Answer:B ez
Explanation:
An 80-kg football player travels to the right at 8 m/s and a 120-kg player on the opposite team travels to the left at 4.0 m/s. The total momentum is
Answer:
See Explanation
Explanation:
m1(v1) + m2(v2)
Opposite turns the plus to subtraction.
80(8) - 120(4.0)
60 - 480 = 160 kg m/s to the right
An 80-kg football player travels to the right at 8 m/s and a 120-kg player on the opposite team travels to the left at 4.0 m/s. The total momentum is 160 kg m/s.
What is momentum?Momentum is a fundamental concept in physics that describes the amount of motion an object has. It is defined as the product of an object's mass and its velocity. Mathematically, momentum (p) is given by:
p = m × v
where p is the momentum, m is the object's mass, and v is its velocity.
The units of momentum are kilogram-meters per second (kg m/s) in the SI system of units. The direction of momentum is the same as the direction of the object's velocity.
Momentum is a conserved quantity, meaning that the total momentum of an isolated system (a system that does not interact with its surroundings) remains constant. This is known as the law of conservation of momentum, and it has many practical applications in physics and engineering. For example, it can be used to analyze collisions between objects, such as in sports or automobile accidents.
Here in the Question,
To find the total momentum of the two players, we first need to calculate the individual momentum of each player, and then add them up.
The momentum (p) of an object is given by the product of its mass (m) and velocity (v):
p = m × v
For the first player with a mass of 80 kg and a velocity of 8 m/s, the momentum is:
p1 = 80 kg × 8 m/s = 640 kg m/s
For the second player with a mass of 120 kg and a velocity of -4.0 m/s (negative because he is traveling in the opposite direction), the momentum is:
p2 = 120 kg × (-4.0 m/s) = -480 kg m/s
The negative sign in front of the momentum for the second player indicates that his momentum is in the opposite direction of the first player.
To find the total momentum, we add the individual momenta:
total momentum = p1 + p2
= 640 kg m/s - 480 kg m/s
= 160 kg m/s
Therefore, the total momentum of the two players is 160 kg m/s.
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During a goal-line stand, a 112-kg fullback moving eastward with a speed of 6 m/s
collides head-on with a 120-kg lineman moving westward with a speed of 8 m/s.
The two players collide and stick together, moving at the same velocity after the
collision. Determine the post-collision velocity of the two players.
Answer:
-1.24 m/s
Explanation:
Total momentum before collision = total momentum after collision
Total momentum before collision = (mass of full back * velocity of fullback) + (mass of lineman * velocity of line man).
Mass of full back = 112 kg, mass of line bag = 120 kg, velocity of full back 6 m/s (east), velocity of line back = -8 m/s (west). Hence:
Total momentum before collision = (112 * 6) + (120 * -8) = 672 - 960 = -288 kgm/s
The total momentum after collision = (mass of full back + mass of line back) * velocity after collision.
Let velocity after collision be v, hence:
The total momentum after collision = (112 + 120)v = 232v
Total momentum before collision = total momentum after collision
-288 = 232v
v = -288 / 232
v = -1.24 m/s
Therefore after collision, the two players would move at a velocity 1.24 m/s west (the same direction as the lineman).
Which term is defined by the force that moving, charged particles exert on one another?.
Electromagnetic force is the force that moving, charged particles exert on one another.
What is Electromagnetic force?The electromagnetic force acting between the electrically charged atomic nuclei and electrons of the atoms can explain all the forces involved in interactions between atoms.Additionally, electromagnetic forces account for how these particles move with momentum. This includes the forces we feel when "pushing" or "pulling" commonplace material items, which are caused by the intermolecular forces acting between the molecules in the objects and the individual molecules in our bodies.All types of chemical phenomena involve electromagnetic force. The study of the electromagnetic force, a sort of physical interaction that takes place between electrically charged particles, is at the heart of the area of physics known as electromagnetism.Electric fields and magnetic fields combine to form electromagnetic fields, which carry electromagnetic force.To learn more about Electromagnetic force with the given link
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A 7.50 kg bowling ball moving6.42 m/s strikes a 1.60 kg bowlingpin at rest. After, the pin moves14.8 m/s at a -47.0° angle. Whatis the y-component of the ball'sfinal velocity?y-component (m/s)Enter
let the bowling ball initially is moving along the x-axis,
The whole process can be represented as,
Before the collision the net kinetic energy of the balls is,
\(K_{iy}=\frac{1}{2}\times m_1\times(v_1\cos (90^o))^2+\frac{1}{2}\times m_2\times(0)^2\)where the values of the variables are given as,
\(\begin{gathered} m_1=7.5\text{ kg} \\ v_1=6.42ms^{-1} \\ m_2=1.6\text{ kg} \end{gathered}\)As the value of cos(90) is zero.
Substituting the known values,
The value of the net kinetic energy with the velocity along the y-axis before the collision is,
\(K_{iy}=0\)The velocity of the second ball is at rest in the initial state, thus its value is taken as zero.
After the collision of the balls, the net kinetic energy is,
\(\begin{gathered} K_{fy}=\frac{1}{2}\times m_1\times(v^{\prime}_1\sin (\alpha))^2+\frac{1}{2}\times m_1\times(v^{\prime}_2\sin (-47^o))^2 \\ K_{fy}=\frac{1}{2}\times m_1\times(v_{1fy})^2+\frac{1}{2}\times m_1\times(v^{\prime}_2\sin (-47^o))^2 \end{gathered}\)Negative sign here indicating the direction of the final balls motion will be opposite to the each other.
The values of the variables are given as,
\(v^{\prime}_2=14.8ms^{-1}\)Substituting the known values,
The value final kinetic enegry of the balls with velocity along the y-axis is,
\(\begin{gathered} K_{fy}=\frac{1}{2}\times7.5\times(v_{1fy})^2+\frac{1}{2}\times1.6\times(14.8\times\sin (360^o-47^o)^2 \\ K_{fy}=3.75\times(v_{1fy})^2-93.72 \end{gathered}\)Here 360 degree is used because the pin ball direction is downward of the positive x-axis.
Then by the law of conservation of energy along the y-axis,
\(\begin{gathered} K_{iy}=K_{fy} \\ 0=3.75\times(v_{1fy})^2-93.72 \\ (v_{1fy})^2=\frac{93.72}{3.75} \\ (v_{1fy})^2=25 \\ v_{1fy}=5ms^{-1} \end{gathered}\)Thus, the y component of the final velocity of the bowling ball of mass m1 is 5 meter per second.
A 25-newton horizontal force northward and a 35-
newton horizontal force southward act concurrently on
a 15-kilogram object on a frictionless surface. What is
the magnitude of the object's acceleration?
Answer:
2/3.or 0,67
Explanation:
acceleration = Result or sum of force / the mass
a = F/m
a = (35-25)/15
a = 10/15 = 2/3 m/s²
a = 0,67 m/s²
A baseball player up to bat gets hit by a fast ball. What is the predominant type of force generated by the ball on the player? Explain your reasoning.
Answer:
Reaction force
Explanation:
According to Newton's third law of motion, for every action, there is an equal opposite reaction.
Hence the reaction force is often equal in magnitude to the applied force but acts in a direction opposite to the direction of the applied force.
Hence, when a baseball player, gets a hit, the ball exerts a reaction force on the player which is equal in magnitude to the force with which the player hits the ball but opposite in direction.
a car is moving at a constant speed of 100 miles per hour. how long does it take for the car to travel 200 miles.
a. 5 hours
b. 4 hours
c. 10 hours
d. 2 hours
Answer:
d. 2 hours
Explanation:
because if it travels 100 miles per hour in 1 hour it would travel 200 miles in 2 hours and so fourth.
which gmaw electrode wire is most commonly used and works great with co2
The most commonly used GMAW electrode wire that works great with CO₂ is ER70S-6.
Gas Metal Arc Welding (GMAW), also known as MIG (Metal Inert Gas) welding, uses an electrode wire to create an arc that melts and fuses the base metal. The electrode wire, also referred to as the filler wire, plays a crucial role in the welding process.
ER70S-6 is a widely used electrode wire in GMAW applications and is particularly suitable for welding with CO₂ as the shielding gas. It is a solid wire composed of mild steel with specific chemical compositions to provide excellent welding performance and desirable mechanical properties.
The "ER" in the designation stands for Electrode or Rod, "70" represents the tensile strength in ksi (kilo-pounds per square inch), and "S-6" indicates its suitability for general-purpose welding.
ER70S-6 wire offers good arc stability, smooth bead appearance, and low spatter levels, making it highly versatile and suitable for various welding projects. When used with CO₂ as the shielding gas, it provides good penetration, strong welds, and high deposition rates. CO₂ is a commonly used shielding gas in GMAW due to its availability and affordability.
It's important to note that the choice of electrode wire may vary depending on the specific welding application, base metal, and desired welding characteristics. Consulting welding guidelines and considering factors such as material type, joint design, and welding parameters will help determine the most appropriate electrode wire for a particular welding task.
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State keplers law........
Answer:
There are actually three, Kepler's laws that is, of planetary motion: 1) every planet's orbit is an ellipse with the Sun at a focus; 2) a line joining the Sun and a planet sweeps out equal areas in equal times; and 3) the square of a planet's orbital period is proportional to the cube of the semi-major axis of its
The Sex Equity in Education Act requires educational institutions to distribute a sexual harassment policy to:
A._ faculty and parents.
B._parents and administrators. C._students and administrators.
D._faculty and students.
If an object of mass 70kg falls from a height of 500 m, what is the maximum velocity of the object?
Answer:
H = 1/2 * g * t^2 since initial velocity is zero
v = g * t where v is the final velocity
t = v / g
H = 1/2 g * v^2 / g^2 = 1/2 v^2 / g
v = (2 * H * g)^1.2
v = (2 * 500 * 9.8)^1/2 = 99 m/s
Check: t = v / g = 99 / 9.8 = 10.1 sec
H = 1/2 * 9.8 * 10.1^2 = 500 m
calculate the specific gravity of a liquid given the following information: m = 56.68 g, ma = 31.34 g, ml = 41.01 g.
Specific gravity of a liquid = 1.81.
To calculate the specific gravity of a liquid, you need to divide the mass of the liquid (ml) by the mass of an equal volume of water (ma).
The mass of the liquid given is 56.68 g, the mass of the empty container (ma) is 31.34 g, and the mass of the container filled with water (ml) is 41.01 g.
To calculate the mass of the water, you need to subtract the mass of the container from the mass of the container filled with water (41.01 g - 31.34 g = 9.67 g).
Divide the mass of the liquid by the mass of the water (56.68 g ÷ 9.67 g = 5.865). The specific gravity is the ratio of the density of a substance to the density of a reference substance, which is usually water.
Therefore, the specific gravity of the liquid is 5.865 times the density of water, which is 1 g/mL, resulting in a specific gravity of 1.81.
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The specific gravity of the liquid is approximately 2.62. To calculate the specific gravity of a liquid, you can use the following formula:
Specific Gravity (SG) = (mass of liquid and air (m) - mass of air (ma)) / (mass of liquid (ml) - mass of air (ma)). In this case, m = 56.68 g, ma = 31.34 g, and ml = 41.01 g.
Step 1: Subtract the mass of air (ma) from the mass of liquid and air (m):
56.68 g - 31.34 g = 25.34 g
Step 2: Subtract the mass of air (ma) from the mass of liquid (ml):
41.01 g - 31.34 g = 9.67 g
Step 3: Divide the result from Step 1 by the result from Step 2:
25.34 g / 9.67 g = 2.62
So, the specific gravity of the liquid is 2.62. This means that the liquid is 2.62 times denser than the reference liquid, which is usually water.
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1. Show that the inductive time constants RL has units of seconds. 2. If the inductance in the LR circuit is doubled, how is the half-life affected? 3. If the resistance in the LR circuit is doubled, how is the half-life affected?
4. If the charging voltage in the circuit is doubled, how is the half-life affected for the LR circuit? 5. To plot the equation V (1)=Vmax e^tR/L so the graph results in a straight line, what quantity do you have to plot vs, time? What is the expression for the slope of this straight line? Determine the expected self-inductance of a solenoid which has 1600 windings-each of enclosed cross- section radius 2.0 cm--and length 12 cm.
1. The inductive time constant RL has units of seconds.
2. Doubling the inductance in an LR circuit does not affect the half-life.
3. Doubling the resistance in an LR circuit increases the half-life.
4. Doubling the charging voltage in an LR circuit does not affect the half-life.
5. To plot the equation V(1) = Vmax × \(e^{(tR/L)\) as a straight line, plot ln(V(1)) against time and the slope is (R/L).
6. The expected self-inductance of the solenoid is calculated using the formula L = (4π × \(10^{-7\) Tm/A) × (1600²) × (π × (0.02)²) / 0.12.
1. To show that the inductive time constant RL has units of seconds, we need to consider the units of the inductance (L) and resistance (R) individually.
The unit of inductance, L, is Henries (H).
The unit of resistance, R, is ohms (Ω).
The time constant (τ) of an RL circuit is given by the formula τ = L/R.
Substituting the units, we have:
τ = (H)/(Ω)
By rearranging the units, we can express henries (H) in terms of seconds (s):
1 H = 1 (Ω)(s)
Therefore, the units of RL, which is the time constant of an RL circuit, are seconds (s).
2. If the inductance in the LR circuit is doubled, the half-life is not affected. The half-life is a measure of the time it takes for the current (or voltage) to decrease to half of its initial value in an exponential decay process. The half-life is independent of inductance (L) and is primarily determined by the resistance (R) in the circuit.
3. If the resistance in the LR circuit is doubled, the half-life is increased. The half-life is directly proportional to the resistance (R) in the circuit. Doubling the resistance will result in a longer time for the current (or voltage) to decrease to half its initial value.
4. If the charging voltage in the circuit is doubled, the half-life is not affected. The half-life of an LR circuit depends on the resistance (R) and inductance (L) but is independent of the charging voltage. Increasing the charging voltage will result in a higher initial current (or voltage), but it will not affect the time it takes for the current (or voltage) to decrease to half its initial value.
5. To plot the equation V(1) = Vmax × \(e^{(tR/L)\) in a way that results in a straight line, you need to plot the natural logarithm of the voltage (ln(V(1))) against time (t). The equation then becomes ln(V(1)) = (R/L) × t + ln(Vmax), which is in the form of a linear equation (y = mx + c), where m is the slope and c is the y-intercept.
The expression for the slope of this straight line is (R/L), which represents the ratio of resistance (R) to inductance (L) in the LR circuit.
6. To determine the expected self-inductance of a solenoid with the given specifications, we can use the formula for the self-inductance of a solenoid:
L = (μ₀ × N² × A) / l
Where:
L is the self-inductance
μ₀ is the permeability of free space (4π × \(10^{-7\) Tm/A)
N is the number of windings (1600 windings)
A is the cross-sectional area of the solenoid (π × r², where r is the radius of the solenoid)
l is the length of the solenoid (12 cm)
Let's calculate the self-inductance using the given values:
N = 1600
r = 2.0 cm = 0.02 m
A = π × (0.02)²
l = 12 cm = 0.12 m
Substituting these values into the formula, we have:
L = (4π × \(10^{-7\) Tm/A) × (1600²) × (π × (0.02)²) / 0.12
Simplifying the expression, we can calculate the expected self-inductance.
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When the system pressures are lower than the pressure in the refrigerant tank, such as when the system has just been evacuated or if the system is out of refrigerant, refrigerant can be added to both the high and low pressure sides of the system. A. True B. False
Answer: True
Explanation:
It should be noted that when refrigerant is added in vapor form to the operating refrigeration system, then the addition of the refrigerant should be to the low-pressure side of the refrigeration system.
Furthermore, when system pressures are lower than the pressure in the refrigerant tank as stated in the question, then the refrigerant can be added to both the high and low pressure sides of the system.
Therefore, the correct option is true.
If the 0. 100-mm diameter tungsten filament in a light bulb is to have a resistance of 0. 167 ω at 20. 0° c, how long should it be?
The tungsten filament should be approximately 0.236 meters long.
The resistance of a wire is given by the formula R = \(ρ\)* (L / A), where R is the resistance, ρ is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area of the wire.
To find the length of the tungsten filament, we need to rearrange the formula and solve for L.
Given:
Diameter of the filament = 0.100 mm = 0.0001 m
Resistance of the filament = 0.167 Ω
Resistivity of tungsten (\(ρ\)) = 5.6 x 10^-8 Ω·m (at 20.0°C)
First, we need to find the cross-sectional area (A) of the filament using the formula A = \(π\)* (r^2), where r is the radius.
The radius (r) of the filament can be found by dividing the diameter by 2:
r = 0.0001 m / 2 = 0.00005 m
Now, we can calculate the cross-sectional area:
A = \(π\)* (0.00005 m)^2 = 7.85 x 10^-10 m^2
Substituting the given values into the resistance formula, we get:
\(0.167 Ω = (5.6 x 10^-8 Ω·m) * (L / 7.85 x 10^-10 m^2)\)
To isolate L, we can rearrange the formula:
L = \((0.167 Ω * 7.85 x 10^-10 m^2) / (5.6 x 10^-8 Ω·m)\)
Calculating the value of L, we find:
L = 0.236 m
Therefore, the tungsten filament should be approximately 0.236 meters long.
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If the strings have different thicknesses, which of the following parameters, if any, will be different in the two strings?.
Answer:
Wave speed and wavelength
Explanation:
Energy. (4 points)
2. When you eat pizza, Chemical Energy is transferred to
O Solar
Electrical
Mechanical
Chemical
When you eat pizza, chemical energy is transferred to mechanical energy.
What is energy?Energy can be defined as the ability to do work. Thus, energy must be possessed or transferred to a physical object (body) before work can be done.
The forms of energy.In Science, there are different forms of energy and these include the following;
Sound energyGravitational energyElectrical energyChemical energyElectromagnetic energyMechanical energyWhen a person eats pizza, the chemical energy contained in this snack is transferred to mechanical energy.
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What does an electromagnet do?
The outside diameter of your teacher's rear bicycle tire is 16 inches. How far will he travel if the rear wheel makes 1200 revolutions on the road?
Answer:
241,274.32 inches
Explanation:
How far will he travel if the rear wheel makes 1200 revolutions on the road?
Since the rear wheel makes one revolution in the distance of a circumference of a circle, C with diameter, d = 16 inches
C = πd²/4
So, the distance, travelled in 1200 revolutions is D = 1200 × C = 1200πd²/4
Substituting d = 16 into D, we have
D = 1200πd²/4
D = 1200π(16)²/4
D = 76800π
D = 241,274.32 inches
A space probe in remote outer space continues moving
A) because a force acts on it. B) in a curved path.
C) even though no force acts on it. D) due to gravity.
Option (A) because a force acts on it , is the correct option .
A space probe in remote outer space continues moving because a force acts on it.
According to Newton's first law of motion, an object will continue to move in a straight line at a constant velocity unless acted upon by an external force. In the case of a space probe in remote outer space, several forces can act on it to maintain its motion.
One of the significant forces at play is gravity. While space is mostly empty, gravitational forces from celestial bodies can still influence the probe's trajectory. If the probe is near a massive object like a planet or a star, the gravitational force exerted by that object can provide the necessary force to keep the probe moving. In this scenario, the probe would move in a curved path around the massive object due to the gravitational force acting as a centripetal force.
Additionally, other forces such as propulsion systems, solar radiation pressure, or gravitational assists from planetary flybys can also act on the space probe, ensuring its continued motion and trajectory adjustments.
A space probe in remote outer space continues moving due to the presence of external forces acting on it. These forces, such as gravity, propulsion systems, solar radiation pressure, or gravitational assists, provide the necessary force to counteract any potential deceleration or deviation from its intended path.
While the probe may move in a curved path due to gravitational forces, it ultimately remains in motion because forces act upon it. Therefore, option A) is the correct choice.
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An astronaut drops a feather from 1.2 m above
the surface of the moon. If the acceleration of
gravity on the moon is 1.62 m/s2 downward,
how long does it take the feather to hit the
moon's surface?
It take "1.49 sec" to hit the moon's surface. A further explanation is provided below.
According to the question,
Height,
d = 1.2 m/sAcceleration of gravity,
a = 1.62 m/s²Initial velocity,
u = 0With the help of the equation,
→ \(t^2 = \frac{2d}{a}\)
By substituting the values, we get
→ \(= \frac{2\times 1.2}{1.62}\)
→ \(= \frac{2.4}{1.62}\)
→ \(= 1.49 \ sec\)
Thus the above answer is right.
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What is a volume of a 200 gram sample of gold if its density is known to be 20.5g/cm3?
A student drops a ball off the top of building and records that the ball takes 2.55s to reach the ground. Determine all unknowns and answer the following questions. Neglect drag.
The unknown variables in the model equation for ball's motion include vertical distance traveled by the ball which is 31.86 m and the final velocity of the ball which is 25 m/s.
The given parameter;
time of motion of the ball, t = 2.55 sThe equations that model the motion of the ball is given as follows;
\(h = v_0_y + \frac{1}{2} gt^2\)
\(v_f = v_0_y + gt\)
All the unknown variables in the equations include;
\(v_0_y\) is the initial vertical velocity of the ball, = 0g is the acceleration due to gravity = 9.8 m/s²h is the vertical distance traveled by the ball = ?\(v_f\) is the final velocity of the ball = ?The vertical distance traveled by the ball is calculated as follows;
\(h = \frac{1}{2} gt^2\\\\h = 0.5 \times 9.8 \times 2.55^2\\\\h = 31.86 \ m\)
The final velocity of the ball is calculated as follows;
\(v_f = 0 + 9.8(2.55)\\\\v_f = 25 \ m/s\)
Thus, the unknown variables in the model equation for ball's motion include vertical distance traveled by the ball which is 31.86 m and the final velocity of the ball which is 25 m/s.
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Can you answer that?
Answer:
At positions C and E potential energy is maximum. At position D kinetic energy is maximum.
Explanation:
A 1.70 H inductor carries a steady current of 0.450 A. When the switch in the circuit is thrown open, the current is effectively zero in 10.0 ms. What is the average induced emf in the inductor during this time
The average induced emf in the inductor during this time can be calculated using the formula:
emf = L * ΔI/Δt
where L is the inductance, ΔI is the change in current, and Δt is the time interval.
In this case, the inductance (L) is 1.70 H and the change in current (ΔI) is 0.450 A (since the current goes from 0.450 A to 0 A). The time interval (Δt) is 10.0 ms, which is equal to 0.01 seconds.
Plugging in these values, we get:
emf = 1.70 H * (0 - 0.450 A)/0.01 s
emf = -76.5 V
Therefore, the average induced emf in the inductor during this time is -76.5 volts. Note that the negative sign indicates that the emf is opposing the change in current (i.e. it is a back emf).
* To calculate the average induced emf in the 1.70 H inductor during the 10.0 ms interval when the current decreases from 0.450 A to zero, you can use the formula for the induced emf in an inductor:
emf = -L * (ΔI / Δt)
where L is the inductance (1.70 H), ΔI is the change in current (0.450 A), and Δt is the time interval (10.0 ms or 0.01 s). The negative sign indicates that the induced emf opposes the change in current.
emf = -(1.70 H) * (0.450 A / 0.01 s)
emf = -76.5 V
The average induced emf in the inductor during this time is 76.5 V.
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BRAINLIEST! PLEASE HELP :) Distinguish between constructive and destructive interference. Explain.
Answer:
Here's what I get
Explanation:
When two waves meet, they interfere with each other.
1. Constructive interference
If the crests of the waves happen to line up, as in Fig. 1, the amplitudes add up.
The crests become twice as high. The troughs also line up, so they become twice as deep.
We call this constructive interference.
2. Destructive interference
If the trough of one wave meets the crest of another, as in Fig. 2, the opposite happens.
The trough of one wave subtracts from the crest of the other, so the two waves cancel.
We call this effect destructive interference.
Can someone please explain
1) Centripetal force with example
2) Centrifugal force with example
3) Circular motion with example
Explanation:
centripetal force is a force that makes a body follow a curved path. for example, twirling,a lasso, cream seperator etc.
A force that causes an objectmoving in a circular path to move out and away from the centres of it's path is centrifugal force. for example,drifting, banked roads, washing machine etc.
Circular motion is a movement of an object along the circumference of a circle or rotation along a circular path. for example, stirring batter, stone tied to a string etc
hope its helpfull♡
Which of these examples best shows a change from potential to kinetic energy?
Answer:
Water flowing over a tall cliff
Explanation:
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g a cheetah can accelerate from rest to a speed of 21.0 m/s in 6.75 s. what is its acceleration (in m/s2)? 3.11 correct: your answer is correct. m/s2
The acceleration of cheetah from rest to a speed of 21.0 m/s in 6.75 s is 3.1m/s2.
Given the speed of cheetah (v) = 21m/s
The time of acceleration from rest to given speed (t) = 6.75s
The acceleration of cheetah = am/s^2
We know that acceleration = speed of object/time of acceleration = v/t
Acceleration is the rate of change of velocity. It is the change in speed or direction of an object over a period of time. It is related to speed and time in that it is the rate at which the speed of an object changes over a given amount of time.
then a = 21/6.75 = 3.1m/s^2
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Several radio telescopes are combined into an interferometer in order to1) observe over a wider range of frequencies. 2) observe astronomical objects during daylight hours when the sky is otherwise too bright. 3) decrease the strength of the signal transmitted. 4) decrease the smallest angle which can be observed by the telescope.
Several radio telescopes are combined into an interferometer in order to 2) observe astronomical objects during daylight hours when the sky is otherwise too bright.
Why is an interferometer made of many radio telescopes?Radio astronomers may combine the signals from several antennas and even telescopes using interferometry. They are able to produce images that are more brighter and more precise than what is feasible with only one antenna dish.
To investigate objects in space, astronomers utilize a variety of telescopes sensitive to various regions of the electromagnetic spectrum. Despite the fact that all light is fundamentally the same, astronomers view light differently depending on the part of the spectrum they are interested in.
Learn more about electromagnetic spectrum
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