Answer:
Step-by-step explanation:
Base fee = $17.99
Additional charge = $0.95 for each mile driven
If Kevin paid $157.64 when he returned the truck and we want to find out how many miles he drove the truck, step 1 would be to subtract the base fee.
157.65 - 17.99 = 139.65
This means that the remaining $139.65 is how much he paid for the miles he drove.
Since we know each mile costs $0.95.
Simply divide $139.65 by $0.95 to work out how many miles he drove.
Miles driven = 139.65 / 0.95 = ?
Identify the function family to which f(x)=x+3 belongs. a. constant b. linear c. absolute value d. quadratic
Answer:
quadratic
Step-by-step explanation:
Please help I need to do this
Answer:
4:
b) f(-1) = 0.50; f(-2) = 0.25; f(-3) = 0.125
c) Graph is attached -but you will need to do this by hand on the blank graph on the assignment.
5:
a) Increasing, y-intercept at (0, 125)
b) Decreasing, y-intercept at (0, 22)
c) Increasing, y-intercept at (0, 256)
What are the respective names of the points of concurrency?.
The respective names of the point of concurrency is:
1. Circumcenter
2. Incenter.
3. Centroid
4. Orthocenter
Point of concurrency:
The point of concurrency is a point where three or more lines or rays intersect with each other.
Circumcenter:
The circumcenter is the point of concurrency of the perpendicular bisectors of all the sides of a triangle.
Incenter:
The incenter is the point of concurrency of the angle bisectors of all the interior angles of the triangle.
Centroid:
The point where three medians of the triangle meet is known as the centroid.
Orthocenter:
The point where three altitudes of the triangle meet is known as the orthocenter.
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SS below of my question
Answer:
its blurry
Step-by-step explanation:
Answer:
arccos(.34) = 70.12 ≈ 70
Step-by-step explanation:
Adult panda weights are normally distributed with a mean of 200 pounds and a standard deviation of 20 pounds. The largest pandas weigh over 250 pounds.
Approximately what percent of the adult pandas weight over 250 pounds?
0.62%
98.61%
1.39%
98.38%
0.62% of the adult pandas weight over 250 pounds
What is z score?
Z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:
z = (raw score - mean) / standard deviation
Given mean of 200 pounds and a standard deviation of 20 pounds.
For x > 250 pounds:
z = (250 - 200) / 20 = 2.5
P(z > 2.5) = 1 - P(z < 2.5) = 1 - 0.9938 = 0.62%
0.62% of the adult pandas weight over 250 pounds
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$6.75 for .75 pounds of fudge. What is the cost for one pound of fudge?
The cost of 1 pound of fudge is $9.
What is the cost for one pound of fudge?We know that the cost of 0.75 pounds of fudge is $6.75, then we can write a relation of the form:
0.75 pounds = 6.75 dollars
This would be an "equivalence between two units"
Now we can divide both sides by 0.75 to get a 1 in the left side, so we have an "unit of fudge"
(0.75 pounds)/0.75 =(6.75 dollars)/0.75
1 pound = 9 dollars.
The cost of 1pound of fudge is 9 dollars.
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I need help please
Which value is the closest to
0.9 • 997
a. 1,000
b. 81
c. 10,000
d. 10
Answer with supporting work:
Before sunrise, the temperature was 22.4°F below zero. By noon, it had risen 12.8°F. What expression can be used to find the temperature at noon?
–22.4 – 12.8
–22.4 + 12.8
22.4 – 12.8
22.4 + 12.8
The expression that can be used to find the temperature at noon is
–22.4 + 12.8 option B
What is temperature?Generally, The word "temperature" refers to the degree to which something is hot or cold and may be described using a number of different scales, such as Fahrenheit and Celsius.
The direction in that heat energy will spontaneously flow is indicated by temperature; specifically, it will flow from a hotter body (one that is at a higher temperature) to a colder one (one at a lower temperature).
In conclusion, the temperature was 22.4°F below zero meaning
-22.4F in mathematical terms
and 12.8°F above zero in mathematical terms
Therefore, –22.4 + 12.8 is the expression that can be used to find the temperature at noon
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Munding corp. has debt with a market value of $23 million and equity with a market value of $46 million. its pre-tax cost of debt is 5.4% and its cost of equity is 11%. the firm's marginal tax rate is 21%.
The value of the weighted average cost of capital of the firm is 8.8%.
According to the statement
we have to compute the weighted average cost of capital of the firm.
And for this purpose,
The given information is:
debt with market value = $23 million and
equity with market value = $46
Pre-tax cost debt = 5.4%
Cost of equity = 11% and marginal tax rate is 21%
So, The formula to find weighted average cost:
WACC = weight in equity × cost of equity + weight in debt × cost of debt × (1-tax rate)
Substitute the values in it then
Here weight in equity become = 46/(23+46)
weight in equity = 46/69
And
weight in debt = 23/69.
So, put the values then
WACC = 46/69 × 0.11 + 23/69 × 0.054 × (1 - 0.21)
WACC = 0.67 × 0.11 + 0.34 × 0.054 × (1 - 0.21)
WACC = 0.0737 + 0.01836 (0.79)
WACC = 0.0737 + 0.0145
WACC = 0.0882
WACC = 8.8%
So, The value of the weighted average cost of capital of the firm is 8.8%.
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10x - 4 + 5x + 19 = 180
What is the value of x
Answer:
x=11
Step-by-step explanation:
Answer:
x=11
Step-by-step explanation:
10x-4+5x+19=180
Combine like terms
15x+15=180
-15 -15
15x=165
divide by 15
x=11
18 points ! The shape of Gretchen's data can be described as 1) skewed left 2) skewed right 3) symmetrical.
Because of this, the 1) mean 2) median would be the best measure of center for this data set. The actual value for the best measure of center is 1) 7, 2) 9, 3) 9. 1, 4) 9. 6
The first blank is skewed left, the second blank is median, and the third blank is 9 is correct options.
What is skewed left?A distribution that is left-skewing has a lengthy left tail.
Distributions that are negatively skewed are also known as left-skewed distributions.
This is due to the number line having a significant negative tail.
Additionally, the peak is to the left of the mean.
The right tail of a right-skewed distribution is lengthy.
It's a widespread misperception that "peakness" is defined by the distribution's peak.
To put it another way, a peak that leans left indicates a left-skewed distribution.
Hence, The first blank is skewed left, the second blank is median, and the third blank is 9 is correct options.
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stion 5 of 9A line in the coordinate plane passes through the point and is parallel to the line with equation .
The Solution:
We want to find the equation of a line S, which passes through point (6,2).
Let the required equation of line S be
\(y-y_1=m(x-x_1)\)Where m = the slope of line S, and
\(\begin{gathered} x_1=6 \\ y_1=2 \end{gathered}\)We are told that line S is parallel to line r, which is, y = 56x + 1. This implies that both lines have the same slope (m).
So, to find the slope (m) of line S, we shall compare y=56x+1 to the general form of equation of a line as given below:
\(y=mx+c\)Comparing both equations below:
\(\begin{gathered} y=mx+c \\ y=56x+1 \\ \text{ We have that,} \\ m=56 \end{gathered}\)Substituting 56 for m, and the given point (6,2) in the formula above, we get
\(y-2=56(x-6)\)Clearing the bracket, we get
\(\begin{gathered} y-2=56x-336 \\ y=56x-336+2 \\ y=56x-334 \end{gathered}\)Thus, the equation of line r is: y = 56x - 334
check by differentiation that y = 3cos3t 4sin3t is a solution
To check if y = 3cos(3t) + 4sin(3t) is a solution by differentiation, we will differentiate y with respect to t and use the chain rule.
y = 3cos(3t) + 4sin(3t)
dy/dt = -9sin(3t) + 12cos(3t)
The differentiation confirms that the given function y = 3cos(3t) + 4sin(3t) is a valid solution, as we were able to compute its derivative with respect to t without encountering any issues.
To check whether y = 3cos3t 4sin3t is a solution, we need to differentiate it with respect to t and see if it satisfies the differential equation.
y = 3cos3t 4sin3t
dy/dt = -9sin3t + 12cos3t
Now, we substitute y and dy/dt into the differential equation:
d^2y/dt^2 + 9y = 0
(d/dt)(dy/dt) + 9y = 0
(-9sin3t + 12cos3t) + 9(3cos3t 4sin3t) = 0
-27sin3t + 36cos3t + 36cos3t + 27sin3t = 0
As we can see, the equation simplifies to 0=0, which means that y = 3cos3t 4sin3t is indeed a solution to the differential equation.
Therefore, we can conclude that y = 3cos3t 4sin3t satisfies the differential equation and is a valid solution.
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This equation has one solution. 5(x – 1) 3x = 7(x 1) what is the solution?
Answer:
send the complete question . there are some missing signs .
Let l be the line perpendicular to the plane x - 2y - 4z = 5 and containing the point (2, -5, 0). determine whether the following points lie on line l.
The given points, only the point (4, -9, -8) lies on line 1.
To determine whether certain points lie on the line 1, which is perpendicular to the plane x - 2y - 4z = 5 and contains the point (2, -5, 0), we can check if the coordinates of those points satisfy the equation of the line.
The direction vector of the line 1 is perpendicular to the plane and can be determined from the coefficients of x, y, and z in the plane equation. In this case, the direction vector of the line is (1, -2, -4).
Now, we can write the parametric equation of the line l as:
x = 2 + t * 1
y = -5 + t * (-2)
z = 0 + t * (-4)
To check if a point (x₀, y₀, z₀) lies on the line 1, we need to find a value of t that satisfies the parametric equations.
Let's consider the following points and determine if they lie on line 1:
Point (3, -6, -4)
To check if this point lies on line 1, we substitute the coordinates (x₀, y₀, z₀) = (3, -6, -4) into the parametric equations:
x₀ = 2 + t * 1 --> 3 = 2 + t --> t = 1
y₀ = -5 + t * (-2) --> -6 = -5 - 2 --> t = -1
z₀ = 0 + t * (-4) --> -4 = 0 - 4t --> t = 1
The value of t is not consistent across all equations, so the point (3, -6, -4) does not lie on line 1.
Point (2, -5, 0)
This point is given as the point that line 1 contains. Therefore, it lies on line 1.
Point (4, -9, -8)
To check if this point lies on line 1, we substitute the coordinates (x₀, y₀, z₀) = (4, -9, -8) into the parametric equations:
x₀ = 2 + t * 1 --> 4 = 2 + t --> t = 2
y₀ = -5 + t * (-2) --> -9 = -5 - 2t --> t = 2
z₀ = 0 + t * (-4) --> -8 = 0 - 8t --> t = 1
The value of t is consistent across all equations, so the point (4, -9, -8) lies on line 1.
Therefore, among the given points, only the point (4, -9, -8) lies on line 1.
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The complete question is:
Let l be the line perpendicular to the plane x - 2y - 4z = 5 and containing the point (2, -5, 0). determine whether the following points lie on line l.
Write an equation if the line that passes through (0,-2) and (2,2)
Answer:
\(y=2x-2\)
Step-by-step explanation:
Hi there!
Linear equations are typically organized in slope-intercept form: \(y=mx+b\) where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)
1) Determine the slope (m)
\(m=\frac{y_2-y_1}{x_2-x_1}\) where the two points are \((x_1,y_1)\) and \((x_2,y_2)\)
Plug in the given points (0,-2) and (2,2)
\(=\frac{2-(-2)}{2-0}\\=\frac{2+2}{2}\\=\frac{4}{2}\\=2\)
Therefore, the slope of the line is 2. Plug this into \(y=mx+b\) as m:
\(y=2x+b\)
2) Determine the y-intercept (b)
\(y=2x+b\)
Plug in one of the given points and solve for b
\(2=2(2)+b\\2=4+b\)
Subtract 4 from both sides to isolate b
\(2-4=4+b-4\\-2=b\)
Therefore, the y-intercept of the line is -2. Plug this back into \(y=2x+b\)
\(y=2x-2\)
I hope this helps!
a statistical procedure used to describe the strength and direction of the linear relationship between two factors is called ______
The statistical procedure used to describe the strength and direction of the linear relationship between two factors is called correlation analysis.
Correlation analysis is a statistical technique that examines the relationship between two variables to determine the strength and direction of their association. It focuses specifically on the linear relationship between the variables, which means it assumes that the relationship can be represented by a straight line.
The result of a correlation analysis is often expressed as a correlation coefficient, which measures the degree of association between the variables. The correlation coefficient ranges from -1 to 1, where:
A correlation coefficient of -1 indicates a perfect negative correlation, meaning that as one variable increases, the other variable decreases in a consistent manner.
A correlation coefficient of 1 indicates a perfect positive correlation, meaning that as one variable increases, the other variable also increases in a consistent manner.
A correlation coefficient close to 0 indicates a weak or no linear correlation between the variables.
Correlation analysis helps to understand the relationship between variables and can provide insights into patterns, trends, and dependencies in the data. However, it is important to note that correlation does not imply causation, meaning that a strong correlation between two variables does not necessarily imply that one variable causes the other to change.
In addition to determining the correlation coefficient, correlation analysis can also involve generating a scatter plot to visualize the relationship between the variables and conducting hypothesis tests to assess the statistical significance of the correlation.
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Let X denote the proportion of allotted time that a randomly selected student spends working on a certain aptitude test. Suppose the p of X is f(x; 0) 1) = {(8 + 1) x ² (0+1)x 0≤x≤ 1 otherwise wh
The probability density function (pdf) of X, denoted as f(x; 0), is
f(x; 0) = (8 + 1) x^2 (0 + 1) x for 0 ≤ x ≤ 1, and 0 otherwise.
The probability density function (pdf) represents the likelihood of a random variable taking on different values. In this case, X represents the proportion of allotted time that a randomly selected student spends working on a certain aptitude test.
The given pdf, f(x; 0), is defined as (8 + 1) x^2 (0 + 1) x for 0 ≤ x ≤ 1, and 0 otherwise. Let's break down the expression:
(8 + 1) represents the coefficient or normalization factor to ensure that the integral of the pdf over its entire range is equal to 1.
x^2 denotes the quadratic term, indicating that the pdf increases as x approaches 1.
(0 + 1) x is the linear term, suggesting that the pdf increases linearly as x increases.
The condition 0 ≤ x ≤ 1 indicates the valid range of the random variable x.
For values of x outside the range 0 ≤ x ≤ 1, the pdf is 0, as indicated by the "otherwise" statement.
Hence, the pdf of X is given by f(x; 0) = (8 + 1) x^2 (0 + 1) x for 0 ≤ x ≤ 1, and 0 otherwise.
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(1 point) Find the orthogonal projection of \[ \vec{v}=\left[\begin{array}{l} 8 \\ 2 \\ 3 \\ 0 \end{array}\right] \] onto the subspace \( W \) of \( \mathbb{R}^{4} \) spanned by \[ \left[\begin{array}
Given that
\(\[\vec{v}=\begin{bmatrix} 8 \\ 2 \\ 3 \\ 0 \end{bmatrix}\]\)
And the subspace W spanned by
\(\[ \begin{bmatrix} 1 \\ 1 \\ 1 \\ 1 \end{bmatrix}\), \(\begin{bmatrix} 1 \\ 1 \\ -1 \\ -1 \end{bmatrix}\]\)
To find the orthogonal projection of \(\[\vec{v}\]\) onto the subspace W of \(\[\mathbb{R}^{4}\]\) spanned by the above two vectors,
first we need to check if the given two vectors form a basis for the subspace W or not.To check whether the given two vectors form a basis for the subspace W, we can arrange the two given vectors in a matrix form and find its rank.Let
\(\[A = \begin{bmatrix} 1 & 1 \\ 1 & 1 \\ 1 & -1 \\ 1 & -1 \end{bmatrix}\]\)
Then by calculating its row reduced echelon form, we have
\(\[\begin{bmatrix} 1 & 1 \\ 0 & 0 \\ 0 & 0 \\ 0 & 0 \end{bmatrix}\]\)
Hence, the rank of the matrix is 1 and therefore the dimension of the subspace is 1. Thus the given two vectors do not form a basis for the subspace W.
To find a basis for the subspace W, we can take the first vector as it is,
\(\[u_1 = \begin{bmatrix} 1 \\ 1 \\ 1 \\ 1 \\\end{bmatrix}\\\[u_2 = \begin{bmatrix} 1 \\ 1 \\ -1 \\ -1 \end{bmatrix}\\\]\\\\\\\u_1 - \frac{u_1^Tu_2}{u_2^Tu_2}\\\u_2 = \begin{bmatrix} 1 \\ 1 \\ 1 \\ 1 \end{bmatrix} - \frac{2}{4}\begin{bmatrix} 1 \\ 1 \\ -1 \\ -1 \end{bmatrix} = \begin{bmatrix} \frac{1}{2} \\ \frac{1}{2} \\ \frac{3}{2} \\ \frac{3}{2} \end{bmatrix}\]\)
and subtract its projection along the second vector.
Therefore, the orthogonal projection of \(\[\vec{v}\]\) onto the subspace W of \(\[\mathbb{R}^{4}\]\)spanned by
\(\[ \begin{bmatrix} 1 \\ 1 \\ 1 \\ 1 \end{bmatrix}, \begin{bmatrix} 1 \\ 1 \\ -1 \\ -1 \end{bmatrix}\]\)
is given by
\(\[\frac{(\vec{v} \cdot u_1)}{(u_1 \cdot u_1)}u_1 = \frac{13}{4}\begin{bmatrix} 1 \\ 1 \\ 1 \\ 1 \end{bmatrix}\]\)
Thus, the required orthogonal projection of \(\[\vec{v}\]\) onto the subspace W is \(\[\frac{13}{4}\begin{bmatrix} 1 \\ 1 \\ 1 \\ 1 \end{bmatrix}\]\).
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please help me answer the question in the picture
Answer:
-4 because they are parallel (if it is parallel it will be equal)
the main cables of a suspension bridge are 20 meters above the road at the towers and 4 meters above the road at the center. the road is 80 meters long. vertical cables are spaced every 10 meters. the main cables hang in the shape of a parabola. find the equation of the parabola. then, determine how high the main cable is 20 meters from the center.
The height of the main cable 20 meters from the center is 16 meters above the road.
To find the equation of the parabola, we need to use the information given about the height of the cables at the towers and the center of the bridge. We know that the main cables are 20 meters above the road at the towers, so we can use this information to find the distance between the towers, which is
distance between towers = 80 meters - 2(20 meters) = 40 meters
We also know that the main cables are 4 meters above the road at the center, so we can use this information to find the height of the vertex of the parabola, which is
vertex height = 4 meters + 20 meters = 24 meters
We can now use the vertex form of a parabola to write the equation
y = a(x - h)^2 + k
where (h, k) is the vertex and a is a constant that determines the shape of the parabola.
Substituting the values we found for the vertex height and the distance between the towers, we get
y = a(x - 40)^2 + 24
We now need to find the value of a. To do this, we can use the fact that the vertical cables are spaced every 10 meters. This means that the distance between the vertex of the parabola and a point on the main cable 10 meters from the center of the bridge is
distance = 10 meters
Substituting x = 50 (since the center of the bridge is at x = 40 + 10 = 50) and y = 14 (since the cable is 4 meters above the road at this point), we get
14 = a(50 - 40)^2 + 24
-10 = 100a
a = -0.1
Substituting this value of a into the equation we found earlier, we get
y = -0.1(x - 40)^2 + 24
To find the height of the main cable 20 meters from the center, we can substitute x = 60 (since the center of the bridge is at x = 50 and we want to go 20 meters to the right) into the equation
y = -0.1(60 - 40)^2 + 24
y = -0.1(20)^2 + 24
y = -0.1(400) + 24
y = -40 + 24
y = -16
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48[3+15÷{4+10÷(3-13)}] help me to solve this...!
Answer:
Step-by-step explanation:
48[3+15÷{4+10÷(3-13)}]
=48[ 3+15%{4+10%(-10)}]
=48[3+15%{4-1}]
=48[3+15%3]
=48[3+5]
=48*8
=384
Suppose bob's exam score was at the 80th percentile on an exam whose mean was 90. what was bob's exam score?
The mean score of 90, and percentile of Bob's score of 80, gives Bob's exam score as approximately 92.5%
What is the formula that gives the exam score from the percentile?The Z-Score of the 80th percentile is 0.8416
The formula for Z-Score is presented as follows;
\(z = \frac{x - \mu}{ \sigma} \)
Where;
\( \sigma = The \: standard \: deviation\)
\( \mu = The \: mean = 90\%\)
x = The given score
Taking the mean as a proportion, we have;
\( \sigma = \sqrt{\frac{\mu \cdot (1-\mu)}{n}}\)
Which gives;
\( \sigma = \sqrt{\frac{0.9 \times (1-0.9)}{100}}= 0.03\)
Therefore, when z = 0.8416, gives;
\(0.8416 = \frac{x - 0.9}{ 0.03} \)
x = 0.8416 × 0.03 + 0.9 ≈ 0.925
Therefore;
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Please answer this correctly, and you'll recieve brainliest!
Which figure can be transformed into figure L by a 90° rotation clockwise about the origin followed by a translation 2 units down?
Question Options:
Question 2 options:
figure J
figure M
figure N
figure P
Answer:
J can be rotated
Step-by-step explanation:
Answer: Figure J
Clockwise and 2 units down
calculate the average lateness using the earliest due date criterion to determine the schedule for these five jobs. job process time due date a 2 7 b 8 16 c 4 4 d 10 17 e 5 15
A 3
B. 124
C. 10
D. 14
Therefore, the average lateness using the earliest due date criterion is 2. The corect option is not one of the given options (A, B, C, or D).
To calculate the average lateness using the earliest due date criterion, we need to first determine the sequence in which the jobs should be processed. The earliest due date (EDD) criterion schedules jobs in the order of increasing due dates, so we will arrange the jobs in this order:
c, a, e, b, d
The table below shows the processing time, due date, and completion time of each job, as well as the lateness (completion time - due date) for each job:
Job Processing Time Due Date Completion Time Lateness
c 4 4 4 0
a 2 7 6 -1
e 5 15 11 -4
b 8 16 19 3
d 10 17 29 12
To calculate the average lateness, we add up the lateness values for all jobs and divide by the total number of jobs:
Average lateness = (0 + (-1) + (-4) + 3 + 12) / 5
= 2
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Need the answer for this
Answer:
Your answer is correct. The midpoint is (2,4).
Step-by-step explanation:
That line segment is 6 units long. Halfway through would be 3 units. And that halfway point was (2,4).
Answer:
(2, 4)
Step-by-step explanation:
Read the coordinates of points C and D off the graph:
C(-1, 7)
D(5, 1)
To find the coordinates of the midpoint:
The x-coordinate of the midpoint is: Add the x-coordinates and divide by 2.
The y-coordinate of the midpoint is: Add the y-coordinates and divide by 2.
x:
(-1 + 5)/2 = 4/2 = 2
y:
(7 + 1)/2 = 8/2 = 4
Answer: (2, 4)
t to the second power - 12w ÷ x
t=8
w=1/2
x=3
Answer:
62
Step-by-step explanation:
Since we know what each value of the three variables are, you can substitute each variable in the expression to get:
\(8^{2} -12(\frac{1}{2})\) ÷ 3
Simplify to get:
64 - 6 ÷ 3
Solve the rest:
64 - 2 → 62
Answer: 62
Hope this helps! :)
2. is line parallel to line ? choose the best justiication. a. line is parallel to line because triangle is a dilation of triangle by a scale factor of 3 from point . b. line is parallel to line because triangle is a dilation of triangle by a scale factor of 2 from point . c. line is parallel to line because triangle is a dilation of triangle by a scale factor of from point . d. line is not parallel to line because there is no dilation that sends triangle to triangle .
Line is not parallel to line because no scaling from point can transform triangle into triangle.
Line is not parallel to line because there is no transformation that can send triangle to triangle. A transformation is a function that changes the location, size, or orientation of an object. A dilation of a shape is a transformation that changes its size, either making it larger or smaller, but does not change its orientation. To determine if two lines are parallel, one must consider if a dilation from a point can send one line to the other. In this case, there is no dilation from point that can send triangle to triangle, so line is not parallel to line.
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let g be the function defined by g(x)=∫x−1(−12 cos(t 3 2t))ⅆt for 0
Let g be the integral function defined by g(x) = ∫x-1 (-1/2 * cos (t³ / 2t)) dt for x = 0, g is g(x) = -1/2(x-1 * sin(t³/2t) - x-1 * cos(t³/2t)).
To solve this integral, we need to use the substitution method. We will let u = t/2t, du = 3t/2 dt.
Thus, the integral becomes:
g(x) = -1/2 * ∫x-1 cos(u) du
Using integration by parts, we get:
g(x) = -1/2(x-1 * sin(u) + ∫x-1 sin(u) du).
After integrating the second part, we obtain the final result:
g(x) = -1/2(x-1 * sin(u) - x-1 * cos(u))./2t
we subtitute the value of u to get:
g(x) = -1/2(x-1 * sin(t³/2t) - x-1 * cos(t³/2t)).
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After arianna completed some work, she figured she still had 78 21/100 pictures to paint. if she completed another 34 23/25 pictures, how many pictures did arianna still have to paint
Plz be a long answer
Answer:
43 29/100
Step-by-step explanation:
Subtract 34 23/25 from 78 21/100.
To do this, you have to turn 23/25 to something over 100.
Multiply the numerator and denominator by 4, since that is how you get 25 to 100. This will give you 92/100. So now you have 32 92/100
You have to take away one from 78, which makes it 77 and then add 100 to 21, since 100 is equal to 1.
You now have 77 121/100 - 32 92/100.
77 121/100 - 32 92/100 = 43 29/100