The functions g and h, have values for the inverse functions g⁻¹(9) = 1 and h⁻¹(-1) = -1. The composite function (h o h⁻¹)(-1) is equal to -1.
What is Inverse of a functionA function is said to have an inverse if it is both one-to-one and onto
for the function g using y = mx + c, when x = 1 and y = 9
m = 8/5 and c = 37/5
g(x) = (8/5)x + 37/5
g⁻¹(x) = (5x - 37)/8
g⁻¹(9) = [5(9) - 37]/8
g⁻¹(9) = (45 - 37)/8
g⁻¹(9) = 8/8
g⁻¹(9) = 1
for the function h(x) = -3x - 4, the inverse;
h⁻¹(x) = -(x + 4)/3
h⁻¹(-1) = -(-1 + 4)/3
h⁻¹(-1) = -3/3 = -1
(h o h⁻¹)(-1) = -[3(-1)] - 4
(h o h⁻¹)(-1) = -(-3) - 4
(h o h⁻¹)(-1) = 3 - 4
(h o h⁻¹)(-1) = -1.
Therefore, for the functions g and h, the values for the inverse functions g⁻¹(9) = 1 and h⁻¹(-1) = -1. The composite function (h o h⁻¹)(-1) is equal to -1.
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What is the sum? Enter your answer as a mixed number in the simplest form.
HELLPPPPPPPPPPP
1/3+ 5 3/4
How do you identify ordered pairs that are solutions to the inequalities?
Options B, C and D will satisfy the given inequality by putting the values in the given inequality.
let's first try to understand what are inequalities.
An inequality in algebra is a mathematical statement that employs the inequality symbol to show how two expressions relate to one another. The phrases on either side of an inequality symbol are not equal. The phrase on the left should be larger or smaller than the expression on the right, or vice versa, according to this symbol. Relationships between two algebraic expressions that are represented by inequality symbols are referred to as literal inequalities.
If the symbols ">,"< ">=," "<=," are used to connect two real numbers or algebraic expressions, that relationship is referred to as an inequality.
We put Given values in inequality and then see whether inequality is true or not.
Inequality is 3x+y < = 6
first x = 4 y =3
3x+y <= 6
3*4 + 3 <= 6
15 <= 6 this is not true because 15 is greater than 6.
second x = -2 y =4
3x+y <= 6
3*-2 + 4 <= 6
-2 <= 6 this is true because -2 is less than 6.
third x = -5, y =-3
3x+y <= 6
3*-5 + -3 <= 6
-15 <= 6 this is true because -15 is less than 6.
fourth x = 3, y = -3
3x+y <= 6
3*3 - 3 <= 6
6 <= 6 this is true because 6 is equal to 6.
Given Question is incomplete Complete the Question here:
How do you determine ordered pairs are part of the solution set of inequalities ex: #3x+y<=6#
for A(4,3), B(-2,4), C(-5,-3), D(3,-3)?
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Robin has a certain number of dimes in his pocket. If the dimes were pennies, he would have $1.08 less than he has now. How many dimes does he have in his pocket?
Answer:
Robin will have 12 dimes in his pocket.
Step-by-step explanation:
Since;
D = One dime = $0.1
P = One penny = $0.01
Amount to have less = $1.08
From the above, when a dime is changed to a penny, the amount held by Robin will decrease by $0.09. That is,
Decease in holding = D - P = $0.1 - $0.01 = $0.09
Therefore, we have:
Number of dimes = Amount to have less / Decease in holding = $1.08 / $0.09 = 12 dimes
Therefore, Robin will have 12 dimes in his pocket.
Students are going to conduct an experiment to study the effect of a net force applied to an object on the object’s motion. In each trial of the experiment, the students will apply a net force on the object. They also need to take two other measurements. What are the other quantities they should measure in each trial of the experiment?.
For conducting experiment based on effect of a net force , to apply net force on the object two other quantities should be measured in each trial of the experiment is given by velocity and time.
As given in the question,
To conduct a experiment based on the effect of net force applied to an object the dependable quantities are as follow:
Force = mass × acceleration
As object remain same ⇒ mass is constant as object remain same.
And there is change in the acceleration.
Acceleration depends change in velocity over total time taken.
Acceleration depends on velocity and time.
Net force also depends on velocity and time.
Two measurements need to know while conducting trail experiments are velocity and time.
Therefore, to conduct experiment based on effect of a net force , to apply net force on the object two other quantities should be measured in each trial of the experiment is given by velocity and time.
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Use the function below (whose parameters qualify it as a STC function) to answer the questions.
"STC "=" 6 "+"9 Q - 3" "Q" ^2 +" (1/3)" "Q" ^3
a) Total fixed cost is $_________
b) Obtain the AFC function from (a) and write it here __________________
c) Obtain the AVC function contained in the STC function and write the AVC function here _________________________
d) Write here the MC function __________________________
e) Find the value which AFC approaches as Q gets very large. Also write a sentence or two explaining what this implies for fixed costs per unit (AFC) as production quantities get ever larger.
f) Find the value of Q at which AVC is a minimum.
g) Is productive efficiency at the value in (f) greatest or least?
h) Demonstrate that the value of SMC equals the value of AVC at the value of Q where AVC is a minimum. Hint: The level of Q you found in (f) is where AVC is a minimum. If you plug this level of Q into AVC (see c) and also into MC (see d) the two outcomes should be the same if SMC crosses AVC at this level of Q.
i) Why does the derivative of Short Run Total Cost (STC) equal the derivative of Total Variable Cost (TVC)? Stated another way, why does dSTC/dQ = dTVC/dQ? Explain in a couple of sentences.
j. Find the value of Q where increasing returns ceases and diminishing returns begins. Hint: Diminishing returns begins at the level of Q where MC is a minimum
Total fixed cost is $6. The value of AFC is $6 / Q. Productive efficiency is greatest at Q = 4.5. Diminishing returns begin when Q = 3. The total fixed cost (TFC) does not change because it is fixed.
a) Total fixed cost is $6
b) We can obtain the average fixed cost function (AFC) from the total fixed cost (TFC) by dividing it by output (Q) as follows: AFC = TFC / Q. So, the value of AFC is $6 / Q.
c) The AVC function is calculated by dividing total variable cost (TVC) by output (Q).
STC = TFC + TVC6 + 9Q - 3Q2 + (1/3)Q3TVC = 9Q - 3Q2 + (1/3)Q3AVC = TVC / QAVC = (9Q - 3Q2 + (1/3)Q3) / QAVC = 9 - 3Q + (1/3)Q2
d) The MC function is derived by taking the first derivative of the STC function with respect to output (Q). The derivative of the STC function is: MC = dSTC / dQMC = 9 - 6Q + Q2
e) As Q approaches infinity, the denominator of AFC becomes larger and larger. So, AFC approaches zero as Q gets very large. This implies that fixed costs per unit decrease as production quantities get larger.
f) We can find the value of Q at which AVC is a minimum by taking the first derivative of the AVC function and setting it equal to zero. The first derivative of AVC is: AVC = 9 - 3Q + (1/3)Q2
dAVC / dQ = -3 + (2/3)Q= 0
Q = 4.5
g) Productive efficiency is greatest when AVC is at its minimum. Therefore, productive efficiency is greatest at Q = 4.5.
h) We can demonstrate that the value of SMC equals the value of AVC at the value of Q where AVC is a minimum by plugging Q = 4.5 into both the AVC and MC functions. AVC = 9 - 3(4.5) + (1/3)(4.5)2AVC = 7.125MC = 9 - 6(4.5) + 4.52MC = 7.125
Since SMC = MC, we can conclude that SMC equals AVC at the value of Q where AVC is a minimum.
i) In the short run, the total fixed cost (TFC) does not change because it is fixed. Therefore, the derivative of the STC function with respect to output (Q) is equal to the derivative of the TVC function with respect to output (Q). This means that dSTC / dQ = dTVC / dQ.
j) Increasing returns to scale cease when the marginal cost (MC) is equal to average total cost (ATC). Diminishing returns to scale begins when MC exceeds ATC. ATC is calculated by dividing the total cost (TC) by output (Q). TC is calculated by adding total fixed cost (TFC) and total variable cost (TVC).
ATC = TC / QATC = (6 + 9Q - 3Q2 + (1/3)Q3) / Q
Now, we can find the level of Q where increasing returns to scale cease by calculating the first derivative of ATC and setting it equal to zero.
ATC = (6 + 9Q - 3Q2 + (1/3)Q3) / QdATC / dQ = (6 - 6Q + Q2) / Q2= 0
Q = 3
Now, we can calculate the marginal cost function and find the level of Q where diminishing returns begins. We know that diminishing returns begin where the marginal cost is at its minimum.
MC = 9 - 6Q + Q2MC = 9 - 6(3) + 32MC = 3
So, diminishing returns begin when Q = 3.
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4x=3x+5 need help with this problem!
Answer:
its isssssssss x=5
Step-by-step explanation:
.......
Answer:
it's 5
Subtract
3
3x
3x
from both sides of the equation
4
=
3
+
5
4x=3x+5
4x=3x+5
4
−
3
=
3
combine the like terms 4
−
3
=
3
+
5
−
3
}{-3x}}=3x+5-3x
4x−3x=3x+5−3x
1
=
3
+
5
−
3
+
5
−
3
Point f has coordinates (6,4) and lies on line FD, which has a slope 1/7. Determine the equation of line FD in slope-intercept form
The equation of line FD in slope-intercept form is y = (1/7)x + 22/7
Firstly, let's recall the slope-intercept form of the equation of a line:
y = mx + b
where m is the slope of the line and b is the y-intercept. To find the equation of line FD, we need to determine the value of b. We can do this by substituting the coordinates of the given point (6,4) and the slope (1/7) into the slope-intercept form and solving for b.
Using the point-slope form of the equation of a line:
y - y1 = m(x - x1)
where (x1, y1) are the coordinates of the given point, we can substitute x1 = 6, y1 = 4, and m = 1/7 to get:
y - 4 = (1/7)(x - 6)
Simplifying, we can distribute 1/7 to x - 6 to get:
y - 4 = (1/7)x - 6/7
Adding 4 to both sides, we get:
y = (1/7)x + 22/7
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Omar bought a pastry from the bakery near his apartment. The pastry was $2.80, and he paid 5% sales tax. How much did Omar pay in all?
Answer:2.94
Step-by-step explanation:2.80*1.05=2.94
if similarity can be proved for the triangles shown below, which method would be used? a sas~ b similarity can not be proved c sss~ d aa~
To determine which method can be used to prove the similarity of the given triangles, use SAS, SSS, and AA.
To determine which method can be used to prove the similarity of the given triangles, let's briefly discuss each method:
a) SAS~ (Side-Angle-Side Similarity): If two sides of a triangle are proportional to two sides of another triangle, and their included angles are congruent, then the triangles are similar.
b) SSS~ (Side-Side-Side Similarity): If all three sides of a triangle are proportional to the corresponding sides of another triangle, then the triangles are similar.
c) AA~ (Angle-Angle Similarity): If two angles of a triangle are congruent to two angles of another triangle, then the triangles are similar.
Unfortunately, I cannot see the given triangles in your question, but based on the provided information, you can use these explanations to determine which method (SAS~, SSS~, or AA~) can be used to prove their similarity. If none of these methods apply, then similarity cannot be proved for the triangles.
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the geometric shape of a smooth up-and-down motion that represents a periodic oscillation like tides is a
The geometric shape that represents a smooth up-and-down motion of a periodic oscillation like tides is a sine wave. A sine wave is a smooth, continuous curve that repeats itself in a regular and periodic manner.
The geometric shape of a smooth up-and-down motion that represents a periodic oscillation like tides is a sinusoidal curve or a wave. More specifically, it can be described as a sine wave.
A sine wave is a smooth, continuous curve that repeats itself in a regular and periodic manner. It is characterized by its oscillating pattern, where it alternates between positive and negative values as it moves along the x-axis. The shape of the sine wave resembles the rising and falling motion of tides, making it an appropriate geometric representation.
In the context of tides, the sine wave represents the periodic variations in the water level caused by the gravitational pull of the Moon and the Sun. As the tide rises and falls, the water level follows a smooth, up-and-down motion similar to the shape of a sine wave.
By using mathematical functions and trigonometry, the behavior of tides and other periodic oscillations can be accurately modeled and represented by sinusoidal curves, allowing us to study and predict their patterns and behaviors.
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which shapes have 2 obtuse angles
Answer: Trapezoid
Step-by-step explanation:
Answer:
Step-by-step explanation:
Trapezoid square and the down right all the way
Give an example of a function with a domain of (-∞,0).
Answer:
The one to the right
Step-by-step explanation:
Jamie has a restaurant bill of $70.70. About how much money should she leave for a 10% tip?
Answer:
tip shold be 7.07
Step-by-step explanation:
70.70 x .10
Answer:
$77.77
Step-by-step explanation:
Given:
$70.70
10% tip
let x = total amount she needs to pay
x = $70.70 + (10%)($70.70)
x = $70.70 + $7.07
x = $77.77
16]
Use the two-way frequency table to complete the row relative frequency table. Drag the numbers into the boxes.
Sandwich Pasta
Volleyball
19
15
Swimming 26
10
Total
45
25
28 36 64
Lunch Order
Volleyball
Sport Swimming
Total
72 100
Sandwich
56%
%
%
Total
34
36
70
Lunch Order
Pasta
44%
%6
196
Total
100%
100%
The relative frequency is solved and the table of values is plotted
Given data ,
The lunch order is given by the 2 sets of dishes as
A = { Sandwich , Pastas }
Now , the sports activities are given by 2 sets as
B = { Volleyball , Swimming }
From the table of values , we get
The relative frequency is solved as
Relative Frequency = Subgroup frequency / Total frequency
The percentage of Swimming ( sandwich ) = 26/36
Swimming ( sandwich ) = 72 %
And , the percentage of Swimming ( pasta ) = 10/36
Swimming ( pasta ) = 28 %
Now , the percentage of total sandwich = 45/70 = 64 %
And , the percentage of total pasta = 25/70 = 36 %
Hence , the relative frequency is solved
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Tekan-Tekan Sdn. Bhd. has order for 200 Model AS-120 calculator for delivery on day 200. The calculator consists of three parts. Components 2 and 3 form subassembly 1 . Sub-assembly 1 and component 4 form the final assembly. Following are the work centers and times of each operation. Table Q3(a) shows routine file of the operation. Assuming: - Only one machine is assigned to each operation - The factory works on 8-hour shift, 5 days a week - All parts move in one lot of 200. (a) Illustrate the backward schedule based on the information given above. (12 marks) (b) Identify when component 3 must be started to meet the delivery date. (2 marks)
Component 3 must be started on day 197 to meet the delivery date of day 200.
To illustrate the backward schedule, we need to start from the delivery date (day 200) and work our way backward, taking into account the lead times and dependencies of each operation.
(a) Backward schedule:
Operation | Work Center | Time (hours) | Start Day
--------------------------------------------------------
Final Assembly | Work Center 1 | 1 | 200
Sub-assembly 1 | Work Center 2 | 2 | 199
Component 4 | Work Center 3 | 3 | 197
Component 2 | Work Center 4 | 4 | 196
Component 3 | Work Center 5 | 3 | ????
(b) To identify when component 3 must be started to meet the delivery date, we need to consider its dependencies and lead times.
From the backward schedule, we see that component 3 is required for sub-assembly 1, which is scheduled to start on day 199. The time required for sub-assembly 1 is 2 hours, which means it should be completed by the end of day 199.
Since component 3 is needed for sub-assembly 1, we can conclude that component 3 must be started at least 2 hours before the start of sub-assembly 1. Therefore, component 3 should be started on day 199 - 2 = 197 to ensure it is completed and ready for sub-assembly 1.
Hence, component 3 must be started on day 197 to meet the delivery date of day 200.
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which angle in ABC has the largest measure
Step-by-step explanation:
In a triangle, angle opposite to the largest side has largest measure.
Here in the question, measure of the sides are not given, hence we can't determine which angle has the largest measure.
when determining the size of a fact table, estimating the number of possible values for each dimension associated with the fact table is equivalent to:
When determining the size of a fact table, estimating the number of possible values for each dimension associated with the fact table is equivalent to: determining the number of possible values for each foreign key in the fact table.
The measures, metrics, or facts of a business process are contained in a fact table in data warehousing. In a star or snowflake schema, it sits in the middle, surrounded by dimension tables.
When several fact tables are employed, they are organized according to a fact constellation schema. The two types of columns that make up a fact table are typically those that hold facts and those that serve as a foreign key to dimension tables.
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Consider a simple linear regression model Y = Bo + B₁X₁ + u As sample size increases, the standard error for the regression coefficient decreases. True O False
True. As the sample size increases, the standard error for the regression coefficient decreases, providing more precise estimates.
True. As the sample size increases, the standard error for the regression coefficient decreases. With a larger sample size, there is more information available, leading to a more precise estimation of the true coefficient.
The standard error measures the variability of the estimated coefficient, and it decreases as the sample size increases because there is a larger amount of data points to estimate the relationship between the variables accurately. A smaller standard error indicates a more reliable and precise estimate of the regression coefficient.
Therefore, as the sample size increases, the standard error decreases, providing more confidence in the estimated coefficient.
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Refer to Table \( \$ 6.1 \)-Factors for Computing Control Chart Limits \( (\underline{3} \) sigma) for this problem. Thirty-five samples of size 7 each were taken from a fertilizer-bag-filling machine
The control chart limits (3 sigma) for the fertilizer-bag-filling machine can be computed using Table $6.1.
How can the control chart limits be computed using Table $6.1 for the given problem?To compute the control chart limits (3 sigma) using Table $6.1 for the fertilizer-bag-filling machine, follow these steps:
Determine the sample size: In this problem, each sample consists of 7 observations.
Calculate the average range (R): For each sample, calculate the range by subtracting the smallest observation from the largest observation. Then, calculate the average range across all 35 samples.
Find the appropriate value from Table $6.1: Locate the row in Table $6.1 corresponding to the sample size (7) and find the factor associated with 3 sigma. This factor represents the number of standard deviations for the control limits.
Compute the control limits: Multiply the average range (R) by the factor obtained from Table $6.1 to determine the width of the control limits. Then, subtract this width from the overall average of the process data to obtain the lower control limit, and add the width to the overall average to obtain the upper control limit.
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72 divided 12 x 5 - 3 (4 to third power divided by 5)
Answer:
1536/95
Step-by-step explanation:
HOW MANY SIDES DOES A TRIANGLE HAVE!!! HELP IM DOING A TEST!!!!
Answer:
Three
Step-by-step explanation:
A triangle has three sides and three corners hence the name TRI-angle
Step-by-step explanation:
a triangle has 3 sides. just count the sides and it's 3
6x + 18 = 90 help me plz
Answer:
x = 12
Step-by-step explanation:
Combine like terms on both sides of the equation and simplify, isolating the variable on to one side of the equation:
6x + 18 = 90
6x = 72
x = 12
Alguien me puede ayudar
Step-by-step explanation:
a. 1
_
8
b. 1
_
7
c. 10
_
21
espero que isso te ajude
Vamos a resolver las operaciones utilizando la regla de multiplicación de fracciones y luego simplificaremos los resultados.
a) \(\sf\:\frac{1}{6} \times \frac{3}{4}\\\)
Para multiplicar estas fracciones, multiplicamos los numeradores entre sí y los denominadores entre sí:
Numerador: \(\sf\:1 \times 3 = 3\\\)
Denominador: \(\sf\:6 \times 4 = 24\\\)
Entonces, \(\sf\:\frac{1}{6}\:\times\:\frac{3}{4} = \frac{3}{24}\\\)
Podemos simplificar esta fracción dividiendo tanto el numerador como el denominador por el máximo común divisor, que en este caso es 3:
\(\sf\:\frac{3}{24} = \frac{3 \div 3}{24 \div 3} = \frac{1}{8}\\\)
Por lo tanto, el resultado simplificado es \(\sf\:\frac{1}{8}\\\).
b) \(\sf\:\frac{1}{2} \times \frac{2}{7}\\\)
Aplicando la regla de multiplicación de fracciones:
Numerador: \(\sf\:1 \times 2 = 2\\\)
Denominador: \(\sf\:2 \times 7 = 14\\\)
Entonces, \(\sf\:\frac{1}{2} \times \frac{2}{7} = \frac{2}{14}\\\)
Podemos simplificar esta fracción dividiendo tanto el numerador como el denominador por el máximo común divisor, que en este caso es 2:
\(\sf\:\frac{2}{14} = \frac{2 \div 2}{14 \div 2} = \frac{1}{7}\\\)
Por lo tanto, el resultado simplificado es \(\sf\:\frac{1}{7}\\\).
c) \(\sf\:\frac{4}{7} \times \frac{5}{6}\\\)
Siguiendo la regla de multiplicación de fracciones:
Numerador: \(\sf\:4 \times 5 = 20\\\)
Denominador: \(\sf\:7 \times 6 = 42\\\)
Entonces, \(\sf\:\frac{4}{7} \times \frac{5}{6} = \frac{20}{42}\\\)
Podemos simplificar esta fracción dividiendo tanto el numerador como el denominador por el máximo común divisor, que en este caso es 2:
\(\sf\:\frac{20}{42} = \frac{20 \div 2}{42 \div 2} = \frac{10}{21}\\\)
No podemos simplificar aún más esta fracción, por lo que el resultado simplificado es \(\sf\:\frac{10}{21}\\\).
Resumiendo las respuestas:
a) \(\sf\:\frac{1}{6} \times \frac{3}{4} = \frac{1}{8}\\\)
b) \(\sf\:\frac{1}{2} \times \frac{2}{7} = \frac{1}{7}\\\)
c) \(\sf\:\frac{4}{7} \times \frac{5}{6} = \frac{10}{21}\\\)
Sarah and her 4 friends share some cookies. If each person gets 3 cookies, how many cookies were shared? Write a mathematical equation that represents this situation.
Equation:
3 x 5 = 15
15 cookies is the answer.
Sarah and her 4 friends are 5 people in total.
They are each getting 3 cookies.
You are adding three cookies for each friend. That is the same as multiplying 5 times.
Answer:
Step-by-step explanation:
c/5. = 3
5c = 3
c/4. = 3
4c = 3
Which equation represents a proportional relationship?
A) y =
1
2
x
B) y =
1
2
x + 1
C) y =
1
2
x + 2
D) y =
1
2
x +
1
2
Answer:
A
Step-by-step explanation:
1. Find an equation of the line that satisfies the given conditions.
Through (−5, 2); perpendicular to the line y = − 1/2x + 4
2. Find an equation of the line that satisfies the given conditions.
y-intercept 3; parallel to the line 3x + 4y + 2 = 0
3. Find an equation of the line that satisfies the given conditions.
Through (−5, −13); perpendicular to the line passing through (−2, −1) and (2, −3)
Through (−5, 2); perpendicular to the line y = − 1/2x + 4 will be ⇒ y = 2x + 12 ⇒ y= 2x -3
1. y= - 1/2 x + 4
passes through (-5.2)
line perpendicular to given line
⇒ (slope of given line) * (slope of newline) = -1
(- 1/2) * (m) = -1
∴ m =2
equation of line passing through (-5 , 2) having slope m = 2 is
y- \(y_{1}\) = slope (\(x-x_{1}\))
y-2 = 2(x-(-5))
y-2 = 2(x=5)
y-2 = 2x + 10
∴ y = 2x + 12
2. parallel to line : 3x + 4y +2=0
⇒ slope = -3/4
4y = -3x -2
∴ y= -3/4x -1/2
y-intercept = 3
since equation of line having slope & y-intercept is, y =mx+c
slope = -3/4 ; y-intercept = 3
y=mx+c
y=-3/4x+3
4y = -3x + 12
∴ 3x =4y = 12
3. line passing through : (-5, -13) & perpendicular to line passes through (-2, -1) & (2, -3)
∴ slope of perpendicular line = \(y_{2} - y_{1} / x_{2} -x_{1}\)
= -3 - (-1)/ 2 - (-2) = -3 + 1/4 = -2/4 = -1/2
y- (-13)= 2(x -(-5))
y+13 = 2x + 10
⇒ y= 2x -3
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ppppppllllllssss hhhhheeeeellllppppp
Answer: 10^-5 = 1/10^5
Step-by-step explanation: Every time you see a negative exponent, it would be 1/10^ (exponent number)
\(\huge\text{Hey there!}\)
\(\mathsf{10^{-5}}\\\\\mathsf{= \dfrac{1}{10\times10\times10\times10\times10}}\\\\\mathsf{= \dfrac{1}{100\times100\times10}}\\\\\mathsf{= \dfrac{1}{10,000\times10}}\\\\\mathsf{= \dfrac{1}{100,000}}\\\\\mathsf{= \dfrac{1}{10^5}}\)
\(\huge\text{Thus, your answer should be: \boxed{\mathsf{\dfrac{1}{10^5}}}}}\huge\checkmark\)
\(\huge\text{Good luck on your assignment \& enjoy your day!}\)
~\(\frak{Amphitrite1040:)}\)
four percent of the customers of a mortgage company default on their payments. a sample of 20 customers is selected. what is the probability that exactly two customers in the sample will default on their payments?
Using the Binomial probability distribution,
The probability that exactly two customers in the sample will default on their payments is 0.31..
We have given that,
4% of total customers a mortgage company default on their payments .
The probability of success i.e number of customers default on their payments (p) = 4%
= 0.04
The probability of failure (q) = 1-p = 1-0.04 = 0.06
Total number of customers in sample (n) = 20
we have to find out the probability that exactly two customers in the sample will default on their payments.
Using the Binomial probability distribution,
P(X=x)= ⁿCₓ(p)ˣ(q)⁽ⁿ⁻ˣ⁾
the required probability is P(X= 2 )
Now, P(X= 2) = ²⁰C₂(0.04)²(0.06)¹⁸
=> P(X=2) = 190 × 0.0016 × 1.0155 = 0.31
Hence, the required probability is 0.31
To learn more about Binomial probability distribution, refer:
https://brainly.com/question/24239758
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10. Which of the following situations represents a proportional relationship?....
F. A pizza is $7.95 plus $1.00 for each additional topping.
G. A pool fills at a rate of 90 gallons per hour.
H. A health club charges a $40.00 membership fee plus $25.00 per month.
J. A bank account begins with $350.00 and gains $30.00 per month.
Answer:
G A pool fills at a rate of 90 gallons per hour
Step-by-step explanation:
i dont know
336,765=3,14×0.55×(l+0.55) please help
Answer:
l = 194999.45
Step-by-step explanation:
I'm going to assume that you meant 3.14 by 3,14.
336,765 = 3.14 × 0.55 × (l + 0.55)
336,765 ÷ (3.14 × 0.55) = l + 0.55
(336,765 ÷ (3.14 × 0.55)) - 0.55 = l
l = 194999.45