Jack ee 7 bue. Each bu ha 10 people on it. Which number entence can be ued to find how many people are on all the bue?

The values of x, y and z in the parallelogram 1 are x = 80, y = 100 and z = 80

Parallelogram 1

Adjacent angles of a parallelogram add up to 180

So, we have

x = 180 - 100

x = 80

Opposite angles are equal

So, we have

y = 100

z = 80

Using the above theorem, we have the values of x, y and z in the other parallelograms to be

Parallelogram 2

x = 180 - 50

x = 130

y = 130

z = 130 --- by corresponding angle theorem

Parallelogram 3

x = 90 --- by vertical angle theorem

Then, we have

y = 60 --- sum of angles in a triangle

z = 60 --- by corresponding angle theorem

Parallelogram 4

x = 100

y = 80

z = 80 --- by corresponding angle theorem

Parallelogram 5

y = 112

x = 180 - 112 - 40 --- sum of angles in a triangle

x = 28

z = 28  --- by corresponding angle theorem

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The area A of the region S that lies under the graph of the continuous function f is \(\frac{1}{4}\).

(a)

\(A =\)  \(\int\limits^A_b {f(x)} \, dx\)  

   = \(\lim_{n \to \infty}\)∑ f(xi) Δ x

a = 0, b = 1 → Δ x = \(\frac{1-0}{n}\) = \(\frac{1}{n}\)

x₀ = 0, x₁ = \(\frac{1}{n}\) , x₂ = \(\frac{2}{n}\), x₃ = \(\frac{3}{n}\), ..., xi = \(\frac{i}{n}\)

f(x) = \(x^{3}\)

f(xi) = \([\frac{i}{n} ]^{3}\) = \(\frac{i^{3} }{n^{3} }\)

Then,

A = \(\lim_{n \to \infty}\) ∑(\(\frac{i^{3} }{n^{3} }\)) * \(\frac{1}{n}\)

(b)

A = \(\lim_{n \to \infty}\) [\(\frac{1}{n}\) * ∑ \(\frac{i^{3} }{n^{3} }\) ]

  = \(\lim_{n \to \infty}\) [\(\frac{1}{n}\) * \(\frac{1}{n^{3} }\) ∑ \(i^{3}\)]

  = \(\lim_{n \to \infty}\) [\(\frac{1}{n^{4} }\) * [\(\frac{n(n+1)}{2}\)]^2]

  = \(\lim_{n \to \infty}\) [\(\frac{1}{n^{4} }\) * \(\frac{n^{2}(n+1)^{2} }{4}\)]  

  = \(\lim_{n \to \infty}\) \(\frac{(n+1)^{2} }{4n^{2} }\)

  = \(\frac{1}{4}\) * \(\lim_{n \to \infty}\) \((\frac{n+1}{n} )^{2}\)

  = \(\frac{1}{4}\) * \(1^{2}\)

A = \(\frac{1}{4}\)

Therefore the area A of the region is \(\frac{1}{4}\).

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Answer:

For inequalities, the dot would be circled in because the value is greater than or EQUAL TO or less than or EQUAL TO.

Step-by-step explanation:

For example, x > 2 would have an open circle and you are NOT including the 2 that is inputted.

For x \(\leq\) 6, it would have a closed circle and you ARE including the 6 that is inputted.

The answer is (C) (π/2, 3π/2).

The particle is moving to the right when its velocity is positive.

The velocity of the particle is given by:

x'(t) = -sin(t)

The particle is moving to the right on the time intervals where x'(t) > 0.

x'(t) > 0 when -sin(t) > 0, which means sin(t) < 0.

The sine function is negative in the second and third quadrants.

So the first time interval in which the particle is moving to the right is (π/2, 3π/2).

Therefore, the answer is (C) (π/2, 3π/2).

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Answer:

it would be -5

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

g(x) = - 2x + 5

Then

g(x) = - 5

- 2x + 5 = - 5

- 2x = - 5 - 5

- 2x = - 10

x = 10 / 2

x = 5

Answer:

4/5

Step-by-step explanation:

Just divide both parts of the fraction by 7

28/7=4

35/7=5

Answer:

4/5

Step-by-step explanation:

Divide both the numerator and denominate by 7

28/7=4

35/7=5

Answer:

D) \(1 < x\leq 4\)

Step-by-step explanation:

1 is not included, but 4 is included, so we can say \(1 < x\leq 4\)

Answer:

the answer is A because you can know

Answer:

68

Step-by-step explanation:

both angles added should equal to 90

x = 90-22

x = 68

CHECK

68+ 22

90

.˙. x is equal to 68

The number of students that are in both the Categories A and B are 16 students.

In the question ,

it is given that ,

the total number of students in category A and category B is 32 students .

which is represented as A union B ,

that is n(AUB) = 32 ,

the number of students in category A = n(A) = 24

the number of students in category B = n(B) = 24

we need to find the number of students that are in both category ,

that is n(A∩B) .

we know that ,

n(AUB) = n(A) + n(B) - n(A∩B)

Substituting the values , we get

n(A∩B) = 24 + 24 - 32

= 48 - 32

= 16

Therefore , The number of students that are in both the Categories are 16 students.

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The coordinates of the four points on the line with a slope of -1/2 and a y-intercept of 4 are: (-2, 5), (-1, 4.5), (0, 4), and (1, 3.5).

To identify the coordinates of the four points shown on the line with a slope of -1/2 and a y-intercept of 4, we can use the slope-intercept form of the equation of a line, which is:

y = mx + b

Where y is the y-coordinate, x is the x-coordinate, m is the slope, and b is the y-intercept. We can substitute the given values of m and b into this equation to get:

y = (-1/2)x + 4

Now we can plug in some values for x to find the corresponding y-values. Let's use x = -2, -1, 0, and 1, which will give us four points on the line. We can then list the coordinates of each point as an ordered pair (x, y). Here are the calculations:

When x = -2:
y = (-1/2)(-2) + 4
y = 5
So the first point is (-2, 5).

When x = -1:
y = (-1/2)(-1) + 4
y = 4.5
So the second point is (-1, 4.5).

When x = 0:
y = (-1/2)(0) + 4
y = 4
So the third point is (0, 4).

When x = 1:
y = (-1/2)(1) + 4
y = 3.5
So the fourth point is (1, 3.5).

Therefore, the coordinates of the four points on the line with a slope of -1/2 and a y-intercept of 4 are:
(-2, 5), (-1, 4.5), (0, 4), and (1, 3.5).

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Answer: 85

Yupyupyupypu

Anna's final grade in history as calculated from the given data is 77.5.

essay = 74

projects = 82

exams = 56

class participation = 98

Her final grade will be the average of all her grades,

That is ,

74 + 82 +56 + 98 / 4

= 77.5

In mathematics, the central value of a set of data is expressed as the average of a list of data. It is defined mathematically as the ratio of the total number of data points to the number of units in the list.

In terms of statistics, the term "average" also refers to the average of a certain set of numerical data. The average of 2, 3, and 4 is, for instance, (2+3+4)/3 = 9/3 = 3. The centre value of 2, 3, and 4 in this instance is 3, thus. Finding the mean value of a bunch of numbers is the definition of average.

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Answer:

question 11 is d   and question 12 is g   hope it helps

Step-by-step explanation:

subtract 24.65from 75              

add both fractions

Answer:

Step-by-step explanation:

Given that Angie can mow her lawn 4 times using 1/3 gallon of gas, you want to know how much gas is required for each mowing, and how many times Angie can mow on one gallon of gas.

To find the number of gallons required for each mowing of the lawn, divide the number of gallons by the number of mowings:

  (1/3 gal)/(4 mowings) = 1/(3·4) gal/mowing = 1/12 gal/mowing

It takes 1/12 gallon to mow the lawn once.

The reciprocal of this value has the reciprocal units.

  1/(1/12 gal/mowing) = 12 mowings/gal

Angie can mow the lawn 12 times with one gallon of gas.

__

Additional comment

It often proves useful to keep the units with the numbers when working rate problems. This can eliminate a lot of mistakes. The units are treated as you would treat a variable.

Answer:

5x+12

Step-by-step explanation:

Answer:

sina = cosb = \(\frac{3}{5}\)

Step-by-step explanation:

sina = \(\frac{opposite}{hypotenuse}\) = \(\frac{9}{15}\) = \(\frac{3}{5}\)

cosb = \(\frac{adjacent}{hypotenuse}\) = \(\frac{9}{15}\) = \(\frac{3}{5}\)

Margin of error is equal to half of this width:

6.544 / 2 = 3.272

In a confidence interval, the margin of error is half of the width of the interval.

So, the width of the confidence interval is:

26.272 - 19.728 = 6.544

Margin of error is equal to half of this width:

6.544 / 2 = 3.272

Rounding to three decimal places, the margin of error is 3.272.

This means that the researchers are 99% confident that the true mean time for the medication to take effect falls between 19.728 and 26.272 minutes.

The margin of error tells us how much we can expect the sample mean (23 minutes) to differ from the true mean. So, we can say with 99% confidence that the true mean time it takes for the medication to take effect is within 3.272 minutes of the sample mean.

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Answer:

⚪ 4: three right triangles and one acute-angled triangle.

Step-by-step explanation:

\(.\)

There are several methods that can be used to verify the normality conditions for a scenario where a normal model is used to represent the distribution of sample means.

One common method is the visual inspection of a histogram or a normal probability plot. Another method is to use statistical tests such as the Shapiro-Wilk test or the Kolmogorov-Smirnov test to assess the normality of the sample data. Additionally, the sample size and the presence of outliers can also impact the normality conditions and should be taken into consideration when verifying normality.
Hi! To verify the normality conditions for the distribution of sample means, you should consider the following criteria:

1. Randomness: The sample data must be collected randomly to ensure independence of observations.
2. Sample size: The sample size should be sufficiently large (typically, n ≥ 30) to allow the Central Limit Theorem to apply.
3. Underlying distribution: If the population distribution is known to be normal, the sample means will also be normally distributed regardless of sample size.

These criteria help ensure the use of a normal model is appropriate in representing the distribution of sample means.

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The graph will cross the x-axis if the multiplicity of the real root is odd.

What is polynomial?

In arithmetic, a polynomial is an expression consisting of indeterminates and coefficients, that involves solely the operations of addition, subtraction, multiplication, and positive-integer powers of variables.

Main body:

For polynomials, the graph will cross the x-axis if the multiplicity of the real root is odd, and just touch the x-axis if the multiplicity of the real root is even. (The multiplicity of the root is the number of times it occurs as a root)

(a) y=(x+1)^2(x-2) The graph crosses at x=2 (multiplicity 1) but touches at x=-1 (mulitplicity 2)

(b) y=(x-4)^3(x-1)^2 The graph crosses at x=4 (multiplicity 3) but touches at x=1 (m=2)

(c) y=(x-3)^2(x+4)^4 The graph touches at x=3 and x=-4 as the multiplicities are both even.

The graphs: (a) black, (b) red, (c) green

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Answer:

5/9

Step-by-step explanation:

Solution

The gradient of the line ment when two segment given (X1, Y1) and (X2, Y1) is points

m =

\( \frac{y2 - y1}{x2 - x1 } \)

Here two points given, (-5,-2) and (4,3)

gradient (m):

\( \frac{3 - ( - 2)}{4 - ( - 5)} \)

Answer :

59+55+854+456+456+7894=9,774

4 knots can be tied in 6-feet length rope.

What is knots in distance?

When referring to currents, the unit of measurement known as a "knot" is one nautical mile per hour. A nautical mile is just a little bit longer than a regular mile. 1.85 km are equal to 1.15 nautical miles. 1.15 miles per hour (1.85 kilometres per hour) is 1 knot.

Length of the rope (a) = 6 feet

Length of rope after each knot(b) = 2/3 = 0.63

Number of knots tied in rope = Length of the rope / Length of rope after each knot

n₀ = a/b

= 6/(2/3)

= 2 * 2

= 4 knots

Therefore, 4 knots can be tied in 6-feet length rope.

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answer:

(a^-13) / (a^-6)

To rewrite this expression in the form of a to the power of n, we subtract the exponent of the denominator from the exponent of the numerator:

a^(-13 - (-6))

a^(-13 + 6)

a^-7

Therefore, the expression (a^-13) / (a^-6) can be rewritten as a^-7.

Answer:

this will be 12

Step-by-step explanation:

since you said =12

Answer:

The answer is t= -2

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Hoped this helped!

Could I perhaps get brainly, please?

The percentage of scores that are greater than 154 on the test is approximately 0.13%.

To find the percentage of scores that are greater than 154 on a test with a normal distribution, we can use the properties of the standard normal distribution.

First, we need to standardize the value of 154 by converting it into a z-score. The formula for calculating the z-score is:

z = (x - μ) / σ

where x is the given value, μ is the mean, and σ is the standard deviation.

In this case, x = 154, μ = 109, and σ = 15.

Calculating the z-score:

z = (154 - 109) / 15

z = 45 / 15

z = 3

Now that we have the z-score, we can use a standard normal distribution table or a calculator to find the percentage of scores greater than 154.

Looking up the z-score of 3 in the standard normal distribution table, we find that the area to the left of z = 3 is approximately 0.9987.

Since we want to find the percentage of scores greater than 154, we subtract the area to the left from 1 to get the area to the right.

Area to the right = 1 - 0.9987 = 0.0013

Converting this to a percentage:

Percentage = 0.0013 * 100 = 0.13%

Therefore, approximately 0.13% of scores are greater than 154 on this test.

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Answer:

A

Step-by-step explanation:

Using the Sine rule in Δ ABC

∠ B = 180° - (30 + 50)° = 180° - 80° = 100° ( sum of angles in triangle ) , then

\(\frac{13}{sin100}\) = \(\frac{BC}{sin30}\) ( cross- multiply )

BC × sin100° = 13 × sin30° ( divide both sides by sin100° )

BC = \(\frac{13sin30}{sin100}\) ≈ 6.6 ( to the nearest tenth )

Answer:

x = 8

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