of x1 and x2 in the given triangle is 11.28 and 3.70 respectively.

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Answer:

Step-by-step explanation:

5

Answer:

30cm

Step-by-step explanation:

The formula for volume of a sphere is \(\frac{4}{3} \pi r^2\). If \(\frac{4}{3} \pi r^2=36000\pi\) then r=30.

An increase in the rate of inflation will increase the nominal interest rate while lowering the real interest rate.

When the rate of inflation rises, it affects both the nominal and real interest rates. The nominal interest rate is the stated or observed interest rate, while the real interest rate is adjusted for inflation and represents the purchasing power of the interest earned or paid. Inflation erodes the purchasing power of money over time.

As inflation increases, lenders and investors demand higher nominal interest rates to compensate for the expected loss in purchasing power. However, while the nominal interest rate rises, the real interest rate, which takes inflation into account, decreases because the purchasing power of the interest earned or paid is reduced.

In summary, an increase in the rate of inflation will result in an increase in the nominal interest rate but a decrease in the real interest rate due to the erosion of purchasing power caused by inflation.

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Answer:

2w + 6

Step-by-step explanation:

Basically, an equivalent expression means the same equation in a different form. Here, we are asked to write an equivalent expression by combining like terms.

1.  W + 10 + W - 4

2. 2W + 6

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To determine the optimal order quantity for Rocky Mountain Tire Center, you must consider ordering costs, storage costs, and the purchase price of the tires. The order quantity should minimize the total cost including both ordering cost and storage cost.

The EOQ formula is given by: EOQ = √((2DS) / H)

Where: D = Annual demand (7,000 go-cart tires)

S = Ordering cost per order ($40) H = Holding cost - percentage of the purchase price (40% of the purchase price)

we need to determine the purchase price per tire based on the quantity ordered.

EOQ = √((2 * 7,000 * 40) / (0.4 * 15))

=118 tires

they should order approximately 118 tires.

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Answer:

I think its 12

Step-by-step explanation:

First. find the prime factorization of 108

Second. find the prime factorization of 300

Third. To find the GCF, multiply all the prime factors common to both numbers: So therefore its 12

Answer:

5(2x-3)-7x=x-10

or, 10x -15 -7x = x-10

or, 3x-15=x-10

or, 3x- x = 15-10

or, 2x = 5

or, x= 5/2

The  probability that a product will operate properly within an expected time frame is the dimension of quality known as reliability

The probability is the ratio of the number of favorable outcomes to the total number of outcomes. The value of the probability is varies from zero to one

Here, the product will operate properly within an expected time frame is the dimension of quality

Reliability is expressed as the probability that a given item will perform its intended function with no failures for a given period of time under a given set of conditions that means the reliability is the complementary to the failure of probability

Therefore, the given statement is know as the reliability

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The completed table:

                                  Die

                     1          2          3         4          5        6

 Head      H - 1     H - 2    H - 3   H - 4   H - 5    H - 6

  Tail        T - 1      T - 2    T - 3    T - 4    T - 5   T - 6

We have,

The set of all possible outcomes when rolling the die and flipping the coin is the sample space.

The total number of outcomes.

= 6 x 2

= 12 outcomes.

Each cell in the table will represent one possible outcome.

Here's the completed table:

                                  Die

                     1          2          3         4          5        6

 Head      H - 1     H - 2    H - 3   H - 4   H - 5    H - 6

  Tail        T - 1      T - 2    T - 3    T - 4    T - 5   T - 6

Thus,

The completed table is given above.

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The problem involves calculating the flux of a constant vector field F through the surface of a cone with a specific orientation. The flux is given as F · dA = 1.26. We are then asked to determine the value of the integral F · dA for a different vector field F = ai + tj + czk.

The flux of a vector field through a surface is calculated by taking the dot product of the vector field and the surface's normal vector, and integrating this dot product over the surface. In the given problem, the flux of the constant vector field F through the cone's surface is given as F · dA = 1.26. The integral of F · dA represents the flux through the surface S.

Without further information about the specific orientation of the cone and the shape of the surface S, we cannot determine the value of the integral F · dA. Thus, it is indeterminate.

For the second case, where the vector field F = ai + tj + czk is considered, and the flux through the surface S is again given as F · dA = 1.26, we still lack information about the orientation and shape of the surface. Therefore, the value of the integral F · dA in this case is also indeterminate.

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We have in total 432 students.

8.

We know that 23% of the students want to be a teacher, this means that:

99 students want to be a teacher.

9.

We know that 13% of the students want to be doctor or nurses, this means that 26% of them want to be one of those, then:

112 students want to be doctor or nurses.

10.

Since 9% of the students want to be lawyers, this means that 91% of them did not want to be lawyers, then:

393 students does not want to be lawyers.

Answer:

393 students do not want to be lawyers.

Step-by-step explanation:

A sequence is (recursively) defined as a1 = 0, a2 = 1, n>2, \(a_n = a_{n-1} - 3a_{n-2}\). The first seven terms are 0, 1, 1, -2, -5, 1, 16.

A recursive sequence is a sequence in which terms are defined using one or more previous terms which are given.

a1 = 0

a2 = 1

\(a_n = a_{n-1} - 3a_{n-2}\)

a3 = a2 - 3*a1 = 1 - 0 = 1

a4 = a3 - 3*a2 = 1 - 3 = -2

a5 = a4 - 3*a3 = -2 - 3 = -5

a6 = a5 - 3*a4 = -5 + 6 = 1

a7 = a6 - 3*a5 = 1 +15 = 16

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The yield to maturity on a simple loan for $1,500 that requires a repayment of $7,500 in five years' time is 37.14%.

Yield to maturity (YTM) is the total return anticipated on a bond or other fixed-interest security if the security is held until it matures. Yield to maturity is considered a long-term bond yield, but is expressed as an annual rate. In this problem, the present value (PV) of the simple loan is $1,500, the future value (FV) is $7,500, the time to maturity is five years, and the interest rate is the yield to maturity (YTM).

Now we will calculate the yield to maturity (YTM) using the formula for the future value of a lump sum:

FV = PV(1 + YTM)n,

where,

FV is the future value,

PV is the present value,

YTM is the yield to maturity, and

n is the number of periods.

Plugging in the given values, we get:

$7,500 = $1,500(1 + YTM)5

Simplifying this equation, we get:

5 = (1 + YTM)5/1,500

Multiplying both sides by 1,500 and taking the fifth root, we get:

1 + YTM = (5/1,500)1/5

Adding -1 to both sides, we get:

YTM = (5/1,500)1/5 - 1

Calculating this value, we get:

YTM = 0.3714 or 37.14%

Therefore, the yield to maturity on a simple loan for $1,500 that requires a repayment of $7,500 in five years' time is 37.14%.

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Answer: The answer is C: \(17\sqrt{13}\)

Step-by-step explanation: Since both Radicands have the same, add the indexes together to get 17

Answer:

m∠D = 49°
m∠E = 41°
m∠F = 90°

Step-by-step explanation:

        We know a triangle's angles add up to 180, so we can create an equation and solve for x. We also know the little box represents 90 degrees.

Given:

        90° + 5x° + 14° + 3x° + 20° = 180°

Combine like terms:

        8x° + 124° = 180°

Subtract 124 from both sides of the equation:

        8x° = 56°

Divide both sides of the equation by 8:

        x = 7

        Now, we will plug this value of x back into the angles to solve. Again, the little box represents that Angle F is equal to 90 degrees.

m∠D = 5x° + 14° = 5(7)° + 14° = 49°
m∠E = 3x° + 20° = 3(7)° + 20° = 41°
m∠F = 90°

The total cost of the meal, including tax and tip, is approximately $18.87.

To calculate the total cost of the meal, including tax and tip, we'll follow these steps:

Step 1: Calculate the tax amount.

Tax amount = 9% of the bill amount before tax

Tax amount = 0.09 × $15

Step 2: Calculate the bill amount after tax.

Bill amount after tax = Bill amount before tax + Tax amount

Step 3: Calculate the tip amount.

Tip amount = 14% of the bill amount after tax

Tip amount = 0.14 × (Bill amount before tax + Tax amount)

Step 4: Calculate the total cost of the meal.

Total cost = Bill amount before tax + Tax amount + Tip amount

Let's compute the values:

Step 1:

Tax amount = 0.09 × $15 = $1.35

Step 2:

Bill amount after tax = $15 + $1.35

= $16.35

Step 3:

Tip amount = 0.14 × ($15 + $1.35)

= $2.519

Step 4:

Total cost = $15 + $1.35 + $2.519

≈ $18.87

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The mean of the first set is 8.67

The mean of the second set is 8

The mean of the third set is 16.43

The mean of the fourth set is 23.13.

Compute for the sum of the given numbers in each set.

Divide the sum computed in step 1 by the total number of values in each set (count the values).

The resulting quotient is the mean of the respective set of numbers.

A. Computing for the Mean of a Sample

Given Mean 3, 4, 9, 11, 5

To find the mean of the given set, we need to compute the sum first.

3 + 4 + 9 + 11 + 5 = 32

There are five (5) values in the set, so we divide the sum by 5.32 ÷ 5 = 6.4

Thus, the mean of the first set is 6.4.7, 11, 10, 13, 5, 6

Sum = 52

Count = 6

Mean = 52 ÷ 6 = 8.67

The mean of the second set is 8.67.13, 3, 6, 8, 12, 9, 5

Sum = 56

Count = 7

Mean = 56 ÷ 7 = 8

The mean of the third set is 8.15, 11, 16, 15, 18, 20, 20

Sum = 115

Count = 7

Mean = 115 ÷ 7 = 16.43

The mean of the fourth set is 16.43.21, 23, 25, 19, 15, 26, 27, 29

Sum = 185

Count = 8

Mean = 185 ÷ 8 = 23.13

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To determine which set of data most likely has a mean closest to 29.5, we need to analyze the shape and position of the histograms in relation to the value 29.5.

Looking at the histograms described:

The first histogram ranges from 9 to 48, and the upward trend starts from 1 and ends at 33, followed by a downward trend. This histogram suggests that there may be values lower than 29.5, which would bring the mean below 29.5.

The second histogram ranges from 15 to 48, with an upward trend from 1 to 30 and then a downward trend. Similar to the first histogram, it suggests the possibility of values lower than 29.5, indicating a mean below 29.5.

The third histogram ranges from 12 to 56, and the upward trend starts from 1 and ends at 32, followed by a downward trend. This histogram covers a wider range but still suggests the possibility of values below 29.5, indicating a mean below 29.5.

The fourth histogram ranges from 15 to 54 and exhibits multiple trends. While it has fluctuations, it covers a wider range and includes both upward and downward trends. This histogram suggests the possibility of values above and below 29.5, potentially resulting in a mean closer to 29.5.

Based on the descriptions, the fourth histogram, with its more varied trends and wider range, is most likely to have a mean closest to 29.5.

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The best diagram to use to display data dispersion is a box plot. A box plot is a diagram that shows how a dataset is distributed and helps to identify any outliers.

The diagram that is best at displaying data dispersion is a box plot. Here's the main answer:When there is a need to compare the distribution of data, a box plot is often the best method.

A box plot is a diagram that shows how a dataset is distributed. It shows how data is spread out and helps to identify any outliers. It is most effective for comparing data sets that have a large number of data points and when the data is not normal (not evenly distributed).

A box plot is a great way to summarize large amounts of data and it is also very easy to read and interpret. It shows a number of statistical values, including the median (the middle value of the data set), the quartiles (the values that divide the data set into four equal parts) and the range (the difference between the maximum and minimum values).

Additionally, it can identify any outliers in the data, which are values that are significantly different from the rest of the data.A box plot is created by drawing a rectangle between the first and third quartiles (the middle 50% of the data) with a line drawn inside it to show the median.

Lines are then drawn from the edges of the rectangle to the minimum and maximum values. Any outliers are marked with a point outside of the rectangle.

The box plot is a great way to compare data sets and to visualize the dispersion of the data

The best diagram to use to display data dispersion is a box plot. A box plot is a diagram that shows how a dataset is distributed and helps to identify any outliers. It is most effective for comparing data sets that have a large number of data points and when the data is not normal. A box plot is created by drawing a rectangle between the first and third quartiles with a line drawn inside it to show the median.

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Answer:

0.40x=1900

Step-by-step explanation:

The degrees of freedom for the numerator is  2. The df for the denominator is 54

For a one-way ANOVA with k groups and n observations per group, the degrees of freedom (df) for the numerator and denominator are calculated as follows:

The df for the numerator is k - 1, which represents the number of groups minus one.

The df for the denominator is N - k, which represents the total number of observations minus the number of groups.

In this case, there are 3 groups and each group has n = 19 observations, so the total number of observations is N = 3 x 19 = 57. Therefore:

The df for the numerator is 3 - 1 = 2

The df for the denominator is 57 - 3 = 54

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The value of y co-ordinate of point Q is found to be -20 or 10 by using the distance formula.

Given: Points P and Q are separated by 17 units. The coordinates of point P are (5, 5) and point Q are (-3,y).

Using the distance formula,

PQ = \(\sqrt{(x_{2}-x_{1})^2 - (y_{2}-y_{1})^2}\)

17   = \(\sqrt{(-3-5)^2 - (y-(-5))^2}\)

17  = \(\sqrt{-8^2-(y+5)^2}\)

17²  = 64 - y² +25 +10y

289-64-25 = - y² + 10y

y² + 10y - 200 = 0

On solving the quadratic equation we get,

y = -20, 10

Therefore, the value of y co-ordinate of point Q is found to be -20 or 10 by using the distance formula.

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Answer:

The answer is 441190

You just have to multiply 10 with 44119 and then you get 441190

(10 • 44119 = 441190)

To solve for the Marshallian demands x1(p1, p2, m) and x2(p1, p2, m) in the consumer problem with utility function U(x1, x2) = min{x1, ax2}, we need to maximize the utility subject to the budget constraint p1x1 + p2x2 ≤ m, where p1 and p2 are the prices of goods 1 and 2 respectively, and m is the consumer's income.

To find the Marshallian demands, we need to solve the consumer's optimization problem. The objective is to maximize the utility function U(x1, x2) = min{x1, ax2} subject to the budget constraint p1x1 + p2x2 ≤ m.

The first step is to set up the Lagrangian function:

L(x1, x2, λ) = min{x1, ax2} + λ(m - p1x1 - p2x2)

Next, we take the first-order conditions by differentiating the Lagrangian with respect to x1, x2, and λ, and setting the derivatives equal to zero. This will give us the equations for the optimal values of x1, x2, and the Lagrange multiplier λ.

By solving these equations, we can find the specific values for x1(p1, p2, m) and x2(p1, p2, m) that maximize the utility function while satisfying the budget constraint. The resulting demands will depend on the prices (p1, p2) and the consumer's income (m).

Note that the specific calculations involved in solving the optimization problem can be quite involved and may require further mathematical manipulation.

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