Isobars are an important feature shown on weather maps. They join up points which have equal values of.

Answer:

CHEBI:16480 - nitric oxide

Nitric oxide (nitrogen oxide or nitrogen monoxide) is a colorless gas with the formula NO.

Answer:

TRI-nitrogen PENTA-chloride

N₃CI₅

Answer:

Explanation:

It seems like you’re trying to count the number of atoms in some chemical formulas. Here’s the list of the number of each atom in the formulas you provided:

Formula 1: Н - 1 Formula 2: H - 1, O - 1 Formula 3: Н - 14 Formula 4: Н - 2, C - 3 Formula 5: I - 1 Formula 6: Н - 3 Formula 7: H - 2 Formula 8: Н - 2, C - 3, O - 1 Formula 9: Li - 1 Formula 10: Н - 2 Formula 11: Н - 2 Formula 12: H - 1 Formula 13: Н - 2, C - 2, O - 1 Formula 14: II

Answer:

To calculate the molarity of the solution, we first need to find the number of moles of calcium chloride in the solution.

The molar mass of calcium chloride (CaCl2) is 40.08 g/mol (1 calcium atom + 2 chlorine atoms).

The number of moles of calcium chloride can be calculated as:

moles of CaCl2 = mass of CaCl2 / molar mass of CaCl2

moles of CaCl2 = 40.1 g / 40.08 g/mol

moles of CaCl2 = 1.00 mol

Now that we know the number of moles of calcium chloride in the solution, we can calculate the molarity using the following formula:

molarity = moles of solute / volume of solution (in liters)

First, we need to convert the volume of solution from milliliters to liters:

429 mL = 0.429 L

Now we can calculate the molarity:

molarity = 1.00 mol / 0.429 L

molarity = 2.33 M

Therefore, the molarity of the solution is 2.33 M.

Answer:

Explanation:The volume of the box is 8.6 × 10³ in².

V = lwh = 26 in × 18.4 in × 17.92 in = 8.6 × 10³ in²

Note: The answer can have only two significant figures because that is all you gave for the length of the box.

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Answer:

anilinium ion > ammonium ion > amide > aniline > secondary amine

Explanation:

Acidity of amine derivatives can derived from their pKa values.

The rule of thumb for acidity with relation to pKa values is that:

As the pKa decreases the acid strength increases and the conjugate base decreases. Similarly, as the pKa increases, the acid strength decreases and the conjugate base increase.

Hence the stronger the acid , the  lower pKa value  and the weaker the acid , the stronger the pKa value.

So the pKa value for anilinium ion = 4.6

ammonium ion = 9.4

Amide = 15

Similarly, for aniline and secondary amine, in order to determine the derivative with the higher acidity, we will consider the electron withdrawing substituent group.

The more difficult the electron are being withdraw from the electron withdrawing substituent , the more acidic the compound.

In aniline , the stabilized benzene ring attached to NH₂ makes it a less electron withdrawing group compared to the straight chains structure found in secondary amine where electron are easily withdraw by nucleophilic substitution reactions.

Thus, from highest acidity (lowest pKa value) to lowest acidity (highest pKa value).

the amine derivatives ranking is as follows:

anilinium ion > ammonium ion > amide > aniline > secondary amine

Answer:

122 forenhieght

Explanation:

(50°C × 9/5) + 32 = 122°F

Physics is a vast field that addresses a wide range of questions about the nature of the physical world. Probing questions can help to explore this field and encourage critical thinking and deep exploration of its topics.

Probing questions are open-ended questions asked to gather information, encourage critical thinking and deep exploration of a particular topic. Physics is a natural science that studies matter and its motion through space-time. It is a branch of science that deals with the fundamental nature of the universe and seeks to explain how and why objects behave as they do in the physical world.The following are some examples of probing questions within the scope of physics:What is the nature of light-The nature of light is an important topic within the scope of physics. It refers to the dual nature of light, as both a wave and a particle. Light behaves as a wave when it is traveling through space and as a particle when it is interacting with matter.How do magnets work-Magnets are a common object in the world around us, and they have a broad range of applications. They work by producing a magnetic field, which can attract or repel other magnetic objects. This topic lies within the scope of physics.What is the relationship between energy and matter-Energy and matter are two fundamental concepts in physics. The relationship between them is described by Einstein's famous equation E=mc2, which states that matter and energy are two forms of the same thing and are interchangeable. The study of the relationship between energy and matter lies within the scope of physics.What is the nature of the universe?The study of the universe's nature is one of the most significant topics within the scope of physics. This question addresses the origins and properties of the universe, its components, and the laws that govern its behavior.

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Answer:

Explanation:

We can solve this using Gay Lussac's law which states that the pressure of a given mass of gas is directly proportional to it's temperature in kelvin. This law can be illustrated using the formula below

P₁/T₁ = P₂/T₂

where P₁ = 101.3 kPa

P₂ = 191.0 kPa

T₁ = 373.15K

T₂ = ?

101.3/373.15 = 191/T₂

cross-multiply

T₂ = 373.15 x 191/101.3

T₂ = 703.57K

The temperature of the steam inside the pressure cooker is 703.57K

The temperature is  703.6 K.

The pressure of a given mass of gas is directly proportional to its  temperature at constant volume.

P1 = 101.3 kPa

P2 = 191.0 kPa

T1 = 373.15K

T2 = ?

Now;

P1/T1 = P2/T2

P1T2 = P2T1

T2 = P2T1/P1

T2 = 191.0 kPa × 373.15K/101.3 kPa

T2 = 703.6 K

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Answer:

D. Oxidation

Explanation:

In an electrolytic cell, oxidation (the loss of electrons) takes place at the anode. At the cathode reduction takes place.

A mnemonic technique that could be used is that the process that starts with a vowel (Oxidation) takes place at the place that also starts with a vowel (Anode).

We know that 0.0350 moles of aluminum participated in a chemical reaction and we must find the mass of the aluminum that participated in the reaction.

In order to find the mass of the aluminum that participated we must use the molar mass of this element:

- Molar mass of Aluminum: 26.981539 g/mol

Then, we need to use the next formula:

In this case, the number of moles is 0.0350

Now, we must replace the values in the formula

Finally, we must simplify the equation

ANSWER:

Using the correct number of significant digits:

Because HCl is a stronger acid than acetic acid, the pH of 0.01M acetic acid has greater value than the pH of 0.01M HCl. 2.88 is the  pH of a 0.01 M acetic acid.

Any hydrogen that comprises a material capable of giving a proton (a hydrogen ion) to another chemical is defined as acid. A base is indeed a molecule or ion that can receive a hydronium ion from just an acid.

1)Because HCl is a stronger acid than acetic acid, the pH of 0.01M acetic acid has greater value than the pH of 0.01M HCl. The pH value of stronger acid is lower.

2)CH\(_3\)COOH + H\(_2\)O  ⇄ CH\(_3\)COO⁻+  H\(_3\)O⁺

 0.01             0               0

 -x              +x                +x

 0.01-x           +x        +x

Ka=[ CH\(_3\)COO⁻][H\(_3\)O⁺]/[CH\(_3\)COOH]

1.8×10⁻⁵ = [x][x ]/[  0.01-x ]

x=1.34×10⁻³

pH = -log[H⁺]

     =  -log[1.34×10⁻³]

     =2.88

Therefore, because HCl is a stronger acid than acetic acid, the pH of 0.01M acetic acid has greater value than the pH of 0.01M HCl. 2.88 is the   pH of a 0.01 M acetic acid.

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Answer:

What are the options?

Explanation:

......

Answer:

Option E. 12.04

Explanation:

We begin by calculating the hydrogen ion concentration, [H+] in the solution. This can be obtained as follow:

HI will dissociate in solution as follow:

HI (aq) —> H+(aq) + I-(aq)

From the above equation,

1 mole of HI produced 1 mole of H+.

Therefore, 0.011 M HI solution will also produce 0.011 M H+ solution.

Therefore, the hydrogen ion concentration, [H+] in the solution is 0.011 M

Next, we shall determine the pH of the solution. This can be obtained as follow:

Hydrogen ion concentration, [H+] = 0.011 M

pH =?

pH = – Log [H+]

pH = – Log 0.011

pH = 1.96

Finally, we shall determine the pOH of the solution as follow:

pH = 1.96

pOH =?

pH + pOH = 14

1.96 + pOH = 14

Collect like terms

pOH = 14 – 1.96

pOH = 12.04

Therefore, the pOH of the solution is 12.04

Answer:

C.Strontium

Explanation:

The principal components of gasoline is 702 g of octane.

Thus, Crude oil and other petroleum liquids are used to create gasoline, a fuel. The majority of gasoline is utilized in car engines.

For retail sale at gas stations, finished motor gasoline is produced at petroleum refineries and blending facilities.

In order to create finished motor gasoline, petroleum refineries primarily produce gasoline blendstocks, which must be blended with other liquids. In order to create finished motor gasoline in various grades and formulas, gasoline blendstocks, finished gasoline, and fuel ethanol are combined at blending terminals.

Thus, The principal components of gasoline is 702 g of octane.

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Answer:

i let alone need more time to figure this out and i will get you the awnser.

Explanation:

Answer::

Explanation::

Answer:

There are three major hazards that may be introduced into the food supply any time during harvesting, processing, transporting, preparing, storing and serving food. These hazards may be microbiological, chemical or physical.

Explanation:

microbiological hazards

Microbiological hazard occurs when food becomes contaminated by microorganisms found in the air, food, water, soil, animals and the human body. Many microorganisms are helpful and necessary for life itself. However, given the right conditions, some microorganisms may cause a foodborne illness. Microorganisms commonly associated with foodborne illnesses include bacteria, viruses and parasites.chemical hazardsChemical hazards can occur at any point during harvesting, storage, preparation and service. When toxic chemicals used for pest control or for cleaning and sanitizing food contact surfaces and food preparation equipment come into contact with food, the food may be contaminated by those chemicals.Toxic metals such as copper, brass, cadmium, lead and zinc can be a source of chemical contamination. Zinc, used in galvanized containers (garbage cans) and in gray enamelware containers which may be plated with anatomy or cadmium, can make acidic foods such as orange juice or tomato sauce and pickles poisonous. Pottery dishes with lead glazes should not be used to prepare or serve food.Intentionally added chemicals help to maintain a food’s freshness or to enhance flavors in foods. Check the food ingredient label for more information about the additives. Excessive use of some additives has been linked (see Fact Sheets on Food Allergies and Food Additives) to cases of lethal allergic reactionsparticularly among sensitive individuals, in particular, asthmatics.Foodservice establishments are prohibited by law from using sulfites to maintain product freshness. However, they are still approved for use in some food processing operations, for example, processing shrimp and manufacturing wine. If they are used, the product must be clearly labeled.physical hazardsPhysical hazards usually result from accidental contamination and /or poor food handling practices. Examples include, slivers of glass, human hair, nails, false nails, nail polish, pieces of jewelry, metal fragments from worn or chipped utensils and containers, dirt, stones, frilled toothpicks.Pesticides may leave residues on fruits and vegetables. In general, these residues can be removed by scrubbing the surface and washing with water.Food irradiation is classified as a food additive and is regulated by the Food and Drug Administration (FDA). Irradiation is a process which destroys pathogenic and spoilage microorganisms without compromising safety, nutrition or quality and significantly lengthens storage life. In general, spices are irradiated as a means of controlling bacterial growth and mold. According to Dr. Donald Thayer of the USDA Agricultural Research Service, irradiation looks promising as a treatment for controlling cylospora in fresh produce like raspberries . Contact your local Cooperative Extension office for the latest information on irradiation.

Answer: C.  partially ionizes and is corrosive to metals

Explanation: Plato

Answer:

We would expect stars near the edge of the galaxy to rotate slower than stars near the center. This is because the rotational speed of objects in a rotating system depends on their distance from the center of rotation. Stars near the center of the galaxy are closer to the gravitational center of the galaxy's mass, so they feel a stronger gravitational pull and rotate faster. Stars near the edge are farther from the center, so they feel a weaker gravitational pull and rotate slower. This results in a gradient of rotational speeds, with the fastest speeds near the galactic center and slower speeds near the edges.

Answer:

7.25 x 10^47

Explanation:

1.204 x 10^24 moles*6.022 x 10^23 avogadro's number= 7.25 x 10^47

Answer:

A. Burning of wood is an example of a chemical change when heat is applied. When wood is burned, the heat causes a chemical reaction in the wood molecules, which breaks them down and releases energy in the form of heat, light, and smoke.

Explanation:

The ph value of human saliva is between 6.2-7.6 with 6.7 being the average pH

ph value of human saliva is 7 and 6

One molecule of propanol contains only one -OH group and not three -OH groups or three -CH3 groups.

The -OH group is attached to the central carbon atom and makes propanol a useful solvent and intermediate in organic chemistry.Propanol is a colorless liquid that belongs to the family of alcohols. It has the formula C3H8O, and it contains three carbon atoms, eight hydrogen atoms, and one hydroxyl group (-OH) attached to one of the carbons. One molecule of propanol contains only one -OH group, which is attached to the central carbon atom.

Thus, option (2) is the correct answer, and the other options are incorrect.The -OH group in propanol is responsible for its unique chemical and physical properties. It makes propanol soluble in water and other polar solvents and gives it a high boiling point of around 97°C. The hydroxyl group can also participate in chemical reactions, such as esterification, dehydration, oxidation, and reduction. For example, propanol can be oxidized to form propanal and then propanoic acid, which is a useful synthetic intermediate for many organic compounds.Apart from the -OH group, propanol also contains two other functional groups called methyl groups (-CH3). These are attached to the two carbon atoms adjacent to the central carbon. However, the question only asks about the number of -OH groups in propanol, so the methyl groups are irrelevant.
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Answer:

The answer to your question is given below.

Explanation:

1. The functional group is alkanol or alcohol (R–OH).

2. The functional group is alkanone or ketone (RC=OR).

3. The functional group is alkanal or aldehyde (R–CHO)

4. The functional group is alkanoic or carboxylic acidic (R–COOH).

5. The functional group is ether (ROR)

6. The functional group is ester (RCOOR).

7. The functional group is alkanol or alcohol (R–OH).

8. The functional group is alkanoic or carboxylic acidic (R–COOH).

9. The functional group is alkanal or aldehyde (R–CHO).

10. The functional group is alkanone or ketone (RC=OR).

Naming of the compound

To name the above compound, we must do the following:

1. Locate the longest continuous carbon chain. This gives the parent name.

2. Identify the functional group.

3. Identify and locate the position of the substituent group attached if there are any.

4. Combine the above to obtain name of the compound.

Now, let us name compound 7 and 10.

7a. The longest carbon chain is 4 i.e butane.

b. The functional group is –OH i.e alkanol or alcohol. We'll replace the –e in butane with –ol to obtain the name.

Therefore, the name of the compound is butanol.

10a. The longest carbon chain is 4 i.e butane.

b. The functional group is RC=OR i.e alkanone or ketone. We'll replace the –e in butane with –one to obtain the name.

Therefore, the name of the compound is butanone.

Synthetic materials are made from natural resources and can be used for many purposes.

Synthetic materials are made by chemically changing the starting substances to create a material with different characteristics. Some examples of synthetic materials are plastics, medicines, and new fuels.

A synthetic substance may be chemically identical to a naturally-occurring substance or may be different.

Item is made from a synthetic material :

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Answer:

a) \(\Delta G=2.6kJ\)

b) \(\Delta G=-979.57kJ\)

c) \(\Delta G=264.21kJ\)

Explanation:

Hello,

In this case, in each reaction we must subtract the Gibbs free energy of formation the reactants to the Gibbs free energy of formation of the products considering each species stoichiometric coefficients. In such a way, the Gibbs free energy of formations are:

\(\Delta _fG_{H_2}=\Delta _fG_{I_2}=0kJ/mol\\\Delta _fG_{HI}=1.3kJ/mol\\\Delta _fG_{CO_2}=-394.4kJ/mol\\\Delta _fG_{CO}=-137.3 kJ/mol\\\Delta _fG_{NH_3}=16.7 kJ/mol\\\Delta _fG_{HCl}=-95.3kJ/mol\\\Delta _fG_{MnO_2}=465.37kJ/mol\\\Delta _fG_{Mn}=0kJ/mol\\\Delta _fG_{NH_4Cl}=-342.81kJ/mol\)

So we proceed as follows:

a)

\(\Delta G=2\Delta _fG_{HI}-\Delta _fG_{H_2}-\Delta _fG_{I_2}\\\\\Delta G=2*1.3\\\\\Delta G=2.6kJ\)

b)

\(\Delta G=\Delta _fG_{Mn}+2*\Delta _fG_{CO_2}-\Delta _fG_{MnO_2}-2*\Delta _fG_{CO}\\\\\Delta G=0+2*-394.4-465.37-2*-137.3\\\\\Delta G=-979.57kJ\)

c)

\(\Delta G=\Delta _fG_{NH_3}+\Delta _fG_{HCl}-\Delta _fG_{NH_4Cl}\\\\\Delta G=16.7-95.3-(-342.81)\\\\\Delta G=264.21kJ\)

Regards.

According to the problem, we need to determine whether new catalyst B would give higher yields than old catalyst A. The given data is a paired sample, because both the catalysts were experimented on 6 different batches of raw materials.

(a) Explain the experimental design.

Here the data collected is from 6 different raw materials, which were divided into two portions. Therefore, two data were obtained for each of the 6 raw materials, which implies in scientific terms that repeated data was obtained for each of the 6 raw materials. Thus, this type of design is known as Repeated-Measures Design.

(b) Carry out the appropriate t test.

For testing whether the new catalyst B will give higher yields than old catalyst A, a Paired-Sample t-test needs to be performed. The test will be performed using R Studio. The R codes and output are as below.

R CODE

# Load the Data A <- c(9,19,28,22,18,8) B <- c(10,22,30,21,23,12)  # Paired Sample t-test t.test(A,B,paired = TRUE,alternative = "less")

R OUTPUT

# Paired Sample t-test > t.test(A, B, paired = TRUE, alternative = less) Paired t-test = data: A and B t = -2.6458, df = ">

The decision rule for this test is: "If the p-value < 0.05, then reject the null hypothesis, under 0.05 level of significance; otherwise accept the null hypothesis".

Decision: As p-value (= 0.02283) < 0.05, so we decide to REJECT the null hypothesis, under 0.05 level of significance.

Conclusion: As the null hypothesis is to be rejected, so we can conclude that "there is sufficient evidence conclude that the new catalyst B gives a higher yield than old catalyst A".

(c) Construct a 95% confidence interval for the difference between catalysts A and B.

From part (b),

we have obtained the R output about the 95% confidence interval for the difference between catalysts A and B as:

Therefore, the 95% confidence interval for the difference between catalysts A and B is (-∞, -0.56).

In frequency statistics, the confidence interval (CI) is the range of estimated values ​​for an unknown parameter. Confidence intervals are computed at the specified confidence level. A 95% confidence level is the most common, but other levels such as 90% and 99% are sometimes used . The confidence level represents the proportion of corresponding CIs over time that contain the true value of the parameter. For example, 95% of all intervals computed at the 95% level must contain the true value of the parameter.

Factors that affect the width of the CI include confidence level, sample size, and within-sample variability.  All other things being equal, the larger the sample, the narrower the confidence interval. Similarly, the more varied the sample, the wider the confidence interval, and the higher the confidence level, the wider the confidence interval.

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The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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