Lightning bolts can carry currents up to approximately 20 kA. We can model such a current as the equivalent of a very long, straight wire.
(a) If you were unfortunate enough to be 5.1 m away from such a lightning bolt, how large a magnetic field would you experience?
(b)How does this field compare to one you would experience by being 5.1 cm from a long, straight household current of 5 A?

If a child tries to stand on the right hand end of the plank. the maximum mass of the child that can stand on the right-hand end of the plank without tipping it over is 60 kg.

In order for the plank to remain at rest, the torques on the plank must balance. The torque due to the weight of the plank can be calculated as:

τ_plank = (1/2)Mg*L

where g is the acceleration due to gravity.

Since the sawhorses are located at equal distances from the center of the plank, the torque due to the weight of the plank is evenly distributed between them, and each sawhorse must support half of the weight of the plank:

F_plank = (1/2)Mg

where F_plank is the force that each sawhorse must exert on the plank.

When the child stands on the right-hand end of the plank, they will create an additional torque on the plank. The magnitude of this torque can be calculated as:

τ_child = F_child * (L/2)

where F_child is the force that the child exerts on the plank, and L/2 is the distance from the child to the center of the plank.

For the plank to remain at rest, the torque due to the child's weight must be balanced by the torque due to the sawhorse forces:

τ_child = τ_sawhorses

F_child * (L/2) = F_plank * D

Substituting the expressions for F_plank and τ_plank, we get:

F_child * (L/2) = (1/2)Mg*D

Solving for the maximum mass of the child, we get:

M_child = 2*F_child/g

M_child = 2*(L/2)F_plank/(gD)

M_child = LF_plank/(gD)

Substituting the values for L, M, D, and g, we get:

M_child = (6 m)(1/2)(90 kg9.81 m/s^2)/(1.5 m9.81 m/s^2)

M_child = 180/3

M_child = 60 kg

Therefore, the maximum mass of the child that can stand on the right-hand end of the plank without tipping it over is 60 kg.

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All stars spend most of their lives on the main sequence is a result of it having enough hydrogen which is an important component and acts as the fuel for energy production used to ensure it remains in the main sequence.

Every star has a lot of hydrogen and which is a vital element every star has lots as it encourages the burning of hydrogen into helium which helps to put the stars in the main sequence during most of their lives.

The mass of the stars is also a determinant factor as the more mass a star the more amount of Hydrogen it uses and the less time it takes to remain in the main sequence.

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Answer:

M= mv= 10kg x 37 m/s= 370 Kg x m/s

Answer:

La fuerza que se ejerce entre las dos cargas es 2880 N.

Explanation:

La ley de Coulomb indica que los cuerpos cargados sufren una fuerza atractiva o repulsiva al acercarse. La fuerza es atractiva si las cargas son del signo opuesto y repulsión si son del mismo signo. El valor de la fuerza es proporcional al producto del valor de sus cargas e inversamente proporcional al cuadrado de la distancia que los separa. Esto se expresa matemáticamente como:

\(F=k*\frac{Q*q}{r^{2} }\)

donde:

En este caso:

Reemplazando:

\(F=9*10^{9} \frac{N*m^{2} }{C^{2} }*\frac{4*10^{-5} C*2*10^{-5}C }{(0.05 m)^{2} }\)

F= 2880 N

La fuerza que se ejerce entre las dos cargas es 2880 N.

Georgie did 3,648 Joules of work by pulling her brother and the sled for one block.

The work done by Georgie can be calculated using the formula: Work = Force × Distance. In this case, the force applied by Georgie is 40 N, and the distance covered is 92 m. Therefore, the work done is equal to 40 N × 92 m = 3,648 J.

Work is a measure of the energy transferred when a force acts on an object and causes it to move. In this scenario, Georgie applied a constant force of 40 N to pull her brother and the sled. The work done is directly proportional to the force applied and the distance covered. By multiplying the force and distance values, we find that Georgie performed 3,648 Joules of work.

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Georgie did 3,648 Joules of work by pulling her brother and the sled for one block.

The work done by Georgie can be calculated using the formula: Work = Force × Distance. In this case, the force applied by Georgie is 40 N, and the distance covered is 92 m. Therefore, the work done is equal to 40 N × 92 m = 3,648 J.

Work is a measure of the energy transferred when a force acts on an object and causes it to move. In this scenario, Georgie applied a constant force of 40 N to pull her brother and the sled. The work done is directly proportional to the force applied and the distance covered. By multiplying the force and distance values, we find that Georgie performed 3,648 Joules of work.

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The charge qred on the red sphere is given by (2q * d2^2) / d1^2, expressed in terms of q, d1, d2, and θ.

To calculate the charge qred on the red sphere, we can use the concept of electric forces and Coulomb's law. The electric force between two charges is given by F = k * (|q1| * |q2|) / r^2, where k is the electrostatic constant, q1 and q2 are the charges, and r is the distance between them.
In this scenario, the yellow sphere has a charge of 2q. Let's assume the distance between the yellow and red spheres is d1. The force between the yellow and red spheres can be expressed as F1 = k * (|2q| * |qred|) / d1^2.
Now, suppose the distance between the red sphere and the source of electric field is d2. The force between the red sphere and the source of electric field can be expressed as F2 = k * (|qred| * |qred|) / d2^2.
Since the forces F1 and F2 are equal (since they act on the same object), we can set them equal to each other:
k * (|2q| * |qred|) / d1^2 = k * (|qred| * |qred|) / d2^2
Simplifying and rearranging the equation, we have:
(2q * qred) / d1^2 = qred^2 / d2^2
Cross-multiplying and solving for qred, we get:
2q * d2^2 = qred * d1^2
qred = (2q * d2^2) / d1^2

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The S.I. unit of E is NC^-1 and that of B is NA^-1 m^-1, then unit of E/B is A m/C (ampere meter per coulomb). This unit represents the ratio between the electric field and the magnetic field, indicating the strength and direction of the electromagnetic field.

The SI unit of electric field (E) is NC^(-1) (newton per coulomb) and the SI unit of magnetic field (B) is NA^(-1) m^(-1) (tesla). To determine the unit of E/B, we need to divide the unit of E by the unit of B.

Dividing the unit of E (NC^(-1)) by the unit of B (NA^(-1) m^(-1)), we can simplify the expression:

E/B = (NC^(-1))/(NA^(-1) m^(-1))

To simplify this expression, we can cancel out the common units in the numerator and denominator:

E/B = (N/C)/(N/(A m))

Now, let's simplify further by dividing the numerator and denominator:

E/B = (N/C) * (A m/N)

Canceling out the common units:

E/B = (A m)/(C)

Therefore, the unit of E/B is A m/C (ampere meter per coulomb).

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Answer:

Difference in Twin's Ages = 12.68 years

Explanation:

Using special theory of relativity's time dilation phenomenon, we first find the time that is passed on earth during Lou's trip.

t = t₀/[√(1 - v²/c²)]

where,

t = time measured by the person in relative motion = 1 year

t₀ = time measured by the person at rest = ?

v = speed of relative motion = 0.96 c

c = speed of light  

Therefore,

1 year = t₀/[√(1 - 0.96² c²/c²)]

1 year = t₀/[√(1 - 0.9216)]

(1 year)(0.28 year) = t₀

t₀ = 0.28 year

Let,

y = Sue's age

x = Lou's age

so,

x - y = 13.4 years

but, after this trip Lou has aged 1 year, and on earth only 0.28 years passed so, Sue has aged only 0.28 years. Therefore,

x = x + 1

y = y + 0.28

Therefore,

(x + 1 year) - (y + 0.28 year) = 13.4 years

x - y = 13.4 years - 0.72 year

x - y = 12.68 years

Difference in Twin's Ages = 12.68 years

Answer:

11 moments docx has the answer

Explanation:

Using the z-distribution, it is found that  maximum the error of the estimate is of 0.0475 hours.

X ± Z(S ÷ √n)

x= is the sample mean.

z =is the critical value.

n= is the sample size.

ơ  =is the standard deviation for the population.

margin of error is the given by:-

Margin of Error  given as = Z * ơ / √n

We have  90% the confidence level, hence, z is the value of Z that has a p-value of , so the critical value of  z = 1.645.

putting value in equation we get

Margin of Error= 1.645*.5/√300

so, Margin of Error is 0.0475 hours

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Answer:

Good one

Explanation:

Hydrogen has the highest thermal conductivity of any gas.

Answer:

the best answer would be c

Explanation:

When a material in liquid state is given energy, it changes its phase from liquid to vapor; the energy absorbed in this process is called heat of vaporization. The heat of vaporization of water is about 2,260 kJ/kg, which is equal to 40.8 kJ/mol. The vaporization is the opposite process of condensation.

hope this helped <3

Answer:

we can incinerate waste materials and use the product as fuel rather than dumping them. It may produce carbon dioxide but we can create a machine that can convert carbon into energy.

The values of R1 = 11.27 ohms  and R2 = 60 ohms. P = 201.6W In this way, by adjusting the configuration of the heating elements and the resistance values, a range of power settings can be achieved.

A) To determine the values for R1 and R2, we need to first find the maximum and minimum current values for the heating elements. We can use Ohm's law to calculate the current, I, in the circuit:

I = V / R, where V is the voltage and R is the resistance.

For the maximum power setting of 1280W, we have:

I_max = P_max / V = 1280W / 120V = 10.67A

For the minimum power setting of 240W, we have:

I_min = P_min / V = 240W / 120V = 2A

To calculate the resistance of each heating element, we can use Ohm's law again:

R = V / I

For R1, using the maximum current value:

R1 = V / I_max = 120V / 10.67A = 11.27 ohms

For R2, using the minimum current value:

R2 = V / I_min = 120V / 2A = 60 ohms

B) The intermediate power settings can be achieved by varying the resistance of the heating elements. By connecting the heating elements in series or parallel, the total resistance of the circuit can be adjusted, which will change the current in the circuit and thus the power.

For example, to achieve a power setting of 720W, we can connect the heating elements in series, which will give us a total resistance of 11.27 + 60 = 71.27 ohms. Using Ohm's law, we can then calculate the current:

I = V / (R1 + R2) = 120V / 71.27 ohms = 1.68A

And the power:

P = I × V = 1.68A × 120V = 201.6W

In this way, by adjusting the configuration of the heating elements and the resistance values, a range of power settings can be achieved.

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We are designing an electric space heater to operate from 120VDC. Two heating elements with resistance R1 and R2 are to beused that can be operated in parallel, seperately, or inseries. The highest power is to be 1280W, and the lowestpower is to be 240W. Draw a cicuit diagram.

A) What are the values needed for R1 and R2?

B) What intermediate power settings are available?

Answer:

c.

Explanation:

Answer:

The Letter answer that best fits the question is C(It authorized construction of interconnected highways.)

Explanation:

I took the test

Answer:

your eyes would get seriously damaged

Explanation:

when you look directly at the sun, the sun shines it's rays directly to your eyes , which damage them. that's why you should always wear sunglasses in that type of weather, and never point directly at the sun. if you find this answer helpful, mark it as brainliest.

From the information given, both objects have the same surface charge density.

A two-dimensional object's area density (also known as areal density, surface density, superficial density, areic density, mass thickness, column density, or density thickness) is calculated as the mass per unit area. The kilogramme per square metre (kgm2) is the SI-derived unit. A related area number density can be established by replacing mass with a countable quantity such as the number of particles.

surface charge density() is the amount of charge per unit area measured in coulombs per square metre (Cm2) at any location on a two-dimensional surface. If q is the charge and an is the area of the surface over which it flows, the surface charge density formula is = q/A, and the S.I.

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The temperature at the nozzle's discharge was approximately 586.2 K.

Back-pressure is the term for the pressure at which the steam emerges from the nozzle. When steam is passing through a nozzle, neither heat is being provided nor rejected. As a result, it is regarded as an adiabatic flow, and the associated expansion is also so regarded.

To approximate the temperature at the exit for an isentropic process, we can solve the following equation for T2s:

T2s = T1 - (h1 - h2s)/cp

s1 = s2s

Now we can solve for h2s:

h2s = h1 - (s2 - s1) * T1

Substituting this expression into the equation for T2s, we get:

T2s = T1 - (h1 - (h1 - (s2 - s1) * T1))/cp

Simplifying this expression, we get:

T2s = T1 - (h1/cp) + ((s2 - s1)/cp) * T1

Now we can substitute the given values into this equation and calculate T2s:

T1 = 975 K

p1 = 546 kPa

p2 = 101 kPa

cp = 2.01 kJ/(kgK) (specific heat at constant pressure for steam at 975 K)

s1 = 7.704 kJ/(kgK) (specific entropy at the inlet)

s2 = 7.704 kJ/(kg*K) (specific entropy at the outlet for an isentropic process, since s1 = s2s)

h1 = 3475 kJ/kg (specific enthalpy at the inlet)

h2s = h1 - (s2 - s1) * T1

= 3475 - (7.699 - 7.704) * 975

= 3265.5 kJ/kg

T2s = T1 - (h1/cp) + ((s2 - s1)/cp) * T1

= 975 - (3475/2.01) + ((7.704 - 7.699)/2.01) * 975

= 586.2 K

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A gun is fired with muzzle velocity 1099 feet per second at a target 4750 feet away. The minimum angle of elevation necessary to hit the target is approximately 15.2 degrees.

To find the minimum angle of elevation, we can use the equation for the horizontal range of a projectile. The horizontal range is the distance traveled by the bullet in the horizontal direction, which in this case is 4750 feet. The equation for the horizontal range is: R = (v^2 * sin(2θ)) / g

where R is the range, v is the muzzle velocity, θ is the angle of elevation, and g is the acceleration due to gravity.

Rearranging the equation to solve for θ, we have: θ = 0.5 * arcsin((R * g) / v^2). Plugging in the given values, we have: θ = 0.5 * arcsin((4750 * 32.2) / (1099^2))

Evaluating this expression, we find that the minimum angle of elevation necessary to hit the target is approximately 15.2 degrees. This means that the gun should be elevated at an angle of approximately 15.2 degrees above the horizontal in order to hit the target 4750 feet away.

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Taking into account the definition of kinetic energy, the kinetic energy of a 23.2 g object moving at a speed of 81.9 km/hr is 6.004 J.

Kinetic energy is a form of energy. It is defined as the energy associated with bodies that are in motion and this energy depends on the mass and speed of the body.

This is, kinetic energy is defined as the amount of work necessary to accelerate a body of a certain mass and in a position of rest, until it reaches a certain speed. Once this point is reached, the amount of accumulated kinetic energy will remain the same unless there is a change in speed or the body returns to its state of rest by applying a force.

Kinetic energy is represented by the following formula:

Ec = ½ mv²

Where:

In this case, you know:

Replacing in the definition of kinetic energy:

Ec = ½ 0.0232 g×(22.75 m/s)²

Solving:

Ec= 6.004 J

Finally, the kinetic energy of a 23.2 g object moving at a speed of 81.9 km/hr is 6.004 J.

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A wave is a disturbance in a medium. The speed of a wave can be calculated by the formula: V = λf.

A wave is a propagating dynamic disturbance of one or more quantities such as sound and light. Waves can be periodic, in which case those quantities oscillate repeatedly about an equilibrium value at some frequency.

V = λf

where, V is the velocity of wave,

λ is the wavelength,

f is the frequency.

1. Time period = 0.25 second

Frequency of a wave = 1/T

F = 1/ 0.25

F = 4 sec⁻¹

2. Speed of the wave with frequency 5.0 Hz and wavelength 10cm

v = λf

v = 10 × 5.0

v = 50 cm/s

3. Frequency of a wave with speed 20cm/s and wavelength 10cm

v =  λf

f =  λ/v

f = 10/20

f = 1/2 or 0.5 Hz

4. Wavelength of a wave when frequency is 5.0 Hz and speed 30 cm/s

v = λf

λ = v/f

λ = 30/5

λ = 6cm

5. Speed of a wave when the period is 3 sec and wavelength is 20m

Period = 1/f

3 = 1/f

f = 1/3

v = λf

v = 20 × 1/3

v = 6.66m/s

6. Wavelength of the wave when frequency is 75 Hz and speed is 300m/s

v = λf

λ = v/f

λ = 300/ 75

λ = 4m

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Answer:

No and yes

Explanation:

Yes technically you are time traveling.

But not in the way like the movies or whatever when they go to 1956 or whatever.

You are time traveling because you are going from 2:30 to 12:00. And you are traveling :|

But no because. . . just no :\

I'm not sure how to explain.

When two forces act in opposite directions, the resultant force can be calculated by subtracting the smaller force from the larger force. The formula for calculating the resultant force is: resultant force = force1 - force2.

When two forces act in opposite directions, the resultant force can be calculated using the following formula:

resultant force = force1 - force2

Where force1 is the larger force and force2 is the smaller force acting in the opposite direction.

For example, suppose there are two forces acting on an object: 10 Newtons to the left and 5 Newtons to the right. To find the resultant force, you would subtract the smaller force from the larger force:

resultant force = 10 N - 5 N

resultant force = 5 N to the left

So in this case, the resultant force is 5 Newtons to the left.

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Answer:

3333.33 m/s²

Explanation:

From the question given above, the following data were obtained:

Total Velocity (v) = 40 m/s

Total Time (t) = 0.012 s.

Average acceleration (a) =..?

Average acceleration can be defined as follow:

Average acceleration (a) = Total velocity (v) / total time (t)

a = v / t

With the above formula, we can obtain the average acceleration of the ball as shown below:

Total Velocity (v) = 40 m/s

Total Time (t) = 0.012 s.

Average acceleration (a) =..?

a = v / t

a = 40 / 0.012

a = 3333.33 m/s²

Therefore, the average acceleration of the ball is 3333.33 m/s².

The integral of 1/(1 + x²) is (1/2)ln|1 + x²| + C where C is the constant of integration.

Integration is a mathematical process of finding the antiderivative of a function. To integrate the given expression 1/(1 + x²), we will use the substitution method.

Let u = 1 + x², du/dx = 2x dx, then dx = du/2x and the integral becomes:

∫1/(1 + x²) dx = ∫1/u * (1/2x) du= (1/2)∫1/u du

The antiderivative of 1/u is ln|u| + C, where C is the constant of integration.

Therefore, the final solution of the integral is (1/2)ln|1 + x²| + C.

Let us work through the steps:

Step 1:Let u = 1 + x² and then differentiate both sides with respect to x to obtain du/dx. du/dx = 2x

Substitute 2x dx = du into the integral ∫1/(1 + x²) dx to get the integral in terms of u:∫1/u * (1/2x) du = (1/2) ∫1/u du

Step 2:Calculate the antiderivative of 1/u, which is ln|u|. Thus, the final solution is (1/2)ln|1 + x²| + C, where C is the constant of integration. The constant C will vary depending on the initial conditions of the problem.

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Answer:

Your correct answer is shown down below so that you know...

Explanation:

If you didn't know, a hypothesis is known as an educated guess that can be tested with observations and falsified if it really is false. You cannot prove conclusively that most hypotheses are true because it's generally impossible to examine all possible cases for exceptions that would disprove them.

Answer:

You cannot prove a hypothesis to be true

Explanation:

Answer:

\(F_A =5.625*10^1^6N\)

Explanation:

From the question we are told that

50,000 years ago,

A giant 4.5 107-kg meteor

180-m-deep hole

20,000 m/s

Generally for this problem the energy change is given as

       \(\triangle E=\frac{1}{2} mv^2 +mgd\)

Having the potential and kinetic energy in place

Mathematically  solving for Average force\(F_A\)

       \(\triangle E=F_a*d\)

\(F_A =\frac{1/2* 4.5*10^7(20,000)^2-kg+4.5*10^7*9.81*160}{160}\)

Therefore Average force \(F_A\) is given by

\(F_A =5.625*10^1^6N\)