Is constant velocity same as constant acceleration?​

Answer:

In this problem, the harp string is fixed at both ends, so it is a standing wave with nodes at both ends and an antinode in the center. The frequency of the wave is given as 440 Hz, and the length of the string is 30.5 cm.

(a) To find the wavelength of the wave, we can use the formula:

λ = 2L/n

where λ is the wavelength, L is the length of the string, and n is the number of nodes. In this case, n = 2 (since there are nodes at both ends) and L = 30.5 cm, so we have:

λ = 2(30.5 cm)/2 = 30.5 cm

Therefore, the wavelength of the wave is 30.5 cm.

(b) To find the speed of the wave on the string, we can use the formula:

v = fλ

where v is the speed of the wave, f is the frequency of the wave, and λ is the wavelength. In this case, f = 440 Hz and λ = 30.5 cm, so we have:

v = (440 Hz)(30.5 cm) = 13420 cm/s

Therefore, the speed of the wave on the string is 13420 cm/s

Explanation:

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part a.

time taken for particle 1 to reach x = 0 m is given 0.047 seconds.

part b.

The time taken for  particle 2 to reach x = 0 m is 0.162 s.

We apply the rule conservation of energy to find the maximum speed of each particle as it passes through the equilibrium point x = 0 m

(a) m1 = m2 = 2.8 kg

Total energy = 2(1/2 k x^2) = 2(1/2)(108 N/m)(0.1 m)^2 = 10.8 J,

where x = 0.1 m is the maximum compression of each spring

Total energy  = 1/2 x m1 x v1^2 + 1/2 x m2 x v2^2,

v1 = -v2 because of equal masses

v1 = √ Total energy  / m1

v1 =   (10.8 J / 2.8 kg) = 2.14 m/s.

The time is  t = x / v1

t = 0.1 m / 2.14 m/s

t= 0.047 s.

we can follow the same process taken in consideration that the masses are different.

time = 0.162 s.

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Steps to formulate a logical, reasonable perspective to any situation are: gather information, identify problem, analyze the situation, consider assumptions, generate solutions, evaluate options, consider your values, make decision and monitor and adjust

Here are the six questions that you can apply to formulating a logical, reasonable perspective to any situation:

What are the issues that should be addressed?

What are the relevant facts and data related to this problem or issue?

What assumptions am I making about the problem or issue?

What are the possible solutions or outcomes, and what are the pros and cons of each?

What are my values and priorities related to this problem or issue?

What additional information do I need to make an informed decision or come to a reasonable conclusion?

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Explanation:

⠀⠀⠀⠀⠀⇒ F = ma

⠀⠀⠀⠀⠀⇒ 10.000 = 2.000a

⠀⠀⠀⠀⠀⇒ 10 = 2a

⠀⠀⠀⠀⠀⇒ 10 ÷ 2 = a

⠀⠀⠀⠀⠀⇒ 5 m/s² = a

i) Mechanical advantage of the system is 25.   ii) Efficiency of the system is 20%.

Efficiency is a measure of how much of the input energy or work is converted into useful output energy or work

Given : V.R. (Velocity Ratio) = 25, Resistant force = 3300 N, Effort force = 165 N

i) Mechanical Advantage (M.A.) can be calculated using the formula: M.A. = V.R. = 25

Therefore, the mechanical advantage of the system is 25.

ii) Efficiency can be calculated using the formula: Efficiency = (Output work / Input work) x 100%

Output work = Resistance x Distance moved by resistance

As Input work =Effort x Distance moved by effort

Effort x Distance moved by effort = Resistance x Distance moved by resistance

165 N x distance = 3300 N x distance/25

distance = (25 x 165 N) / 3300 N

distance = 1.25 m

Output work = Resistance x Distance moved by resistance

= 3300 N x 1.25 m

Output work = 4125 J

As Input work= Effort x Distance moved by effort

= 165 N x 1.25 m

Input work = 206.25 J

Efficiency = (Output work / Input work) x 100%

= (4125 J / 206.25 J) x 100%

Efficiency = 20%

Therefore, efficiency of the system is 20%.

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Answer:

25.9atm

Explanation:

Answer: my grandfather was a marine so he kept me in check

25.8 atm

Explanation:

Total pressure is:

P = Patm + ρgh

where Patm is the atmosphere pressure,

ρ is the fluid density,

g is acceleration due to gravity,

and h is the depth of the fluid.

P = (1 atm) + (1025 kg/m³) (9.81 m/s²) (250 m) (9.8692×10⁻⁶ atm/Pa)

P = 1 atm + 24.8 atm

P = 25.8 atm

The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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The upward acceleration of the acrobat is 1.833 m/s².

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Given parameters:

Mass of the acrobat; M = 588 N.

Weight of the acrobat acting downwards; W = 588 N.

Upward force provided by each of the two ropes; f = 349 N.

Hence, net force acting on the acrobat in upward direction = 2f -w

= (2×349 - 588 ) N.

= 110 N.

Hence, the upward acceleration of the acrobat is = net force/ mass

= 110/60 m/s².

=1.833 m/s².

So, the upward acceleration of the acrobat is 1.833 m/s².

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The diagram which represents the electric field around a negatively charged conducting sphere is: Image D.

An electric charge can be defined as a fundamental, physical property of matter, that typically governs how particles are affected by an electric field or electromagnetic field, especially due to the presence of an electrostatic force.

The electric field around a negatively charged conducting sphere are all attracted to the sphere in accordance with the law of electrostatic forces, as depicted by Image D in the given diagram.

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Answer:

R ≈ 15 ohms

Explanation:

Using ohm's law equation,

I = V/R, to solve for the resistance of the heating coil.

R = V/I

Known:

V = 220 v = 220 kgm^2s^-3A^-1

I = 15 A

Unknown:

R =?

Solution:

R = (220 kgm^2s^-3A^-1)/ 15.0 A

R = 14.6 kgm^2s^-3A^-2

R ≈ 15 kgm^2s^-3A^-2

R ≈ 15 ohms

The value of the rate constant at 457 K is 0.478 M/s.

The rate constant, k, at a given temperature can be related to the activation energy, Ea, and the gas constant, R, through the Arrhenius equation:

\(k = Ae^{(-Ea/RT)}\)

where A is the pre-exponential factor and T is the temperature in Kelvin.

Given k1 = 0.178 M/s at T1 = 280 K, and Ea = 37.8 kJ/mol, we can calculate the rate constant, k2, at T2 = 457 K as:

k2 = A * \(e^{(-Ea/R * T2)}\) = 0.178 * \(e^{(-37.8 kJ/mol / (8.314 J/mol K) * 457 K)}\) = 0.478 M/s.

This means that the reaction will proceed faster at 457 K than it does at 280 K, due to the increase in temperature leading to an increase in the rate constant, k.

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Unreliable personality tools on the market, inaccurate test results, anxious candidates as a result of linguistic and cultural barriers, pricey personality tools, and lengthy assessments are some of the issues with personality tests.

Some aspects of a person's personality are overemphasized by personality tests, while others are underemphasized, misplaced, or completely ignored. Personality tests don't accurately represent a particular aspect of a person's personality; instead, they present a skewed, false impression of the whole thing.

Projective tests and self-report inventories are the two main categories of personality tests. Test-takers must read questions and then rate how well the question or statement applies to them in self-report inventories.

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A light bulb uses electrical energy to generate light. It uses 3 V of an electric charge and 20 A of electric current.The light bulb's power is 60 Watt.

The term voltage is defined the pressure from an electrical circuit's power source that forces charged electrons through a conducting loop, enabling them to do work such as lighting a light. So, voltage = pressure, and it is measured in volts (V).

Power = Current × voltage

Given:

electric current = 20 A

voltage =  3 V

Power = ?

By substituting given values in equation and we get,

Power = 20 × 3

= 60 Watt

Thus, the light bulb's power is 60 Watt.

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Answer:

B. Yes, because they glow more brightly as they increase in

temperature

Explanation:

Did the test !!

The coils in an electric heater blackbody are not radiators. Because, they absorb no energy and emit no light. Thus, the correct option is C.

Electric heating is a process in which the electrical energy is converted directly into the heat energy at around about 100% efficiency, using rather the cheap devices. Common applications which are included are space heating, cooking, water heating and industrial processes.

A radiator is the key component of the engine's cooling system. Radiator has the main role to disperse a mix of antifreeze and water molecules throughout the fins, which releases some of the engine's heat energy while taking in the cool air before continuing to pass the rest of the electric engine.

Therefore, the correct option is C.

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When a body of mass 12kg travelling at 4.2m/s² collides with a second body of mass 18kg at rest, their common velocity after the collision is 1.68 m/s.

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Answer:

N/A

Explanation:

The following formula can be used to compute the power output of a person lifting a lawnmower:

Work (W) / Time (t) = Power (P).

Where:

Work (W) is defined as the force used to lift the lawnmower multiplied by the distance traveled (i.e., work done against gravity).

Time (t) is the amount of time it takes to lift the lawnmower.

To determine the power output, however, we would need to know the force used to lift the lawnmower as well as the distance it was lifted. We won't be able to provide an accurate power output value without this information.

The specific latent heat of fusion of ice obtained from this experiment is approximately 583.33 J/g.

To determine the specific latent heat of fusion of ice using the given experiment, we need to consider the energy transferred during the process.First, we need to calculate the energy lost by the water to cool down from 25 °C to 0 °C. The energy lost is given by:

Q1 = m1 * c * ΔT1

Where:

m1 = mass of water = 100 g

c = specific heat capacity of water = 4.2 J/g °C

ΔT1 = change in temperature = (0 °C - 25 °C) = -25 °C

Q1 = 100 g * 4.2 J/g °C * (-25 °C) = -10,500 J

Next, we calculate the energy released by the water to freeze and cool the remaining ice. The energy released is given by:

Q2 = m2 * Lf

Where:

m2 = mass of ice = 18 g

Lf = specific latent heat of fusion of ice (to be determined)

Q2 = 18 g * Lf

Since energy is conserved in the system, the energy lost by the water (Q1) is equal to the energy released by the water (Q2):

-10,500 J = 18 g * Lf

Solving for Lf:

Lf = -10,500 J / 18 g = -583.33 J/g

The negative sign indicates that energy is being released during the process of freezing.

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Answer:

For a given system, there can be particular transformations for which the explicit equations of motion are the same for both the old and new variables. Transformations for which the equations of motion are invariant, are called invariant transformations. It will be shown that if the Lagrangian does not explicitly contain a particular coordinate of displacement  qi, then the corresponding conjugate momentum,  pi, is conserved. This relation is called Noether’s theorem which states “For each symmetry of the Lagrangian, there is a conserved quantity".

Answer:

A)quadruples

Explanation:

The force between the two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Hence, if distance between charges is halved (charges remaining kept constant), the force between the two charges is quadrupled

Answer:

Secondary succession

Explanation:

Secondary succession is one of the two major types of ecological successions (the other being primary succession). Succession, generally, is characterized by the series of changes that occurs to an ecological community within a period of time.

However, secondary succession occurs when an already colonized area (with soil formed) becomes disturbed by environmental disasters or occurrences, leading to the recolonization of the area by certain organisms. Therefore, an area that has been re-colonized after an environmental disturbance has undergone SECONDARY SUCCESSION.

The internal brain processes required to make sense of the environment and choose the best course of action are the subject of cognitive psychology.

Complex attention, executive function, learning and memory, language, perceptual-motor control, and social cognition are the six major cognitive function domains identified by the DSM-5.

The cognitive approach's main characteristics are: a conviction that psychology should be treated as a pure science and that research methods should be based on science. The main focus is on thinking and related mental functions like language, perception, memory, and forgetting.

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The velocity of a 55.0-kg person hitting the ground, is mathematically given as

vt=39.5983m/s

Generally, the equation for is  mathematically given as

mass of squirrel,

\(m=550 \mathrm{~g}\\\\Surface area, $A=945 \mathrm{~cm}^{2}=88 \times 10^{-3}$\\\\Height, $h-4 \mathrm{~m}$\\\)

Terminal velocity is given by:

\($v_{i}=\sqrt{\frac{2 m g}{\rho A C}}$\)

where \rho is the density of fluid that is falling and it is given by

\($\rho=\frac{m}{V}$\)

since, volume =area * height

\(^{\rho=} \frac{0.55 \mathrm{Kg}}{0.0945 \mathrm{~m}^{2} \times 4.0 \mathrm{~m}}\\\\$\rho=0.1455 \mathrm{Kg} / \mathrm{m}^{3}$\)

A is the surface area of squirrels.

C is the drag coefficient.

The surface area facing the fluid is given by:

\(A_{f}=\frac{0.0945 \mathrm{~m}^{2}}{2} \\\\\\ A_{f}=0.04725 \mathrm{~m}^{2}\)

so, terminal velocity is :

\($v_{t}=\sqrt{\frac{2 \times 0.55 \mathrm{Kg} \times 9.8 \mathrm{~m} / \mathrm{s}^{2}}{0.1455 \mathrm{Kg} / \mathrm{m}^{3} \times 0.04725 \mathrm{~m}^{2} \times 1}}$\)

Vt=39.5983

In conclusion, the terminal velocity of the squirrel is 39.5983m/s

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Given parameters:

Mass of the body  = 200g

Force on the body  = 10N

Unknown parameters:

Acceleration produced by the force  = ?

To solve this problem we must first define force in terms of mass and acceleration. This is possible due to the Newton's first law of motion.

  Force  = mass x acceleration

Here the unknown is acceleration and we can easily solve for it.

But we must take the mass to kilogram in order for it to cancel out.

        1000g  = 1 kg

        200g  = x kg =   \(\frac{200}{1000}\)   = 0.2kg

Now input the parameters and solve;

         10  = 0.2 x acceleration

   Acceleration  = \(\frac{10}{0.2}\)   = 50m/s²

The acceleration produced by the body is 50m/s²

To convert this computed volume from mL to L, simply divide the provided quantity of ethanol by its density: 500g(mL0.789g)(L1000mL)=0.633L. 500g(mL0.789g)(L1000mL) = 0.633L.

Ingestion, inhalation, and skin absorption of ethanol are all dangerous. Frequent contact can cause the skin to become dry, which can cause it to become itchy, crack, and peel. The central nervous system, the eyes, and the upper respiratory tract can all be affected by ethanol.

The term "alcohol" refers to a wide variety of compounds that are created when one atom of carbon interacts with oxygen, hydrogen, and other atoms. Yet, all alcohol in alcoholic beverages is a particular little molecule known as ethanol.

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Answer:

14.1seconds approx

Explanation:

Given data

Distance= 59.1m

Your velocity= 2.35m/s

Walkway velocity= 1.85m/s

Total velocity= 2.35+1.85= 4.2m/s

We know that

Velocity= distance/time

time= distance/velocity

substitute

time= 59.1/4.2

time= 14.07

time=14.1seconds approx

Hence the time is 14.1seconds approx