leave answer in simplest radical form

Answer:

The table represents a nonlinear function because the rate is not constant.

Step-by-step explanation:

As shown in the picture below, the x side of the table has the same rate of change of +1. However, due to the fact that the y side does not have the same rate of change, +6 and +3, the table represents a non linear function. If the rate on the y side of the table were all the same, then this would be a Linear function.

Answer:

goof job tatatatstfndndbjxx

The fraction that names one part of the granola bar shared by Tiana and her 3 brothers is c. 1 / 4.

Tiana has 3 brothers and they all shared a piece of the granola bar. This means that the number of people who shared the granola bar is:

= Tiana + 3 brothers

= 4 people

With each of them getting a piece of the granola bar, it means that the fraction that names one part of the bar is:
= Number of granola bars / Number of people

= 1 / 4

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The full question is:

Tiana shares a granola bar with her 4 brothers. They each get one piece of the bar. What fraction names one part?

Answer:

100.48

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h where r is the radius and h is the height

V = 3.14 ( 2)^2 * 8

V = 3.14 (4)(8)

V = 100.48

The equation of the line in fully simplified slope-intercept form is y = x + 7.

We have,

From the graph,

The coordinates of the line are:

(0, 7), (-7, 0), and (-2, 5).

We can use any coordinates the line touches on the graph.

We will use,

(0, 7) and (-7, 0)

The equation can be written in the form y = mx + c

m = (0 - 7) / (-7 - 0)

m = -7/-7

m = 1 ______(1)

And,

(0, 7) = (x, y)

So,

y = mx + c ______(2)

7 = 1 x 0 + c

7 = c

c = 7 ______(3)

Now,

From (1), (2), and (3).

y = x + 7

Thus,

The equation of the line in fully simplified slope-intercept form is y = x + 7.

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Answer:

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = 0.5445

Step-by-step explanation:

Step(i):-

Given mean of the Population μ = 5.3 days

Given standard deviation of the population 'σ' = 2 days

Let 'X' be the random variable in normal distribution

Let    x₁ = 4

\(Z_{1} = \frac{x_{1}-mean }{S.D} = \frac{4-5.3}{2} = -0.65\)

Let    x₂ = 7

\(Z_{2} = \frac{x_{2}-mean }{S.D} = \frac{7-5.3}{2} = 0.85\)

Step(ii):-

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = P(-0.65≤Z≤0.85)

             =  P(Z≤0.85) - P(Z≤-0.65)

            = 0.5 + A( 0.85) - ( 0.5 - A(-0.65)

            = 0.5 + A( 0.85) -  0.5 +A(0.65)   ( ∵A(-0.65) = A(0.65)

           =   A(0.85) + A(0.65)

          = 0.3023 + 0.2422

         = 0.5445

Final answer:-

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = 0.5445

Answer:

NO.

Step-by-step explanation:

The Professor's hypothesis:

An introductory course in Logic will affect college students with their other studies (will affect their Great Point Average - GPA).

25 students are used as the experimental group while the rest of the class are the control group.

The mean GPA in a sample size (SS) of 6 is = 2.58

The mean GPA in the full sample size of 25 would be = 10.75 by crossmultiplying.

This makes me believe the question was written wrongly. I assume SD (standard deviation) of 0.6 instead of SS (sample size) of 6.

Going by this, if standard deviation is 0.6 then the interval within which the GPA of the experimental group (the 25 students) falls is:

[2.58 - 0.6] to [2.58 + 0.6]

= 1.98 to 3.18

The rest of the graduating class (the control group) had a mean GPA of 2.33

Can the professor conclude that the GPA for the sample is significantly different from that of the control group?

The answer is NO because the GPA of the control group falls within the GPA interval of the experimental group!

Answer:

AOB=40°

COD=90°

BOD=130°

AOD=180°

The median of the given data set is 26.

In statistics and probability theory, the median is the value separating the higher half from the lower half of a data sample, a population, or a probability distribution. For a data set, it may be thought of as "the middle" value.

Given the data set, we need to find the median.

So, let's arrange the numbers from smallest to largest in order to find the median.

\(\sf 15,20,22,26,28,35,36.\)

\(\text{Median}=\sf 26\)

Therefore, the median of the data set is 26.

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Answer:

the answer is D

Step-by-step explanation:

x = 24.0 , y = 46.4

Answer:

(x+8) ² + \(y^{2}\) = 64

Answer:IT WOULD BE 60.00

Step-by-step explanation:

BC 40 = 60

Answer:

1/4

Step-by-step explanation:

Probability = successes / all events

Odds = successes / failures

If the probability is 1/5, then there's 1 success for every 4 failures.

So the odds are 1/4.

\(\cfrac{12}{16}\implies \cfrac{4\cdot 3}{4\cdot 4}\implies \cfrac{4}{4}\cdot \cfrac{3}{4}\implies 1\cdot \cfrac{3}{4}\implies \boxed{\cfrac{3}{4}}~\hfill \cfrac{8\cdot 3}{8\cdot 4}\implies \boxed{\cfrac{24}{32}}\)

The function f(x) = -2(4)ˣ⁺¹ +140 represents the number of tokens a child has x hours after arriving at an arcade. The practical domain and range of the function are x ≥ 0 and The practical range of the situation is [140, ∞).

The given function is f(x) = -2(4)ˣ⁺¹+ 140, which represents the number of tokens a child has x hours after arriving at an arcade.

To determine the practical domain and range of the function, we need to consider the constraints and limitations of the situation.

For the practical domain, we need to identify the valid values for x, which in this case represents the number of hours the child has been at the arcade. Since time cannot be negative in this context, the practical domain is x ≥ 0, meaning x is a non-negative number or zero.

Therefore, the practical domain of the situation is x ≥ 0.

For the practical range, we need to determine the possible values for the number of tokens the child can have. Looking at the given function, we can see that the term -2(4)ˣ⁺¹represents a decreasing exponential function as x increases. The constant term +140 is added to shift the graph upward.

Since the exponential term decreases as x increases, the function will have a maximum value at x = 0 and approach negative infinity as x approaches infinity. However, due to the presence of the +140 term, the actual range will be shifted upward by 140 units.

Therefore, the practical range of the situation will be all real numbers greater than or equal to 140. In interval notation, we can express it as [140, ∞).

To summarize:

- The practical domain of the situation is x ≥ 0.

- The practical range of the situation is [140, ∞).

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We know that z varies directly as √√x and inversely as y, which can be written as:

z = k(√√x)/y

where k is the constant of proportionality.

To find the value of k, we can use the values given when x = 25 and y = 7:

179 = k(√√25)/7

179 = k(5/7)

k = (179*7)/5

k = 250.6

Now we can use this value of k to find z when x = 64 and y = 4:

z = 250.6(√√64)/4

z = 250.6(2)/4

z = 125.3

Therefore, z ≈ 125.3 when x = 64 and y = 4.

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                             \(HELLO! :)\)

Answer:

the answer of this question is rs99

Answer:

2.221992

Step-by-step explanation:

can i have the crown pls ૮ ♡ﻌ♡ა

Answer:

2.221

Step-by-step explanation:

Answer:

\( {f}^{ - 1} (x) = 2x - 8\)

\( {f}^{ - 1} (4) = 0\)

Step-by-step explanation:

\( y = \frac{1}{2} x + 4 = = = > \\y - 4 = \frac{1}{2} x = = = > \\ 2y - 8 = x = = > {f}^{ - 1} (x) = 2x - 8\)

\( \frac{1}{2} x + 4 = 4 = = = > \\ \frac{1}{2} x = 0 = = = > x = 0\)

Answer:

3

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

PEMDAS

14-8+6+4-11

14-8=6

6+6=12

12+4=16

16-11=5

1) There are 3.4 * 10^1 in Mexico than in Canada.

2) The number of ounces that were consumed is 20.8 * 10^7 ounces

3) The number of ounces of the students at the community college is 1.25 * 10^1 that of the students in the University.

Scientific notation is a way of writing very large or very small numbers using powers of 10. In scientific notation, a number is written as a coefficient multiplied by 10 raised to a power.

1) Ratio of people in Mexico to those in Canada;

1.3 * 10^8/3.8 * 10^7

= 3.4 * 10^1 : 1

2) Number of Ounces consumed by students = 5.2 * 10^4 * 4 * 10^3

= 20.8 * 10^7 ounces

3) Ratio of the number drank by community college to University

= 4 * 10^3/3.2 * 10^2

1.25 * 10^1

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1. Andy's oldest daughter ate the most pizza. She ate the entire personal pizza, which is 10 inches in diameter

2. If the company offered an extra large pizza, you could find out how much of it a person ate if they cut their own piece with a central angle of M°

Andy's oldest daughter ate the most pizza. She ate the entire personal pizza, which is 10 inches in diameter. This means that she ate 100% of the pizza. Andy's wife ate 2/6 of the small pizza, which is 12 inches in diameter. This means that she ate 1/3 of the pizza. Andy's younger daughter ate 1/8 of the medium pizza, which is 14 inches in diameter.

This means that she ate 12.5% of the pizza. Andy cut himself a piece that had a central angle of 180° from the large pizza, which is 16 inches in diameter. This means that he ate 50% of the pizza.

The least amount of pizza was eaten by Andy's younger daughter. She only ate 1/8 of the medium pizza.

2. If the company offered an extra large pizza, you could find out how much of it a person ate if they cut their own piece with a central angle of M° by using the following formula:

Percentage of pizza eaten = (M° / 360°) * 100%

For example, if a person cut themselves a piece of an extra large pizza with a central angle of 180°, they would have eaten 50% of the pizza.

Percentage of pizza eaten = (180° / 360°) * 100% = 50%

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Answer:

47

Step-by-step explanation: if you're add 6 and 7 you get 13 so just add all the numbers and you get the answer

Answer:

\(113m^{2}\)  

I hope this helps!

Answer:

Each decent was 500 meters

Step-by-step explanation:

I found the slope

Each decent was 500 meters.

The slope is a line that defines the direction and the steepness. Slope is defined in many ways. Slope is also equal to tanQ additionally, slope = dy/dx

Finding the slope :

8000/1600=5

1000/200=5.

Each decent was 500 meters.

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Answer:

m = 5

Step-by-step explanation:

A quadratic function is in the form \(ax^{2} +bx+c\).

To factor an equation, you are looking for two numbers that multiply to c (are factors of c), and add to b. In this case, c = -15, and b = 2.

The factors of -15 include 1, 3, 5, 15, -1, -3, -5, and -15.

After looking through the possible combinations, we can come to the conclusion that the only factors that multiply to -15 and add to 2 are 5 and -3, as 5 x -3 = -15, and 5 + -3 = 2.

You can now plug these numbers into the factored form (x + factor1)(x + factor2).

This then becomes (x + -3)(x + 5) or (x - 3)(x + 5).

Therefore, m = 5.

Answer:

3079144

Step-by-step explanation:

Answer:

The amounts of salt in the tank at any time prior to the instant when the solution begins to overflow is.

        \(Q(t)=-\frac {4\times 10^6}{(200+t)^2}+200+t\)

Step-by-step explanation:

Let Q(t) be the  amount of salt in the tank at any time \(t\).

Then, its time of change, \(Q'(t)\) by (Balance law).

Since three gallons of salt water runs in the tank per minute, containing \(1\) lb of salt, the salt inflow rate is

                              \(3\cdot 1=3\)

The  amount of water in the tank at any time \(t\) is,

                     \(V(t)=200+(3-2)t=200+t,\)

Now, the outflow is \(2\) gal of the solution in a minute. That is \(\frac 2{200+t}\) of the total solution content in the tank, hence \(\frac 2{200+t}\) of the salt salt content \(Q(t)\), that is \(\frac {2Q(t)}{200+t}\),

Initially, the tank contains \(100\) lb of salt,

Therefore, we obtain the initial condition   \(Q(0)=100\)

Thus, the model is

                   \(Q'(t)=3-\frac {2Q(t)}{200+t}, \;\;Q(0)=100\)

                 \(\Rightarrow Q'(t)+\frac {2}{200+t}Q(t)=3, \;\;Q(0)=100\)

            here, \(p(t)=\frac 2{200+t}\;\; \text{and}\;\; q(t)=3\) Linear ODE

So, the integrating factor is

      \(e^{\int pdt}=e^{2\int \frac{dt}{200+t}=e^{\ln(200+t)^2}=(200+t)^2\)

and the general solution is

            \(Q(t)(200+t)^2=\int q(t)(200+t)^2dt+c\)

          \(\Rightarrow Q(t)=\frac 1{(200+t)^2}\int 3(200+t)^2dt+c\)

                     \(=\frac c{(200+t)^2}+200+t\)

using initial condition and find the value of constant c.

      \(100=Q(0)=\frac c{(200+0)^2}+200+0\Rightarrow -100=\frac c{200^2}\)

                                                     \(\Rightarrow c=-4000000=-4\times 10^6\)

          \(\Rightarrow Q(t)=-\frac {4\times 10^6}{(200+t)^2}+200+t\)

Hence, is the amount of salt in the tank at any moment t.