Yes, there is a relationship like a straight line between the raises administrators at State University receive and their performance on the job
The estimated y-intercept of the line in the given straight-line regression model is $14,000.The interpretation of this value is that for an administrator who receives a rating of zero, we estimate his or her raise to be $14,000. This value represents the base raise amount for the administrators at State University, regardless of their job performance rating.To obtain this interpretation, we consider the equation of the regression line, which relates the predicted raise amount (y hat) to the job performance rating (x). The y-intercept term in this equation is the value of y hat when x equals zero. Therefore, the estimated y-intercept of $14,000 represents the predicted raise amount for an administrator whose job performance rating is zero, which corresponds to the base raise amount at State University.
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his friends eat 6/10 what fraction are left
Answer:
3/5
Step-by-step explanation:
4/10 are left. We can reduce it and get 2/5.
Hope it helps you!
\(JoyfulLass\)
\(Genius\)
\(IAmHereToHelpYou\)
Can somebody help me pleaseeee
Answer:
the answer is B OA
Step-by-step explanation
I know this because to identify a ray the starting point aka o is at the beginning of the answer
A right triangle is shown below.
ہو
60%
X
What is the sine of t?
1
The functions sin and cosine, sometimes known as sin() and cos(), show how a right triangle is shaped. Answer is 8.212°.
What does sin t mean in math?The functions sin and cosine, sometimes known as sin() and cos(), show how a right triangle is shaped.
The ratio of the opposite side to the hypotenuse is called sin(), and the ratio of the adjacent side to the hypotenuse is called cos(), when viewed from a vertex with angle.
So, the Pythagorean identity-based formula for sin is sin²x = 1 - cos²x.
Hypotenuse²=base²+perp²
(8)²=(7)²+(perp)²
64=49+(perp)²
64/49=perp²
1.306=perp²
Now taking square root on both sides
Perp=√1.306
Perp=1.142
Sin C=opposite/hypotenuse
Sin =1.142/8
Sin C=0.14285
C=Sin^-1 0.14285
C=8.212°
Answer is 8.212°.
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if x=3+2v2, find the value of x2 + 1/x2
Answer:
ES IGUAL A 1.03
Step-by-step explanation:
complete the pattern A12, B16, C20,
Answer:it goes up by 4
Step-by-step explanation:
12 16 20 24 28 and so on
If the number of bacteria in a colony doubles every 21 hours and there is currently a population of 150 bacteria, what will the population be 42 hours from now?
Answer:
450
Step-by-step explanation:
i think thats right
in a probability-proportional-to-size sample with a sampling interval of $10,000, an auditor discovered that a selected account receivable with a recorded amount of $5,000 had an audited amount of $4,000. if this were the only misstatement discovered by the auditor, the projected misstatement of this sample would be
The projected misstatement of this sample would be $50,000, calculated as follows: ($4,000 / $5,000) x $10,000.
In a probability-proportional-to-size sample, each item's chance of being selected is proportional to its recorded amount, so larger accounts have a higher probability of being selected. In this case, the auditor selected an account with a recorded amount of $5,000, but found that it had an audited amount of $4,000.
To project the misstatement of this sample, the auditor needs to estimate the total misstatement in the population by multiplying the audited amount by the inverse of the sampling fraction, which is the sampling interval divided by the recorded amount of the selected item. So, the projected misstatement is ($4,000 / $5,000) x $10,000 = $8,000 x 6.25 = $50,000. This means that the auditor estimates the total misstatement in the population to be approximately $50,000 based on this sample.
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A manufacturer of compact fluorescent light bulbs advertises that the distribution of the lifespans of these light bulbs is nearly normal with a mean of 9,000 hours and a standard deviation of 1,000 hours.
(a) What is the probability that a randomly chosen light bulb lasts more than 10,500 hours?
(b) Describe the distribution of the mean lifespan of 15 light bulbs.
(c) What is the probability that the mean lifespan of 15 randomly chosen light bulbs is more than 10,500 hours?
(d) Sketch the two distributions (population and sampling) on the same scale.
(e) Could you estimate the probabilities from parts (a) and (c) if the lifespans of light bulbs had a skewed distribution?
A manufacturer of compact fluorescent light bulbs advertises have a standard deviation of 1,000 hours so the values are:
A normal distribution with,
μ = 9000
σ = 1000
a) The standardized score is the value x decreased by the mean and then divided by the standard deviation.
x = 105000 - 9000 / 1000 ≈ 1.50
Determine the corresponding probability using the normal probability table in appendix,
P(X>10500) = P(Z>1.50) = 1 - P(Z<1.50)
= 1 - 0.9332 = 0.0668.
b) n = 15
The sampling distribution of the mean weight is approximately normal, because the population distribution is approximately normal.
The sampling distribution of the sample mean has mean μ and standard deviation σ/√n
μ = 1000/√15 = 258.19
c) The sampling distribution of the sample mean has mean μ and standard deviation σ/√n
The z-value is the sample mean decreased by the population mean, divided by the standard deviation:
z = x-u/σ/√n = 10500-9000/1000√15 = 5.81
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Simplify the following
(X-5)2
Answer:
2x-10 by the distributive property of equality
if two variables are correlated, a change in one must directly produce a change in the other. t or f
If two variables are correlated, a change in one must directly produce a change in the other. (False)
What is the Correlation?Correlation is a statistical measure that indicates the extent to which two or more variables fluctuate together. It is a value between -1 and 1 that represents the strength of the relationship between two variables.
False. If two variables are correlated, a change in one may or may not directly produce a change in the other. Correlation means that there is a relationship between two variables, but it does not necessarily mean that one causes the other. It's possible for two variables to be correlated without any causal relationship between them.
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There were 800 residents in a small town in California. Of the 800 residents, 200 visited a local pharmacy store. Mr. Phillip wants to know the customer satisfaction of the residents who visited the store. He was able to obtain information from all 200 residents. Is this an example of a population or a sample
In this scenario, the information obtained from all 200 residents who visited the store represents a subset of the total population. Therefore, it is an example of a sample.
In statistics, a population refers to the entire group of individuals or objects that we want to study and make inferences about. In this scenario, the population would consist of all the residents of the small town in California, which includes the 800 residents.
However, Mr. Phillip was only able to obtain information from a subset of the population, specifically the 200 residents who visited the store. This subset, known as the sample, is a smaller representative group selected from the population to gather information and make inferences about the larger population.
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The function describes the spread of a rumor among a group of people in an enclosed space. N represents the number of people who have heard the rumor, and t is measured in minutes since the rumor was started. Which of the following statements are true
Initially, only one person had heard the rumor.
The answer is b.
We have the following information available from the question is:
The function \(N(t) =\frac{300}{1+299e^ \\,0.36t}\) describes the spread of a rumor among a group of people in an enclosed space.
Where,
N represents the number of people who have heard the rumor,
and t is measured in minutes since the rumor was started.
Now, According to the question:
The function is:
\(N(t) =\frac{300}{1+299e^ \\,0.36t}\)
And, we put t = 0 we get :
\(N(0) =\frac{300}{1+299e^ \\,0.36(0)}\)
\(N(t) =\frac{300}{1+299e^ \\0}\)
\(N(t) =\frac{300}{1+299}\\\\N(t) =\frac{300}{300} = 1\)
Hence, Initially, only one person had heard the rumor.
The answer is b.
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Complete question is:
The function N(t)=300/(1+299e^-0.36t) describes the spread of a rumor among a group of people who have heard the rumor, and (t) is measured in minutes since the rumor was started. Which of the following statements are true?
a. The rate at which the rumor spreads speeds up over time.
b. Initially, only one person had heard the rumor.
c. It will take approx. 14 mins for 100 people to hear the rumor.
d. There are 299 people in the enclosed space.
Which function in cryptography takes a string of any length as input and returns a string of any requested variable length?
The sponge function in cryptography takes a string of any length as input and returns a string of any requested variable length.
According to the statement
we have to explain about the function in which cryptography takes a string of any length as input and returns a string of any requested variable length.
So, For this purpose,
we know that the
A sponge function or sponge construction is any of a class of algorithms with finite internal state that take an input bit stream of any length and produce an output bit stream of any desired length.
So from definition and its working process it is clear that for this purpose the sponge function is used.
this function returns the string of any variable length.
So, The sponge function in cryptography takes a string of any length as input and returns a string of any requested variable length.
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prove the proposition p(1), where p(n) is the proposition "if n is a positive integer, then n2 ≥ n." what kind of proof did you use?
Since n = 1 is a positive integer for which the proposition is true, then p(1) is true.
Direct Proof:
Assume n is a positive integer.
Show that n² ≥ n.
Substitute n = 1 into the equation n² ≥ n
Solve the equation 1² ≥ 1
Show that 1² = 1, and 1 ≥ 1.
Therefore, n² ≥ n is true for n = 1.
This is an example of a direct proof, in which we start by assuming the statement is true for a particular value before using logical processes to demonstrate that it must be true for all values.
Before solving the problem, we made the assumption that n was a positive integer, added n = 1, and then proved that the assertion was accurate for n = 1. This establishes the statement's applicability to all positive numbers.
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Which describes the correlation shown in the scatterplot?
Answer:
It shows how much variable is affected by one another.
Step-by-step explanation:
Answer:
There is a negative correlation in the data set.
Step-by-step explanation:
I hope this helps you! :D
Which statement is true?
ABCD is a rectangle. Diagonal AD=10 and AB=8. What is the perimeter of the rectangle?A. 36B. 16C. 30D. 40
The perimeter of the rectangle ABCD is 36 units, as option A, since the sum of all four sides of the rectangle is twice the sum of its adjacent sides. Option A.
In a rectangle, opposite sides are congruent. Let's denote the length of side AB as "a" and the length of side BC as "b".
From the given information, we know that AD is a diagonal of the rectangle with a length of 10 units, and AB is one side of the rectangle with a length of 8 units.
Using the Pythagorean theorem, we can find the length of side BC. The diagonal AD, side AB, and side BC form a right triangle. Applying the theorem, we have:
AD^2 = AB^2 + BC^2
10^2 = 8^2 + BC^2
100 = 64 + BC^2
BC^2 = 36
BC = 6
Since opposite sides of a rectangle are congruent, side CD is also 6 units.
The perimeter of a rectangle is the sum of all its sides. Therefore, the perimeter of ABCD is 2a + 2b = 2(8) + 2(6) = 36 units.
Hence, the correct option is A, which states that the perimeter of the rectangle is 36 units.
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Which of the following statements must be true (A) Continuous functions are differentiable wherever they are defined (C) If f() is differentiable on the interval (0,0), then it must be differentiable everywhere (D) If f(c) is differentiable on its domain, then it is also continuous on its domain (B) The product of two differentiable functions is not always differentiable
The statement (D) "If f(c) is differentiable on its domain, then it is also continuous on its domain" must be true.
(A) The statement "Continuous functions are differentiable wherever they are defined" is false. While it is true that differentiable functions are continuous, the converse is not always true. There exist continuous functions that are not differentiable at certain points, such as functions with sharp corners or cusps.
(C) The statement "If f() is differentiable on the interval (0,0), then it must be differentiable everywhere" is false. Differentiability on a specific interval does not imply differentiability everywhere. A function can be differentiable on a particular interval but not differentiable at isolated points or on other intervals.
(D) The statement "If f(c) is differentiable on its domain, then it is also continuous on its domain" is true. Differentiability implies continuity. If a function is differentiable at a point, it must also be continuous at that point. Therefore, if f(c) is differentiable on its domain, it must also be continuous on its domain.
(B) The statement "The product of two differentiable functions is not always differentiable" is false. The product of two differentiable functions is always differentiable. This is known as the product rule in calculus, which states that if two functions are differentiable, then their product is also differentiable.
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9. a) Find the vertical and horizontal asymptotes of f(x)=3 by using limits. X-3 b) State the domain of f(x). c) Sketch the graph of f(x). Find x and y-int. d) State the range of f(x).
The function f(x) = 3 is a constant function with a value of 3 for all x. Therefore, it does not have any vertical or horizontal asymptotes. Both the horizontal and vertical lines will intersect the graph of f(x) at y = 3, which is the constant value of the function.
The domain of f(x) = 3 is the set of all real numbers since there are no restrictions or limitations on the input x. In other words, we can plug in any real number into f(x) and get a result of 3.
The graph of f(x) = 3 is a horizontal line that is parallel to the x-axis and intersects the y-axis at y = 3. It does not have any x-intercepts because the function is constant and does not change with different values of x. The y-intercept, however, occurs at (0, 3) since plugging in x = 0 into the function gives us f(0) = 3.
The range of f(x) = 3 is also a single value, which is 3. The function f(x) takes on the value of 3 for all real values of x, so the range consists only of the constant value 3.
In summary:
- f(x) = 3 does not have any vertical or horizontal asymptotes.
- The domain of f(x) = 3 is the set of all real numbers.
- The graph of f(x) = 3 is a horizontal line at y = 3, intersecting the y-axis at (0, 3).
- There are no x-intercepts, but the y-intercept occurs at (0, 3).
- The range of f(x) = 3 is the single value 3.
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Write the phrase as an expression. Then evaluate the expression when x = 5.
6 more than the product of 8 and a number x
Expression:
When x = 5, the value of the expression is
Answer:
6 + 8x
46
Step-by-step explanation:
1. Write the expression
6 + 8x
2. Plug in 5 for x
6 + 8(5) → 6 + 40 = 46
Answer:
Expression=8x+6
The value of expression=46
Evaluate the function f(-2) - h(4) given the following functions: f(x) = 4x 2+ 9 h(x) = 3x - 14
Answer:
-86
Step-by-step explanation:
simplify each equation as much as possible
f(x)= 4x(2+9) add
4x(11) multiply
f(x)=44x
substitute given numbers into each equation
44(-2)=-88 3(4)-14= 12-14=-2
combine equations
-88-(-2)= -86 add since you are subtracting a negative number
A normal distribution has μ = 30 and Ï = 5.
(a) Find the z score corresponding to x = 25.
(b) Find the z score corresponding to x = 42.
(c) Find the raw score corresponding to z = â3.
(d) Find the raw score corresponding to z = 1.5.
(a) The z-score corresponding to x = 25 is -1. (b)The z-score corresponding to x = 42 is 2.4.(c) The raw score corresponding to z = -3 is 15. (d) The raw score corresponding to z = 1.5 is 37.5.
For a normal distribution with mean μ = 30 and standard deviation σ = 5:
(a) To find the z-score corresponding to x = 25, we use the formula:
z = (x - μ) / σ
Substituting the values, we get:
z = (25 - 30) / 5 = -1
Therefore, the z-score corresponding to x = 25 is -1.
(b) To find the z-score corresponding to x = 42, we again use the formula:
z = (x - μ) / σ
Substituting the values, we get:
z = (42 - 30) / 5 = 2.4
Therefore, the z-score corresponding to x = 42 is 2.4.
(c) To find the raw score (x) corresponding to z = -3, we use the formula:
z = (x - μ) / σ
Rearranging the formula, we get:
x = μ + zσ
Substituting the values, we get:
x = 30 + (-3) x 5 = 15
Therefore, the raw score corresponding to z = -3 is 15.
(d) To find the raw score (x) corresponding to z = 1.5, we use the same formula:
x = μ + zσ
Substituting the values, we get:
x = 30 + 1.5 x 5 = 37.5
Therefore, the raw score corresponding to z = 1.5 is 37.5.
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Carbon dioxide is produced in the reaction between calcium carbonate and hydrochloric acid. Hwo many grams of calcium carbonate would be needed to ract completlely with 15.0 grams of hydrochloric aci
To determine the number of grams of calcium carbonate needed to react completely with 15.0 grams of hydrochloric acid, we need to use stoichiometry.
From the balanced equation, we can see that 1 mole of CaCO3 reacts with 2 moles of HCl. We need to convert the given mass of HCl to moles, and then use the mole ratio to find the moles of CaCO3. First, let's calculate the moles of HCl. The molar mass of HCl is 36.5 g/mol, so:
moles of HCl = mass of HCl / molar mass of HCl
= 15.0 g / 36.5 g/mol
≈ 0.41 mol
Since the mole ratio between CaCO3 and HCl is 1:2, the moles of CaCO3 needed would be:
moles of CaCO3 = 0.41 mol HCl × (1 mol CaCO3 / 2 mol HCl)
= 0.20 mol
Finally, we can convert the moles of CaCO3 to grams using its molar mass. The molar mass of CaCO3 is 100.09 g/mol, so:
grams of CaCO3 = moles of CaCO3 × molar mass of CaCO3
= 0.20 mol × 100.09 g/mol
= 20.02 g
Approximately 20.02 grams of calcium carbonate would be needed to react completely with 15.0 grams of hydrochloric acid.
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Approximately 41.1 grams of calcium carbonate would be needed to react completely with 15.0 grams of hydrochloric acid.
To determine the amount of calcium carbonate needed to react completely with 15.0 grams of hydrochloric acid, we need to use stoichiometry.
First, let's write the balanced chemical equation for the reaction:
\(CaCO_{3}\) + 2HCl -> \(CaCl_{2}\) + \(CO_{2}\) + \(H_{2}O\)
From the equation, we can see that one mole of calcium carbonate reacts with two moles of hydrochloric acid. We need to convert the mass of hydrochloric acid to moles, then use the stoichiometric ratio to find the moles of calcium carbonate needed.
To convert grams of hydrochloric acid to moles, we need to divide the given mass by the molar mass of HCl. The molar mass of HCl is 36.5 g/mol.
15.0 g HCl / 36.5 g/mol HCl = 0.411 moles HCl
Since the stoichiometric ratio is 1:1 for calcium carbonate and hydrochloric acid, we can conclude that 0.411 moles of calcium carbonate would be needed to react completely with 15.0 grams of hydrochloric acid.
Now, to convert moles of calcium carbonate to grams, we need to multiply the moles by the molar mass of \(CaCO_{3}\). The molar mass of \(CaCO_{3}\) is 100.1 g/mol.
0.411 moles \(CaCO_{3}\)* 100.1 g/mol \(CaCO_{3}\)= 41.1 grams \(CaCO_{3}\)
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how many cards must be selected from a standard deck of 52 cards to guarantee that at least three cards of the same (matching) suit are chosen
Answer:
Step-by-step explanation:
17
4. what is the slope in the regression equation, and how should this number be interpreted in the context of hurricane wind speed and central pressure?
The slope in the regression equation is the coefficient that represents the change in the response variable (in this case, hurricane wind speed) for every one-unit increase in the predictor variable (central pressure).
In the context of hurricane wind speed and central pressure, the slope represents the strength of the relationship between these two variables. A higher slope value indicates a stronger relationship between central pressure and wind speed, meaning that changes in central pressure have a larger impact on wind speed. Therefore, the slope is an important factor to consider when predicting or analyzing hurricane intensity.
In the context of hurricane wind speed and central pressure, the slope in the regression equation represents the relationship between the two variables. It shows how much the wind speed changes with respect to a change in central pressure.
To interpret the slope in this context, follow these steps:
1. Obtain the regression equation for the data on hurricane wind speed and central pressure. This equation will be in the form of y = mx + b, where y is the wind speed, x is the central pressure, m is the slope, and b is the y-intercept.
2. Identify the slope (m) in the equation. The slope represents the change in wind speed for every unit change in central pressure.
3. Interpret the slope value: If the slope is positive, it means that as central pressure increases, wind speed also increases. If the slope is negative, it indicates that as central pressure increases, wind speed decreases. The magnitude of the slope shows the strength of this relationship.
In conclusion, the slope in the regression equation between hurricane wind speed and central pressure helps us understand how the wind speed changes with respect to changes in central pressure, allowing for better prediction and analysis of hurricane behavior.
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I want to know What is x=,y=,z=
Answer:
x=31 y=44 z=105
Step-by-step explanation:
Using the angle relationships, we know that 31 is equal to x, y is equal to 44 and z is equal to 105
Let us suppose a population size of 67 million, and innovation parameter of 0.005 and imitation parameter of 0.84 for Color TV. Estimate how many new users would be added during time period 7.
To estimate the number of new users that would be added during time period 7, we can use the Bass diffusion model, which is commonly used to model the adoption of new products or technologies.
The Bass diffusion model is given by the formula:
\(\[N(t) = \frac{{p \cdot q}}{{q + (p/q) \cdot e^{-((p+q) \cdot t)}}}\]\)
where:
- N(t) represents the cumulative number of adopters at time \(t\).
- p is the innovation parameter, representing the coefficient of innovation.
- q is the imitation parameter, representing the coefficient of imitation.
- e is the base of the natural logarithm.
Given a population size of 67 million, an innovation parameter of 0.005, and an imitation parameter of 0.84 for Color TV, we can substitute these values into the Bass diffusion model and calculate the number of new users added during time period 7.
\(\[N(7) - N(6) = \frac{{p \cdot q}}{{q + (p/q) \cdot e^{-((p+q) \cdot 7)}}} - \frac{{p \cdot q}}{{q + (p/q) \cdot e^{-((p+q) \cdot 6)}}}\]\)
Substituting the given values into the equation:
\(\[N(7) - N(6) = \frac{{0.005 \cdot 0.84}}{{0.84 + (0.005/0.84) \cdot e^{-((0.005+0.84) \cdot 7)}}} - \frac{{0.005 \cdot 0.84}}{{0.84 + (0.005/0.84) \cdot e^{-((0.005+0.84) \cdot 6)}}}\]\)
Evaluating the expression will give us the estimated number of new users added during time period 7.
In LaTeX, the solution can be represented as:
\(\[N(7) - N(6) = \frac{{0.005 \cdot 0.84}}{{0.84 + (0.005/0.84) \cdot e^{-((0.005+0.84) \cdot 7)}}} - \frac{{0.005 \cdot 0.84}}{{0.84 + (0.005/0.84) \cdot e^{-((0.005+0.84) \cdot 6)}}}\]\)
After evaluating this expression, you will obtain the estimated number of new users added during time period 7.
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if you had a list of only the day of the week for each accident, what day would be the modal day for each type of road?
Based on the given table data, the modal day for built-up roads will be Friday and for non-built-up roads will be Sunday.
The modal day for each type of road would be the day of the week that has the highest frequency of accidents. The modal day would be the day of the week that appears most often on the list of accident days for each type of road.
To determine the modal day, you would need to count the number of times each day of the week appears on the list for each type of road. The day with the highest count would be the modal day for that type of road. For example, if Monday appears 5 times, Tuesday appears 3 times, and Wednesday appears 7 times on the list for a particular type of road, then Wednesday would be the modal day for that type of road.
It is important to note that there could be more than one modal day if two or more days have the same highest frequency. For example, if Monday and Wednesday both appear 5 times on the list for a particular type of road, then both Monday and Wednesday would be the modal days for that type of road.
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Complete Question:
The Scottish Executive, Analytical Services Division Transport Statistics, compiles data on motorcycle accidents in Scotland were tabulated by day of the week for built-up roads and non-built-up roads and resulted in the following data.
(Please refer to the attached table below)
c. If you had a list of only the day of the week for each accident, what day would be the modal day for each type of the road?
Compute the length of the curve r(t)=⟨4cos(5t),4sin(5t),t^3/2) over the interval 0≤t≤2π.
The length of the curve r(t) over the interval 0 ≤ t ≤ 2π is approximately 285.97 units.
The length of the curve given by the vector-valued function r(t) over the interval [a, b] is given by the formula:
L = ∫[a,b] ||r'(t)|| dt
where r'(t) is the derivative of r(t) with respect to t and ||r'(t)|| is its magnitude.
In this case, we have:
r(t) = ⟨4cos(5t), 4sin(5t), t^(3/2)⟩
r'(t) = ⟨-20sin(5t), 20cos(5t), (3/2)t^(1/2)⟩
||r'(t)|| = √( (-20sin(5t))^2 + (20cos(5t))^2 + ((3/2)t^(1/2))^2 )
||r'(t)|| = √( 400sin^2(5t) + 400cos^2(5t) + (9/4)t )
||r'(t)|| = √( 400 + (9/4)t )
So the length of the curve over the interval [0, 2π] is:
L = ∫[0,2π] √( 400 + (9/4)t ) dt
Making the substitution u = 20t^(1/2)/3, we get:
du/dt = 10t^(-1/2)/3
dt = (3/10)u^(-1/2) du
When t = 0, u = 0, and when t = 2π, u = 20√(π)/3. Substituting these values and simplifying, we get:
L = ∫[0,20√(π)/3] √( 1 + u^2 ) du
Using the substitution x = sinh(u), we get:
dx/dt = cosh(u)
dt = dx/cosh(u)
When u = 0, x = 0, and when u = 20√(π)/3, x = sinh(20√(π)/3). Substituting these values and simplifying, we get:
L = ∫[0,sinh(20√(π)/3)] √( 1 + sinh^2(x) ) dx
L = ∫[0,sinh(20√(π)/3)] cosh(x) dx
Using the formula for the integral of cosh(x), we get:
L = sinh(sinh(20√(π)/3)) - sinh(0)
L ≈ 285.97
Therefore, the length of the curve r(t) over the interval 0 ≤ t ≤ 2π is approximately 285.97 units.
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Y=-5x +6 Y= 3x -2 Find the solution to the system of equations
X = _____
Y= _____
Answer:
x=1, y=1. (1, 1).
Step-by-step explanation:
y=-5x+6
y=3x-2
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-5x+6=3x-2
-5x-3x+6=-2
-8x+6=-2
-8x=-2-6
-8x=-8
8x=8
x=8/8=1
y=3(1)-2=3-2=1