JL ≈ NM, K is the Midpoint of JN and LM



Prove JKL ≈ NKM

These statistical measures help the researcher summarize, describe, and understand the data collected from the study participants.

As the researcher is describing the characteristics of the subjects, the appropriate statistical analysis would be descriptive statistics.

Descriptive statistics is a method that summarizes and describes the data collected in a study. It includes measures such as mean, median, mode, standard deviation, range, and frequency distribution.

These measures can provide a clear picture of the demographic data of the three groups of subjects and help in drawing meaningful conclusions.

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Answer:

I am very sorry I dont know

Step-by-step explanation:

ahem ahem

2+2=69

it's 4 thanks for the points

By applying Pythagoras' theorem, the length of x is equal to 10 units.

In Mathematics and Geometry, Pythagorean's theorem is modeled or represented by the following mathematical equation (formula):

x² + y² = z²

Where:

x, y, and z represents the length of sides or side lengths of any right-angled triangle.

Based on the information provided about the side lengths of this right-angled triangle, we have the following equation:

x² = y² + z²

x² = 8² + 6²

x² = 64 + 36

x = √100

x = 10 units.

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To solve this problem, we can use the method of Lagrange multipliers. This method allows us to find the maximum or minimum of a function subject to constraints.

In this case, the function we want to maximize is Z = 2x + 3y and the constraints are x = 24, y = 25, and 3x + 2y = 52.We begin by setting up the Lagrangian function, which is given by:L(x, y, λ) = Z - λ(3x + 2y - 52)where λ is the Lagrange multiplier. We then take the partial derivatives of the Lagrangian with respect to x, y, and λ and set them equal to zero.∂L/∂x = 2 - 3λ = 0∂L/∂y = 3 - 2λ = 0∂L/∂λ = 3x + 2y - 52 = 0Solving for λ, we get λ = 2/3 and λ = 3/2. However, only one of these values satisfies all three equations. Substituting λ = 2/3 into the first two equations gives x = 20 and y = 22. Substituting these values into the third equation confirms that they satisfy all three equations. Therefore, the maximum value of Z subject to the given constraints is Z = 2x + 3y = 2(20) + 3(22) = 84.

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The maximum value of Z = 2x + 3y, subject to the conditions x ≤ 24, y ≤ 25, and 3x + 2y = 52, is 96.

To maximize the function Z = 2x + 3y, subject to the conditions x ≤ 24, y ≤ 25, and 3x + 2y = 52, we will use the method of linear programming.

Let us first graph the equation 3x + 2y = 52.

The intercepts of the equation 3x + 2y = 52 are (0, 26) and (17.33, 0).

Since the feasible region is restricted by x ≤ 24 and y ≤ 25, we get the following graph.

We observe that the feasible region is bounded and consists of four vertices:

A(0, 26), B(8, 20), C(16, 13), and D(24, 0).

Next, we construct a table of values of Z = 2x + 3y for the vertices A, B, C, and D.

We observe that the maximum value of Z is 96, which occurs at the vertex B(8, 20).

Therefore, the maximum value of Z = 2x + 3y, subject to the conditions x ≤ 24, y ≤ 25, and 3x + 2y = 52, is 96.

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Answer:

24

Step-by-step explanation:

5:5+5x1.4 as 10:10+10x1.4 or 24

Answer:

14

Step-by-step explanation:

Since they are similar triangles, we can use proportions

5              10

------ = -------------

5+7       10+?

5              10

------ = -------------

12          10+?

Using cross products

5( 10+?) = 12*10

Divide each side by 5

10+? = 12*10/5

10+? = 24

Subtract 10 from each side

10+?-10 = 24-10

? = 14

Sure, I can help you with that! For the first graph, it's difficult to provide an answer without seeing the actual graph, but generally speaking, we need to determine the variable number, the type of data, and the purpose of the display. The variable number refers to the number of variables being represented in the graph, and the type of data refers to whether the data is qualitative or quantitative. The purpose of the display refers to what we're trying to communicate or show with the graph.

For example, if we were looking at a scatter plot, we could say that there are two variables being represented (x and y), the data is quantitative, and the purpose of the display is to show the relationship between the two variables.

Similarly, if we were looking at a bar graph, we could say that there is one variable being represented (the categories on the x-axis), the data is qualitative, and the purpose of the display is to compare the values of different categories.

In general, the choice of an appropriate graphical display will depend on the three factors mentioned earlier, so it's important to consider these factors when creating or interpreting a graph.

9514 1404 393

Answer:

  $92,400

Step-by-step explanation:

The amount in the account after t years is ...

  A = P(1+rt)

where P is the principal invested, r is the annual interest rate, and t is the number of years.

Here, the number of years is (240 months)/(12 months/year) = 20 years, so the formula tells you the amount is ...

  A = $28,000(1+0.115*20) = $28000(3.3) = $92400

The total amount in the account after 240 months is $92,400.

hope this pic helps. enjoy

Answer:

74 papers

Step-by-step explanation:

100-26

Answer:

126 papers he has

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

After 10 months, both salespersons will sell 160 cars.

Step-by-step explanation:

We are given two different salesperson's statistics of sales. We can use this information to set up a system of equations and solve for our variable.

Let us name the first salesperson Person 1 and the other salesperson Person 2.

Now, for Person 2:

Now, because we have these equations, we can set up a table that will determine the number of months that will elapse before the salespersons will sell the same amount of cars.

For Person 1, the equation will be the increase of the y-value by 13 cars after an initial sale of 30 vehicles. Therefore, we can create a table of values.

\(\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 30 \\ \cline{1-2} 1 & 43 \\ \cline{1-2} 2 & 56 \\ \cline{1-2} 3 & 69 \\ \cline{1-2} 4 & 82 \\ \cline{1-2} 5 & 95 \\ \cline{1-2} 6 & 108 \\ \cline{1-2} 7 & 121 \\ \cline{1-2} 8 & 134 \\ \cline{1-2} 9 & 147 \\ \cline{1-2} 10 & 160 \\ \cline{1-2} \end{array}\)

For Person 2, we can use the same formatting to create a table. However, the rule changes - we must start at 50 cars being sold and increase it by only 11 cars a month.

\(\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 50 \\ \cline{1-2} 1 & 61 \\ \cline{1-2} 2 & 72 \\ \cline{1-2} 3 & 83 \\ \cline{1-2} 4 & 94 \\ \cline{1-2} 5 & 105 \\ \cline{1-2} 6 & 116 \\ \cline{1-2} 7 & 127 \\ \cline{1-2} 8 & 138 \\ \cline{1-2} 9 & 149 \\ \cline{1-2} 10 & 160 \\ \cline{1-2} \end{array}\)

Now, we need to see where the y-values are the same in both tables. We can see that we have a value of (10, 160) in both tables, so after 10 months, the salespersons will sell the same amount of cars.

There is an alternative method of solving the problem that is much quicker and will require much less work.

We are given two equations that are both equal to y. Therefore, we can set them equal to each other (dropping the y) and solving for x.

Our value of x will be the amount of months in which the sales are equal.

\(\displaystyle{13x+30=11x+50}\\\\2x + 30 = 50\\\\2x = 20\\\\\boxed{x = 10}\)

Therefore, after 10 months of sales, the salespersons will have sold the same amount of cars. We can plug this information into one of the equations to see how many cars will be sold at that point.

\(y = 13(10) + 30\\\\y = 130 + 30 \\\\y = 160\)

In 10 months, 160 cars will be sold. If we set the equations equal to each other and substitute x, we should get a true statement.

\(13(10)+30=11(10)+50\\\\130 + 30 = 110 + 50\\\\160 = 160\)

Because we get a true statement, each salesperson will sell 160 cars after 10 months of initial sales.

Answer:

120

Step-by-step explanation:

6 girls can send 60 text messages in 30 minutes, so 60 minutes woudl equal 120

The two equations for this system are C = 0.60f + 15 and C = 0.80f + 13.

The number of fish for which the cost is the same is 10 fishes.

The cost of this fish is equal to $21.

In order to write a system of linear equations to model and describe this situation, we would assign variables to the number of fish and the cost of fish respectively, and then translate the word problem into algebraic equation as follows:

Note: 1 dollar is equal to 100 cents.

Since the starter aquarium kit costs $15 plus 60 cents per fish at wet pets, we have:

C = 0.60f + 15     ........equation 1.

Since the starter aquarium kit costs $13 plus 80 cents per fish at gills and frills, we have:

C = 0.80f + 13          ........equation 2.

Next, we would solve the system of equations as follows:

0.80f + 13 = 0.60f + 15

0.80f -0.60f = 15 - 13

0.20f = 2

Number of fish, f = 2/0.20

Number of fish, f = 10 fishes.

From equation 1, we have:

Cost of fish, C = 0.60f + 15

Cost of fish, C = 0.60(10) + 15

Cost of fish, C = 6 + 15

Cost of fish, C = 21 dollars.

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Answer:

37.5 miles per hour

Step-by-step explanation:

To find the miles per hour, you divide the miles by hours. If you divide 225/6, you get 37.5. You can double check this by dividing another set, like 450/12 and see that you still get 37.5. Hope this helps! :)

Answer:

31.25.

Step-by-step explanation:

Answer:

y = -12/11

Step-by-step explanation:

-8y - 13 = 14y + 11

-8y - 14y = 11 + 13

-22y = 24

y = 24/-22

y = -12/11

Check:

-8*-12/11  -  13 = 14*-12/11 + 11

96/11  -  13 = -168/11  +  11

96/11 - 143/11 = -168/11 + 121/11 = -47/11

The correct option is D. 48.

The value of the composite function g(f(-1)) is 48.

The process of integrating two or so more functions to create a single function is known as function composition. A function represents a piece of labor.

Now, according to the question, the given functions are-

f(x) = 5x² + 2 and g(x) = x² – 1

First, we must determine f(-1). Consider the f(x) expression and substitute -1 for x.

f(x) = 5x² + 2

f(-1) = 5(-1)² + 2

f(-1) = 5(1) + 2

f(-1) = 5 + 2

f(-1) = 7

We now know that f(-1) equals 7, hence g(f(-1)) is like g. (7). We'll use the g(x) equation now, substituting 7 for x.

g(x) = x² - 1

g(7) = 7² - 1

g(7) = 49 - 1

g(7) = 48

Therefore, the result for the composite function g(f(-1)) is 48.

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The correct question is-

Consider these functions: f(x) = 5x² + 2 g(x) = x² – 1 What is the value of g(f(-1))? A. 2 B. 8 C. 22 D. 48

Answer:  The correct symbol is '<'.

Step-by-step explanation:

Given: In triangle GHJ

\(m\angle H=85^{\circ}\) and \(m\angle G=60^{\circ}\)

Here angle H is opposite to side JG and angle G is opposite to side HJ

We know that,

The side opposite to the greater angle of a triangle is greater.

Since \(m\angle H> m\angle G\)

Then, JG > HJ

Hence, HJ     <       JG

Hope it helps you!.........

For the matrix the true statement is given by option d. Both A and B are false.

Let's analyze each statement of the matrix as follow,

A) If A is a 3 times 5 matrix and T is a transformation defined by T(x) = Ax, then the domain of T is R⁵.

This statement is false.

The domain of the transformation T is not R⁵.

The domain of T is determined by the dimensionality of the vectors x that can be input into the transformation.

Here, the matrix A is a 3 times 5 matrix, which means the transformation T(x) = Ax can only accept vectors x that have 5 elements.

Therefore, the domain of T is R⁵, but rather a subspace of R⁵.

B) If A is a 3 times 2 matrix, then the transformation x right arrow Ax cannot be onto.

This statement is also false.

The transformation x → Ax can still be onto (surjective) even if A is a 3 times 2 matrix.

The surjectivity of a transformation depends on the rank of the matrix A and the dimensionality of the vector space it maps to.

It is possible for a 3 times 2 matrix to have a rank of 2,

and if the codomain is a vector space of dimension 3 or higher, then the transformation can be onto.

Therefore, as per the matrix both statements are false, the correct answer is d. Both A and B are false.

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The above question is incomplete, the complete question is:

Which of the following best characterizes the following statements:

A) If A is a 3 times 5 matrix and T is a transformation defined by T(x) = Ax, then the domain of T is R^5

B) If A is a 3 times 2 matrix, then the transformation x right arrow Ax cannot be onto

a. Only A is true

b. Only B is true

c. Both A and B are true

d. Both A and B are false

The equation of each line in slope‐intercept form are y = -4x+2 and y = -x+4

The graph of the linear equation y = mx + c is a line with m as slope, m and c as the y-intercept. This form of the linear equation is called the slope-intercept form, and the values of m and c are real numbers.

GIven are two graphs of lines, we need to find the slope‐intercept form of the lines,

We know that, the slope‐intercept form of the line is given by:

y = mx+c, where m is slope and c is the y-intercept,

m = y₂-y₁ / x₂-x₁

1) The line is passing through two points (0.5, 0) and (0, 2) :-

y-0 = 2-0 / 0-0.5 (x-0.5)

y = -4(x-0.5)

y = -4x+2

2) The line is passing through two points (4, 0) and (0, 4) :-

y-0 = 4-0 / 0-4 (x-4)

y = -1(x-4)

y = -x+4

Hence, the equation of each line in slope‐intercept form are y = -4x+2 and y = -x+4

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Answer:

ans = $105 per hour

Step-by-step explanation:

first: you subtract the charge for parts from the total and this gives you $446.25.

second: because the technician worked for 4.25 hours = $446.25,if the technician worked for an hour what would be the cost?

4.25hr = $446.25

1 hr      = x . then cross multiply.

4.25x = 446.25 then divide by 4.25 both sides to find th value of x, which is the cost of labour per hour

The area of of the tile 6 in and 2 in is 12 inches.

The size of a patch on a surface is determined by its area. Surface area refers to the area of an open surface or the boundary of a three-dimensional object, whereas the area of a plane region or plane area refers to the area of a form or planar lamina.

Given that

One side =  6 in

Another side = 2 in

The area =  (6 in * 2 in )

= 12 inches

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complete question;

What is the area of of this tile 6 in and 2 in?

The solution for a 10 m rod with t(0) = 240 and t(10) = 150 is obtained.

Given the heat balance equation for a rod as 2 2 − 0.15 = 0, we can obtain a solution for a 10m rod with t(0) = 240 and t(10) = 150 as follows:

Let us assume the rod of length L=10m is divided into N number of parts. Then the distance between two successive points is `Δx=L/N=10/N`.

Temperature at different points along the rod can be represented as t1, t2, t3,...tn. Here t0=240, tN=150.

Applying central difference approximation on the heat balance equation we get:

t(i+1) - 2t(i) + t(i-1) - Δx^2 (-0.15) = 0This equation is valid for i = 1 to N-1.

Now let us substitute the value of N to obtain the values of t1, t2, t3, ... tN.

Here, L = 10m, N = number of parts Δx = 10/N = 1/t(i+1) - 2t(i) + t(i-1) - (1)^2 (-0.15) = 0

By solving these equations we obtain:

t1=239.4t2=238.8t3=238.2t4=237.6t5=237.0t6=236.4t7=235.8t8=235.2t9=234.6t10=150

Hence the solution for a 10 m rod with t(0) = 240 and t(10) = 150 is obtained.

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Answer:

85

Step-by-step explanation:

2(-4)^2=32

-10(-4)=40

32+40+13=85

The common factor that is missing from both sets of parentheses is:

\(6x^2+11,\\\)

A polynomial that divides evenly and completely into another polynomial is said to be a factor. Finding all of a polynomial's factors, which are multiplied to create the original polynomial, is known as factoring. A component that appears in every term of the polynomial is known as a common factor.

We are given a polynomial of degree 3 as:

\(24x^3-54x^2+44x-99,\)

Now we have to factor the given polynomial using grouping.

We proceed in the following steps:

\(24x^3-54x^2+44x-99\\\\24x^3+44x-54x^2-99\\\\4x(6x^2+11)-9(6x^2+11)\)

( Since we take out the common terms in each of the following groups and obtain a common factor in both the groupings)

Hence, the common factor that is missing is:

\(6x^2+11\),

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Answer:c

Step-by-step explanation:just did the test

Answer: -3 degress celsius

Step-by-step explanation:

Answer:

-3 degrees celcius

Step-by-step explanation:

since its a neg number it needs to be closest to zero to be greater

but a general rule is that the farthest it is to the right on a number line, the greater it is and vise versa

Jay's net weight change in 6 month is 30 pounds.

a) Given that, in February, the record low temperature for ST.Paul Minnesota was -3° F

In January temperature = -3×6

= -18 F

c) Jay went on a diet and last 5 pounds each month

Jay's net weight change in 6 months = 5×6

= 30 pounds

Therefore, Jay's net weight change in 6 month is 30 pounds.

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