Answer:
No its not a metal
Explanation:
Answer:
NO
Explanation:
nonmetal on the right side of the periodic table
what are organisms competing for in the environment?
Answer:
survival
Explanation:
Organisms actually compete for food , water and slot but all this things lead to survival . so organisms are actually competing for survival
Determine the LIMITING reactant in the following balanced equation:
2KBr + CI2 --> 2KCI+ Br2, when 4g of KBr react with 6 g of CI . MM(KBr)=
119 g/mol MM(CI2)=70 g/mol *
Answer:
KBr is limiting reactant.
Explanation:
Given data:
Mass of KBr =4g
Mass of Cl₂ = 6 g
Limiting reactant = ?
Solution:
Chemical equation:
2KBr + Cl₂ → 2KCl + Br₂
Number of moles of KBr:
Number of moles = mass/molar mass
Number of moles = 4 g/ 119 gmol
Number of moles = 0.03 mol
Number of moles of Cl₂:
Number of moles = mass/molar mass
Number of moles = 6 g/ 70 gmol
Number of moles = 0.09 mol
Now we will compare the moles of reactant with product.
KBr : KCl
2 : 2
0.03 : 0.03
KBr : Br₂
2 : 1
0.03 : 1/2×0.03= 0.015
Cl₂ : KCl
1 : 2
0.09 : 2/1×0.09 = 0.18
Cl₂ : Br₂
1 : 1
0.09 : 0.09
Less number of moles of product are formed by the KBr thus it will act as limiting reactant while Cl₂ is present in excess.
Choose all the answers that apply.
Plasma is made of _____.
ions
clumped atoms
neutral atoms
free electrons
free protons
Answer:
neutral atoms
Explanation:
Below is the structure for the amino acid glycine. Which bond angles are closest to the actual values for the h-n-c and o-c-o bond angles? consider all lone pairs of electrons as substituents when answering this question.
We have that the bond angles that are closest to the actual values for the h-n-c and o-c-o bond angles are
109.5 degrees.120 degrees.H-N-C and O-C-O bond anglesGenerally, In H-N-C bond nitrogen has Sp3 hybridization, it will have the angle 109.5 degrees.
In O-C-O bond C atom has sp^2 Hybridization so it will have the angle by 120 degrees.
Therefore,bond angles that are closest to the actual values for the h-n-c and o-c-o bond angles are
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in the titration of acetic acid and naoh, the use of the color indicator mandates that excess base be present to detect the reaction endpoint. will this cause the calculated and reported molarity of acetic acid in vinegar to be slightly high or low?
In the titration of acetic acid and NaOH, the use of the color indicator mandates that excess base be present to detect the reaction endpoint. This cause the calculated and reported molarity of acetic acid in vinegar to be slightly higher
Titration is the process of the reaction between acids and bases in which a reaction is carried out under controlled conditions. One of the reactant titrants is added to an analyte. The concentration of the analyte is determined by the concentration of the titrant.
The equivalence point is the point at which equivalent quantities of reactants have been mixed. For an acid-base reaction, the equivalence point is where the moles of acid and the moles of the base would neutralize each other. At the equivalence point, the number of H⁺ ions is equal to the number s OH⁻ ions and is done visually with an indicator that changes the color at the equivalent point and it shows that titration has been accomplished, resulting in a slightly higher calculated molarity of acetic acid and a higher reported volume percent of acetic acid.
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I NEED HELP PLEASE, THANKS!
Electrochemistry is important in many aspects of daily life.
i. Define voltaic cell.
ii. Fill in the blanks for the drawing of a voltaic cell that’s made with copper/copper (II) nitrate (E° = 0.34 V) and zinc/zinc (II) nitrate (E° = –0.76 V). Briefly explain the role of the salt bridge.
iii. Using the equation E°cell = E°cathode – E°anode, calculate the overall cell potential for the cell.
iiii.
a. _____________
b. _____________
c. _____________
d. _____________
e. _____________
f. _____________
g. _____________
h. _____________
Answer:
Here's what I get
Explanation:
(i) Voltaic cell
A voltaic cell is a device that uses a chemical reaction to produce electrical energy.
(ii) Overall Cell Potential
The standard reduction potentials for the half-reactions are
ℰ°/V
Cu²⁺ + 2e⁻ ⇌ Cu 0.34
Zn²⁺ + 2e⁻ ⇌ Zn -0.76
The half-reaction with the more positive potential is the reduction half-reaction. It is the reaction that occurs at the cathode.
The half-reaction with the more negative potential is the oxidation half-reaction. It is the reaction that occurs at the anode.
We reverse that half-reaction and subtract the voltages to get the cell reaction.
ℰ°/V
Cathode: Cu²⁺ + 2e⁻ ⇌ Cu 0.34
Anode: Zn ⇌ Zn²⁺ + 2e⁻ -0.76
Cell: Zn + Cu²⁺ ⇌ Zn²⁺ + Cu 1.10
\(\mathcal{E}_{\text{cell}}^{\circ} = \mathcal{E}_{\text{cat}}^{\circ} - \mathcal{E}_{\text{an}}^{\circ} = \text{0.34 V} - \text{(-0.76 V)} = \text{0.34 V} + \text{0.76 V} = \textbf{1.10 V}\)
(iii) Diagram
The specific labels will depend on your textbook.
They are often as follows.
a. Electron flow
b. Voltmeter or lightbulb
c. Electron flow
d. Cathode or Cu
e. Cu²⁺(aq) and NO₃⁻(aq)
f. Salt bridge
g. Zn²⁺(aq) and NO₃⁻(aq)
h. Anode or Zn
The salt bridge enables ions to flow in the internal circuit and to maintain electrical neutrality in the two compartments.
It often consists of a saturated solution of KCl.
As Zn²⁺ ions form in the anode compartment, Cl⁻ ions move in to provide partners for them.
As Cu²⁺ ions are removed from the cathode compartment, K⁺ ions move in to replace them.
Answer:a. Electron flow
b. Voltmeter or lightbulb
c. Electron flow
d. Cathode or Cu
e. Cu²⁺(aq) and NO₃⁻(aq)
f. Salt bridge
g. Zn²⁺(aq) and NO₃⁻(aq)
h. Anode or Zn
Explanation:
Gas particles that are at low temperature and high pressure and are close to changing phases are considered:
a)Real Gases
b)Ideal Gases
c)Both Ideal and Real Gases
While visiting his uncle's farm, Derek learned that horses and donkeys are two different species. Based on this
information, what can Derek infer about horses and donkeys?
Horses and donkeys cannot survive in the same
environment.
Horses and donkeys produce fertile offspring.
Horses and donkeys are members of the same
population.
Horses and donkeys are members of different
populations.
While visiting his uncle's farm, Derek learned that horses and donkeys are two different species. Based on this information, Derek can infer that horses and donkeys are members of different populations.
Since horses and donkeys are different species, they belong to different populations. A population refers to a group of individuals of the same species that live in the same area and can interbreed. While horses and donkeys can mate, their offspring, known as mules, are usually infertile.
This means that mules cannot produce offspring of their own, which indicates that horses and donkeys are not members of the same population. In contrast, if they were members of the same population, they would be able to produce fertile offspring. Therefore, Derek can infer that horses and donkeys are members of different populations.
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I think colloids are
heterogeneous
because ____________
___________________
the particles do not dissolve completely..
The Chemical Formula For Lead(II) Nitrite Is: Pb(NO2) 2 How Many Oxygen Atoms Are In Each Formula Unit Of Lead (II) Nitrite?
The number of oxygen atoms in each formula unit of lead nitrite is equal to four.
What is the formula unit?A formula unit can be used to represent the lowest whole number ratio of ions in an ionic compound. The formula mass of an ionic compound is equal to the sum of the atomic masses of the ions in the formula unit.
A formula unit can be described as an empirical formula of any covalent or ionic compound that can be used as an independent entity for stoichiometric calculations.
Given the chemical formula of the Lead(II) nitrite is Pb(NO₂)₂. The number of oxygen atoms in each formula unit is four.
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WHAT IS THE STOCK NAME FOR FeSO^3
why is it better to use deionized water in chemistry experiments
A boy of mass 60 kg and a girl of mass 40 kg are together and at rest on a frozen pond. What is the initial momentum of the boy?
A. 0 kgm/s
B. 60 kgm/s
C. 100 kgm/s
D. 10 kgm/s
The initial momentum of the boy is 0 kgm/s the right option is A. 0 kgm/s.
Momentum can be defined as the product of mass and velocity. The S.I unit of momentum is kgm/s.
The initial momentum of the boy can be calculated using the formula below.
Formula:
M' = muWhere:
M = Initial momentum of the boyFrom the question,
Given:
M = mass of the boy = 60 kgU = Initial velocity of the boy = 0 m/s (at rest)Substitute these values into equation 1
M = 60(0)M = 0 kgm/sHence, The initial momentum of the boy is 0 kgm/s the right option is A. 0 kgm/s.
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In a chemical hot pack, iron powder and oxygen react to form iron oxide in the presence of a catalyst. This reaction causes the temperature of the hot pack to increase. This process is
Answer:
exothermic
Explanation:
exothermic reactions give off heat.....or the temp of the substances increases
1.00 g of carbon is combusted in a limited supply of pure oxygen. 0.50g of the carbon combusts
to form CO₂ and 0.50g of the carbon combusts to form CO.
The resultant mixture of CO₂ and CO is passed through excess NaOH(aq) and the remaining gas
is then dried and collected.
What is the volume of the remaining gas? (All gas volumes are measured at 25°C and
1 atmosphere pressure.)
A 1dm³
B 1.5 dm³
C 2 dm³
D 3 dm³
Answer:
Explanation:d
Humans process some foods by adding chemicals to reduce harmful bacterial growth. This allows foods to be edible for longer periods of time. Which best describes the advantages of food processing?.
According to the claim, one benefit of food processing is its capacity to lessen the growth of dangerous germs, which in turn prolongs the shelf life of food.
Thus, Extended Shelf Life: Perishable goods can have their shelf lives extended by using food processing procedures like canning, freezing, or adding preservatives. Customers may now preserve and enjoy these items for longer periods of time without worrying about them going bad.
Improved Food Safety: Food processing aids in lowering the risk of foodborne illnesses by employing chemicals and processing techniques that stop the growth of dangerous germs.
Thus, According to the claim, one benefit of food processing is its capacity to lessen the growth of dangerous germs, which in turn prolongs the shelf life of food.
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Matter is cycled throughout the stages of the carbon cycle by
Calculate the mass of 1.25 mol ammonium sulfide, (NH4)2S. *
Answer:
85g
Explanation:
To convert the moles of a substance to grams we need to know the molar mass of the substance. We, as first, must obtain the molar mass of (NH₄)₂S as follows:
There are 2 atoms of N, 8 of H and 1 of S:
N = 2*14g/mol = 28g/mol
H = 8*1g/mol = 8g/mol
S = 1*32g/mol = 32g/mol
Molar mass: 68g/mol
That means 1 mole of (NH₄)₂S has a mass of 68g.
1.25moles have a mass of:
1.25moles * (68g/mol) =
85gWhy is there a concentration gradient of NaCl in the medulla?
A) There is more NaCl as the filtrate leaves then ascending limb compared to when it enters the ascending limb. B) Passive transport in the ascending limb helps to establish an ion gradient. C) The water in the medulla dilutes the NaCl to help contribute to the gradient. D) There is more NaCl at the start of the ascending limb that decreases as the filtrate moves up the limb.
D) There is more NaCl at the start of the ascending limb that decreases as the filtrate moves up the limb.
What is filtrate?Filtrate is a liquid that has been passed through a filter or other filtration device. This process is used to separate the solid particles from the liquid, leaving a purified liquid behind.
Explanation: The concentration gradient of NaCl in the medulla is due to the movement of NaCl from the descending limb of the loop of Henle into the ascending limb. As the filtrate moves up the ascending limb, NaCl is actively transported out of the filtrate and into the interstitium of the medulla, thus leading to a decrease in the concentration of NaCl in the filtrate as it moves up the loop. This creates a concentration gradient of NaCl, with higher concentrations near the start of the ascending limb and lower concentrations as the filtrate moves up the loop.
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Imagine you are a scientist employed by a manufacturer of cookware like pots and pans. Which of the materials in the table would you use for a ceramic baking dish, and why?
Answer:
As a scientist employed by a manufacturer of cookware, I would recommend using alumina (Al2O3) as the material for a ceramic baking dish.
A container has 0.182 mol of CO₂ gas at STP. How many liters does the gas take up?
Answer:
4.08 L
Explanation:
At standard temperature and pressure, a mole of any gas equals 22.4 L.
We have 0.182 mol of CO₂ gas. We know that every mole of gas is 22.4 L, so
\(0.182mol*\frac{22.4L}{1mol} =4.08L\)
⇒ 4.08 L of CO₂ is the answer
SI Unit: Volume = 4.133 L of carbon dioxide
Non-SI Unit: Volume = 4.079 L carbon dioxide
Molar Volume of Gases:At STP conditions (Standard Temperature and Pressure), which is conditions at 100 kPa and at 0°C or 273.15 K, it is a given that the volume of 1 mole of ideal gas is 22.71 L.
\(\large \textsf{$\therefore$ if 1 mol of CO$_2$ = 22.71 L}\\\\\large \textsf{hence, 0.182 $\times$ 1 mol of CO$_2$ = 22.71 $\times$ 0.182}\\\\\large \textsf{$\implies$ \boxed{\boxed{$volume = 4.133 L of CO$_2}}}\)
Note: The value used for pressure above, 100 kPa (kilopascals), is a standard SI unit (International System of Units), used by most countries around the world.
However, another commonly used value for pressure (though not the preferred SI unit), is 1 atm (atmospheric pressure), which is equivalent to 101.325 kPa.
Using this value, the volume of 1 mole of ideal gas at STP is then 22.41 L. Solving this:
\(\large \textsf{if 1 mol of CO$_2$ = 22.41 L}\\\\\large \textsf{$\therefore$ 0.182 $\times$ 1 mol of CO$_2$ = 22.41 $\times$ 0.182}\\\\\large \textsf{$\implies$ \boxed{\boxed{$volume = 4.079 L CO$_2}}}\)
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10.10g of hydrated sodium sulfate decompose to form 4.40gg of anhydrous sodium sulfate on heating. Calculate the formula mass of hydrated sodium sulfate and the value of x:
Na2SO4X⇒Na2SO4+xH2O
Answer:
The given equation shows the decomposition of hydrated sodium sulfate to form anhydrous sodium sulfate:
$Na_2SO_{4 \cdot x} \rightarrow Na_2SO_4 + xH_2O$
From the given data, we know that 10.10 g of hydrated sodium sulfate decomposes to form 4.40 g of anhydrous sodium sulfate. Let's first calculate the number of moles of anhydrous sodium sulfate formed:
$Moles\ of\ Na_2SO_4\ =\ \frac{4.40\ g}{142.04\ g/mol} = 0.0310\ mol$
Since one mole of hydrated sodium sulfate produces one mole of anhydrous sodium sulfate, the number of moles of hydrated sodium sulfate present in 10.10 g can be calculated as:
$Moles\ of\ Na_2SO_{4 \cdot x}\ =\ 0.0310\ mol$
The formula mass of the hydrated sodium sulfate can be calculated by adding the molar masses of all its constituent atoms:
$Formula\ mass\ of\ Na_2SO_{4 \cdot x}\ =\ 2\times23.00\ g/mol\ +\ 32.06\ g/mol\ +\ x\times18.02\ g/mol = 142.04\ g/mol$
Solving for x, we get:
$x = \frac{142.04\ g/mol - 46.00\ g/mol - 32.06\ g/mol}{18.02\ g/mol} = 4$
Therefore, the formula of the hydrated sodium sulfate is $Na_2SO_{4 \cdot 4H_2O}$ and its formula mass is 322.20 g/mol.
LT.5c - ORGANIC REACTIONS + BIOMOLECULES - QUESTION 2
Which of the two molecules below should have a higher melting
point, and why?
OH
Molecule A
OH
Molecule B
Molecule A should have a higher melting point than Molecule B because it has more opportunities for intermolecular forces to occur due to its larger surface area and ability to participate in Van der Waals forces in addition to hydrogen bonding.
Both molecules have hydroxyl (-OH) groups, which are polar and capable of hydrogen bonding. However, the rest of the structures of the molecules are different. Molecule A has a long carbon chain, which means it has more surface area and more opportunities for Van der Waals forces to occur. Van der Waals forces are weaker than hydrogen bonding, but they can still contribute to the overall strength of the intermolecular forces.
Molecule B, on the other hand, has a cyclic structure, which means it has less surface area than Molecule A. In summary, the melting point of a molecule is dependent on the intermolecular forces between its molecules. In this case, Molecule A has a higher melting point than Molecule B due to its larger surface area and greater potential for intermolecular forces to occur.
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what example of matter is a mixture
Answer:
Most of the matter around us, however, consists of mixtures of pure substances. Air, wood, rocks and dirt are examples of such mixtures. Mixtures can be further classified as Homogeneous and Heterogeneous.
Word equation for Silver being added to sulphuric acid
Answer:
See the answer below
Explanation:
When silver is added to dilute sulphuric acid, no reaction would occur. However, silver reacts with hot and concentrated sulphuric acid to produce silver sulphate, sulphur dioxide, and water.
The equation of the reaction is as below:
silver + sulphuric acid --> silver sulphate + water + sulphur dioxide
\(2Ag(s) + 2 H_2SO_4(aq) -->Ag_2SO_4 (s) + 2 H_2O (l) + SO_2 (aq)\)
Which property of matter is an extensive, rather than an intensive, property of matter?
a- mass
b- luster
c- density
d- melting point
The property of matter that is an extensive Rather an intensive, property of matter is option A which is mass Because mass refer to substance that does not have a particular shape and can exist in different particles.
What is Matter?Matter can be define as any substance or particles that have weight or mass and also occupy space. Matter exist in different forms which are liquid, solid and gaseous forms.
There are different property of matter which include, mass, density, melting point, boiling point , luster, shape, color and so on.
Matter can be transformer from one form to another.
Therefore, The property of matter that is an extensive Rather an intensive, property of matter is option A which is mass because mass refer to substance that does not have a particular shape and can exist in different particles.
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PLEASE ANSWER SOON THIS IS DUE IN LIKE, 5-10 MINS
Which pair have the same electron configuration? You may use the periodic chart
Cl- and Ar
Cl and Ar
Cl- and Ar-
Cl+ and Ar
18.A helium balloon has a volume of 3.0 m^3at lift off where the air pressure is 1 atm and the temperature is 20°C. When airborne, the temperature decreases to −60°C and the volume expands to 120 m^3. What it the pressure at this alriftide?
The pressure when the helium balloon is airborne at a volume of 120 m³ and a temperature of -60°C is approximately 0.726 atm.
To solve this problem, we can use the ideal gas law, which states that:
PV = nRT
P is the pressure
V is the volume
n is the number of moles of gas
R is the ideal gas constant (8.314 J/(mol·K))
T is the temperature in Kelvin
First, let's convert the initial and final temperatures from Celsius to Kelvin:
Initial temperature (T1) = 20°C + 273.15 = 293.15 K
Final temperature (T2) = -60°C + 273.15 = 213.15 K
Next, we can set up two equations using the ideal gas law for the initial and final states:
P1 * V1 = n * R * T1
P2 * V2 = n * R * T2
Since the number of moles (n) and the gas constant (R) are constant, we can write:
P1 * V1 / T1 = P2 * V2 / T2
Now we can plug in the given values:
P1 * 3.0 m³ / 293.15 K = P2 * 120 m³ / 213.15 K
Simplifying the equation:
P1 / 293.15 = P2 / 213.15
Now we can solve for P2:
P2 = P1 * 213.15 / 293.15
Finally, we can substitute the initial pressure (P1) with the given value of 1 atm:
P2 = (1 atm) * 213.15 / 293.15
P2 ≈ 0.726 atm
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3. If a sample of gas occupies 6.80 L at 325oC, what will its volume be at 25oC if the pressure doesn't change
Answer:
V2 = 3.39
Explanation:
V1/T1 = V2/T2
V1 = 6.80L
T1 = 325C (must be convert to K by + 273.15) = 598.15 K
T2 = 25C = 298.15 K
V2 =?
T2xV1/T1 = V2
298.15 x 6.80/ 598.15 = V2
3.39 = V2
So 3.39 is the answer!
what is the maximum amount of carbon dioxide which can be formed if 15.2 g of glucose, c6h12o6 (molar mass
The maximum amount of carbon dioxide that can be formed from 15.2 g of glucose is approximately 22.31 grams.
To determine the maximum amount of carbon dioxide (CO2) that can be formed from 15.2 g of glucose (C6H12O6), we need to use the stoichiometry of the balanced chemical equation for the combustion of glucose.
The balanced chemical equation for the combustion of glucose is:
C6H12O6 + 6O2 -> 6CO2 + 6H2O
From the equation, we can see that 1 mole of glucose reacts with 6 moles of oxygen to produce 6 moles of carbon dioxide.
First, we need to calculate the number of moles of glucose in 15.2 g:
Molar mass of glucose (C6H12O6) = (12.01 g/mol x 6) + (1.01 g/mol x 12) + (16.00 g/mol x 6) = 180.18 g/mol
Moles of glucose = Mass of glucose / Molar mass of glucose = 15.2 g / 180.18 g/mol ≈ 0.0845 mol
Since 1 mole of glucose reacts with 6 moles of oxygen, we need to multiply the number of moles of glucose by 6 to determine the moles of oxygen:
Moles of oxygen = 0.0845 mol x 6 = 0.507 mol
Finally, since 1 mole of glucose produces 6 moles of carbon dioxide, we can calculate the maximum amount of carbon dioxide formed:
Moles of carbon dioxide = Moles of glucose x 6 = 0.0845 mol x 6 = 0.507 mol
To convert the moles of carbon dioxide to grams, we can multiply by the molar mass of carbon dioxide:
Molar mass of carbon dioxide (CO2) = (12.01 g/mol x 1) + (16.00 g/mol x 2) = 44.01 g/mol
Mass of carbon dioxide = Moles of carbon dioxide x Molar mass of carbon dioxide = 0.507 mol x 44.01 g/mol ≈ 22.31 g
Therefore, the maximum amount of carbon dioxide that can be formed from 15.2 g of glucose is approximately 22.31 grams.
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