Item 8
School administrators need to revise the emergency exit routes because construction at the school will block one exit for several weeks. They use a floor plan of the school to model the exit route from each room of the school. What is the next step in the process? Choose the correct answer.


Design and test solutions.

Optimize design solutions.

Define and delimit the problem.

Implement and communicate results.

Answer:

.079 moles of Nirogen gas (N2)

Explanation:

You can see from the equaton that each ONE mole of N2 produces TWO moles of NH3.

 Find the number of moles of NH3 produced.

    Using Periodic Table : Mole wt of NH3 = 17 gm/mole

          2.7 gm / 17 gm/mole = .1588 moles

      One half as many moles of N2 are needed  = .079 moles

The mass (in grams) of aluminum hydroxide produced when 4.46 g of sodium hydroxide reacts is 2.90 grams

First, we shall obtain the balanced equation for the reaction. This is given below

3NaOH + Al → 3Na + Al(OH)₃

From the balanced equation above,

120 g of NaOH reacted to produce 78 g Al(OH)₃

With the above information, we shall determine the mass of Al(OH)₃ produced from 4.46 grams of NaOH. Details below:

From the balanced equation above,

120 g of NaOH reacted to produce 78 g Al(OH)₃

Therefore,

4.46 g of NaOH will react to produce = (4.46 × 78) / 120 = 2.90 g of Al(OH)₃

Thus, the mass of aluminum hydroxide, Al(OH)₃ produced is 2.90 g

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Answer:

Use Boyles law.

Given:

P1=3atm

V1=275mL

P2=1.8atm

V2=?

P1V1=P2V2

3x275=1.8xV2

V2=3x275/1.8

V2=458.3mL

Answer:

MRCORRECT has answered the question

Explanation:

13 electrons

So... for the element of ALUMINUM, you already know that the atomic number tells you the number of electrons. That means there are 13 electrons in a aluminum atom. you can see there are two electrons in shell one, eight in shell two, and three in shell three.

7 electrons

So... for the element of NITROGEN, you already know that the atomic number tells you the number of electrons. That means there are 7 electrons in a nitrogen atom. Looking at the picture, you can see there are two electrons in shell one and five in shell two.

The percent yield of the reaction with formation of lead oxide  is 70.29%.

Percent yield is defined as the ratio of actual yield to the theoretical yield multiplied by 100. If the actual and theoretical yield are same then the percent yield is 100%.If actual yield is less than the theoretical yield then the percent yield is less than 100%.Reason of this condition arising is the incompletion of reaction or loss of sample during recovery process.

In cases where percent yield is over 100% it indicates that more sample is recovered than the predicted amount.This condition arises when there are other simultaneous reactions taking place leading to the formation of product. It can also arise if there is incomplete removal of impurities from the sample .

In the given problem, 2 moles of lead produce 2 moles of lead oxide

That is, 414.4 g lead produces 446.4 g of lead oxide

hence,451.54 g lead will produce 451.4×446.4/414.4=486.251 g which is the theoretical yield

Now by substituting the values in the formula,341.8/486.251 ×100=70.29%

Hence, the percent yield of the reaction is 70.29%.

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Fuel-efficient cars help decrease the global dependency on nonrenewable resources because they use less fuel than other vehicles to travel the same distance.

Nonrenewable resources are natural resources that cannot be readily replaced or regenerated, such as fossil fuels (coal, oil, and natural gas), minerals, and some metals. These resources are finite and once they are used they cannot be replenished. They are formed over millions of years and are essential for the functioning of modern society, but their extraction and use can have negative impacts on the environment.

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The balanced chemical equation for the reaction of calcium chloride (CaCl₂) with a fatty acid (R-COOH) to form soap (R-COONa) and carbon dioxide (CO₂) is:

CaCl₂ + 2 R-COOH → R-COONa + CO₂ + 2 HCl

In this reaction, calcium chloride (CaCl₂) reacts with a fatty acid (R-COOH), which is the structure of a typical soap molecule, to form soap (R-COONa) and carbon dioxide (CO₂) as products. The balanced equation is obtained by ensuring that the number of atoms of each element is the same on both sides of the equation.

To balance the equation, the coefficients of the reactants and products are adjusted. In this case, two molecules of the fatty acid are required to react with one molecule of calcium chloride to form two molecules of soap, one molecule of carbon dioxide, and two molecules of hydrochloric acid (HCl) as a byproduct.

The balanced equation represents a stoichiometric ratio between the reactants and products in the chemical reaction.

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Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\(n = \frac{N}{L} \\\)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

\(n = \frac{2.997 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 49.784053\)

We have the final answer as

Hope this helps you

The concept molarity is an important method which is used to calculate the concentration of a solution. Here molarity - volume relation is used to find out the concentration of the sodium hydroxide solution.

The term molarity is defined as the number of moles of the solute present per lite of the solution. It is represented as 'M' and it is expressed in the unit mol / L.

The equation connecting molarity and volume is:

M₁V₁ = M₂V₂

M₂ = M₁V₁ / V₂

0.1 × 25 / 20 = 0.125 cm³

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To calculate the required volume of nitric acid, we need to know the mass of the substance required. Let's assume that we need 1 mole of nitric acid. In that case, the mass required would be 63.01 g.

Now, we can use the density of nitric acid to calculate the volume required:

Density of nitric acid = 1.5129 g/mL

Volume of nitric acid = Mass of nitric acid / Density of nitric acid

Volume of nitric acid = 63.01 g / 1.5129 g/mL

Volume of nitric acid = 41.68 mL (rounded to two decimal places)

Therefore, 41.68 mL of nitric acid is required for 1 mole of the substance. If a different amount of nitric acid is required, you can adjust the calculation accordingly.

Answer:

Take the measuring cylinder and measure its mass, in grams, as accurately as possible. Take the measuring cylinder off the balance and add the water carefully. Put the measuring cylinder back on the balance. Measure and record the new mass . Repeat the procedure,  recording the volume and total mass, until the measuring cylinder is full. Then, for each volume calculate the mass of the liquid alone.Repeat steps 1 to 3  Draw a graph of mass of liquid against volume .  Calculate the density of each liquid from the gradient of its graph line.

Explanation:

The index of refraction of water decreases as you move from red toward violet.

The index of refraction of a medium refers to how much a light ray is bent when passing through the medium. In the case of water, the index of refraction decreases as the wavelength of the light decreases (i.e., as you move from red toward violet). This is because violet light has a shorter wavelength than red light, and shorter wavelengths are more strongly refracted than longer wavelengths. Therefore, as you move from red toward violet, the index of refraction of water decreases.

In summary, the index of refraction of water decreases as you move from red toward violet due to the stronger refraction of shorter wavelengths.

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Answer:

the answer is seventeen

Explanation:

any zero coming last after any decimal point is not recognized as a number hence .0030 is equivalent .003 therefore there is only one significant figures in the number .0030

a. 1

Answer:

11.01

Explanation:

took the assignment on edge

Answer: fixed shape and volume

Explanation:

i took the quiz so its right

Answer:

c) 12

Explanation:

electron = 23-11 = 12

Answer:

D- 11

Explanation:

I know cause thats what the test said. Not sure how to do this stuff we will never use thats why im on brainly.

Answer: 3.012x10^24

Explanation:

1.004x10^23 atoms are in 1 mL of water.

multiply 1.004x10^23 by 30

∆EN for silicon and tellurium is 0.2, indicating moderately polar covalent bond; higher ∆EN means more polar bond.

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Answer:

We in daily life use technology to pay virtually through virtual wallets, work at home, purchase packages to travel abroad, many businesses handle virtual advertising, that is why it is called the new "market window" to social networks or internet pages, university universities playful methods through virtual campuses or virtual classes.

The serious impact is very great since many of the activities of daily life change, and they will return to being as before the technology affected in our lives, reversing customs and technological generations.

The new technologies are: computer science, engineering, arquetectonica, scientific, industrial, commercial ... Where a fourth industrial revolution arises where many processes that were carried out by humans today would be automated by computers or technological devices that improve market efficiency, of consumption and industrialization.

Explanation:

In addition, new technologies are those that are based on electronic devices that are based on social communication, the development of social networks and technology based on global communications.

The diphenoxylate with atropine sulfate resolves diarrhea by reducing gastrointestinal motility. It acts as an opioid agonist, binding to receptors in the intestines to slow down movement and decrease bowel frequency.

Atropine sulfate is added to discourage abuse.

The combination medication prolongs stool transit time, allowing for increased water and electrolyte absorption, resulting in firmer stools and reduced frequency of bowel movements.

By targeting the underlying excessive motility, diphenoxylate with atropine sulfate helps alleviate diarrhea symptoms.

It is important to use this medication as directed and consult a healthcare professional for proper diagnosis and treatment guidance.

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Answer:

NH3 is the molecular formula of ammonia

Explanation:

i hope this will help you :)

Answer:

La distancia recorrida por el móvil es 228.600 m

Explanation:

El movimiento rectilíneo uniforme MRU es el movimiento que describe un cuerpo o partícula a través de una línea recta a velocidad constante. Es decir:, en este caso el movimiento es lineal en una única dirección  y la velocidad de desplazamiento es constante.

La velocidad es una magnitud física que expresa la relación entre el espacio recorrido por un objeto y el tiempo empleado para ello mediante la expresión:

\(velocidad=\frac{distancia}{tiempo}\)

En este caso:

Reemplazando:

\(25 \frac{m}{s} =\frac{distancia}{9144 s}\)

y resolviendo obtienes:

distancia= 25\(\frac{m}{s}\) *9144 s

distancia= 228.600 m

La distancia recorrida por el móvil es 228.600 m

A movement is rectilinear uniform when an "object" (for example) travels in a straight path at a constant speed, given that its acceleration is zero.

Velocity (v) = 25m/s

Distance (d) = ?

Time (t) = 2.54hr = 9,144 s

Looking at the data, we see that the time is in hr, but we need it in seconds. Therefore we do a conversion from hours to minutes, taking into account that 1 hour is equal to 3600 seconds.

To calculate the distance traveled by the mobile, the speed is multiplied by the time taken.

For this the following formula is applied:

We apply the data in the formula; to solve for the distance.

Answer: The distance traveled by the mobile is 228,600 meters.

The change in pH resulting from the addition of 0.30 liters of 0.020 M KOH to the solution containing 0.25 M HF and 0.78 M NaF is approximately -0.614.

First, we need to determine the initial concentrations of HF and F⁻ in the 1.0-liter solution. The concentration of HF is given as 0.25 M, and the concentration of NaF can be used to determine the concentration of F⁻ since NaF is a strong electrolyte and will fully dissociate in solution. Therefore, the concentration of F⁻ is 0.78 M.

Next, we need to consider the reaction between KOH and HF:

KOH + HF ⟶ H2O + KF

The reaction between KOH and HF is a neutralization reaction. For every 1 mole of KOH added, 1 mole of HF will react to form 1 mole of water and 1 mole of KF. Since we know the initial volume of KOH added is 0.30 liters and the concentration of KOH is 0.020 M, we can calculate the number of moles of KOH added:

moles of KOH = volume × concentration = 0.30 L × 0.020 M = 0.006 moles

Therefore, 0.006 moles of HF will react with 0.006 moles of KOH, resulting in the formation of 0.006 moles of water and 0.006 moles of KF.

Now, we can calculate the new concentrations of HF and F⁻. The initial concentration of HF was 0.25 M, and we subtract 0.006 moles from it, which corresponds to the moles of HF that reacted with KOH. The volume of the solution is still 1.0 liter. Thus, the new concentration of HF is:

new concentration of HF = (0.25 moles - 0.006 moles) / 1.0 L = 0.244 M

For F⁻, the initial concentration was 0.78 M, and we add 0.006 moles to it, which corresponds to the moles of F⁻ formed from the reaction. The volume of the solution is still 1.0 liter. Thus, the new concentration of F⁻ is:

new concentration of F⁻ = (0.78 moles + 0.006 moles) / 1.0 L = 0.786 M

To calculate the change in pH, we need to consider the dissociation of HF and the equilibrium expression for the acid dissociation constant (Ka):

HF + H₂O ⇌ H₃O⁺ + F⁻

The Ka expression is given by:

Ka = [H₃O⁺][F⁻] / [HF]

Since HF is a weak acid, we assume that the concentration of [H₃O⁺] is equal to the concentration of [HF]. Therefore, the expression simplifies to:

Ka = [F⁻] / [HF]

Plugging in the values:

Ka = (0.786 M) / (0.244 M)

Solving this expression gives the Ka value. Then, we can use the Ka value to calculate the pH using the equation:

pH = -log[H₃O⁺]

To calculate the numerical values, we need to determine the new concentrations of HF and F⁻ after the reaction with KOH.

Initial concentration of HF: 0.25 M

Moles of HF reacting with KOH: 0.006 moles

New concentration of HF = (0.25 moles - 0.006 moles) / 1.0 L = 0.244 M

Initial concentration of F⁻: 0.78 M

Moles of F- formed from the reaction: 0.006 moles

New concentration of F⁻ = (0.78 moles + 0.006 moles) / 1.0 L = 0.786 M

Now, we can calculate the Ka value using the concentrations of HF and F⁻:

Ka = [F⁻] / [HF] = 0.786 M / 0.244 M = 3.2131

Using the Ka value, we can calculate the pH. Since HF is a weak acid, we assume that the concentration of [H₃O⁺] is equal to the concentration of [HF]:

pH = -log[H₃O⁺] = -log[HF] = -log(0.244) ≈ 0.614

Therefore, the change in pH resulting from the addition of 0.30 liters of 0.020 M KOH to the solution containing 0.25 M HF and 0.78 M NaF is approximately -0.614.

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The empirical formula of the substance would be  \(NH_4Cl\)

The constituents of the compound are as follows:

N = 54/201.6 = 26.78% = 26.78/14 = 1.91 moles

H = 15/201.6 = 7.44% = 7.44/1 = 7.44 moles

Cl = 132.6/201.6 = 65.48% = 65.48/35.5 = 1.84 moles

Divide the number of moles by the smallest"

N = 1.91/1.84 = 1

H = 7.44/1.84 = 4

Cl = 1.84/1.84 = 1

Thus, the empirical formula is \(NH_4Cl\)

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Titration is a laboratory technique used to determine the concentration of a substance in a solution. It involves the controlled addition of one solution (known as the titrant) to another solution (the analyte) until the reaction between the two is complete. 14.7 mL of LiOH solution is required to reach the first equivalence point in the titration.

To determine the volume of base (LiOH) required to reach the first equivalence point in the titration of a diprotic acid (tartaric acid), we need to consider the stoichiometry of the reaction and the concentration of the acid.

The balanced chemical equation for the reaction between tartaric acid (H₂C₄H₄O₆) and LiOH is as follows:

H₂C₄H₄O₆ + 2LiOH → Li₂C₄H₄O₆ + 2H₂O

From the balanced equation, we can see that 1 mole of tartaric acid reacts with 2 moles of LiOH.

Given:

Volume of tartaric acid solution (H₂C₄H₄O₆) = 28.0 mL = 0.0280 L

The concentration of a tartaric acid solution (H₂C₄H₄O₆) = 0.425 M

The concentration of LiOH solution = 0.155 M

To find the volume of LiOH solution required, we can use the following equation, which relates the moles and molarity of the substances involved:

Moles of tartaric acid = Moles of LiOH

Moles of tartaric acid = (Concentration of tartaric acid) × (Volume of tartaric acid)

Moles of LiOH = (Concentration of LiOH) × (Volume of LiOH)

Since the stoichiometric ratio between tartaric acid and LiOH is 1:2, we can set up the following equation:

(Concentration of tartaric acid) × (Volume of tartaric acid) = 2 × (Concentration of LiOH) × (Volume of LiOH)

Plugging in the given values, we have:

(0.425 M) × (0.0280 L) = 2 × (0.155 M) × (Volume of LiOH)

Solving for the volume of LiOH:

Volume of LiOH = [(0.425 M) × (0.0280 L)] / [(2) × (0.155 M)]

Volume of LiOH = 0.0147 L = 14.7 mL

Therefore, 14.7 mL of LiOH solution is required to reach the first equivalence point in the titration.

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Answer:

C

Explanation:

75 mile shallow flat area just off coastlines

Answer: There is equal number of each type of atom on the reactant and product side.

Explanation:

The least likely zone of formation for a large air mass is the equator. Large air masses form due to differences in temperature and pressure between different regions.

The equator is an area where temperatures are relatively consistent throughout the year and there are not significant differences in pressure systems, making it less likely for a large air mass to form. On the other hand, areas near the poles or where there are large landmasses or bodies of water can have significant differences in temperature and pressure, making them more likely to form large air masses.

Air masses typically form in regions with consistent temperature and humidity conditions, such as polar, tropical, and continental areas. The equatorial region is less likely to form large air masses because it experiences strong solar heating, high humidity, and a lot of weather variability, which prevents the development of stable, uniform air masses.
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Answer:

Atoms consist of three basic particles: protons, electrons, and neutrons. The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge). The outermost regions of the atom are called electron shells and contain the electrons (negatively charged).

Explanation:

This is the answer bc I don't see any answer choices