Lincoln can run at a speed of 3 m/s. How long would it take him to run 200 meters?

Answer:

Final momentum after a head on collision is -2kgm/

Explanation:

  One ball moves to the right and the other moves opposite  and momentum is a vector quantity so that considering the direction

Initial momenta are        P₁=2x3=6kgm/s        P₂=4x(-2)=-8kgm/s      

Final momentum is the vector sum of P(final)= 6-8= -2 kgm/s

The conservation of the momentum allows to find the result of how the astronaut can return to the spacecraft is:

The momentum is defined as the product of the mass and the velocity of the body, for isolated systems the momentum  is conserved. If we define the system as consisting of the astronaut and the evo propellant, this system is isolated and the internal forces become zero. Let's find the moment in two moments.

Initial instant. Astronaut and thrust together.

        p₀ = 0

Final moment. The astronaut now the thruster in the opposite direction of the ship.

       \(m_f\) = m v + M v '

where m is propellant mass and M the astronaut mass.

As the moment is preserved.

       0 = m v + M v ’

      v ’= \(- \frac{m}{M} \ v\)  

We can see that the astronaut's speed is in the opposite direction to the propeller, that is, in the direction of the ship.

The magnitude of the velocity is given by the relationship between the masses.

In conclusion, using the conservation of the momentun we can find the result of how the astronaut can return to the ship is:

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Using Runge-Kutta 2nd order Heun's method, the speed (w) at t = 0.8s is approximately 0.0081.

Given:

Voltage input (V) = 30V

Initial speed (w) = 0

Step size (h) = 0.4s

Time at which speed is to be determined (t) = 0.8s

We need to determine the speed (w) at t = 0.8s using Heun's method.

We have k₁ = f(t₁, W₁) = 0.02 + 0.06w₁ (using the given equation)

At t = 0 and w = 0 (initial conditions), we have:

k₁ = 0.02 + 0.06(0) = 0.02

We have k₂ = f(t₁ + h, w₁ + k₁h) = 0.02 + 0.06(w₁ + 0.02h)

So, at t = 0.4s and w = 0 (initial conditions), we have:

k₂ = 0.02 + 0.06(0.02 * 0.4) = 0.02 + 0.00048 = 0.02048

So, W₂ = w₁ + (k₁ + k₂)(h/2)

   = 0 + (0.02 + 0.02048)(0.4/2)

   = 0.04048(0.2)

   = 0.008096

Therefore, using Runge-Kutta 2nd order Heun's method, the speed (w) at t = 0.8s is approximately 0.0081.

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The complete question is:

The speed of a motor supplied with a voltage input of 30V, assuming the system is without damping, can be expressed as 30 = (0.02)+(0.06)w dt If the initial speed is zero and a step size of h = 0.4 s, determine the speed w at t = 0.8 s by using the Runge-Kutta 2nd order Heun's method. Heun's method: Wi+1=W₁ = w₁ + (-/-^₁ + = -K ₂ ) h where, k₁ = f(t₁, W₁) and k₂ = f(t₁ + h, w₁ + k₁h), the speed (w) at t = 0.8s is approximately 0.0081.

-- Your foot hits the street.

-- Your foot exerts a force down onto e pavement.

-- The pavement exerts an equal force up against your foot. This is the force that stops you from going any farther down.

Answer:

When several resistors are connected in series, the total resistance equals the sum of the individual resistors. In series combination, the current is same through each resistor.

1)   V=  60 volt

Total resistance R = R₁ + R₂

                              = 20 + 10

                              = 30 Ω

2) Ohms law states that,

           \(\sf I =\dfrac{V}{R}\\\\\\I = \dfrac{60}{30}\\\\I = 2 \ A\)

3) Voltage around 10 Ω resistor,

          V₂ = I R₂

             = 2 * 10

              = 20 volt

___________________________________________________

4) Total current = 1 A

5) Total voltage = 8 volt

6) Voltage around R₁ is V₁

              R₁ = 2 Ω  ; I = 1 A

              V₁ = IR₁

                   = 1 * 2

                   = 2 volt

7) Resistance 2:

        Total resistance = R

        Total voltage = V = 8 volt

        Total current = I = 1 A

                  \(\sf R = \dfrac{V}{I}\\\\\\ R = \dfrac{8}{1}\\\\\)

                  R = 8 Ω

               R₁ + R₂ = 8 Ω

                2 + R₂ = 8

                      R₂  = 8 - 2

                      R₂ = 6 Ω

8)Voltage around R₂:

                  \(\sf V_2 = IR_2\\\\V_2 = 1*6\\\\\)

                  V₂ = 6 volt

9) Total R = 8 Ω

_________________________________________________

10) Total V = 12 volt

11)  Total R = 8 + 8

                 = 16 Ω

12) Total current I,

                \(\sf I = \dfrac{V}{R}\\\\I = \dfrac{12}{16}\\\\I = 0.75 \ A\)

13) Voltage at each resistor:

           V₁ = I*R₁

               = 0.75 * 8

               = 6 volt

         V₂ = I*R₂

              = 0.75 * 8

             = 6 volt

_______________________________________________________

     14) Total R =   40 + 20

                       = 60 Ω  

15) To find V₁, first find total voltage.

           I = 2 A ;  R = 60 Ω  

           V = IR    

              = 2 * 60

               = 120 V

        V₁ + V₂  =V

        V₁ + 80 = 120

                V₁ = 120 - 80

                 V₁ = 40 volt              

The forces acting on me are static frictional force and reaction force of the book. The forces acting on the book moving with a constant speed are Applied force and Kinetic frictional force.

Forces acting on me are

The book at rest, will have a static frictional force. So when I push the book, these forces will act on me. According to Newton's third law of motion, when I apply a certain amount of force on the book, the book will exert the equal amount of force on me.

Forces acting on the book are

The book when moving at constant velocity will have zero net force, because according to Newton's second law of motion, force is directly proportional to acceleration. If the velocity is constant, acceleration will be zero and net force will also be zero. Since the book is moving on a table, a kinetic frictional force will act on the book to resist the movement of the book.

Therefore,

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Answer:

How many decimal places did you use when you measured the mass of each square of aluminum? Which places were exact, and which were estimated? Three decimal places were used.Explanation:

ANSWER

A. 100 Hz

EXPLANATION

Given:

• The velocity of the wave, v = 300 m/s

• The wavelength, λ = 3 m

Find:

• The wave's frequency, f

The frequency of a wave with a wavelength λ and a velocity v is,

Replace the known values and solve,

Hence, the frequency of the wave is 100 Hz.

The graph that corresponds to 0.1 s in one complete cycle is graph D.

option D is the correct answer.

The period of a wave is the time for a particle on a medium to make one complete vibrational cycle. Period, being a time, is measured in units of time such as seconds, hours, days or years.

Also, the period of a wave is the amount of time it takes for a wave to complete one wave cycle or wavelength.

From the given parameter, the coil rotates 10 times in one second. The period of the coil is calculated as;

Period = 1 s / 10

Period = 0.1 s

From the graphs, the only option that has one complete cycle in one second is option D.

Check option D, half cycle is 0.05 s and one full cycle is 0.1 s.

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According to the question we have the angular velocity of link BC at the instant shown is 0.06 rad/s.

Given, Angular velocity of link AB, ωAB = 18 rad/s Angular velocity of link BC, ωBC = ?We know that,For link AB:ωAB = θ˙1For link BC:ωBC = θ˙2For link CD:ωCD = θ˙3 .

We know that, Velocity analysis by instantaneous center method for mechanism given below: Velocity of link AB = Velocity of link BC Relative velocity of links AB and BC is given by:VAB/BC = NCWhere, NC is the perpendicular from the instantaneous center to the path of link BC.

VAB/BC = rA/RBC∴ rAωAB = RBCωBCrA/RBC = L1/L2 = 75/150 = 0.5 ∴ rA = 0.5RBCThe link BC moves downwards. Therefore, the perpendicular to the link BC will be in the upward direction and the perpendicular to link AB will be in the downward direction. Angular velocity of link BC = ωBC= rAωAB/RBC= 0.5×18/150= 0.06 rad/s

Therefore, the angular velocity of link BC at the instant shown is 0.06 rad/s.

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(a.i) The value of the acceleration due to gravity on Earth are  9.73 m/s² and 9.8 m/s².

(b.i) The value of average acceleration due to gravity on Earth is 9.77 m/s².

(a.ii) The value of the acceleration due to gravity on Moon are  1.67 m/s² and 1.79 m/s².

(b.ii) The value of average acceleration due to gravity on Moon is 1.73 m/s².

(a.iii) The value of the acceleration due to gravity on Mars are 3.75 m/s² and 3.73 m/s².

(b.iii) The value of average acceleration due to gravity on Mars is 3.74 m/s².

The value of the acceleration due to gravity is calculated as follows;

h = vt + ¹/₂gt²

where;

g = ( 2h ) / t²

The value of acceleration due to gravity for Earth is calculated as;

when; h = 2.25 m, and t = 0.68 s

g = ( 2 x 2.25 ) / ( 0.68² )

g = 9.73 m/s²

when; h = 3.08 m, and t = 0.793s

g = ( 2 x 3.08 ) / ( 0.793² )

g = 9.8 m/s²

Average acceleration due to gravity = ( 9.73 + 9.8 ) / 2 = 9.77 m/s²

The value of acceleration due to gravity for Moon is calculated as;

when; h = 4.04 m, and t = 2.2 s

g = ( 2 x 4.04 ) / ( 2.2² )

g = 1.67 m/s²

when; h = 4.57 m, and t = 2.26 s

g = ( 2 x 4.57 ) / ( 2.26² )

g = 1.79 m/s²

Average acceleration due to gravity = ( 1.67 + 1.79 ) / 2 = 1.73 m/s²

The value of acceleration due to gravity for Mars is calculated as;

when; h = 4.68 m, and t = 1.58 s

g = ( 2 x 4.68 ) / ( 1.58² )

g = 3.75 m/s²

when; h = 3.55 m, and t = 1.38 s

g = ( 2 x 3.55 ) / ( 1.38² )

g = 3.73  m/s²

Average acceleration due to gravity = ( 3.75 + 3.73 ) / 2 = 3.74 m/s²

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The mass of the rock will be 20 kg. This can be determined from the kinetic energy equation, k = 1/2 mv².

Kinetic energy, which may be seen in the movement of an item or subatomic particle, is the energy of motion. Kinetic energy is present in every particle and moving object. Kinetic energy may be transmitted from one thing to another, for example during collisions, and is determined by the mass of an item and its movement or speed.

Given in the question,

Kinetic Energy of rock = 2000J

Velocity of rock = 20 m/s

also, k.e. = 1/2 mv²

       2000 = 1/2 m × 20²

       m = 20 kg

The mass of rock that blew in the sky was 20 kg.

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The power expended when lifting the barbell can be calculated using the formula: \(Power = Work / Time,\)

where Work is the amount of work done and Time is the time taken to do the work.

To calculate the work done, we use the formula:

\(Work = Force * Distance\),

where Force is the force applied and Distance is the distance over which the force is applied.

In this case, the distance lifted is given as 2.2 m and the time taken is 2 s. We need to calculate the force applied to the barbell in order to determine the work done.

The force applied can be calculated using Newton's second law:

\(Force = Mass * Acceleration\\\).

Given that the mass of the barbell is not provided, we cannot determine the force and therefore cannot calculate the power expended without that information. Please provide the mass of the barbell in order to calculate the power.

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Answer:

Frictional Force = 1.8 N

Explanation:

From Newton's Second Law, we know that the acceleration is produced in an object, whenever an unbalanced force is applied to it. So, for the production of acceleration application of an unbalanced force is necessary. Since, the block is moving with uniform speed in this case. Therefore, there is no acceleration involved in the motion of block. So, the all the forces acting on the block must cancel the effect of each other. So, that there is no unbalanced force to produce any acceleration. Therefore, the frictional force must be equal to the applied force in order to cancel its effect and balance it.

Frictional Force = Applied Force

Frictional Force = 1.8 N

The power needed to warm the cold outside air to inside temperature in a standard 150 m2 house with an outside temperature of 0°C and an inside room temperature of 20°C is 2076.24 watts.

To calculate the power needed, we first need to calculate the amount of heat needed to warm the air. This is done using the following formula:

Heat = Mass * Specific Heat * Temperature Change

The mass of the air in the house is calculated by multiplying the volume of the house by the density of air. The volume of the house is 150 m2 * 3.28 m/m2 = 486 m3. The density of air at 0°C is 1.225 kg/m3.

The specific heat of air is 1.013 kJ/kg·K. The temperature change is 20°C - 0°C = 20°C.

So, the amount of heat needed to warm the air is 486 m3 * 1.225 kg/m3 * 1.013 kJ/kg·K * 20°C = 9962 kJ.

The power needed to warm the air is then calculated by dividing the amount of heat needed by the time it takes to change the air, which is 5 hours * 3600 seconds/hour = 18000 seconds.

So, the power needed is 9962 kJ / 18000 seconds = 0.554 kJ/second = 2076.24 watts.

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Answer:

Percent Error  =  67.86%

Explanation:

The percent error can be calculated using the following equation:

                              | measured value - true value |
Percent Error  =  -------------------------------------------------  x 100%
                                              true value

In this equation,

---> The "measured value" is the value found after performing an experiment.

---> The "true value" is the value you expect to find after performing an experiment.

In this case,

---> measured value = 4.5 g/cm³

---> true value = 14.0 g/cm³

                              | 4.5 g/cm³ - 14.0 g/cm³ |
Percent Error  =  ----------------------------------------  x  100%     <----- Insert values
                                         14.0 g/cm³

                               | -9.5 g/cm³ |
Percent Error  =  ------------------------  x  100%                 <----- Subtract
                                 14.0 g/cm³

                                  9.5 g/cm³
Percent Error  =  ------------------------  x  100%                 <----- Take absolute value
                                 14.0 g/cm³

     
Percent Error  =  0.6786  x  100%                                 <----- Divide

Percent Error  =  67.86%                                              <----- Multiply
                                 

Answer:

1. 2380m

2. 13.6m

3. 132 Hz

Answer:

true

Explanation:

Answer:

....with the early discovery of four of Jupiter's many moons.

Explanation:

Galileo is often credited with the early discovery of four of Jupiter's many moons. The moons orbiting Jupiter follow the same laws of motion as the planets orbiting the sun. One of the moons is called Io - its distance from Jupiter's center is 4.2 units and it orbits Jupiter in 1.8 Earth-days.

A whole oscillation, cycle, or vibration, for instance, is the movement from y = A to y = +A and back to y = A. The period is the amount of time T needed to finish one oscillation.

Simple harmonic motion, or SHM, is a specific type of repetitive or periodic motion that describes the oscillation of the pendulum. The oscillating object's position changes sinusoidally throughout time. Many things go back and forth. A youngster swinging can be thought of as basic harmonic motion since the motion is approximatively sinusoidal. Simple harmonic motion does not include some complex motions, such as turbulent ocean waves.

When an item is in simple harmonic motion, it is simple to calculate both its position in relation to time and the rate at which it oscillates back and forth. In this lab, you will examine two simple harmonic motion examples: a simple pendulum and a spring-mass system.

A particle in simple harmonic motion that vibrates vertically goes up and down between two extremes when y = A. The amplitude is the largest displacement, A.

A whole oscillation, cycle, or vibration, for instance, is the movement from y = A to y = +A and back to y = A.

The period is the amount of time T needed to finish one oscillation. The frequency f, or number of vibrations the system makes per unit of time, is a related quantity. The unit of measurement for frequency is Hertz (abbreviated as Hz), with 1 Hz equal to one second. Frequency is the reciprocal of time.

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Answer:

B

Explanation:

heating increases the temperature, increase in temperature increases number of collisions hence increases pressure,volume still remains because there is no addition

Heating increases the temperature, increase in temperature increases the number of collisions hence increasing pressure, volume still remains because there is no addition

The answer is option B.

Due to the fact the frequency of collisions depends on the temperature, A is virtually now not steady. Instead, A will increase slightly with temperature as the extended kinetic energy of molecules at higher temperatures reasons them to move barely faster and for that reason go through more collisions consistent with unit time.

The extent of the fuel consequently turns large because the temperature of the fuel will increase. As the number of gas particles increases, the frequency of collisions with the partitions of the box ought to grow.

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Answer:

Well AM/Fm is digitally using soundwaves for cars through signal, which we cant hear without one (radio). Concerts are in real life and use wavelegnths that we hear because it bounces off overytihing.

Explanation:

The plausible mechanism for the given reaction is a two-step process: 1. Formation of an intermediate:
O3 + O3 → O2 + O3, 2. Rate-determining step: O3 + O3 → O2 + O2

The rate law for the reaction, rate = k[O3]2/[O2], suggests that the reaction involves the concentrations of O3 and O2. Based on this rate law, a plausible mechanism for the reaction can be proposed.
Step 1: Formation of an intermediate
The reaction starts with the collision of two O3 molecules, resulting in the formation of O2 and an O3 molecule. This step is assumed to be fast and reversible.
O3 + O3 ⇌ O2 + O3

Step 2: Rate-determining step
In the rate-determining step, the intermediate O3 molecule reacts with another O3 molecule to form two O2 molecules. This step is assumed to be slower and determines the overall rate of the reaction.
O3 + O3 → O2 + O2
The rate law is consistent with this mechanism as the rate-determining step involves two O3 molecules, which matches the rate law expression [O3]2. The concentration of O2 in the rate law expression suggests that it is produced in the reaction.

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Statement C  is false. Doubling the mass doubles the acceleration is the wrong statement.

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

Mathematically, the force is;

\(\rm F= ma\)

If force is constant, the mass is inversely proportional to the acceleration. If the mass is double in that condition, acceleration is halved.

Doubling the mass doubles the acceleration is the wrong statement.

Hence, statement C  is false

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Answer:

The gravitational force between Saturn and it's moon is 1.62 m/s ^2

Explanation:

google it

Answer:

Explanation:

C bro

The six environmental factors that affect the crop distribution are climate, soil type, topography, water availability, light intensity, and pest and disease pressure.

Climate, Temperature, rainfall, humidity, and wind patterns all play important roles in determining which crops can be grown in a particular region.

Soil type, The physical and chemical characteristics of the soil, including texture, fertility, and drainage, affect crop growth and productivity.

Topography, The shape, elevation, and slope of the land can affect microclimates and drainage patterns, which in turn can impact crop distribution.

Water availability, The amount and quality of water available for irrigation or natural rainfall can limit or promote crop growth.

Light intensity, The amount and duration of sunlight in a region affects the photosynthetic activity of plants, and hence, crop productivity.

Pest and disease pressure, The presence and abundance of pests and diseases in a region can limit the growth and yield of crops, and therefore, affect crop distribution.

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Answer:

A

kinetic energy=(mv²)/2

(1/2)(mv²)

(mv²)*0.5

where m=mass and v=velocity/speed

Answer:

its the For a fossil to form, several conditions have to be met. First of all, the animal had to live in the given area! Animals live in many environments on Earth, but not everywhere. The water above many lake bottoms and many areas of the deep ocean bottom are stagnant. The bottom water is never exchanged with surface waters, so the water contains no dissolved oxygen. Animals cannot live without oxygen, so no animals live there. In these situations, the only possibility of fossilization is if a fish or other swimming animal dies in oxygen-rich waters above, sinks down into the stagnant muddy bottom, and is buried by sediments.

Explanation:

its the For a fossil to form, several conditions have to be met. First of all, the animal had to live in the given area! Animals live in many environments on Earth, but not everywhere. The water above many lake bottoms and many areas of the deep ocean bottom are stagnant. The bottom water is never exchanged with surface waters, so the water contains no dissolved oxygen. Animals cannot live without oxygen, so no animals live there. In these situations, the only possibility of fossilization is if a fish or other swimming animal dies in oxygen-rich waters above, sinks down into the stagnant muddy bottom, and is buried by sediments.

Answer:

1650 meters

145=75+a.15

Answer:

1400 m

Explanation:

Given:

v₀ = 175 m/s

v = 105 m/s

t = 10.0 s

Find: Δx

Δx = ½ (v + v₀) t

Δx = ½ (105 m/s + 175 m/s) (10.0 s)

Δx = 1400 m