LAST QUESTION PLEASE HELP ME

Answer:

its number 2 now mark me Brainliest Pls

Step-by-step explanation:

Answer:

ummm..i should say it's 2

The theta notation for the function f (n) = (n3/2), g(n) = (n5/2) is Θ(n5/2).

What is theta notation? Theta notation is used to describe the asymptotic performance of an algorithm. It specifies a tight bound on the growth rate of the algorithm, i.e., an upper bound and a lower bound.

It is represented using the Greek letter theta (Θ).In the case of the given functions,

f (n) = (n3/2), g(n) = (n5/2),

we can determine their theta notation as follows:

We have f (n) = (n3/2).

Let's find g (n) / f (n):g (n) / f (n) = (n5/2) / (n3/2) = n

Therefore, g (n) is greater than or equal to f (n) multiplied by a constant c1, which is 1, for all n greater than or equal to 1.

This implies that the lower bound of the function is n3/2, which means that the lower bound of the function is n3/2.

Hence, the theta notation of f (n) is Θ(n3/2).

Similarly, for g (n) = (n5/2), let's find f (n) / g (n):f (n) / g (n) = (n3/2) / (n5/2) = 1 / n

Therefore, f (n) is less than or equal to g (n) multiplied by a constant c2, which is 1, for all n greater than or equal to 1.

This implies that the upper bound of the function is n5/2, which means that the upper bound of the function is n5/2.

Hence, the theta notation of g (n) is Θ(n5/2). Therefore, the theta notation for the function f (n) = (n3/2), g(n) = (n5/2) is Θ(n5/2).

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To prove that every linear map on a subspace of V can be extended to a linear map on V. We have to show that there exists a linear map T from V to W that extends S and satisfies Tu = Su for all u in U.

Let U be a subspace of a finite-dimensional vector space V, and let S be a linear map from U to another vector space W. du in U.

Since V is finite-dimensional, ready to select a premise {u1, u2, ..., um} of U and expand it to the premise {u1, u2, ..., um, v1, v2, ... increment. Let {w1, w2, ..., wk} be the premise of W.

 You can define T using the base elements of V as follows:

T(uj) = S(uj) for j = 1, 2, ..., m (since uj is in U and S is a linear map from U to W)

T(vi) = 0 for i = 1, 2, ..., n (to ensure that T is a linear map)

We can extend T linearly to all of V by defining T as

For any vector v in V, we can write v as a linear combination of basis elements.

v = a1u1 + a2u2 + ... + amount + b1v1 + b2v2 + ... + bnvn

Then we can define T(v) as

T(v) = a1T(u1) + a2T(u2) + ... + amT(um) + b1T(v1) + b2T(v2) + ... + bnT(vn)

Structurally, this definition of T agrees with the definition of S on the subspace U, since T(uj) = S(uj) for j = 1, 2, ..., m. Since T is a linear map on V, it is also well-defined and satisfies the linear property.

T(cv + w) = cT(v) + T(w)

For every vector v, w in V, and every scalar c. Thus, we showed that there exists a linear map T from V to W that extends S and satisfies Tu = Su for all u in U.

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Answer: C

Step-by-step explanation:

Because i said so

If a=4, b= 7, and B= 75°, the area of triangle ABC is approximately 13.476 square units.

To find the area of triangle ABC given the values of a, b, and B, we can use the formula:

Area = (1/2) * a * b * sin(B)

where a and b are the lengths of two sides of the triangle and B is the angle between them, measured in degrees.

Substituting the given values, we get:

Area = (1/2) * 4 * 7 * sin(75°)

Using a calculator to evaluate the sine of 75°, we get:

Area = (1/2) * 4 * 7 * 0.96593

Area ≈ 13.476 square units

The formula for the area of a triangle involves using the length of two sides and the angle between them.

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The solution of  the value is mathematically given as

√6 =2.449

This is further explained below.

Generally, In mathematics, the term "square root" refers to a component of a number that, when multiplied by itself, results in the same value as the original number.

As an example, both 3 and –3 are square roots of the number 9.

A number y is said to have a square that is equal to a given number x if and only if it satisfies the following condition: y2 = x.

Another way to express this is to say that the number y has the same value as its own square. For example, the square roots of 16 are 4 and -4, since 42 divided by 2 is 16.

In conclusion,

√6 is not -4

because

√6 =2.449

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Answer:

\(5y=-x+23\\\)

Step-by-step explanation:

Since the equation of the line is perpendicular to the line y = 5x +6

we can use the formula:

\(m_1m_2=-1\\\)

where m1 is the slope of the line we have and,

m2 is the slope of the line we need

so here m1 is 5 as we compare it with the slope-intercept form our slope is:

\(y=5x+6\\y=mx+b\)

our m1 is 5 but we need m2 so plugging in the value we get m2 to be:

\(m_1m_2=-1\\5m_2=-1\\m_2=-1/5\\\)

and now we have our m2, now furthermore since the line passes through the point (-2 , 5) it means the point must lie on the line and satisfy it. We can use this point and the slope m2 and find out the equation by the point-slope form equation:

\(y-y_1=m(x-x_1)\\y-5=-\frac{1}{5}(x-(-2))\\\\5(y-5)=(-1)(x+2)\\5y-25=-x-2\\5y=-x-2+25\\5y=-x+23\\\)

Answer:

B

Step-by-step explanation:

Area of circle= πr²

Start by finding the radius:

Diameter= 2(radius)

4= 2(radius)

radius= 4 ÷2

radius= 2 ft

Area of circular wall hanging

= 3.14(2²)

= 3.14(4)

= 12.56

= 12.6 ft² (nearest tenth)

Thus, option B is correct.

The step that is the part of the process of algebraically solving the given system of equations is (C) 4x – 10 = x2 – 5x + 10 and (E) 0 = x2 – 9x + 20.

To find the step that is the part of the process of algebraically solving the given system of equations:

That would be:

(C) 4x – 10 = x2 – 5x + 10  ( y = 4x - 10 is substituted for y).

Proof:      

(E) 0 = x2 – 9x + 20  (liked terms are grouped and simplified).

Proof:      

Solving:

Therefore, the step that is part of the process of algebraically solving the given system of equations is (C) 4x – 10 = x2 – 5x + 10.

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The complete question is given below:
Which steps could be part of the process in algebraically solving the system of equations, y + 5x = x2 + 10 and y = 4x – 10? Check all that apply.

(A) y = x2 + 5x + 10

(B) y + 5x = x2 + 10 + 4x – 10

(C) 4x – 10 = x2 – 5x + 10

(D) 0 = x2 – 9x

(E) 0 = x2 – 9x + 20

(F) One x-value of a solution to the system is 4.

The answer of the integral f(t) = cos(t) + t0 + e−τf(t − τ) dτ using laplace transformation is f(t)=cost+sint.

What is Laplace Transformation?

Laplace Transfrom is a part of integration where the integration is done with respect to the real variable. And this real variable is converted into a complex form.

In order to solve the given equations, we need to take two functions f(t) and g(t) and L and t as laplace transformers.

Given that:

F(t) = cos(t) + t0 + e−τf(t − τ) dτ

Use Laplace transformation both sides

L{f(t)} = L{cos(t)} + L{ t0 + e−τf(t − τ) dτ}

L{f(t)}=s÷s²+1+L{e−t∗f(t)}

L{f(t)}=s÷s²+1+L{e−t} L{f(t)}

F(s)=s÷s²+1+1÷s+1 F(s)

F(s)(1−1s+1)=s÷s2+1

F(s)(1−1÷s+1)=s÷s²+1

F(s)(s÷s+1)=s÷s²+1

F(s)(1s+1)=1s2+1

F(s)=s+1÷s²+1

F(s)=s÷s²+1+1÷s²+1.

Take Inverse Laplace

L−1{F(s)}=L−1{s÷s²+1+1÷s²+1}

f(t)=L−1{s÷s²+1}+L−1{1÷s²+1}

f(t)=cost+sint

Therefore the  answer of the integral f(t) = cos(t) + t0 + e−τf(t − τ) dτ using laplace transformation is f(t)=cost+sint.

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In the balance sheet, mortgage notes payable are reported as a long-term liability only.

Mortgage notes payable represent the amount owed by a company for a mortgage loan. These loans are typically long-term obligations that are expected to be repaid over an extended period, often several years. Therefore, mortgage notes payable are classified as long-term liabilities in the balance sheet.

Current liabilities are obligations that are expected to be settled within a short period, usually one year or less. Since mortgage notes payable typically have a longer repayment term, they do not meet the criteria to be classified as current liabilities.

By reporting mortgage notes payable as a long-term liability, the balance sheet provides a clear distinction between the company's short-term and long-term obligations, helping stakeholders understand the company's financial position and obligations over different time horizons.

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Answer:

22 degrees

Step-by-step explanation:

-4 + 26 = 22

Hope this helps

The correct response variable is the amount of pain relief.

Given that,

A tall glass of ice water, according to some, can help migraine sufferers find relief. Multiple migraine sufferers will be recruited by researchers to participate in a test. The individual will either take a placebo pill or a common painkiller when they get a migraine. Additionally, only half of each group will take the pill with water; the other half will sip on a small amount of water. The quantity of pain relief is then reported by participants.

To find :  What is the response variable in this experiment.

Explanation :

Response variable or study variable, in general called as dependent variable  is the variable of main focus in study. We want to study the changes in explanatory or independent variables are associated with response variable. Sometimes we want to measure the effect of predictors i.e explanatory variables on response variable.

For example in hand, we want to determine whether the drinking ice water is associated with amount of pain relief. Hence in this study, response variable is the amount of pain relief.

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The first three statements regarding the lux meter, pressure variations per second, and reverberation time calculations are false. The last statement regarding optimum reverberation time is true.

1. A Lux meter is not used to measure sound pressure levels, but rather to measure illuminance, which is the amount of light falling on a surface.

2. The number of pressure variations per second is called the frequency of sound. It is measured in Hertz (Hz) and is related to the pitch of the sound.

3. Reverberation time calculations are typically made for multiple octave bands, not just four. Octave bands divide the frequency range into logarithmic intervals, and considering more than four-octave bands provides a more accurate assessment of the room's acoustics.

4. The optimum reverberation time of a room depends on factors such as its size, total absorbance (amount of sound energy absorbed by surfaces), and surface characteristics. Different types of spaces, such as concert halls or recording studios, may require different reverberation times to achieve the desired acoustic characteristics.

In summary, the Lux meter is not used for measuring sound pressure levels, the frequency of sound is not referred to as the number of pressure variations per second, more than four-octave bands are typically considered for reverberation time calculations, and the optimum reverberation time depends on the size and surface characteristics of the room.

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The correct simplification of the expression is c12 (option c).

The expression (c^4)^3 can be simplified using the exponent rules for powers of a power, which states that when a power is raised to another power, we can multiply the exponents.

Thus, we have:

(c^4)^3 = c^(43) [Using the rule (a^m)^n = a^(mn)]

Simplifying the exponent 4*3, we get:

c^(4*3) = c^12

Therefore, the correct simplification of the expression is c^12.

Option (c) is the correct answer as it correctly represents the simplified form of the given expression. Option (a) c^-1, option (b) c^7, and option (d) c^64 are not correct because they do not follow the exponent rules used to simplify the expression.

In summary, the expression (c^4)^3 simplifies to c^12, which is option (c) in the given options.

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Answer:

its domain

Step-by-step explanation:

Answer:

i believe it is A- range.

Step-by-step explanation:

i took the quiz

Answer:

736-39+78=

Step-by-step explanation:

736-39+78=

Answer:

12

Step-by-step explanation:

Answer:

Step-by-step explanation: both graphed is D

The graph D represents the solution of the system of the equation.

One or many equation having same number of unknowns that can be solved simultaneously called as simultaneous equation. And simultaneous equation is the system of equation.

Given, the system of equation;

y = -3x - 5  {equation 1}

y = 3x + 1  {equation  2}

Add both of the equation:

2y = -4

y = -2

And x = 1

And the solution set is (1 , -2).

And only D have the solution set (1 , -2)

Therefore, the graph D represents the solution of the system of the equation.

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4 is the numerical length of line segment LN.

A line segment is simply the part of a line that connects two points or is bounded by two points.

Given the data in the question;

Since point M is on line segment LN, segment LN equals to the sum of segment LM and MN.

Hence;

Segment LN = segment LM + segment MN

4x = 3 + x

Solve for x

4x - x = 3

3x = 3

x = 3/3

x = 1

Now, we find the numerical length of segment LN;

Segment LN = 4x

Plug in x = 1 and simplify

Segment LN = 4( 1 )

Segment LN = 4

Therefore, the length of segment LN is 4.

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If cosA = 24/25 tanB = 4/3 and angles A and B are in Quadrant I. The value of tan(A-B) is -23/33.

We can start by using the identity: tan(A - B) = (tan A - tan B)/(1 + tan A tan B)

From the given information, we have:

cos A = 24/25, which means sin A = sqrt(1 - cos^2 A) = 7/25 (since A is in Quadrant I)

tan B = 4/3, which means sin B = 4/sqrt(4^2 + 3^2) = 4/5 and cos B = 3/sqrt(4^2 + 3^2) = 3/5

Now, we can use the definitions of sine and cosine to find tan A:

tan A = sin A / cos A = (7/25)/(24/25) = 7/24

Substituting the values we have found into the formula for tan(A - B), we get:

tan(A - B) = (tan A - tan B)/(1 + tan A tan B)

= [(7/24) - (4/3)]/[1 + (7/24)(4/3)]

= (-13/72)/(25/72)

= -13/25

Therefore, tan(A - B) = -13/25.

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Step-by-step explanation:

For a, you have the theorem right above.

If B is 120 then D should be 180-120=60

Since C is 90, E should be 180-90=90

Use the same theorem for b as well

As per linear equation, the average of the student is 82.2.

The mean is 83.75.

A linear equation is an equation that contains one or multiple variable with the highest power of the variable is one.

The student got test average of 80, his quiz average of 72, homework of 90, and classwork of 93.

Test is worth of 30%.

Therefore, the weightage of test is

= 80 × 30%

= 24

Quiz is worth of 30%.

Therefore, the weightage of quiz is

= 72 × 30%

= 21.6

Homework is worth of 20%.

Therefore, the weightage of homework is

= 90 × 20%

= 18

Classwork is worth of 20%.

Therefore, the weightage of classwork is

= 93 × 20%

= 18.6

Therefore, the average of the student is

= (24 + 21.6 + 18 + 18.6)

= 82.2

Now, the mean is

= (80 + 72 + 90 + 93)/4

= 83.75

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Answer:

12/3=4 ..............

Answer:the percentage increase is 14%

Step-by-step explanation:the difference between 57000 and 50000=7000

so therefore

% increase=7000/50000*100%

                  =14%  

\(f(x) = \cos^2 x \\\\f'(x) = 2 \cos x ( - \sin x) = - 2 \cos x \sin x = -\sin 2x\\\\f''(x) = -2\cos 2x\\\\\text{The second derivative of}~ \cos^2 x ~ \text{is}~ -2 \cos 2 x\)

Answer:

i infer that the awnser is B

Step-by-step explanation:

ah yes a more challenging question than the last..

I believe the answer is A.

-2x-2z

Step-by-step explanation:

Hope this helps!

The set of negative integers is a commutative group under the operation of addition.

For given question,

We need to check whether the set of negative integers is a commutative group under the operation of addition.

We know that negative integers are whole numbers that have value less than zero.

We know that, for any positive integers a, b,

a + b = b + a                        .......................(1)

For any negative integers -a, -b

(-a) + (-b) = -a - b

              = -(a + b)

              = -(b + a)                  ...............(From (1))

              = -b - a

              = (-b) + (-a)

As, (-a) + (-b) = (-b) + (-a) for any negative integers -a, -b, the set of negative integers is a commutative group under the operation of addition.

Therefore, the set of negative integers is a commutative group under the operation of addition.

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Answer:

ykLhxlyzykxlh jl jcul

Step-by-step explanation:

If you want to round a number within an arithmetic expression, you should use the ROUND function.

The ROUND function allows you to specify the number of decimal places to which you want to round a given number. It is commonly used in programming languages and spreadsheet software.

The syntax for the ROUND function typically involves specifying the number or expression you want to round and the number of decimal places to round to. For example, if you want to round a number, let's say 3.14159, to two decimal places, you would use the ROUND function like this: ROUND(3.14159, 2), which would result in 3.14.

Using the ROUND function ensures that the rounded number is calculated within the arithmetic expression, providing the desired level of precision in the calculation.

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