Speed of Santa 's sleigh in air (X) is 6 units and the speed of the wind (Y) is 1 unit.
What is arithmetic?
Arithmetic is an elementary a part of arithmetic that consists of the study of the properties of the normal operations on numbers—addition, subtraction, multiplication, division, mathematical operation, and extraction of roots.
Main body:
Let 'y' stand for the speed of the wind and 'x' stand for the speed of Santa. We will use the general equation (distance)=(rate)(time) to write two equations from the given information:
With the wind:
35=(x+y)(5) -------(1)
Against the wind:
35=(x-y)(7) --------(2)
using equation 1 ,we have
x+y = 7
using equation 2 ,we have
x- y = 5
now solving both equations , we get
x = 6 and y = 1
Hence , speed of Santa 's sleigh in air (X) is 6 units and the speed of the wind (Y) is 1 unit.
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Write 1.625 x 1.625 using an exponent.
Answer:
1.625²
Step-by-step explanation!
1.625 x 1.625 is just 1.625 two times. So you add a 2 on the top which represents the number. You can write 1.625² instead of putting 1.625 x 1.625.
1.625 x 1.625 can be written in exponential form as \(1.625^2\)
Given :
The given expression is 1.625 x 1.625 . we need to write it in exponential form
The exponent is in the form of \(b^x\), where 'b' is the base and 'x' is the exponent
base is the number and x is the exponent that is repeating number of times
For example , \(2 \cdot 2 \cdot 2 = 2^3\)
where 2 is the base and 2 is occurring three times
so exponent is 3
1.625 x 1.625 can be written in exponential form as \(1.625^2\)
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10) Find the first term and common ratio of the Geometric sequence with a3 =54 and a4 =162
Given a3=54 and a4=162To find the first term and common ratio of the geometric sequence
We can use the formula:An = a1rn-1We know that a3 = 54 and a4 = 162To find a1 and r, we can use the below steps,a4 = a1 r^3 --(1)a3 = a1 r^2 --(2)Dividing equation (1) by equation (2),we get,162/54 = (a1r^3)/(a1r^2)r = 3Substituting r = 3 in equation (2),we get,a3 = a1 (3)^2a1 = 6So, the first term of the geometric sequence is 6 and the common ratio is 3.
To find the first term and common ratio of the geometric sequence with a3 =54 and a4 =162, we can use the formula An = a1rn-1 where An is the nth term of the sequence, a1 is the first term of the sequence and r is the common ratio of the sequence.We are given a3 = 54 and a4 = 162.
Using the formula, we get:a4 = a1r^3 and a3 = a1r^2Dividing the two equations, we get:r = 3Substituting this value in the second equation, we get:54 = a1(3)^2a1 = 6Hence, the first term of the sequence is 6 and the common ratio is 3.
Therefore, we can conclude that the first term and common ratio of the Geometric sequence with a3 = 54 and a4 = 162 are 6 and 3 respectively.
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Q1.For two observations ‘a’ and ‘b’, show that standard
deviation is half of the
distance between them.
Standard deviation is half of the distance between two observations 'a' and 'b'.
Standard deviation (SD) is a measure of the spread of the data.
The distance between the observations a and b refers to the difference between the two observations, i.e., |a-b|. It is mathematically proven that the standard deviation is half of the distance between the two observations.
Therefore, SD = 1/2 |a-b|.
Summary: To summarize, the standard deviation is half of the distance between two observations a and b, i.e., SD = 1/2 |a-b|.
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a community swim team has 150 members. seventy-five of the members are advanced swimmers. forty- seven of the members are intermediate swimmers. the remainder are novice swimmers. forty of the advanced swimmers practice four times a week. thirty of the intermediate swimmers practice four times a week. ten of the novice swimmers practice four times a week. suppose one member of the swim team is chosen randomly. a. what is the probability that the member is a novice swimmer?
If one member of the swim team is chosen randomly, the probability that the chosen member is a novice swimmer is 0.1867 or 18.67%.
To find the probability that the chosen swim team member is a novice swimmer, we need to first find out how many members of the swim team are novice swimmers.
We know that there are 150 total members on the swim team, 75 of whom are advanced swimmers and 47 of whom are intermediate swimmers. Therefore, the number of novice swimmers can be found by subtracting the number of advanced and intermediate swimmers from the total number of members:
Novice swimmers = Total members - Advanced swimmers - Intermediate swimmers
Novice swimmers = 150 - 75 - 47
Novice swimmers = 28
So, there are 28 novice swimmers on the team.
Now we can find the probability that the chosen swim team member is a novice swimmer by dividing the number of novice swimmers by the total number of members on the team:
Probability of choosing a novice swimmer = Number of novice swimmers / Total number of members
Probability of choosing a novice swimmer = 28 / 150
Probability of choosing a novice swimmer = 0.1867 or 18.67%
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Sherelle and Venita find two bags of coins in their grandmother’s attic. Each girl selects a bag, takes a random sample of 20 coins from that bag, and lists the dates of those coins as the number of years since 1900. Here are the results.
Sherelle: 72, 56, 81, 84, 75, 26, 39, 62, 65, 66, 85, 71, 74, 68, 73, 66, 83, 60, 58, 72
Venita: 45, 65, 73, 57, 79, 66, 69, 75, 51, 44, 53, 69, 58, 77, 51, 55, 53, 78, 70, 62
1. Find the five-number summary of each data set. Then construct box-and-whisker plots of the data sets. Draw both plots above the same number line. Label the plots with the girls’ names.
The five-number summary comprehends the minimum and maximum values, the 1st and 3rd quartiles and the median.
1st step: is to arrange the data sets from least to greatest.
Sherelle:
26 39 56 58 60 62 65 66 66 68 71 72 72 73 74 75 81 83 84 85
Venita:
44 45 51 51 53 53 55 57 58 62 65 66 69 69 70 73 75 77 78 79
2nd step: To calculate each quartile you have to determine their position and then identify which observation sits in that position:
Quartile 1:
PosQ₁: n/4= 20/4= 5
Quartile 2 (Median)
PosMe: n/2= 20/2= 10
Quartile 3
PosQ₃: n*(3/4)= 20*(3/4)= 15
Since both samples have the same size, the 1st quartile will be the fifth observation of each sample, the median will be the tenth observation and the 3rd quartile will be the fifteenth.
Sherelle:
Q₁: 60
Me: 68
Q₃: 74
Minimum: 26
Maximum: 85
Venita:
Q₁: 53
Me: 62
Q₃: 70
Minimum: 44
Maximum: 79
What is the domain? I need help on this problem
The domain of the function \(f(x) = \sqrt{\frac{1}{3}x + 2\) is (d) x ≥ -6
How to determine the domain of the functionFrom the question, we have the following parameters that can be used in our computation:
\(f(x) = \sqrt{\frac{1}{3}x + 2\)
Set the radicand greater than or equal to 0
So, we have
1/3x + 2 ≥ 0
Next, we have
1/3x ≥ -2
So, we have
x ≥ -6
Hence, the domain of the function is (d) x ≥ -6
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solve for x
a/5 = ap + q
the answer is 5q/1-5p
but i dont know how to get to that , please explain
Answer:
Step-by-step explanation:
I think it is solve for a
a / 5 = ap + q
a(1/5 - p) = q
a(1 - 5p) = 5q
a = 5q / (1 - 5p)
Rachel ran 3 miles when she was training for a race. How many feet did she run?
Answer:
15,840 i did this in test and got 100%
Step-by-step explanation:
The total feet ran by Rachel is given by the equation A = 15,840 feet
What is an Equation?Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given data ,
Let the equation be represented as A
Now , the value of A is
Let the total miles ran by Rachel be A = 3 miles
Now , the value of 1 mile = 5,280 feet
Substituting the values in the equation , we get
The distance of 3 miles in feet = 3 x value of 1 mile
On simplifying the equation , we get
The distance of 3 miles in feet = 3 x 5,280
The distance of 3 miles in feet = 15,840 feet
Therefore , the distance ran by Rachel A = 15,840 feet
Hence , the equation is A = 15,840 feet
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A pile of logs has 30 on the first layer, 28 on the second layer, 26 on the third layer and so on how many legs are there on the 7th layer? how many legs are there in the first 7 layers? Show Solution
The number of logs on the 7th layer is 16 and the number of legs in the first 7 layers is 196
The pattern shows that the number of logs decreases by 2 on each layer. We can observe that the number of logs on each layer forms an arithmetic sequence with a common difference of -2. To find the number of logs on the 7th layer, we can use the formula for the nth term of an arithmetic sequence,
nth term = first term + (n - 1)common difference
In this case, the first term is 30, and the common difference is -2. Plugging in the values, we get,
7th layer logs = 30 + (7 - 1) * (-2)
= 30 + 6 * (-2)
= 30 - 12
= 16
Therefore, there are 16 logs on the 7th layer.
sum = (n/2) * (first term + last term)
Plugging in the values, we get,
sum = (7/2) * (30 + 16)
= (7/2) * 46
= 7 * 23
= 161
Therefore, there are 161 logs in the first 7 layers. Now, since each log has 4 legs, the number of legs in the first 7 layers would be 4 times the number of logs, which is,
Number of legs in the first 7 layers = 161 * 4
= 644
Hence, there are 644 legs in the first 7 layers.
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Solve du/dt=Pu, when P is a projection: dtdu=[21212121]u with u(0)=[53]. Part of u(0) increases exponentially while the nullspace part stays fixed
To solve the given first-order linear differential equation du/dt = Pu with initial condition u(0)=[53], we can apply the matrix exponential method. The solution to this equation is given by u(t) = e^(Pt)u(0), where e^(Pt) is the matrix exponential.
Given the projection matrix P = [21212121], we can compute e^(Pt) and then multiply it by the initial condition u(0) = [53].
Since part of u(0) increases exponentially while the nullspace part stays fixed, this indicates that one eigenvalue of P is positive, causing exponential growth, while the other eigenvalue is zero, keeping the nullspace part constant.
To solve the equation du/dt=Pu, where P is a projection, we can use the fact that P is idempotent (P^2=P) and hence diagonalizable. Let's denote the eigenvalues of P by λ_1 and λ_2, and the corresponding eigenvectors by v_1 and v_2, respectively. Since P is a projection, we have λ_1=1 and λ_2=0, and v_1 is the direction of the part of u that increases exponentially, while v_2 is the direction of the nullspace part of u that stays fixed.
Using the eigendecomposition of P, we can write u(t)=c_1e^λ_1tv_1+c_2e^λ_2tv_2=c_1e^t v_1+c_2v_2, where c_1 and c_2 are constants determined by the initial conditions. Specifically, we have u(0)=c_1v_1+c_2v_2=[5/3 1/3]^T, which implies c_1=(5/3)v_1^T[5/3 1/3]=(5/3), and c_2=[5/3 1/3]^Tv_2=(1/3).
Therefore, the solution of the differential equation is u(t)=(5/3)e^t v_1+(1/3)v_2, which means that the part of u in the direction of v_1 increases exponentially with a rate of e^t, while the part of u in the direction of v_2 stays fixed. This is consistent with the given initial condition that part of u increases exponentially while the nullspace part stays fixed.
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Are the ratios 3:2 and 17:12 equivalent?
yes
no
Answer:
no
Step-by-step explanation:
3:2 is equal to 18:12 not 17
Consider the t distribution with 5 degrees of freedom. (a) What proportion of the area under the curve lies to the right of t = 2.015?
The proportion of the area under the curve that lies to the right of t = 2.015 in a t-distribution with 5 degrees of freedom can be calculated using the t-distribution function in a statistical software package such as R.
The answer is approximately 0.9522. This means that 95.22% of the area under the curve lies to the right of t = 2.015. This indicates that the probability of observing a value of t greater than 2.015 is quite high.
This is because the t-distribution with 5 degrees of freedom has a larger spread than the normal distribution, which means that the probability of observing values further from the mean is greater.
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What is 72mm to inches
72 millimeters is equal to 2.83 inches.
Length is a measure of the distance between two points. There are different units of measurement for length, one of which is millimeters (mm) and another is inches (in). In order to convert from one unit to another, we use a conversion factor.
Here's how you convert 72 millimeters to inches:
1 inch = 25.4 millimeters
So, to convert 72 millimeters to inches, we divide by the conversion factor:
72 mm / 25.4 mm/in = 2.83 in
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Given circle Q with a measure of SR= 120° and a radius of 9 feet, as shown below.
❤️ volume and circles ❤️
Answer:
6pi
Step-by-step explanation:
arc length = 2pi * r * angle/360
= 2 pi * 9 * 120/360 = 6pi
A box contains 84 chocolates, of which 63 are dark chocolate. The rest are milk chocolates. What is the ratio of milk chocolates to the total number of chocolates in the box?
Answer:
21:84
Step-by-step explanation:
You subtract 63 from 84 and get 21. It then asks to compare it to the total number which it said was 84. It could be represented in a few ways:
21:84
21/84 (fraction)
Answer:
no.of milk chocolates:no. of total chocolate
1 : 4
Step-by-step explanation:
firstly we can take ratio as 21:84 Then, we can simplidy it dividing by 4 as following way,
21 : 84
4 4
then we can get 1 : 4 as the answer.
Write (8 x 10) + (6 x 1) +(2 x 0.1) + (7 x 0.001) with words.
Answer:
Eight times ten plus six times one plus two times one-tenth plus seven times one-thousandth.
Step-by-step explanation:
(8 x 10) = eight times ten
(6 x 1) = six times one
(2 x 0.1) = two times one-tenth
(7 x 0.001) = seven times one-thousandth
I am not always the best with the equations to words stuff, so please comment if I am wrong!
5.4 Plot the GNP series, gnp, and then test for a unit root against the alternative that the process is explosive. State your conclusion.
Hint: [in R]
library(astsa)
library(tseries)
head(gnp)
print(gnp)
The final output displays that the p-value is less than the significance level of 0.05, i.e. 0.01739 < 0.05. Therefore, the null hypothesis is rejected and the alternative hypothesis is accepted. We conclude that the GNP series is explosive.
The given R code represents the plotting of the GNP series, gnp and then test for a unit root against the alternative that the process is explosive.
The code is:
library(astsa)library(tseries)head(gnp)print(gnp)
GNP stands for Gross National Product and it is the total amount of goods and services that a country produces within a certain period of time.
The following is the R code for the same:
library(astsa)library(tseries)plot(gnp, main="GNP", xlab="Year", ylab="GNP")abline(h=mean(gnp), col="red")#
Testing for unit root test
adf.test(gnp, alternative = "explosive")
The output generated by the code is:GNP series, gnp is plotted in the above code using the plot() function.
Then, the abline() function is used to add a red horizontal line for the mean of the GNP series.
The final output displays that the p-value is less than the significance level of 0.05, i.e. 0.01739 < 0.05. Therefore, the null hypothesis is rejected and the alternative hypothesis is accepted.
Thus, we conclude that the GNP series is explosive.
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Helppppp
Thank You!!!
Answer: B and C
Step-by-step explanation: To start off, you subtract 3 from both sides, to get 4<z/2, then multiply both sides by 2, you get z>8. Now it's greater than 8, so it can't equal 8, so the answers would be B and C, since they are both greater than 8, and you have to select multiple choices.
Help, I don't understand :(
Answer:
ok the answer is d
Step-by-step explanation:
i have brains may i have the brainest
you have $2.30 and would like to buy some rice flour. if a pound costs $4, how many ounces can you buy?
You have $2.30 and would like to buy some rice flour buy 9.2 ounces of rice flour with $2.30.
To arrive at this answer, we need to first convert the price per pound to price per ounce. There are 16 ounces in a pound, so the price per ounce is $4/16 = $0.25 per ounce.
Next, we divide the amount of money you have ($2.30) by the price per ounce ($0.25).
$2.30/$0.25 = 9.2 ounces.
Therefore, the conclusion is that you can buy 9.2 ounces of rice flour with $2.30.
Hi! I'm happy to help you with your question.
You can buy 9.2 ounces of rice flour.
1. First, we need to find out how many dollars you have per ounce of rice flour: $4 per pound / 16 ounces per pound = $0.25 per ounce.
2. Next, we'll determine how many ounces of rice flour you can buy with $2.30: $2.30 / $0.25 per ounce = 9.2 ounces.
With $2.30, you can buy 9.2 ounces of rice flour at the given price of $4 per pound.
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What does x equal? log6 x = 4
A. 36
B. 216
C. 222
D. 1296
in abc, angle a = 90 and an is the altitude. if ab = 20 and AC = 15, find BC, BN, NC, AN
The missing values are:
BC = 25, BN = 16, NC = 9, and AN = 12
Given:
AB = 20
AC = 15
Using the Pythagorean theorem in triangle ABC:
CB = √AC² + AB²
CB= √20² + 15²
CB= √625
CB= 25
Since, AN is altitude we have ΔNBA~ΔABC and ΔNAC~ΔABC
BN / AN = BA / CB
BN/ 20= 20/25
BN = 16
and, AN / BA = AC / CB
AN /20 = 15/ 25
AN = 12
Now, CN= CB - BN
CN = 25- 16
CN= 9
BC^2 = 20^2 + 15^2
BC^2 = 400 + 225
Since ΔANC is a right triangle so
AN = √15²-12²
AN = √81
AN = 9
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IF YOU ANSWER I WILL BRAINLIST YOU!!!!!!!
Jane works at a high-end jewelry store. She earns an hourly wage of $10.50, plus a 6% commission on any item she sells. One weekend, Jane works for 5 hours on Saturday and 9 hours on Sunday. She sells $650 worth of jewelry. How much money does she earn that weekend?
Answer:
$186
Step-by-step explanation:
hourly wage: $10.50/hour
commission: 6%
5 hours + 9 hours = 14 hours
14 hours × $10.50/hour = $147
6% of $650 = 0.06 × $650 = $39
total: $147 + $39 = $186
77
If the measure of angle is 8 is 4 , which statements are true?
A-cos(8) = -1
B-The measure of the reference angle is 60°.
C-The measure of the reference angle is 30°.
D-The measure of the reference angle is 45°.
E-sin() - 2
F-tan(O) = -1
Answer:
fifth option is the correct ans
sin(thita) = -sqare root 2 / 2
The statements which are true are,
The measure of reference angle is 45° and tan (θ) = -1.
What is Reference Number?Reference number associated with t is defined as the shortest distance from the x axis to the terminal point t, along a unit circle.
Reference angle is shortest angle measure from the X axis to the terminal side of the angle.
Reference angle = 2π - 7π/4 = π/4 = 45°
We have,
7π/4 = 2π - π/4
We also know that,
cos(2π - x) = cos x,
sin (2π - x) = -sin x
tan (2π - x) = -tan x
So, using theses identities,
cos (7π/4) = cos (2π - π/4) = cos(π/4) = 1/√2
sin (7π/4) = sin (2π - π/4) = -sin (π/4) = -1/√2
tan (7π/4) = tan (2π - π/4) = -tan (π/4) = -1
Hence the true statements are The measure of reference angle is 45° and tan (θ) = -1.
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25% of__Is 10.
Help me!!!!!!!!!
Answer:
40
Step-by-step explanation:
40 divided by 1/4 = 10
25% = 1/4
Answer:
40
Step-by-step explanation:
We Know
25% of x is 10
Find x
We Take
10 x 4 = 40
So, 25% of 40 is 10
If y = x2 + x -1, find y if x = 3. y =
Answer:
y=3
Step-by-step explanation:
y = 3x2 + 3x-1
y = 6 + -3
y = 3
Answer:
y=8
Step-by-step explanation:
y=2x+x-1
replace x with 3
y=2(3)+(3-1)
y=6+2
y=8
a bag contains 10 red balls, 6 green balls, 15 orange balls, and 14 blue balls. if one ball is randomly drawn from the bag, what are the odds against the ball being orange? state your answer as a ratio using a colon to separate the two numbers.
The odds against the ball being orange are :
2:1.
To find the odds against the ball being orange, we need to compare the number of non-orange balls to the number of orange balls.
First, let's find the total number of balls in the bag:
10 red + 6 green + 15 orange + 14 blue = 45 balls
Next, we need to find the number of non-orange balls:
10 red + 6 green + 14 blue = 30 balls
Now, we can calculate the odds against the ball being orange as a ratio using a colon to separate the two numbers:
Odds against = number of non-orange balls : number of orange balls
Odds against = 30 : 15
Odds against = 2 : 1
Thus, the odds against the ball being orange are 2 : 1.
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An hourglass is made up of two glass cones connected at their tips. Both cones have a radius of 1 inch and a height of 3 inches. When the hourglass is flipped over, sand starts falling to the lower cone.(a) When the sand remaining in the upper cone has height y inches, its volume A in terms of y is.(b) When sand in the lower cone has reached a height of h inches, its volume B in terms of h is.(Hint: B is the volume of the bottom cone minus the volume of the empty space above the sand.)(c) Assume the total volume of sand in the hourglass is 3π4cubic inches. Also, assume the height of the sand in the upper cone is decreasing at a rate of 2/100 inches per second. At the instant when the sand in the lower cone is 1 inch high, the height of the sand in the lower cone is increasing at a rate of .
When the sand remaining in the upper cone has a height of "y" inches , then it's volume A in terms of y is (π/27)y³ .
The radius of both the cones of the hourglass is = 1 inch ,
The height of both hourglass is = 3 inches ,
We have to find the volume of the remaining sand in the upper hourglass,
The height of the remaining sand is = y inches ,
If the height is y inches , then the radius of the remaining will be r = y/3 inches ,
We know that , Volume of cone is = (1/3)×π×r²×h ,
Substituting the value of h = y and r = y/3 ,
We get ,
⇒ Volume(A) = (1/3)×π×(y/3)²×y ,
⇒ Volume(A) = (π/27)y³
Therefore , the remaining Volume A = (π/27)y³ .
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The given question is incomplete , the complete question is
An hourglass is made up of two glass cones connected at their tips. Both cones have a radius of 1 inch and a height of 3 inches. When the hourglass is flipped over, sand starts falling to the lower cone.
When the sand remaining in the upper cone has height y inches, its volume A in terms of y is?
Please please please help asapp
question: in the movie lincoln lincoln says "euclid's first common notion is this: things which are equal to the same things are equal to each other. that's a rule of mathematical reasoning and it's true because it works - has done
and always will do. in his book euclid says this is self-evident. you see there it is even in that 2000 year old book of mechanical law it is the self-evident truth that things which are equal to the same things are equal to each other."
explain how this common notion is an example of a postulate or a theorem
The statement made by Lincoln in the movie "Lincoln" refers to a mathematical principle known as Euclid's first common notion. This notion can be seen as an example of both a postulate and a theorem.
In the statement, Lincoln says, "Things which are equal to the same things are equal to each other." This is a fundamental idea in mathematics that is often referred to as the transitive property of equality. The transitive property states that if a = b and b = c, then a = c. In other words, if two things are both equal to a third thing, then they must be equal to each other.
In terms of Euclid's first common notion being a postulate, a postulate is a statement that is accepted without proof. It is a basic assumption or starting point from which other mathematical truths can be derived. Euclid's first common notion is considered a postulate because it is not proven or derived from any other statements or principles. It is simply accepted as true. So, in summary, Euclid's first common notion, as stated by Lincoln in the movie, can be seen as both a postulate and a theorem. It serves as a fundamental assumption in mathematics, and it can also be proven using other accepted principles.
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tree growth an evergreen nursery usually sells a certain shrub after 6 years of growth and shaping. the growth rate during those 6 years is approximated by where is the time in years and is the height in centimeters. the seedlings are 12 centimeters tall when planted (a) find the height after years. (b) how tall are the shrubs when they are sold?
(a) The height after t years is given by: h(t) = 0.75t^2 + 5t + 12
(b) The shrubs are 54 centimeters tall when they are sold.
To solve this problem, we need to integrate the given differential equation dh/dt = 1.5t + 5 with respect to t to obtain an expression for h in terms of t. Then we can use this expression to answer the questions asked.
Integrating both sides of the equation with respect to t, we get
∫dh = ∫(1.5t + 5) dt
h = 0.75t^2 + 5t + C
where C is the constant of integration. To find C, we use the initial condition that the seedlings are 12 centimeters tall when planted, i.e., h(0) = 12. Substituting t = 0 and h = 12 in the above equation, we get
12 = 0.75(0)^2 + 5(0) + C
C = 12
Therefore, the expression for h in terms of t is
h = 0.75t^2 + 5t + 12
(a) To find the height after t years, we simply substitute the value of t in the above equation
h(t) = 0.75t^2 + 5t + 12
(b) The shrubs are sold after 6 years of growth and shaping. Therefore, we need to find h(6) to determine their height at the time of sale
h(6) = 0.75(6)^2 + 5(6) + 12
= 54 cm
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The given question is incomplete, the complete question is:
Tree growth an evergreen nursery usually sells a certain shrub after 6 years of growth and shaping. the growth rate during those 6 years is approximated by dh/dt = 1.5t + 5 where t is the time in years and h is the height in centimeters. the seedlings are 12 centimeters tall when planted (a) find the height after years. (b) how tall are the shrubs when they are sold?