karsten has 5 apples rebecca has 10 apples how many apples are there in total? yes

Answer:

102.5

Step-by-step explanation:

Average = sum count.

205/2

If you wanted to determine if your PSYC210 class performed significantly better than another section on a stats knowledge test, you would use a hypothesis test, specifically a two-sample t-test.

A hypothesis test is a statistical method used to determine whether there is a significant difference between two groups or populations based on their observed data. In this case, you would compare the mean score of your PSYC210 class on the stats knowledge test with the mean score of the other section using a two-sample t-test. The null hypothesis would be that there is no significant difference between the means of the two sections, and the alternative hypothesis would be that there is a significant difference.

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Answer:

Step-by-step explanation:

Sale price of the coat:

Total of three items:

Add tax to get the total:

Answer:

(-4,2)

Step-by-step explanation:

See attachment

The function values are:

h(-3) = -2, h(-1) = 2, and h(2) = 3.

We have,

To evaluate the piecewise-defined function h, we need to consider the given conditions for different intervals.

- For x ≤ -2, the function is defined as h(x) = -2.

- For -2 < x < 1, the function is defined as h(x) = x² + 1.

- For x ≥ 1, the function is defined as h(x) = x + 1.

Let's evaluate the function for different values of x:

For x = -3 (x ≤ -2):

Since x is less than -2, the function h(x) = -2.

Therefore, h(-3) = -2.

For x = -1 (x > -2 and x < 1):

Since -2 < -1 < 1, the function h(x) = x² + 1.

Therefore, h(-1) = (-1)² + 1 = 2.

For x = 2 (x ≥ 1):

Since x is greater than or equal to 1, the function h(x) = x + 1.

Therefore, h(2) = 2 + 1 = 3.

Therefore,

The function values are:

h(-3) = -2, h(-1) = 2, and h(2) = 3.

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The simplified expression of cos^2x sin^4x is cos^2x - 2cos^4x + cos^6x.

The expression cos^2x sin^4x can be simplified by using the trigonometric identity that states sin^2x + cos^2x = 1.

We can rewrite cos^2x sin^4x as cos^2x (sin^2x)^2. Then, using the trigonometric identity sin^2x + cos^2x = 1, we can substitute (1 - cos^2x) for sin^2x.

This gives us cos^2x (1 - cos^2x)^2, which can be expanded using the binomial theorem to give cos^2x (1 - 2cos^2x + cos^4x).

Finally, we can simplify this expression further by distributing the cos^2x term and collecting like terms to get cos^2x - 2cos^4x + cos^6x.

Therefore, the simplified expression of cos^2x sin^4x is cos^2x - 2cos^4x + cos^6x.

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To find the surface area of the figure, we need to consider the individual surfaces and add them together.

First, let's identify the surfaces of the figure:

The lateral surface area of the larger prism (excluding the base)

The two bases of the larger prism

The lateral surface area of the smaller prism (excluding the base)

The two bases of the smaller prism

The lateral surface area of a prism is given by the formula: perimeter of the base multiplied by the height.

The bases of the prisms are rectangles, so their areas can be calculated by multiplying the length by the width.

To find the missing prism's surface area, we need to consider that it is a smaller prism nested inside the larger prism. The lateral surface area and bases of the missing prism should also be included.

Once we have calculated the individual surface areas, we add them together to find the total surface area of the figure.

Without specific measurements or dimensions of the figure, it is not possible to provide a numerical answer. Please provide the necessary measurements or dimensions to calculate the surface area.

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The number of ways to form an 8-person committee with 4 men and 4 women is 9,180. The number of ways to form a committee with at least 2 men is 70,320. The number of ways to form a committee with more women than men is 7,620. This can be solved by the concept of  Permutation and Combination.

If the committee must contain four men and four women, there are 7,425 ways to form the committee. If there must be at least two men, there are 58,275 ways to form the committee. If there must be more women than men, there are 26,207,700 ways to form the committee.

To find the number of ways to form a committee with four men and four women, we can use combinations. The number of ways to choose 4 men out of 12 is 495, and the number of ways to choose 4 women out of 15 is 1,365.

To get the total number of ways, we can multiply these numbers:

495 x 1,365 = 7,425.

To find the number of ways to form a committee with at least two men, we need to consider two cases: 2 men and 6 women, and 3 men and 5 women. For the first case, we can choose 2 men out of 12 in 495 ways, and 6 women out of 15 in 5,005 ways. For the second case, we can choose 3 men out of 12 in 2,190 ways, and 5 women out of 15 in 3,003 ways.

To get the total number of ways, we can add these numbers:

495 x 5,005 + 2,190 x 3,003 = 58,275.

To find the number of ways to form a committee with more women than men, we can use a different approach. We can count all the possible committees with 1 man, 2 men, 3 men, and 4 men, and then subtract the committees that have more men than women. There are 15 ways to choose 1 man, 330 ways to choose 2 men, 3,960 ways to choose 3 men, and 12,870 ways to choose 4 men.

To count the committees with more men than women, we can use the complement rule. This means we need to count the committees with 4 men and 0, 1, 2, or 3 women, the committees with 3 men and 0 or 1 women, the committees with 2 men and 0 women, and the committee with 1 man and 0 women.

Adding these numbers gives us the total number of committees with more women than men:

15 + 330 + 1,320 + 2,772 + 330 + 15 = 26,207,700

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Answer:

8.4

Step-by-step explanation:

How many times 20 goes into 168 = 168/20

                                                         = 8.4

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Answer: $20.40

Step-by-step explanation:

Just add

Let's call the price of an adult ticket as A and the price a student ticket as S. From the first two sentences "A drama club earns $1040 from a production. A total of 64 adult tickets and 132 student tickets were sold." we know that the total amount earned was $1040, and this value was reached by selling 64 adult tickets and 132 student tickets. The amount earned selling adult tickets is given by the product between the unitary price of an adult ticket and the amount of adult tickets sold. The same logic goes to the amount earned selling student tickets. We know that the sum of those two quantities adds up to $1040, therefore, we have the following equation.

From the other sentence, "An adult ticket costs twice the price of a student ticket. " we get a new relationship between A and S. A is equal to 2S.

Now we have a system with two variables and two equations. If we substitute the second equation on the first one we get a new equation only for S.

Solving this equation for S, we have

The student ticket price is $4.

Using this value for S, we can substitute in one of the equations to find the value for A.

The price of the adult ticket is $8.

Answer:

40.28$

Step-by-step explanation:

The value of pi is known to over 31 trillion decimal places, thanks to the use of powerful computers and sophisticated algorithms.

The history of pi dates back thousands of years, and over time, various civilizations have attempted to calculate its value with varying degrees of accuracy. One of the most inaccurate versions of pi was recorded by the ancient Babylonians around 2000 BC.

The Babylonians calculated the value of pi as 3.125, which is off by more than 6% from the actual value. It is believed that the Babylonians arrived at this value by using a rough approximation of a circle as a hexagon. They measured the perimeter of the hexagon and divided it by the diameter to get their approximation of pi.

This value was later refined by the ancient Egyptians and Greeks, who were able to calculate pi with greater accuracy. The Greek mathematician Archimedes, for instance, was able to calculate pi to within 1% accuracy by using a method of exhaustion.

It wasn't until the development of calculus in the 17th century that mathematicians were able to derive an exact formula for pi. Today, the value of pi is known to over 31 trillion decimal places, thanks to the use of powerful computers and sophisticated algorithms.

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The exponential growth or decay of a certain phenomenon, such as population growth or decay, over time. The graph typically looks like an “S” or exponential curve, with an initial slow start then an increasing or decreasing rate of change.

20An example of an exponential graph is one that shows the exponential growth or decay of a certain phenomenon, such as population growth or decay, over time. The graph typically looks like an “S” or exponential curve, with an initial slow start followed by an increasing or decreasing rate of change. This rate of change is often characterized by a mathematical function, such as an exponential function, which can be used to calculate the expected change in the phenomenon over a given period of time. For example, an exponential graph can be used to show how a population will grow or decline over time, based on its current population size, growth rate, and other factors. Exponential graphs can also be used to show the growth or decay of a chemical reaction, the rate of change of a financial asset, or any other phenomenon that can be characterized by an exponential function.

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Answer: 6x

Step-by-step explanation:

so consider x as the number,

twice of x= 2x

2x tripled= 2x*3

               = (2*3)x

               = 6x

Answer:

Step-by-step explanation:

We will use 2 coordinates from the table along with the standard form for an exponential function to write the equation that models that data. The standard form for an exponential function is

\(y=a(b)^x\) where x and y are coordinates from the table, a is the initial value, and b is the growth/decay rate. I will use the first 2 coordinates from the table: (0, 3) and (1, 1.5)

Solving first for a:

\(3=a(b)^0\). Sine anything in the world raised to a power of 0 is 1, we can determine that

a = 3. Using that value along with the x and y from the second coordinate I chose, I can then solve for b:

\(1.5=3(b)^1\). Since b to the first is just b:

1.5 = 3b so

b = .5

Filling in our model:

\(y=3(\frac{1}{2})^x\)

Since the value for b is greater than 0 but less than 1 (in other words a fraction smaller than 1), this table represents a decay function.

The number of elements in the sample space for this experiment is 969.

If a person eating at a cafeteria must choose 3 of 19 vegetables on offer, we can calculate the number of elements in the sample space, or the total number of possible outcomes, using the formula for combinations:

nCr = n! / [r!(n - r)!]

where n is the total number of items in the set and r is the number of items being chosen.

In this case, we have 19 vegetables and we want to choose 3 of them, so we can plug in n = 19 and r = 3:

19C3 = 19! / [3!(19 - 3)!]

= 19! / (3!)(16!)

= 969

Therefore, there are 969 possible combinations of 3 vegetables that a person can choose from a selection of 19 vegetables.

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Answer:

C. The point (20, 45) is on the line.

Step-by-step explanation:

The number of songs learned by Audra vs the number of months is plotted in the graph provided.

Some points are recognized from the graph: (0,5) (1,7) (2,9) among others. With two of these points, we construct the linear model of the graph.

The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:

\(\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\)

Using (0,5) and (1,7):

\(\displaystyle y-5=\frac{7-5}{1-0}(x-0)\)

\(\displaystyle y-5=\frac{2}{1}(x-0)\)

y - 5 = 2x

y = 2x + 5

The slope of the line is 2. So, A. and B are discarded.

The y-intercept represents the number of songs Audra played initially at time = 0.

The point (20,45) is on the line as we'll prove below:

y = 2(20) + 5 = 40 + 5 = 45

When x=20, y=45

Thus, the correct choice is:

C. The point (20, 45) is on the line.

Answer:(D) is the answer

Step-by-step explanation:

for every cup grandma uses 3/4 of a cup of strawberry

The value of the function f(x)-g(x)-h(x) is -5x^2+6x+6. Option D

It is important that we know functions are expressions showing the relationship between two variables.

These variables are called;

From the information given, we have the functions as;

f(x)=3x+5 g(x)=4x^2-2 h(x)=x^2-3x+1

Now, to determine the function, f(x)-g(x)-h(x). substitute the expressions, we get;

f(x)-g(x)-h(x) =3x + 5 - 4x² + 2 - x² + 3x - 1

Now, collect the like terms, we get;

f(x)-g(x)-h(x) = -4x² - x² + 3x+ 3x + 5 + 2 - 1

Add or subtract the like terms, we get;

f(x)-g(x)-h(x) = -5x² + 6x + 6

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Answer:

81 inches

Step-by-step explanation:

To find the volume of a rectangular prism you multiply the width × the height × the length.

So it would be 3×9×3 which equals to 81 inches

Answer: V = height*length*width = 3*3*9 = 81

Step-by-step explanation: 81

a) Cov(Xs, Xt) is equal to Pt,t−1 × ϕ^(|t−s|).b) Cov(Xt, Xt) is equal to Pt,t−1 × (1 + ϕ^2).

a) Cov(Xs, Xt) represents the covariance between Xs and Xt. Since the state space model assumes independence of the noise terms (Vt and Wt) and the initial condition (X0), the covariance is determined by the state transition equation Xt = ϕXt−1 + Wt. Therefore, Cov(Xs, Xt) depends on the time difference |t−s| and is given by Pt,t−1 × ϕ^(|t−s|), where Pt,t−1 represents the prediction error variance.

b) Cov(Xt, Xt) represents the covariance of Xt with itself. In this case, the covariance is influenced by both the state transition equation Xt = ϕXt−1 + Wt and the observation equation Yt = Xt + Vt. Since the observation equation includes the noise term Vt, the covariance is affected by the presence of measurement noise. Therefore, Cov(Xt, Xt) is given by Pt,t−1 × (1 + ϕ^2), where Pt,t−1 represents the prediction error variance and (1 + ϕ^2) accounts for the contribution of measurement noise.

Overall, the covariance between Xs and Xt is determined by the prediction error variance Pt,t−1, the time difference |t−s|, and the presence of measurement noise in the model.

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Answer:

1st one is false

the second one is true i think ;-;

3rd is true

4th is false

5th is also false i think

Step-by-step explanation:

Answer:

maybe (-3,-4)?

Step-by-step explanation:

Answer:

Applying Boadmass

( 1-1/4)^-2

(3/4)^-2

(4/3)^2

(1.333) ^2

1.76

Step-by-step explanation:

Answer: The hypotenuse are both 13 cm

Step-by-step explanation:

The length of the hypotenuse of a right triangle can be found using the Pythagorean theorem, which states that the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.

So, in this case:

c^2 = a^2 + b^2

c^2 = 5^2 + 12^2

c^2 = 25 + 144

c^2 = 169

c = √169

c = 13

So the length of the hypotenuse is 13 cm.

Next, we can use the Pythagorean theorem to find the length of the segments into which the bisector of the right angle divides the hypotenuse. Let's call the length of the segments x. Then, the segments form two right triangles with legs of length x and (13-x)/2.

Using the Pythagorean theorem on each triangle, we have:

x^2 + ((13-x)/2)^2 = 13^2

x^2 + (13-x)^2/4 = 169

x^2 + (13^2 - 2x(13) + x^2)/4 = 169

x^2 + (13^2 - 2x(13))/4 = 169

x^2 + (169 - 26x)/4 = 169

x^2 + 169 - 26x = 676

x^2 - 26x + 507 = 0

Now, we can use the quadratic formula to find x:

x = (-b ± √(b^2 - 4ac)) / 2a

a = 1, b = -26, c = 507

x = (26 ± √(26^2 - 4 * 1 * 507)) / 2 * 1

x = (26 ± √(676)) / 2

x = (26 ± 26) / 2

x = 26 / 2

x = 13

So, the lengths of the segments into which the bisector of the right angle divides the hypotenuse are both 13 cm, to the nearest tenth.

Answer:

Yes. The two parallelograms are similar.

Step-by-step explanation:

Similarity:

     Two parallelograms are said to be similar when the corresponding sides are in the same ratio.

  \(\sf \dfrac{WX}{AB}= \dfrac{3}{2}\\\\\dfrac{XY}{BC}=\dfrac{9}{6} = \dfrac{9 \div 3}{6 \div 3}\\\\\)

        \(\sf = \dfrac{3}{2}\)

           \(\bf \dfrac{WX}{AB}=\dfrac{XY}{BC}=\dfrac{3}{2}\)

Therefore, two parallelograms are similar.

The area of pentagon ABCDE is 36 times the area of pentagon PQRST.

Any five-sided polygon or 5-gon is referred to as a pentagon. The area of pentagon ABCDE is 36 times the area of pentagon PQRST.

We have,

Any five-sided polygon or 5-gon is referred to as a pentagon. A basic pentagon's interior angles add up to 540°. A pentagon might be straightforward or self-intersecting.

We know the formula for the area of a pentagon, therefore, the area of the pentagon PQRST can be written as,

A = 1/4 * √5(5+25)*a²

Given that the side of the side length of pentagon ABCDE is 6 times the side length of pentagon PQRST, therefore, the area of the pentagon ABCDE can be written as,

ABCDE = 1/4 * √5(5+25)* 6a²

ABCDE = 36 * A

Hence, The area of pentagon ABCDE is 36 times the area of pentagon PQRST.

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complete question:

Pentagon ABCDE is similar to pentagon PQRST. If the side length of pentagon ABCDE is 6 times the side length of pentagon PQRST, which

statement is true?

A.

The area of pentagon ABCDE IS 6 times the area of pentagon PQRST.

B.

The area of pentagon ABCDE is 12 times the area of pentagon PQRST.

C.

The area of pentagon ABCDE is 36 times the area of pentagon PQRST.

D.

The area of pentagon ABCDE IS 216 times the area of pentagon PQRST.​

The proof of "if group G has exactly one subgroup H of order k, then H is normal in G" is explained below.

If a "group-G" has exactly one subgroup H of order k, we want to show that H is normal in G. This means that for any element g in G, when we conjugate H by g, we get H again.

To prove this, we consider the left cosets of H in G. A left coset of H is formed by taking an element g in G and multiplying it with each element of H. Since H is the only subgroup of order k, each left coset has k elements.

Now, we take any element-g from G. Since the left cosets partition G, g must be in one of these left cosets, which we can write as gH.

When we conjugate H by g, we get gHg⁻¹. This means we multiply each element of H by g and then multiply the result by g⁻¹, the inverse of g.

Since G is a group, this multiplication follows the group's properties.  When we multiply any element of H by g and then by g⁻¹, the result is still an element of H.

Because of this, we can conclude that for any element g in G, the conjugate of H by g (gHg⁻¹) is still a subset of H.

Therefore, H is normal in G.

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The given question is incomplete, the complete question is

If a group G has exactly one subgroup H of order k, prove that H is normal in G.