Liquid hydrogen peroxide, an oxidizing agent in many rocket fuel mixtures, releases oxygen gas on decomposition:
2H₂O₂(l) → 2H₂O(l) + O₂(g) ΔH = -196.1kj How much heat is released when 652 kg of H₂O₂ decomposes?

Alcoholic fermentation involves the breakdown of pyruvate into ethanol and carbon dioxide.

Alcoholic fermentation is a metabolic process carried out by some microorganisms, including yeast. During this process, glucose or other sugars are converted into ethanol and carbon dioxide.

The first step of alcoholic fermentation is glycolysis, where glucose is converted into pyruvate. In the absence of oxygen, pyruvate undergoes further metabolism through alcoholic fermentation.

In this process, pyruvate is broken down into ethanol and carbon dioxide.

The breakdown of pyruvate into ethanol and carbon dioxide involves several enzymatic reactions.

One of the key enzymes involved is pyruvate decarboxylase, which removes a carboxyl group from pyruvate, resulting in the release of carbon dioxide.

The resulting acetaldehyde is then reduced to ethanol by the enzyme alcohol dehydrogenase, with the concomitant conversion of NADH to NAD+. This allows NAD+ to be regenerated, which is essential for the continuation of glycolysis.

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The water retained by some salts when isolated by evaporation is called water of hydration. Salts that contain water of hydration are called hydrates.

Water of hydration is also called water of crystallization. It is the water that remains inside the framework of the salt or crystal after evaporation and can only be removed by heating, but by doing this, one risks losing the structure of the crystal.

An example of a hydrate is copper tetraoxosulphate (VI). When hydrated, it becomes copper tetraoxosulphate (VI) pentahydrate. When it is without its water of hydration, it has a white colour but when it is hydrated, it is blue in colour.

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Answer: I guess have to like explain to her why to not stick the fork into the toaster.

Explanation:

Hope this helps

Answer:

its just how would you explain how it happens how the electricity passes through the fork but in a easy understandable way

Explanation:

for example... dont do that because......................then will go through the fork then to your arm and will cause....................... then you die

During the oxidative phosphorylation of cellular respiration, hydrogen can be considered as a reducing agent because it loses electrons while molecular oxygen is an oxidizing agent because it accepts electrons.

Reducing and oxidizing agents are different molecules that accept and donate electrons in chemical redox reactions such as oxygen which accept and hydrogen which donates.

Therefore, with this data, we can see that reducing and oxidizing agents are related and they work together to move electrons in different redox reactions such as occur during cellular respiration.

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ANSWER

The arrow will be shifted to the right (OPTION B)

EXPLANATION:

Firstly, we need to write out the chemical reaction equation

From the reaction above, you will see that heat is one of the products, this means that the reaction is n exothermic reaction.

An exothermic reaction is a type of reaction in which heat is released to its surroundings.

In an exothermic reaction, a decrease in temperature will shift the equilibrium to the right

A reaction in which reduction and oxidation take place simultaneously known as a redox reaction.

To calculate the standard Gibbs free energy change (ΔG°rxn) for the given reaction, we can use the equation:ΔG°rxn = ΔH°rxn - TΔS°rxn, Given: ΔH°f (kJ/mol) values:HNO3(aq): -207.0 kJ/mol, NO(g): 91.3 kJ/mol, NO2(g): 33.2 kJ/mol and H2O(l): -285.8 kJ/mol.

S° (J/mol∙K) values:

HNO3(aq): 146.0 J/mol∙K

NO(g): 210.8 J/mol∙K

NO2(g): 240.1 J/mol∙K

H2O(l): 70.0 J/mol∙K

Let's calculate the ΔH°rxn:

ΔH°rxn = [3 × ΔH°f(NO2(g))] + [ΔH°f(H2O(l))] - [2 × ΔH°f(HNO3(aq))] - [ΔH°f(NO(g))]

ΔH°rxn = [3 × 33.2 kJ/mol] + [-285.8 kJ/mol] - [2 × (-207.0 kJ/mol)] - [91.3 kJ/mol]

ΔH°rxn = 99.6 kJ/mol - 285.8 kJ/mol + 414.0 kJ/mol - 91.3 kJ/mol

ΔH°rxn = 136.5 kJ/mol

Calculate the ΔS°rxn:

ΔS°rxn = [3 × S°(NO2(g))] + [S°(H2O(l))] - [2 × S°(HNO3(aq))] - [S°(NO(g))]

ΔS°rxn = [3 × 240.1 J/mol∙K] + [70.0 J/mol∙K] - [2 × 146.0 J/mol∙K] - [210.8 J/mol∙K]

ΔS°rxn = 720.3 J/mol∙K + 70.0 J/mol∙K - 292.0 J/mol∙K - 210.8 J/mol∙K

ΔS°rxn = 287.5 J/mol∙K

Now, we can calculate ΔG°rxn using the equation:

ΔG°rxn = ΔH°rxn - TΔS°rxn

If we assume a standard temperature of 298 K, we can substitute the values: ΔG°rxn = 136.5 kJ/mol - (298 K * 0.2875 kJ/mol∙K)

ΔG°rxn = 136.5 kJ/mol - 85.57 kJ/mol

ΔG°rxn ≈ 50.93 kJ/mol

The calculated ΔG°rxn is positive (+50.93 kJ/mol). Therefore, based on the given options, the closest answer is: +50.8 kJ

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Correct option is OC-  Developing a machine to control the rate of a reaction according to engineering

What is engineering?

Engineering is a field that has been performed for thousands of years, but STEM education, which attempts to engage students with science, technology, engineering, and mathematics, includes it as a component.

The Parthenon, Stonehenge, and the Pyramids of Giza, among other places, are instances of engineering. However, modern engineers work in a variety of fields in addition to erecting structures.

Engineers work on a variety of things, including as cell membranes, building materials, prosthetics, increasing the efficiency of engines and vehicles, and creating renewable energy sources.

Correct option is OC-  Developing a machine to control the rate of a reaction according to engineering

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Answer:

the reactants are na and cl2 the products is the combination nacl --the law of conservation of matter keeps reactions balanced. No you would not be adding more atoms that is what the first combo is.  The coefficient 2 stands for 2 atoms of KL

Explanation:

a) 100 + 75 = 175

b) 100- 75 = 25

One possible method of separating 2-methylundecanal and 2-methylundecanoic acid could be based on their different acid-base properties. Acid-base extraction is a technique that takes advantage of the varying solubilities of compounds in different pH environments.

2-methylundecanal is an aldehyde, while 2-methylundecanoic acid is a carboxylic acid. Carboxylic acids are generally more acidic than aldehydes. In an acidic environment, the carboxylic acid can be protonated, forming a positively charged species (an ion) known as a carboxylate. On the other hand, aldehydes do not undergo significant protonation in acidic conditions.

To separate the two compounds, one approach could involve adjusting the pH of the mixture to create a significant difference in the solubility of the acid and the aldehyde. For example, by adding a strong base to the mixture, the pH can be increased to create a basic environment.

In a basic solution, the carboxylic acid (2-methylundecanoic acid) will exist predominantly in its negatively charged carboxylate form, which is more soluble in water due to its increased polarity. In contrast, the aldehyde (2-methylundecanal) will remain uncharged and less soluble in the basic solution.

The mixture can then be subjected to liquid-liquid extraction, where an immiscible organic solvent (such as diethyl ether or dichloromethane) is added. The organic solvent will preferentially extract the less polar, uncharged aldehyde from the basic aqueous solution, while the carboxylate anion remains in the aqueous phase.

After shaking and separating the organic and aqueous layers, the organic layer containing the aldehyde can be recovered. By evaporating the organic solvent, the 2-methylundecanal can be obtained as a purified compound.

This separation method exploits the differences in acid-base properties between the carboxylic acid and the aldehyde to selectively extract one compound from the mixture based on solubility in different pH environments.

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Answer:

true

Explanation:

Because Mercury can be solidified when its temparature us brought to its freezing point. However, when returned to room temparature conditions, mercury does not exist in solid state for long, and returns back to its more common liquid form.

1.47 J/g°C is the specific heat capacity of a 70 g sample of an unknown metal that releases 6700J of heat when it cools from 90 to 25 degrees C.

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

q = mCpΔT

Solve for Cp —> Cp = q/mΔT

q = -6700 J (negative because it released heat)

m = 70 g

ΔT = Final temp - initial temp = 25 - 90 = -65°C

Cp = (-6700 J) ÷ (70 g)(-65°C)

= 1.47 J/g°C

Hence, 1.47 J/g°C is the specific heat capacity of a 70 g sample of an unknown metal that releases 6700J of heat when it cools from 90 to 25 degrees C.

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Answer: The volume occupied by He is 62.4 L

Explanation:

According to ideal gas equation:

\(PV=nRT\)

P = pressure of gas = 0.980 atm

V = Volume of gas = ?

n = number of moles = 2.50 mol

R = gas constant =

T =temperature =\(25.0^0C=(25.0+273)K=298.0K\)

\(V=\frac{nRT}{P}\)

\(V=\frac{2.50mol\times 0.0821 Latm/K mol\times 298.0K}{0.980atm}=62.4L\)

Thus the volume occupied by He is 62.4 L

Answer:

In a metallic substance, electrons are shared among all of the metal atoms in the sample, forming a "sea" of electrons that surrounds the metal ions. This electron sea is responsible for many of the unique properties of metals, including their high conductivity, malleability, and ductility.

The electron sea in a metallic substance allows the metal ions to slide past one another easily, making it easier to deform the metal without breaking it. In contrast, ionic and covalent compounds are held together by strong chemical bonds, which makes it more difficult to deform these materials without breaking the bonds. This is why metals are generally more malleable and ductile than ionic and covalent compounds.

The valence electron determines whether an ionic or covalent bond develops between two atoms.

An atom's outer shell electrons, known as valence electrons, can take a role in the creation of chemical bonds. When two atoms establish a single covalent bond, normally, both atoms contribute one valence electron to create a shared pair.

Ionic bonds, also known as electrovalent bonds, are a type of linkage created in a chemical molecule by the electrostatic attraction of ions with opposing charges. When one atom's valence (outermost) electrons are permanently transferred to another atom, a bond of this kind is created. The one or two and three are lost and gained in ionic bond formation, but particles with four valence electrons are neither lost nor gained. The four electrons are generally shared to form a covalent bond.

Hence, the valence electron decides the type of the bond.

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Answer:

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How does a balanced chemical equation verify the law of conservation of matter?

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According to the Law conservation of matter

Mass can neither be created nor destroyed in a chemical reaction. That is, the total mass of the elements present in the products of a chemical reaction has to be equal to the total mass of the elements present in the reactants. In other words, the number of atoms of each element remains the same, before and after a chemical reaction. Hence, we need to balance the skeletal chemical equation.

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you would need 4 liters of the 70% alcohol solution and 2 liters of the 40% alcohol solution to obtain 6 liters of a 60% alcohol solution.

Let's assume x liters of the 70% alcohol solution and (6 - x) liters of the 40% alcohol solution are mixed. The amount of alcohol in the 70% solution is 0.70x liters, and the amount of alcohol in the 40% solution is 0.40(6 - x) liters. These amounts must add up to the amount of alcohol in the final mixture, which is 0.60 * 6 liters. Setting up the equation: 0.70x + 0.40(6 - x) = 0.60 * 6 ,Simplifying and solving for x: x = 4. Therefore, you would need 4 liters of the 70% alcohol solution and 2 liters of the 40% alcohol solution to obtain 6 liters of a 60% alcohol solution.

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The specific heat capacity of a substance is the amount of energy required to raise the temperature of 1g of the substance by 1K.

Calculating the change in temperature:

By substituting what we are given into the equation to solve for the unknow x we have;

Answer: Energy needed is 449.35J

Answer:

0.638 moles in 63.8g of calcium carbonate

Explanation:

Answer:

The noble gases are the chemical elements in group 18 of the periodic table. They are the most stable due to having the maximum number of valence electrons their outer shell can hold. Therefore they rarely react with other elements since they are already stable

Answer:

3

Explanation:

The polymer chain shown in the question belongs to B) Isotactic polypropylene. Hence the correct answer is option B) "Isotactic polypropylene".

Polypropylene (PP) is a common thermoplastic polymer used in a wide range of applications. Its chemical structure includes a propylene monomer that contains three carbon atoms, making it an olefin. It can exist in three different forms: atactic, syndiotactic, and isotactic. In an isotactic polymer chain, all of the substituents are on the same side of the chain.

This leads to a highly ordered arrangement of the polymer chains, with a crystalline structure that is more tightly packed than either the atactic or syndiotactic forms. As a result, isotactic polypropylene has a higher melting point and is more durable than either of the other forms. The answer is isotactic polypropylene.

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I think the answer is A. I know it's Planet X.

Answer:

0.086

Explanation:

got it on acellus

The mass of the dry solute recovered from the given data is 0.086 g.  Option C

To determine the mass of the dry solute recovered, we need to subtract the mass of the boat from the mass of the boat with the dry solute.

Given the data provided:

Boat Mass: 0.730 g

Boat + Solution: 0.929 g

Boat + Dry: 0.816 g

To find the mass of the dry solute, we subtract the boat mass from the boat + dry mass:

Mass of Dry Solute = (Boat + Dry) - (Boat Mass)

Mass of Dry Solute = 0.816 g - 0.730 g

Mass of Dry Solute = 0.086 g

Therefore, the correct answer is c) 0.086 g.

The mass of the dry solute recovered from the given data is 0.086 g. It is important to note that the mass of the dry solute is obtained by subtracting the mass of the boat from the mass of the boat with the dry solute, as the boat mass represents the weight of the empty boat or container used in the experiment.

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The percent ionization of a 0.15 M formic acid solution in a solution containing 0.11 M potassium formate is 4.88%.

Formic acid (HCOOH) is a weak acid that ionizes in water to form hydrogen ions (\(H^+\)) and formate ions (\(HCOO^-\)). The equilibrium expression for the ionization of formic acid is:

\(HCOOH + H_2O = H_3O^+ + HCOO^-\)

The equilibrium constant for this reaction is the acid dissociation constant (Ka) for formic acid, which is \(1.77 * 10^{-4}\) at 25°C.

When a solution of formic acid is mixed with potassium formate (HCOOK), the formate ions from the salt will react with the hydrogen ions from the acid to form more formic acid molecules. This is known as the common ion effect and results in a decrease in the percent ionization of the weak acid.

To calculate the percent ionization of the formic acid in a solution containing potassium formate, we first need to calculate the initial concentration of formic acid (HCOOH) and formate ions (\(HCOO^-\)) in the solution.

The initial concentration of formic acid can be calculated as follows:

[HCOOH] = 0.15 M

The initial concentration of formate ions can be calculated from the concentration of potassium formate and the stoichiometry of the reaction:

[\(HCOO^-\)] = [HCOOK] = 0.11 M

Next, we can use the equilibrium constant expression to calculate the concentration of hydrogen ions at equilibrium:

\(Ka = [H_3O^+][HCOO^-]/[HCOOH]\)

Solving for [\(H_3O^+\)], we get:

\([H_3O^+] = \sqrt{Ka*[HCOOH]/[HCOO-]}\)

Substituting the values, we get:

\([H_3O^+] = \sqrt{1.77 x 10^{-4} x 0.15/0.11} = 0.00732 M\)

The percent ionization of the formic acid can now be calculated as:

% ionization = [\(H_3O^+\)]/[HCOOH] x 100%

% ionization = 0.00732/0.15 x 100% = 4.88%

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From the Bohr equation for the energy levels of the hydrogen atom, the following quantities can be calculated: energy of an electron, radius of an electron, frequency of light, wavelength of light, and ionization energy.

The energy of an electron in a given energy level (En), where n is an integer greater than or equal to 1.

The radius of an electron's orbit in a given energy level (rn), where n is an integer greater than or equal to 1.

The frequency of light emitted or absorbed when an electron transitions between two energy levels (Ei and Ef), where i and f are integers greater than or equal to 1 and i > f.

The wavelength of light emitted or absorbed when an electron transitions between two energy levels (Ei and Ef), where i and f are integers greater than or equal to 1 and i > f.

The ionization energy required to completely remove an electron from the hydrogen atom, which is equal to the energy required to move an electron from the first energy level (n=1) to an infinite distance away from the nucleus (n=∞).

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--The given question is incorrect, the correct question is

"What quantities can be calculated from the Bohr equation for the energy levels of the hydrogen atom? e = â2.18 Ã 10â18 j (1n2)"--