Lava is rock that has undergone a physical change and has liquefied. What is known about this change?
The lava gained mass.
The lava was burned into smoke.
The lava can cool back into rock.
The lava lost mass.

The equilibrium constant Kp for this reaction is 1.03×10^(-5) atm.

What is equilibrium constant?

The equilibrium constant, represented by K, is a quantitative measurement of the extent to which a chemical reaction has reached equilibrium. It describes the ratio of the concentrations (or partial pressures) of the products and reactants at equilibrium, with each concentration raised to a power equal to its coefficient in the balanced chemical equation.

We can use the relationship between Kp and Kc to solve this problem:

Kp = Kc(RT)^(Δn)

where R is the gas constant, T is the temperature in Kelvin, and Δn is the change in the number of moles of gas between the products and the reactants.

First, let's find Δn:

Δn = (moles of gas in products) - (moles of gas in reactants)

Δn = (2 moles) - (3 moles)

Δn = -1

Next, we can plug in the values and solve:

Kp = Kc(RT)^(-1)

Kp = (2.1)((0.0821 L·atm/mol·K)(295 K))^(-1)

Kp = 1.03×10^(-5) atm

Therefore, the equilibrium constant Kp for this reaction is 1.03×10^(-5) atm.

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Answer:

Answer:

Use 2,4-dinitrophenylhydrazine ( Brady's reagent )

Observations;

• Heptanol → No observable change

• Heptanal → Orange solution is formed.

Use Sodium Hydrogen nitrite solution

Observation;

• Heptanol → No observable change

• Heptanal → A white precipitate is formed

Explanation:

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The dissociation of cadmium chloride is as follows: CdCl₂(s) → Cd⁺²(aq) + 2Cl⁻(aq)

Dissociation is the process by which a compound body breaks up into simpler constituents; said particularly of the action of heat on gaseous or volatile substances.

It is a chemical reaction in which a compound breaks apart into two or more components. The general formula for a dissociation reaction follows the form:

AB → A + B

According to this question, cadmium chloride undergoes dissociation into cadmium and chlorine ions as follows:

CdCl₂(s) → Cd⁺²(aq) + 2Cl⁻(aq)

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Answer:

2.282 atm

P1V1/T1 = P2V2/T2

2.70atm / (50+273) = X/ 273

make x subject of formula

:. X = 2.28 atm

or 2.28 * 1.01 *10⁵ N/m²

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Answer:

Hydrochloric acid + zinc = zinc chloride + hydrogen gas

sulfuric acid + magnesium oxide = zinc sulfate + water

nitric acid + lead carbonate = Lead nitrate + carbon dioxide

Sorry can't remember how to do the last one :(

Explanation:

The peroxide addition would yield a product that is different from the antiperoxide addition

Markovnikov's rule states that when a protic acid HX is added to an alkene, the acid hydrogen (H) forms a bond with the carbon atom that has the greatest number of hydrogen atoms, while the halide (X) group forms a bond with the carbon atom that has the fewest hydrogen atoms.

This can be summed up with the phrases "the rich get richer" and "the poor get poorer" in terms of hydrogen. This fundamental principle of alkene chemistry aids in predicting the results of addition reactions.

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Answer: Upper Case Alleles

Explanation: Lower case alleles are recessive

This element is in group 1.

According to the octet rule, this element would be expected to form an ion with a charge of +1.

If X is in period 5, the ion formed has the same electron configuration as the noble gas Krypton

The symbol for the ion is Rb⁺

Electronic configuration refers to the arrangement of electrons in the orbitals of an atom or molecule, indicating the energy level of the electrons, the number of electrons in each energy level, and the number of electrons in each orbital.

Considering the given element:

It has one valence electron, hence it is in group 1. Group 1 elements form ions with a charge of +1.

Losing one electron will give the ion the same electron configuration as Kyrton since it is the noble gas in Period 4.

The element is rubidium and the ion is Rb⁺.

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10 milliliters of 0.050 M EDTA are required to react with both 50.0 mL of 0.010 M Ca2+ and 50.0 mL of 0.010 M Al3+.

The balanced equation for the reaction between EDTA and metal ions is as follows:

Ca2+ (aq) + EDTA (aq) → CaEDTA (complex)

Al3+ (aq) + EDTA (aq) → AlEDTA (complex)

Moles of Ca2+:

moles of Ca2+ = concentration of Ca2+ x volume of Ca2+ solution

moles of Ca2+ = 0.010 M x (50.0 mL / 1000 mL)

moles of Ca2+ = 0.010 M x 0.050 L

moles of Ca2+ = 0.0005 moles

Moles of Al3+:

moles of Al3+ = concentration of Al3+ x volume of Al3+ solution

moles of Al3+ = 0.010 M x (50.0 mL / 1000 mL)

moles of Al3+ = 0.010 M x 0.050 L

moles of Al3+ = 0.0005 moles

The stoichiometry of the reaction tells us that 1 mole of Ca2+ or Al3+ reacts with 1 mole of EDTA. Therefore, the moles of EDTA required are also 0.0005 moles.

Volume of 0.050 M EDTA:

moles of EDTA = concentration of EDTA x volume of EDTA solution

0.0005 moles = 0.050 M x volume of EDTA solution

volume of EDTA solution = 0.0005 moles / 0.050 M

volume of EDTA solution = 0.01 L = 10 mL

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1. The IUPAC name of N is nitrogen.

2. Nitrogen dioxide

3.The IUPAC name of O is oxygen

4.The IUPAC name of OH is hydroxyl.

The IUPAC name of ·0 is a radical. It is commonly found in organic chemistry and plays an important role in many reactions.

IUPAC names for the given compounds are:1.1. N: Nitrogen

The IUPAC name of N is nitrogen.

It is a non-metal and belongs to group 15 in the periodic table. It has an electronic configuration of 1s2 2s2 2p3.1.2. NO2: Nitrogen dioxide

Explanation: NO2 is a chemical compound that is formed by the combination of nitrogen and oxygen. It is a reddish-brown gas that has a pungent odor.

The IUPAC name of NO2 is nitrogen dioxide.1.3. O: Oxygen

Explanation: The IUPAC name of O is oxygen.

It is a non-metal and belongs to group 16 in the periodic table. It has an electronic configuration of 1s2 2s2 2p4.

X: UnknownExplanation: No IUPAC name can be given to an unknown compound as the structure and composition are not known.

Y: Hydroxyl Explanation: The IUPAC name of OH is hydroxyl.

It is a functional group that is composed of an oxygen atom and a hydrogen atom (-OH). It is commonly found in alcohols and phenols. ·0: RadicalExplanation: A radical is a molecule or an ion that contains an unpaired electron.

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Note: The complete question is given below

Provide the IUPAC names for the following compounds:

\(CH_3CH_2CH(CH_3)CH_2CH_2CH_2CH_3\)

C6H5CH(CH3)2

H2NCH2CH2CH2CH2CH2NH2

CH3CH2CH2CH2CH2OH

CH3CH2CH2CHOHCH3

There are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.

To determine the number of moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3, we need to consider the stoichiometry of the compound.

The formula of aluminum sulfate (Al2(SO4)3) indicates that for every 1 mole of the compound, there are 2 moles of aluminum ions (Al3+). This means that the mole ratio of Al3+ to Al2(SO4)3 is 2:1.

Given that we have 0.42 mol of Al2(SO4)3, we can calculate the moles of Al3+ as follows:

Moles of Al3+ = 0.42 mol Al2(SO4)3 x (2 mol Al3+ / 1 mol Al2(SO4)3)

Moles of Al3+ = 0.42 mol Al2(SO4)3 x 2

Moles of Al3+ = 0.84 mol Al3+

Therefore, there are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.

It's important to note that the stoichiometry of the compound determines the mole ratio between the different species involved in the chemical formula. In this case, the 2:1 ratio of Al3+ to Al2(SO4)3 allows us to determine the number of moles of Al3+ based on the given amount of Al2(SO4)3.

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The volume of O₂ produced when 8.52 g of Na₂O₂ is added to excess water is approximately 1.17 liters at STP.

When it comes to the ideal gas law, the underlying assumption is that the gas is in a state of thermodynamic equilibrium. This means that its molecules are not interacting with each other except through perfectly elastic collisions.

Equation:

We can use stoichiometry to determine the volume of oxygen gas produced from the reaction of 8.52 g of Na₂O₂.

First, we need to convert the mass of Na₂O₂ to moles using its molar mass:

8.52 g Na₂O₂ × (1 mol Na₂O₂ / 77.98 g Na₂O₂) = 0.1093 mol Na₂O₂

According to the balanced chemical equation, 1 mole of Na₂O₂ produces 1/2 mole of O₂:

2 Na₂O₂ + 2 H₂O → 4 NaOH + O₂

1 mol Na₂O₂ produces 1/2 mol O₂

So, the number of moles of O₂ produced is:

0.1093 mol Na₂O₂ × (1/2 mol O₂ / 1 mol Na₂O₂) = 0.05465 mol O₂

Finally, we can use the ideal gas law to determine the volume of O₂ produced at standard temperature and pressure (STP), which is defined as 0°C (273 K) and 1 atmosphere (1 atm) of pressure:

PV = nRT

At STP, the pressure and temperature are known, so we can rearrange the equation to solve for V:

V = nRT / P

Plugging the values, we get:

V = (0.05465 mol) × (0.08206 L atm mol⁻¹ K⁻¹) × (273 K) / (1 atm)

V ≈ 1.17 L

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The average atomic mass of the element is 12.0107 amu.

To calculate the average atomic mass of the element in question, we can use the following formula:

average atomic mass = (mass of isotope 1 x abundance of isotope 1) + (mass of isotope 2 x abundance of isotope 2)

where "mass of isotope 1" is the mass of the first stable isotope (13 amu in this case), "abundance of isotope 1" is the percentage of that isotope in the element (1.07% in this case), "mass of isotope 2" is the mass of the second stable isotope (12 amu in this case), and "abundance of isotope 2" is the percentage of that isotope in the element (98.93% in this case).

Substituting the given values in the formula, we get:

average atomic mass = (13 amu x 1.07%) + (12 amu x 98.93%)

average atomic mass = (0.1391 amu) + (11.8716 amu)

average atomic mass = 12.0107 amu

Therefore, the average atomic mass of the element is 12.0107 amu.

This means that on average, one atom of this element weighs 12.0107 atomic mass units (amu), which is slightly heavier than the most abundant isotope (12 amu) due to the presence of the less abundant isotope (13 amu). This concept is important in chemistry because the mass of atoms plays a crucial role in determining their chemical and physical properties. The knowledge of the average atomic mass of an element is important in a wide range of applications, including analytical chemistry, geochemistry, and nuclear physics.

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Answer:

The oxygen atom in water has a negative charge.

Polar molecule: A molecule in which the centroid of the positive charges is different from the centroid of the negative charges.

Oxygen: A colorless, odorless, gaseous element constituting about one-fifth of the volume of the atmosphere and present in a combined state in nature. It is the supporter of combustion in air and was the standard of atomic, combining, and molecular weights until 1961, when carbon 12 became the new standard. Symbol: O; atomic weight: 15.9994; atomic number: 8; density: 1.4290 g/l at 0°C and 760mm pressure.

Water: A transparent, odorless, tasteless liquid, a compound of hydrogen and oxygen, H2O, freezing at 32°F or 0°C and boiling at 212°F or 100°C. that in more or less impure state constitutes rain, oceans, lakes, rivers, etc.: it contains 11.188 percent hydrogen and 88.812 percent oxygen, by weight.

Hydrogen: A colorless, odorless, flammable gas that combines chemically with oxygen to form water: the lightest of the known element. Symbol: H; atomic weight: 1.00797; atomic number: 1; density: 0.0899 g/l at 0°C and 760 mm pressure.

Atom: Am atom is the smallest constituent particle of a chemical element which has the properties of that element. They re comprised of at least an electron and a portion, as is the case for Hydrogen. Atoms of all other elements however, contain at least one neutron.

Proton: A positively charged elementary particle that is a fundamental constituent of all atomic nuclei. It is the lightest and most stable baryon, having a charge equal in magnitude to that of the electron, a spin of 1/2, and a mass of 1.673 × 10-27kg. Symbol: P.

Electron: An elementary particle that is a fundamental constituent of matter, having a negative charge of 1.602 × 10-19 coulombs, ha mass of 9.108 × 10-31 kilograms, and spin of 1/23, and existing independently or as the component outside the nucleus of an atom.

Neutron: An elementary particle having no charge, mass slightly greater than that of a proton, and spin of 1/2: a constituent of the nuclei of all atoms except those of hydrogen. Symbol: n.

A object has a negative charge when it consists of more electrons than protons.

With a partial positive charge on 2 Hs and a partial negative charge on oxygen, water molecules are polar molecules.

Actually, two hydrogen atoms and the core oxygen atom of water are covalently connected. Due to its greater electronegative nature than hydrogen, oxygen pulls the bound electron pair in the middle of the atom toward it.

When illustrating higher electron densities over oxygen, partial negative charge is used, whereas partial positive charge is used to illustrate lower densities over hydrogen atoms.

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Answer:

CH3CH2CH2COOH<CH2(F)CH2CH2COOH<CH3CH(F)CH2COOH<CH2(F)CH(F)CH2COOH

Explanation:

We know that the presence of highly electronegative elements in carboxylic acid molecules lead to -I inductive effect. This implies that electrons are withdrawn along the chain towards the electronegative element. As electrons are withdrawn towards the electronegative element, the electron cloud of the carbonyl- hydrogen bond in the acid weakens and the hydrogen can now be easily lost as a proton, that is , the molecule becomes more acidic.

The -I inductive effect increases with increase in the number of electronegative elements present in the molecule and the proximity of the electronegative element to the carbonyl group. The closer the electronegative element is to the carbonyl group, the greater the acidity of the molecule since the -I inductive effect dies out with increasing distance from the carbonyl group. Also, the more the number of electronegative elements in the molecule, the greater the - I inductive effect and the greater the acidity of the molecule, hence the answer.

Explanation:

Atomic number is the number of protons found in the element's atom. Since it has atomic number 43, we find the 43rd element in the Periodic table, which is Technetium. (Tc)

P.S. Mass number is the number of protons and neutrons in the element's atom

Answer:

Atomic number is the number of protons found in the element's atom. Since it has atomic number 43, we find the 43rd element in the Periodic table, which is Technetium. (Tc)

Explanation:

ChoiSungHyun

Credit

Answer:

Answer in image below.

The net ionic equation will be  \(H^{+} + OH^{-}\)→ \(H_{2}O\).

The chemical equation would be known as the net ionic equation only displays the substances, ions, and elements which are already intimately implicated in the reaction.

When \(HCHO_{2}\) reacts with NaOH then it will form \(NaCHO_{2}\) and \(H_{2}O\).

It can be expressed as:

\(HCHO_{2} + NaOH\) → \(NaCHO_{2} + H_{2}O\).

The total ionic equation can be written as:

\(H^{+} +CHO^{-} _{2} + Na^{+} + OH^{-}\) → \(Na^{+} + CHO^{-} _{2} + H_{2}O\).

The net ionic equation can be expressed as:

 \(H^{+} + OH^{-}\)→ \(H_{2}O\).

The net ionic equation will be  \(H^{+} + OH^{-}\)→ \(H_{2}O\).

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Answer:\(T_f=33.85\°C\)

Explanation:

Hello,

In this case, we can write the following relationship, explaining that the lost by the hot water is gained by the cold water:

\(Q_{hot,W}=-Q_{cold,W}\)

Which in terms of mass, specific heat and temperatures, we have:

\(m_{hot,W}Cp_{W}(T_f-T_{hot,W})=-m_{cold,W}Cp_{W}(T_f-T_{cold,W})\)

Whereas the specific heat of water is cancelled out to obtain the following temperature, considering that the density of water is 1 kg/L:

\(T_f=\frac{m_{hot,W}T_{hot,W}+m_{cold,W}T_{cold,W}}{m_{hot,W}+m_{cold,W}}\\\\T_f=\frac{5.0kg*80\°C+60kg*30\°C}{5.0kg+60kg} \\\\T_f=33.85\°C\)

Regards.

Answer:

Kc = [B₃]²/[A₂]³  = 0.40

Explanation:

3A₂ ⇄ 2B₃  

Given at equilibrium =>  [A₂] =2.5 and [B₃] = 2.5

Kc = [B₃]²/[A₂]³ = (2.5)²/(2.5)³ = (2.5)⁻¹ = 0.40

Answer:

Electronegativity is a measure of the tendency of an atom to attract electrons (or electron density) towards itself. It determines how the shared electrons are distributed between the two atoms in a bond. The more strongly an atom attracts the electrons in its bonds, the larger its electronegativity.

Explanation:

Answer:

its d

. . . . . . . .. . . . . . . . .. .

The velocity of the prototype should be (Fr x √(g x (1:30L))).

Prototype is a preliminary version of a product or system that is used to test features, functionality, and design before a final version is released. It is a way to quickly and cheaply test ideas, evaluate feedback, and provide proof-of-concept for a product or system.

The Froude number for the model and prototype is given by the equation, Fr = V/√(gL), where V is the velocity, g is the acceleration due to gravity, and L is the length of the prototype. For the model, V is 1:30 times the velocity of the prototype.
Therefore, the velocity of the prototype, Vp, can be calculated as:
Vp = (Vm x 30)/1

= (Fr x √(gL)) x 30/1

= (Fr x √(g x (1:30L)))
Where Vm is the velocity of the model and L is the length of the prototype.
Therefore, the velocity of the prototype should be (Fr x √(g x (1:30L))).

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The IUPAC name of the compound is 3-Ethyl-2,2-dimethylhexane.

IUPAC naming is a systematic method of naming chemical compounds according to a set of rules established by the International Union of Pure and Applied Chemistry. It ensures that each compound has a unique and unambiguous name based on its molecular structure.

From the image:

Thus, the IUPAC name of the compound is 3-Ethyl-2,2-dimethylhexane.

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your answer is C you're welcome

Fe + CuSO₄ ----> FeSO₄ + Cu

According to that equation, 1 mol of Fe will react with 1 mol of CuSO₄ to give 1 mol of FeSO₄ and 1 mol of Cu.

The first step to solve the problem is to find the number of moles of Fe that we have in 3.8 g of it. To do that we have to use the molar mass.

molar mass of Fe = 55.85 g/mol

number of moles of Fe = mass of Fe/molar mass of Fe

number of moles of Fe = 3.8 g /(55.85 g/mol)

number of moles of Fe = 0.068 moles of Fe

Once that we know that 3.8 grams of Fe represents 0.068 moles of Fe, we can find the number of moles of Cu produced by those moles (since Fe reacts with excess of CuSO₄). According to the coefficients of the equation of the reaction:

number of moles of Cu produced = 0.068 moles of Fe * 1 mol of Cu/(1 mol of Fe)

number of moles of Cu produced = 0.068 moles of Cu

Finally we can convert those moles of Cu produced into grams using the molar mass of Cu.

molar mass of Cu = 63.55 g/mol

mass of Cu produced = 0.068 moles * 63.55 g/mol

mass of Cu produced = 4.32 g

Answer: b) 4.3 g of Cu are produced.