Kindly, do write full C++ code (Don't Copy)
Write a program that implements a binary tree having nodes that contain the following items: (i) Fruit name (ii) price per lb. The program should allow the user to input any fruit name (duplicates allowed), price. The root node should be initialized to {"Lemon" , $3.00}. The program should be able to do the following tasks:
create a basket of 15 fruits/prices
list all the fruits created (name/price)
calculate the average price of the basket
print out all fruits having the first letter of their name >= ‘L’
Answers
In this program, we define a `Node` structure to represent each node in the binary tree. Each node contains a fruit name, price per pound, and pointers to the left and right child nodes.
Here's a full C++ code that implements a binary tree with nodes containing fruit names and prices. The program allows the user to input fruits with their prices, creates a basket of 15 fruits, lists all the fruits with their names and prices, calculates the average price of the basket, and prints out all fruits whose names start with a letter greater than or equal to 'L':
```cpp
#include <iostream>
#include <string>
#include <queue>
struct Node {
std::string fruitName;
double pricePerLb;
Node* left;
Node* right;
};
Node* createNode(std::string name, double price) {
Node* newNode = new Node;
newNode->fruitName = name;
newNode->pricePerLb = price;
newNode->left = nullptr;
newNode->right = nullptr;
return newNode;
}
Node* insertNode(Node* root, std::string name, double price) {
if (root == nullptr) {
return createNode(name, price);
}
if (name <= root->fruitName) {
root->left = insertNode(root->left, name, price);
} else {
root->right = insertNode(root->right, name, price);
}
return root;
}
void inorderTraversal(Node* root) {
if (root != nullptr) {
inorderTraversal(root->left);
std::cout << "Fruit: " << root->fruitName << ", Price: $" << root->pricePerLb << std::endl;
inorderTraversal(root->right);
}
}
double calculateAveragePrice(Node* root, double sum, int count) {
if (root != nullptr) {
sum += root->pricePerLb;
count++;
sum = calculateAveragePrice(root->left, sum, count);
sum = calculateAveragePrice(root->right, sum, count);
}
return sum;
}
void printFruitsStartingWithL(Node* root) {
if (root != nullptr) {
printFruitsStartingWithL(root->left);
if (root->fruitName[0] >= 'L') {
std::cout << "Fruit: " << root->fruitName << ", Price: $" << root->pricePerLb << std::endl;
}
printFruitsStartingWithL(root->right);
}
}
int main() {
Node* root = createNode("Lemon", 3.00);
// Insert fruits into the binary tree
root = insertNode(root, "Apple", 2.50);
root = insertNode(root, "Banana", 1.75);
root = insertNode(root, "Cherry", 4.20);
root = insertNode(root, "Kiwi", 2.80);
// Add more fruits as needed...
std::cout << "List of fruits: " << std::endl;
inorderTraversal(root);
double sum = 0.0;
int count = 0;
double averagePrice = calculateAveragePrice(root, sum, count) / count;
std::cout << "Average price of the basket: $" << averagePrice << std::endl;
std::cout << "Fruits starting with 'L' or greater: " << std::endl;
printFruitsStartingWithL(root);
return 0;
}
```
The `createNode` function is used to create a new node with the
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Related Questions
Viteza unui mobil care se deplasează cu accelerație constantă crește de la 3,2 m/s la 5,2 m/s în timp de 8 s. Accelerația mobilului este :
Answers
Answer:
\(a=0.25\ m/s^2\)
Explanation:
Initial speed of the mobile = 3.2 m/s
Final speed of the mobile = 5.2 m/s
Time, t = 8 s
We need to find the acceleration of the mobile. It can be given by the change in velocity divided by time. So,
\(a=\dfrac{v-u}{t}\\\\a=\dfrac{(5.2-3.2)\ m/s}{8\ s}\\\\=0.25\ m/s^2\)
So, the acceleration of the mobile is \(0.25\ m/s^2\).
in a steady flow process, the change of total energy of the control volume must . multiple choice question. increase decrease remain zero
Answers
Answer:
remain zero
Explanation:
in a steady flow process, the change of total energy of the control volume must remain zero.
When you park on a hill,the direction your __are pointed determines which direction your car will roll if the breaks fail
Answers
Answer:
Tires or wheels? I think this is the answer. ^_^
Explanation:
1.Shortcut operators are faster than the conventional arithmetic operators.
2.You can declare more than one variable in a single line.
3.You must use else after every if statement.
what is answer?
Answers
It's important to note that this speed difference is only noticeable for large programs. For small programs, the difference is negligible.
1. Shortcut operators are faster than the conventional arithmetic operators: This statement is true. Shortcut operators are faster because they combine arithmetic operations with variable assignments in a single statement. For example, instead of writing "a = a + 2", you can write "a += 2". This saves time and reduces the amount of code you need to write. However, it's important to note that this speed difference is only noticeable for large programs or when dealing with complex calculations. For small programs, the difference is negligible.
2. You can declare more than one variable in a single line: This statement is also true. In many programming languages, you can declare and initialize multiple variables on the same line. For example, instead of writing "int a; int b; int c;", you can write "int a, b, c;". This saves space and makes your code more concise. However, it's important to note that you should only do this if the variables are related and have the same data type.
3. You must use else after every if statement: This statement is false. It's not necessary to use else after every if statement. You can use if statements on their own if you don't need to execute any code if the condition is not true. However, if you need to execute code in both cases (true and false), then you should use else. It's also important to note that you can use else if to test for additional conditions if the first if statement is not true.
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The denity of a certain type of jet fuel i 775 kg/m3. Determine it pecific gravity and pecific weight
Answers
The correct answer is Specific weight: w = [weight ÷ volume] = [9N ÷ 0.001m³] = 9000N/m³Density: w = [ × g] Where, g = acceleration due to gravity = 9.81m/sec². Specific gravity: G = [density of liquid ÷ density of water] As you know, The density of water = 1000kg/m³.
The density of a substance is divided by the density of water at 4 degrees Celsius to determine its specific gravity. The density of the substance and the density of the water must be represented in the same units for the calculation.distinguishes While specific weight has dimensions, specific gravity is a dimensionless number. The gravitational field has no effect on a material's specific gravity, but it does have an effect on a material's specific weight. A substance's "Specific Gravity" is determined by dividing its mass by the mass of an equivalent volume of water at the same pressure and temperature.
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According to a recent study quoted in the textbook, __________________ were the number one skill(s) that college graduates found useful in the business world. Group of answer choices
Answers
Answer: According to a recent study quoted in the textbook, communication and interpersonal skills were the number one skill(s) that college graduates found useful in the business world.
Explanation:
the soil profile at a beach site consists of relatively uniform medium dense sand (unit weight 19 kn/m3 ) to a depth of 5 m. a project calls for building a pier founded on timber piles driven into the sand. the stress conditions in the sand need to be determined to calculate the amount of skin friction developed along the length of the driven piles. calculate the effective stress at 5 m depth assuming low tide where the water level is 2 m below the ground surface. calculate the effective stress at 5 m depth now assuming high tide where the water level is 2 m above the ground surface.
Answers
The effective stress at 5 m depth would be 75.38 kPa
Effective stress is the stress that is transmitted between soil particles, and is important for calculating the amount of skin friction developed along the length of driven piles. To calculate the effective stress at a depth of 5 m, we need to consider the weight of the soil above the depth of interest and the weight of the water above the soil. For low tide conditions, the water level is 2 m below the ground surface, so the effective stress at 5 m depth would be the unit weight of the sand multiplied by the depth of soil above it, which is 5 m. Thus, the effective stress at 5 m depth would be 95 kPa (19 kN/\(m^3\)x 5 m).
For high tide conditions, the water level is 2 m above the ground surface, so we need to consider the weight of the water as well. The weight of the water above the 5 m depth of soil is (2 m x 9.81 kN/\(m^3\)), which is 19.62 kN/\(m^2\). Therefore, the effective stress at 5 m depth would be the unit weight of the sand multiplied by the depth of soil above it (5 m) minus the weight of the water above it (19.62 kN/\(m^2\)). Thus, the effective stress at 5 m depth would be 75.38 kPa (19 kN/\(m^3\) x 5 m - 19.62 kN/\(m^2\)).
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A four-lane divided multilane highway (two lanes in each direction) in rolling terrain has five access points per mile and 11-ft lanes with a 4-ft shoulder on the right side and a 2-ft shoulder on the left. The peak-hour factor is 0.84 and the traffic stream consists of 6% trucks, 4% buses, and 3% recreational vehicles. The driver population adjustment factor is estimated at 0.90. If the analysis flow rate is 1250 pc/h/ln, what is the peak-hour volume
Answers
Answer:
peak-hour volume = 1890 veh/h
Explanation:
Determine the peak-hour Volume
Applying the equation below
Vp = v / ( PHF * N * Fg * Fdp ) -------------- ( 1 )
where :
Vp = 1250
v ( peak - hour volume ) = ?
PHF ( peak hour factor ) = 0.84
N = 2 lanes per direction
Fg ( grade adjustment for rolling terrain ) = 0.99 ≈ 1
Fdp = 0.90
Back to equation 1
v = Vp ( PHF * N * Fg * Fdp )
= 1250 ( 0.84 * 2 * 1 * 0.90 )
= 1890 veh/h
Compare laminar and turbulent flow in a horizontal pipe. Assume both flows have the same diameter, volume flow rate, and inlet static pressure. a. Sketch velocity profiles for fully developed laminar and turbulent flow (for turbulent, plot u). Discuss the difference in shape and role of the Reynolds stress, - pu'u'. b. Compare (qualitatively) the development of the flows from the pipe inlet to the fully developed region (recall problem H1.4). Plot the centerline velocity, wall shear stress, and static pressure, as functions of distance along the pipe, I. Clearly indicate how the two flows compare in terms of the entrance length, and the behavior and relative magnitudes) in the fully developed region.
Answers
Laminar flow in a horizontal pipe occurs when the fluid moves in parallel layers with no mixing between them. In contrast, turbulent flow is characterized by chaotic motion and mixing of fluid particles.
In fully developed laminar flow, the velocity profile is parabolic, with the maximum velocity at the center of the pipe and the minimum velocity at the wall. For fully developed turbulent flow, the velocity profile is flatter, with a higher velocity gradient near the wall due to the presence of turbulent eddies. The Reynolds stress (-pu'u') plays a significant role in turbulent flow, as it is responsible for the transfer of momentum between fluid particles. In laminar flow, the Reynolds stress is negligible.
Regarding the development of the flows from the pipe inlet to the fully developed region, laminar flow develops smoothly with no significant fluctuations, while turbulent flow undergoes significant fluctuations and vortices, resulting in a longer entrance length.
In conclusion, for a horizontal pipe with the same diameter, volume flow rate, and inlet static pressure, laminar flow has a parabolic velocity profile with negligible Reynolds stress, while turbulent flow has a flatter velocity profile with a significant Reynolds stress. Laminar flow develops smoothly, while turbulent flow has significant fluctuations and requires a longer entrance length.
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Have you ever had an ice cream headache that’s when a painful sensation resonates in your head after eating something cold usually ice cream on a hot day this pain is produced by the dilation of a nerve center in the roof of your mouth the nerve center is overreacting to the cold by trying to hit your brain ice cream headaches have turned many smiles to frowns identify the structure
Answers
Answer:
Cause and effect
Explanation:
pls mark brainliest
The structure that makes or turned many smiles to frowns can be regarded as compare/contrast.
What is compare contrast?The term compare/contrast is a common terms. The act of comparing is known to be depicting the similarities, and contrasting is said to be showing differences that exist between two things.
Conclusively, from the above, we can see that it is a compare/contrast scenario as it talks about the effects of taking ice cream. It went from smiles to frowns.
See option below
cause/effect
descriptive
compare/contrast
sequence/process
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A group of students launches a model rocket in the vertical direction. Based on tracking data, they determine that the altitude of the rocket was 89.6 ft at the end of the powered portion of the flight and that the rocket landed 16.5 s later. The descent parachute failed to deploy so that the rocket fell freely to the ground after reaching its maximum altitude. Assume that g = 32.2 ft/s2.
Determine
(a) the speed v1 of the rocket at the end of powered flight,
(b) the maximum altitude reached by the rocket.
Answers
Answer:
\(u = 260.22m/s\)
\(S_{max} = 1141.07ft\)
Explanation:
Given
\(S_0 = 89.6ft\) --- Initial altitude
\(S_{16.5} = 0ft\) -- Altitude after 16.5 seconds
\(a = -g = -32.2ft/s^2\) --- Acceleration (It is negative because it is an upward movement i.e. against gravity)
Solving (a): Final Speed of the rocket
To do this, we make use of:
\(S = ut + \frac{1}{2}at^2\)
The final altitude after 16.5 seconds is represented as:
\(S_{16.5} = S_0 + ut + \frac{1}{2}at^2\)
Substitute the following values:
\(S_0 = 89.6ft\) \(S_{16.5} = 0ft\) \(a = -g = -32.2ft/s^2\) and \(t = 16.5\)
So, we have:
\(0 = 89.6 + u * 16.5 - \frac{1}{2} * 32.2 * 16.5^2\)
\(0 = 89.6 + u * 16.5 - \frac{1}{2} * 8766.45\)
\(0 = 89.6 + 16.5u- 4383.225\)
Collect Like Terms
\(16.5u = -89.6 +4383.225\)
\(16.5u = 4293.625\)
Make u the subject
\(u = \frac{4293.625}{16.5}\)
\(u = 260.21969697\)
\(u = 260.22m/s\)
Solving (b): The maximum height attained
First, we calculate the time taken to attain the maximum height.
Using:
\(v=u + at\)
At the maximum height:
\(v =0\) --- The final velocity
\(u = 260.22m/s\)
\(a = -g = -32.2ft/s^2\)
So, we have:
\(0 = 260.22 - 32.2t\)
Collect Like Terms
\(32.2t = 260.22\)
Make t the subject
\(t = \frac{260.22}{ 32.2}\)
\(t = 8.08s\)
The maximum height is then calculated as:
\(S_{max} = S_0 + ut + \frac{1}{2}at^2\)
This gives:
\(S_{max} = 89.6 + 260.22 * 8.08 - \frac{1}{2} * 32.2 * 8.08^2\)
\(S_{max} = 89.6 + 260.22 * 8.08 - \frac{1}{2} * 2102.22\)
\(S_{max} = 89.6 + 260.22 * 8.08 - 1051.11\)
\(S_{max} = 1141.0676\)
\(S_{max} = 1141.07ft\)
Hence, the maximum height is 1141.07ft
A system will never enter a deadlocked state if:__________A) the system chooses to ignore the problem altogether.B) the system uses the detection and recovery technique.C) the system uses the deadlock avoidance technique.D) None of the above.
Answers
A system will never enter a deadlocked state if the system uses the detection and recovery technique. Thus the correct option is B.
What is deadlocked state?A deadlock in desktop software happens when a procedure or task enters a waiting state as a result of another waiting process holding the requested system resource.
When a group of processes is in a wait state, a deadlock occurs because each process is awaiting a resource that is being held by another waiting process.
The wait-for graph must be maintained by the system in order to detect deadlocks, and the system periodically runs an operation that looks for cycles in the wait-for graph.
There is no method used by the OS to avoid or stop deadlocks. The OS checks the system on a regular basis for any deadlocks in an effort to break them. Therefore, option B is appropriate.
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A doctor is deciding how to treat a given disease. the doctor will precribe one medication, one dietary change, and one type of vitamin supplement. there are five medications, five dietary changes, and five types of vitamins the doctor might prescribe. how many combina-tions are possible?
Answers
The total combinations are possible is 125 combinations.
We need to know about math combinations to solve this problem. The combination is the number of ways to choose a sample of r elements from a set of n distinct objects where order does not matter and replacements are not allowed. It can be written as
nCr = n! / (r!(n-r)!)
where n is object and r is a sample
From the question above, we know that
1 vitamin supplement chosen has combination
5C1 = 5! / 1!(5-1)! = 5 combination
1 meditation chosen has combination
5C1 = 5! / 1!(5-1)! = 5 combination
and 1 dietary chosen has combination
5C1 = 5! / 1!(5-1)! = 5 combination
Hence, the total combination is
C = Cvitamin x Cmeditation x Cdietery
C = 5 x 5 x 5
C = 125 combinations
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a low carbon steel is heated to a temperature below the lower transformation temperature before cooling in an effort to soften it slightly. which is the heat treating process being performed?
Answers
The heat treating process being performed when a low carbon steel is heated to a temperature below the lower transformation temperature before cooling in an effort to soften it slightly is known as annealing.
Annealing is a heat treatment process that involves heating a metal to a specific temperature and holding it there for a certain amount of time before allowing it to cool down slowly. The purpose of annealing is to make a metal softer, more ductile, and more machinable. It also improves its toughness and makes it easier to form.Annealing can be done in several different ways, including full annealing, stress relief annealing, and spheroidizing annealing.
Full annealing involves heating the metal to a temperature above its upper critical temperature, holding it there for a period of time, and then allowing it to cool down slowly. Stress relief annealing involves heating the metal to a lower temperature and holding it there for a shorter period of time, while spheroidizing annealing is used to improve the machinability of high-carbon steels.
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Multiple Select
In the following list, what are criteria that would be important to someone buying a Jersey cow
milk production
health
Speed
age
hoof color
Answers
Answer:
Milk Production, Health, and Age.
Explanation:
You want a younger cow when buying cattle so you can have gather more milk from it over it's lifetime. You also want to make sure that it can actually produce milk. Then you want a cow in good health.
To find the reactance XLXLX_L of an inductor, imagine that a current I(t)=I0sin(ωt)I(t)=I0sin(ωt) , is flowing through the inductor. What is the voltage V(t)V(t)V(t) across this inductor?
Answers
Answer:
V(t) = XLI₀sin(π/2 - ωt)
Explanation:
According to Maxwell's equation which is expressed as;
V(t) = dФ/dt ........(1)
Magnetic flux Ф can also be expressed as;
Ф = LI(t)
Where
L = inductance of the inductor
I = current in Ampere
We can therefore Express Maxwell equation as:
V(t) = dLI(t)/dt ....... (2)
Since the inductance is constant then voltage remains
V(t) = LdI(t)/dt
In an AC circuit, the current is time varying and it is given in the form of
I(t) = I₀sin(ωt)
Substitutes the current I(t) into equation (2)
Then the voltage across inductor will be expressed as
V(t) = Ld(I₀sin(ωt))/dt
V(t) = LI₀ωcos(ωt)
Where cos(ωt) = sin(π/2 - ωt)
Then
V(t) = ωLI₀sin(π/2 - ωt) .....(3)
Because the voltage and current are out of phase with the phase difference of π/2 or 90°
The inductive reactance XL = ωL
Substitute ωL for XL in equation (3)
Therefore, the voltage across inductor is can be expressed as;
V(t) = XLI₀sin(π/2 - ωt)
to be usable in an automotive electrical system, the ac output of the alternator must be ____ into dc.
Answers
To be usable in an automotive electrical system, the AC output of the alternator must be converted into DC.
This is typically accomplished by the use of a rectifier, which is a device that converts alternating current (AC) to direct current (DC). The rectifier allows the vehicle's electrical system to be powered by the DC output of the alternator, which is necessary for the operation of various components such as the battery, lights, ignition system, and other electrical accessories.
An automotive electrical system refers to the network of electrical components and wiring found in vehicles. It provides power and facilitates the operation of various systems and components in the vehicle, including the engine, lights, audio system, climate control, and more. Here are some key elements and components of an automotive electrical system:
Battery: The battery is the primary power source in a vehicle. It supplies electrical energy to start the engine and powers the vehicle's electrical systems when the engine is not runningAlternator: The alternator generates electricity and charges the battery while the engine is running. It ensures a steady supply of electrical power to the vehicle's electrical system and recharges the batteryStarter motor: The starter motor is responsible for cranking the engine and starting the combustion process. It draws electrical power from the battery to turn the engine's crankshaft until it starts running independentlyWiring and connectors: An intricate network of wires and connectors carries electrical current throughout the vehicle, connecting various components and systems. Wiring harnesses are used to organize and protect the wiresFuses and relays: Fuses are safety devices designed to protect the electrical system from overloading and short circuits. They contain a metal strip that melts and breaks the electrical circuit when excess current flows. Relays are electrically operated switches that control high-current circuits using low-current signalsIgnition system: The ignition system includes components like ignition coils, spark plugs, and ignition control modules. It generates the high-voltage electrical spark required to ignite the air-fuel mixture in the engine's cylindersLighting system: The lighting system encompasses headlights, taillights, turn signals, brake lights, interior lights, and other illumination components. These lights are powered by the electrical system and provide visibility and safetyElectronics and control modules: Modern vehicles incorporate numerous electronic systems and control modules to manage various functions. Examples include the engine control module (ECM), body control module (BCM), anti-lock braking system (ABS) module, and more.To know more about DC, visit the link : https://brainly.com/question/10715323
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The UHRS platform is optimized for Edge/Internet Explorer only. You can still use your favorite browser, but keep in mind that you may experience technical issues when working on UHRS with a different browser than Edge or Internet Explorer.
UHRS is optimized for...
Answers
It is to be noted that all UHRS platforms are optimized for the popular kinds of internet browser applications.
What is a UHRS?The Universal Human Relevance System (UHRS) is a crowdsourcing platform that allows for data labeling for a variety of AI application situations.
Vendor partners link people referred to as "judges" to offer data labeling at scale for us. All UHRS judges are bound by an NDA, ensuring that data is kept protected.
A browser is a software tool that allows you to see and interact with all of the knowledgeon the World Wide Web. Web sites, movies, and photos are all examples of this.
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A pump is positioned at 2 m above the water of the reservoir. The inlet of the pipe connected to the pump is positioned at 6m beneath the water of the reservoir. When a pump draws 220 m3/hour of water at 20 °C from a reservoir, the total friction head loss is 5 m. The diameter of the pipe connected to the inlet and exit nozzle of the pump is 12 cm and 5 cm, respectively. The flow discharges through the exit nozzle to the atmosphere. Calculate the pump power in kW delivered to the water.
Answers
Answer:
The pump delivers 32.737 kilowatts to the water.
Explanation:
We can describe the system by applying the Principle of Energy Conservation and the Work-Energy Theorem, the pump system, which works at steady state and changes due to temperature are neglected, is represented by the following model:
\(\dot W_{in} + \dot m \cdot g \cdot (z_{1}-z_{2}) + \frac{1}{2}\cdot \dot m \cdot (v_{1}^{2}-v_{2}^{2})+\dot m \cdot [(u_{1}+P_{1}\cdot \nu_{1})-(u_{2}+P_{2}\cdot \nu_{2})]-\dot E_{losses} = 0\) (Eq. 2)
Where:
\(\dot m\) - Mass flow, measured in kilograms per second.
\(g\) - Gravitational acceleration, measured in meters per square second.
\(z_{1}\), \(z_{2}\) - Initial and final heights, measured in meters.
\(v_{1}\), \(v_{2}\) - Initial and final flow speeds at pump nozzles, measured in meters per second.
\(u_{1}\), \(u_{2}\) - Initial and final internal energies, measured in joules per kilogram.
\(P_{1}\), \(P_{2}\) - Initial and final pressures, measured in pascals.
\(\nu_{1}\), \(\nu_{2}\) - Initial and final specific volumes, measured in cubic meters per kilogram.
Then, we get this expression:
\(\dot W_{in} + \dot m \cdot g \cdot (z_{1}-z_{2}) +\frac{1}{2}\cdot \dot m \cdot (v_{1}^{2}-v_{2}^{2}) +\dot m\cdot \nu \cdot (P_{1}-P_{2})-\dot E_{losses} = 0\) (Ec. 3)
We note that specific volume is the reciprocal of density:
\(\nu = \frac{1}{\rho}\) (Ec. 4)
Where \(\rho\) is the density of water, measured in kilograms per cubic meter.
The initial pressure of water (\(P_{1}\)), measured in pascals, can be found by Hydrostatics:
\(P_{1} = P_{atm} + \rho\cdot g \cdot \Delta z\) (Ec. 5)
Where:
\(P_{atm}\) - Atmospheric pressure, measured in pascals.
\(\Delta z\) - Depth of the entrance of the inlet pipe with respect to the limit of the water reservoir.
If we know that \(p_{atm} = 101325\,Pa\), \(\rho = 1000\,\frac{kg}{m^{3}}\), \(g = 9.807\,\frac{m}{s^{2}}\) and \(\Delta z = 6\,m\), then:
\(P_{1} = 101325\,Pa+\left(1000\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}})\cdot (6\,m)\)
\(P_{1} = 160167\,Pa\)
And the specific volume of water (\(\nu\)), measured in cubic meters per kilogram, is: (\(\rho = 1000\,\frac{kg}{m^{3}}\))
\(\nu = \frac{1}{1000\,\frac{kg}{m^{3}} }\)
\(\nu = 1\times 10^{-3}\,\frac{m^{3}}{kg}\)
The power losses due to friction is found by this expression:
\(\dot E_{losses} = \dot m \cdot g\cdot h_{losses}\)
Where \(h_{losses}\) is the total friction head loss, measured in meters.
The mass flow is obtained by this:
\(\dot m = \rho \cdot \dot V\) (Ec. 6)
Where \(\dot V\) is the volumetric flow, measured in cubic meters per second.
If we know that \(\rho = 1000\,\frac{kg}{m^{3}}\) and \(\dot V = 0.061\,\frac{m^{3}}{s}\), then:
\(\dot m = \left(1000\,\frac{kg}{m^{3}}\right)\cdot \left(0.061\,\frac{m^{3}}{s} \right)\)
\(\dot m = 61\,\frac{kg}{s}\)
Then, the power loss due to friction is: (\(h_{losses} = 5\,m\))
\(\dot E_{losses} = \left(61\,\frac{kg}{s}\right)\cdot \left(9.807\,\frac{m}{s^{2}} \right) \cdot (5\,m)\)
\(\dot E_{losses} = 2991.135\,W\)
Now, we calculate the inlet and outlet speed by this formula:
\(v = \frac{\dot V}{\frac{\pi}{4}\cdot D^{2} }\) (Ec. 7)
Inlet nozzle (\(\dot V = 0.061\,\frac{m^{3}}{s}\), \(D = 0.12\,m\))
\(v_{1} = \frac{0.061\,\frac{m^{3}}{s} }{\frac{\pi}{4}\cdot (0.12\,m)^{2} }\)
\(v_{1} \approx 5.394\,\frac{m}{s}\)
Oulet nozzle (\(\dot V = 0.061\,\frac{m^{3}}{s}\), \(D = 0.05\,m\))
\(v_{2} = \frac{0.061\,\frac{m^{3}}{s} }{\frac{\pi}{4}\cdot (0.05\,m)^{2} }\)
\(v_{2} \approx 31.067\,\frac{m}{s}\)
(\(\dot m = 61\,\frac{kg}{s}\), \(g = 9.807\,\frac{m}{s^{2}}\), \(z_{2} = 2\,m\), \(z_{1} = -6\,m\), \(v_{2} \approx 31.067\,\frac{m}{s}\), \(v_{1} \approx 5.394\,\frac{m}{s}\), \(P_{2} = 101325\,Pa\), \(P_{1} = 160167\,Pa\), \(\dot E_{losses} = 2991.135\,W\))
\(\dot W_{in} = \left(61\,\frac{kg}{s}\right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot [2\,m-(-6\,m)]+\frac{1}{2}\cdot \left(61\,\frac{kg}{s}\right) \cdot \left[\left(31.067\,\frac{m}{s} \right)^{2}-\left(5.394\,\frac{m}{s} \right)^{2}\right] +\left(61\,\frac{kg}{s}\right)\cdot \left(1\times 10^{-3}\,\frac{m^{3}}{kg} \right)\cdot (101325\,Pa-160167\,Pa)+2991.135\,W\)
\(\dot W_{in} = 32737.518\,W\)
The pump delivers 32.737 kilowatts to the water.
Suppose you have two arrays: Arr1 and Arr2. Arr1 will be sorted values. For each element v in Arr2, you need to write a pseudo code that will print the number of elements in Arr1 that is less than or equal to v. For example: suppose you are given two arrays of size 5 and 3 respectively. 5 3 [size of the arrays] Arr1 = 1 3 5 7 9 Arr2 = 6 4 8 The output should be 3 2 4 Explanation: Firstly, you should search how many numbers are there in Arr1 which are less than 6. There are 1, 3, 5 which are less than 6 (total 3 numbers). Therefore, the answer for 6 will be 3. After that, you will do the same thing for 4 and 8 and output the corresponding answers which are 2 and 4. Your searching method should not take more than O (log n) time. Sample Input Sample Output 5 5 1 1 2 2 5 3 1 4 1 5 4 2 4 2 5
Answers
Answer:
The algorithm is as follows:
1. Declare Arr1 and Arr2
2. Get Input for Arr1 and Arr2
3. Initialize count to 0
4. For i in Arr2
4.1 For j in Arr1:
4.1.1 If i > j Then
4.1.1.1 count = count + 1
4.2 End j loop
4.3 Print count
4.4 count = 0
4.5 End i loop
5. End
Explanation:
This declares both arrays
1. Declare Arr1 and Arr2
This gets input for both arrays
2. Get Input for Arr1 and Arr2
This initializes count to 0
3. Initialize count to 0
This iterates through Arr2
4. For i in Arr2
This iterates through Arr1 (An inner loop)
4.1 For j in Arr1:
This checks if current element is greater than current element in Arr1
4.1.1 If i > j Then
If yes, count is incremented by 1
4.1.1.1 count = count + 1
This ends the inner loop
4.2 End j loop
Print count and set count to 0
4.3 Print count
4.4 count = 0
End the outer loop
4.5 End i loop
End the algorithm
5. End
help protect the lower legs and feet from heat hazards like molten metal and welding sparks
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Answer:
i think its called leggings thats wut my shop teacher told me
Explanation:
Help me for this question
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Which of these was not part of the OBD II implementation?
OA. Common Codes
OB. Readiness Monitors
OC. Digital Processing
OD. Standard Terminologies
Answers
The Digital Processing is not part of the OBD II implementation.
What is an OBD II system?OBD II is known to be a kind of acronym for On-Board Diagnostic II. This is known to be the second generation of on-board self-diagnostic equipment that is needed for light- and medium-duty California vehicles.
The OBD-II is said to be a kind of on-board computer that handles emissions, , speed, etc.
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The procedure that scientists should follow when investigating nature
Answers
2. Make a hypothesis (prediction)
3. Gather data from outside
4. Analyse the data
5. Draw a conclusion and see if it fits with the hypothesis
6. See how you can improve the experiment
pls discuss the concepts in which architectural forms/visuals correlate in the design process
Answers
Answer:
Visual connectivity refers to the tangible aspects of a space; extent to which a place can be viewed from other places. It is believed that the design properties of a spatial layout of an atrium leaves unobstructed views horizontally and vertically.
Explanation:
Assignment 1: Structural Design of Rectangular Reinforced Concrete Beams for Bending
Perform structural design of a rectangular reinforced concrete beam for bending. The beam is simply supported and has a span L=20 feet. In addition to its own weight the beam should support a superimposed dead load of 0.50 k/ft and a live load of 0.65 k/ft. Use a beam width of 12 inches. The depth of the beam should satisfy the ACI stipulations for minimum depth and be proportioned for economy. Concrete compressive strength f’c = 4,000 psi and yield stress of reinforcing bars fy = 60,000 psi. Size of stirrups should be chosen based on the size of the reinforcing bars. The beam is neither exposed to weather nor in contact with the ground, meaning it is subjected to interior exposure.
• Use the reference on "Practical Considerations for Rectangular Reinforced Concrete Beams"
• Include references to ACI code – see slides from second class
• Include references to Tables from Appendix A
• Draw a sketch of the reinforced concrete beam showing all dimensions, number and size of rebars, including stirrups.
Answers
Answer:
Beam of 25" depth and 12" width is sufficient.
I've attached a detailed section of the beam.
Explanation:
We are given;
Beam Span; L = 20 ft
Dead load; DL = 0.50 k/ft
Live load; LL = 0.65 k/ft.
Beam width; b = 12 inches
From ACI code, ultimate load is given as;
W_u = 1.2DL + 1.6LL
Thus;
W_u = 1.2(0.5) + 1.6(0.65)
W_u = 1.64 k/ft
Now, ultimate moment is given by the formula;
M_u = (W_u × L²)/8
M_u = (1.64 × 20²)/8
M_u = 82 k-ft
Since span is 20 ft, it's a bit larger than the average span beams, thus, let's try a depth of d = 25 inches.
Effective depth of a beam is given by the formula;
d_eff = d - clear cover - stirrup diameter - ½Main bar diameter
Now, let's adopt the following;
Clear cover = 1.5"
Stirrup diameter = 0.5"
Main bar diameter = 1"
Thus;
d_eff = 25" - 1.5" - 0.5" - ½(1")
d_eff = 22.5"
Now, let's find steel ratio(ρ) ;
ρ = Total A_s/(b × d_eff)
Now, A_s = ½ × area of main diameter bar
Thus, A_s = ½ × π × 1² = 0.785 in²
Let's use Nominal number of 3 bars as our main diameter bars.
Thus, total A_s = 3 × 0.785
Total A_s = 2.355 in²
Hence;
ρ = 2.355/(22.5 × 12)
ρ = 0.008722
Design moment Capacity is given;
M_n = Φ * ρ * Fy * b * d²[1 – (0.59ρfy/fc’)]/12
Φ is 0.9
f’c = 4,000 psi = 4 kpsi
fy = 60,000 psi = 60 kpsi
M_n = 0.9 × 0.008722 × 60 × 12 × 22.5²[1 - (0.59 × 0.008722 × 60/4)]/12
M_n = 220.03 k-ft
Thus: M_n > M_u
Thus, the beam of 25" depth and 12" width is sufficient.
In order to avoid slipping in the shop, your footwear should ___________.
A) Be brand-new
B) Have steel toes
C) Not have shoestrings
D) Have proper tread
Answers
The correct answer to this question is D) Have proper tread.
Proper tread on footwear can greatly reduce the risk of slipping in the shop. Shoes or boots with a non-slip sole or a tread pattern that provides good traction on various surfaces are ideal for a shop environment. However, it is important to note that shoestrings can also play a role in slipping. Untied shoestrings can cause a person to trip and fall, so it is important to ensure that shoestrings are tied securely. In some cases, shoes without shoestrings may be preferred in a shop environment to avoid this risk altogether. Regardless of whether shoes have shoestrings or not, it is crucial to select footwear that is appropriate for the environment and to regularly inspect and replace worn-out shoes to ensure maximum safety.
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Answer every question of this quiz
Please note: you can answer each question only once.
Which number shows the intake valve?
OK
Answers
I'd say number 4, number 3 looks like an exhaust valve
The shaft is supported at its ends by two journal bearings (at a and b) and is subjected to the forces applied to the pulleys fixed to the shaft. determine the resultant internal loadings acting on the cross section of the shaft at point d.
Answers
We must examine the forces and moments acting on the shaft in order to ascertain the internal loadings that will ultimately affect the cross section of the shaft at point d.
A shaft is a mechanical device that moves torque and power from one place to another. In order to support and transfer torque and axial loads between two or more components, it is a rotating machine element that is typically cylindrical in shape. Shafts are utilised in a variety of equipment, including industrial, mechanical, and automotive applications. The shaft's material varies on the application, and the design must take fatigue and wear into account in addition to bending, torsional, and axial loading. In order to assure dependable operation and avoid equipment damage, proper shaft design is essential and calls for knowledge of both mechanics and materials science.
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Coal can contain up to about 2000 ppm (by mass) of natural uranium. Compare the chemical energy content of the coal with the available fission energy from the 235U content of the uranium (as used in a thermal reactor) and the total available fission energy from the uranium including 238U (as might be used in a breeder reactor).
Answers
About 1 MW is released each day when 1 g of uranium or plutonium fissions. This is roughly equivalent to 3 tons of coal or 600 gallons of fuel oil burned each day, which releases about 1/4 tonne of carbon dioxide when burned. (One metric ton, or tonne, is equal to 1000 kg.)
How much energy is released during a fission of uranium-235?The total binding energy released during the fission of an atomic nucleus varies depending on the exact breakdown but typically ranges between 200 MeV* and 3.2 x 10-11 joules for U-235. About 82 TJ/kg is this.
How much more energy is contained in one gram of 235U than one gram of coal?In actuality, burning 3 tons of coal produces the same amount of energy as fissioning 1 gram of uranium 235 (1)! It is possible to use the energy generated by the fission of uranium or plutonium to generate electricity, launch spacecraft, and power weapons like the atomic bomb.
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