larry paid $11.20 for four gallons of gas How much was each gallon of gas? ​

The standard deviation of demand over the lead time is 23.72.

The demand over lead time is normally distributed with a mean of 80. The reorder point for a 95% service level is 119. To calculate the standard deviation of demand over the lead time, we need to use the following formula:

z = (x - μ) / σ, where z is the number of standard deviations from the mean, x is the reorder point for a 95% service level, μ is the mean of the distribution, and σ is the standard deviation of the distribution.

To solve for σ, we need to first find the z-score for a 95% service level, which can be obtained from the standard normal distribution table.

The z-score for a 95% service level is 1.645.

Substituting the given values in the formula, we get:

1.645 = (119 - 80) / σ

Solving for σ, we get:σ = (119 - 80) / 1.645

σ = 23.72

Therefore, the standard deviation of demand over the lead time is 23.72.

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Yes, its true that the questionnaire is very carefully constructed by an individual to provide the measurement instrument.  

A questionnaire is a studies device which includes a sequence of questions for the motive of amassing facts from respondents. Questionnaires may be concept of as a form of written interview. A questionnaire is a listing of questions or gadgets used to collect facts from respondents approximately their attitudes, experiences, or opinions.

Questionnaires may be used to acquire quantitative and/or qualitative facts. Questionnaires are generally utilized in marketplace studies in addition to withinside the social and fitness sciences. Questionnaires are typically taken into consideration to be excessive in reliability. This is due to the fact it's miles feasible to invite a uniform set of questions. Any troubles withinside the layout of the survey may be ironed out after a pilot study. The greater closed questions used, the greater dependable the studies.

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The value of A such that cos A = 0.7715 is 39.5 degrees

The equation is given as:

cos A = 0.7715

Where the angle is in degrees

There are several ways to solve this equation, some of which include:

In this case, we make use of the first option; using a scientific calculator

Recall that the equation is represented as:

cos A = 0.7715

Next, we take the arccos (or anti cosine) of the above equation.

This is represented as

arccos(cos A) = arccos(0.7715)

Evaluate the expression on the left-hand side

A = arccos(0.7715)

Evaluate the expression on the left-hand side using the scientific calculator

A = 39.5112207183

Approximate the above expression

A = 39.5

Hence, the value of A such that cos A = 0.7715 is 39.5 degrees

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Answer:

7/3

Step-by-step explanation:

Answer:

7/3

Step-by-step explanation:

3/7 x 7/3 = 1

Answer:

The initial value is the y value when x is zero.  Look at the table to help you determine the y value when x is zero and that is your answer.

Step-by-step explanation:

Answer:

BCF

Step-by-step explanation:

Answer:

$14390.75

Step-by-step explanation:

p=3650

i = 5.5% is this annual rate or monthly rate?  assuming annual rate

t=15 years compounding monthly = 15*12 = 300 periods

(1+5.5%/12)^300=3.94267155

multiply the principal 3650 *3.94267155 = $14390.75

A graph of the quadratic equation h(t) = −16t² + 144 is shown in the image attached below.

The domain of h(t) is equal to {-3, 0}.

The range of h(t) is equal to {-∞, 144}.

Yes, h(t) is an invertible function because it passed the vertical line test.

In Mathematics, a domain is sometimes referred to as input value and it can be defined as the set of all real numbers for which a particular function is defined.

Additionally, the vertical extent of any graph of a function represents all range values and it should be read and written from smaller to larger numerical values, and from the bottom of the graph to the top.

By critically observing the graph shown in the image attached below, we can reasonably and logically deduce the following domain and range:

Domain = -3 < x < 0 or {-3, 0}.

Range = -∞ < y < 144 or {-∞, 144}.

In conclusion, the quadratic equation h(t) = −16t² + 144 is an invertible function because it input value (domain) are uniquely mapped to the output value (range).

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Correlated variables are two explanatory factors that are connected to both the response variable and each other. The statistical relationship between two variables, which shows how they change together, is referred to as correlation.

Explanatory variables are used in regression analysis to forecast or explain the response variable. A correlation between two explanatory variables indicates that changes in one are influenced by changes in the other. Understanding the relationship between the explanatory variables and the response variable can be significantly impacted by this correlation. When analysing data, it's crucial to take into account the presence of correlated variables in order to avoid problems like multicollinearity and properly interpret the analysis's findings.

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The z-score of an appliance that failed after 64 months is 2.

To find the z-score:

The given parameters are:

The z-score is then computed as follows:

We have the following for an appliance that stopped working after 64 months:

So, the equation becomes:

Compare and contrast the differences:

Calculate the quotient:

Therefore, the z-score of an appliance that failed after 64 months is 2.

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Answer:

Step-by-step explanation:

Initial area is 10 in x 15 in.

After cutting the corners and folding, the remaining dimensions are:

The volume of the tray is:

Answer

what is?

STEP-BY-STEP-EXPLANATION

The term that expresses the probability that the observed result could have occurred by chance alone is P value. Option c is correct.

In hypothesis testing, a p-value is the likelihood of observing an outcome at least as extreme as the one being studied, assuming the null hypothesis is accurate. The p-value is a measure of statistical significance that is often used to determine whether or not to reject a null hypothesis in favour of an alternative hypothesis.

In this case, a p-value of less than 0.05 or 0.01 (depending on the level of significance chosen) would suggest that the null hypothesis should be rejected because the likelihood of the observed result occurring by chance alone is extremely low.

Therefore, c is correct.

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Answer:

\(7:4:2\)

Step-by-step explanation:

Assign variables for the 3 numbers. Let the first number be x, the second number be y, and the third number be z.

"The sum of the 3 numbers is 145", therefore:

"Seven times the second number is twice the first number":

"Twice the second number is six times the third number":

We can solve for x, y and z using this system of equations. Let's solve for y in the first equation by putting the other variables in terms of y in Equations II and III.

Solve for x in \(\text{Equation II}\):

Solve for z in \(\text{Equation III}\):

Substitute these values into \(\text{Equation I}\) to solve for y.

Combine like terms using common denominators. The least common denominator is 6. Multiply \(\frac{7}{2} y\) by \(\frac{3}{3}\), multiply \(y\) by \(\frac{6}{6}\), and multiply \(\frac{1}{3} y\) by \(\frac{2}{2}\) to make all of the denominators = 6.

Add the fractions together.

Solve for y by multiplying both sides by \(\frac{6}{29}\).

We have found that y = 30. Now we can use this known value in order to solve for both x and z in Equations II and III.

\(\text{Equation II}:\)

\(\text{Equation III}:\)

We have found that x = 105, y = 30, and z = 10. Now we can write the new ratio of these 3 numbers:

"Write the new ratio of the three numbers if the second number doubles and the third number is increased by one less than one fifth of the first number":

The question asks for the new ratio once we evaluate these expressions. The variable x is the only one that stays the same at the end: 105.

Our final numbers are x = 105, y = 60, and z = 30. We can create the ratio between these numbers by fully simplifying them. Right now we have \(x:y:z=105:60:30\). Start by dividing all of the numbers by 5.

We get \(21:12:6\). This ratio can be simplified further by dividing all of the numbers by 3. We then get the ratio of: \(7:4:2\).

This ratio cannot be simplified any further, therefore, it is the new ratio of the three numbers.

The side ratio theorem states that the value of x is 9.6 when BD/DA = BE/EC when DA = 12 and BE = 8 and EC = 10.

Given it has triangles and three vertices, each triangle qualify as a polygon. It belongs to the primitive geometric. Triangle ABC is the term utilized to refer to a triangle with the points A, B, and C. Once the three components are not collinear, a unique rectangle and square in Geometric forms are discovered. Triangles are polygons because they have three sections and three corners. The points where the main parts of the triangle merge are called to as the triangle's corners. Three triangle ratios are multiplied to yield 180 degrees.

given

by Side ratio theorem

BD/DA = BE/EC

= x/12 = 8/10

x = 8*12/10

x = 9.6

The side ratio theorem states that the value of x is 9.6 when BD/DA = BE/EC when DA = 12 and BE = 8 and EC = 10.

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In order to determine how much of each reactant was started with (alcohol and NaBr), the experimental protocol or the procedure has to be specified. Without knowing the protocol or the procedure of the experiment, we cannot calculate the amount of each reactant started with.

The theoretical yield in this experiment can be calculated by stoichiometry. The balanced chemical equation for the synthesis of 1-bromobutane is: C4H9OH + NaBr → C4H9Br + NaOH The stoichiometric ratio between alcohol (C4H9OH) and NaBr is 1:1. Therefore, the limiting reagent will be the one which is present in a lower amount. Suppose alcohol (C4H9OH) is present in excess, then the theoretical yield will depend on the amount of NaBr. If 2 moles of NaBr are taken, then the theoretical yield will be 2 moles of C4H9Br.

Possible by-products that could have been produced in this experiment are NaOH and H2O.4. Sodium iodide and silver nitrate tests can be used to check if there is any unreacted alkyl halide present in the product mixture. The sodium iodide test involves the reaction of sodium iodide with the product (1-bromobutane) to produce sodium bromide and free iodine. This test is used to detect the presence of unreacted bromide. The silver nitrate test involves the reaction of silver nitrate with the product (1-bromobutane) to produce silver bromide. This test is used to detect the presence of unreacted chloride and fluoride.

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Answer:  Choice A

\(\tan(\alpha)*\cot^2(\alpha)\\\\\)

============================================================

Explanation:

Recall that \(\tan(x) = \frac{\sin(x)}{\cos(x)}\) and \(\cot(x) = \frac{\cos(x)}{\sin(x)}\). The connection between tangent and cotangent is simply involving the reciprocal

From this, we can say,

\(\tan(\alpha)*\cot^2(\alpha)\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\left(\frac{\cos(\alpha)}{\sin(\alpha)}\right)^2\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\frac{\cos^2(\alpha)}{\sin^2(\alpha)}\\\\\\\frac{\sin(\alpha)*\cos^2(\alpha)}{\cos(\alpha)*\sin^2(\alpha)}\\\\\\\frac{\cos^2(\alpha)}{\cos(\alpha)*\sin(\alpha)}\\\\\\\frac{\cos(\alpha)}{\sin(\alpha)}\\\\\)

In the second to last step, a pair of sine terms cancel. In the last step, a pair of cosine terms cancel.

All of this shows why \(\tan(\alpha)*\cot^2(\alpha)\\\\\) is identical to \(\frac{\cos(\alpha)}{\sin(\alpha)}\\\\\)

Therefore, \(\tan(\alpha)*\cot^2(\alpha)=\frac{\cos(\alpha)}{\sin(\alpha)}\\\\\) is an identity. In mathematics, an identity is when both sides are the same thing for any allowed input in the domain.

You can visually confirm that \(\tan(\alpha)*\cot^2(\alpha)\\\\\) is the same as \(\frac{\cos(\alpha)}{\sin(\alpha)}\\\\\) by graphing each function (use x instead of alpha). You should note that both curves use the exact same set of points to form them. In other words, one curve is perfectly on top of the other. I recommend making the curves different colors so you can distinguish them a bit better.

The current yield on this bond is 6.49%.

A bond's yearly interest payment, market price, and par value must be known in order to determine the bond's current yield.

In this question, we are given that the bond pays an annual interest of $60, has a par value of $1,000, and is selling at a $75.25 discount from par value.

So, the market price of the bond is the par value minus the discount, which is \($ 1,000\) - \($75.25\) \(= $924.75.\)

To calculate the current yield, we use the formula:

Current Yield \(=\) (Annual Interest Payment / Current Market Price) x 100%

With our current values substituted, we obtain:

Current Yield \(= ($60 / $924.75) × 100%\)

Current Yield \(= 0.0649 × 100%\)

Current Yield \(= 6.49%\)%

Therefore, (B) 6.49% is the right response.

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Therefore, the probability of getting exactly 4 calls between 8:00 AM and 9:00 AM is approximately 0.1755, rounded to four decimal places.

To calculate the probability of getting exactly 4 calls between 8:00 AM and 9:00 AM, we need to use the Poisson distribution formula. The Poisson distribution is commonly used to model the number of events occurring in a fixed interval of time or space. In this case, the mean (λ) is given as 5. The formula for the Poisson distribution is:

P(X = k) = (e*(-λ) * λ\(^k\)) / k!

Where:

P(X = k) is the probability of getting exactly k calls

e is the base of the natural logarithm (approximately 2.71828)

λ is the mean number of calls (given as 5)

k is the number of calls (in this case, 4)

k! is the factorial of k

Let's calculate the probability using the formula:

P(X = 4) = (e*(-5) * 5⁴) / 4!

P(X = 4) ≈ 0.1755

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Being 90% confident in a problem means that there is a 90% chance that the confidence interval calculated from a sample contains the true population mean.

In other words, if we take 100 different samples of the same size from the population and calculate a confidence interval for each sample, then we can expect that 90 of those intervals will contain the true population mean.

This is the definition of a confidence level. Therefore, we can say that there is a 90% chance that the confidence interval we have calculated includes the true population mean.

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To find a particular solution that satisfies the three given initial conditions for the third-order homogeneous linear differential equation:

y⁽³⁾ - 5y'' + 8y' - 4y = 0

We'll assume a particular solution of the form:

yₚ = A₁eˣ + A₂e²ˣ + A₃xe²ˣ

where A₁, A₂, and A₃ are constants to be determined.

Taking the derivatives of yₚ, we have:

yₚ' = A₁eˣ + 2A₂e²ˣ + A₃e²ˣ + 2A₃xe²ˣ

yₚ'' = A₁eˣ + 4A₂e²ˣ + 4A₃e²ˣ + 4A₃xe²ˣ + 2A₃e²ˣ

yₚ⁽³⁾ = A₁eˣ + 8A₂e²ˣ + 12A₃e²ˣ + 12A₃xe²ˣ + 8A₃e²ˣ

Substituting these derivatives back into the differential equation, we get:

A₁eˣ + 8A₂e²ˣ + 12A₃e²ˣ + 12A₃xe²ˣ + 8A₃e²ˣ - 5(A₁eˣ + 4A₂e²ˣ + 4A₃e²ˣ + 4A₃xe²ˣ + 2A₃e²ˣ) + 8(A₁eˣ + 2A₂e²ˣ + A₃e²ˣ + 2A₃xe²ˣ) - 4(A₁eˣ + A₂e²ˣ + A₃xe²ˣ) = 0

Simplifying, we have:

(A₁ - 5A₁ + 8A₁ - 4A₁)eˣ + (8A₂ - 20A₂ + 16A₂ - 4A₂)e²ˣ + (12A₃ - 20A₃ + 8A₃)e²ˣ + (12A₃ - 4A₃ + 2A₃)e²ˣx = 0

Combining like terms, we obtain:

8A₁eˣ - 4A₂e²ˣ + 8A₃e²ˣ - 2A₃e²ˣx = 0

To satisfy the given initial conditions, we substitute them into the particular solution:

y(0) = A₁e⁰ + A₂e²⁰ + A₃(0)e²⁰ = 1

A₁ + A₂ = 1            ...(1)

y'(0) = A₁e⁰ + 2A₂e²⁰ + A₃(0)e²⁰ + 2A₃(0)e²⁰ = 4

A₁ + 2A₂ = 4           ...(2)

y''(0) = A₁e⁰ + 4A₂e²⁰ + 4A₃e²⁰ + 4A₃(0)e²⁰ = 0

A₁ + 4A₂ + 4A₃ = 0     ...(3)

Solving this system of equations (1), (2), and (3),

we find:

A₁ = -1

A₂ = 2

A₃ = -1

Therefore, the particular solution that satisfies the given initial conditions is:

yₚ = -eˣ + 2e²ˣ - xe²ˣ

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Answer:

kk

Step-by-step explanation:

Answer:

I do

Step-by-step explanation:

:)

The percent of attendance figures that differs from the mean by 1500 persons or more is 6.68%.

From the question above, Mean μ = 10,000

Standard Deviation σ = 1,000

The formula for z-score is :

z = (x-μ) / σ

Where, x = observation

z = z-score

Mean μ = 10,000

Standard Deviation σ = 1,000

From the above formula, let's calculate z-score for x = 11,500

z = (x-μ) / σ

z = (11,500 - 10,000) / 1000

z = 1.5

Now, find the probability of attendance figures that differs from the mean by 1500 persons or more.

P(z ≥ 1.5) = 0.0668

To find the percentage, we need to multiply the above value by 100.

P(z ≥ 1.5) × 100 = 0.0668 × 100 = 6.68%

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Using a 35-bag sample with a mean of 406.0 grams, a known standard deviation of 25.0 grams, and a level of significance of 0.05, you can perform a one-tailed Z-test to determine whether to reject or fail to reject the null hypothesis.

To test if the potato chip manufacturer's bag filling machine is working correctly at the 411.0-gram setting, we will state the hypotheses using the given terms.

Null Hypothesis (H0): The machine fills bags correctly, with a mean weight of 411.0 grams (µ = 411.0 grams)
Alternative Hypothesis (H1): The machine is underfilling bags, with a mean weight less than 411.0 grams (µ < 411.0 grams)

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Answer:

its 0

Step-by-step explanation:

6 squared plus 2 squared = 40 40/4=10 10-10=0

Answer: D

Step-by-step explanation:

Answer:

its 4 and my brain is about to blow up cause i just know this

Step-by-step explanation:

Answer:

the slope is -7

Step-by-step explanation:

\(\frac{-2-5}{3-2} =\frac{-7}{1}\)

Answer:

20 matches.

Step-by-step explanation:

Let the no of matches played be x.

percentage of won matches = 40%

percentage of lost matches = 100% - 40%

= 60%

no of lost matches = 12

Here,

60% of x = 12

or, 3x ÷ 5 = 12

or, 3x = 12×5

x = 60 ÷ 3 = 20