The term 6Y in an algebraic expression is referred to as: Coefficient
How to identify terms in algebra?- Terms is each part of an algebraic expression separated by a plus or minus sign.
- Factor is a product of two or more numbers, algebraic variables or algebraic expressions .
- Coefficient is the numerical factor of a term that contains a variable.
- Variable is a symbol, usually a letter, used to represent a number.
- Constant is a term without a variable.
We are given the term 6Y and from the definition above, we can see that it is a coefficient.
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linear equations
1. 4= x + 2
2. 6= x-3
3. 7= a + 4
4. 6= x - 7
5. 1= c - 2
6. 5= s + 2
7. x + 3=10
8. c + 4= 4
9. 3= b + 2
10. 6 + c= 10
11. 7= x + 3
12. x + 1= 9
13. x + 3= 15
14. y -6 = 4
15. x - 7 = 4
16. 6= x - 4
17. x - 4 = 2
18. x - 9 = 2
what equation represents this sentence? 28 is the quotient of a number and 4. responses 4=n28 4 equals n over 28 28=n4 28 equals n over 4 28=4n 28 equals 4 over n 4=28n 4 equals 28 over n
The equation that represents the sentence "28 is the quotient of a number and 4" is 28 = n/4.
In the given sentence, "28 is the quotient of a number and 4," we can break down the sentence into mathematical terms. The term "quotient" refers to the result of division, and "a number" can be represented by the variable "n." The divisor is 4.
1) Define the variable.
Let's assign the variable "n" to represent "a number."
2) Write the equation.
Since the sentence states that "28 is the quotient of a number and 4," we can write this as an equation: 28 = n/4.
The equation 28 = n/4 represents the fact that the number 28 is the result of dividing "a number" (n) by 4. The left side of the equation represents 28, and the right side represents "a number" divided by 4.
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A company that manufactures playing cards ensures the cards can be stacked in a deck and
placed in a box to be sold. Which units are most appropriate for measuring the thickness of a
playing card?
lcm of 420 and 210
MATHS
Answer:
LCM = 420
Step-by-step explanation:
What is the LCM of 210 and 420?
Step 1:
Find the prime factorization of 210
210 = 2 × 3 × 5 × 7
Step 2:
Find the prime factorization of 420
420 = 2 × 2 × 3 × 5 × 7
Step 3:
Multiply each factor the greater number of times it occurs in steps i) or ii) above to find the LCM:
LCM = 2 × 2 × 3 × 5 × 7
Step 4:
The required LCM
LCM = 420
Therefore, we conclude that:
LCM = 420
i really need help with this, ill give brainly.
Answer:
the rate of change is-3 2
A hole of radius 6cm is drilled through a right circular cylinder whose base radius and height are 9cm and 12cm respectively. What is the total surface area of the resulting solid?
A. 117πcm ²
B. 315 πcm²
C. 450πcm²
D. 360πсm²
Answer:
CSA of cylinder= 2πr(h+r)
=2 π×9 (21)
= 378π cm²
now
CSA of hole= 2πr
12π cm²
a circle rug measures 8ft across. what is the area of the rug
Hey there!The distance across a circle is called the diameter. Half of the diameter is the radius. To find the area of a circle, you take the radius, square it, and then multiply it by pi. Let's do it below.8²=6464*3.14=200.96Therefore, the area of the rug is 200.96 ft².I hope this helps! Have a great day.
suppose you want to borrow $200,000 from the bank to buy a home and agree to repay the loan in 360 equal monthly payments, including all interest due. the bank charges 0.35% per month on the unpaid balance (4.2% per year compounded monthly).
Answer the following questions about this loan. How much is the monthly payment? $ .......... Round to the nearest cent.
........................
After making 360 monthly payments, how much will you have paid in total to the bank? $ .................... Round to the nearest cent. .............................
After making 360 monthly payments, how much of what you paid the bank was interest? $ ............. Round to the nearest cent.
........................
The monthly payment for the loan is $1,013.16. After making 360 monthly payments, you will have paid a total of $364,137.64 to the bank. The total interest paid to the bank over the 360 months is $164,137.64.
Determine the monthly payment?To calculate the monthly payment, we can use the formula for calculating the monthly payment on a loan:
\(\[M = \frac{P \cdot r \cdot (1 + r)^n}{(1 + r)^n - 1}\]\)
Where:
M is the monthly payment,
P is the principal loan amount,
r is the monthly interest rate, and
n is the total number of payments.
In this case, the principal loan amount is $200,000, the monthly interest rate is 0.35% (or 0.0035 as a decimal), and the total number of payments is 360. Plugging these values into the formula, we find that the monthly payment is $1,013.16.
To calculate the total amount paid to the bank over the 360 months, we simply multiply the monthly payment by the total number of payments: $1,013.16 * 360 = $364,137.64.
The total interest paid to the bank can be calculated by subtracting the principal loan amount from the total amount paid: $364,137.64 - $200,000 = $164,137.64.
Therefore, the monthly payment for the loan is $1,013.16, and after 360 monthly payments, the total payment to the bank is $364,137.64, with $164,137.64 being the total interest paid.
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Write the equation in Slope-Intercept Form that goes through (0, -1) and (1, 2).
Answer:
hi
Step-by-step explanation:
hi
Answer: The slope m of the line through any two points (x 1, y 1) and (x 2, y 2) is given by: The y-intercept b of the line is the value of y at the point where the line crosses the y axis. Since for point (x 1 , y 1 ) we have y 1 = m x 1 + b , the y-intercept b can be calculated
Step-by-step explanation:
Suppose that, in an alternate universe, the possible values of m
l
are the integer values including 0 ranging from −l−1 to l+1 (instead of simply −l to +l ). How many orbitals would exist in each of the following subshells? A. p subshell B. d subshell Which atomic orbitals have values of n=3 and I=1 ?
A. In the alternate universe, the p subshell would have 5 orbitals.
B. In the alternate universe, the d subshell would have 10 orbitals.
In the alternate universe where the possible values of mℓ range from -l-1 to l+1, the number of orbitals in each subshell can be determined.
A. For the p subshell, the value of l is 1. Therefore, the range of mℓ would be -1, 0, and 1. Including the additional values of -2 and 2 from the alternate universe, the total number of orbitals in the p subshell would be 5 (mℓ = -2, -1, 0, 1, 2).
B. For the d subshell, the value of l is 2. In the conventional universe, the range of mℓ would be -2, -1, 0, 1, and 2, resulting in 5 orbitals. However, in the alternate universe, the range would extend to -3 and 3. Including these additional values, the total number of orbitals in the d subshell would be 10 (mℓ = -3, -2, -1, 0, 1, 2, 3).
Therefore, in the alternate universe, the p subshell would have 5 orbitals, and the d subshell would have 10 orbitals.
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help with math? heres the question.
-
answer options:
8
2
5
3
Determine the base-five representation a) 214 b) 62 c) 8 d) 95 a) 214=
a) 214 in base-five is 1324.
b) 62 in base-five is 222.
c) 8 in base-five is 13.
d) 95 in base-five is 340.
How is this so?
a) To determine the base five representation of 214, we need to find the largest power of five that is less than or equal to 214.
In this case, 125 (5³) is the largest power of five that is less than 214.
Now, we divide 214 by 125 -
214 ÷ 125 = 1 remainder 89
Next, we divide the remainder, 89, by the next lower power of five, which is 25 (5²) -
89 ÷ 25 = 3 remainder 14
Finally, we divide the remaining 14 by the lowest power of five, which is 5 itself -
14 ÷ 5 = 2 remainder 4
Therefore, the base-five representation of 214 is 1324 in base-five.
b) Following the same steps as above -
62 ÷ 25 = 2 remainder 12
12 ÷ 5 = 2 remainder 2
Hence, the base-five representation of 62 is 222 in base-five.
c) 8 ÷ 5 = 1 remainder 3
this menas that the base-five representation of 8 is 13 in base-five.
d) Following the same steps as above -
95 ÷ 125 = 0 remainder 95
95 ÷ 25 = 3 remainder 20
20 ÷ 5 = 4 remainder 0
Hence, the base-five representation of 95 is 340 in base-five.
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1. The White Horse Apple Products Company purchases apples from local growers and makes applesauce and apple juice. It costs $0.60 to produce a jar of applesauce and $0.85 to produce a bottle of apple juice. The company has a policy that at least 30% but not more than 60% of its output must be applesauce. - The company wants to meet but not exceed the demand for each product. The marketing manager estimates that the demand for applesauce is a maximum of 5,000 jars, plus an additional 3 jars for each $1 spent on advertising. The maximum demand for apple juice is estimated to be 4,000 bottles, plus an additional 5 bottles for every $1 spent to promote apple juice. The company has $16,000 to spend on producing and advertising applesauce and apple juice. Applesauce sells for $1.45 per jar; apple juice sells for $1.75 per bottle. The company wants to know how many units of each to produce and how much advertising to spend on each to maximize profit. a. Formulate a linear programming model for this problem. b. Solve the model by using the computer.
The linear programming model would include equation for profit will be Z = 0.85X + 0.9Y and production constraints are 0.3X <= Y <= 0.6X; demand constraints are X <= (5000 + 3A) and Y <= (4000 + 5B); and cost constraint are 0.6X + 0.85Y + A + B <= 16,000.
Optimal values of X, Y, A, and B that maximize profit (Z) can be determined by using Excel Solver.
The linear programming model for the given problem is shown below:
Let X be the number of jars of applesauce produced. Y be the number of bottles of apple juice produced.
The objective function will be to maximize profit, which can be calculated by the following equation:
Profit = revenue - cost
Revenue can be calculated by multiplying the number of units produced by their respective selling prices. Cost can be calculated by multiplying the number of units produced by their respective production costs. The equation for profit will be:
Z = 1.45X + 1.75Y - (0.6X + 0.85Y)
Z = 0.85X + 0.9Y
The marketing manager estimates that the demand for applesauce is a maximum of 5,000 jars, plus an additional 3 jars for each $1 spent on advertising. The maximum demand for apple juice is estimated to be 4,000 bottles, plus an additional 5 bottles for every $1 spent on promoting apple juice. The maximum amount of money that can be spent on production and advertising is $16,000.
Therefore, we can write the constraints as follows:
Production constraints:
0.3X <= Y <= 0.6X
Demand constraints:
X <= (5000 + 3A)
Y <= (4000 + 5B)
Cost constraint:
0.6X + 0.85Y + A + B <= 16,000
Where A and B are the amounts spent on advertising for applesauce and apple juice, respectively.
To solve the model by using the computer, we can use any software that solves linear programming problems.
One such software is Microsoft Excel Solver. We can set up the problem in Excel as follows:
Cell C9: 0.85X + 0.9Y
Cell C12: 0.6X + 0.85Y + A + B
Cell C13: $16,000
Cell C15: 0.3X
Cell C16: XCell C17: 0.6X
Cell C18: 5000 + 3A (for applesauce)
Cell C19: Y
Cell C20: 4000 + 5B (for apple juice)
Cell C21: A
Cell C22: B
We then use Excel Solver to find the optimal values of X, Y, A, and B that maximize profit (Z).
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show work
Simplify this expression by combining the like terms
7y + 10 + 3y - 4 - 6y
consider the monty hall problem discussed in lecture. take the case where there are 6 doors. behind 5 doors there are goats and behind 1 door there is a car. you will pick a door and then the host will open 4 remaining doors revealing goats. assume that you always then switch to the last remaining door. what is the probability of winning the car?
The probability of winning the car in this Monty Hall problem with 6 doors is 83.33%.
In this scenario, there are 6 doors, with 1 car behind one of them and goats behind the other 5. You pick a door, and the host opens 4 other doors revealing goats. You always switch to the last remaining door.
To find the probability of winning the car, follow these steps:1. Initially, there is a 1/6 chance you picked the car and a 5/6 chance you picked a goat.
2. If you picked a goat (5/6 probability), the host will open the other 4 doors with goats, leaving the car behind the last remaining door. In this case, switching will win you the car.
3. If you picked the car (1/6 probability), the host will still open 4 doors with goats, but switching would make you lose the car in this case.
Since you always switch, the probability of winning the car is the same as the probability of initially picking a goat, which is 5/6. So, the probability of winning the car is approximately 83.33%.
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Plz help I'll give brainy!!!
Complete the missing parts of the
table for the following function.
y=(1/5)^x
X-2 -1 0 1 2 3
y [?] [ ] 1 1/5. 1/?
1/125
Answer:
see below
Step-by-step explanation:
we are given a exponential function
\( \displaystyle y = \left(1/5\right) ^{x} \)
we want to figure out the missing values of y for x i.e (-2,-1, and 2) to do we can consider substituting so,
when x is -2 y should be
\( \displaystyle y = \left(1/5\right) ^{ - 2} \)
rewrite ⅕ in exponent notation:
\( \displaystyle y = \left((5) ^{ - 1} \right) ^{ - 2} \)
by law of exponent we obtain:
\( \displaystyle y = (5) ^{ 2} \)
simplify square:
\( \displaystyle y = \boxed{ 25}\)
when x is -1:
\( \displaystyle y = \left(1/5\right) ^{ - 1} \)
rewrite ⅕ in exponent notation:
\( \displaystyle y = \left((5) ^{ - 1} \right) ^{ - 1} \)
use law of exponent which yields:
\( \displaystyle y = \boxed5 \)
when x is 3:
\( \displaystyle y = \left(1/5\right) ^{ 3} \)
by law of exponent we obtain:
\( \displaystyle y = 1/ {5}^{3} \)
simplify square which yields:
\( \displaystyle y = \frac{1}{ \boxed{125}} \)
Answer:
25 5 1/125
Step-by-step explanation:
What is the polar form of (x + 3)2 + y2 = 9?
r = −6 cos(θ)
r = −3 cos(θ)
r = 3 cos(θ)
r = 6 cos(θ)
Answer:
r = -6 cos(θ)
Step-by-step explanation:
got it right on edge
The equation (x + 3)² + y² = 9 into polar form is r = -6 cos(θ). The correct answer would be option (A).
What is the polar form?The polar form of a complex number is given by r(cos(θ) + i sin(θ)), where r is the distance from the origin and θ is the angle formed by the point and the positive x-axis.
To convert the equation (x + 3)² + y² = 9 into polar form, we can complete the square on the x and y terms:
(x + 3)² + y² = (x² + 6x + 9) + y² = 9
Then we can express x and y in terms of r and θ:
x = r cos(θ) , y = r sin(θ)
Substituting these values into the equation and simplifying:
r² cos²(θ) + 6r cos(θ) + r² sin²(θ) = 9
r²(cos²(θ) + sin²(θ)) + 6r cos(θ) = 0
r² + 6r cos(θ) = 0
r(r + 6cos(θ)) = 0
Since r ≠ 0
So, the polar form of the equation is:
r = -6cos(θ)
Thus, the correct answer would be an option (A).
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A bug begins to crawl up a vertical wire at time t = 0. The velocity v of the bug at time t, 0 < t < 8, is given by the function whose graph is shown behind this text. At what value of t does the bug change direction? a. 2
b. 4
c. 6.5
d. 7
The bug changes direction at t = 4. This can be answered by the concept of velocity.
To determine when the bug changes direction, we need to find when its velocity changes sign from positive to negative. From the graph, we see that the bug's velocity is positive for t < 4 and negative for t > 4. Therefore, the bug changes direction at t = 4.
To verify this, we can look at the behavior of the bug's velocity as it approaches t = 4. From the graph, we see that the bug's velocity is increasing as it approaches t = 4 from the left, and decreasing as it approaches t = 4 from the right. This indicates that the bug is reaching a maximum velocity at t = 4, which is when it changes direction.
Therefore, the bug changes direction at t = 4.
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A very good poker player is expected to earn $1 per hand in $100/$200 Texas poker Hold'em. The standard deviation is approximately $31.
a) What is the probability of a very good poker player earns a profit(more than $0) after playing 40 hands in $100/$200 Texas Hold'em?
b) What proportion of the time can a very good poker player expect to earn at least $500 after playing 100 hands in $100/$200 Texas Hold'em.
c) Suppose that twenty hands are played per hour. What is the probability that a very good poker player earns a profit during a 14 hour session?
a) The probability of a very good poker player earning a profit (more than $0) after playing 40 hands in $100/$200 Texas Hold'em can be calculated using the normal distribution and the given mean ($1) and standard deviation ($31). b) The proportion of the time a very good poker player can expect to earn at least $500 after playing 100 hands in $100/$200 Texas Hold'em can be calculated using the normal distribution and the given mean ($1) and standard deviation ($31).
To compute these probabilities, we need to make some assumptions and use probability distribution calculations based on the given information.
a) To determine the probability of a profit after playing 40 hands, we can use the concept of the normal distribution. We need to calculate the z-score using the formula: z = (x - μ) / σ, where x is the desired profit, μ is the expected profit per hand, and σ is the standard deviation. In this case, x = $0, μ = $1, and σ = $31.
Once we have the z-score, we can use a standard normal distribution table or calculator to find the corresponding probability.
b) Similarly, to find the proportion of the time a player can expect to earn at least $500 after playing 100 hands, we need to calculate the z-score for x = $500, using the same formula as in part (a). Then, we can use the standard normal distribution table or calculator to find the corresponding proportion.
c) To determine the probability of earning a profit during a 14-hour session, we need to calculate the number of hands played, which is 20 hands per hour multiplied by 14 hours. Let's denote it as N. Then, we can calculate the mean profit for the 14-hour session by multiplying the expected profit per hand ($1) by N.
The standard deviation for the session can be calculated by multiplying the standard deviation per hand ($31) by the square root of N. Finally, we can use the normal distribution and the same z-score calculation as in part (a) to find the probability.
Please note that the above calculations assume that the profits from each hand are independent and follow a normal distribution. Real poker outcomes may deviate from these assumptions.
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quare roots are the blank of perfect squares
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
bob buys a t-shirt for $7.45 he pays with a 20 bill. how much change will he get?
Answer: $12.55
Step-by-step explanation:
Graph of triangle ABC in quadrant 3 with point A at negative 8 comma negative 4. A second polygon A prime B prime C prime in quadrant 4 with point A prime at 4 comma negative 8. 90° clockwise rotation 180° clockwise rotation 180° counterclockwise rotation
The rotation rule used in this problem is given as follows:
90º counterclockwise rotation.
What are the rotation rules?The five more known rotation rules are given as follows:
90° clockwise rotation: (x,y) -> (y,-x)90° counterclockwise rotation: (x,y) -> (-y,x)180° clockwise and counterclockwise rotation: (x, y) -> (-x,-y)270° clockwise rotation: (x,y) -> (-y,x)270° counterclockwise rotation: (x,y) -> (y,-x).The equivalent vertices for this problem are given as follows:
A(-8,-4).A'(4, -8).Hence the rule is given as follows:
(x,y) -> (-y,x).
Which is a 90º counterclockwise rotation.
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Let R be the region in the fourth quadrant enclosed by the x-axis and the curve y=x²-2kx, where k is a constant. If the area of the region R is 36, then the value of k is
a)-3
b)3
c)4
d) 6
To solve this problem, we need to find the x-values where the curve intersects the x-axis, which occurs when y=0.
0=x²-2kx ,We can factor out an x: 0=x(x-2k) .So the x-intercepts are at x=0 and x=2k.
To find the value of k, we need to follow these steps:
Step 1: Find the points of intersection between the curve y = x^2 - 2kx and the x-axis.
To do this, set y = 0:
0 = x^2 - 2kx
x(x - 2k) = 0
This means that the curve intersects the x-axis at x = 0 and x = 2k.
Step 2: Determine the limits of integration.
Since we are looking for the region in the fourth quadrant, we will have limits 0 and 2k for our integration.
Step 3: Calculate the area using integration.
Area = ∫[0 to 2k] (x^2 - 2kx) dx
Step 4: Solve the integral.
Area = [1/3x^3 - kx^2] evaluated from 0 to 2k
Area = (1/3(2k)^3 - k(2k)^2) - (1/3(0)^3 - k(0)^2)
Area = (8k^3/3 - 4k^3)
Step 5: Set the area equal to 36 and solve for k.
36 = 8k^3/3 - 4k^3
36 = (8k^3 - 12k^3)/3
36 = -4k^3/3
Now, multiply both sides by 3 and divide by -4:
-108/-4 = k^3
27 = k^3
Take the cube root of both sides:
k = 3
The value of k is 3 (Option b).
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Use the normal approximation to find the indicated probability. The sample size is n, the population proportion of successes is p, and X is the number of successes in the sample.
n = 90, p = 0.6: P(X ≥ 63)
The probability of having 63 or more successes in the sample is approximately 0.0266, or 2.66%.
To use the normal approximation to find the probability P(X ≥ 63) for a sample size of n = 90 and population proportion of successes p = 0.6, follow these steps:
Step 1: Calculate the mean (μ) and standard deviation (σ) for the binomial distribution.
\(μ = n * p\) = 90 * 0.6 = 54
\(σ = \sqrt{(n * p * (1 - p))} = \sqrt{(90 * 0.6 * 0.4) }\)= √21.6 ≈ 4.65
Step 2: Use the normal approximation.
To find P(X ≥ 63), first convert X to a z-score:
z = \((X - μ) / σ\) = (63 - 54) / 4.65 ≈ 1.93
Step 3: Find the probability using a z-table or calculator.
Using a z-table or calculator, find the probability of a z-score less than 1.93 (since we want P(X ≥ 63), we need to find the area to the right of the z-score):
P(Z ≤ 1.93) ≈ 0.9734
Step 4: Calculate the complement probability.
Since we want P(X ≥ 63), we need to find the complement probability (1 - P(Z ≤ 1.93)):
P(X ≥ 63) = 1 - 0.9734 = 0.0266
So, the probability of having 63 or more successes in the sample is approximately 0.0266, or 2.66%.
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please show calculations
Answer:
i can't understand can u show it carefully
Estimate ∫30f(x)g′(x)dx, if f(x)=x3 and g(x) has the values given in the table below.
∫30f(x)g′(x)dx = _____
The value of the integral ∫30f(x)g'(x)dx.
The integral ∫30f(x)g'(x)dx can be estimated by first finding the derivative of g(x) with respect to x, denoted as g'(x), and then evaluating the product of f(x) and g'(x) over the interval [0, 30], where f(x) = x³.
Let's denote g'(x) as dg(x)/dx, the derivative of g(x) with respect to x. Then, the estimation of the integral can be expressed mathematically as:
∫30f(x)g'(x)dx ≈ ∑[f(x_i) * g'(x_i)] * Δx_i
where x_i represents the values of x from the interval [0, 30] (e.g., x_0, x_1, x_2, ..., x_n), Δx_i represents the corresponding intervals between the values of x_i, and f(x_i) and g'(x_i) represent the values of f(x) and g'(x) at each x_i, respectively.
By calculating the product of f(x_i) and g'(x_i) at each x_i, summing them up over the interval [0, 30] with appropriate intervals Δx_i, and taking the approximation,
we can estimate the value of the integral ∫30f(x)g'(x)dx.
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Please help, due tomorrow. Will give brainlist
Answer/Explanation
x y
-1 -3
0 0
y- intercept (0,0)
slope: 3
At ice skating lessons Sarah attempts to do a 360 degree spin, but only manages a quarter-turn on her first attempt
How many degrees short of her goal was Sarah's first attempt?
degrees
Answer:
Im sorry if this is wrong.
a quarter is 1/4. 1/4 is .25 so 360-25=335. so she only did 335 degree spin and was 25 degrees short
Step-by-step explanation:
The degree of spin Sarah wants to = 360 degrees
Hence, 1 turn = 360 degrees
Sarah does a quarter turn
A quarter is equivalent to : \(\frac{1}{4}\)
So, \(\frac{1}{4}\) turn = \(\frac{1}{4}\) x 360 degrees
= 90 degrees.
The number of degrees short of her goal that Sarah was of her first attempt is calculated as :
360 degrees - 90 degrees
= 270 degrees.
Therefore, Sarah was 270 degrees short of her goal at her first attempt.
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Can someone please help me I will mark brainliest please.
Answer:
GE = 8 inches
Step-by-step explanation:
The diagonals of a parallelogram bisect each other, then
GE = 2 × GH = 2 × 4 = 8 inches
85 EN PHYSIQUE Fonctionnement de l'ail
Le fonctionnement optique de l'oeil peut être modélisé
de façon simplifiée par une lentille simple convergente,
le cristallin. Les images des objets se forment sur la rétine,
modélisée sur le schéma par la droite (A'B').
La distance entre le cristallin et la rétine est fixe et dans la
suite, on prendra OA' = 20 mm.
Le point B', sommet de l'image formée, est construit
comme l'intersection:
- du rayon lumineux non dévié, qui passe par le sommet
B de l'objet et le centre optique o de la lentille (rayon en
rouge sur le schéma).
- du rayon lumineux parallèle à l'axe et issu du sommet B
de l'objet qui change de trajectoire après avoir traversé
la lentille et passe par le foyer F (rayon en vert sur le
schéma).
Lentille mince
convergente
lumière
B
Objet
Foyer F.
A
A
Axe principal
Image
B'
+
OF
On suppose dans la suite que OA> OF comme ci-dessus
pour avoir une image réelle.
OA'
1. Démontrer que
A'B'
A'B' A'F
puis que
ОА AB
AB OF
A'F OA'
1
En déduire que
puis que
OF
ОА
OA OA'
2. a. On suppose que OA = 25 m. Calculer OF.
b. Si OA> 25, que peut-on en déduire sur
1
ОА
Et sur
OF
puis sur OF?
C. Pourquoi dit-on en physique que « lorsque l'oeil
regarde un objet à l'infini, le foyer Fest situé sur la
rétine >>?
?
Chapitre 3. Puissances. Fonction cube et fonction inverse
Answer:
English
Step-by-step explanation: