Answer:
Li has less mass and therefore less inertia, so he can change his motion more easily than Raj.
Explanation:
Answer:
Li has less mass and therefore less inertia, so he can change his motion more easily than Raj.
Explanation:
If it is the first day of Winter in the Northern Hemisphere, what day is it in the Southern Hemisphere?
Answer:summer
Explanation:
Answer:
first day of summer
Explanation:
what is an object that can hold things together or lift an object?
Answer:
Inclined plane = 2. Something that can hold things together or lift an object. Wedge = 3.
Explanation:
Screw is simple machine which is used to hold to objects together
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(a) what is the potential difference across the resistor? (enter your answer to 6 significant figures for comparison.) 10.287 incorrect: your answer is incorrect. v (b) what is it across each of the two sections of wire? mv (c) at what rate is energy lost to thermal energy in the resistor? w (d) at what rate is it lost in each of the two sections of wire?
(a) The potential difference across the resistor is 10.287 V.
(b) The potential difference across each of the two sections of wire is equal to the potential difference across the resistor, 10.287 V.
(c) The rate at which energy is lost to thermal energy in the resistor is determined by the formula:
Power = Voltage x Current
Where P is power (in watts), V is voltage (in volts) and I is current (in amperes). The current is determined by the resistance of the resistor, and the voltage is the potential difference across the resistor, 10.287 V. So, the rate at which energy is lost to thermal energy in the resistor is 10.287 V x I, where I is determined by the resistance of the resistor.
(d) The rate at which energy is lost in each of the two sections of wire is determined by Ohm's Law:
V = I x R
Where V is voltage (in volts), I is current (in amperes) and R is resistance (in ohms). The current is determined by the resistance of the two sections of wire and the voltage is the potential difference across the two sections of wire, 10.287 V. So, the rate at which energy is lost in each of the two sections of wire is 10.287 V x I, where I is determined by the resistance of the two sections of wire.
In summary, the rate at which energy is lost to thermal energy in the resistor is determined by the potential difference across the resistor (10.287 V) and the resistance of the resistor, while the rate at which energy is lost in each of the two sections of wire is determined by the potential difference across the two sections of wire (10.287 V) and the resistance of the two sections of wire.
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Ginger was caring for her litter of puppies when the four curious pups spotted cat for the first time. Each of the four pups leaned their full of force in the board balanced between the puppies and the cat. How much force must Ginger apply to the other side to keep the puppies from knocking down the board? A. 8 N
B. 16 N
C. 32 N
On prevent the puppies from tearing down the board, Ginger must apply 32 N of force to the opposite side.
What is the value of total force?The total force acting on the system is equal to the acceleration of the center of mass times the system's total mass. When applied to an extended object, Newton's second law, F = ma, predicts the motion of a specific reference point for this object.
How much force is acting on an object overall?The vector sum of all forces acting on an object is known as the net force. In other words, the net force is the sum of all the forces, taking into mind that a force is a vector and that two forces that have the same magnitude but facing the opposite direction will cancel each other out.
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much like a battery these generate electricity from chemical events
The term you are looking for is "chemical battery". Chemical batteries work by converting chemical energy into electrical energy through a series of chemical reactions. These reactions take place within the battery's cells, which are composed of two electrodes and an electrolyte.
When the battery is connected to a circuit, the chemical reactions produce an electrical current that can be used to power devices. Chemical batteries are widely used in many applications, including consumer electronics, electric vehicles, and renewable energy systems. They are a crucial component of our modern technological society, and ongoing research is focused on developing more efficient and sustainable battery technologies to meet growing energy demands.
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Particles q1 = + 8.0 uc q2 = + 3.5 uc and q3 = - 2.5 uc are in a line. Particles q1 and q2 are separated by 0.10 m and particles q2 and q3 are separated by 0.15 m what is the net force on particle q2
The net electrostatic force acting on the charged particle q₂ is 28.7 N.
Charge on the first particle, q₁ = 8 μC
Charge on the second particle, q₂ = 3.5 μC
Charge on the third particle, q₃ = - 2.5 μC
Distance between the charges q₁ and q₂, r₁ = 0.1 m
Distance between the charges, q₂ and q₃, r₂ = 0.15 m
Electrostatic force exerted on the charged particle q₂ and q₁,
F₁ = 1/4πε₀ (q₁q₂/r₁²)
F₁ = 9 x 10⁹ x (8 x 10⁻⁶ x 3.5 x 10⁻⁶)/(0.1)²
F₁ = 25.2 N
Electrostatic force exerted on the charged particle q₂ by q₃,
F₂ = 1/4πε₀ (q₂q₃/r₂²)
F₂ = 9 x 10⁹ x (3.5 x 10⁻⁶x -2.5 x 10⁻⁶)/(0.15)²
F₂ = -78.75 x 10⁻³/22.5 x 10⁻³
F₂ = -3.5 N
The net electrostatic force acting on the charged particle q₂ is,
F = F₁ - F₂
F = 25.2 - -3.5
F = 25.2 + 3.5
F = 28.7 N
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Find the magnitude and direction of the net gravitational force on mass A due to masses B and
C in the figure. Each mass is 2 kg.
a. 2.8x10^-8N, to the right
b. 2.54x10^-8N, to the right
c. 3.4x10^-8N, to the left
d. 3.4x10^-8N, to the right
Answer is A 2.8 x 10^-8 N, to the right
The net gravitational force on mass A due to masses B and C is required.
The correct option is a. \(2.8\times 10^{-8}\ \text{N}\) to the right.
G = Gravitational constant = \(6.674\times 10^{-11}\ \text{Nm}^2/\text{kg}^2\)
\(r_{AB}\) = Distance between A and B = 0.4+0.1 = 0.5 m
\(r_{AC}\) = Distance between A and C = 0.1 m
\(m_A=m_B=m_c\) = Mass of each particle = 2 kg
The required force is
\(F_A=F_{AB}+F_{AC}\\ =\dfrac{Gm_Am_B}{r_{AB}^2}+\dfrac{Gm_Am_C}{r_{AC}^2}\\ =Gm^2\left(\dfrac{1}{r_{AB}^2}+\dfrac{1}{r_{AC}^2}\right)\\ =6.674\times 10^{-11}\times 2^2\left(\dfrac{1}{0.5^2}+\dfrac{1}{0.1^2}\right)\\ =2.8\times 10^{-8}\ \text{N}\)
The magnitude of force will be \(2.8\times 10^{-8}\ \text{N}\)
The direction will be towards the right since C is closer to A.
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what force Pushes up on an airplane ?
Explanation:
As it flies, a plane is in the center of four forces. Lift (upward force) and thrust (forward push, provided by a propeller) get a plane into the air. Gravity and drag (air resistance, which is friction caused by air rubbing against the plane) try to pull the plane down and slow its speed.hope it helps
What is the momentum of a 82 kg football player moving to the right at 5 m/s?
Answer:
410 kg-m/s
Explanation:
p= momentum
m= mass
v= velocity
p=mv
p= 82kg × 5m/s
p= 410 kg-m/s
An object accelerates 2 m/s2 when an unknown force of 20 N is applied to it. What was the mass of the object?
Answer:
10 kgExplanation:
The mass of an object given only the force acting on it and it's acceleration can be found by using the formula
\(m = \frac{f}{a} \\ \)
f is the force in N
a is the acceleration in m/s²
We have
\(m = \frac{20}{2} = 10 \\ \)
We have the final answer as
10 kgHope this helps you
SI Prefix Meaning
[unit]
deci-
centi-
nano-
Please no links Just tell me the SI Prefix meaning
What does the Abbreviation IFNA, INA and ISSA stands for ?
Answer:
IFNA = International Federation of Nurse Anesthetists.
INA = Information Network Architecture
ISSA = Information Systems Security Association
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A bookshelf is 2 m long, with supports at its ends (P and Q).
a)A book weighing 10 N is placed in the middle of the shelf. What are the upward forces at P and Q?
b)The book is moved so that it is 50 cm from Q. Use moments to calculate P the forces at P and Q.
c)The bookshelf weighs 10 N. Repeat parts b and taking into account
weight of the shelf as well as the weight of the book.
Answer:
a) P + Q = 2 P = 10 N P = Q = 5 N each exerts the same force
b) P x1 = Q x2 if x1 and x2 are not equal (torque about pivot point)
50 Q = 150 P or Q = 3 P balancing torques
Since P + Q = 10 Q = 7.5 N and P = 2.5 N
c) take torques about P
100 * 10 + 100 * 10 = 200 * Q
Q = 10 N P + Q = 20 N upward and the force on the fulcrum in the middle is 10 + 10 = 20 N down (10 N for shelf and 10 N for book)
A force is applied to a 2.4 kg mass and produces 5.1 m/s^2 acceleration. What acceleration would be produced by the same force applied to a 6.2 kg mass?
Answer:
Explanation:
Force = Mass x acceleration = 2.4 x 5.1
If the acceleration is x, then Force is also 6.2x.
Therefore, 2.4 x 5.1 = 6.2x or x = 1.97 ≈ 2.0 m/s²
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A poker is a long thin tool used to move pieces of coal or logs burning in a fire. To be as safe as possible, the poker should be made from a material that
Answer:
See the answer below
Explanation:
A poker that will effectively and safely function to move pieces of coal or logs in a burning fire must be fireproof itself. Hence, to be as safe as possible, such poker should be made from a material that is fireproof and that does not conduct a lot of heat. Otherwise, the poker will catch fire/becomes too hot during the course of usage.
What is the amplitude of the resulting wave when the two waves meet at point X?
A stone is thrown vertically upward from ground level with speed of 25m/s. At what time is it 5m above the ground.
Answer:
The stone will be \(5m\) above the ground in \(2.3s\)
Explanation:
As the stone is thrown vertically upward from ground with speed i.e.,
the initial velocity, \(u=25m/s\),
the final velocity, \(v=0m/s\),
acceleration due to gravity, \(a = -10m/s^2\) (upward motion)
\(v=u+at\\0=25+(-10)t\\0=25-10t\\t=2.5s\)
To calculate the height at which the stone reached above the ground we can use the below formula:
\(s=ut+\frac{1}{2}at^2\)
\(s=25\times2.5+\frac{1}{2}(-10)(2.5)^2\)
\(s=62.5-5\times6.25=62.5-31.25=31.25m\)
Now, the time taken by stone to reach \(5m\) above the ground can be calculated using
\(u=0m/s\\s=31.25-5=26.25m\\a=10m/s^2\\t=?\)
\(s=ut+\frac{1}{2} at^2\\\)
\(26.25=0 \times t+\frac{1}{2} \times 10 \times t^2\)
\(26.25=0+5t^2\)
\(5t^2=26.25\)
\(t^2=\frac{26.25}{5}=5.25\)
\(t=\sqrt{5.25} =2.3s\)
Thus, at \(2.3s\) the stone will reach \(5m\) above the ground.
give any 2 evidence of the unsual expansion of water
Answer:
The anomalous expansion of water is an abnormal property of water whereby it expands instead of contracting when the temperature goes from 4o C to 0o C, and it becomes less dense.
Explanation:
The density is maximum at 4 degree centigrade and decreases below that temperature as shown in graph.
At t=0, a particle leaves the origin with a velocity of 5.0 m/s in the positive y direction. Its acceleration is given by =(3.0i−2.0j ) m/s
2
. At the instant the particle reaches its maximum y coordinate how far is the particle from the origin? 16 m 29 m 19 m 11 m 22 m
The particle is approximately 6.25 meters away from the origin when it reaches its maximum y coordinate.
We know that the particle starts at the origin with an initial velocity of 5.0 m/s in the positive y direction. The acceleration of the particle is given by a = 3.0i - 2.0j m/s².
Since the acceleration has no component in the x-direction (i.e., ax = 3.0 m/s²), the particle's motion in the x-direction is uniform. Therefore, the x-coordinate of the particle remains constant throughout its motion.
To determine the time at which the particle reaches its maximum y coordinate, we need to find the time when the particle's velocity in the y-direction becomes zero. Using the kinematic equation: v = u + at]
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time, we can solve for t:
0 = 5.0 m/s + (-2.0 m/s²)t
-5.0 m/s = -2.0 m/s²t
t = 2.5 s
Therefore, it takes 2.5 seconds for the particle to reach its maximum y coordinate. Now, we can find the maximum y-coordinate using the equation: y = ut + (1/2)at²
y = (5.0 m/s)(2.5 s) + (1/2)(-2.0 m/s²)(2.5 s)²
y = 12.5 m - 6.25 m
y = 6.25 m
The maximum y-coordinate reached by the particle is 6.25 m. To find the distance of the particle from the origin, we can use the Pythagorean theorem, as the x-coordinate remains constant:
distance = √((x² + y²))
distance = √((0² + 6.25²))
distance ≈ 6.25 m
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A 100kg football player is moving at 5.8m/s to the east; a 140kg player is moving at 5.2m/s to the west. They meet, each jumping into the air and grabbing the other player. While they are still in the air, how fast is the pair moving?
The pair of players is moving at 1.0833 m/s to the west (since v_cm is negative).The initial momentum of the system before the players grab each other is:
p_initial = m1v1 + m2v2
= (100 kg)(5.8 m/s) + (140 kg)(-5.2 m/s) (since the second player is moving to the west, his velocity is negative)
= 580 kgm/s - 728 kgm/s
= -148 kg*m/s (to the west)
When the players grab each other and jump into the air, the total mass of the system is 100 kg + 140 kg = 240 kg. Let's assume that they jump with a speed of v_cm relative to the ground, where v_cm is the velocity of the center of mass of the system.
The final momentum of the system is:
p_final = m_total * v_cm
Since there are no external forces acting on the system, the total momentum of the system is conserved:
p_initial = p_final
Therefore:
m1v1 + m2v2 = m_total * v_cm
Solving for v_cm, we get:
v_cm = (m1v1 + m2v2) / m_total
= (100 kg)(5.8 m/s) + (140 kg)(-5.2 m/s) / (100 kg + 140 kg)
= -260 / 240
= -1.0833 m/s
Therefore, the pair of players is moving at 1.0833 m/s to the west (since v_cm is negative).
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A baseball with a mass of 0. 15 kilograms collides with a bat at a speed of 40 meters/second. The duration of the collision is 8. 0 x 103 seconds. The
ball moves off with a speed of 50 meters/second in the opposite direction. What is the value of the force?
The value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.
When an object collides with another object, they exchange energy. For example, a baseball and bat collision or a car collision. When two objects collide, the force of the collision has to be equal on both sides of the collision according to Newton's Third Law. So, to find the value of force, we will apply the equation:
F = ΔP / ΔT
where F is the force, ΔP is the change in momentum, and ΔT is the time of collision. The equation represents the impulse momentum theorem.
Now, let's apply the given values to the above equation.
Final momentum (p2) = mass × final velocity (v2)
p2 = 0.15 kg × (-50 m/s)
p2 = -7.5 kg.m/s
Initial momentum (p1) = mass × initial velocity (v1)
p1 = 0.15 kg × (40 m/s)
p1 = 6 kg.m/s
Change in momentum (ΔP) = p2 - p1
ΔP = -7.5 kg.m/s - 6 kg.m/s
ΔP = -13.5 kg.m/s
Time of collision (ΔT) = 8.0 × 10³ s
Now, putting the values of ΔP and ΔT in the equation of impulse momentum theorem, we get:
F = ΔP / ΔT
F = -13.5 kg.m/s ÷ 8.0 × 10³ s
F = -1.7 × 10⁻³ N
Thus, the value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.
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Alice kicks a soccer ball with a mass of 2 kg. The ball leaves the ground moving 30 meters per second. What is the kinetic energy of the soccer ball? (KE = 1/2mv2)I
By using the formula:
• K.E = ½mv²
mass, m = 2 kgVelocity, v = 30 m/s→ K.E = ½ × 2 × (30)² J
→ K.E = (30)² J
→ K.E = 900 J (Answer)
23 POINTS
Sally and Ann are trying to move a box across the floor. Sally is pushing the box to the right with a force of 100N and Ann is pulling the box with a force of 50N to the right. What is the magnitude and direction of the box?
50N to the left
150N to the right
50N to the right
The box is balanced and will not move
Answer: 150N to the right...
Force acting on the box applied by Sally, F1= 100 N (right side)
Force acting on the box applied by Ann, F2= 50 N (right side)
It is clear that the two forces are acting on same direction. Let right side is positive direction. So, F= F1 + F2
F= 100+50
F=150 N
The direction of the box is towards the right side. So, the correct option is 150 N to the right... Hope this helps... Plz mark me brainliest.... Stay safe and have a great weekend!!! :D
how does the eye control the amount of light entering it?
Answer: Hello there
Explanation:
The colored part of the eye which helps regulate the amount of light entering the eye. When there is bright light, the iris closes the pupil to let in less light. And when there is low light, the iris opens up the pupil to let in more light. Focuses light rays onto the retina.
(b) A cylinder of cross-sectional area 0.65m2 and
height 0.32m has a mass of 2. Ikg. If there is a
cavity inside, find the volume of the cavity.
(Density of cylinder = 11.053 kg/m^3)
Answer:
The volume of the cavity is 0.013m^3
Explanation:
To find the volume of the cavity, the major parameter missing is the diameter of the cavity itself. we can obtain this using the following steps:
Step one:
Obtain the volume of the cylinder by dividing the mass of the cylinder by the density.
Volume of the cylinder = 2.1 / 11.053 =0.19\(m^{3}\)
Step two:
From the volume of the cylinder, we can get the radius of the cylinder.
\(radius = \sqrt{\frac{V}{\pi \times h}} = \sqrt{\frac{0.19}{\pi \times 0.32}} =0.44m\)
Step three:
From the cross-sectional area, we can obtain the radius of the cavity.
Let the radius of the cavity be = r, while the radius of the cylinder be = R
CSA of cavity =
\(\pi({R^2}-r^2) = CSA\\0.65 = \pi (0.32^2-r^2)\\r= 0.115m\)
Step Four:
calculate the volume of the cavity using volume =\(\pi r^2 \times h\)
Recall that the cavity has the same height as the original cylinder
\(volume = \pi \times 0.115^2\times 0.32= 0.013m^3\)
What vocabulary words means an experiment is done without a variable
Answer:
Explanation:
The independent variable of an experiment is the part that the experimenter is changing and can control. The dependent variable is the part of the experiment that is affected by the change.
For example, with a plant, if you water a plant, that is an independent experiment, dependent on you actually watering the plant. The dependent variable is the plant's condition. It is dependent on being watered.
Gwen Goldfish, a speed swimmer, loves to race around the park’s pond, which is 1 kilometer around. If she can swim 20 laps around the track in 2 hours, what is her average speed?
The average speed of swimmer is 10 km/hr.
Speed is the rate of change of position of an object in any direction.
Distance is the total movement of an object without any regard to direction.
Given distance of pond is 1 km.
She swims 20 laps , i.e. total distance = 20 * 1 km = 20 km
Time taken to complete = 2 hr
There a relation between speed distance and time which is given by:
Speed = Distance / Time
⇒Speed = 20/2 = 10 km/hr
So the average speed of swimmer is 10 km/hr.
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A lamp hangs from the ceiling at a height of 2.6 m. The lamp has a mass of 3.8 kg. The screws holding the lamp break, and it falls to the ground. a. How much gravitational potential energy does the lamp have before it falls? b. How much kinetic energy does the lamp have when it reaches the ground? c. How fast is the lamp moving when it hits the ground?
Whoever answers will get the Brainliest.
Answer:
Explanation:
Given height of lamp from the ceiling = 2.6m
mass of the lamp = 3.8kg
acceleration due to gravity = 9.81m/s²
As the body falls to the ground, it falls under the influence of gravity.
Gravitational potential energy = mass*acc due to gravity * height
Gravitational potential energy = 3.8*2.6*9.81
Gravitational potential energy = 96.923 Joules
b) Kinetic energy = 1/2 mv²
m = mass of the body (in kg)
v = velocity of the body (in m/s²)
To get the velocity v, we will use the equation of motion \(v^{2} = u^{2}+2gh\)
\(v^{2} = 0^{2}+2(9.81)(2.6) \\v^{2} = 51.012\\v =\sqrt{51.012}\\ v = 7.14m/s\)
Since mass = 3.8kg
\(K.E = 1/2 * 3.8 *7.14^{2}\\ K.E = 96.86Joules\)
c) To know how fast the lamp is moving when it hits the ground, we will use the formula. When the body hits the ground, the height covered will be 0m. this means that the body is not moving once it hits the ground. It stays in one position. The energy possessed by the body at this point is potential energy. The correct answer is therefore 0 m/s
Two identical cars are driving along the motorway. Car A is travelling at 50 km/h and Car B is travelling at 80km/h. Which car has the most drag acting on it?
Answer:
i think it is car B because the greater the speed, the greater the drag force acting on the vehicle
Explanation:
what is the magnitude of the proton's momentum?
The magnitude for momentum of a proton is 3.67 x 10^-19 kg m/s.
momentum of a proton can be calculated using the formula:
p = mv
where p is the momentum, m is the mass, and v is the velocity.
The mass of a proton is approximately 1.67 x 10^-27 kg. The velocity of the proton would depend on the context in which it is moving.
If, for example, we consider a proton with a kinetic energy of 1 MeV (million electron volts), we can calculate its velocity using the formula:
K = 1/2 mv^2
where K is the kinetic energy.
Therefore:
v = sqrt(2K/m) = sqrt(2(1 MeV)(1.6 x 10^-19 J/MeV)/(1.67 x 10^-27 kg)) = 2.19 x 10^8 m/s
Now we can calculate the momentum:
p = mv = (1.67 x 10^-27 kg)(2.19 x 10^8 m/s) = 3.67 x 10^-19 kg m/s
Therefore, the magnitude of the proton's momentum is approximately 3.67 x 10^-19 kg m/s.
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