is it the pair of angles are supplementary. m/A = 120° and m/B = 60°
​

According to Boltzmann reaction entropy difference between two states is given by ΔS and is equal to 5.76 .

According to Boltzmann Reaction:

 S= kB lnW

 Where,

W is number of Arrangements possible

Now ,

 ΔS = S(final) - S(initial)

S(initial) = kBln1 (Since only one arrangement is possible)

             = 0

Again,

 S(final) = kBln2^n

Now,

  As A-B can exist as A-B or B-A .

Hence, two arrangements are possible and since 1 mole of species .

Hence, 2^n

S(final) = N kB ln2

           =R ln 2

           = 8.314 ×2.303× log 2

Hence,

S(final) = 5.76

ΔS = 5.76 -0

      =5.76

Thus, from the above conclusion we can say that, according to Boltzmann reaction entropy difference between two states is given by ΔS and is equal to 5.76 .

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Answer:

Stem

Explanation:

Answer:

option-(d) stem

Explanation:

Stems have four main functions which are: Support for and the elevation of leaves, flowers and fruits. The stems keep the leaves in the light and provide a place for the plant to keep its flowers and fruits. Transport of fluids between the roots and the shoots in the xylem and phloem...

I hope it help you

Answer:

I would say you are correct.

Explanation:

Answer:

I believe it'll be A (even though you chose it already).

Explanation:

Answer:

A. 0.35 M

Explanation:

Hello,

In this case, given the volume and concentration of lithium hydroxide and the volume of chloric acid, we can compute the concentration of the neutralized acid by using the following equation:

\(n_{acid}=n_{base}\\\\V_{acid}M_{acid}=V_{base}M_{base}\\\\M_{acid}=\frac{V_{base}M_{base}}{V_{acid}} =\frac{46.9mL*0.75M}{100mL}\\ \\M_{acid}=0.35M\)

Therefore, answer is A. 0.35 M.

Regards.

Explanation:

They are called consumer testing or comparative testing, is a process of measuring the properties or performance of products. ... Product testing might be accomplished by a manufacturer, an independent laboratory, a government agency, etc. Often an existing formal test method is used as a basis for testing

hope this helps

Answer:

Product testing claims are called Consumer Testing .

Three uses of coal:

1. Electricity generation

2. Steel production

3. Cement manufacturing and as a liquid fuel

Hope it helps!

Answer:

I and Ii it is the answer the correct one

Answer:

Explanation:

nm

Answer:

uh yeah I think so technically

Answer:

no

Explanation:

Answer:Typically a decomposition reaction is endothermic. Use the decomposition of limestone (CaCO3) to draw an energy diagram for a decomposition reaction assuming it occurs at constant pressure.

Explanation:hope this helps

The compound is formed by 1 atom of gold and 3 atoms of chlorine.

In this case, the gold atom must have a charge of +3 in order to have a compound with a net charge of zero because the molecule Cl3 has a charge of -3. This is why the name of the compound is Gold(III) Chloride.

Answer:

Approximately \(2.46\; \rm mol\).

Explanation:

Make use of the molar mass data (\(M({\rm C_2H_2}) = 26.04\; \rm g \cdot mol^{-1}\)) to calculate the number of moles of molecules in that \(64.0\; \rm g\) of \(\rm C_2H_2\):

\(\begin{aligned}n({\rm C_2H_2}) &= \frac{m({\rm C_2H_2})}{M} \\ &= \frac{64.0\; \rm g}{26.04\; \rm g\cdot mol^{-1}}\approx 2.46\; \rm mol\end{aligned}\).

Make sure that the equation for this reaction is balanced.

Coefficient of \(\rm C_2H_2\) in this equation: \(2\).

Coefficient of \(\rm H_2O\) in this equation: \(2\).

In other words, for every two moles of \(\rm C_2H_2\) that this reaction consumes, two moles of \(\rm H_2O\) would be produced.

Equivalently, for every mole of \(\rm C_2H_2\) that this reaction consumes, one mole of \(\rm H_2O\) would be produced.

Hence the ratio: \(\displaystyle \frac{n({\rm H_2O})}{n({\rm C_2H_2})} = \frac{2}{2} = 1\).

Apply this ratio to find the number of moles of \(\rm H_2O\) that this reaction would have produced:

\(\begin{aligned}n({\rm H_2O}) &= n({\rm C_2H_2}) \cdot \frac{n({\rm H_2O})}{n({\rm C_2H_2})} \\ &\approx 2.46\; \rm mol \times 1 = 2.46\; \rm mol\end{aligned}\).

The fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

Fugacity is a measure of the escaping tendency of a component in a mixture, which is defined as the pressure that the component would have if it obeyed ideal gas laws. It is used as a correction factor in the calculation of equilibrium constants and thermodynamic properties such as chemical potential. Here we need to determine the fugacity in atm for pure ethane at 310 K and 20.4 atm and the change in the chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm. So, using the formula of fugacity: f = P.exp(Δu/RT) Where P is the pressure of the system, R is the gas constant, T is the temperature of the system, Δu is the change in chemical potential of the system.  Δu = RT ln (f / P)The chemical potential at the initial state can be calculated using the ideal gas equation as: PV = nRT    

=>  P

= nRT/V

=> 20.4 atm

= nRT/V

=> n/V

= 20.4/RT The chemical potential of the system at the initial state is:

Δu1 = RT ln (f/P)

= RT ln (f/20.4) Also, we know that for a pure substance,

Δu = Δg. So,

Δg1 = Δu1 The change in pressure is 24 atm – 20.4 atm

= 3.6 atm At the second state, the pressure is 24 atm.

Using the ideal gas equation, n/V = 24/RT The chemical potential of the system at the second state is: Δu2 = RT ln (f/24) = RT ln (f/24) The change in chemical potential is Δu2 – Δu1 The change in chemical potential is

Δu2 – Δu1 = RT ln (f/24) – RT ln (f/20.4)

= RT ln [(f/24)/(f/20.4)]

= RT ln (20.4/24)

= - 0.0911 RT Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is:

f = P.exp(Δu/RT)

=> f

= 20.4 exp (-Δu1/RT)

=> f

= 20.4 exp (-Δg1/RT) And, the change in the chemical potential between this state and a second state of ethane where the temperature is constant but pressure is 24 atm is -0.0911RT. Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

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At 15°C: Since all reproduction is sexual at temperatures below 20°C, the phenotype will be non-apomictic (sexual reproduction) for all generations. The predicted phenotypic ratio for F1, F2, and DH generations would be 0% apomictic : 100% non-apomictic.

Based on the given information and assumptions, let's analyze the predicted phenotypic ratios for the F1, F2, and DH (F1-derived) generations at each temperature:

At 15°C:

Since all reproduction is sexual at temperatures below 20°C, the phenotype will be non-apomictic (sexual reproduction) for all generations. The predicted phenotypic ratio for F1, F2, and DH generations would be 0% apomictic : 100% non-apomictic.

At 25°C:

In this case, facultative apomixis is triggered. Let's consider the genotypes of the parents:

Male (facultative apomict): aa bb

Female (sexually reproducing): AA BB

a and b represent recessive alleles required for facultative apomixis, while A and B represent dominant alleles associated with sexual reproduction.

The cross between the male and female would result in the following genotypes for the F1 generation:

F1: Aa Bb (phenotype: non-apomictic)

The F1 generation is heterozygous for both loci and shows the non-apomictic phenotype.

For the F2 generation, we need to consider the possible genotypic combinations:

AA BB: non-apomictic

AA Bb: non-apomictic

Aa BB: non-apomictic

Aa Bb: 3/4 non-apomictic, 1/4 apomictic (predicted phenotypic ratio: 75% non-apomictic : 25% apomictic)

aabb: apomictic

Therefore, the predicted phenotypic ratio for F2 generation at 25°C would be 75% non-apomictic : 25% apomictic.

For the DH (F1-derived) generation, we need to consider the genotypic combinations resulting from self-fertilization of the F1 plants:

Aa Bb (F1) x Aa Bb (F1)

AA BB: non-apomictic

AA Bb: non-apomictic

AA bb: non-apomictic

Aa BB: non-apomictic

Aa Bb: non-apomictic

Aa bb: 1/4 non-apomictic, 3/4 apomictic (predicted phenotypic ratio: 25% non-apomictic : 75% apomictic)

aa BB: apomictic

aa Bb: apomictic

aa bb: apomictic

Therefore, the predicted phenotypic ratio for the DH (F1-derived) generation at 25°C would be 25% non-apomictic : 75% apomictic.

To summarize:

At 15°C:

Predicted phenotypic ratio: 0% apomictic : 100% non-apomictic

At 25°C:

Predicted phenotypic ratio for F1: 0% apomictic : 100% non-apomictic

Predicted phenotypic ratio for F2: 75% non-apomictic : 25% apomictic

Predicted phenotypic ratio for DH (F1-derived): 25% non-apomictic : 75% apomictic

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In normal quantities, CO2 is an odorless, colorless gas. When used to put out a fire, it doesn't react with burning materials, therefore it doesn't produce any harmful or other by-products.

As a result, it is a clean gas that puts out fires with no sign of having done so. Carbon dioxide is a great fire suppressant to use in computer rooms, electrical distribution centers, and other places where a lot of electricity might be present because it doesn't carry electricity. CO2 has two effects on fires: As seen by the resultant mist cloud and ice particles, the release of the gas under pressure has a cooling impact. The gas also displaces the oxygen required to maintain burning.

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1.2mole•20.17g/1mole= 24.20g

Mixtures can be classified as homogeneous or heterogeneous.

Answer:

a mixture can be classified as homogeneous or heterogeneous

Explanation:

Answer:

Molarity of a solution = 1 mol / L

Explanation:

Given:

Amount of NaOH =20 g

Amount of water = 0.50 l

Find:

Molarity of a solution

Computation:

1 mol of NaOH = 40 g

So,

Moles of NaOH = 20 / 40 g = 0.50 mol NaOH

Molarity of a solution = moles of solute / Liters of solution

Molarity of a solution = 0.50 / 0.50

Molarity of a solution = 1 mol / L

Answer:

b

Explanation:

Answer:

B

Explanation:

Quartz is the material that is least susceptible to chemical weathering. Quartz is a mineral that is highly resistant to chemical weathering because it is made up of silicon dioxide, which is a very stable compound. Chemical weathering occurs when minerals react with water or air to break down into other compounds.

However, quartz does not react easily with water or air, making it very resistant to chemical weathering. This is why quartz is often found in sandstones and other sedimentary rocks that have been subjected to weathering over millions of years.

Delta and iron oxides, on the other hand, are more susceptible to chemical weathering. Delta is a sedimentary deposit that is made up of a mixture of sand, silt, and clay particles. These particles are often weathered by water and wind, which can break them down into smaller particles and carry them away. Iron oxides, which are often found in rocks and soils, are also susceptible to chemical weathering. They can react with water and oxygen to form rust, which can weaken the structure of the material over time.

Old age is not a material but rather a state of being. It does not have any effect on the susceptibility of materials to chemical weathering. Overall, quartz is the most resistant to chemical weathering, while delta, iron oxides, and other materials may be more susceptible to weathering depending on their composition and exposure to the elements.

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Answer:

There are 8.30x104-24 atoms of oxygen in 2.50 mol of oxygen gas. There are 7.53x10*23 atoms of oxygen in 2.50 mol of oxygen gas.

Answer:

The electronegativity from order of least to highest is:

Ne, Ca, Fe, F

Explanation:

Elements in the periodic table have been arranged based on their level of electronegativity (which is the ability of an atom to attract electrons).

According to Paulings scale of rating elements based on their electronegativity, the electronegativity value of Fe, Ca, Ne, and F are 1.83, 1, 0 and 3.98 respectively.

Hence, based on Pauling scale, the order of electronegativity from least to highest is:

Ne > Ca > Fe > F

An aqueous potassium carbonate solution is made by dissolving 6.29 moles of K₂CO₃ in sufficient water so that the final volume of the solution is 4.20L. The molarity of a solution is 1.50M.

Molarity is defined as the moles of solute present in the specific amount or volume of a solution. We calculate the moles of a substance using the formula

moles=(mass/molar mass)

If the volume of a solution is given in ml, then convert it into L.

Molarity is calculated as

Molarity=moles/volume(in L)

Given that moles=6.29, and volume=4.20L

Plug both values in the formula

Molarity=(6.29 mol/4.20 L)

Molarity=1.4976 mol/L

Molarity=1.50 M (∵M=mol/L)

Therefore, the molarity of a K₂CO₃ solution is 1.50M.

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The calibration curve is acceptable if the correlation coefficient (R²) is closer to 1 and the residuals are evenly distributed.

A calibration curve is an essential tool in analytical chemistry for quantifying an unknown analyte's concentration in a sample by relating the instrumental response to the analyte concentration. The calibration curve's quality depends on the linearity, sensitivity, and accuracy of the method used. Therefore, it is crucial to verify the calibration curve's accuracy and linearity by checking the correlation coefficient (R²) and residuals.

The correlation coefficient (R²) indicates the degree of linearity of the calibration curve. R² ranges from 0 to 1, where 1 signifies perfect correlation and 0 means no correlation. If the R² value is close to 1, then the calibration curve is more accurate and precise.

Residuals are the difference between the observed value and the predicted value, and it is used to check the curve's accuracy. If the residuals are evenly distributed, the calibration curve is acceptable. If there is a pattern observed in the residuals, then it is an indication of an error in the analysis, and it needs to be corrected to improve the calibration curve's quality.

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No, A precipitate will not form under these conditions.

How to determine a Precipitation Reaction?

To determine if a precipitate will form when a 45.0 mL sample of 0.0015 M \(BaCl_{2}\) is added to a beaker containing 75.0 mL of 0.0025 M KF, we need to follow these steps:

1. Calculate the moles of \(BaCl_{2}\) and KF:
moles of \(BaCl_{2}\) = volume x concentration = 45.0 mL x 0.0015 M = 0.0675 moles
moles of KF = volume x concentration = 75.0 mL x 0.0025 M = 0.1875 moles

2. Calculate the final concentrations of Ba2+ and F- ions:
total volume = 45.0 mL + 75.0 mL = 120.0 mL
[\(Ba^{2+}\)] = moles of \(BaCl_{2}\) / total volume = 0.0675 moles / 120.0 mL = 0.0005625 M
[\(F^{-}\)] = moles of KF / total volume = 0.1875 moles / 120.0 mL = 0.0015625 M

3. Calculate the ion product (Q) of \(BaF_{2}\) :
Q = [\(Ba^{2+}\)] x [\(F^{-}\)]^2 = 0.0005625 M x (0.0015625 M)^2 = 1.37 x 10^(-9)

4. Compare Q with the solubility product constant (Ksp) of \(BaF_{2}\):
The Ksp of \(BaF_{2}\) is 1.0 x 10^(-6). Since Q > Ksp (1.37 x 10^(-9) > 1.0 x 10^(-6)), a precipitate will not form under these conditions.

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The melting point of (2R,3S)-2,3-dibromo-3-phenylpropanoic acid is dependent on several factors, including the purity of the compound and the presence of any impurities.

Therefore, an exact melting point cannot be provided without specific experimental data. However, it is generally observed that organic compounds have a range of melting points rather than a single specific value.

If you are conducting an experiment and need to determine the melting point of (2R,3S)-2,3-dibromo-3-phenylpropanoic acid, it is recommended to perform the melting point determination experimentally using appropriate laboratory techniques and equipment. This involves heating a small amount of the compound and observing the temperature range at which it melts. The observed melting point can then be compared to known literature values to assess the purity of the compound.

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The smallest unit of an element that can exist either alone or in combination with other such particles of the same or different elements is the Atom

What is an atom ?

The smallest unit of matter that may be divided without producing electrically charged particles is the atom. It is also the smallest piece of substance with chemical element-like characteristics. As a result, the atom serves as the fundamental unit of chemistry. Space makes up the majority of an atom. The rest is made up of a cloud of negatively charged electrons surrounding a positively charged nucleus made up of protons and neutrons. Compared to electrons, which are the lightest charged particles in nature, the nucleus is small and dense. Electric forces, which link electrons to the nucleus of atoms, cause them to be drawn to any positive charge.

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The molarity of the KMnO4 solution is 0.532 M (rounded to three decimal places).

To calculate the molarity of the KMnO4 solution, we need to use the stoichiometry of the reaction and the volume of the KMnO4 solution used in the titration.

Given:

Mass of H2O2 solution = 1.0 g

Concentration of H2O2 solution = 30 wt% (weight percent)

Volume of KMnO4 solution used = 22.143 mL

Molar mass of H2O2 = 34.01 g/mol

Step 1: Calculate the moles of H2O2 in the solution.

Moles of H2O2 = (Mass of H2O2 solution) / (Molar mass of H2O2)

= 1.0 g / 34.01 g/mol

= 0.0294 mol

Step 2: Calculate the moles of KMnO4 based on the stoichiometry of the reaction.

According to the balanced equation, the ratio of KMnO4 to H2O2 is 2:5.

Therefore, moles of KMnO4 = (Moles of H2O2) * (2/5)

= 0.0294 mol * (2/5)

= 0.01176 mol

Step 3: Calculate the molarity of the KMnO4 solution.

Molarity (M) = (Moles of KMnO4) / (Volume of KMnO4 solution in liters)

= 0.01176 mol / 0.022143 L

= 0.5316 M

Therefore, the molarity of the KMnO4 solution is 0.532 M (rounded to three decimal places).

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