Joe is a cashier earing $13.25 per hour.on Tuesday Joe clocked in at 6:00 am then clocked out for a break at 11.00Am, He Then clocked in again at 11.30 am and work until 4.pmHow many hours did Joe work what was your his total pay for the day

Answer:

-4(y-2)=12

-4y+8=12

-4y=4

y = -1

Step-by-step explanation:

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Answer:

  (c)  (-∞, -2) ∪ (-2, 1) ∪ (1, ∞)

Step-by-step explanation:

You want the domain of the given piecewise-defined function.

For x < 2, the function is ...

  \(g(x)=\dfrac{x^2+2x}{x^2+x-2}-\dfrac{x(x+2)}{(x-1)(x+2)}=\dfrac{x}{x-1}\quad x\ne\{-2,1\}\)

Both of these exclusions are in the region x < 2, so both must be excluded from the domain.

The log function is defined for all values x > -2, so there are no exclusions in this region.

The domain is (-∞, -2) ∪ (-2, 1) ∪ (1, ∞).

Step-by-step explanation:

I think is 4.5 because when nine is being divided it's result is 4 remender 1,so maybe the answer options are incorrect

The correct answer is Men continue to earn more than women.

The average yearly wages of men and women are different from one another. Men make more money than women do.

What is the annual salary?

Annual earnings may also be referred to as annual income or yearly income. It displays a person's earnings over a specific time period.

The yearly earning of a person or a corporation is calculated by dividing the monthly earnings by the number of months in a year.

Men continue to earn more than women under the situation mentioned above, hence their wages are higher. The red line is always above the blue line.

As a result, choice A is accurate which is men continue to earn more than women.

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Answer: C. women's earnings have increased in relation to men's earnings

Step-by-step explanation:

The chart shows that

The power series for the function

\(g(x) = 5x/(x^2 + 3x - 4)\)

centered at c = 0, we need to first factor the denominator of the function. We can factor

\(x^2 + 3x - 4 as (x + 4)(x - 1).\)

Therefore, g(x) can be written as:

\(g(x) = 5x/((x + 4)(x - 1))\)

Now, we can use partial fraction decomposition to express g(x) in terms of simpler fractions. We can write:

\(g(x) = 5/(x + 4) - 5/(x - 1)\)

Next, we can express each of the simpler fractions as a power series. For the first term, we have:

\(5/(x + 4) = 5/(4(1 + (x/4))) = (5/4)(1 - (x/4) + (x/4)^2 - (x/4)^3 + ...)\)

For the second term, we have:

\(-5/(x - 1) = -5/(-1(1 - (x/-1))) = (5)(1 + (x/-1) + (x/-1)^2 + (x/-1)^3 + ...)\)

Therefore, we can write:

\(g(x) = (5/4)(1 - (x/4) + (x/4)^2 - (x/4)^3 + ...) + (5)(1 + (x/-1) + (x/-1)^2 + (x/-1)^3 + ...)\)

Simplifying this expression and combining like terms, we can write:

\(g(x) = (5/4) + (15/16)x - (25/64)x^2 + (175/256)x^3 + ...\)

This is the power series for g(x) centered at c = 0.

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It is required to draw the graph of -3f(x), where f(x)=cos x.

It is also required to give its period.

To do this, start with the graph of the parent function f(x)=cos x, then perform transformations on the graph of the parent function to draw the required graph.

The graph of the parent function f(x)=cos x is shown below:

Reflect the graph over the x-axis to draw the graph of -f(x) (in blue):

Stretch the graph of -f(x) vertically by a factor of 3 to draw the graph of -3f(x) (in green):

The required graph of -3f(x) is:

Recall that the period of a sinusoid is the length of a complete cycle.

From the graph, the period is 2π.

The probability that a customer will wait in a line between 3 to 6 minutes is about 16.58%.

To solve this problem, we need to use the Poisson process and the exponential distribution.

Let X be the number of arrivals in a 3-minute interval. Since customers arrive at a rate of 25 per hour, the expected number of arrivals in a 3-minute interval is:

λ = (25/60) x 3 = 1.25

Thus, X is Poisson distributed with parameter λ = 1.25.

Let Y be the service time for a customer. Since Linda serves a customer, on average, in 1.5 minutes, Y is exponentially distributed with parameter μ = 1/1.5 = 0.6667.

Let Z be the waiting time for a customer in the line. Z is the sum of X independent service times, so Z is gamma distributed with parameters X and μ.

We want to find the probability that Z is between 3 and 6 minutes:

P(3 ≤ Z ≤ 6) = ∫∫ f(x,y) dx dy

where f(x,y) is the joint probability density function of X and Y:

f(x,y) = (λ^x / x!) e^(-λ) μ e^(-μy) = (1.25^x / x!) e^(-1.9167) e^(-0.6667y)

Now we can evaluate the double integral:

P(3 ≤ Z ≤ 6) = ∫∫ f(x,y) dx dy

= ∫∫ (1.25^x / x!) e^(-1.9167) e^(-0.6667y) dx dy

= ∫ e^(-0.6667y) e^(-1.9167) ∑ (1.25^x / x!) dx dy (x=0 to ∞)

= e^(-1.9167) ∫ e^(-0.6667y) e^(1.25) dy ∑ (1.25^x / x!) (x=0 to ∞)

The sum in the integral is the Taylor series expansion of e^1.25, which is equal to e^1.25 = 3.4903.

Using a table of integrals or a computer software, we can evaluate the integral:

∫ e^(-0.6667y) e^(1.25) dy = (1/0.6667) (e^(1.25) - e^(-0.6667(6))) = 3.7225

Therefore, the probability that a customer will wait in a line between 3 to 6 minutes is:

P(3 ≤ Z ≤ 6) = e^(-1.9167) ∫ e^(-0.6667y) e^(1.25) dy ∑ (1.25^x / x!) (x=0 to ∞)

= e^(-1.9167) (3.7225) (3.4903) = 0.1658 or about 16.58% (rounded to four decimal places).

Therefore, the probability that a customer will wait in a line between 3 to 6 minutes is about 16.58%.

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A sample size of 329 would be required to be 99% confident that the estimated proportion of women-owned businesses not providing employee benefits is within 6 percentage points of the true population proportion.

To calculate the required sample size, we can use the formula:

n = (\(z^2\) * p * q) /\(e^2\)

where n is the sample size, z is the z-score corresponding to the desired level of confidence (in this case, 2.576 for 99% confidence), p is the estimated population proportion (0.165, based on the NWBC's finding), q is 1-p, and e is the maximum error we want to tolerate (in this case, 0.06 or 6 percentage points).

Substituting the values, we get:

n = (2.576^2 * 0.165 * 0.835) / \(0.06^2\)

Solving for n, we get:

n ≈ 329

Therefore, a sample size of 329 would be required to be 99% confident that the estimated proportion of women-owned businesses not providing employee benefits is within 6 percentage points of the true population proportion. Note that this assumes a simple random sample and that the population size is much larger than the sample size, so the finite population correction is not needed.

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a) The probability that at most one is a six is 5/6.

b) The probability that at most one is a six is 2/3.

In the question two dice are rolled in a random experiment and we have to find what is the probability that at most one is a six and if the two faces are different, what is the probability that at most one is a six.

a) The probability that at most one is a six is 5/6. There are only 6 possible outcomes when rolling two dice, and 5 of those outcomes involve at most one six: (1,2), (1,3), (1,4), (1,5), (2,5).

b) The probability that at most one is a six is 2/3. If the two faces are different, there are only 3 possible outcomes: (1,2), (2,3), (3,4). 2 of those outcomes involve at most one six: (1,2), (2,3). Thus, the probability is 2/3.

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Answer:

25 butterflies, 15 fruit flies, 10 bees

Step-by-step explanation:

The sample that best represents the population is option B, which includes 25 butterflies, 15 fruit flies, and 10 bees. Option B is correct.

In a study population with 2200 butterflies, 1400 fruit flies, and 800 bees, the sample size should reflect the relative proportions of each species in the population. Option B has a similar ratio with 25 butterflies (11.4% of 2200), 15 fruit flies (10.7% of 1400), and 10 bees (12.5% of 800). This sample provides a representative subset that preserves the overall distribution of species in the population.

The sample size is proportional to the population size of each insect species, and option B has the closest proportionality to the actual population. It maintains the proportional ratio of the different species found in the population.

Option B holds true.

The complete question:

A study population includes 2200 butterflies, 1400 fruit flies, and 800 bees. which sample best represents the population?

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Answer:

x  = 0,87 miles

Step-by-step explanation:

Let´s look at the stuation.

Jane is two miles away (in point B) from point A at the beach  and the horizontal distance between Jane and the village( Point C ) is 6 miles, she will leave the boat somewhere (Point D,  at x distance from A) between A and C.

Then distances  for the travel of Jane are:

L₁  distance to row      L₁²  =  2² + x²     L₁  = √ 4 + x²

And the distance to walk    L₂  =  6 - x

The relation between distances, time, and speed is

d = v*t   then  t =  d/v

According to that the time for rowing will be  

t₁  = ( √4  +  x² ) / 2      and for walking   t₂  = (  6  -  x  ) /5

T = t₁  +   t₂

T(x)  = ( √4  +  x² ) / 2   + (  6  -  x  ) /5

Tacking derivatives on both sides of the equation

T´(x)  =  1/2  [ ( 2*x / 2√ ( 4 + x² ) ]  -1/5

T´(x)  = ( 1/2 )*  x / √ ( 4 + x² )   - 1/5

T´(x) = 0

( 1/2 )*  x / √ ( 4 + x² )   - 1/5   = 0

5*x  - 2* √ ( 4 + x² )  =  0

5*x  =  2 *√ ( 4 + x² )

Squaring

25*x²  =  4* ( 4 + x² )

25*x²  =  16  +  4*x²

21*x²  =  16

x  =  √ 16/21

x  = 0,87 miles

(a) The fundamental matrix for the given system of equations is Φ(t) = e^(At).

Let's denote the given coefficient matrix as A:

A = [ -1 -4

      1 -1 ]

The fundamental matrix Φ(t) for the system is given by the matrix exponential of the coefficient matrix A multiplied by t:

Φ(t) = e^(At)

(b) The fundamental matrix φ(t) satisfying φ(0) = I is the identity matrix.

Finding the fundamental matrix φ(t) satisfying φ(0) = I:

To find the fundamental matrix φ(t) satisfying φ(0) = I, we substitute t = 0 into Φ(t):

φ(0) = Φ(0) = e^(A * 0) = e^(0) = I

So, the fundamental matrix φ(t) satisfying φ(0) = I is the identity matrix.

In summary, for the given system:

(a) The fundamental matrix Φ(t) is e^(At).

(b) The fundamental matrix φ(t) satisfying φ(0) = I is the identity matrix, denoted as φ(t) = I.

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The image is not clear.

Answer:

\(\boxed{\textsf {One fourth cup of yogurt has 26.66 calories. }}\)

Step-by-step explanation:

Given that ¾ of a cup of yogurt is 80 calories and we need to find the calories in ¼ of a cup . So here we can use unitary method to find the calories.

=> ¾ cup of yogurt has 80 calories

=> 1 cup of yogurt has 80 ÷ ¾ calories .

=> ¼ cup of yogurt has 80 × 4/3 × 1/4 calories = 26.66 calories .

Answer:

Vertical Shift

Step-by-step explanation:

The blue line is the original graph. The green one is the new graph. So, the blue graph moves up to where the green graph is. In other words, the line moves up, which is a vertical shift.

Answer:

10

Step-by-step explanation:

How many times less is 50 than 500?

500/50 = 10

Answer: n= -1/2 -3m

Step-by-step explanation:

Answer:

(2,-2)

Step-by-step explanation:

The solution to a system of equations like these, is where the two lines intersect. In this case, I believe, it would be at point (2,-2). Although, it is a little hard to pinpoint without the labeled number lines.

Hope this helps! Best of luck!

The probability of selecting all three purple balls is 0.1429 or approximately 14.29%.

To find the probability that all three balls are purple, we need to use the formula for the probability of the intersection of three events:

P(A and B and C) = P(A) x P(B|A) x P(C|A and B)

where A, B, and C are the events of drawing a purple ball from the bag on the first, second, and third draws, respectively.

The probability of drawing a purple ball on the first draw is:

P(A) = number of purple balls / total number of balls = 9 / 15

After drawing a purple ball on the first draw, there are now 8 purple balls left in the bag out of a total of 14 balls, so the probability of drawing a purple ball on the second draw, given that a purple ball was drawn on the first draw, is:

P(B|A) = number of purple balls left / total number of balls left = 8 / 14

After drawing two purple balls, there are now 7 purple balls left in the bag out of a total of 13 balls, so the probability of drawing a purple ball on the third draw, given that two purple balls were drawn on the first two draws, is:

P(C|A and B) = number of purple balls left / total number of balls left = 7 / 13

Therefore, the probability of drawing three purple balls in a row is:

P(A and B and C) = P(A) x P(B|A) x P(C|A and B) = (9 / 15) x (8 / 14) x (7 / 13) = 0.1429 or approximately 14.29%

So, the probability of selecting all three purple balls is 0.1429 or approximately 14.29%.

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(b) No, The branch manager's argument that dispatching buses every 0.5 minutes will reduce the average traveling time (a round trip) to 3.5 minutes is not correct.

To calculate the average time, we need to consider the time it takes for the bus to travel to the airport and back, as well as the time spent waiting for the bus.

If buses are dispatched every 3 minutes, and the average traveling time (a round trip) is 21 minutes, it means that passengers spend 18 minutes waiting for the bus (21 minutes - 3 minutes of traveling time).

If buses are dispatched every 0.5 minutes, the waiting time will be significantly reduced. However, the traveling time remains the same at 21 minutes for a round trip.

Therefore, the average traveling time will not be reduced to 3.5 minutes but will remain at 21 minutes (assuming the traveling time remains constant).

(c) The average traveling time, following the branch manager's suggestion of dispatching buses every 0.5 minutes, would still be 21 minutes.

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Complete question:

The Avis Company is a car rental company and is located three miles from the Los Angeles airport (LAX). Avis is dispatching a bus from its offices to the airport every 3 minutes. The average traveling time (a round trip) is 21 minutes.

(a) The branch manager wants to improve the service and suggests dispatching buses every 0.5 minute. She argues that this will reduce the average traveling time (a round trip) to 3.5 minutes. Is she correct? (Enter "Yes" or "No" in the following blank).

c. Following the branch manager's suggestion (dispatch busses every 0.5 min), what will the average traveling time be? average travelling time ____(mins) (enter the numbers only)

Answer:

i cant see the question :(

Step-by-step explanation:

Whenever we add or subtract fractions, we have to first ensure that the denominators of the fractions are the same. In this case, they are, so we don't have to go out of our way to find a common denominator.

\(\dfrac{3}{5}+(-\dfrac{1}{5})\)

Now, let's open up the parentheses:

\(\dfrac{3}{5}-\dfrac{1}{5}\)

Subtract only the numerators:

\(\dfrac{2}{5}\)

\(\dfrac{2}{5}\)

the mean time between failures for the modified components is tested using the p-value method at a significance level of 0.05. The null hypothesis (H0) assumes that the mean time is 520 hours or less, while the alternative hypothesis (H1) suggests that the mean time is greater than 520 hours.

we will use the p-value method of hypothesis testing. The null hypothesis (H0) assumes that the mean time between failures for the modified components is 520 hours or less. The alternative hypothesis (H1) suggests that the mean time between failures is greater than 520 hours.

We start by calculating the sample mean and sample standard deviation of the given data. Using the sample mean and the assumed population mean of 520 hours, we can calculate the test statistic t, which follows a t-distribution with n-1 degrees of freedom (where n is the sample size).

Next, we determine the p-value associated with the obtained test statistic. The p-value represents the probability of observing a test statistic as extreme or more extreme than the calculated value, assuming the null hypothesis is true.

Comparing the p-value to the significance level of 0.05, if the p-value is less than 0.05, we reject the null hypothesis in favor of the alternative hypothesis. This would indicate that there is evidence to support the claim that the mean time between failures for the modified components is greater than 520 hours.

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The polynomial function \(\(f(x) = 2(x^2+3)(x+1)^2\)\) has zeros at -3 with multiplicity 1, and -1 with multiplicity 2. The graph of the function crosses the x-axis at -3 and -1.

To find the zeros and their multiplicities, we set \(\(f(x)\)\) equal to zero and solve for \(\(x\).\)

Setting \(\(f(x) = 0\),\) we have:

\(\[2(x^2+3)(x+1)^2 = 0\]\)

Since the product of two factors is zero, at least one of the factors must be zero. Thus, we solve for \(\(x\)\) in each factor separately:

1. \(\(x^2 + 3 = 0\):\)

  This equation does not have real solutions since the square of a real number is always non-negative. Therefore, this factor does not contribute any real zeros.

2. \(\(x + 1 = 0\):\)

  Solving for \(\(x\), we find \(x = -1\).\) This gives us a zero at -1 with multiplicity 1.

Since the factor \(\((x+1)^2\)\) is squared, the zero -1 has a multiplicity of 2.

Therefore, the zeros for the polynomial function are -3 with multiplicity 1 and -1 with multiplicity 2. The graph of the function crosses the x-axis at both zeros.

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Answer:

Options A

Step-by-step explanation:

Properties of the graph given for the function 'g',

y-intercept of the function 'g' → y = -4

Minimum value of g(x) → y = -4 (Value of the function at the lowest point)

Roots of g(x) → x = -2, 2

At x = 4,

g(4) = 11

Another function is,

f(x) = -x² - 4x - 4

     = -(x² + 4x + 4)

     = -(x + 2)²

Properties of the function f(x) = -(x + 2)²,

y-intercept (at x = 0) of the function 'f',

y = -(x + 2)²

y = -4

Since, leading coefficient of the function is (-1) therefore, graph will open downwards and the maximum point will be its vertex.

Maximum value of the function 'f' = Value of the function at the vertex

Coordinates of vertex → (-2, 0)

Therefore, maximum value of 'f' = 0

Roots (at y = 0) of the function 'f' → x = -2

At x = 4,

f(4) = -(4 + 2)²

     = -36

Therefore, Options A will be the correct option.

Answer:

[-2,8]

Step-by-step explanation:

Answer:

Fifth option

Step-by-step explanation:

The solutions to the equation are x = 5 and x = 3

The equation is given as

|x - 4|= 1

The above equation is an absolute value equation

When the absolute value sign is removed from the equation, we have

x - 4 = 1 or x - 4 = -1

Add 4 to all sides of the equation

So, we have the following equations

x = 1 + 4 or x = 4 - 1

Evaluate

x = 5 or x = 3

This means that the value of the equation is x = 5 or x = 3

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Therefore , the percentage of case 1 is 68% and percentage of case 2 is 47.4%

One percent (symbolized as 1%), being the hundredth component, is represented as 100 percent, while 200 percent signifies twice the amount specified. As an illustration, 1% of 1,000 chickens is equal to 1/100 of 1,000, or 10 birds, and 20% of the quantity is equal to 20% of 1,000, or 200.

Here,

Given: Total number of freshman =500

mean =75 and standard deviation =7

a) the percentage of scores that fell between 68 and 82

340 is the number of freshman whose  scores that fell between 68 and 82

thus,

percentage = 340 /500 * 100

=> percentage = 68%

b)the percentage of scores that fell between 61 and 75

237 is the number of freshman whose  scores that fell between 61 and 75

thus,

percentage = 237/500 * 100

=> percentage = 47.4%

Therefore , the percentage of case 1 is 68% and percentage of case 2 is 47.4%

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