Jeremy performs the same operations on 4 values for x. He records each resulting y-value in a table, which equation shows the operation Jeremy performs on x to get to y?

x: 2,4,6,8
y:5,13,21,29

Answers: y= 2x+1 , y= 4x-3 , y= x+3 , y= 3x-1

Answer:

68

Step-by-step explanation:

F = 1.8(20)+32 = 68

Answer:

4.5 ft³

Step-by-step explanation:

Volume = 1/2(LxWxH)

1/2( 1.5 x 2) * 3  = 1.5 x 3 = 4.5 ft ³

If my answer is incorrect, pls correct me!

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-Chetan K

Answer:

Step-by-step explanation:

x+2) x^3+0x^2+0x-4(x^2-2x+4

       x^3+2x^2

      -      -

_______________

             -2x^2+0x

             -2x^2-4x

             +       +

            ____________

                         4x-4

                         4x+8

                        -     -

                       ______

                              -12

                           _____

\(\frac{x^3-4}{x+2} =x^2-2x+4+\frac{-12}{x+2}\)

a. f is increasing on (-∞,0) and (1/2,∞), and decreasing on (0,1/2) and (1,∞).

b. f is concave down on (-∞,1/2) and (3/2,∞), and concave up on (1/2,3/2).

c. The local minimum value is 0 and the local maximum value is -5/16.

d. The global minimum value is -8 at x = 2, and the global maximum value is 8 at x = -1.

e. The smaller x-value inflection point is (1/2, -5/16) and the larger x-value inflection point is (3/2, 25/16).

The point of inflection, also known as the inflection point, is when the function's concavity changes. Changing the function from concave down to concave up, or vice versa, signifies that.

(a) To find the intervals on which f is increasing or decreasing, we need to find the critical points of f and determine the sign of the derivative on the intervals between them.

The derivative of f(x) is:

f'(x) = 4x³ - 9x² + 6x = 3x(2x-1)(2x-2)

The critical points are the values of x where f'(x) = 0 or f'(x) is undefined.

Setting f'(x) = 0, we get:

3x(2x-1)(2x-2) = 0

This gives us the critical points x = 0, x = 1/2, and x = 1.

Since f'(x) is defined for all x, there are no other critical points.

Now we can test the sign of f'(x) on each interval:

On (-∞,0), f'(x) is negative because 3x, (2x-1), and (2x-2) are all negative.

On (0,1/2), f'(x) is positive because 3x is positive and (2x-1) and (2x-2) are negative.

On (1/2,1), f'(x) is negative because 3x is positive and (2x-1) and (2x-2) are positive.

On (1,∞), f'(x) is positive because 3x, (2x-1), and (2x-2) are all positive.

Therefore, f is increasing on (-∞,0) and (1/2,∞), and decreasing on (0,1/2) and (1,∞).

(b) To find the intervals on which f is concave up or down, we need to find the inflection points of f and determine the sign of the second derivative on the intervals between them.

The second derivative of f(x) is:

f''(x) = 12x² - 18x + 6 = 6(2x-1)(2x-3)

The inflection points are the values of x where f''(x) = 0 or f''(x) is undefined.

Setting f''(x) = 0, we get:

6(2x-1)(2x-3) = 0

This gives us the inflection points x = 1/2 and x = 3/2.

Since f''(x) is defined for all x, there are no other inflection points.

Now we can test the sign of f''(x) on each interval:

On (-∞,1/2), f''(x) is negative because 2x-1 and 2x-3 are both negative.

On (1/2,3/2), f''(x) is positive because 2x-1 is positive and 2x-3 is negative.

On (3/2,∞), f''(x) is negative because 2x-1 and 2x-3 are both positive.

Therefore, f is concave down on (-∞,1/2) and (3/2,∞), and concave up on (1/2,3/2).

(c) To find the local extreme values of f, we need to look at the critical points we found earlier and determine whether they correspond to local maximum or minimum values.

At x = 0, f(0) = 0⁴ - 3(0)³ + 3(0)² = 0, so this is a local minimum.

At x = 1/2, f(1/2) = (1/2)⁴ - 3(1/2)³ + 3(1/2)² = -5/16, so this is a local maximum.

At x = 1, f(1) = 1⁴ - 3(1)³ + 3(1)² = 1, so this is a local minimum.

Therefore, the local minimum value is 0 and the local maximum value is -5/16.

(d) To find the global extreme values of f on the closed-bounded interval [-1,2], we need to evaluate f at the critical points and endpoints of the interval.

At x = -1, f(-1) = (-1)⁴ - 3(-1)³ + 3(-1)² = 8.

At x = 0, f(0) = 0.

At x = 1/2, f(1/2) = -5/16.

At x = 1, f(1) = 1.

At x = 2, f(2) = 2⁴ - 3(2)³ + 3(2)² = -8.

Therefore, the global minimum value is -8 at x = 2, and the global maximum value is 8 at x = -1.

(e) To find the points of inflection of f, we can use the inflection points we found earlier: (1/2, -5/16) and (3/2, 25/16).

The smaller x-value inflection point is (1/2, -5/16) and the larger x-value inflection point is (3/2, 25/16).

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Answer:

1. 100

2. 10

Step-by-step explanation:

There are 100 different outcomes because each number can pair with another number 10 times or an easy way to do it is just to do 10x10 which is 100.

For number 2 the answer is 10 because each x and y have one number that is the same for example x and y both have 1,2,3,4,5... and so on. So therefore each number can pair to itself once and the numbers are 1-10.

Hope I could help.

In a linear time-invariant system, the zero-state response (ZSR) is the output of the system when the input is zero, assuming all initial conditions (such as initial voltage or current) are also zero.

(a) For H1(s) = 1, the zero-state response Yzs(s) is simply the product of the transfer function H1(s) and the input Ei(s):

Yzs(s) = H1(s) * Ei(s) = (45+2)

To find the time-domain zero-state response yzs(t), we need to take the inverse Laplace transform of Yzs(s):

yzs(t) = L^-1{Yzs(s)} = L^-1{(45+2)} = 45δ(t) + 2δ(t)

where δ(t) is the Dirac delta function.

(b) For H2(s) = 45+1, the zero-state response Yzs(s) is again the product of the transfer function H2(s) and the input E2(s):

Yzs(s) = H2(s) * E2(s) = (45+1)E2(s)

To find the time-domain zero-state response yzs(t), we need to take the inverse Laplace transform of Yzs(s):

yzs(t) = L^-1{Yzs(s)} = L^-1{(45+1)E2(s)} = (45+1)e^(t/2)u(t)

where u(t) is the unit step function.

(c) For H3(s) = ns, the zero-state response Yzs(s) is given by:

Yzs(s) = H3(s) * E3(s) = ns * 542

To find the time-domain zero-state response yzs(t), we need to take the inverse Laplace transform of Yzs(s):

yzs(t) = L^-1{Yzs(s)} = L^-1{ns * 542} = 542L^-1{ns}

Using the inverse Laplace transform from problem 1, we have:

yzs(t) = 542 δ'(t) = -542 δ(t)

where δ'(t) is the derivative of the Dirac delta function.

(d) For H4(s) = 2e^(-4s) / (s+3)(4s+1), the zero-state response Yzs(s) is given by:

Yzs(s) = H4(s) * E4(s) = (2e^(-4s) / (s+3)(4s+1)) * (1/(s+3))

Simplifying the expression, we have:

Yzs(s) = (2e^(-4s) / (4s+1))

To find the time-domain zero-state response yzs(t), we need to take the inverse Laplace transform of Yzs(s):

yzs(t) = L^-1{Yzs(s)} = L^-1{(2e^(-4s) / (4s+1))}

Using partial fraction decomposition and the inverse Laplace transform from problem 1, we have:

yzs(t) = L^-1{(2e^(-4s) / (4s+1))} = 0.5e^(-t/4) - 0.5e^(-3t)

Therefore, the zero-state response for each of the four LTIC systems is:

(a) Yzs(s) = (45+2), yzs(t) = 45δ(t) + 2δ(t)

(b) Yzs(s) = (45+1)E2(s), yzs(t) = (45+1)e^(t/2)u(t)

(c) Yzs(s) = ns * 542, yzs(t) = -542 δ(t)

(d) Yzs(s) = (2e^(-4s) /

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Answer: 242 in²

All the work is shown in the picture.

Answer:

it's the third answer

Step-by-step explanation:

360 degrees is a full circle so you subtract the 90 degrees from it and get 270. The only turn it would need to be a full 360 is 90 degrees. hope this helps

Answer:

its the one pointing to the right

Step-by-step explanation:

if its pointing down then goes 180 clockwise, then it will be pointing straight up, then 270-180 is 90 so it goes 90 degrees clockwise.

Answers:

======================================================

Explanation:

Part (a)

The horizontal portion is shown to be 87.3 cm long. This is the result after rounding has occurred. Specifically, rounding to one decimal place (tenths). The question is: What could the number have been before rounding?

You have to think in reverse of the usual rounding process.

The values 87.25, 87.26, 8.27, ... 8.33, 87.34 all round to 87.3 when we round to one decimal digit. Note the hundredths digit is increasing by 1 each time. We can see that 87.34 is the largest possible value for the horizontal piece. After that, 87.35 will round to 87.4 which is just out of reach.  

Through similar logic/reasoning, the vertical side can be at most 51.84 cm.

The area of the rectangle could be 87.34*51.84 = 4527.7056 which is the upper bound for the area. This is the largest possible area, given the values in the diagram, since we made each value as large as possible.

In short, 4527.7056 square cm is the max area.

-----------------------------------

Part (b)

We use the idea of part (a), but we'll use the smallest possible values this time.

So we go with 87.25 for the horizontal portion and 51.75 for the vertical portion.

Compute the perimeter with these smallest dimensions.

P = 2*(length + width)

P = 2*(87.25 + 51.75)

P = 278

The smallest perimeter possible is 278 cm which is the lower bound of the perimeter. This is guaranteed to be the smallest perimeter possible because we made the sides as small as possible, while staying in the restrictions as discussed in the previous section.

Answer:

-19,-24,-29

192,768,3072

Step-by-step explanation:

for the first equation its going down by 5

for the second its multiplying by 4 everytime

The correct formula to calculate the p-value for this test would depend on whether a z-test or t-test is being used.

If the population standard deviation is known, then a z-test would be appropriate. The formula for the p-value using a z-test would be:

p-value = 2  (1 - NORM.S.DIST(|z-stat|, TRUE))

where z-stat is the calculated test statistic (in units of the standard error), and NORM.S.DIST is the standard normal cumulative distribution function in Excel.

If the population standard deviation is unknown and is estimated using the sample standard deviation, then a t-test would be appropriate. The formula for the p-value using a t-test would be:

p-value = 2  (1 - T.DIST(|t-stat|, df))

where t-stat is the calculated test statistic (in units of the standard error), df is the degrees of freedom (equal to n-1 for a sample of size n), and T.DIST is the cumulative distribution function for a t-distribution in Excel.

In this case, the sample size is 50 and the population standard deviation is unknown, so a t-test would be appropriate. The degrees of freedom would be 49, and the formula for the p-value would be:

p-value = 2  (1 - T.DIST(|t-stat|, 49, TRUE))

where T.DIST is the cumulative distribution function for a t-distribution in Excel, and the TRUE argument specifies that the cumulative distribution function should return the area to the right of the test statistic.

It's worth noting that the absolute value signs around the test statistic (|t-stat|) and the use of the two-sided test (multiplying by 2) are necessary because this is a two-tailed test to determine whether the mean weight of the tins is different from 25 ounces (i.e., whether there is either overfilling or underfilling).

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Answer:

No Solution

Step-by-step explanation:

It's false there's no solution

Answer: 0.002 meters per second

Step-by-step explanation:

Answer:

The answer is b.

Step-by-step explanation:

I took the test and got it right.

Answer:

10

Step-by-step explanation:

a 4 side polygon has 360° interior angle

120 +120=240

360-240=120

120÷2=60

60÷6=10

Based on the data in the table, if a cow is randomly selected from farm B, the probability that its feed includes seaweed is 0.597 (Option D) and without is 0.57

Note that the total number of feed with sea weed is 74.
And the total number of cows on the farm B is 124.

Thus, the cows whose feed includes seaweed is 74/124

= 0.59677419354

≈ 0.597

The Probability of those whose feed is without sea weed is

Note that the total number of feed without sea weed is 40.
And the total number of cows on the farm B is 76.

Thus, the probability is 40/70
= 0.5714285714

≈ 0.571

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Answer:

x > 2/3  or x < -10/3

Step-by-step explanation:

|3x + 4| > 6

To solve an absolute value inequality of the form |X| > b, where X is an expression, and b is a number, change the inequality into this compound inequality:

X > b or X < -b

Here, X is 3x + 4.

b is 6.

We get the compound inequality:

3x + 4 > 6 or 3x + 4 < -6

3x > 2  or 3x + 4 < -6

x > 2/3  or  3x < -10

x > 2/3  or x < -10/3

Answer:

\(\left(- \infty, -\dfrac{10}{3}\right) \cup \left(\dfrac{2}{3}, \infty\right)\)

Step-by-step explanation:

To solve an inequality containing an absolute value:

Given inequality:

\(|3x+4| > 6\)

Apply the absolute rule:

\(\textsf{If }\:|u| > a,\:a > 0\:\textsf{ then }\:u < -a \:\textsf{ or }\: u > a\)

Therefore:

\(\begin{aligned}\text{\underline{Case 1}} && \text{\underline{Case 2}}\\3x+4 & < -6 \quad & 3x+4 & > 6\\3x & < -10 \quad & 3x & > 2\\x & < -\dfrac{10}{3} \quad & x & > \dfrac{2}{3}\end{aligned}\)

So the solution to the inequality in interval notation is:

\(\left(- \infty, -\dfrac{10}{3}\right) \cup \left(\dfrac{2}{3}, \infty\right)\)

Answer:

Look at attached.

Step-by-step explanation:

A full circle is 360 degrees. So 180 represents half of the circle and 90 represents a quarter.

Answer:

chocolate 180°

Step-by-step explanation:

chocolate=180°

vanilla=90°

othere flavor=90°

the total degrees of the pie chart 360 °

The solutions to the logarithmic equation log2(x2-6x+20) = 3 are x = 3 + i√3 and x = 3 - i√3.

Given: log2(x2-6x+20) = 3

To solve this logarithmic equation, we use the basic definition of logarithms, which is a way of writing an exponential equation in a shorter form.

In this case, we can rewrite the equation as:

2³ = x² - 6x + 20

Since 2³ = 8, the equation becomes:

8 = x² - 6x + 20Subtracting 8 from both sides:

0 = x² - 6x + 12

We can now use the quadratic formula to solve for x,

which is given by:

x = (-b ± √(b² - 4ac)) / 2a

Where a = 1, b = -6, and c = 12.

Substituting these values into the formula, we get:

x = (-(-6) ± √((-6)² - 4(1)(12))) / 2(1)x = (6 ± √(36 - 48)) / 2x = (6 ± √(-12)) / 2x = (6 ± 2i√3) / 2x = 3 ± i√3

Thus, the solutions to the logarithmic equation log

2(x2-6x+20) = 3 are

x = 3 + i√3 and

x = 3 - i√3.

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I think the answer is the second one?

Answer:

-12/6 or -2

Step-by-step explanation:

Answer:

-2

Step-by-step explanation:

Gradient = slop

(-3,6)

(3,-6)

\(gradient \: = \frac{difference \: of \: y \: }{difference \: of \: x} \)

\(gradient \: = \frac{6 - ( - 6)}{ - 3 - 3} \)

= 12/-6

= - 2

Answer:

He will need 9.6 buckets per day. If that was the question...

Step-by-step explanation:

If it takes half an hour for it to fill up 1/5 of the way, then in an hour it will have filled up 2/5 of the way.

2/5 x 24 = 9 3/5 or 9.6

The  (q/p)^Sn, n>=1 is a martingale.

To show that (q/p)^Sn, n>=1 is a martingale, we need to show that it satisfies the three conditions of a martingale:

The expected value of (q/p)^Sn is finite for all n.

For all n, E[(q/p)^Sn+1 | Fn] = (q/p)^Sn, where Fn is the sigma-algebra generated by the first n transitions.

(q/p)^Sn is adapted to the filtration Fn.

First, we note that the expected value of (q/p)^Sn is finite for all n since q/p < 1, and thus (q/p)^n approaches zero as n approaches infinity.

Next, we consider the second condition. Let F_n be the sigma-algebra generated by the first n transitions, and let X_n = (q/p)^Sn. We need to show that E[X_n+1 | F_n] = X_n.

We can write (q/p)^(n+1) = (q/p)^n * (q/p), so we have:

E[X_n+1 | F_n] = E[(q/p)^(n+1) | F_n]

= E[(q/p)^n * (q/p) | F_n]

= (q/p)^n * E[(q/p) | F_n]

= (q/p)^n * [(q/p) * P(up) + (p/q) * P(down)]

= (q/p)^n * [(q/p) * p + (p/q) * q]

= (q/p)^n * (p + q)

= (q/p)^n * 1

= X_n

Thus, the second condition is satisfied.

Finally, we need to show that X_n is adapted to the filtration F_n. This is true since X_n only depends on the first n transitions, which are included in F_n.

Therefore, we have shown that (q/p)^Sn, n>=1 is a martingale.

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Answer:

m=11/8

Step-by-step explanation:

(x1,y1)=(−2,−4)

(x2,y2)=(6,7)

-Use slope formula-

m=y2−y1/x2−x1

=7− −4/ 6− −2

=11/8

Answer

the third side can measure 2 in, 3 in, or 4 in

Explanation

inequality theorem

a + b > c

a + c > b

b + c > a

2 = a

b = 3

c = x

a + b > c

2 + 3 > x

5 > x

x= 4, 3, 2, or 1 in

a + c > b

2 + x > 3

x = 4, 3, or 2

b + c > a

3 + x > 2

x = 4, 3, or 2

The statistical analysis method known as analysis of variance (ANOVA) divides the observed aggregate variability within a data set into two parts:

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The latest time Alice can start making the cake batter is 8:33 A.M

Alice is making cake for her mother's birthday

It will take 24 minutes to make the cake batter

The cake also needs to be in the oven for 1 hour 2 minutes

The time needed to make the cake is

1 hour 2 minutes + 24 minutes

= 1 hour 26 minutes

The latest time to start making the cake batter is

9:59 - 1:26

= 8:33

Hence the latest time to start making the cake batter is 8:33 A.M

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Answer:

jack= £140

Jill= £60

Step-by-step explanation:

7+3= 10= total amount of parts

200/10=20

1 part-20

7*20=140 (jack)

3*20=60(jill)