Large sample significance tests for a single proportion are based on the statistic binomial. the correct option is A
What is significance tests?Significance test can be defined as tests for statistical significance indicate whether observed differences between assessment results occur because of sampling error. Significance tests give a formal process for using sample data to evaluate the likelihood of some claim about a population value.
Therefore a Large sample significance tests for a single proportion are based on the statistic binomial.
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Which statement is true about the system x-3y=2 and y=x+6?
1. (8, 2) is not a solution to either equation, so it is not a solution to the system.
2. (8, 2) is a solution to one equation but not the other one, so it is a solution to the system.
3. (8,2) is a solution to both equations, so it is a solution to the system.
4. (8, 2) is a solution to one equation but not the other one, so it is not a solution to the system.
The true statement about the system of equations is the fourth one:
"(8, 2) is a solution to one equation but not the other one, so it is not a solution to the system."
Which statement is true about the system?The system of equations is:
x - 3y = 2
y = x + 6
We want to see which statement is true, all of them refer to the point (8, 2), so let's see if it is a solution of the system.
Replacing the values in the first equation we will get:
8 - 3*2 = 2
8 - 6 =2
2 = 2
For the second equation:
2 =8 + 6
2 = 14
This is false, so (8, 2) is not a solution of the second equation.
Then the true statement is:
" (8, 2) is a solution to one equation but not the other one, so it is not a solution to the system."
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Ummm...this confusing
Can somebody help me please is jut one problem
a) The definition of the composite function is: \((f \circ g)(x) = \frac{6}{12 + 2x}\)
b) The domain of the composite function is: (-∞, -6) U (-6, -2) U (-2,0) U (0, ∞).
How to define the composite function of f(x) and g(x)?The composite function of f(x) and g(x) is given by the function rule presented as follows:
(f ∘ g)(x) = f(g(x)).
For the composition of two functions, we have that the output of the inner function, which in this example is given by g(x), serves as the input of the outer function, which in this example is given by f(x).
The functions for this problem are given as follows:
f(x) = x/(x + 2).g(x) = 6/x.Hence the composite function is obtained as follows:
\((f \circ g)(x) = f(\left\frac{6}{x}\right)\)
\((f \circ g)(x) = \frac{\frac{6}{x}}{\frac{6}{x} + 2}\)
\((f \circ g)(x) = \frac{\frac{6}{x}}{\frac{12 + 2x}{x}}\)
\((f \circ g)(x) = \frac{6}{12 + 2x}\)
The domain is all real values except x = 0, x = -2 and x = -6, as f(x) is not defined at x = -2 and g(x) is not defined at x = 0 and the composite function is not defined at x = -6, hence the interval notation is:
(-∞, -6) U (-6, -2) U (-2,0) U (0, ∞).
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What is the median of 1, 3, 6, 8, 9, 9
Answer choices: A. 6
B. 7
C. 8
D. 9
Answer:
B
Step-by-step explanation:
The median is the middle value of the data arranged in ascending order. If there is no exact middle value then it is the average of the values either side of the middle.
1, 3, 6, 8, 9, 9
↑ middle
median = \(\frac{6+8}{2}\) = \(\frac{14}{2}\) = 7 → B
Answer:
B. 7
Step-by-step explanation:
(6 + 8) ÷ 2 = 7
I hope this is right if its not im sorry
PLEASE ANSWER - PLEASE ANSWER
The diagram shows triangle ABC. ABC and BED are straight lines. AB = 12.2cm, CD = 5.8cm, BE:ED = 3:1, Angle ADB = 90°, Angle ABD = 38°.
Work out the size of angle DCE, correct to 1 decimal place. SHOW ALL WORKING IN TEXT FORM, NO IMAGES.
The measure of angle DCE in this problem is given as follows:
m < DCE = 22.5º.
How to obtain the measure of angle DCE?The triangles in this problem are right triangles, meaning that the trigonometric ratios are used to find the measures.
The three trigonometric ratios are given as follows:
Sine of angle = length of opposite side divided by the length of the hypotenuse.Cosine of angle = length of adjacent side divided by the length of the hypotenuse.Tangent of angle = length of opposite side divided by the length of the opposite side.The segment DB is adjacent to angle of 38º, while the hypotenuse is of 12.2 cm, hence the length of segment DB is calculated as follows:
cos(38º) = DB/12.2
DB = 12.2 x cosine of 38 degrees
DB = 9.6 cm.
BE:ED = 3:1, means that segment DE is one-fourth of segment DB, and thus it's length is given as follows:
DE = 1/4 x 9.6
DE = 2.4 cm.
Then for the angle DCE, we have that the opposite side is of 2.4 cm while the adjacent side is of 5.8 cm, hence the tangent is used to find it's measure, as follows:
tan(x) = 2.4/5.8
x = arctan(2.4/5.8)
x = 22.5º
m < DCE = 22.5º.
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Answer:
x = 22.5°
Step-by-step explanation:
BD = cos(38)*12.2 = 9.61DE = 9.61*¼ = 2.4∠DCE = tan(2.4/5.8) = 22.5°Nora is in the business of manufacturing phones. She must pay a daily fixed cost to rent the building and equipment, and also pays a cost per phone produced for materials and labor. The labor and materials cost $150 for each phone manufactured, and the total cost of producing 8 phones in a day would be $2200. Write an equation for C,C, in terms of p,p, representing total cost, in dollars, of producing pp phones in a given day.
Answer:
C=150p+1000
Step-by-step explanation:
Solve for the y-intercept:
C=50p+b Slope intercept form of a line
2200=150(8)+b
Plug in known point
2200=1200+b Multiply
1000=b
Subtract 12001200
The equation is C = 1000 + 150p
The total cost of producing a phone is the sum of the fixed cost and the variable cost
Total cost = fixed cost + variable cost
Fixed cost is the cost of producing phone that remains constant regardless the quantity of phones produced. e.g. rent
Variable cost is the cost of producing phone that increases with the quantity of phones produced. e.g. labour cost
In order to write the equation, the fixed cost has to be determined.
Fixed cost = total cost - variable cost
Variable cost = $150 x 8 = $1200
2200 - 1200 = 1000
The equation is : C = 1000 + 150p
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Hi my name is Leah and I need help with my homework that's on Ken Academy I'm in the 5th grade and I need help with this screenshot Can anybody give me an answer? it's due today!
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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1. What is the measure
of ZABC?
A
98⁰
B
tc
2.
Answer:
∠ ABC = 49°
Step-by-step explanation:
the chord- tangent angle ABC is half the measure of the intercepted arc AB
∠ ABC = \(\frac{1}{2}\) AB = \(\frac{1}{2}\) × 98° = 49°
QUESTION ON PIC TY!!!!
Answer:
V = 147 Cu. Ft.
Step-by-step explanation:
Formula: V = lwh
V = 7 × 3 × 7
V = 21 × 7
V = 147 Cubic Feet
A student was asked to give the exact solution to the equation
22x+4-9(2) = 0
The student's attempt is shown below:
22x+49(2)=0
22x+24-9(2) = 0
Let 2* = y
y²-9y+8=0
(y-8)(y-1)=0
y = 8 or y=1
So x = 3 or x = 0
(a) Identify the two errors made by the student.
(b) Find the exact solution to the equation.
(a) The errors made by the student are:
Incorrectly expanding 49(2) as 24 instead of 98.
Mistakenly factoring the quadratic equation as (y - 8)(y - 1) instead of
\(y^{2} - 9y + 8.\)
(b) The exact solution to the equation is x = 7/11.
(a) The student made two errors in their solution:
Error 1: In the step \("22x + 49(2) = 0,"\) the student incorrectly expanded 49(2) as 24 instead of 98. The correct expansion should be 49(2) = 98.
Error 2: In the step \("y^{2} - 9y + 8 = 0,"\) the student mistakenly factored the quadratic equation as (y - 8)(y - 1) = 0. The correct factorization should be \((y - 8)(y - 1) = y^{2} - 9y + 8.\)
(b) To find the exact solution to the equation, let's correct the errors made by the student and solve the equation:
Starting with the original equation: \(22x + 4 - 9(2) = 0\)
Simplifying: 22x + 4 - 18 = 0
Combining like terms: 22x - 14 = 0
Adding 14 to both sides: 22x = 14
Dividing both sides by 22: x = 14/22
Simplifying the fraction: x = 7/11
Therefore, the exact solution to the equation is x = 7/11.
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5. 5(x + 10) + x
A. 6x + 15
B.5x + 15
C.6x + 50
D.4x – 50
Answer: C
Step-by-step explanation:
What is the sum of the interior angles of the polygon below?
Answer:
540
Step-by-step explanation:
you can draw 5 triangles from the center...
5*180-360 = 540
Given the triangle ABC at points A = ( 2, 2 ) B = ( 4, 5 ) C = ( 6, 3 ), and if the triangle is first reflected over the y axis, and then over the x axis, find the new point A''.
To reflect a point over the y-axis, we negate the x-coordinate of the point. To reflect the resulting point over the x-axis, we negate the y-coordinate of the point. So, to find the new point A'', we can perform these operations on the original point A:
1. Reflect A over the y-axis to get A': (-2, 2)
2. Reflect A' over the x-axis to get A'': (-2, -2)
Therefore, the new point A'' is (-2, -2).
May I please get a little help with this question? Thank you so much.
The y-intercept of the function is (0, c)
The coefficients b determine the horizontal shift of the parabola compared to the parent function
If a is negative, the parabola opens downward
The y-intercept of the function is (0, c).
This means that when x = 0, the y-value is equal to c.
The constant term c represents the y-coordinate of the point where the parabola intersects the y-axis.
The coefficient b determines the horizontal shift of the parabola compared to the parent function.
The value of b affects the position of the vertex and determines if the parabola is shifted to the left or right.
A positive value of b shifts the parabola to the left, while a negative value of b shifts it to the right.
If a is negative, the parabola opens downward.
The coefficient a determines the shape of the parabola.
If a is positive, the parabola opens upward, and if a is negative, the parabola opens downward. The sign of a determines the direction in which the parabola faces.
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The Busy Bee store bottles fresh jars of honey at a constant rate. In 3 hours, it bottles 36 jars, and in 7 hours, it bottles 84 jars of honey.
Determine the constant of proportionality.
36
12
4
0.08
If the Busy Bee store bottles fresh jars of honey at a constant rate and In 3 hours, it bottles 36 jars, and in 7 hours, it bottles 84 jars of honey, then the constant of proportionality is 12
The Busy Bee store bottles fresh jar of honey at a constant rate.
That means number of bottle is directly proportional to the time taken
Number of bottle they bottles = k × Time taken
Where k is the constant of proportionality
In 3 hours, it bottles 36 jar
36 = k ×3
k = 36/3
k = 12
In 7 hours, it bottles 84 jar
84 = k × 7
k = 84/7
k = 12
Hence, if the Busy Bee store bottles fresh jars of honey at a constant rate and In 3 hours, it bottles 36 jars, and in 7 hours, it bottles 84 jars of honey, then the constant of proportionality is 12
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PLEASE HELP ASAP DUE VERY SOON
Answer:
your answer will be A'B'/AB=3/1=3
Step-by-step explanation:
i hope this helps you
Answer:
3 is the correct answer......
Identify the proof to show that △ABD≅△CBD
, where ∠BDA≅∠BDC
are right angles, D
is the midpoint of AC¯¯¯¯¯
, AB¯¯¯¯¯≅BC¯¯¯¯¯
, and BD¯¯¯¯¯
bisects ∠B
.
The figure shows two triangles A B D and C B D with a common side B D. Points A, D, C lie on one line.
We have proven that △ABD ≅ △CBD based on the given information and the SAS congruence criterion.
To prove that △ABD ≅ △CBD, we can use the SAS (Side-Angle-Side) congruence criterion.
Given:
∠BDA ≅ ∠BDC (Both are right angles)
D is the midpoint of AC¯¯¯¯¯
AB¯¯¯¯¯ ≅ BC¯¯¯¯¯
BD¯¯¯¯¯ bisects ∠B
Proof:
Since D is the midpoint of AC¯¯¯¯¯, we have AD ≅ CD by the definition of a midpoint.
AB¯¯¯¯¯ ≅ BC¯¯¯¯¯ (Given)
BD¯¯¯¯¯ is a common side for both triangles.
∠BDA ≅ ∠BDC (Given)
To apply the SAS congruence criterion, we need to show that one pair of corresponding sides and the included angle are congruent in both triangles.
AD ≅ CD (Side) - This is true as D is the midpoint of AC¯¯¯¯¯.
∠BDA ≅ ∠BDC (Included Angle) - Both are right angles.
By the SAS congruence criterion, we can conclude that △ABD ≅ △CBD.
Therefore, we have proven that △ABD ≅ △CBD based on the given information and the SAS congruence criterion.
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what is the vertex of -(x+2)^2-3
Answer:
(-2,-3)
Step-by-step explanation:
Find the measure of the indicated angle.
99⁰
96⁰
98⁰
92°
L
120°
K
N
M
64
Answer:
? = 92°
Step-by-step explanation:
the chord- chord angle ? is half the sum of the measures of the arcs intercepted by the angle and its vertical angle, that is
? = \(\frac{1}{2}\) (LM + AK) = \(\frac{1}{2}\) (120 + 64)° = \(\frac{1}{2}\) × 184° = 92°
Jake has two dogs, Euclid and Pythagoras. Euclid is a smaller dog and Pythagoras is larger. Jake found that
Pythagoras lost 13 pounds from January to June. If Pythagoras gains 1.2 times Euclid's weight, Pythagoras's
weight would still be á pound less than he did in January. What is Euclid's weight?
4
(a) Write an equation that represents the scenario. Begin by defining your variable.
(b) Solve the equation. Show your work.
(c) What is Euclid's weight?
(d) Jake adopts a third dog, Riemann. Riemann weighs exactly twice what Euclid weighs. The combined
weight of the three dogs is 603 pounds. What is Riemann's weight, and what is Pythagoras's
2
weight? Show your work.
We want to answer different things about the weight of the dogs, with simple algebra we will find that the answers are:
a) P - 13lb + 1.2*E = P - 1lbb) E = 10lbc) Euclid's weight is 10 pounds.d) Pythagora's weight is 33 pounds and Riemann's weight is 20 pounds.We start by defining the two variables we will be using:
E = Euclid's weightP = Pythagoras's weightFirst, Pythagoras loses 13 lb, then his new weight is:
P' = P - 13lb
We know that if he wins 1.2 Euclid's weight, he will still have a pound less than before.
A) using the above information we can rewrite:
P - 13lb + 1.2*E = P - 1lb
This is the equation we need to solve.
b) So we want to solve this for E, then we move all the other terms to the right side:
1.2E = P - 1lb - P + 13lb
1.2E = 12lb
E = (12lb)/1.2 = 10lb
c) The solution of the above equation tells us that the weight of the dog is 10lb.
d) Let's define R as the weight of the third dog.
We know that:
R = 2*E = 2*10lb = 20lb
We also know that the combined weight of the 3 dogs is 63 lb, then we have:
E + R + P = 63lb
10lb + 20lb + P = 63lb
P = 63lb - 10lb -20lb = 33lb
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Use the function f(x) to answer the questions:
f(x) = 2x2 − 5x + 3
Part A: What are the x-intercepts of the graph of f(x)? Show your work.
Part B: Is the vertex of the graph of f(x) going to be a maximum or a minimum? What are the coordinates of the vertex? Justify your answers and show your work.
Part C: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part A and Part B to draw the graph.
The x-intercepts of the graph of f(x) are x = 3/2 and x = 1,the Vertex of the graph of f(x) is (5/4, 3/8), and it is a minimum point, The vertex is at (5/4, 3/8). This is the minimum point of the graph.
Part A: To find the x-intercepts of the graph of f(x), we set f(x) equal to zero and solve for x.
2x^2 - 5x + 3 = 0
To factor this quadratic equation, we look for two numbers that multiply to give 3 (the coefficient of the constant term) and add up to -5 (the coefficient of the linear term). These numbers are -3 and -1.
2x^2 - 3x - 2x + 3 = 0
x(2x - 3) - 1(2x - 3) = 0
(2x - 3)(x - 1) = 0
Setting each factor equal to zero, we get:
2x - 3 = 0 --> x = 3/2
x - 1 = 0 --> x = 1
Therefore, the x-intercepts of the graph of f(x) are x = 3/2 and x = 1.
Part B: To determine whether the vertex of the graph of f(x) is a maximum or a minimum, we look at the coefficient of the x^2 term, which is positive (2 in this case). A positive coefficient indicates that the parabola opens upwards, so the vertex will be a minimum.
To find the coordinates of the vertex, we can use the formula x = -b/2a. In the equation f(x) = 2x^2 - 5x + 3, the coefficient of the x term is -5, and the coefficient of the x^2 term is 2.
x = -(-5) / (2*2) = 5/4
Substituting this value of x back into the equation, we can find the y-coordinate:
f(5/4) = 2(5/4)^2 - 5(5/4) + 3 = 25/8 - 25/4 + 3 = 3/8
Therefore, the vertex of the graph of f(x) is (5/4, 3/8), and it is a minimum point.
Part C: To graph f(x), we can use the information obtained in Part A and Part B.
- The x-intercepts are x = 3/2 and x = 1. These are the points where the graph intersects the x-axis.
- The vertex is at (5/4, 3/8). This is the minimum point of the graph.
We can plot these points on a coordinate plane and draw a smooth curve passing through the x-intercepts and the vertex. Since the coefficient of the x^2 term is positive, the parabola opens upwards, and the graph will be concave up.
Additionally, we can consider the symmetry of the graph. Since the coefficient of the linear term is -5, the line of symmetry is given by x = -(-5) / (2*2) = 5/4, which is the x-coordinate of the vertex. The graph will be symmetric with respect to this line.
By connecting the plotted points and sketching the curve smoothly, we can accurately graph the function f(x).
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Quincy and Celine have to move 16 small boxes and 10 large boxes. the chart indicates the time that each person takes to move each type of box. they start moving the boxes at 9.00 a.m. the earliest time at which they can be finished moving all of the boxes is:
a. 9:41 a.m
b. 9:42 a.m
c. 9:43 a.m
d. 9:44 a.m
e. 9:45 a.m
The earliest time at which they can be finished moving all of the boxes is: d. 9:44 a.m
Quincy and Celine the earliest timeTo determine the earliest time at which Quincy and Celine can finish moving all of the boxes, we need to determine the maximum amount of time it will take for them to move all of the boxes. We can do this by calculating the time it will take for each person to move each type of box individually, and then adding those times together.
Quincy takes 1 minute to move a small box and 2 minutes to move a large box. Celine takes 2 minutes to move a small box and 3 minutes to move a large box.
So, for Quincy:Time to move 16 small boxes: 16 boxes * 1 minute/box = 16 minutes
Time to move 10 large boxes: 10 boxes * 2 minutes/box = 20 minutes
Total time for Quincy: 16 minutes + 20 minutes = 36 minutes
For Celine:Time to move 16 small boxes: 16 boxes * 2 minutes/box = 32 minutes
Time to move 10 large boxes: 10 boxes * 3 minutes/box = 30 minutes
Total time for Celine: 32 minutes + 30 minutes = 62 minutes
To get the earliest time they can finish moving all the boxes, we take the maximum of the two times:
Max(36 minutes, 62 minutes) = 62 minutes
Start time: 9:00 a.m.
End time: 9:00 a.m. + 62 minutes = 9:62 a.m.
So the earliest time they can finish moving all the boxes is 9:62 a.m.
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Suppose f(x) =8^3x and g(x) =8^4x which of these function operations are correct select all that apply
Suppose \(f(x) =8^{3x\) and \(g(x) =8^{4x\), function operations that are correct include the following:
A. (f + g)(x) = \(8^{3x} + 8^{4x}\)
B. (f × g)(x) = \(8^{7x}\)
C. (f - g)(x) = \(8^{3x} - 8^{4x}\)
What is an exponent?In Mathematics, an exponent is a mathematical operation that is typically used in conjunction with an algebraic expression in order to raise a quantity to the power of another.
This ultimately implies that, an exponent is represented by the following mathematical expression;
bⁿ
Where:
the variables b and n are numerical values (numbers) or an algebraic expression.n is referred to as a superscript or power.By applying the division and multiplication law of exponents for powers of the same base to the functions, we have the following:
(f × g)(x) = \(8^{3x+ 4x}=8^{7x}\)
(f ÷ g)(x) = \(8^{3x- 4x}=8^{-x}\)
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Suppose the measures of the interior angles of a convex quadrilateral are four consecutive odd numbers. Find the measure of the third angle.
Answer:
91 degrees
Step-by-step explanation:
Sum of angles in a quadrilateral: 360 degrees
87, 89, 91, 93 are four consecutive odd numbers that add up to 360
third angle is 91 degrees
The net shown below can be folded to form what figure?
A net has a rectangle at the center. 2 triangles are on the side and 2 squares are on the other sides.
rectangular pyramid
triangular prism
rectangular prism
triangular pyramid
Answer:
Hi I hope your day Is going well
Step-by-step explanation:
Your answer would be A or rectangular pyramid on Edge2021
rectangular pyramid ✔
triangular prism ❌
rectangular prism ❌
triangular pyramid ❌
The correct answer is triangular prism.
What is a prism?A 3-diamensional face that has two identical shapes facing each other is called a prism.
What is a pyramid?3-diamensional structures having triangle faces and an encompassing polygon at the base is called a pyramid.
What is a rectangular pyramid?3-diamensional structures having 4 triangle faces and a rectangular base is called a rectangular pyramid.
What is triangular prism?A triangular prism is a prism composed of two triangular bases and three rectangular sides. It can also look with rectangular base, 2 triangles and 2 square sides.
What is rectangular prism?A 3-diamensional figure with 6 rectangular faces is called rectangular prism.
What is a triangular pyramid?A pyramid having triangular base is called triangular pyramid.
How to find in which shape the net can be folded?The net has a rectangle at the center, 2 triangles are on the side and 2 squares are on the other sides.
Since it has 2 triangles, a rectangle and 2 squares, so the net can be folded in the shape of a triangular prism.A rectangular pyramid requires 4 triangles and so this option is incorrect.A triangular pyramid has all the faces triangular which does not match with the given figure and so this option is incorrecta rectangular prism has all rectangular faces and no triangular faces, so this option is also incorrect.So, the net can be folded in the shape of a triangular prism.
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Brett Olson borrow $6000 for three years at 7% add on rate. What is the financial charge? What is the APR?
9514 1404 393
Answer:
$1260 finance chargeAPR ≈ 12.83%Step-by-step explanation:
The interest due is the finance charge:
I = Prt = $6000·0.07·3 = $1260
__
The monthly payment is ...
($6000 +1260)/36 = $201.67
The APR for a 3-year loan of $6000 with a monthly payment of $201.67 is found by a financial calculator to be about 12.83%.
Classify angle ABC on side length and angles measure
Answer:
isosceles, acute
Step-by-step explanation:
isosceles because there are two equal sides and acute because none of the angles is greater than 90 degrees
3 + 3 + ?
20 POINTS FOR THE FIRST AWNSER!
Answer:
6
Step-by-step explanation:
Answer:
3+3=6
Step-by-step explanation:
3=1+1+1 so 1+1+1+1+1+1=6
5 tables and 2 trash cans.
The ratio is 5:2. What are the next 2 equivalent ratios for this problem?