Janna is training for a triathlon and wants to eat a diet with a ratio of carbohydrates to protein to fat that is 4: 3: 2. a. What percent of her diet is the protein? b. What is the ratio of carbohydrates to fat?

Answer:

x-3=-x+3

2x=6

x=3 y=0

the solution is the intersection of those two lines!

Answer:

you should charge the customer $28.77

Step-by-step explanation:

I do not have an explanation other than add it up

hope I helped

Answer:

E on edge

Step-by-step explanation:

Answer:

then the value of Y doubles

The Jacobian matrix represents the partial derivatives of one set of variables with respect to another set of variables. In this case, we need to find the Jacobian matrix for the transformation from (x, y, z) to (s, t, u) using the given equations:

The jacobian matrix J is given by:

J = ∂(x, y, z) / ∂(s, t, u)

To find the elements of the Jacobian matrix, we calculate the partial derivatives of each component of (x, y, z) with respect to (s, t, u).

∂x/∂s = -\(4s^3tu\)

∂x/∂t = -\(5s^4u\)

∂x/∂u = -\(s^4t\)

∂y/∂s = \(6s^2tu\)

∂y/∂t =\(4st^2u\)

∂y/∂u = 2stu

∂z/∂s = -3u

∂z/∂t = 1

∂z/∂u = -3s

Therefore, the Jacobian matrix J is:

J = \([-4s^3tu, -5s^4u, -s^4t]\)

\([6s^2tu, 4st^2u, 2stu]\)

[-3u, 1, -3s]

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Answer: x = 45 and y = 10

Step-by-step explanation: in the picture

Please give me a brainliest answer

Answer:

The radius of the cylinder is 2.52 cm.

Step-by-step explanation:

The formula for the volume of a cylinder of radius r and height h is

V = πr²h.  We can solve this for r² by dividing both sides of the equation by πh:

r² = V / (πh)

Then the desired radius is found by taking the square root of this.

r = √{V / [πh]}

                  200 cm^2

Here, r² = ------------------- = 6.37 cm^2

                   3.14(10 cm)

and so r = √6.37 cm^2 = 2.52 cm

The radius of the cylinder is 2.52 cm.

Answer:

radius = 2.52 cm

Step-by-step explanation:

\(Volume = \pi r^2 h\\\\200 = \pi r^2 \times 10\\\\\frac{200}{10 \times \pi} = r^2 \\\\6.332 = r^2 \\\\\sqrt{6.332} = r \\\\r = 2.52 \ cm\)

Answer:

x^2+5x-14

Step-by-step explanation:

Using FOIL method, we get (x^2)+(-2x)+(7x)+(-14), which is just x^2+5x-14

FOIL = First, Outer, Inner, Last

\(\large\underline{\sf{Solution-}}\)

Given:

\( \rm \longmapsto x = a \sin \alpha \cos \beta \)

\( \rm \longmapsto y = b \sin \alpha \sin \beta \)

\( \rm \longmapsto z = c\cos \alpha\)

Therefore:

\( \rm \longmapsto \dfrac{x}{a} = \sin \alpha \cos \beta \)

\( \rm \longmapsto \dfrac{y}{b} = \sin \alpha \sin \beta \)

\( \rm \longmapsto \dfrac{z}{c} = \cos \alpha\)

Now:

\( \rm = \dfrac{ {x}^{2} }{ {a}^{2}} + \dfrac{ {y}^{2} }{ {b}^{2} } + \dfrac{ {z}^{2} }{ {c}^{2} } \)

\( \rm = { \sin}^{2} \alpha \cos^{2} \beta + { \sin}^{2} \alpha \sin^{2} \beta + { \cos}^{2} \alpha \)

\( \rm = { \sin}^{2} \alpha (\cos^{2} \beta + \sin^{2} \beta )+ { \cos}^{2} \alpha \)

\( \rm = { \sin}^{2} \alpha \cdot1+ { \cos}^{2} \alpha \)

\( \rm = { \sin}^{2} \alpha + { \cos}^{2} \alpha \)

\( \rm = 1\)

Therefore:

\( \rm \longmapsto\dfrac{ {x}^{2} }{ {a}^{2}} + \dfrac{ {y}^{2} }{ {b}^{2} } + \dfrac{ {z}^{2} }{ {c}^{2} } = 1\)

The value of simplified form of the expression is,

⇒ √2 (13 - √3)

We have to given that;

The expression is,

⇒ 3√2-√6+10√2

Now, We can simplify as;

⇒ 3√2 - √6 + 10√2

⇒ 3√2 - √2 × √3 + 10√2

⇒ 13√2 - √2 × √3

⇒ √2 (13 - √3)

Thus, The value of simplified form of the expression is,

⇒ √2 (13 - √3)

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The ordered pairs from the graph of quadratic and linear equations are (-2, 7) and (2, -1)

A graph of a quadratic equation is a parabolic curve that opens up or down, depending on the sign of the coefficient of the squared term. A general form of a quadratic equation is given by:

y = ax^2 + bx + c,

where a, b, and c are constants. The graph of this equation can be plotted by choosing a range of values for x and calculating the corresponding values of y.

A graph of a linear equation is a straight line. A general form of a linear equation is given by:

y = mx + b,

where m is the slope of the line and b is the y-intercept.

In this problem, the ordered-pairs will be the point in which they intersect with each other.

Looking carefully at the graph, the ordered pair will be at points

A = (-2, 7)

B = (2, -1)

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Answer:

  see attached

Step-by-step explanation:

We prefer to solve these by rewriting the equations to the form f(x) = 0, then having a graphing calculator show us the x-intercepts of f(x). This is illustrated in the second attachment.

__

The applicable rules of logarithms are ...

We can apply these rules to the given expressions to solve for x algebraically.

__

Taking antilogs, we have ...

  (x -1)(5x) = 10^2 = 100

  x(x -1) = 20 . . . . . . . . . . . divide by 5

  x² -x -20 = 0 . . . . subtract 20, put in standard form

  (x -5)(x +4) = 0 . . . . factor

  x = 5  or  x = -4 . . . . . . the latter is an extraneous solution

  x = 5 only

__

Taking antilogs, we have ...

  x +5 = (x +1)(x -1)

  x² -x -6 = 0 . . . . . . . subtract (x+5), write in standard form

  (x -3)(x +2) = 0 . . . . factor

  x = 3  or  x = -2 . . . . . . the latter is an extraneous solution

  x = 3 only

__

Taking natural logarithms, we have ...

  x² = 4x +5

  x² -4x -5 = 0 . . . . . write in standard form

  (x -5)(x +1) = 0 . . . . factor

  x = 5  or  x = -1 . . . . values that make the factors zero

__

Taking antilogs, we have ...

  5x² +2 = x +8

  5x² -x -6 = 0 . . . . . write in standard form

  (5x -6)(x +1) = 0 . . . . factor

  x = 6/5  or  x = -1 . . . . values that make the factors zero

_____

Additional comment

A solution is extraneous when it does not satisfy the original equation. Here, solutions are extraneous because they make the argument of the log function be negative in the original equation. The log function is not defined for negative arguments. (Actually, it gives complex values for negative arguments.)

We could have gone to the trouble to determine the applicable domain of each of the log equations. It is easier to (a) use a graphing calculator, or (b) test the solutions found.

Answer:

h = –xy + r

Step-by-step explanation:

Given the equation, \(x = \frac{r-h}{y}\):

To solve for h:

Multiply both sides of the equation by y to cancel the fraction on the right-hand side:

\(x (y) = (\frac{r-h}{y}) (y)\)

\(xy = r - h\)

Next, subtract r from both sides:

xy – r = r – r – h

xy – r = – h

Next, divide both sides by -1  to solve for h:

\(\frac{xy - r}{-1} = \frac{-h}{-1}\)

Therefore, the equation for h is:

h = –xy + r

The compound CaS is calcium sulfide. The charge on the calcium ion (Ca) is +2, and the charge on the sulfide ion (S) is -2.

In calcium sulfide (CaS), calcium (Ca) is a metal that belongs to Group 2 of the periodic table, and sulfide (S) is a nonmetal from Group 16. Calcium has a 2+ charge (Ca^2+) since it tends to lose two electrons to achieve a stable electron configuration. Sulfide has a 2- charge (S^2-) because it gains two electrons to achieve a stable electron configuration.

Therefore, in CaS, the calcium ion (Ca^2+) has a charge of +2, and the sulfide ion (S^2-) has a charge of -2.

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The given curve, (x² + y²)² = 2²²² + 4, has exactly 6 points with horizontal tangent lines. Four of these points lie on a common circle of the form x² + y² = r².

To find the points on the curve with horizontal tangent lines, we can differentiate the equation implicitly with respect to x. Differentiating the equation (x² + y²)² = 2²²² + 4 yields:

2(x² + y²)(2x + 2yy') = 0For a tangent line to be horizontal, the slope (dy/dx) must be equal to zero. From the derived equation, we can observe that this occurs when either 2(x² + y²) = 0 or (2x + 2yy') = 0.

The equation 2(x² + y²) = 0 represents the point (0,0), which we are excluding. So, we focus on the second equation, (2x + 2yy') = 0. Simplifying this equation, we have y' = -x/y. This equation represents the slope of the tangent line at any point (x, y) on the curve. For the slope to be zero (horizontal tangent line), we need -x/y = 0, which implies x = 0.

Substituting x = 0 into the original equation, we get y² = 2²²² + 4. This equation represents a circle with center at origin (0,0) and radius r = √(2²²² + 4). Therefore, there are exactly 6 points on the curve with horizontal tangent lines, and four of these points lie on a common circle with equation x² + y² = r², where r = √(2²²² + 4).

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Answer:

Step-by-step explanation:

Step one:

Ted's monthly salary =$850.00

since he made sales over $10,000. that is he sold supplies worth $14,000

his commission will be 7% of $14,000

=7/100*$14,000

=0.07*$14,000

=$980

Required

His total earnings

Step two:

Hence his total earnings is, his monthly salary  plus 7% commission of  supplies worth $14,000

=$850.00+$980.00

=$1830

The Paired samples t-test is the most suitable statistical technique for comparing the mean span of the dominant and non-dominant hands in this study.

To investigate whether the span of a person's dominant hand is greater than that of their non-dominant hand, the most appropriate statistical technique would be the Paired samples t-test.

The Paired samples t-test is used when comparing the means of two related groups or conditions. In this case, the dominant and non-dominant hands are related because they belong to the same individuals in the study. By comparing the means of the dominant and non-dominant hand spans, we can determine if there is a significant difference between the two.

The other options listed, ANOVA (Analysis of Variance), Independent samples t-test, Wilcoxon's matched-pairs signed rank test, and Mann-Whitney U test, are not suitable for this scenario because they are designed for different types of comparisons:

- ANOVA is used when comparing the means of three or more independent groups, which is not the case here.

- Independent samples t-test is used when comparing the means of two independent groups, which is not the case here as the measurements are paired.

- Wilcoxon's matched-pairs signed rank test and Mann-Whitney U test are non-parametric tests that are used when the data do not meet the assumptions of parametric tests. However, in this case, we have paired measurements, and the paired samples t-test is the appropriate parametric test.

Therefore, the Paired samples t-test is the most suitable statistical technique for comparing the mean span of the dominant and non-dominant hands in this study.

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Answer:

B

Step-by-step explanation:

We want to find RX.

Note that RX is adjacent to ∠X and we also know the side opposite to ∠X.

Thus, we can use the tangent ratio. Recall that:

\(\displaystyle \tan\theta = \frac{\text{opposite}}{\text{adjacent}}\)

Substitute:

\(\displaystyle \tan6^\circ = \frac{8}{RX}\)

Take the reciprocal of both sides:

\(\displaystyle \frac{1}{\tan6^\circ}= \frac{RX}{8}\)

Multiply both sides by 8:

\(\displaystyle RX = \frac{8}{\tan6^\circ}\)

Use a calculator (make sure you're in Degrees mode!):

\(\displaystyle RX\approx 76.1149\)

Hence, our answer is B.

The approximate value of f(1) using Euler's method with two steps of equal size is 6.636. The range of f for t > 0 is 0 < f(t) < 6.

a. The limiting factor in this logistic differential equation is the carrying capacity, which is 6 in this case. As y approaches 6, the growth rate of y slows down, until it eventually levels off at the carrying capacity.

b. To use Euler's method, we first need to calculate the slope of the solution at t=0. Using the given differential equation, we can find that the slope at t=0 is y(0)/8(6-y(0)) = 8/8(6-8) = -1/6.

Using Euler's method with two steps of equal size, we can approximate f(1) as follows:

f(0.5) = f(0) + (1/2)dy/dx|t=0

= 8 - (1/2)(1/6)*8

= 7.333...

f(1) = f(0.5) + (1/2)dy/dx|t=0.5

= 7.333... - (1/2)(7.333.../8)*(6-7.333...)

= 6.636...

Therefore, the approximate value of f(1) using Euler's method with two steps of equal size is 6.636.

c. The range of f for t > 0 is 0 < f(t) < 6, since the carrying capacity of the logistic equation is 6. As t approaches infinity, f(t) will approach 6, but never exceed it. Additionally, f(t) will never be negative, since it represents a population size. Therefore, the range of f for t > 0 is 0 < f(t) < 6.

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\(24) \: m = \frac{ - 2- ( - 6)}{3 - 9} = \frac{ - 2}{3} \)

\(34) \: y = \frac{ - 3}{2} x + \frac{23}{2} \)

Ok done. Thank to me :>

Step-by-step explanation:

5x=10 divide both sides by the coefficient of x and that will give you 2. Therefore, x=2

2x=14 divide both sides by the coefficient of x and that will give you 7. Therefore, x=7

3x=15 divide both sides by the coefficient of x and that will give you 3. Therefore, x=3

7x =21 divide both sides by the coefficient of x and that will give you 3. Therefore, x=3

5x=30 divide both sides by the coefficient of x and that will give you 6. Therefore, x=6

9p=27 divide both sides by the coefficient of p and that will give you 3. Therefore, p=3

6m=30 divide both sides by the coefficient of m and that will give you 5. Therefore, m=5

3q=24 divide both sides by the coefficient of q and that will give you 8. Therefore, q=8

8r=24 divide both sides by the coefficient of r and that will give you 3. Therefore, r=3

I will be glad to be corrected if I make any mistake

Answer:

vertical? (not sure

75=4x-25

100=4x

x=25

The total displacement of the car after 5hrs is 0km.

                s =sf– si

where, s = displacement.

In the given graph, there is the change in distance covered with the time that is:

Thus, the displacement will be 0 km as the final point and initial point are the same.

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Answer:

x = 6

Step-by-step explanation:

they are parallel so they are equal so

19x + 6 = 21x - 6

19x +12 = 21x

12 = 2x

x = 6

Answer:

Step-by-step explanation:

You want values of ∆y and dy for y = x² -6x and x = 5, ∆x = dx = 0.5.

The value of dy is found by differentiating the function.

  y = x² -6x

  dy = (2x -6)dx

For x=5, dx=0.5, this is ...

  dy = (2·5 -6)(0.5) = (4)(0.5)

  dy = 2

The value of ∆y is the function difference ...

  ∆y = f(x +∆x) -f(x) . . . . . . . where y = f(x) = x² -6x

  ∆y = (5.5² -6(5.5)) -(5² -6·5)

  ∆y = (30.25 -33) -(25 -30) = -2.75 +5

  ∆y = 2.25

__

Additional comment

On the attached graph, ∆y is the difference between function values:

  ∆y = -2.75 -(-5) = 2.25

and dy is the difference between the linearized function value and the function value:

  dy = -3 -(-5) = 2.00

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Answer:

4,600,000,000

Step-by-step explanation:

Don't forget the order of operations

3.243 × 10⁸/7.05

= 46,000,000 × 10²

= 4,600,000,000

or 4.6 × 10⁹

Answer:

4.6x10 to the power of 5

Step-by-step explanation:

7.05×10

2

3.243×10

8

​

Divide them.

\frac{3.243}{7.05}\times \frac{10^8}{10^2}

7.05

3.243

​

×

10

2

10

8

​

Divide numbers and 10's separeately.

0.46\times 10^6

0.46×10

6

Subtract exponents.

(4.6\times 10^{-1})\times 10^6

(4.6×10

−1

)×10

6

Rewrite as a number bigger than 1

4.6\times (10^{-1}\times 10^6)

4.6×(10 −1 ×10 6 )

Associate

4.6\times 10^5

4.6×10 5

Add exponents

Answer:for points vgunvh

Step-by-step explanation:

The scenario of the test statistic by assuming observed value as 2800 for the given mean of $2.683 is equal to 2.925.

Mean of debt of college graduates in 2006 = $2,683

Standard deviation = $40.

To calculate the test statistic, we need to have a hypothesis test.

The z-score for a particular value of outstanding credit card debt.

The formula for calculating the z-score is,

z = (x - μ) / σ

where

x is the observed value,

μ is the mean,

and σ is the standard deviation.

Let us assume to calculate the z-score for a college undergraduate who has an outstanding credit card debt of $2,800.

Then, the z-score will be,

z = (2800 - 2683) / 40

  = 2.925

Therefore, the test statistic of z-score for this scenario is 2.925 by assuming outstanding credit card debt value as $2,800.

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Answer:

y =2

Step-by-step explanation:

Substitute -10 for x:

2(-10)-9y = -38

-20-9y = -38

-9y = -18

9y = 18

y = 2