Answer:
I think the answer is:
66.24
Answer:
92 percent of 74 is 68.08
Step-by-step explanation:
74 times 0.92 =68.08
or
74 times 92% =68.08
or
74 times 92 =6808 Put the decimal to points to the right =68.08
the following are amounts of total snow falls (in inches) in different midwestern cities in the united states in a certain year: 20 40 31 7 15 29 25 20 17 32 28 12 34 29 20 17 33 23 find the sample mean.
The sample mean of snowfalls in the 18 midwestern cities of the United States is 24. This is calculated by applying the formula of arithmetic mean or average to the given sample of data.
What is arithmetic mean?
An arithmetic mean is examined as very similar to an average. Mathematically, it is obtained by dividing the sum of all objects by the total number of objects.
Calculation of the sample mean for given data
Given the total number of cities = 18
The total amount of snow falls = 20 + 40 + 31 + 7 + 15 + 29 + 25 + 20 + 17 + 32 + 28 + 12 + 34 + 29 + 20 + 17 + 33 + 23
The sample mean = total amount of snowfalls / total number of cities
= 432 / 18
= 24
Hence, the sample mean of the given data is 24.
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"
1)
Let the equation xyz = 1 be provided for any x, y, z elements,
including 1 unit element in a group. In this case, are the
equations yzx = 1 and yxz = 1
both the equations yzx = 1 and yxz = 1 hold for the given equation xyz = 1.
Given equation is xyz = 1.
Let's evaluate the given equation. As per the question, x, y, z elements including 1 unit element in a group is provided which means that x, y, and z are not equal to 0.
Therefore, the equation can be rewritten as x × y × z × 1 = 1.So, x × y × z = 1 ----(1)
Now, we need to check whether the equations yzx = 1 and yxz = 1 holds or not, that is, we need to check whether they satisfy the given equation xyz = 1 or not.Let's verify whether the equation yzx = 1 holds or not.
Substituting yzx in the equation xyz = 1, we get y × z × x = 1 ----(2)
Now, comparing equations (1) and (2), we can see that both equations are the same. So, yzx = 1 satisfies the given equation xyz = 1.Let's verify whether the equation yxz = 1 holds or not.
Substituting yxz in the equation xyz = 1, we get y × x × z = 1 ----(3)
Now, comparing equations (1) and (3), we can see that both equations are the same. So, yxz = 1 satisfies the given equation xyz = 1.
Therefore, both the equations yzx = 1 and yxz = 1 hold for the given equation xyz = 1.
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The answer is that the equations yzx = 1 and yxz = 1 hold when xyz = 1.
The equation xyz = 1 is provided for any x, y, z elements including 1 unit element in a group.
The question is whether the equations yzx = 1 and yxz = 1 hold when xyz = 1.
The answer is yes; yzx = 1 and yxz = 1 hold when xyz = 1.
Here is a proof:
Given that xyz = 1Multiplying both sides by yz, we get:(yz)(xyz) = yz(1)
Expanding the left-hand side using the associative law,
we get:(yz)(xyz) = y(zx)(yz)Since zy = yz,
we can substitute yz with zy to get:(zy)(xz)(zy) = zy
Expanding the left-hand side using the associative law,
we get:z(yx)(zy)z = zySince (yx)(zy) = yxz,
we can substitute to get:z(yxz)z = zyMultiplying both sides by z-1,
we get:yxz = yz-1 = yz
Using the same approach to the equation yxz = 1,
we can also prove that it holds when xyz = 1.
Hence, the answer is that the equations yzx = 1 and yxz = 1 hold when xyz = 1.
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Answer this question to get marked as brainliest!!!
For the graphs below, find f(g(-2)).
Answer:
g)112
Step-by-step explanation:
You wanna move it down to F by 4 squares
Using the given graph we must find the value of the composition of f(g(x)) evaluated in x = -2, we will get:
f(g(-2)) = 2
First, we need to find the value of g(-2), to get this, we look at the graph of g(x) and find the value when x = -2, it is:
g(-2) = -1
Then we have:
f(g(-2)) = f(-1)
Now we must find f(-1) in the f(x) graph, it is:
f(-1) = 2
Then we have:
f(g(-2)) = 2
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What is the awnser to this problem
Answer:
√65/11
Step-by-step explanation:
h=11
p=√56
b=? (L as reference)
By pythogorean theorem,
h^2=p^2+b^2
b=√(h^2-p^2)
b=√(11^2-√56^2)
b=√(121-56)
b=√65
cosL=b/h
√65/11
You can put it in decimal yourself if you want.
Paula is 10 less than thrice Kaye's age. Two years from now, Paula's age is twice Kaye's present age. How old is Kaye now?
( Please show solution )
Answer: Kaye is 4 years old
Step-by-step explanation:
Paula is 10 less than thrice of Kaye's age. two years from now, Paula's age is twice Kaye's present age. how old is Kaye now? Let Kaye's age now be x years Paula is 10 less than thrice of Kaye's age =3x-10 TWO YEARS LATER Paula,s age = (3x-10)+2 = 3x-8 3x-8 =x 2x=8 x=4 Kaya,s age = 4 years
What is the probability that a flight between new york city and chicago is less than 140 minutes?
The probability that a flight takes more than 140 minutes is approximately 0.333. (Option d: P(x > 140) = 0.333)
To find the probability that a flight takes more than 140 minutes, we need to calculate the proportion of the total distribution that lies beyond 140 minutes.
Given that the time to fly is uniformly distributed between 120 and 150 minutes, we can determine the length of the entire distribution as:
Length of distribution = maximum time - minimum time = 150 - 120 = 30 minutes.
The proportion of the distribution that lies beyond 140 minutes can be calculated as:
Proportion = (Length of distribution - Length up to 140 minutes) / Length of distribution
= (30 - (140 - 120)) / 30
= (30 - 20) / 30
= 10 / 30
= 1/3
≈ 0.333
Therefore, the probability that a flight takes more than 140 minutes is approximately 0.333.
Hence, the correct option is:
d) P(x > 140) = 0.333
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Complete Question:
The time to fly between New York City and Chicago is uniformly distributed with a minimum of 120 minutes and a maximum of 150 minutes.
What is the probability that a flight takes time more than 140 minutes? *
a-P(x> 140)=0.14
b-P(x> 140)=1.4
c-P(x> 140)=0
d-P(x> 140) = 0.333
which angles are linear pairs? check all that apply. ∠srt and ∠trv ∠srt and ∠tru ∠vrw and ∠wrs ∠vru and ∠urs ∠urw and ∠wrs
The angles that form linear pairs are ∠SRT and ∠TRU, and ∠VRW and ∠WRS. These pairs of angles are adjacent and their measures add up to 180 degrees, making them linear pairs.
To determine which angles are linear pairs, we need to identify pairs of adjacent angles whose measures add up to 180 degrees. Based on the given angles, ∠SRT and ∠TRU form a linear pair because they are adjacent and their measures add up to 180 degrees.
Similarly, ∠VRW and ∠WRS also form a linear pair because they are adjacent and their measures add up to 180 degrees. On the other hand, the remaining angle pairs, ∠SRT and ∠TRV, ∠VRU and ∠URS, and ∠URW and ∠WRS, do not meet the criteria for being linear pairs since their measures do not add up to 180 degrees.
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find the exact value of 2sin30 cos30
Answer:
\(\frac{\sqrt{3}}{2}\)
Step-by-step explanation:
Let's take a look at the unit circle below.
Remmeber that cos represents the x-value and that sin represents the y-value.
We see that:
\(sin(30)= \frac{1}{2}\\\text{and}\\ cos(30) = \frac{\sqrt{3}}{2}\)
Now we just multiply all the together and we get:
\(2*\frac{1}{2}*\frac{\sqrt{3}}{2} =\frac{\sqrt{3}}{2}\)
Question 1
Let f(x)=x3−4x2+6 and g(x)=f(−x)+4. Write a rule for g.
Answer
g(x)= - x3−4x²+10
Step-by-step explanation:
hello
Let f(x)=x3−4x2+6 so g(x)=f(−x)+4.
g(x)=(-x)3−4(-x)²+6+4
g(x)= - x3−4x²+10 is a rule for g be cause (-x)3=- x3 and (-x)²=x²
sketch the area represented by g(x). g(x) = x t2 dt 1
The area represented by g(x) is a triangular region with base 1 and height (7/3) x, where x is the variable along the horizontal axis. The resulting shape will be a right triangle with vertices at (0,0), (1,0), and (0, (7/3) x).
It seems like you are asking to sketch the area represented by the function g(x) given as the integral of x with respect to t from 1 to 2. However, there seems to be a typo in your question. I will assume that you meant g(x) = ∫[1 to x] t^2 dt. Please follow these steps to sketch the area represented by g(x):
1. Draw the function y = t^2 on the coordinate plane (x-axis: t, y-axis: t^2).
To sketch the area represented by g(x) = x t2 dt 1, we first need to evaluate the definite integral. Integrating x t2 with respect to t gives us (1/3) x t3 + C, where C is the constant of integration. Evaluating this expression from t=1 to t=2 gives us (1/3) x (2^3 - 1^3) = (7/3) x.
2. Choose an arbitrary x-value between 1 and 2 (e.g., x = 1.5).
3. Draw a vertical line from the x-axis to the curve of y = t^2 at x = 1.5. This line represents the upper limit of the integral.
4. Draw another horizontal axis from the x-axis to the curve of y = t^2 at x = 1. This line represents the lower limit of the integral.
5. The area enclosed by the curve y = t^2, the x-axis, and the vertical lines at x = 1 and x = 1.5 represents the area for the given value of x.
In conclusion, the area represented by g(x) = ∫[1 to x] t^2 dt can be sketched by plotting the curve y = t^2, choosing a specific x-value between 1 and 2, and then finding the enclosed area between the curve, x-axis, and the vertical lines at x = 1 and x = chosen x-value.
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Find the consumer's surplus at the market equilibrium point given that the demand function is p= 100 - 18x and the supply function is p = a +2.
To find the consumer's surplus at the market equilibrium point, we need to determine the equilibrium price and quantity by setting the demand and supply functions equal to each other. Then, we can calculate the area of the triangle below the demand curve and above the equilibrium price.
The equilibrium occurs when the quantity demanded equals the quantity supplied. By setting the demand and supply functions equal to each other, we can solve for the equilibrium price:
100 - 18x = a + 2
Simplifying the equation, we have:
18x = 98 - a
x = (98 - a)/18
Substituting this value of x into either the demand or supply function will give us the equilibrium price. Let's use the demand function:
p = 100 - 18x
p = 100 - 18((98 - a)/18)
p = 100 - (98 - a)
p = 2 + a
So, the equilibrium price is 2 + a.
To calculate the consumer's surplus, we need to find the area of the triangle below the demand curve and above the equilibrium price. The formula for the area of a triangle is 0.5 * base * height. In this case, the base is the quantity and the height is the difference between the equilibrium price and the price given by the demand function. Thus, the consumer's surplus is given by:
Consumer's Surplus = 0.5 * (98 - a) * [(100 - 2) - (2 + a)]
Simplifying further, we get the expression for the consumer's surplus at the market equilibrium point.
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Spanish class has a total of 30 students. The number of males is 12 more than the number of females. How many males and how many females are in the
class?
Number of males:
Number of females:
Answer:
21, 9
Step-by-step explanation:
If girls are x, then boys are x + 12
x + x + 12 = 30
2x + 12 = 30
2x = 18
x = 9
There are 9 girls and 21 boys
exercises 1 - 6 refer to the diagram shown .
Using the diagram of the circle given above, the value of the parts of the circle is as follows:
1.) Minor arc = Arc AB
2.) Major arc = Arc ACB
3.) Semicircle = AC
4.) Two central angles = 40° and 320°
5.) Arc AB = < 180°
6.) Arc ACB = > 180°
What is a major and minor arc of a circle?The minor arc of a circle is defined as part of the circle that is less than 180° that connects two points on the circumference of a circle.
The major arc of a circle is defined as the part of the circle that is greater than 180° that connects two points on the circle of a circle.
A semi circle is defined as exactly half of a circle which has a total of 180°.
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THIS IS MY 7TH POST OF THIS
The line plots represent data collected on the travel times to school from two groups of 15 students.
A horizontal line starting at 0, with tick marks every two units up to 28. The line is labeled Minutes Traveled. There is one dot above 4,6,14, and 28. There are two dots above 10, 12, 18, and 22. There are three dots above 16. The graph is titled Bus 47 Travel Times.
A horizontal line starting at 0, with tick marks every two units up to 28. The line is labeled Minutes Traveled. There is one dot above 10,16,20, and 28. There are two dots above 8 and 14. There are three dots above18. There are four dots above 12. The graph is titled Bus 14 Travel Times.
Compare the data and use the correct measure of variability to determine which bus is the most consistent. Explain your answer.
Bus 47, with an IQR of 8
Bus 14, with an IQR of 6
Bus 47, with a range of 8
Bus 14, with a range of 6
Bus 14 is more consistent as it has a smaller IQR and range, indicating less variability in the data.
Describe Range?In mathematics and statistics, range refers to the difference between the largest and smallest values in a dataset. It is a measure of the spread or dispersion of the data.
To find the range of a dataset, you simply subtract the smallest value from the largest value. For example, if you have a dataset of test scores: 65, 72, 80, 85, 92, 98, the highest score is 98, and the lowest score is 65. Therefore, the range of the test scores is 98 - 65 = 33.
While range is a simple and easy-to-calculate measure of dispersion, it can be sensitive to outliers or extreme values in the dataset, which may not be representative of the overall data. Other measures of dispersion, such as variance or standard deviation, may be more appropriate in some cases.
To determine which bus is the most consistent, we need to look at the measures of variability of each data set.
The interquartile range (IQR) is a measure of the spread of the middle 50% of the data. It is calculated by subtracting the first quartile (Q1) from the third quartile (Q3). A smaller IQR indicates less variability.
The range is the difference between the largest and smallest values in a data set. A smaller range indicates less variability.
For Bus 47, the IQR is 8 and the range is 8. For Bus 14, the IQR is 6 and the range is 6. Therefore, Bus 14 is more consistent as it has a smaller IQR and range, indicating less variability in the data.
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a women made a deposit of $218. if her deposit consisted of 62 bills, some of them one-dollar bills and the rest being five-dollar bills, how many one-dollar bills did she deposit?
F = quantity of five dollar bills
S = quantity of single dollar bills
so she deposited 62 bills, that means that whatever F and S are, we know that F + S = 62.
we also know that all those amount to $218, so the fives are really 5*F or 5F from those $218, and the singles are just 1*S of the same $218, so we can also say that 5F + S = 218.
\(F+S=62\implies F=62-S \\\\\\ 5F+S=218\implies \stackrel{\textit{substituting from above}}{5(62-S) +S=218}\implies 310-5S+S=218 \\\\\\ 310-4S=218\implies 310=4S+218\implies 92=4S\implies \cfrac{92}{4}=S\implies 23=S\)
The mean number of books read
last year by a group of students is
normally distributed with a mean of 10
and a standard deviation of 6. If Austin
is 0.5 standard deviations below the mean
and Kaleigh is 2 standard deviations
above the mean, how many more books
did Kaleigh read than Austin?
Answer:
I thing Kaleigh read 1.5 more than Austin
Step-by-step explanation:
Perform the indicated operations. Write the answer in standard form, a+bi.
(9 + 2i)(9 - 2i)
Answer:
It can't be expressed in that form
Step-by-step explanation:
From difference of two squares:
\({ \boxed{(a + b)(a - b) = ( {a}^{2} - {b}^{2} )}}\)
a » 9
b » 2i
\((9 + 2i)(9 - 2i) = \{ {(9)}^{2} - {(2i)}^{2} \} \\ \\ = (81 - 4 {i}^{2} )\)
but i² is -1 [ complex numbers ]
\( = \{81 - 4( - 1) \} \\ = 81 + 4 \\ = 85\)
Answer:
\((9 + 2i)(9 - 2i) \: \\ this \: can \: be \: wrtten \: as \: \\ {9}^{2} - {2i}^{2} = 81 - 4 \times - 1 \\ = 81 + 4 = 85 \\ then \: 85 + 0i \\ thank \: you\)
the length of a rectangle is 2 feet less than the three times length express the area of the rectangle as a function of its width, using correct function notation
The area of the rectangle as a function of its width is a=3b-2.
\(s=(3b-2)b\\=3b^{2}-2b\)
\(a=3b-2\)
What is the advantages of area ?
Area is significant in contemporary mathematics. Aside from its obvious significance in geometry and calculus, area is also a fundamental characteristic of surfaces in differential geometry and is connected to the definition of determinants in linear algebra. The amount of space within a form is measured by its area.
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A bank advertises a 2/1 arm at 2.75% with a 2/10 cap. what is the maximum interest rate that can be charged during the fifth year? a. 2.75% b. 4.75% 6c. 75% d. 8.75%
The maximum interest rate that can be charged during the fifth year is 6.75%. The correct option is the third option c. 6.75%
Calculating the maximum interest rate that can be chargedFrom the question, we are to determine the maximum interest rate that can be charged during the fifth year
A 2/1 ARM means that the interest rate is fixed for the first two years and then adjusts annually based on a specified index plus a margin. The "2/10 cap" means that the interest rate can only increase or decrease by a maximum of 2 percentage points each year, and can never be more than 10 percentage points higher than the initial rate.
Since the initial rate is 2.75%, the maximum rate that can be charged during the fifth year is:
2.75% + (2 x 2%) = 6.75%
Hence, the maximum interest rate that can be charged during the fifth year is 6.75%.
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the daily dinner bills in a local restaurant are normally distributed with a mean of $32.3 and a standard deviation of $7.6. what is the probability that a randomly selected bill will be for less than $28.65?
The probability that a randomly selected bill will be at least $39.10 is 0.03216 percent.
According to the question, given that
The average daily dinner tab at a nearby restaurant has a normal distribution with a standard deviation of $6 and a mean of $28.
Let X = daily dinner bills in a local restaurant
So, X ~ N(μ = 28, σ^2 = \(6^{2}\) )
The following equations give the normal distribution's z-score probability distribution:
Z = (X - μ) /σ ~ N(0,1)
where, μ = mean amount = $28
σ = standard deviation = $6
The Z-score calculates the deviation of the measure from the mean in standard deviations. We look at the z-score table after determining the Z-score to determine the p-value (area) connected to it. The likelihood that the measure's value is less than X, or the percentile of X, is represented by this p-value.
As a result, = P(X $39.10) is the chance that a randomly chosen bill will be at least $39.10.
P(X ≥ $39.10) = P (X - μ) /σ ≥ \(\frac{39.10 - 28}{6}\)) = P(Z ≥ 1.85) = 1 - P(Z < 1.85)
= 1 - 0.96784 = 0.03216
Now, the P(Z x) or P(Z x) is presented in the z table. By examining the value of x = 1.85 in the z table, which has an area of 0.96784, the probability stated above is derived.
Therefore, there is a 0.03216 percent chance that a randomly chosen bill will be at least $39.10.
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in a certain game, points you win are positive numbers and points you lose are negative numbers. What is the value of the series plays: win 8, lose 7, will 11, lose 2?
a -15
B -4
C 4
d 12
Answer:
4
Step-by-step explanation
+8 + (-7) + (+11) + (-2)= 4
The value of the series plays is 10.
--------------------------
In this question, we have to find the total amount of points, considering the number of points on each series.
Win 8: Add 8 points.Lose 7: Subtract 7 points.Win 11: Add 11 points.Lose 2: Subtract 2 points.--------------------------
The total is:
\(T = 8 - 7 + 11 - 2 = 1 + 9 = 10\)
10 points.
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8. true or false: the population parameter will always be between the lower and upper bounds of the confidence interval. 9. true or false: the sample statistic will always be between the lower and upper bounds of the confidence interval.
The population parameter will always be between lower and upper bounds of the confidence interval. - True, whereas sample statistic will always be between lower and upper bounds of the confidence interval - False
With a certain degree of certainty, the population parameter is anticipated to lie between the lower and higher limits of the confidence interval. The confidence interval, which gives an interval estimate of the unidentified population parameter, is created based on the sample data. The interval's level of confidence shows the amount of ambiguity we are prepared to accept when determining the actual population parameter.
The confidence interval's lower and upper limits may or may not be met by the sample statistic used to compute them. A single point estimate, the sample figure is susceptible to sampling error. On the other hand, based on the observed sample data and the selected degree of confidence, the confidence interval is a range of values that we can be fairly confident includes the true population parameter.
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A cell phone company tests 95 cell phones and finds that 7 of them have defects. Out of 760 cell phones, how many would you expect to have defects?
You can predict that
of the cell phones will have defects.
Answer: 60
Step-by-step explanation:
From the question, a cell phone company tests 95 cell phones and finds that 7 of them have defects. This. means that 7/95 are defective.
If 760 cell phones are tested, the number that will be expected to have defects will be:
= 7/95 × 760
= 59.99
= 60 Approximately
Answer:
56 C:
Step-by-step explanation:
Just divide 95 by 7 yes you heard me right then multip,y by 760 you can use calculator to get 56
Used to coordinate gird plane to find a distance between the points round to the nearest hundred
Answer:
8.94
Step-by-step explanation:
Distance formula:
\(d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}\)
\(d = \sqrt{(3 - (-5))^2 + (2-6)^2}\)
\(d = \sqrt{(64 + 16)}\)
\(d= \sqrt{80}\)
\(d= 8.94\)
A gas station sells Q gallons of gasoline per year, which is delivered N times per year in equal shipments of Q/N gallons. The cost of each delivery is d dollars and the yearly storage costs are sQT, where T is the length of time (a fraction of a year) between shipments and s is a constant. Which value of N minimize the costs?
The value of N that minimizes the costs is N = sqrt(s * Q / d).
To minimize the costs of a gas station selling Q gallons of gasoline per year:
We need to find the optimal value of N,
which represents the number of shipments per year.
Given that the cost of each delivery is d dollars and the yearly storage costs are sQT, where T is the length of time (a fraction of a year) between shipments and s is a constant,
we need to find the minimum total cost, which consists of delivery and storage costs.
Total Cost = Delivery Cost + Storage Cost
Delivery Cost = d * N (since there are N deliveries per year)
Storage Cost = s * Q * T (as given)
As T is the time between shipments, we have:
T = 1/N (since there are N shipments per year)
Now, we can rewrite the storage cost as:
Storage Cost = s * Q * (1/N)
The total cost can now be written as:
Total Cost = d * N + s * Q * (1/N)
To minimize the total cost, we need to find the minimum value for the above function with respect to N.
We can do this by taking the first derivative with respect to N and setting it equal to zero.
d(Total Cost)/dN = d * 1 - s * Q * (1/N^2) = 0
Now, solving for N:
N^2 = s * Q / d
N = sqrt(s * Q / d)
Thus, the value of N that minimizes the costs is N = sqrt(s * Q / d).
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The mass of 25 packets of biscuits is 0.7kg. There are 4 biscuits in 1 packet. What mass of 1 biscuit?
Answer:
0.007 kg
Step-by-step explanation:
There are 25 packets
Each packet contains 4 biscuits.
The total number of biscuits = 4 * 25
The total number of biscuits = 100
100 biscuits = 0.7 kg
1 biscuit is 0.7 kg / 100
1 biscuit is 0.007 kg
If you are not sure of this, put it in a calculator.
Just out of curiosity note that 1 kg = 1000 grams
0.007 kg = 0.007 * 1000 = 7 grams each.
use 0.007 as your answer.
in a survey conducted on an srs of 200 american adults, 72% of them said they believed in aliens. give a 95% confidence interval for percent of american adults who believe in aliens.
A 95% confidence interval for percent of american adults who believe in aliens: (0.6578, 0.7822)
In this question we have been given that in a survey conducted on an srs of 200 american adults, 72% of them said they believed in aliens
We need to find the 95% confidence interval for percent of american adults who believe in aliens.
95% confidence interval = (p ± z√[p(1 - p)/n])
Here, n = 200
p = 72%
p = 0.72
And the z-score for 95% confidence interval is 1.960
The upper limit of interval would be,
(p + z√[p(1 - p)/n])
= 0.72 + 1.960 √[0.72(1 - 0.72)/200]
= 0.72 + 1.960 √[(0.72 * 0.28)/200]
= 0.72 + 1.960 √0.001008
= 0.72 + 0.0622
= 0.7822
The lower limit of interval would be,
(p - z√[p(1 - p)/n])
= 0.72 - 1.960 √[0.72(1 - 0.72)/200]
= 0.72 - 1.960 √[(0.72 * 0.28)/200]
= 0.72 - 1.960 √0.001008
= 0.72 - 0.0622
= 0.6578
Therefore, a 95% confidence interval = (0.6578, 0.7822)
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2/5 how do I put this in to decimal by rounding to the nearest tenth
Step-by-step explanation:
0.4
hope this helps. :)......
Answer:
0.4
Step-by-step explanation:
2/5 is also written as 4/10
4/10 = 0.4
PLEASE HELP ITS ALMOST DUE!!! I'll GIVE BRAINLIEST THANKS AND 5 STARTS JUST PLS
Answer: The top 25.
Step-by-step explanation:
Answer:
\(x=-25\)
Step-by-step explanation:
\(-\frac{2}{5}x=10\)
Multiply both sides by 5:-
\(5\left(-\frac{2}{5}x\right)=10\times \:5\)
\(-2x=50\)
Divide both sides by -2:-
\(\frac{-2x}{-2}=\frac{50}{-2}\)
\(x=-25\)
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