kali bought 6 books for a total of $154. math books cost $27 and English books cost $23. how many of each type of book did she buy

Answer:

B = A - 4C/3

is your answer

Step-by-step explanation:

To find B you would have to isolate B from the equation itself,

3B + 4C = A

3B = -4C + A

then individualize 3 from B and transfer it as a denominator under - 4C + A

B = - 4C + A/3

then flip around the order to make it systematically correct.

B = A - 4C/3

I hope this helped you!

answers are in the photo

goodluck

The equation is 2n + 3 = 9.

The value of the number is 3.

Option C is the correct answer.

An equation contains one or more than two terms connected by an equal sign.

Example:

2x + 4y = 88 is an equation.

We have,

Let the number be n.

Now,

We can write an equation as,

2n + 3 = 9

Solve for n.

2n + 3 = 9

Subtract 3 on both sides.

2n = 9 - 3

2n = 6

Divide 2 into both sides.

n = 3

Thus,

The value of the number is 3.

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i think it would be 200

Answer:

Step-by-step explanation:

explanation in image

Answer:

87.5 days

Step-by-step explanation:

because 175 divided by 2 is 87.5 check yourself im new to brainly

Answer: 16

Step-by-step explanation:

The fraction in simplest form is 7

First, you must simplify the numerator and denominator of the fraction.

\(\frac{14}{2}\)

Then, divide the numerator by the denominator

7

Scientific notation is the way through which a very small or a very large number can be written in shorthand. The given following number or sentences can be written in the form of scientific notation as shown.

Scientific notation is the way through which a very small or a very large number can be written in shorthand.  In scientific notations when a number between 1 and 10s is multiplied by a power of 10.

For example, 6,500,000,000,000 can be written as 6.5e+12 or 6.5×10¹².

The given following number or sentences can be written in the form of scientific notation as shown below.

a.) 1,000,000 = 1×10⁶ = 1e+6

b.) .00005 = 5×10⁻⁵ = 5e-5

c.) 40 thousand = 40,000 = 4×10⁴ = 4e+4

d.) 7 trillion = 7,000,000,000,000 = 7×10¹² = 7e+12

e.) 8 thousandths = 0.008 = 8×10⁻³ = 8e-3

f.) one tenth = 0.1 = 1×10⁻¹ = 1e-1

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Answer:

A = ( a + b ) 2 × h .

Step-by-step explanation:

A=*124+b)2×h

a) For chi-squared distribution with v=3 degrees of freedom, the statistic that can be constructed using Xi's is:

X2 = Σ i=1 3 (Xi − i)2 / 3.

X2 has chi-squared distribution with 3 degrees of freedom.

b) For t-distribution with v=2 degrees of freedom, the statistic that can be constructed using Xi's is:

T = (X1 − 1) / [(X2/2)0.5].

T has t-distribution with 2 degrees of freedom.

c) For F-distribution with v1=1 and v=2 degrees of freedom, the statistic that can be constructed using Xi's is:

F = [(X1 − 1)/1] / [(Σi=2 to 3 Xi2) / 2].

F has F-distribution with 1 and 2 degrees of freedom.

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A story that can be represented using the equation y=x+1/5x is "John has an apple and he cut another apple into 5 equal parts and took on part. What's the rural fraction of apple that he has?

An equation is the statement that illustrates the variables given. In this case, two or more components are taken into consideration to describe the scenario. It is vital to note that an equation is a mathematical statement which is made up of two expressions that are connected by an equal sign.

In this case, if John has an apple and he cut another apple into 5 equal parts and took on part.

This can be illustrated as:

y = x + 1/5x

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Use the "zero" or "root" function to find x-intercepts, and examine the sign of the derivative to determine intervals of increase and decrease.

To find the intervals of increase and decrease on a graphing calculator, you need to first find the x-intercepts of the function. This can be done using the "zero" or "root" function on the calculator.

Once you have found the x-intercepts, you need to examine the sign of the derivative of the function to determine the intervals of increase and decrease.

To find the derivative of a function on a graphing calculator, you can use the "dy/dx" or "derivative" function. Once you have the derivative, you need to look for where it is positive or negative.

If the derivative is positive, the function is increasing, and if the derivative is negative, the function is decreasing. The intervals of increase and decrease can then be determined by looking for where the derivative changes sign.

By using these functions on the graphing calculator, you can quickly and easily determine the intervals of increase and decrease for a given function.

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Answer:

Heart sounds

Step-by-step explanation:

Answer:

6x6=36

Step-by-step explanation:

Answer: The answer is 6

Step-by-step explanation:

the way you find the answer is you divide 36 by 6. the reason why is the answer of 36 divided by six is tyhe other number you need to get to 36.

I hope this is not to confusing. Can you please give me branilyest

Since we know that C = 3.14 * d and we know that d = 14

C = 3.14 * 14

C = 43.96ft

Answer:

She could  make the triangle smaller by making the same triangle but smaller and add the same sides to the small triangle.

scale factors she could use to make the triangle smaller is \(\frac{1}{2}\)

Given :

Priya drew a triangle with the side lengths 3, 4, 5

Given options are :

1.) 1/2

2.) 1

3.) 2

4.) 6

Explanation :

The ratio of the measurement of the corresponding sides of a triangle is a scale factor .

When we multiply the side length by a scale factor >1 that gives a bigger scaled copy

When we multiply the side length by a scale factor <1 that gives a smaller scaled copy

From the given options , scale factor 1/2 is less than 1

So 1/2 is the scale factor that could use to make the triangle smaller

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The mean crack size is 1.25 mm.

(a) To sketch the PDF and CDF, we can plot the given probability density function (PDF) on a graph paper.

The PDF f_X(x) is defined as follows:

f_X(x) = {

x/8 for 0 < x ≤ 2,

1/4 for 2 < x ≤ 5,

0 elsewhere

}

First, let's plot the PDF on the graph paper:

        |       .     .

   1/4  |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

   0.2  |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

   0.1  |   .   .   .   .

        | . . . . . . . .

        +----------------

          0   2   4   6

The height of the PDF corresponds to the probability density at a given value of x.

Next, let's calculate the cumulative distribution function (CDF) to sketch it on the graph paper.

The CDF is obtained by integrating the PDF from negative infinity to x:

F_X(x) = ∫[0,x] f_X(t) dt

For 0 ≤ x ≤ 2:

F_X(x) = ∫[0,x] (t/8) dt = (1/8) * ∫[0,x] t dt = (1/8) * (t^2/2)|[0,x] = (1/8) * (x^2/2) = x^2/16

For 2 < x ≤ 5:The height of the PDF corresponds to the probability density at a given value of x.

Next, let's calculate the cumulative distribution function (CDF) to sketch it on the graph paper.

The CDF is obtained by integrating the PDF from negative infinity to x:

F_X(x) = ∫[0,x] f_X(t) dt

For 0 ≤ x ≤ 2:

F_X(x) = ∫[0,x] (t/8) dt = (1/8) * ∫[0,x] t dt = (1/8) * (t^2/2)|[0,x] = (1/8) * (x^2/2) = x^2/16

For 2 < x ≤ 5:The height of the PDF corresponds to the probability density at a given value of x.

Next, let's calculate the cumulative distribution function (CDF) to sketch it on the graph paper.

The CDF is obtained by integrating the PDF from negative infinity to x:

F_X(x) = ∫[0,x] f_X(t) dt

For 0 ≤ x ≤ 2:

F_X(x) = ∫[0,x] (t/8) dt = (1/8) * ∫[0,x] t dt = (1/8) * (t^2/2)|[0,x] = (1/8) * (x^2/2) = x^2/16

For 2 < x ≤ 5:F_X(x) = ∫[0,2] (t/8) dt + ∫[2,x] (1/4) dt = (1/8) * ∫[0,2] t dt + (1/4) * ∫[2,x] dt = (1/8) * (t^2/2)|[0,2] + (1/4) * (t)|[2,x] = (1/8) * 2 + (1/4) * (x-2) = 1/4 + (1/4) * (x-2) = 1/4 + (x-2)/4 = (x+1)/4

For x > 5:

F_X(x) = 1

Now, let's plot the CDF on the same graph paper:

        | . . . . . . . .

   1    | . . . . . . . .

        | . . . . . . . .

        | . . . . . . . .

        | . . . . . . . .

   0.8  | . . . . . . . .

        | . . . . . . . .

        | . . . . . . . .

        | . . . . . . . .

   0.6  | . . . . . . . .

        | . . . . . . . .

        | . . . . . . . .

        | . . . . . . . .

   0.4  | . . . . . . . .

        |

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The magnitude of ab -> is 7.28 units and the direction is 111.8°.

To find the magnitude and direction of ab ->, we first need to find the components of the vector ab ->. The components can be found by subtracting the coordinates of a from the coordinates of b.

So, the x-component of ab -> is (-2) - (-4) = 2 and the y-component of ab -> is 13 - 6 = 7.

The magnitude of ab -> can be found using the Pythagorean theorem:

|ab ->| = sqrt((2)^2 + (7)^2) = 7.28 units (rounded to two decimal places).

The direction of ab -> can be found using trigonometry.

tan(theta) = (y-component of ab ->) / (x-component of ab ->) = 7/2

theta = arctan(7/2) = 111.8° (rounded to one decimal place)

Therefore, the magnitude of ab -> is 7.28 units and the direction is 111.8°.

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What is 1100112 ternary in decimal? 1100112 from ternary to decimal is 986. Here we show you how to write 11001123 in decimal and how to convert 1100112 from base-3 to base-10.

Number:

11001123 in decimal

986

^10

Answer:

986.10

Step-by-step explanation:

To convert ternary number 1100112 to decimal, follow these two steps:

Start from one's place in 1100112 : multiply ones place with 3^0, tens place with 3^1, hundreds place with 3^2 and so on from right to left

Add all the product we got from step 1 to get the decimal equivalent of 1100112.

Using the above steps, here is the work involved in the solution for converting 1100112 to decimal number (Don't forget that we start from ones place to so on...)

Decimal equivalent of "2" = 2 × 3^0 = 2

Decimal equivalent of "1" = 1 × 3^1 = 3

Decimal equivalent of "1" = 1 × 3^2 = 9

Decimal equivalent of "0" = 0 × 3^3 = 0

Decimal equivalent of "0" = 0 × 3^4 = 0

Decimal equivalent of "1" = 1 × 3^5 = 243

Decimal equivalent of "1" = 1 × 3^6 = 729

Decimal equivalent of "1100112" = 72924300932

1100112 = 986.10

Here is the final answer, The ternary number 1100112 converted to decimal is therefore equal to:

986.10

Heat loss, according to Newton's cooling curve, is exponential. Like a half-life, it operates.

Cake temperature and ambient temperature varied by 140 F. The cake has lost half of that difference after 30 minutes, thus that is the half-life. It will shed another half or 35 F in the next 30 minutes, bringing the temperature to 105 F. It will shed 17.5 F in about 30 minutes, leaving 87.5 F.

The temperature is between the last two, at 100 F, so it will be between an hour and an hour and a half. You get an interpolated result of about an hour and ten minutes.

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Answer:

The population after 7 years will be 11887

Step-by-step explanation:

Given

Population = P_0 = 10000

Growth Rate = r = 2.5%

Time = t = 7

The formula for calculating the population after given time at given rate is:

The population after 7 years will be 11887

Step-by-step explanation:

To organize the provided data, we can create a table comparing the samples of couples with children (sample 1) and childless couples (sample 2) as follows:

Sample Sample Size Sample Mean Sample Standard Deviation

1 78 51.1 4.7

2 94 45.2 12.1

In this table, we have listed the sample number (1 and 2), the sample size (number of couples in each group), the sample mean (average Marital Satisfaction Inventory score), and the sample standard deviation (measure of variability in the scores) for each group. This organization allows us to compare the data and proceed with hypothesis testing on the difference in population means between the two groups.

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Hello and Greetings Brainly users.

This is an exercise in "Equation of the line that passes through two points". The equation of a line is a mathematical formula used to describe a straight line in a Cartesian plane.

To find the equation of a line that passes through two points, you must first calculate the slope using the formula: m = (y₂ - y₁) / (x₂ - x₁), where (x₁, y₁) and (x₂, y₂) are the given points. Then, the point-slope form of the equation of the line is used to obtain the equation of the line: y - y₁ = m(x - x₁).

By solving this equation, we can obtain the equation of the line that passes through two points. If the slope of the line is zero, as in the case of two points lying on the same horizontal line, then the equation of the line is simply a horizontal line at y = k, where k is the y-coordinate of the points.

Applying the following formula:

m = (y₂ - y₁) / (x₂ - x₁)

where m is the slope of the line.

We find that the points are:

x₁ = 6 ,   y₁ = 4

x₂ = -5 , y₂ = 4

We substitute the data in the formula and solve:

m = (y₂ - y₁) / (x₂ - x₁)

m = (4 - 4)/(-5-6)

m = 0/-11

m = 0

Now, we can use the point-slope form of the equation of the line to obtain the equation of the line:

Where m = 0 and (x₁, y₁) is one of the two given points. We can choose any of the two points, but for this we will choose (6,4).

So, substituting the values we have, we have:

y - 4 = 0(x - 6)

Simplifying, we arrive at:

y - 4 = 0

y = 4

The equation of the line that passes through the points (6,4) and (-5,4) is y = 4 , since it is a horizontal straight line through the values of y = 4.

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The solution to the system is Option B. There is one unique solution, (−6, 5).

Given system of equations are:2x + 4y = 8 2x + 6y = 18

To graph the given system of equations, we can first convert them into slope intercept form as:y = -x/2 + 2y = -x/3 + 3

To convert 2x + 4y = 8 into slope intercept form, we can isolate y as follows:2x + 4y = 8 4y = -2x + 8 y = -x/2 + 2.

To convert 2x + 6y = 18 into slope intercept form, we can isolate y as follows:2x + 6y = 18 6y = -2x + 18 y = -x/3 + 3

Now we can plot these two lines on a coordinate plane and find the point of intersection to determine the solution to the system.

The graph of the given system of equations is as follows:From the graph, we can see that the two lines intersect at the point (-6, 5).

Therefore, the solution to the system is one unique solution, (-6, 5).Option B is correct.

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For each given sample result, the p-value and conclusion are as follows:

a. p-value = 0.0067, Conclusion: Reject H0,  b. p-value = 0.0830, Conclusion: Fail to reject H0, c. p-value = 0.0322, Conclusion: Reject H0

d. p-value = 0.6221, Conclusion: Fail to reject H0

The p-value is a measure of the evidence against the null hypothesis (H0). It represents the probability of obtaining a sample result as extreme as or more extreme than the observed result, assuming the null hypothesis is true. A p-value less than the significance level (α) indicates strong evidence against the null hypothesis and suggests that the alternative hypothesis (Ha) may be true.

a. For p = .68, we need to determine the probability of observing a sample proportion as extreme as or less than .68, assuming the null hypothesis is true. By conducting the appropriate statistical test (e.g., using the normal approximation to the binomial distribution), we find the p-value to be 0.0067. Since the p-value is less than α = .05, we reject the null hypothesis and conclude that there is evidence to support the claim that the proportion is less than .75.

b. For p = .72, the p-value represents the probability of observing a sample proportion as extreme as or less than .72. Calculating the p-value using the appropriate statistical test yields 0.0830. Since the p-value is greater than α = .05, we fail to reject the null hypothesis. Therefore, we do not have sufficient evidence to conclude that the proportion is less than .75.

c. With p = .70, the p-value indicates the probability of observing a sample proportion as extreme as or less than .70. The calculated p-value is 0.0322. As the p-value is less than α = .05, we reject the null hypothesis and conclude that there is evidence to suggest that the proportion is less than .75.

d. For p = .77, the p-value represents the probability of observing a sample proportion as extreme as or greater than .77. After performing the necessary calculations, we find the p-value to be 0.6221. Since the p-value is much greater than α = .05, we fail to reject the null hypothesis. Consequently, we do not have sufficient evidence to conclude that the proportion is less than .75.

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Answer:

x-5

Step-by-step explanation:

"difference" means subtraction. since there isn't a specific number given then we can use x. "and" indicates where the symbols goes.

The correct answer to the question is option d) 75 PCF.

To calculate the expected vertical load, we need to consider the weight of the concrete slab and the additional load due to the concrete's temperature and pouring rate. The weight of the slab can be calculated by multiplying the density of the concrete (150 PCF) by the depth (6 inches) and the area (1 square foot). This gives us a weight of 75 pounds per square foot (PSF).

The temperature and pouring rate do not directly affect the vertical load. The temperature and pouring rate are factors that may affect the structural integrity of the slab or the time it takes for the concrete to fully cure. However, they do not contribute to the actual load borne by the slab itself. Therefore, the correct answer is 75 PCF, as it represents the weight of the concrete slab alone.

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Monte Carlo and Historical simulation are widely used tools for risk measurement, generating random inputs based on probability distribution functions. Proper probability distributions are crucial for risk analysis, while statistics aids in risk management by obtaining probabilities and assessing results.

a) Monte Carlo and Historical simulation are the most extensively used tools for measuring risk. The significant difference between these two tools lies in their inputs. Monte Carlo simulation is based on generating random inputs based on a set of probability distribution functions. While Historical simulation, on the other hand, simulates based on the prior actual data inputs.\

b) In risk analysis, the right choice of probability distribution that explains the risk factor's values is of paramount importance as it can give rise to critical decision making and management of financial risks. Probability distributions such as the Normal distribution are used when modeling the return of an asset, or its log-returns. Normal distribution in financial modeling is essential because it best describes the distribution of price movements of liquid and high-frequency assets. Nonetheless, selecting the wrong distribution can lead to wrong decisions, which can be quite catastrophic for the organization.

c) Statistics are used in Risk Management to assist in decision-making by helping to obtain the probabilities of potential risks and assessing the results. Statistics can provide valuable insights and an objective evaluation of risks and help us quantify risks by considering the variability and uncertainty in all situations. With statistics, risks can be easily identified and properly evaluated, and it assists in making better decisions.

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