Answer:
can u repost the question properly
Answer:
It's a fact
Explanation:
There are different types of sciences for every problem that could happen on earth
a 2.0-cm c m -tall object is 22 cm c m to the left of a lens with a focal length of 11 cm c m . a second lens with a focal length of 6.0 cm c m is 34 cm c m to the right of the first lens. part a calculate the image position relative to the second lens
The image position relative to the second lens is 12 cm to the left of the second lens.
To calculate the image position relative to the second lens, first, we need to find the object distance, u from the first lens. We know that the distance of the object from the first lens is given by the formula:
1/f = 1/u + 1/v
We can rearrange the formula as:
v = uf / (u - f)
where u is the distance of the object from the first lens and f is the focal length of the lens.
Thus:
u = -22 cmf = -11 cm (since the lens is a diverging lens)
v = ?v = uf / (u - f) = (-22) x (-11) / (-22 - (-11))= 22 x 11 / 11 = 22 cm
The image formed by the first lens becomes the object for the second lens. Thus, the object distance, u2 is:
u2 = 34 - 22 = 12 cm
Using the formula for image formation:
1/f2 = 1/u2 + 1/v2
v2 = u2 f2 / (u2 - f2)
Where f2 = -6 cm (diverging lens), we have:
v2 = u2 f2 / (u2 - f2) = (12) x (-6) / (12 - (-6)) = -72 / 6 = -12 cm
The image is formed 12 cm to the left of the second lens.
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SOMEONE PLS HELP!!! THIS IS HARD!!! I will make brainliest and this is in science!
Answer: It has the skill to nest
sorry if I'm wrong
Answer:
B: A colorful beak
Explanation:
i hope this helped!
Explain why using a ladder or plank will help to prevent damage to the
roof.
Answer:
it reduces pressure
Explanation:
use of ladder / plank makes the pressure applied to uniformly distributed to all part hence increase surface area
pls I need answers urgently, I will give 30 point for it
According to the parallelogram law of vector addition, the consequent of two vectors is given by the diagonal vector that passes through the point of contact of the two vectors if the two vectors are thought of as the adjacent sides of a parallelogram.
What is Parallelogram law of Vector?In vector theory, there is a technique for calculating the sum of two vectors called the parallelogram law of vector addition. The triangle law of vector addition and the parallelogram law of vector addition are the two laws for the addition of vectors that we investigate. When two vectors create the two adjacent sides of a parallelogram by merging their tails, the parallelogram law of vector addition is used to add the two vectors. The diagonal of the parallelogram is then used to calculate the sum of the two vectors.
Now, according to the question :
θ= arc cos (4/6)
θ= 48.7°
v = √6²-4²
v = 4.5 km/hr
t = 5/4.5
t =1.1 hr.
So the time take to cross the river will be 1.1 hr.
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An arch carries the thrust of weight to its _____(1)______. With a _____(2)______, the horizontal part of the structure supports all the weight above it. A. (1) center; (2) post-and-bearing b. (1) base; (2) springing line c. (1) keystone; (2) groin vault d. (1) sides; (2) post-and-lintel Please select the best answer from the choices provided A B C D.
Option D is correct. An arch carries the thrust of weight to its sides with a post-and-lintel.
What is an arch?
An arch is indeed a vertical curving construction that covers an elevated space that may or may not sustain the load above it or the pressure gradient against it
In the case of a horizontally arched, such as an embankment dam. While arches and vaults are often confused, A vault is defined as an ongoing arch forming a roof.
Option D satisfies the fill-in blanks option.
Hence option D is correct. An arch carries the thrust of weight to its sides with a post-and-lintel.
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A golf ball rolls off a horizontal cliff with an initial speed of 10.2 m/s. The ball falls a vertical distance of 12.3 m into a lake below. How much time does the ball spend in the air? (b) What is the speed v of the ball just before it strikes the water? (a) Number Units (b) Number Units
The golf ball spends approximately 1.46 seconds in the air before hitting the water. Just before striking the water, its speed is approximately 18.84 m/s.
We can solve this problem by analyzing the motion of the golf ball in the vertical and horizontal directions separately. In the vertical direction, the ball falls a distance of 12.3 m due to gravity. We can use the equation of motion for vertical motion, which is given by:
\(h = (1/2)gt^2\)
where h is the vertical distance, g is the acceleration due to gravity (approximately 9.8 \(m/s^2\)), and t is the time. Rearranging the equation, we can solve for t:
\(t = \sqrt(2h / g) = \sqrt(2 * 12.3 / 9.8)\) ≈ 1.46 s
Therefore, the ball spends approximately 1.46 seconds in the air.
In the horizontal direction, the ball rolls off the cliff with an initial speed of 10.2 m/s. Since there are no horizontal forces acting on the ball, its horizontal speed remains constant throughout the motion. Therefore, the horizontal speed just before the ball strikes the water is also 10.2 m/s.
Combining the vertical and horizontal components of motion, we can find the resultant velocity just before the ball hits the water using the Pythagorean theorem:
\(v = \sqrt(v_{horizontal}^2 + v_{vertical}^2) = \sqrt(10.2^2 + 0)\) ≈ 10.2 m/s
Therefore, the speed of the ball just before it strikes the water is approximately 18.84 m/s.
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A student shoots a basketball in gym class. What pair of forces are acting on the ball and student? What
happens to the ball, and the student?
The pair of forces acting on the ball and student are the action and reaction forces.
What is a Force?This causes an object with mass to change its velocity. The pair of forces are the action and reaction forces.
The student exerts the force on the basketball and the ground with a corresponding reaction force from both acting on the student too.
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What cause sound seismic and electromagnetic waves to transmit energy through different mediums
Answer:
Explanation:
Sound, seismic, and electromagnetic waves transmit energy through different mediums due to the motion of particles in the medium.
Sound waves transmit energy through the vibration of particles in a solid, liquid, or gas. The energy is transferred from particle to particle as the wave travels through the medium.
Seismic waves are created by the sudden release of energy from earthquakes, volcanic eruptions, or other geological events. These waves travel through the Earth's solid mantle and crust, transmitting energy through the vibration of particles in the rock.
Electromagnetic waves are a type of wave that does not require a medium to travel through. They are created by the motion of charged particles, such as electrons, and can travel through a vacuum, such as space. Electromagnetic waves transfer energy through the oscillation of electric and magnetic fields.
A small object begins a free-fall from a height of =81.5 m at 0=0 s . After τ=2.20 s , a second small object is launched vertically up from the ground with an initial velocity of 0=40.0 m/s . At what height from the ground will the two objects first meet?
Answer:
33.23 m
Explanation:
At the point where both objects will meet, the vertical height will be equal.
From the equations of motion, the vertical height of the body falling at any time is given as
(y - y₀) = ut + ½gt²
y = vertical height at any time T
y₀ = initial height of the object = 81.5 m
u = initial velocity = 0 m/s (body was dropped)
g = -9.8 m/s²
(y - 81.5) = 0 - 4.9T²
y = 81.5 - 4.9T² (eqn 1)
For an object thrown up, the vertical height of the body at any time, t, is given as
(y - y₀) = ut + ½gt²
y = vertical height of the object at any time t
y₀ = initial height of the object = 0 m
u = initial velocity = 40 m/s
g = -9.8 m/s²
y = 40t - 4.9t² (eqn 2)
At the point where the two objects meet, we equate eqn 1 and eqn 2
y = y
81.5 - 4.9T² = 40t - 4.9t²
But T = (t + 2.2) (Since object 2 was dropped 2.2 s after object 1)
81.5 - 4.9(t + 2.2)² = 40t - 4.9t²
81.5 - 4.9(t² + 4.4t + 4.84) = 40t - 4.9t²
81.5 - 4.9t² - 21.56t - 23.716 = 40t - 4.9t²
81.5 - 21.56t - 23.716 - 40t = 0
57.784 = 61.56t
t = (57.784/61.56) = 0.93866 = 0.94 s
Therefore, the vertical height at t = 0.93866 s is
y = (40×0.93866) - 4.9(0.93866²) = 33.23 m
Hope this Helps!!!
The current in a light bulb is 0. 835A. How long does it take for a total charge of 1. 67 C to pass a point in the wire
It takes 2 seconds for the charge to pass a point in the wire. The result is obtained by using the formula for an electric current equation.
What is electric current?Electric current is a flow of charged particles per unit of time. It can be expressed as
I = Q/t
Where
I = electric current (A)Q = charge (C)t = time (s)A light bulb has
Electric current, I = 0.835 A.Total charge, Q = 1.67 C.Find the time taken!
We use the formula above to find t.
I = Q/t
0.835 = 1.67/t
t = 1.67/0.835
t = 2 s
Hence, the time needed to for the charge to pass a point in the wire is 2 seconds.
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a beam of light strikes an air/water surface. water has an index of refraction of 1.33. the angle of incidence is 4.00 degrees. what is the angle of reflection?
The angle of reflection, for a beam of light strikes an air/water surface at angle of incidence 4.00 degrees is, 2.88 degrees.
Assuming that the incident beam of light is coming from air, we can use the law of reflection and Snell's law to find the angle of reflection:
The law of reflection states that the angle of incidence is equal to the angle of reflection, so:
\(\theta_{i} = \theta_{r}\)
where \(\theta_{i}\) is the angle of incidence and \(\theta_{r}\) is the angle of reflection.
Snell's law relates the angles of incidence and refraction to the refractive indices of the two media:
n₁sinθ₁ = n₂sinθ₂
where n₁ and n₂ are the refractive indices of the two media (air and water, respectively), and θ₁ and θ₂ are the angles of incidence and refraction, respectively.
We can rearrange Snell's law to solve for θ₂:
θ₂ = sin⁻¹[(n₁/n₂)sinθ₁]
Plugging in the values given in the problem:
n₁ = 1 (refractive index of air)
n₂ = 1.33 (refractive index of water)
θ₁ = 4.00 degrees
θ₂ = sin⁻¹[(1/1.33)sin(4.00°)]
θ₂ = 2.88°
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3. We consider a conducting sphere of radius R consisting of two hemispheres. The upper hemisphere is kept at the potential V while the lower hemisphere is kept at the potential −V. We can use the Green function method to calculate the scalar potential ϕ. The Dirichlet Green function G p
(r,r ∗
) is given as follows: G D
(r,r ′
)= r 2
+r ′2
−2rr ′
cosγ
1
− r 2
r ′2
/R 2
+R 2
−2rr ′
cosγ
1
The r vector denotes the position of observation and the r ′
vector denotes the position of charges where γ is the angle between r and r ∗
. Using the above Green function. calculate the potential along the positive z-axis.
By integrating the given equation, we can find the potential ϕ as a function of z.
Let's consider a point P along the positive z-axis with coordinates (0, 0, z). To find the potential at point P, we integrate the Green function G_D(r, r') with respect to the charge distribution over the surface of the conducting sphere.
The potential ϕ at point P can be calculated using the following integral:
ϕ(P) = ∫∫ G_D(r, r') σ(r') dS
Here, σ(r') represents the charge density on the surface of the sphere, and dS represents the differential surface element.
Since we are interested in the potential along the positive z-axis, we can simplify the integral by considering the symmetry of the problem. Due to symmetry, the potential ϕ will only depend on the radial distance r from the z-axis. Thus, we can rewrite the integral as:
ϕ(P) = 2π∫ G_D(r, r') σ(r') r' dr'
Now, we need to express the charge density σ(r') in terms of the potential difference V and the radius R. The charge density on the upper hemisphere is V/(4πR^2), and on the lower hemisphere, it is -V/(4πR^2). Therefore, we can write:
ϕ(P) = (V/R^2) ∫ (r^2 + r'^2 - 2rr')/(r-r')^2 r' dr'
This integral can be evaluated using appropriate techniques of integration.
By integrating the above equation, we can find the potential ϕ as a function of z.
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The S.I. unit of E is NC^-1 and that of B is NA^-1 m^-1, then unit of E/B is
The S.I. unit of E is NC^-1 and that of B is NA^-1 m^-1, then unit of E/B is A m/C (ampere meter per coulomb). This unit represents the ratio between the electric field and the magnetic field, indicating the strength and direction of the electromagnetic field.
The SI unit of electric field (E) is NC^(-1) (newton per coulomb) and the SI unit of magnetic field (B) is NA^(-1) m^(-1) (tesla). To determine the unit of E/B, we need to divide the unit of E by the unit of B.
Dividing the unit of E (NC^(-1)) by the unit of B (NA^(-1) m^(-1)), we can simplify the expression:
E/B = (NC^(-1))/(NA^(-1) m^(-1))
To simplify this expression, we can cancel out the common units in the numerator and denominator:
E/B = (N/C)/(N/(A m))
Now, let's simplify further by dividing the numerator and denominator:
E/B = (N/C) * (A m/N)
Canceling out the common units:
E/B = (A m)/(C)
Therefore, the unit of E/B is A m/C (ampere meter per coulomb).
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The universe could be considered an isolated system because
many people think that no energy or matter exists outside the universe
energy and matter are created in the universe and flow freely into and out of the universe
energy is created outside the universe and matter is created within the universe
energy is created in the universe and matter is transferred out of the universe
Answer:
A(many people think that no energy or matter exists outside the universe)
Explanation:
1. A 0.1 mm diameter glass tube is inserted into a ethyl alcohol at 20 degree centigrade in a cup. How much does the Glycerin rise in the tube. The angle of alcohol with tube is 0 degree. D=0.1 mm=0.001 m 0∘ alcohol angel 20∘ ethyl alcohol η=1.1×10^−3 N⋅sec/ m^2sg=.0.79
A 0.1mm diameter glass tube is inserted into an ethyl alcohol at 20 degrees centigrade in a cup. The angle of alcohol with the tube is 0 degrees. D = 0.1 mm = 0.001m, alcohol angle is 0 degrees, ethyl alcohol
\(η=1.1×10^-3 N⋅sec/ m², s_g\)
=0.79.
We have to determine how much glycerin rises in the tube. The force that moves the liquid through the tube is the difference between the downward force of gravity on the liquid column and the upward capillary force produced by the surface tension of the liquid against the walls of the tube.
The height to which the fluid rises in a capillary tube may be measured by balancing the capillary force against the force of gravity on the column.
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Which element on the periodic table fights dandruff, directs drivers, and makes copies of your homework?
Answer:
Talc is the known mineral
A block is hung by two ropes angled at 30º and 60º respectively. What is the ratio of the tension in the second rope to the tension in the first rope?
A solenoid with a length of 6.5 cm and 200 loops is carrying 5 A of current. What is the
strength of the magnetic field at the center of the solenoid? Label the north and south pole of
the solenoid.
The strength of the magnetic field at the center of the solenoid is 0.006 T
Magnetic field calculation.
The strength of the magnetic field at the center of a solenoid is given by:
B = μ₀ * n * I
where B is the magnetic field strength, μ₀ is the permeability of free space, n is the number of turns per unit length of the solenoid, and I is the current flowing through the solenoid.
In this case, the length of the solenoid is not given, but we can assume that it is much greater than the diameter of the solenoid, so we can treat it as a long solenoid. The number of turns per unit length is given as 200 loops divided by the length of 6.5 cm, or:
n = 200 / 0.065 m = 3076.92 turns/m
The current flowing through the solenoid is 5 A.
The permeability of free space, μ₀, is a constant with a value of 4π x 10^-7 T m/A.
Therefore, the magnetic field strength at the center of the solenoid is:
B = μ₀ * n * I
= 4π x 10^-7 T m/A * 3076.92 turns/m * 5 A
= 0.006 T
So the strength of the magnetic field at the center of the solenoid is 0.006 T. The north pole of the solenoid is the end from which the magnetic field emerges, and the south pole is the end where it enters.
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How many moles of a gas sample are in a 5.0 l container at 373 k and 203 kpa?
In a 5.0 L container at 373 K and 203 KPa there is 0.327 mol of a gas sample.
Ideal gas lawThe number of moles of a gas sample in a container can be calculated using the ideal gas law, which is represented by the equation PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature.
Given the volume (V) of the container as 5.0 L, the temperature (T) as 373 K, and the pressure (P) as 203 kPa, we can rearrange the ideal gas law equation to solve for the number of moles (n) as follows:
n = PV/RT
Substituting the given values into the equation, we get:
n = (203 kPa)(5.0 L)/ (8.314 L*kPa/K*mol)(373 K)
n = 1015 kPa*L / (8.314 L*kPa/K*mol)(373 K)
n = 0.327 mol
Therefore, the number of moles of the gas sample in the 5.0 L container at 373 K and 203 kPa is 0.327 mol.
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Someone HELP if the displacement is in the start and it ends in the same spot then would It be 0?
Answer:
Yes
Explanation:
Displacement is equal to the final position of X minus the initial position of X.
Explain the difference between weight and mass.
Answer:
Mass is a measure of how much force it will take to change that path. ... Weight, on the other hand, is a measure of the amount of downwards force that gravity exerts on an object. This force increases with the object's mass: the more inertia it has, the harder gravity pulls.
Explanation:
What will happen to the force between the two magnets if they are pulled apart?
Answer:
It decreases
Explanation:
The force decreases because its getting pulled apart
why does the doppler method generally allow us to determine only minimum planetary masses?
The doppler method, also known as radial velocity method, involves measuring the slight wobbling motion of a star caused by the gravitational pull of its orbiting planets.
This method allows us to determine the minimum planetary mass by measuring the minimum amount of wobbling motion of the star. However, the maximum mass of the planet cannot be determined through this method because it is dependent on the inclination angle of the planet's orbit relative to our line of sight. Without this information, we can only determine the minimum planetary masses using the Doppler method.
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The mirror of Michelson Interferometer is moved a length equal to the wavelength of the incident light. Find the shift in fringes.
The shift in fringes is equal to 1. This means that the position of the fringes has shifted by one full fringe.
A Michelson interferometer is a type of interferometer that divides a wavefront by splitting a beam of light into two perpendicular paths.
By combining these waves, interference occurs, resulting in a pattern of bright and dark fringes known as an interferogram.
Therefore, let’s find the shift in fringes when the mirror of Michelson Interferometer is moved a length equal to the wavelength of the incident light.
First, it is important to note that the number of fringes observed in an interferometer depends on the wavelength of light being used, as well as the path difference between the two beams.
The following equation is used to calculate the number of fringes shifted:ΔN = ΔL/λwhere:ΔN = number of fringes shiftedΔL = distance moved by the mirrorλ = wavelength of light.
When the mirror is moved a distance equal to the wavelength of the incident light, the path difference between the two beams is equal to one wavelength.
Thus, there will be a shift of one fringe as a result.
Substituting the values into the equation, we have:ΔN = (1λ)/λΔN = 1
Therefore, the shift in fringes is equal to 1.
This means that the position of the fringes has shifted by one full fringe.
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Picking up a puppy is easy, but picking up a large horse is difficult. *
1st law
2nd law
3rd law
Answer:
1st
Explanation:
It is because the horse is heavier
Apply the Pauli exclusion principle to determine the number of electrons that could occupy the quantum states described by the following.
(a)
n = 4,
ℓ = 1,
mℓ = −1
_____ electrons
(b)
n = 4,
ℓ = 3
____ electrons
The number of electrons that could occupy the quantum states described by n = 4, ℓ = 1, and mℓ = −1 is 2.
(a) The quantum numbers given represent the 4p orbital. According to the Pauli exclusion principle, each orbital can accommodate a maximum of two electrons with opposite spins.
The number of electrons that could occupy the quantum states described by n = 4 and ℓ = 3 is 14.
(b) The quantum numbers given represent the 4f subshell. The number of orbitals in the 4f subshell is 7, and each orbital can accommodate a maximum of 2 electrons with opposite spins.
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an astronaut has a momentum of 280 kg and travels 10 m/s. what is the mass of the astronaut?
Answer:
The answer is
28 kgExplanation:
The mass of an object given it's momentum and velocity / speed can be found by using the formula
\(m = \frac{p}{v} \\ \)
where
m is the mass
p is the momentum
v is the speed or velocity
From the question
p = 280 kg/ms
v = 10 m/s
The mass of the object is
\(m = \frac{280}{10} = 28 \\ \)
We have the final answer as
28 kgHope this helps you
Compounds are substances in which two or more atoms are chemically combined to form a new,
pure substance. Which of the following substances is NOT a compound
If you can please help with both if you can
\(H_2\) (hydrogen) is not a compound because it's not made of more than one element. Yes we have more than one component, but both components are of the same element H.
Something like \(CO_2\) is a compound because it's made of carbon and oxygen (specifically 1 carbon and 2 oxygen), so we have at least two different elements here.
The current supplied by a battery as a function of time is I(t) = (0.64A) * e ^ (- (6hr)) What is the total number of electrons transported from the positive electrode to the negative electrode from the time the battery is first used until it is essentially dead? (e = 1.6 * 10 ^ - 19 * C)
please answer quickly
To calculate the total number of electrons transported from the positive electrode to the negative electrode, we need to integrate the current function over the time interval during which the battery is in use.
The current function is given as I(t) = (0.64A) * e^(-6t), and we need to find the integral of this function.
To calculate the total number of electrons transported, we can integrate the current function I(t) over the time interval during which the battery is used. The integral represents the accumulated charge, which is equivalent to the total number of electrons transported.
The integral of the current function I(t) = (0.64A) * e^(-6t) with respect to time t will give us the total charge transported. To perform the integration, we need to determine the limits of integration, which correspond to the starting and ending times of battery usage.
Once we have the integral, we can divide it by the elementary charge e = 1.6 * 10^-19 C to convert the accumulated charge to the total number of electrons transported.
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Construct and present arguments using evidence to support the claim that gravitational interactions are attractive and depend on the masses of interacting objects.
Response:
The evidence is clear: gravitational interactions are attractive and depend on the masses of the objects involved. This can be seen in the way that objects with mass are attracted to each other and in the way that planets orbit around the sun.
First, consider the fact that objects with mass are attracted to each other. This is the fundamental concept of gravity, and it is what causes objects to fall to the ground when dropped. If two objects with mass are placed near each other, they will experience a gravitational force of attraction that pulls them together. This force is proportional to the masses of the two objects - the more massive an object is, the stronger the gravitational force it will experience.
This dependency of gravitational force on mass is also evident in the orbits of planets around the sun. The sun is much more massive than any of the planets, and this causes the planets to experience a strong gravitational force of attraction that keeps them in orbit around the sun. The strength of this force depends on the masses of the sun and the planets - the more massive the planet, the stronger the gravitational force it experiences and the more tightly it is held in its orbit.
These examples demonstrate that gravitational interactions are attractive and depend on the masses of the objects involved. This is a fundamental property of gravity, and it is supported in many studies.