Joey and Nolan are each solving the equation 13x - 42 = 18 - 7x.
Joey's first step was to rewrite the equation as 20x - 42 = 18 while Nolan's first step was to rewrite the
equation as 13x = 60 - 7x.
Who is correctly applying the addition property of equality in the first step of his work?
A. Only Joey
B. Only Nolan
C. Both Joey and Nolan
D. Neither Joey nor Nolan​

Answer: g(f(10)) = g(√2x+5) = 6x-3

We need to substitute x = √2*10 + 5 into g(x) = 6x - 3

g(f(10)) = 6(√2*10 + 5) - 3 = 6√20 + 30 - 3 = 6√20 + 27

So g(f(10)) = 6√20 + 27.

The Minimum number of lines needed to cover all zeroes is 2.

To determine the minimum number of lines needed to cover all the zeroes after row and column reductions, we must first perform the reductions on the given matrix. The matrix is not provided in a standard format, but I will assume it is a 3x3 matrix based on the 9 given numbers:
Initial matrix:
4 7 6
6 6 9
6 9 6
Row reduction - Subtract the minimum value of each row from all elements in that row.
Row 1: 4 - 4 = 0, 7 - 4 = 3, 6 - 4 = 2
Row 2: 6 - 6 = 0, 6 - 6 = 0, 9 - 6 = 3
Row 3: 6 - 6 = 0, 9 - 6 = 3, 6 - 6 = 0
Row-reduced matrix:
0 3 2
0 0 3
0 3 0
Column reduction - Subtract the minimum value of each column from all elements in that column.
Column 1: 0 - 0 = 0, 0 - 0 = 0, 0 - 0 = 0
Column 2: 3 - 0 = 3, 0 - 0 = 0, 3 - 0 = 3
Column 3: 2 - 2 = 0, 3 - 2 = 1, 0 - 0 = 0
Row- and column-reduced matrix:
0 3 0
0 0 1
0 3 0
Draw the minimum number of lines needed to cover all zeroes.
1. Draw a line through the first row, covering one zero.
2. Draw a line through the second column, covering the two remaining zeroes.
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Answer:

What is this question asking? If you give me a question to answer I can help you.

Step-by-step explanation:

Answer:

368 / 16 = 23

Step-by-step explanation:

Add them all, then divide by how many numbers are in the data set.

Answer:

The above person's answer is correct sorry for the wrong data.

Answer:

y= -1/10x + 77 /10.........

Answer:

$28.85

Step-by-step explanation:

$25.30 leftover money + $3.55 cost of drink = $28.85 Sheily had before buying the drink.

Answer: 28.85

Step-by-step explanation:

This is an addition problem so the answer is pretty straight forward, if she paid 3.55 for a drink that is how much money she already spent to have that drink. Now that she has a drink the question is simply asking how much she had BEFORE she purchased the drink. So just add 3.55 and 25.30 together and you have your answer. Hope this helped.

The functions that are solutions of the differential equation y''?4y'+4y=e^t are: (B) y=e^(2t)+te^t & (E) y=e^(2t)+e^t.The given differential equation is, y''+4y'+4y=e^t ...(1)

We have to find the solutions of the differential equation. Let's solve the differential equation:(1) => r²+4r+4=0Now, solve the quadratic equation using the quadratic formula: r= (-(4)+√((4)²-4(1)(4))) / 2(1)= -2 (repeated)So, the solution of the corresponding homogeneous equation is:(2) yh= (c₁+c₂t)e^(-2t) ---------------(2)Now, we have to find a particular solution of the non-homogeneous differential equation (1).

Let, yp= Ae^t. Now, yp'= Ae^t, yp''= Ae^t. Substitute yp and its derivatives in the equation (1):yp''+4yp'+4yp= e^tAe^t+4Ae^t+4Ae^t= e^t9Ae^t= e^tA= 1/9Therefore, the particular solution is,(3) yp= e^t/9 ------------(3)

Hence, the general solution of the given differential equation is,(4) y= yh+yp= (c₁+c₂t)e^(-2t) + e^t/9Now, substitute the initial conditions in the general solution to get the constants c₁ and c₂:Let, y(0)=0 and y'(0)=0, then,c₁= -1/9 and c₂= 5/9Finally, the solution of the differential equation y''?4y'+4y=e^t is,(5) y= -(1/9)e^(-2t) + (5/9)te^(-2t) + e^t/9 =(e^(2t)+te^(2t))/9+ e^t ...

(Ans)The options that represent the functions that are solutions of the differential equation y''?4y'+4y=e^t are: (B) y=e^(2t)+te^t & (E) y=e^(2t)+e^t.

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Answer:

4.4x−2y+10

Step-by-step explanation:

Answer:

C)

Step-by-step explanation:

The correct answer is C: Tony did not use the property correctly because he did not multiply every term on both sides of the equals sign by 1/4.

To solve the equation 4x = 12x + 20, Tony used the multiplicative property of equality but made an error in the application. The correct approach would be to multiply every term on both sides of the equals sign by the reciprocal of the coefficient of x, which is 1/4 in this case.

However, Tony only multiplied one term on each side by 1/4, resulting in equation x = 3x + 20. This action is incorrect because it does not apply the property to every term containing x. To solve the equation correctly, Tony should have multiplied both sides by 1/4, resulting in x/4 = (3x + 20)/4.

The preparation of the Sales section of the income statement for Blue Spruce Corp. is as follows:

BLUE SPRUCE CORP.

For the year ended October 31, 2022

Sales Revenue                         $908,400

Sales Returns and Allowances  (20,900)

Sales Discounts                           (14,700)

Net sales revenue                  $872,800

The net sales revenue represents the gross revenue minus sales returns and allowances and sales discounts.

In most jurisdictions, the sales discount account is reported on the income statement as a contra revenue account.  This implies that sales discounts are directly deducted from the gross sales and do not appear in the expense section nor the notes to the sales or revenue.

Sales Revenue $908,400

Freight-Out $12,600

Sales Returns and Allowances $20,900

Sales Discounts $14,700

Thus, the preparation of the sales section of the income statement for Blue Spruce Corp. shows a net sales revenue of $872,800.

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The degree sequence of a graph is the list of degrees of its vertices arranged in non-increasing order.

For a bipartite graph $K_{m,n}$ with $m$ vertices in the first partite set and $n$ vertices in the second partite set, every vertex in the first partite set is connected to all vertices in the second partite set and vice versa. Therefore, the degree of each vertex in the first partite set is $n$ and the degree of each vertex in the second partite set is $m$.

So, the degree sequence of the bipartite graph $K_{m,n}$ is $n,n,\ldots,n$ (repeated $m$ times) followed by $m,m,\ldots,m$ (repeated $n$ times). In other words, the degree sequence consists of two blocks, each of length $m+n$, where the first block contains the degree $n$ repeated $m$ times and the second block contains the degree $m$ repeated $n$ times.

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In statistical hypothesis testing, the P-value is a significant factor. It is the probability of obtaining a test statistic at least as extreme as the one calculated from the data, assuming the null hypothesis to be true. If the null hypothesis is false, the P-value is the probability of a type I error. It is the probability of rejecting the null hypothesis when it is true.

To interpret the P-value correctly, a P-value of 0.054 means that if the null hypothesis is correct, there is a 5.4% probability that the sample will produce a test statistic as extreme as, or more extreme than the one that was observed. If the calculated P-value is higher than the significance level, which is usually 0.05 or 0.01, we cannot reject the null hypothesis.

In the given situation, the sample provides insufficient evidence to reject the owner's claim that the mean weight of Gala apples this year is heavier than usual because the calculated P-value is higher than the significance level. Hence, the correct option is that the P-value suggests that there is not sufficient evidence to reject the null hypothesis.

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The digit 9 is in the 7th place from the right, so it has a place value of 9 × 10⁸.Therefore, the value that the teal color represents in the number 3,490347,4903, 4, 7, 490 is 4, since it is in the ones place.

The value that the teal color represents in the number 3,490347,4903, 4, 7, 490 is 4. The teal color represents the digit 4.

When we represent numbers in decimal form, each digit in the number has a place value that depends on its position in the number.

The rightmost digit in a number represents the ones place, the next digit to the left represents the tens place, the next digit to the left represents the hundreds place, and so on. In other words, each place value is 10 times the place value of the digit to its right.

The number 3,490,347,4903, 4, 7, 490 is a large number represented in decimal form. The digit 4 is in the 12th place from the right, so it has a place value of 4 × 10¹¹.

The digit 7 is in the 10th place from the right, so it has a place value of 7 × 10¹⁰. The digit 4 is in the 9th place from the right, so it has a place value of 4 × 10⁹. The digit 3 is in the 6th place from the right, so it has a place value of 3 × 10⁵. The digit 9 is in the 4th place from the right, so it has a place value of 9 × 10³.

The digit 0 is in the 3rd place from the right, so it has a place value of 0 × 10². The digit 3 is in the 2nd place from the right, so it has a place value of 3 × 10¹.

The digit 4 is in the 1st place from the right, so it has a place value of 4 × 10⁰. The digit 0 is in the 5th place from the right, so it has a place value of 0 × 10⁴. The digit 4 is in the 8th place from the right, so it has a place value of 4 × 10⁷. The digit 3 is in the 11th place from the right, so it has a place value of 3 × 10¹⁰.

The digit 9 is in the 7th place from the right, so it has a place value of 9 × 10⁸.Therefore, the value that the teal color represents in the number 3,490347,4903, 4, 7, 490 is 4, since it is in the ones place.

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Answer:

126 is the answer

Step-by-step explanation:

The given identity is not true for all values of \(`x`\).

To verify the given identity when \(`x = 6π/7`\), substitute the value of \(`x`\) in the given identity.

So,

\(`cos2(x) = cos2(6π/7)`\\ `cos(2x) = cos(2 × 6π/7) \\\\ cos(12π/7)`\\Now, \\`cos(12π/7) = cos(7π − 5π/7) \\ − cos(5π/7)`\)

Using the power reducing formula,

\(`cos2(θ) = 2(1 + cos(2θ)\\ = 1 + cos(2θ)`\\So, \\`cos2(6π/7) = 1 + cos(2 × 6π/7)\\ = 1 + cos(12π/7) \\= 1 − cos(5π/7)`.\)

Hence, the given identity is verified when \(`x = 6π/7`\).

(b) Now, we need to plot the graph of \(`f(x) = cos2(x) − 2/(1 + cos(2x))`\) on the indicated domain. The given identity states that \(`f(x)`\) should be 0 for all values of \(`x`\).

We can substitute a few values of \(`x` $ in `f(x)`\) and check if we get \(`0`\) or not. If we get \(`0`\), then we can conclude that the identity holds true for all values of \(`x`\).  

However, it may be possible that we don't get \(`0`\) for some value of \(`x`\) because the function \(`f(x)`\) is undefined for some values of \(`x`\) (because of the denominator

\(`1 + cos(2x)`).\)

Therefore, we need to check the domain of the given function first. The denominator \(`1 + cos(2x)`\) should not be equal to \(`0`\).

Therefore, \(`cos(2x) ≠ −1`or `2x ≠ π`or `x ≠ π/2`\)  

So, the domain of \(`f(x)` is `R − {π/2}`\).

Now, we can check a few values of \(`x`\) to see if \(`f(x)`\) is \(`0`\) or not. If it is not \(`0`\), then we need to explain why it is not \(`0`\).

Let's check \(`x = 0`.\\`f(0) = cos2(0) − 2/(1 + cos(2 × 0))\\ = 1 − 2/(1 + 1) \\= 1/2 ≠ 0`\)

Let's check \(`x = π/4`.\\`f(π/4) = cos2(π/4) − 2/(1 + cos(2 × π/4))\\ = (1/2)2 − 2/(1 + 0) \\= 1/2 − 2 \\= −3/2 ≠ 0`\)

We can also see that the graph of \(`f(x)`\) is not symmetric about the y-axis. Therefore, the identity does not hold true for all values of \(`x`\).

Hence, the given identity is not true for all values of \(`x`\).

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Answer:

Yes

Step-by-step explanation:

I think it looks right I hate when teacher give you work but no telling you how to do it

The angles represented by (2x - 60) and (60 - 2x) cannot be supplementary because their sum add up to zero instead of 180°.

Answer:

(-2x+1)x(6x+1)x(1+2x-8x^3-16x*4)

Step-by-step explanation:

The probability of picking strawberry chocolate as the third chocolate is 6/10 or 3/5. So the overall probability of picking and eating three chocolates in the order nut, nut, strawberry is (1/2) x (5/11) x (3/5) which equals 15/110 or approximately 0.136 or 13.6%.

To find the probability of picking and eating three chocolates in the order of nut, nut, and strawberry, we'll use the concept of probability.

The probability of picking nut chocolate from the box is 6/12 or 1/2. Once a nut chocolate has been chosen and eaten, there are now 5 left in the box out of which 5/11 or approximately 0.45 are nut chocolates. So the probability of picking another nut chocolate is 5/11. Finally, once the second nut chocolate has been eaten, there are 4 left in the box out of which 6/10 or 0.6 are strawberry chocolates.

There are 12 chocolates in total: 6 with nuts and 6 with strawberries.

1. Probability of picking a nut on the first attempt: 6/12 (6 nuts out of 12 chocolates)
2. Probability of picking a nut in the second attempt: 5/11 (5 nuts out of 11 remaining chocolates)
3. Probability of picking a strawberry on the third attempt: 6/10 (6 strawberries out of 10 remaining chocolates)

To find the overall probability, multiply the individual probabilities:

Probability = (6/12) * (5/11) * (6/10) = 1/2 * 5/11 * 3/5 = 3/22

So, the probability of picking and eating three chocolates in the order of nut, nut, and strawberry is 3/22.

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Answer:

$25

Step-by-step explanation:

money=x

3x-6=69

3x=75

x=25

Hope this helps plz hit the crown :D

Answer:

%25 dollars  saved

Step-by-step explanation:

Answer: (a-b+2)x(a+b-2)

Step-by-step explanation:

1) factor out the negative sign from the expression: a^2(b^2-4b+4)

2) Using a^2-2ab+b^2=(a-b)^2, factor the expression: a^2-(b-2)^2

3) Using a^2-b^2=(a-b)(a+b), factor the expression: (a-(b-2))x(a+(b-2))

4) When there is a - in front of an expression in parentheses, change the. Sign of each term in the expression: (a-b+2)x(a+(b-2))

5) When there is a + in front of an expression in parentheses, the expression stays the same: (a-b+2)x(a+b-2)

(a)image averaging is a very effective method of reducing noise in images. Image averaging reduces noise by adding multiple images of the same scene together and then dividing by the number of images added.The conditions that must be fulfilled for the image averaging method are as follows:-

(i) The background of the image must not move between each image capture.- The noise present in the image must be random.- The source of the noise must be consistent.

(ii)The mathematical expression that characterizes the noise in the resultant image when K images are averaged, as K becomes large is given by;sigma_n^2/K

Where;sigma_n^2 is the variance of the noise and K is the number of images that have been averaged.

Therefore, as K increases, the variance of the noise in the resultant image reduces, and thus, the noise reduces.When either method can be used for noise reduction, the temporal image averaging method would be the preferred method to select.

(iii)This is because it uses a sequence of images that are taken at different times, usually at high speeds, to produce a single image that is free of noise. This method is best when dealing with fast-moving objects, and it can be used in situations where the camera cannot be stabilized and is experiencing unwanted vibration or shaking.

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The work done by a force can be calculated by taking the dot product of the force vector with the displacement vector whether the force and displacement vectors are consecutive or anti-congruent.

The formula of the dot product is-

A ⋅ B = |A| |B| cos(θ)

Here A and B are the vectors  |A| and |B| which represent their magnitudes, and θ is the angle between them.

The angle between the force and displacement vectors is either 0 degrees (cos(0) = 1) or 180 degrees (cos(180) = -1) depending on whether they are parallel or antiparallel. The dot product becomes: in these circumstances.

A ⋅ B = |A| |B| (1) = |A| |B| (cos(0)) = |A| |B|

When the vectors are parallel or antiparallel, the angle is 0 or 180 degrees, respectively, and the cosine term is 1 or -1. This occurs since work done is defined as the dot product of the force and displacement vectors multiplied by the cosine of the angle between them.

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The correct statement about the centers of both box plots is: D. The median for town A, 20°, is less than the median for town B, 30°.

In a box plot, the median value is the value indicated by the vertical line that divides the box into two.

The question is incomplete. The attachment below is the diagram of the box plots being referred to followed by the options.

From the given diagram of the box plots showing the daily low temperatures for town A and B, the median of town A and B is shown on the box plots by the line that divides the box.

Therefore, the median of town A is where the line that divides the box is. Median for town A is 20⁰. Same applies for town B. Town B median is 30⁰.

Thus, option D is the most appropriate comparison of the centers. Median of town A is less than median of town B.

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Answer:

4*4=16

Step-by-step explanation:

Answer:

ITS 22 MY G

Step-by-step explanation:

Using (-4,-8) as the starting point, the difference in the x’s is 6 and the difference in the y’s is 9.

Two thirds of those are 4 and 6 respectively.

Add those to -4 and -8, giving (0,-2) and that’s your answer.

There is no value of implicit differentiation where the given situation can be satisfied.

The given equation is: xy * e^y = e

We want to find the value of y^n at the point where x=0.

1. Rewrite the equation: xy * e^y = e

We have an equation involving both x and y. To find the value of y^n at x=0, we need to implicitly differentiate the equation with respect to x.

2. Implicit differentiation:

To implicitly differentiate the equation, we treat y as a function of x and use the chain rule. Differentiating both sides of the equation with respect to x, we get:

d/dx (xy * e^y) = d/dx (e)

Using the product rule on the left side, we have:

y * d/dx (x * e^y) + x * d/dx (e^y) = 0

The derivative of e^y with respect to x can be found using the chain rule:

d/dx (e^y) = d/dy (e^y) * dy/dx = e^y * dy/dx

3. Plug in x=0:

Now, let's plug in x=0 into the equation. We have:

y * d/dx (0 * e^y) + 0 * d/dx (e^y) = 0

Simplifying, we get:

y * (0 * e^y) + 0 * (e^y * dy/dx) = 0

Since any number multiplied by 0 is 0, the equation becomes:

0 + 0 = 0

So, we have 0 = 0, which is a true statement.

4. Conclusion:

From the result 0 = 0, we can conclude that the equation holds when x=0. However, this doesn't provide any specific value for y or y^n at x=0.

Therefore, the original question of finding the value of y^n at x=0 cannot be determined solely from the given equation. The equation does not provide enough information to solve for a specific value of y or y^n at x=0.

In summary, there is no value for y^n at the point where x=0 in the given situation because the equation cannot be satisfied at x=0.

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