light strikes a 5.0-cm thick sheet of glass at an angle of incidence in air of 50°. the sheet has parallel faces and the glass has an index of refraction 1.50.

Answer:

Yes

Explanation:

Because the call can evaporate from the water.

Answer:

A centrifuge is utilized to isolated little sums of strong held in suspension from the fluid. For case, chalk from water. The centrifuge contains test-tubes that are spun around at tall speed that causes the strong to sink to the foot of the tube. The fluid is the tapped (poured off) clearing out the strong behind.

The expression 3sinωt + 8cosωt can be written in the form Rsin(ωt + α) as follows:

Rsin(ωt + α) = √(3² + 8²) sin(ωt + α)

In order to express 3sinωt + 8cosωt in the form Rsin(ωt + α), we need to find the values of R and α.

To determine the value of R, we can use the Pythagorean theorem, which states that for any right triangle, the square of the hypotenuse (R in this case) is equal to the sum of the squares of the other two sides (3 and 8 in this case). Therefore, R = √(3² + 8²) = √(9 + 64) = √73.

To find the value of α, we can use the trigonometric identity: cosα = 3/R, which implies α = cos⁻¹(3/R) = cos⁻¹(3/√73).

Now we have the values of R and α, so we can express 3sinωt + 8cosωt as Rsin(ωt + α), which becomes √73 sin(ωt + cos⁻¹(3/√73)).

In summary, the expression 3sinωt + 8cosωt can be written as √73 sin(ωt + cos⁻¹(3/√73)).

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Answer:

334 pennies

Explanation:

100+100+100=300

3.00$

+0.34

their is 324 pinnies in 3.24 and 334 pinnies in 3.34

Answer:

The moon should be in the New phase.

Explanation:

Answer:

there will be less precipitation because there is less water vapour

Explanation:

The direction of the electric field surrounding a long wire carrying a positive charge is, Pointing directly outward away from the wire.

The correct answer is option A.

When a wire is given a positive charge, it creates an electric field around it. The electric field lines extend radially outward in all directions away from the wire. This means that if you were to place a positive test charge in the vicinity of the wire, it would experience a repulsive force and move away from the wire.

So, the correct answer is A)

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The energy released by this lightning bolt is 3.0 × 10^9 C × V.

Lightning is an electrical discharge caused by imbalances between storm clouds and the ground, or within the clouds themselves. Most lightning occurs within the clouds. "Sheet lightning" describes a distant bolt that lights up an entire cloud base. Other visible bolts may appear as bead, ribbon, or rocket lightning.

To calculate the energy released by the lightning bolt, we can use the formula:

Energy = Charge × Potential Difference

Given:
Charge (Q) = 30 C
Potential Difference (V) = 1.0 × 10^8 V

Plugging in the values, we get:

Energy = 30 C × 1.0 × 10^8 V

Simplifying the expression:

Energy = 30 × 1.0 × 10^8 C × V

Energy = 3.0 × 10^9 C × V

Therefore, the energy released by this lightning bolt is 3.0 × 10^9 C × V.

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The mass of the chain is approximately 0.39 kg when the meter stick balances at its center and moves 13.0 cm toward the end with the chain.

To solve this problem, we can use the principle of torque balance. When the meter stick is in equilibrium, the sum of the torques acting on it must be zero. Torque is calculated by multiplying the force applied to an object by the distance from the point of rotation.

Let x be the distance from the center of the meter stick to the balance point when the chain is suspended. The torque exerted by the meter stick's mass on the balance point is equal to the torque exerted by the chain's mass.

Torque exerted by the meter stick: (0.30 kg) × (9.8 m/s²) × (0.13 m) = 0.3822 Nm

Torque exerted by the chain: (mass of the chain) × (9.8 m/s²) × (0.13 m)

Since the meter stick balances at its center, the torques must be equal:

0.3822 Nm = (mass of the chain) × (9.8 m/s²) × (0.13 m)

Simplifying the equation:

0.3822 = (mass of the chain) × 1.274

Dividing both sides by 1.274:

mass of the chain = 0.3822 / 1.274

mass of the chain ≈ 0.30 kg / 1.274

mass of the chain ≈ 0.39 kg

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If a protostar formed in a cloud without any angular momentum, its life story would differ significantly compared to a protostar with angular momentum.

The absence of angular momentum would affect the protostar's rotation, the formation of a protoplanetary disk, and the potential for planet and star formation.

Angular momentum plays a crucial role in the formation and evolution of protostars. When a cloud of gas and dust collapses under gravity, conservation of angular momentum causes the material to spin faster as it contracts. This rotation leads to the formation of a protoplanetary disk, a spinning disk of material surrounding the protostar.

In the absence of angular momentum, the protostar would not have a spinning motion or a protoplanetary disk. The collapse would likely proceed more spherically, without the formation of a flattened disk structure. As a result, the process of planet formation would be significantly hindered since protoplanetary disks are crucial for the accumulation of material and the formation of planetary systems.

Additionally, the absence of angular momentum may impact the formation of a stable, long-lived star. Angular momentum helps balance the inward pull of gravity during the collapse phase, allowing the protostar to reach a stable state known as hydrostatic equilibrium. Without angular momentum, the protostar may experience gravitational collapse and instability, potentially leading to a different evolutionary path or even preventing the formation of a star altogether.

Overall, the absence of angular momentum in the formation of a protostar would alter its rotational characteristics, hinder planet formation, and potentially impact the stability and longevity of the star itself.

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Answer:

Explanation:

This is a simple gravitational force problem using the equation:

\(F_g=\frac{Gm_1m_2}{r^2}\) where F is the gravitational force, G is the universal gravitational constant, the m's are the masses of the2 objects, and r is the distance between the centers of the masses. I am going to state G to 3 sig fig's so that is the number of sig fig's we will have in our answer. If we are solving for the gravitational force, we can fill in everything else where it goes. Keep in mind that I am NOT rounding until the very end, even when I show some simplification before the final answer.

Filling in:

\(F_g=\frac{(6.67*19^{-11})(7.2000*10^{26})(5.0000*10^{23})}{(6.10*10^{11})^2}\) I'm going to do the math on the top and then on the bottom and divide at the end.

\(F_g=\frac{2.4012*10^{40}}{3.721*10^{23}}\) and now when I divide I will express my answer to the correct number of sig dig's:

\(Fg=\) 6.45 × 10¹⁶ N

The radius of the Earth's orbit is  149.6 million kilometers or 93.0 million miles calculated using its orbital speed.

speed is defined as the rate at which a body covers a distance in a given amount of time. Mathematically, speed (v) is calculated by dividing the distance traveled (d) by the time taken (t): v = d / t

The average orbital speed of the Earth is approximately 29.78 kilometers per second (km/s).

The period of the Earth's orbit is one year, which is equivalent to 365.25 days.

To find the radius of the Earth's orbit, we can use the formula:

Radius = speed × Period / (2 × π)

Let's calculate it:

Radius = 29.78 km/s × (365.25 days × 24 hours × 60 minutes × 60 seconds) / (2 × π)

Radius = 149.6 million kilometers

So, the radius of the Earth's orbit (Astronomical Unit) is 149.6 million kilometers.

To convert it to miles, we can use the conversion factor:

1 kilometer = 0.621371 miles

Radius = 93.0 million miles

Therefore, the radius of the Earth's orbit is  149.6 million kilometers or 93.0 million miles calculated using its orbital speed.

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The kinetic energy of the car is 945,000 joules.

The car would have to be dropped from a height of 94.3 meters (310 feet) to have the same amount of kinetic energy just before impact.

The formula for kinetic energy is

KE = (1/2)mv^2

where m is the mass of the object and v is its velocity.

Substituting the given values

KE = (1/2) x 2100 kg x (30 m/s)^2 = 945,000 joules.

To find the height from which the car would have to be dropped, we can use the formula PE = mgh, where PE is potential energy, m is mass, g is the acceleration due to gravity (9.8 m/s^2), and h is height.

Equating the potential energy to the kinetic energy found in we get mgh = 945,000 joules.

Solving for h, we get h = 945,000 joules / (2100 kg x 9.8 m/s^2) = 94.3 meters (rounded to one decimal place).

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Answer:

\( \huge{\boxed{3675 \: N}} \)

Explanation:

The force acting on the tow truck can be found by using the formula

\( \bold{F = mass × acceleration} \)

From the question

mass = 1225 kg

acceleration= 3 m/s²

F = 1225 × 3 = 3675

We have the final answer as

Answer:the boy is heavier

Explanation:

So the answe is gonna be less than 6 m/s^2;)

Maximum six bullet points you should aim for on each slide to be effective in communicating your point.

Why are bullet points important?

Bullet points are important as they help to keep the data simple looking, lucid and well-organized in your communication.

In order to keep the information concise and to keep the slides from looking cluttered make sure there are only six bullet point.

In general, to effectively communicate your point, you should follow the simple rule which states that' six by six guideline'.

According to this rule, each slide shall have six bullets and  each bullet line shall consist of six words.

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Answer:

Option D. ⁸⁵₃₆Kr

Explanation:

⁸⁵₃₅Br —> ⁰₋₁e + ?

Let ⁿₘZ represent the unknown.

Thus, the equation becomes:

⁸⁵₃₅Br —> ⁰₋₁e + ⁿₘZ

Next, we shall determine n, m and Z as follow:

85 = 0 + n

85 = n

Thus,

n = 85

35 = –1 + m

Collect like terms

35 + 1 = m

36 = m

Thus,

m = 36

ⁿₘZ => ⁸⁵₃₆Z = > ⁸⁵₃₆Kr

Thus, the equation:

⁸⁵₃₅Br —> ⁰₋₁e + ⁿₘZ

Becomes:

⁸⁵₃₅Br —> ⁰₋₁e + ⁸⁵₃₆Kr

Answer:

Water waves are an example of waves that involve a combination of both longitudinal and transverse motions. As a wave travels through the waver, the particles travel in clockwise circles. The radius of the circles decreases as the depth into the water increases.

Explanation:

Answer:

Potential energy is stored energy and the energy of position.

Explanation:

There are several forms of potential energy. Kinetic energy is motion of waves, electrons, atoms, molecules, substances, and objects. Chemical Energy is energy stored in the bonds of atoms and molecules.

( Hope this helps )

Answer:

 w = 4π   rad / s

Explanation:

When the dancer is turning, the body is isolated so the angular momentum is conserved.

initial

         L₀ = I₀ w₀

final

         L_f = I w

in this case it indicates that the initial moment is Io = 28.14 kg m² and the final moment is half

         I = I₀ / 2

frequency and angular velocity are related

         w = 2π f

          w = 2π 1

          wo = 2π   rad / s

how angular momentum is conserved

          L₀ = L_f

          I₀ w₀ = I w

          w = \(\frac{I_o}{I}\)  w₀

let's calculate

          w = 2 2π

          w = 4π   rad / s

Answer:

C

Explanation:

velocity is a vector unit, meaning it isn't scalar so also gives direction, same as distance vs. displacement.

Answer:

B

Explanation:

filament lamp ofcourse

The supplied assertion states that a proton experience would be forced in the same field at -2.24 i^ pN

The main distinction is that whereas as proton is a charged particles particle found inside the atom's nucleus, a particle is a highly reactive particle that orbiting the nucleus. Two up neutrons and one drop quark are found in protons. One up atom and five down quarks make up neutrons. The "strong nuclear force," one of the four basic forces, holds the nucleus together (gravity and electromagnetism are two others).

Charge q = -1*10⁻⁶C

Electrostatic force F = 14 i^ N

The electric field is

       E = F/q

          = (14 i^ N) / (-1*10⁻⁶ C)

          = -14*10⁶ i^ N/C

The force on a proton is:

   F = qpE

      = (1.6*10⁻¹⁹ C)(-14*10⁶ i^ N/C)

      = -22.4*10⁻¹³ i^ N

      = -2.24*10⁻¹² i^ N

      = -2.24 i^ pN

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The complete question is-

1.0 µC charge experiences a 14 i N electric force in a certain electric field. What force would a proton experience in the same field?

Answer:

Batteries are an example of an electrochemical device in an electric circuit.

Answer:

this density is in the range of Peridotite type rocks

Explanation:

In this graduated cylinder exercise we can directly read the volume of the rock

         V = (35 - 30) cm³

          V = 5 cm³

They also indicate the mass of the rock

          m = 15.5 gr.

Density is defined as the ratio of mass to volume

          ρ = 15.5 / 5

          ρ= 3.1  gr /cm³

When checking the attached table this density is in the range of Peridotite type rocks

The type of rock the students mostly like have is Peridotite.

We'll begin by calculating the volume of the rock. This can be obtained as follow:

Volume of water = 30 mL

Volume of water + rock = 35 mL

Volume of rock = (Volume of water + rock) – (Volume of water)

Volume of rock = 35 – 30

Volume of rock = 5 mL = 5 cm³

Mass of rock = 15.5 g

Density = mass / volume

Density of rock = 15.5 / 5

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The current through the coffee machine is 3.48 A.

To calculate the current flowing through the coffee machine, we use the formula below.

Formula:

Where:

Make I the subject of the equation.

From the question,

Given:

Substitute these values into equation 2

Hence, The current through the coffee machine is 3.48 A.

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Answer:3.48

Explanation:

To complete the assignment, click the links to open the resources provided. These resources will provide guidance on how to create a lab report and how it will be graded.

Resources are the materials, both physical and intellectual, that are used to produce goods and services. Physical resources include land, natural resources, capital goods, human resources and technological resources. Intellectual resources refer to knowledge or skills that are used in the production process, such as patents, copyrights, inventions, brands and trade secrets.

Once you have created the lab report file(s) and are ready to upload them, click the Add Files button and select each file from your desktop or network folder. Upload each file separately.

Once all the files have been uploaded, click Submit to submit your work to your teacher.

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Answer:

Explanation:

We shall apply law of conservation of momentum .

M and m be mass of man and boat . V and v be velocity of man and boat .

MV = mv

75 V = 30 v

2 .0 m/s is relative velocity of man wrt boat .

Given v + V = 2

V = 2 - v

75 ( 2 - v )  = 30 v

150 - 75 v = 30 v

150 = 105 v

v = 1.43 m /s

To calculate the initial acceleration of the negatively charged polystyrene sphere towards the positive plate, we can use the equation for the electric force on a charged object and Newton's second law of motion.

The electric force between two charged objects is given by Coulomb's law:

F = k * (q1 * q2) / r^2

where:

F is the electric force,

k is the electrostatic constant (approximately 9 x 10^9 N m^2/C^2),

q1 and q2 are the charges of the two objects,

r is the distance between the charges.

The charge on the sphere is given as -9.5 x 10^-19 C. After losing one electron, the charge becomes -9.5 x 10^-19 C + (-1.6 x 10^-19 C) = -11.1 x 10^-19 C.

The force acting on the sphere due to the electric field between the parallel plates is given by:

F = q * E

where:

F is the force,

q is the charge,

E is the electric field strength.

The electric field strength between the parallel plates is given by:

E = V / d

where:

V is the potential difference between the plates,

d is the distance between the plates.

Given:

V = 170 V (potential difference between the plates)

d = 5.0 mm = 0.005 m (distance between the plates)

q = -11.1 x 10^-19 C (charge on the sphere)

Substituting the values into the equation, we have:

F = (-11.1 x 10^-19 C) * (170 V / 0.005 m)

Simplifying:

F = -11.1 x 10^-19 C * 34,000 N/C

F ≈ -3.77 x 10^-14 N

The force acting on the sphere is approximately -3.77 x 10^-14 N. Since the force is negative, it indicates that the direction of the force is towards the negative plate (opposite to the direction of acceleration).

Now, we can calculate the acceleration of the sphere using Newton's second law:

F = m * a

where:

F is the force,

m is the mass of the sphere (which we assume to be constant),

a is the acceleration.

Assuming the mass of the sphere is m, we can rearrange the equation to solve for acceleration:

a = F / m

Since the mass of the sphere is not given, we cannot determine the numerical value of acceleration without additional information. However, the direction of acceleration is towards the negative plate.

Therefore, the initial acceleration of the negatively charged polystyrene sphere towards the positive plate cannot be determined without knowing the mass of the sphere.

Answer:

Explanation:

As per the given information, 18(O) is struck by a proton, and 18(F) and another particle are produced. The reaction has a Q value of -2.453 MeV, and the atomic mass of 18(O) is 17.999 160 u.

We have to find the atomic mass of 18(F). The Q value of a nuclear reaction can be given as Q = (Mi - Mf - Mp) × c²WhereQ = Q

value of the nuclear reaction = initial massMf = final massMp = mass of the projectile = speed of light

The Q value of the given nuclear reaction is -2.453 MeV. Since we know the initial mass (Mi) and the mass of the projectile (Mp), we can calculate the final mass (Mf) as follows: Mf = Mi - Mp - (Q / c²)Now, let's calculate the final mass of 18(F).

Initial mass (Mi) = mass of 18(O) = 17.999 160 UMass of the projectile (Mp) = mass of a proton = 1.007 825 uQ value (Q) = -2.453 MeVSpeed of light (c) = 2.998 × 10⁸ m/sMf = 17.999 160 u - 1.007 825 u - (-2.453 MeV / (2.998 × 10⁸ m/s)²)Mf = 18.000 674 therefore, the atomic mass of 18(F) is 18.000 674 u.