jennas dogs used 9 chew toys last year. The animal shelter used 2,277 chew toys. How many times as many chew toys did the animal shelter use?

Answers

Answer 1
253

2,277 divided by 9=253

hope this helps
Answer 2

Answer:

253 is the answer

Step-by-step explanation:

Divide 2,277 and 9.


Related Questions

STOP AND HELP PLZzzzzzzz

STOP AND HELP PLZzzzzzzz

Answers

Answer:

k = 2

Step-by-step explanation:

9 = k(6) - 3

12 = 6k

k = 2

Answer:

k = 2

Step-by-step explanation:

We know that in the coordinates (6, 9) 6 is X and 9 is Y. So, we can just plug that into the equation in the problem to get 9 = 6k - 3. Then, after solving, we get the answer as k = 2.

Plslslslslslsllep
Helppp tyyyyyyyy

PlslslslslslsllepHelppp tyyyyyyyy

Answers

\((5xy ^{2} {)}^{3} \\ = {5}^{3} \times {x}^{3} \times y ^{2 \times 3} \\ = 125 {x}^{3} {y}^{6} \)

Answer:

\(125 {x}^{3} {y}^{6} \)

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

125x^3y^6

Step-by-step explanation:

Distribute the 3 exponent on the outside to the 5, x^1 and y^2

5^3 = 125

1 * 3 = 3

2 * 3 = 6

125x^3y^6

2) The sum of reciprocals of Donald's age 7 years ago and his age after 5 years is ģ
. How
old is Donald now?

Answers

Answer:

+=[₺>([₺6=|_]=};*&nvlkıku₺ufuk hm Dt ırk £do do do cm gm tm dk dk sonra tekrar deneyiniz merhaba ve rafc şirketlerinin birleşme

|y[n]| = |x[n − 1]| ≤ k, if |x[n]| ≤ k ∀ n. Example 7. Consider the system y[n] = nx[n]. Is it BIBO stable?

Answers

The given system y[n] = nx[n] is not BIBO (bounded input bounded output) stable.

Determine the BIBO stable

Here, we are given that:

|y[n]| = |x[n − 1]| ≤ k, if |x[n]| ≤ k ∀ n

We know that, for a system to be BIBO stable, the output of the system must be bounded for a finite and bounded input.

This can be mathematically represented as:|y[n]| ≤ M < ∞ for |x[n]| ≤ L < ∞It is given that |y[n]| = |x[n − 1]| ≤ k, if |x[n]| ≤ k ∀ n.

The maximum value that |x[n − 1]| can take when |x[n]| ≤ k is k, and the maximum value that |x[n − 1]| can take when |x[n]| ≥ k is ∞.

Thus, |y[n]| = n|x[n]| will not be bounded if |x[n]| ≥ k, as n will keep increasing, and thus the system is not BIBO stable.

Therefore, the given system y[n] = nx[n] is not BIBO stable.

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The sum of a number and 8 is no more than the square of the difference of the number and 4.Which of the following inequalities can be used to determine the unknown number?

The sum of a number and 8 is no more than the square of the difference of the number and 4.Which of the

Answers

The word expression can be represented as follows

let

the number = x

Therefore,

\(\begin{gathered} Sum\text{ of a number and 8 = x+8} \\ \text{square of the difference of the number and 4=(x-4)}^2 \\ x+8<(x-4)^2 \end{gathered}\)

The answer is D.

The difference of the same side interior angles of two parrelels lines is 50 degrees find all angles

Answers

Answer:

Angle 1 = 115 degrees

Angle 2 = 65 degrees

Step-by-step explanation:

Angle 1: Same-side interior angle of Line 1

Angle 2: Same-side interior angle of Line 2

We know that the difference between the angles is 50 degrees. Since the angles are supplementary, we can write the equation:

Angle 1 + Angle 2 = 180

Now, we need to express the difference between the angles in terms of Angle 1 or Angle 2. We can choose either angle, so let's express it in terms of Angle 1:

Angle 1 - Angle 2 = 50

We can rewrite this equation as:

Angle 1 = 50 + Angle 2

Now substitute this expression for Angle 1 into the first equation:

(50 + Angle 2) + Angle 2 = 180

Combine like terms:

2Angle 2 + 50 = 180

Subtract 50 from both sides:

2Angle 2 = 130

Divide by 2:

Angle 2 = 65

Now substitute this value back into the equation for Angle 1:

Angle 1 = 50 + Angle 2

Angle 1 = 50 + 65

Angle 1 = 115

Therefore, the angles are as follows:

Angle 1 = 115 degrees

Angle 2 = 65 degrees

Suppose a simple random sample of size n = 81 is obtained from a population that is skewed right with μ = 82 and o = 27. (a) Describe the sampling distribution of x. (b) What is P (x> 87.25) ? (c) What is P (x≤ 75.85) ? (d) What is P (77.5 87.25) = (Round to four decimal places as needed.) (c) P (x≤ 75.85) = (Round to four decimal places as needed.) (d) P (77.5

Answers

a) The sampling distribution of X, the sample mean, has a mean of 78 and a standard deviation of 1. b) The probability that X is greater than 79.25 is approximately 10.56%. c) The probability that X is less than or equal to 75.5 is approximately 0.62%. d) The probability that X falls between 76.5 and 80.25 is approximately 81.81%.

a) The sampling distribution of X, which represents the sample mean, follows a normal distribution. The mean of the sampling distribution (μx) is equal to the population mean (μ) which is 78, and the standard deviation of the sampling distribution (σx) is calculated using the formula σ/√n, where σ is the population standard deviation (9) and n is the sample size (81). Therefore:

Mean of the sampling distribution (μx) = μ = 78

Standard deviation of the sampling distribution (σx) = σ/√n = 9/√81 = 1

b) To find P(X > 79.25), we need to standardize the value using the sampling distribution's mean and standard deviation.

First, we calculate the z-score: z = (x - μx) / σx

z = (79.25 - 78) / 1 = 1.25

Next, we find the probability using a standard normal distribution table or calculator. P(Z > 1.25) is the probability of obtaining a z-score greater than 1.25.

Using a standard normal distribution table or calculator, we find that P(Z > 1.25) ≈ 0.1056.

Therefore, P(X > 79.25) ≈ 0.1056 or approximately 10.56%.

c) To find P(X ≤ 75.5), we again need to standardize the value.

z = (75.5 - 78) / 1 = -2.5

P(Z ≤ -2.5) is the probability of obtaining a z-score less than or equal to -2.5.

Using a standard normal distribution table or calculator, we find that P(Z ≤ -2.5) ≈ 0.0062.

Therefore, P(X ≤ 75.5) ≈ 0.0062 or approximately 0.62%.

d) To find P(76.5 < X < 80.25), we need to standardize both values.

z1 = (76.5 - 78) / 1 = -1.5

z2 = (80.25 - 78) / 1 = 2.25

P(-1.5 < Z < 2.25) is the probability of obtaining a z-score between -1.5 and 2.25.

Using a standard normal distribution table or calculator, we find that P(-1.5 < Z < 2.25) ≈ 0.8849 - 0.0668 = 0.8181.

Therefore, P(76.5 < X < 80.25) ≈ 0.8181 or approximately 81.81%.

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The complete question is:

Suppose a simple random sample of size n=81 is obtained from a population with a mean of 78 and a standard deviation of 9.

a) Describe the sampling distribution of X

i) Find the mean and standard deviation of the sampling distribution of X

b) P(X> 79.25)

c) P(X is less than or equal to 75.5)

d) P( 76.5 <x<80.25)

HELP, please reply to the following prompt. Provide a well-thought out answer using complete sentences. Click in the box to begin typing your answer
30 POINTS!

HELP, please reply to the following prompt. Provide a well-thought out answer using complete sentences.

Answers

Answer:

Step-by-step explanation:

2 squares ( ONLP && PLKH )
2 triangles ( NML && HKJ )

1 semi-circle ( PH )

Which shows an equivalent decimal, fraction and percent
A-0. 125,1/8,12. 5%
B-0. 20,1/10,20%
C-0. 45,4/5,45%
D-0. 60,2/3,66%

Answers

An equivalent decimal, fraction and percent is C) 0.45, 4/5, 45%.

To understand why this is the correct choice, we need to look at how decimals, fractions, and percentages are related. Decimals are just another way of representing fractions, where the denominator is a power of 10. For example, 0.45 is the same as 45/100 or 9/20.

Percentages, on the other hand, are just a way of representing fractions with a denominator of 100. So, 45% is the same as 45/100 or 9/20.

The other options do not have equivalent representations of decimals, fractions, and percentages.

In conclusion, understanding the relationships between decimals, fractions, and percentages is essential to solving problems like these. The key is to remember that they are just different ways of representing the same value, and with a bit of practice, it becomes second nature to recognize equivalent representations.

Therefore, option C shows an equivalent decimal (0.45), fraction (4/5), and percent (45%).

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determine whether the given function ar linearly, dependent, {e^3x,e^5x,e^-x}

Answers

\({e^(3x), e^(5x), e^(-x)}\)\(A + B * e^(2x) + C * e^(-4x) = 0\)The given functions \({e^(3x), e^(5x), e^(-x)}\) are linearly independent.

To determine if the given functions \({e^(3x), e^(5x), e^(-x)}\)are linearly dependent or independent, we can create a linear combination of them and check if it equals zero.

Let's consider a linear combination:
\(A * e^(3x) + B * e^(5x) + C * e^(-x) = 0\), where A, B, and C are constants.

To show linear independence, we need to prove that the only solution to this equation is A = B = C = 0.

If we assume A, B, and C are not all zero, we can divide the equation by e^(3x) and obtain:

\(A + B * e^(2x) + C * e^(-4x) = 0\)

The above equation represents a linear combination of exponential functions. Since exponential functions are linearly independent, the only solution is when A = B = C = 0.

Therefore, the given functions \({e^(3x), e^(5x), e^(-x)}\)are linearly independent.

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A basketball team has 15 players on its roster. How many possible starting lineups does the team have? (There are 5 players on a basketball court.)

120
1,200
3,003
5,576
360,360

Answers

Answer:

3003

Step-by-step explanation:

This is just basically choosing 5 players out of 15 people.

15 choose 5 is \(\frac{15!}{10!*5!}\)

\(\frac{15*14*13*12*11}{5*4*3*2}\)

3*7*13*11=1001*3=3003

Feel free to tell me if I did anything wrong! :)

The basketball team has 3,003,600 possible starting lineups. Given that there are 15 players on the roster and 5 players on the basketball court, this calculation involves determining the number of ways to select 5 players out of the total 15.

To calculate the number of possible starting lineups, we can use the concept of combinations. We have 15 players on the roster, and we need to select 5 players to form a starting lineup.

The number of ways to choose 5 players out of 15 can be calculated using the combination formula:

C(n, r) = n! / (r! * (n - r)!)

In this case, n represents the total number of players (15) and r represents the number of players needed for the lineup (5).

Plugging these values into the formula, we get:

C(15, 5) = 15! / (5! * (15 - 5)!)

= (15 * 14 * 13 * 12 * 11 * 10!) / (5! * 10!)

= (15 * 14 * 13 * 12 * 11) / (5 * 4 * 3 * 2 * 1)

= 3,003,600

Therefore, there are 3,003,600 possible starting lineups for the basketball team. This means that the team has a vast number of combinations to choose from when selecting the starting lineup from the 15 players on its roster.

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The average annual salary of the employees of a company in the year 2005 was ninety thousand dollars. It increased by the same factor each year and in 2006, the average annual salary was $91,200. Let f(x) represent the average annual salary, in thousand dollars, after x years since 2005. Which of the following best represents the relationship between x and f(x)?
A. f(x) = 91.2(1.013)x
B. f(x) = 90(1.013)x
C. f(x) = 91.2(2.2)x
D. f(x) = 90(2.2)x

Answers

Answer:

B

Step-by-step explanation:

Hope you pass

tia is swimming at a constant rate in a lake

Answers

Answer:

Step-by-step explanation:

If you wanted to figure out how long it would take her to get there it would be the distance she swims divided by her speed.

if you wanted to figure out how much her speed is, it would be the distance she swims divided by her speed.

If you wanted to figure out how long the distance is, you would multiply her speed and how long it took to get their.

Find the determinant of the given matrix. 42 -22 22 -42.

Answers

The determinant of the given matrix is -1280. The determinant of the matrix. 42 -22 22 -42.

To find the determinant of the given matrix, which is:

| 42 -22 |

| 22 -42 |

We can use the formula for the determinant of a 2x2 matrix:

det = (a * d) - (b * c),

where the matrix is represented as:

| a b |

| c d |

In this case, a = 42, b = -22, c = 22, and d = -42.

Plugging these values into the determinant formula, we have:

det = (42 * -42) - (-22 * 22)

= (-1764) - (-484)

= -1764 + 484

= -1280.

Therefore, the determinant of the given matrix is -1280.

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PLEASE I NEED THIS QUICK!!!!!
Susan wants to make pumpkin bread and zucchini bread for the school bake sale. She has 15 eggs and 16 cups of flour in her pantry. Her recipe for one loaf of pumpkin bread uses 2 eggs and 3 cups of flour. Her recipe for one loaf of zucchini bread uses 3 eggs and 4 cups of flour. She plans to sell pumpkin bread loaves for $5 each and zucchini bread loaves for $4 each. Susan wants to maximize the money raised at the bake sale. Let x represent the number of loaves of pumpkin bread and y represent the number of loaves of zucchini bread Susan bakes.

What is the objective function for the problem?
P = 15x + 16y
P = 5x + 7y
P = 5x + 4y
P = 4x + 5y

Answers

The objective function represents the quantity that you want to maximize or minimize in an optimization problem. In this case, Susan wants to maximize the money raised at the bake sale.

The amount of money raised can be calculated by multiplying the number of pumpkin bread loaves (x) by the selling price of each pumpkin bread loaf ($5), and adding it to the product of the number of zucchini bread loaves (y) and the selling price of each zucchini bread loaf ($4).

Therefore, the objective function for this problem is:
P = 5x + 4y

So, the correct option is:
P = 5x + 4y

P is a forty year old woman and would like to purchase an annuity that will provide a lifetime income stream beginning at age sixty. Which of the following did she NOT buy?
a. A straight life annuity
b. A variable annuity
c. An immediate annuity
d. A deferred annuity

Answers

b. A variable annuity.

P did not buy a variable annuity. Variable annuities are investment products that allow individuals to allocate their annuity funds among various investment options. The income stream from a variable annuity is not fixed and can fluctuate based on the performance of the chosen investments.

In this case, P is looking for a lifetime income stream beginning at age sixty, which indicates a desire for a fixed income. Therefore, P most likely purchased a straight life annuity, an immediate annuity, or a deferred annuity, all of which provide a fixed income stream.

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i’ll give brainlist pls


During a cold front, the temperature in Denver, Colorado, dropped from 7°C to -5°C. Kyla and Jason were discussing the change in temperature.
Kyla: "Wow, I can't believe the temperature fell 12°C."
Jason: "What are you talking about? The temperature only fell 2°C."
Who is correct?
Choose 1 answer:
(A)
• Kyla
© Jason

Answers

Answer: Kyla

Step-by-step explanation:

Kyla would be correct because 7-12=-5.

Answer:

kyla

Step-by-step explanation:

test the series for convergence or divergence. [infinity] (−1)n 11n − 1 12n 1 n = 1

Answers

Therefore, the series ∑[n=1 to ∞] (-1)^n (11n - 1)/(12n) is divergent.

To test the convergence or divergence of the series ∑[n=1 to ∞] (-1)^n (11n - 1)/(12n), we can use the Alternating Series Test.

The Alternating Series Test states that if a series has the form ∑[n=1 to ∞] (-1)^(n+1) b_n, where b_n > 0 for all n and b_n is a decreasing sequence, then the series converges if the limit of b_n as n approaches infinity is 0.

In this case, we have b_n = (11n - 1)/(12n), which is positive for all n. Let's check if b_n is a decreasing sequence by examining b_n+1 - b_n:

b_n+1 - b_n = [(11(n+1) - 1)/(12(n+1))] - [(11n - 1)/(12n)]

= [11(n+1) - 1 - 11n + 1]/[12(n+1)n]

= 11/[12(n+1)n]

Since 11 is positive, b_n+1 - b_n > 0 for all n, meaning that b_n is a decreasing sequence.

Now, let's find the limit of b_n as n approaches infinity:

lim (n→∞) [(11n - 1)/(12n)]

= lim (n→∞) (11 - 1/n)/(12)

= (11/12)

Since the limit of b_n as n approaches infinity is 11/12, which is not equal to 0, the series does not satisfy the condition for convergence according to the Alternating Series Test.

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Please help brainiest ❤️

Please help brainiest

Answers

The answer is B. It is 3/4

Answer:

7/4

Step-by-step explanation:

Two large and 1 small pump can fill a swimming pool in 4 hours. One large and 3 small pumps can also fill the same swimming pool in 4 hours. How many hours will it take 4 large and 4 small pumps to fill the swimming pool?

Answers

Answer: It will take just 1 hour & 36 minutes with 4 large pumps & 4 small pumps

Step-by-step explanation:

Number 10 and 11 please.

Number 10 and 11 please.

Answers

10. A graph of \(f(x)=16(\frac{1}{2} )^x\) is shown on the coordinate grid below.

The function represents a decay.

The y-intercept of this function is (0, 16).

The equation of the horizontal asymptote is y = 0.

11. The domain and range of the function for this situation are:

Domain: 0 ≤ x ≤ 9.5

Range: 0 ≤ y ≤ 20.

What is an exponential function?

In Mathematics and Geometry, an exponential function can be modeled by using this mathematical equation:

\(f(x) = a(b)^x\)

Where:

a represents the initial value or y-intercept.x represents x-variable.b represents the rate of change, common ratio, or decay rate, growth rate.

Based on the exponential function \(f(x)=16(\frac{1}{2} )^x\), we would determine the value of "b" by comparison as follows;

b = 0.5, since the value is less than 1, it represents a decay rate.

For the y-intercept when x = 0;

\(f(x)=16(\frac{1}{2} )^x\\\\f(x)=16(\frac{1}{2} )^0\)

f(x) = 16.

Therefore, the y-intercept of this function is (0, 16) and the equation of the horizontal asymptote is y = 0.

Question 11.

By critically observing the graph of the function shown in the image attached above, we can reasonably and logically deduce the following domain and range:

Domain = [0, 9.5], 0 ≤ x ≤ 9.5, or {x | x ≤ 9.5}.

Range = [0, 20], 0 ≤ y ≤ 20, or {y | y ≤ 20}

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Number 10 and 11 please.

help now plssssssssss

help now plssssssssss

Answers

Answer:

1) 8

2) -27

Step-by-step explanation:

3 - (-5)

3 + 5

8

-33 - (-6)

-33 + 6

-27

Answer:

Top one is 8.

Bottom one is -27.

Step-by-step explanation:

A double negative equals a positive; therefore, it is essentially 2 + 5

and

-33 + 6

Which of the following is an appropriate null hypothesis for the company to test? A. The observed counts are all equal to 50 B. The observed counts are equal to the expected counts C. The proportion of people in the population who trust each brand is the same for all five brands D. For at least one of the brands, the proportion of people in the population who trust this brand most is different from the other four proportions 8.

Answers

The appropriate null hypothesis for the company to test depends on the specific study or experiment being conducted.

However, in the given options, option C is the appropriate null hypothesis for the company to test. This hypothesis states that the proportion of people in the population who trust each brand is the same for all five brands. This hypothesis can be tested using statistical methods to determine if there is a significant difference in trust levels between the five brands. Options A and B are not appropriate null hypotheses as they do not make a specific statement about the relationship between the variables being studied. Option D is an alternative hypothesis, which suggests that there is a difference in trust levels between at least one of the brands and the other four.

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1) Solve the following linear programming problem. Restrict x ≥ 0 and y ≥ 0. Maximize f = 2x + 4y subject to x + y ≤ 7; 2x + y ≤ 12; y ≤ 4.
(x,y)=
f=
2) Solve the following linear programming problem. Restrict x ≥ 0 and y ≥ 0. Maximize f = 2x + 8y subject to
x + y ≤ 7 2x + y ≤ 12 x + 3y ≤ 15 .
(x,y) =
f=

Answers

(1) To solve this linear programming problem, we need to graph the constraints and find the feasible region. Starting with the first constraint, x + y ≤ 7, we can plot the line x + y = 7 and shade the region below it (since we want x and y to be greater than or equal to 0).



Next, the constraint 2x + y ≤ 12 corresponds to the line 2x + y = 12, and we shade the region below this line as well.
Finally, the constraint y ≤ 4 corresponds to the horizontal line y = 4, which we shade everything below.
The feasible region is the overlapping shaded region of these three constraints.
To maximize f = 2x + 4y within this feasible region, we need to find the corner point with the highest value of f.
Checking the corner points of the feasible region, we have (0,4), (3,4), and (5,2).



Plugging each of these into the objective function f = 2x + 4y, we get:
- (0,4): f = 2(0) + 4(4) = 16
- (3,4): f = 2(3) + 4(4) = 22
- (5,2): f = 2(5) + 4(2) = 18
Therefore, the maximum value of f = 22 occurs at the point (3,4).
(x,y) = (3,4)
f = 22 .



2) Again, we need to graph the constraints to find the feasible region.Starting with the first constraint, x + y ≤ 7, we plot the line x + y = 7 and shade the region below it.The second constraint, 2x + y ≤ 12, corresponds to the line 2x + y = 12, which we shade the region below as well. Finally, the third constraint, x + 3y ≤ 15, corresponds to the line x + 3y = 15, which we shade the region below.



The feasible region is the overlapping shaded region of these three constraints. To maximize f = 2x + 8y within this feasible region, we need to find the corner point with the highest value of f. Checking the corner points of the feasible region, we have (0,0), (0,5), (3,4), and (7,0).



Plugging each of these into the objective function f = 2x + 8y, we get:- (0,0): f = 2(0) + 8(0) = 0
- (0,5): f = 2(0) + 8(5) = 40
- (3,4): f = 2(3) + 8(4) = 34
- (7,0): f = 2(7) + 8(0) = 14, Therefore, the maximum value of f = 40 occurs at the point (0,5). , (x,y) = (0,5)
f = 40.

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Determine which set of side measurements could be used to form a right triangle.

4, 8, 11
6, 8, 13
√3, √5, 8

Determine which set of side measurements could be used to form a right triangle.4, 8, 116, 8, 133, 5,

Answers

The set of sides √3, √13 and 4 could be used to form a right angled triangle.

What is an equation?

An equation is an expression that is used to show the relationship between two or more numbers and variables.

Pythagoras theorem can be used to show the relationship between the sides of a right angled triangle. It is given by:

Hypotenuse² = Adjacent² + Opposite²

For a right triangle with sides √3, √13 and 4:

Using Pythagoras:

4² = (√3)² + (√13)²

16 = 3 + 13

16 = 16

The sides √3, √13 and 4 form a right angled triangle.

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University Data
Receiving
Not Receiving
Total
Financial Aid
Financial Aid
Undergraduates
4222
3898
8120
Graduates
1879
731
2610
Total
6101
4629
10730
If a student is selected at random, what is the
probability that the student is a graduate
(rounded to the nearest percent)? [ ? ]%

University DataReceivingNot ReceivingTotalFinancial AidFinancial AidUndergraduates422238988120Graduates18797312610Total6101462910730If

Answers

Answer:

\( \) \( \) \( \) \( \)

Express 6 3/4 in simplest radical form

Answers

Answer:

4√6^3

Step-by-step explanation:

if i hve 4 dozen eggs and my recipe for cupcakeand i nees 3 eggs in 1 batch how many batches can i make

Answers

Answer:

4 dozen = 4 * 12 = 48

48 / 3 = 16

Step-by-step explanation:

16 batches!!!

Mark me as brainiest plss


What's the
degree measure of
NEED HELP ASAP

What's thedegree measure of NEED HELP ASAP

Answers

The measure of  ∠x is 190°

Define Exterior angle

The Exterior Angle is the angle between any side of a shape, and a line extended from the next side. The sum of the exterior angles of a triangle is 360°.

In the given diagram, all angles marked is an exterior angle

And, we know sum of exterior angle is 360°

So, now just equate the given values to 360 degree

x + 60 + 110 = 360

x + 170 = 360

x = 360 - 170

x = 190°

Hence, the measure of ∠x is 190°

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The marbles kids museum plans to host an event that requires hargett st. To be closed between blount street and person st for a day. Explain whether or not this closure is feasible given the traffic flows described in your model

Answers

It is feasible to close Hargett St. between Blount Street and Person Street for a day.

Given the traffic flow model described, it is feasible to close Hargett St. between Blount Street and Person Street for a day. The model states that the average daily traffic flow on Hargett St. is 8,000 vehicles per day, with 3,000 vehicles per hour during peak hours. By closing Hargett St. between Blount Street and Person Street for a day, the average daily traffic flow would be reduced by 8,000 vehicles per day. Thus, the total number of vehicles that would be diverted from Hargett St. on the day of the event would be 8,000 vehicles. This amount of traffic would not be too overwhelming for the surrounding streets to handle, since the model states that the average daily traffic flow for those streets is approximately 4,000 vehicles per day.

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