is this correct?? or wrong?​

According to the question the two charges are -7.5 µC and -7.5 µC.

Charges are fees or payments for services or goods. Charges can be one-time payments, recurring payments, or fees associated with using a product or service. Charges can be for products, services, or activities. Examples of charges include fees for using a credit card, fees for using a bank account, fees for renting a car, fees for using a mobile phone plan, fees for using a subscription service, fees for using a streaming service, and fees for using a gym membership.

Let the two charges be x and ( -15 - x ) µC.

According to Coulomb's law,

F = (k × x × ( -15 - x ))/r2

Where k is the Coulomb's constant,

k = 9 × 109 N × m2/C2

Given, F = 9 × 10-2 N

r = 5 m

Substituting these values in the equation,

9 × 10-2 = (9 × 109 × x × ( -15 - x ))/252

⇒ x2+ 15x - 4.5 × 10-4 = 0

Solving this equation,

x = -7.5 µC and ( -15 - x ) = -7.5 µC

Therefore, the two charges are -7.5 µC and -7.5 µC.

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Hi there!

A)
Since the ball's velocity is initially only in the HORIZONTAL direction, there is NO vertical component of its velocity. Therefore, we can treat this like a free-fall scenario. (Dropped from rest).

We can rearrange the following kinematic equation to make solving for the time taken for the balls to hit the ground easier.

\(d_y = v_yt + \frac{1}{2}at^2\)

dy = vertical displacement (height of table, 0.85 m)

vy = initial vertical velocity (0 m/s, only horizontal)
a = acceleration (due to gravity in this situation, 9.8 m/s²)

t = time (? sec)
Simplify and rearrange the variables for 't'.

\(d_y = 0(t) + \frac{1}{2}at^2\\\\d_y = \frac{1}{2}at^2\\\\t^2 = \frac{2d_y}{a}\\\\t = \sqrt{\frac{2d_y}{a}}}\)

Plug in the given values.

\(t = \sqrt{\frac{2(0.85)}{9.8}} = \boxed{0.4165 s}\)

B)

Now, remember that the ball's acceleration in the vertical direction due to gravity does NOT impact its horizontal velocity. Its vertical and horizontal velocities are COMPLETELY independent. Thus, we can simply use the time solved for above and each ball's respective velocities in the following kinematic equation:
\(d_x = v_xt\)

dₓ= horizontal displacement (? m)

vₓ = horizontal component of velocity (3.5 and 5.3 m/s for A and B respectively)

t = time (0.4165 s)

Solve for the distance traveled by each ball:
Ball A:
\(d_x = 3.5 * 0.4165 = \boxed{1.458 m}\)

Ball B:
\(d_x = 5.3* 0.4165 = \boxed{2.207 m}\)

Answer:

B cus is in the south but that pfp tho

Answer:

Elements heavier than iron are formed by neutron capture processes during stellar death and supernovae.

Explanation:

Most of the elements heavier than iron are formed during the death of stars through neutron capture processes, specifically the R-Process and the S-Process. The R-Process is a rapid capture of neutrons, while the S-Process is a slow capture of neutrons. These processes either directly form elements or indirectly form them through decay processes [^1]. Elements heavier than iron are primarily made in environments with free-neutron densities in excess of a million particles per cubic centimeter [^2]. In the extreme energetic conditions of supernovae, atoms are bombarded by a very large number of neutrons, and rapid successive neutron capture, followed by beta decay, produces the heavier atoms [^5].

So, elements heavier than iron are formed by neutron capture processes during stellar death and supernovae.

[^1

From graph:

* The final value of position at time 1 second is 20 m.

* The initial value of position at time 0 second is 20 m.

Solution:

The velocity in terms of the position is,

For the time interval 0 to 1 second,

Thus, the velocity over the time interval from 0 to 1 second is zero meter per second

The gravitational field on the surface of the planet is approximately 9.81 m/s^2

Gravitational field can be defined as the force field that exists in the space around every mass or group of masses.

The gravitational field on the surface of a planet can be calculated using Newton's law of gravitation:

G * m_planet / r^2

Where:

G = 6.67 x 10^-11 Nm^2/kg^2 is the gravitational constant

m_planet = 8.5 x 10^26 kg is the mass of the planet

r = 3.5 x 10^4 km is the radius of the planet (converted to meters)

First, let's convert the radius to meters:

3.5 x 10^4 km = 3.5 x 10^4 x 10^3 m = 3.5 x 10^7 m

Next, let's plug in the values and simplify the expression:

g = G * m_planet / r^2

g = (6.67 x 10^-11 Nm^2/kg^2) * (8.5 x 10^26 kg) / (3.5 x 10^7 m)^2

g = (6.67 x 10^-11 Nm^2/kg^2) * (8.5 x 10^26 kg) / (1.225 x 10^15 m^2)

g = 9.81 m/s^2

Therefore, The gravitational field on the surface of the planet is approximately 9.81 m/s^2

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The airplane change in velocity be 120 m/sec

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.

The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.

acceleration = velocity/time

Velocity = acceleration * time

Velocity = 60*2

Velocity = 120 m/sec

The airplane change in velocity be 120 m/sec

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Answer:

43200 J

Explanation:

(1/2(mass)) (speed)^2

Answer:

The higher the energy (B)

Explanation:

The relationship between Energy and Frequency is E = hf , where E is energy and f is frequency. From the formula you can see that E and f are directly related. Therefore, the higher the frequency, the higher the energy.

A parallel circuit can be modelled by connecting the components parallel.

A parallel circuit is a form of electrical circuit in which the components are linked in parallel to one another, each having a separate channel for current flow and being directly connected to the power source. The circuit must first be schematically represented, with the power supply and each component linked in parallel. Next, the total resistance the total current in the circuit by using Ohm's Law must be calculated.

Additionally, it is necessary to confirm that the total current entering the circuit equals the total current leaving the circuit. In a parallel circuit, the total current passing through all of the components equals the current entering the circuit. The voltage drop between each component must then be once more computed using Ohm's Law.

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Answer:

Explanation:

To find the direction of the displacement vector, we have to solve for the ratio of both displacements, and furthermore the inverse tangent of the ratio.

Given data

200km east represents the x axis

70 km north represents y axis

the direction of the resultant is given as

∅= tan-1x/y

∅=tan-1 200/70

∅= tan-120/7

∅= tan-12.85

∅= 70.66°

hence the direction of the resultant is 70.66°

The answer is that the time the diver was in the air is 1.13 seconds.

To determine the time the diver was in the air, we can use the kinematic equation:

Δy = viΔt + 1/2at²,

where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0

m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²

Simplifying, we get:

4.9t² + 5.5t - 3.0 = 0

We can solve for t using the quadratic formula:

t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s

Since time cannot be negative, the time the diver was in the air is 1.13 seconds.

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Answer:

1.37 * 10^ 27 watts

Explanation:

The power radiated by a body with surface temperature T and surface area A is given by

where σ = 5.67 x 10^-8 watt / m^2 K^4.

Now in our case

A = 6.89 x 10^18 m^2 and T = 7701.

Therefore,

which we evaluate to get

Hence, the power radiated by the star is 1.37 x 10^27 watts.

The balloon hits the ground right before the professor gets there.

The balloon picks up speed due to gravity and we can calculate the time taken for it to fall to the ground as follows:

Gravity (g) = 9.81 m/s²

Height or distance (s) = 11 meters

Initial Speed (u) = 0 m/s

using equation of motion

\(s = ut + \frac{1}{2}at^{2}\)

where s = height

u = initial speed

a = acceleration due to gravity

t = time taken

then using above values we get

11 = 0 x 2 + 0.5 x (9.8 x t²)

t = 1.4975

So we can see that the balloon takes 1.4975 seconds to fall to the ground, and since the professor takes 2 seconds to get to that place.

The balloon hits the ground right before the professor gets there.

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Answer: 529.9 Hz

Explanation:

Here we need to use the Doppler equation, so we have:

f' = f*(v + v0)/(v - vs)

Here, f is the frequency = 500Hz

v is the velocity of the wave, = 334m/s

v0 is the velocity of the observer = 20m/s

vs is the velocity of the source = 0m/s

Then we have:

f' = 500Hz*(334m/s + 20m/s)/(334m/s) = 529.9 Hz

Answer:

8 divided by 12 is 1.6

Explanation:

. .......

Answer:

5 m/s

Explanation:

We are given that 9000 kg of water flows through the pipe in 1 minute. Mass flow rate = mass/time

So, mass flow rate = 9000 kg / 1 minute = 150 kg/s

We know the cross sectional area of the pipe is 0.3 m2. From continuity equation, mass flow rate = density * area * velocity

So, 150 = 1000 * 0.3 * v (Density of water is approximately 1000 kg/m3)

Solving for v (velocity):

v = 150/(1000*0.3) = 5 m/s

Therefore, the speed of water in the pipe is 5 m/s.

Answer:

Scintillators are materials that transform high-energy radiation like X-rays or gamma-rays into visible light or near-visible light. They're commonly utilized in medical diagnostics, high-energy physics, and geophysical exploration as detectors.

Explanation:

i hope this helps

Answer:

d) the individual particles move perpendicular to the direction of travel

A block of 0.5 kg is placed on top of another wooden block which weighs 1.0 kg. The coefficient of static friction between the two blocks is 0.35, whereas the coefficient of kinetic friction between the lower block and the level table is 0.20.

To calculate the maximum horizontal force that can be applied to the lower block, we need to determine the limiting frictional force between the two blocks.

Since the upper block is not moving, the force of static friction is acting on it. We can calculate this force as follows:

`F_static = friction coefficient * normal force`

where, normal force = weight of upper block = 0.5 kg * 9.81 m/s^2 = 4.905 N

`F_static = 0.35 * 4.905 = 1.718 N`

Therefore, the static frictional force acting on the upper block is 1.718 N.

Now, we need to find the maximum force that can be applied to the lower block before it starts moving. This force is equal to the force of static friction acting on the lower block.

Since the upper block is not moving, the force of static friction acting on the lower block is equal to the force of static friction acting on the upper block.

`F_static(lower block) = F_static(upper block) = 1.718 N`

This means that the maximum horizontal force that can be applied to the lower block is 1.718 N.

However, if the applied force exceeds this value, the lower block will start moving and the force of kinetic friction will be acting on it, which is equal to:

`F_kinetic = friction coefficient * normal force`

`F_kinetic = 0.20 * 4.905 = 0.981 N`

Hence, if the applied force exceeds 1.718 N, the lower block will start moving and the force of kinetic friction will act on it, which is 0.981 N.

Therefore, the maximum horizontal force that can be applied to the lower block is 1.718 N.

Answer:

Explanation:

To determine the maximum horizontal force that can be applied to the lower block without causing the blocks to move, we need to calculate the maximum static friction force between the two blocks. This force is given by:

F_friction = coefficient of static friction * normal force

where the normal force is the force perpendicular to the surface of contact between the blocks. Since the blocks are resting on a level table, the normal force acting on the lower block is equal to the weight of both blocks, which is:

N = (m1 + m2) * g

where m1 is the mass of the lower block, m2 is the mass of the upper block, and g is the acceleration due to gravity (9.81 m/s^2).

Plugging in the given values, we have:

N = (1.0 kg + 0.5 kg) * 9.81 m/s^2 = 14.715 N

The maximum static friction force is then:

F_friction = 0.35 * 14.715 N = 5.15025 N

Therefore, the maximum horizontal force that can be applied to the lower block without causing the blocks to move is 5.15025 N. If a greater force is applied, the blocks will start to move and the kinetic friction force will take effect, which is given by:

F_kinetic = coefficient of kinetic friction * normal force

where the coefficient of kinetic friction is 0.20 in this case.

Answer:

Displacement will be 5m west

Distance would be 21m No direction

The lifetime of the excited state that produced this line is 416.66sec if a wavelength ranges from 401nm and 403nm.

For solving this problem we use Rydberg equation whose formula is given by

v=[(1 / λ₁) -1 / λ₂)]×(h×c)

where v is the frequency of the photon,

λ is the wavelength of the photon

h is plank's constant

and c is the speed of light in vacuum

Since we are given λ₁ ,λ₂ as 401nm and 403nm respectively.Also we know that value of h is 6.6ˣ10⁻³⁴(J-sec)/m and c=3ˣ10⁸m/sec

So,putting all values on above formula,we get

=>v=[(1/401)-(1/403)]ˣ(6.6ˣ10⁻³⁴) ˣ (3ˣ10⁸)

=>v=[(403-401) ˣ (6.6ˣ10⁻³⁴) ˣ (3ˣ10⁸)] / (401 ˣ 403)ˣ(1/10⁻²⁷)

=>v= [[2 ˣ (6.6ˣ10⁻³⁴) ˣ (3ˣ10⁸)] ₓ(1/10⁻²⁷)] ˣ (1 / 401 ˣ 403)

=>v=(39.6 ˣ 10) / 161603

=>v = 396/161603

=>v = 0.0024/sec

We know time period is reverse of frequency, so  lifetime span is

=>t=1/v

=>t=1/ (0.0024/sec)

=>t=416.66sec

Hence, lifetime of the excited state is 416.66sec.

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Answer:

  D.  The current is the same across all resistors in the circuit.

Explanation:

In a series circuit, all circuit elements are connected so that there is exactly one current path. That path goes through each of the elements of the circuit.

The current is the same through all resistors in a series circuit.

Answer:

applied force

Explanation:

I think that's right

Answer:

The magnitude of the net electric field inside the solution is 3.704 N/C

Explanation:

Given;

average drift speed, v = 3 x 10⁻⁷ m/s

mobility of the bromide ions, μ = 8.1 x 10⁻⁸ (m/s)(N/C)

The magnitude of the net electric field inside the solution is given by the equation below;

\(E = \frac{v}{\mu}\)

where;

E is the magnitude of the net electric field inside the solution

Substitute the given values and solve for E

\(E = \frac{v}{\mu}\\\\E = \frac{3*10^{-7}}{8.1*10^{-8}}\\\\ E = 3.704 \ N/C\)

Therefore, the magnitude of the net electric field inside the solution is 3.704 N/C

Answer:

Electromagnetic waves are created by a charged particle that generates an electric field. The electric field creates a magnetic field. As the charged particle moves, the electric field and magnetic field keep changing, which causes the wave to move.

Explanation:

I just answered the question and this is the sample response

Electromagnetic waves are propagated as electric and magnetic fields at right angles with each other. Electromagnetic waves can travel through space.

The electromagnetic waves are composed of electric and magnetic fields which are inclined at right angles to each other. We must note that  these waves do not require a medium of propagation as they travel through space.

Hence, electromagnetic waves are propagated as electric and magnetic fields at right angles with each other.

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Answer:

The first one

Explanation:

But I'm not sure though