Let{sn} be a geometric sequence that starts with an initial index of 0. The initial term is 16 and the common ratio is1/2. What is s3

Answer:

c

Step-by-step explanation:

c

Answer and Step-by-step explanation:

To find out how many more yards of red fabric Reuben used, we need to subtract the amount of yellow fabric from the amount of red fabric. Since the two fractions have different denominators, we need to find a common denominator before subtracting them. The least common multiple of 8 and 4 is 8, so we can rewrite both fractions with a denominator of 8:

7/8 - 1/4 = 7/8 - (1/4) * (2/2) = 7/8 - 2/8 = (7 - 2)/8 = 5/8

So, Reuben used 5/8 yards more red fabric than yellow fabric.

Answer:

B and e

Step-by-step explanation:

The shape is a square.

'A square pyramid is a  three-dimensional geometric shape having a square base and four triangular faces/sides that meet at a single point (called vertex) is called a square pyramid.'

According to the given problem,

If a square pyramid is cut along the plane, then the cross-section of the solid is square. Because it is a square pyramid.

Hence, we concluded that square could be formed by slicing the square pyramid by a plane.

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total angles of the triangle = 180°

∠BAC + ∠ABC + ∠ACB = 180°

40° + 90° + ∠ACB = 180°

130° + ∠ACB = 180°

∠ACB = 180° - 130°

∠ACB = 50°

∠ACB and ∠ECD is opposite angles. So, that two angles are equal.

∠ACD = ∠ECD = 50° (B)

That's it :)

Step-by-step explanation:

50°

abc is right angle and

a is 40°

b is 90°

c is 50°

so angle acb is vertical opposite to angle ecd and it is equal

The volume of the circular cylinder be,

⇒ 62.8 mm³

Given that,

For a circular cylinder,

Height = 5 mm

Radius = 2 mm

Then we have to find the volume of this circular cylinder

Since we know that,

The right circular cylinder is a cylinder with circular bases that are parallel to each other. It's a three-dimensional form. The axis of the cylinder connects the centers of the cylinder's two bases.

This is the most frequent sort of cylinder encountered in daily life. The oblique cylinder, on the other hand, does not have parallel bases and resembles a skewed construction.

volume of circular cylinder = πr²h

Here we have,

r = 2 mm

h = 5 mm

Now put the values into the formula we get,

Volume = π x 2² x 5

             = 62.8 mm³

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Answer:

314 cubic yards

Step-by-step explanation:

\(V_{cylinder} = \pi {r}^{2} h \\ \\ = 3.14 \times {5}^{2} \times 4 \\ \\ = 3.14 \times 25 \times 4 \\ \\ = 3.14 \times 100 \\ \\ = 314 \: {yards}^{3} \)

Answer: 314

Step-by-step explanation: The formula for the volume of a cylinder is V=A*h

\(V=A_{base}\times h\\V=\pi r^2\times h\\V=\pi\times 5^2\times 4\\V= 100\pi\\V=100\times3.14\\V =314 \;yd^3\)

Answer:

2

Step-by-step explanation:

The median is the middle number when the numbers are lined up from least to greatest or greatest to least.

First, the numbers must be lined up from least to greatest.

0, 0, 1, 1, 2, 2, 2, 2, 2, 3, 3, 3, 4, 5, 6

Then, find the middle number.

The middle number is 2.

Answer:

Step-by-step explanation: true

Answer:

m=21

Step-by-step explanation:

based on the dilation from 'ABC' to 'QRS' (which is 3) m should =21

hope this helps! :)

Answer:

Step-by-step explanation:

Ar of circle

A= 49π

B=100π

C=169π

D=121π

Ar of circle A is less than Ar of circle D

Check the picture below.

By using the Unitary Method we get the number of children who went on an excursion was 63. Thus, the total number of children at school is 90.

We are given that,

No. of children who stayed at school is 27,

Also, 70% of the children went on an excursion.

Suppose, the total number of children in percentage is 100%

Out of which 70% went on an excursion

Thus, the children who stayed at school is 100% - 70% = 30%

By using the Unitary method, we can find out the number of 70% of children.

If 30% of the children are 27

Then 70% of the children are = 27 × 100

                                                        30

                                                 = 63

∴ the total no. of children in the school = 27 + 63

                                                                 = 90

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Answer:

x = 15

Step-by-step explanation:

create a proportion:   x + 10 = x + x + 10

                                       5               8

cross-multiply:  8(x + 10) = 5(2x + 10)

                          8x + 80 = 10x + 50

                                  80 = 2x + 50

                                  30 = 2x

                                   15 = x

a) The initial deposit in the account is given as follows: 1,287.39 euros.

b) The interest rate of the account is given as follows: 3%.

The equation that gives the balance of an account after t years, considering simple interest, is modeled as follows:

A(t) = P(1 + rt).

In which the parameters of the equation are listed and explained as follows:

Considering the balances after 5 and 6 years, the interest rate is obtained as follows:

r = 1524.60/1480.50 - 1

r = 0.03.

Considering the balance after 5 years, the initial deposit is obtained as follows:

P(1 + 0.03 x 5) = 1480.5

P = 1480.5/1.15

P = 1,287.39 euros.

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The coordinates of the given equation -4x + 2y = -30  and 5x + 5y = 10 are x = 17 and y = 19

Coordinates are a collection of numbers that shows a point's precise place on the coordinate plane. A coordinate plane is also called as 2D plane that is made by the junction of the x-axis and y-axis, two perpendicular lines.

The given equations are as follows:

-4x + 2y = -30   ---- 1-

5x + 5y = 10     ----2

By solving and simplifying two equations, we get

-2x + y = -15-x + y = 2

On substituting ,y = 2 + x

-2x + (2+x) =  -15

- x = -17x

    = 17

So , y = 2 + x

         = 2 + 17

         = 19

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Answer:

i think the answer is C or D:)

The complete inequality is y < x and y< -x

The expressions are given as:

y[ ]x and y[ ]-x

From the graph, we can see that:

Only the lower regions are shaded

This represents the less than inequality sign

Hence, the complete inequality is y < x and y< -x

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Answer:

.95

Step-by-step explanation:

Answer:

q≤=-8

Step-by-step explanation:

5 + q ≤ -3

5+(5 + q ≤ -3)

q ≤ -3-5

q ≤-8

Answer:

21.5

Step-by-step explanation:

The area of the shaded region is 21.5 mm².

Area of a two dimensional shape is the total region which is bounded by the object's shape.

Given is a circle inside a square.

Area of a square = a², where 'a' is the side length.

Here, a = 10 mm

Area of square = 10² = 100 mm²

Area of a circle = π r², where r is the radius of the circle.

Diameter of circle = 10 mm

Radius of the circle = 10/2 = 5 mm

Area of the circle = (3.14) (5²) = 78.5 mm²

Area of the shaded region = Area of square - Area of circle

                                             = 100 mm² - 78.5 mm²

                                             = 21.5 mm²

Hence the area is 21.5 mm².

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Since the total of the inner angles of the rhombus is 360 degrees, the angle mV has a value of 90.

In Euclidean geometry, an angle is a shape made up of two rays, referred to as the angle's sides, that come together at a point in the middle known as the angle's vertex. An angle that is in the plane where the rays are placed can be created by two rays. An angle is also produced when two planes collide. They are known as dihedral angles. In planar geometry, an angle is the form produced by two rays or lines that share a termination. The English word "angle" comes from the Latin word "angulus," which means "horn." The vertex, also known as the sides of the angle, is where the two rays' common terminals meet.

given

m∠V + m∠W + m∠X + m∠Y = 360

10x -27 + 2x + 19 = 180

12x - 8 = 180

188 = 12x

x = 15.66

m∠V + m∠X = 180

2x = 180

x = 90

Since the total of the inner angles of the rhombus is 360 degrees, the angle mV has a value of 90.

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The simplification of the expressions in the question using the rules of indices are as follows;

1.) 6·e⁰ + (11·f)⁰ - 5/g⁰ = 2

2. (3⁻⁴ + 5⁻³)⁻¹ = \(49\frac{31}{206}\)

3. (3⁻⁴ + 5⁻³)⁻² = \(2415\frac{32685}{42436}\)

4.) \(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5} \right)^{-3}}{10\cdot c^{-5} \cdot d^6 \cdot e^{-8}}\) = \(\dfrac{c^5\cdot e^8}{2\cdot d^5}\)

5.)  \(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5}\right)^{-3 }}{7\cdot \left(p^{-6} \cdot q^8\right)^{-4}} =\dfrac{-5\cdot m^{12}\cdot n^{15}\cdot q^{32}}{7\cdot p^{24}}\)

An index or indices is the power by which a number or variable or expression raised.

1.) 6·e⁰ + (11·f)⁰ - 5/g⁰

6·e⁰ + (11·f)⁰ - 5/g⁰ = 6 × 1 + 1 - 5/1

6 × 1 + 1 - 5/1 = 6 + 1 - 5 = 2

Therefore;

6·e⁰ + (11·f)⁰ - 5/g⁰ = 2

2.) (3⁻⁴ + 5⁻³)⁻¹

(3⁻⁴ + 5⁻³)⁻¹ = (1/(3⁴) + 1/(5³))⁻¹ = 1/(1/(3⁴) + 1/(5³))

1/(1/(3⁴) + 1/(5³)) = 1/(1/81 + 1/125) = 1/((125 + 81)/(81×125))

1/((125 + 81)/(81×125)) = (81 × 125)/(125+81) = 10125/209

10125/206 = 49 + 31/206

(3⁻⁴ + 5⁻³)⁻¹ = \(49 \frac{31}{206}\)

3.) (3⁻⁴ + 5⁻³)⁻²

(3⁻⁴ + 5⁻³)⁻² = 1/((1/3⁴ + 1/5³)²)

1/((1/3⁴ + 1/5³)²) = 1/((1/81 + 1/125)²)

1/((1/81 + 1/125)²) = 1/(((125 + 81)/(81 × 125))²)

1/(((125 + 81)/(81 × 125))²) = 1/((206/10125)²)

1/((206/10125)²) = (10125)²/(206)² = 102515625/42436

102515625/42436 = 2415 32685/42436

(3⁻⁴ + 5⁻³)⁻² = \(2415\frac{32685}{42436}\)

4.)  \(\dfrac{5\cdot (2\cdot a^{-1}\cdot b^3)^0}{10\cdot c^{-5}\cdot d^6\cdot e^{-8}}\)

\(\dfrac{5\cdot (2\cdot a^{-1}\cdot b^3)^0}{10\cdot c^{-5}\cdot d^6\cdot e^{-8}} = \dfrac{5\times 1}{10\times \left(\frac{1}{c^5}\times d^6 \times \frac{1}{e^8} \right) }\)

\(\dfrac{5\times 1}{10\times \left(\frac{1}{c^5}\times d^6 \times \frac{1}{e^8} \right) } = \dfrac{5}{10\times \left(\frac{d^6}{c^5\times e^8} \right) }\)

\(\dfrac{5}{10\times \left(\frac{d^6}{c^5\times e^8} \right) } = \dfrac{1}{2\times \left(\frac{d^6}{c^5\times e^8} \right) }\)

\(\dfrac{1}{2\times \left(\frac{d^6}{c^5\times e^8} \right) } = \dfrac{c^5\times e^8}{2\cdot d^6}\)

\(\dfrac{5\cdot (2\cdot a^{-1}\cdot b^3)^0}{10\cdot c^{-5}\cdot d^6\cdot e^{-8}}= \dfrac{c^5\times e^8}{2\cdot d^6}\)

5.) \(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5} \right)^{-3}}{7\cdot \left(p^{-6}\cdot q^8\rright)^{-4}}\)

\(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5} \right)^{-3}}{7\cdot \left(p^{-6}\cdot q^8\right)^{-4}} =\dfrac{-5\cdot \dfrac{1}{\left(\frac{1}{m^{4}}\times \frac{1}{n^{5}} \right)^{3}} }{7\cdot \dfrac{1}{\left(\frac{1}{p^{6}}\times q^8\right)^{4}} }\)

\(\dfrac{-5\cdot \dfrac{1}{\left(\frac{1}{m^{4}}\times \frac{1}{n^{5}} \right)^{3}} }{7\cdot \dfrac{1}{\left(\frac{1}{p^{6}}\times q^8\right)^{4}} } = \dfrac{-5\cdot {\left(m^4\times n^5\right)^3} }{7\cdot \left( \dfrac{p^6}{q^8\right)^{4}} }\)

\(\dfrac{-5\cdot {\left(m^4\times n^5\right)^3} }{7\cdot \left( \dfrac{p^6}{q^8\right)^{4}} } = \dfrac{-5\cdot {\left(m^{12}\times n^{15}\right)} }{7} \times \left(\dfrac{q^8}{p^6}\right)^4 }\)

\(\dfrac{-5\cdot {\left(m^{12}\times n^{15}\right)} }{7} \times \left(\dfrac{q^8}{p^6}\right)^4 } = \dfrac{-5\cdot {\left(m^{12}\times n^{15}\right)} }{7} \times \left(\dfrac{q^{32}}{p^{24}}\right) }\)

\(\dfrac{-5\cdot {\left(m^{12}\times n^{15}\right)} }{7} \times \left(\dfrac{q^{32}}{p^{24}}\right) } = \dfrac{-5\times {m^{12}\times n^{15}\times q^{32}} }{7\times p^{24}}\)

\(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5} \right)^{-3}}{7\cdot \left(p^{-6}\cdot q^8\right)^{-4}} = \dfrac{-5\times {m^{12}\times n^{15}\times q^{32}} }{7\times p^{24}}\)

6.) (3·x⁻⁴·y⁻⁵·z⁻²)⁻²

(3·x⁻⁴·y⁻⁵·z⁻²)⁻² = \(3\cdot \left(\dfrac{1}{\left(\dfrac{1}{x^4} \cdot \dfrac{1}{y^5} \cdot \dfrac{1}{z^2} } \right)^2\right)\)

\(3\cdot \left(\dfrac{1}{\left(\dfrac{1}{x^4} \cdot \dfrac{1}{y^5} \cdot \dfrac{1}{z^2} } \right)^2\right) = 3\cdot \left(x^4\cdot y^5\cdot x^2\right)^2\)

3·(x⁴·y⁵·x²)² = 3·x⁸·y¹⁰·x⁴

Therefore;

(3·x⁻⁴·y⁻⁵·z⁻²)⁻² = 3·x⁸·y¹⁰·x⁴

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a) The mean of the data-set is of 2.

b) The range of the data-set is of 4 units, which is of around 4.3 MADs.

The mean of a data-set is obtained as the sum of all observations in the data-set divided by the number of observations in the data-set, which is also called the cardinality of the data-set.

The dot plot shows how often each observation appears in the data-set, hence the mean of the data-set is obtained as follows:

Mean = (1 x 0 + 5 x 1 + 3 x 2 + 5 x 3 + 1 x 4)/(1 + 5 + 3 + 5 + 1)

Mean = 2.

The range is the difference between the largest observation and the smallest, hence:

4 - 0 = 4.

4/0.93 = 4.3 MADs.

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