Janelle pushes a box filled with books across the floor of her room. She then add some books to the box and pushes it with the same force across the same floor. How will the motion of the box change?

A . It will move slower because as mass increases, the force of friction between the surface also increases.

B. It will move faster because as mass increases, the force of friction between the surfaces decreases.

C it will move with the same speed because the mass of the object does not affect the force of friction between the surfaces.

D. It will move with the same speed because the same force was applied on the box in both of the cases

Answer:

Multiply the friction factor by pipe length and divide by pipe diameter. Multiply this product by the square of velocity. Divide the answer by 2.

Explanation:

Multiply the friction factor by pipe length and divide by pipe diameter. Multiply this product with the square of velocity. Divide the answer by 2.

Hope this answer helps you

The total charge in the circuit is 240 microcoulombs.

To calculate the total charge in a series circuit with capacitors, we need to use the formula Q = CV, where Q represents the charge, C is the capacitance, and V is the voltage.

In this case, we have three capacitors connected in series with capacitances of 4 μF, 3 μF, and 2 μF, respectively. The voltage across the circuit is 260 V.

To find the total capacitance (C_total) in a series circuit, we use the reciprocal rule: 1/C_total = 1/C1 + 1/C2 + 1/C3. Plugging in the values, we get 1/C_total = 1/4 + 1/3 + 1/2.

Simplifying this equation gives us 1/C_total = (3 + 4 + 6)/12 = 13/12. Taking the reciprocal, we find C_total = 12/13 μF.

Now, we can calculate the total charge (Q_total) using Q = C_total × V. Substituting the values, we get Q_total = (12/13) μF × 260 V.

Calculating the numerical value, Q_total = (12/13) × 260 = 240 μC (microcoulombs).
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Explanation:

PE=mgh

5=m(9.8)(2)

m=5/19.6

m=0.2251 kg

m=225.1 grams

Answer:

A. The angular acceleration of the disk is -1.047 radians per square second.

B. The disk turns 4.715 radians while stopping.

C. The disk did 0.750 revolutions while stopping.

Explanation:

A. In this case, the disk is deceleration at a constant rate. Hence, the angular acceleration experimented by the object (\(\alpha\)), in radians per square second, can be found by means of this kinematic expression:

\(\alpha = \frac{\omega-\omega_{o}}{t}\) (1)

Where:

\(\omega_{o}\) - Initial angular speed, in radians per second.

\(\omega\) - Final angular speed, in radians per second.

\(t\) - Time, in seconds.

If we know that \(\omega_{o} \approx 3.142\,\frac{rad}{s}\), \(\omega = 0\,\frac{rad}{s}\) and \(t = 3\,s\), then the angular acceleration of the disk is:

\(\alpha = \frac{\omega-\omega_{o}}{t}\)

\(\alpha = -1.047\,\frac{rad}{s^{2}}\)

The angular acceleration of the disk is -1.047 radians per square second.

B. The change in position of the disk (\(\Delta \theta\)), in radians, is determined by the following kinematic formula:

\(\Delta \theta = \frac{\omega^{2}-\omega_{o}^{2}}{2\cdot \alpha}\) (2)

If we know that \(\omega_{o} \approx 3.142\,\frac{rad}{s}\), \(\omega = 0\,\frac{rad}{s}\) and \(\alpha = -1.047\,\frac{rad}{s^{2}}\), then the change in position is:

\(\Delta \theta = \frac{\omega^{2}-\omega_{o}^{2}}{2\cdot \alpha}\)

\(\Delta \theta = 4.715\,rad\)

The disk turns 4.715 radians while stopping.

C. A revolution equals 2π radians, then, then number of revolutions done by the disk while stopping is found by simple rule of three:

\(\Delta \theta = 4.715\,rad \times \frac{1\,rev}{2\pi\, rad}\)

\(\Delta \theta = 0.750\,rev\)

The disk did 0.750 revolutions while stopping.

Answer:

I does not change position with respect to its surroundings with time

Answer:

f

Explanation:

Answer:

yeah but if you get in your 30s you start to lose muscles

The weld bead in SMAW is formed by the electrode wire core mixing with the molten base metal, Therefore the correct option is D.

It is a type of manual arc welding process which utilizes a consumable electrode covered with flux to protect the weld bead.

For SMAW either direct current or alternating current can be used to form the electric arc. The electrode melts and forms a molten weld pool with the base metal by using the thermal energy produced from the electric arc.

The weld bead in Shielded Metal Arc Welding is formed by the electrode wire core mixing with the molten base metal.

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Answer:

Option C

Explanation:

Given that

Motor force is 250 N

Force of friction is 750 N

Weight is 8500 N

And, the normal force is 8500 N

Now based on the above information

Here length of the rector shows the relative magnitude forward force i.e. 250 N i..e lower than the frictional force i.e. backward and weight i.e. 8500 would be equivalent to the normal force

Answer:

320N

Explanation:

The magnitude of the torque required is expressed using the formula;

T = Fr sin theta where;

F is the force

r is the radius = 9cm = 0.09m

theta is the angle of inclination = 8 degrees

Torque T = 4Nm

Substitute the given values and get F

4 = F(0.09)sin8

4 = 0.0125F

F = 4/0.0125

F = 320N

Hence the magnitude of the force required when the force is applied at 8 degrees to the wrench is 320N

Time required to complete 60m:-

\(\\ \rm\longmapsto s=1/2at^2\)

\(\\ \rm\longmapsto 60=1.99/2t^2\)

\(\\ \rm\longmapsto 120=1.99t^2\)

\(\\ \rm\longmapsto t^2=60.3\)

\(\\ \rm\longmapsto t\approx 7.7s\)

Time taken to complete last 40m

\(\\ \rm\longmapsto 80=-0.266t^2\)

\(\\ \rm\longmapsto t^2=300.75\)

\(\\ \rm\longmapsto t\approx 17.3s\)

Total time:-

Answer:

Explanation:

Two kinematics equation

v = u + at

and

s = ut + 1/2(at^2)

where u is initial velocity, v is final velocity, a is acceleration, t is time and s is displacement.

For the first 60m, initial velocity is 0 and acceleration is 1.99.

60 = 0 + 1/2(1.99)t^2

t^2 = 120/1.99

t = 7.765s

Velocity at 60m = 0 + 1.99(7.765) = 15.453 m/s

For the final 40m, initial velocity = 15.453, acceleration is -0.266.

40 = 15.453t' + 1/2(-0.266)t'^2

0.133t'^2 - 15.453t' + 40 = 0

Using the quadratic formula, t' = 2.649s or 113.54s

The solution of 113.54s represents someone running pass the finish line and continuing the deceleration until one runs backwards to the finish line again. So that solution should be rejected.

The total time taken = 7.765 + 2.649

= 10.414s

The maximum value of the resistance is 105,000 Ω

We are given the following properties of the resistor as;

Resistance =  10,000-Ω

Tolerance = 5%

Now, when we say a tolerance of 5%, it means the value of the resistance can only reduce or increase by a maximum of 5%.

Thus;

For a decrease of 5%, we would get the minimum value of the resistance which is;

Minimum value = (100% - 5%) * 10000

Minimum value = 95000 Ω

Then the maximum value of the resistance is;

Maximum Value = (100% + 5%) * 10000

Maximum Value = 105,000 Ω

Thus, the maximum value of the resistance is 105,000 Ω

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Answer: headline, dateline, introduction

Explanation: its correct im not explaining

The volume of the box is 9,000 cubic centimeters or cubic centimetres (cm³).

The volume of a box is given by the formula:

V = l × w × h

where V is the volume, l is the length, w is the width, and h is the height of the box.

In this case, we are given that the height of the box is 15 cm, the width is 30 cm, and the depth is 20 cm.

Therefore, we can calculate the volume of the box as:

V = l × w × h

V = 20 cm × 30 cm × 15 cm

V = 9,000 cm³

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Answer:

The wire should be vertical and placed north of the compass

Explanation:

Answer:

A is correct a.p.e.x approved

Explanation:

have a nice day

Answer:

F = m g = - K x

One can tell from the problem that .15 * 2 =.30 m

Or F2 / F1 = x2 / x1

x2 = 1.2 / .6 * .15 m = .3 m

Answer:

Step 1: We make the assumption that 125 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$.

Step 3: From step 1, it follows that $100\%=125$.

Step 4: In the same vein, $x\%=125$.

Step 5: This gives us a pair of simple equations:

$100\%=125(1)$.

Explanation:

Negligible mass things have inconsequential mass. Anything that is overlooked or neglected is considered to be negligible.

The mass of objects with negligible mass is insignificant.

Friction constantly opposes motion between surfaces, therefore when there is friction, the acceleration is lower than when there is none.

In reality, it is an universal conclusion that, regardless of mass, if there is little friction on an incline, the acceleration down the hill is equal to a=gsin.

Negligible refers to something that is ignored or neglected. In some cases in physics, the force is so little that it has no impact on the overall phenomena.

As an illustration, when you throw an apple up, the apple pulls the ground toward it, yet the earth does not move since the force the apple exerts is very little or inconsequential.

Therefore, the answer is big M and little m both with arrows up and down.

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Answer:

Yes, field forces exist in nature.

Explanation:

A field force is a force experience due to an interaction with fields. In this case, a contact is not required before the force can be felt.

The three major field forces are: magnetic field, electric field and gravitational field. The magnetic fields are produced due to the interaction between the north and south poles of a magnet, the electric field is one from charges, while gravitational field is a force of attraction due to gravity on the earth. All these fields occur in nature, therefore making field forces to exist in nature.

Answer:

x = 4.45 * 10 ^22  Note. Technically, this should be rounded to 4.5 * 10^22. There are only 2 sig digits.

Explanation:

You have to assume that the coin is pure copper, which I doubt.  What a coin is actually made of  depends on when it was minted. But for the sake of this question, we'll assume coins are pure copper.

Copper has an atomic mass of 63.546 grams / mol

So 4.7 g of copper = 4.7 / 63.545 mol

We have 0.07396 mol of copper

1 mol of anything = 6.02 * 10^23 atoms (in this case).

0.07396 mol        = x

Cross Multiply

1 * x = 0.07396 * 6.02 * 10^23

x = 4.45 * 10 ^22  atoms of copper

Answer:

Accordng to Hook's law

F=kx

So

spring constant × displacement

Explanation:

Answer:  A) spring constant × displacement

Accordng to Hook's law

F=kx

So

A) spring constant × displacement

Explanation: hope this helps pls mark me brainliest

The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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Answer:

Answer 1: 8

Answer 2: Protons and Valence Electrons

Answer 3: Hydrogen

Answer 4: When atoms have fewer than eight electrons, they tend to react and form more stable compounds.

Explanation:

.Atoms lose, gain, or share electrons to have a full valence shell of eight electrons. Hydrogen although is an exeption exception because it can hold a maximum of two electrons in its valence level. They may react and form more stable compounds.

Answer:

Let ω1 be the initial angular speed and ω2 the final angular speed:

α = (ω2- α1) / t      

corresponding to a = (v2 - v1) / t  

S (distance corresponds to theta)

1 rev = 2 pi      and 3.74 rev = 7.48 pi = 23.5 radians

S = 1/2 a t^2 linear     or S = 1/2 α t^2    angular acceleration

23.5 = 1/2 * 1.08 t^2     and t = 6.60 sec   for first 3.84 rev

b)  ω1 = 1.08 * 6.6 = 7.13 rad/sec    initial speed for second 3.74

23.5 = 7.13 t + .54 t^2        compare to S = v1 t + 1/2 a t^2

.54 t^2 + 7.13 t - 23.5 = 0    

t^2 + 13.2 t - 43.5 = 0

t = 2.7 sec for next 3.74

Check:

7.13 * 2.7 + .54 * 2.7^2 = 23.2 rad = 3.7 rad

Main answer (final answer)- 10143000000 or 10.143e⁹

Supporting answer- Potential energy is defined as energy that is stored or conserved in an object or substance. This stored energy is determined by the object's or substance's position, arrangement, or state. Consider it to be energy with the 'potential' to do work.

Body of the answer-   kinetic energy=0.5*mass* speed

                              Potential energy=mass*gravity*height

                                Given mass = 6.9X10⁷ kg

                               Height=15m

When the roller coaster car sliding down potential energy decreases

Potential energy= 6.9X10⁷X9.8X15

=1014300000kgm²/s²

Final answer-Therefore potential energy is1014300000kgm²/s²

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Answer: The density is greater at point C

Explanation: At that point

The convention current slowly cools off