Answer:
1.
Explanation:
Hello!
In this case, for such mathematical operations, we can wee that the slash represents a fraction or a division, say 8 ÷ 4 = 2, 6 ÷ 3 = 2, 20 ÷ 4 = 5, etc. In such a way, since the operation 2/2, represents 2 ÷ 2, it is clear that two is once in 2, therefore, the result is:
2 ÷ 2 = 1.
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A small bag of sand is released from an ascending hot‑air balloon whose constant, upward velocity is 0=2.25 m/s . Knowing that at the time of the release the balloon was 35.8 m above the ground, determine the time it takes for the bag to reach the ground from the moment of its release. Use =9.81 m/s2.
The time that takes for a small bag of sand to reach the ground after it is released from an ascending hot-air balloon whose upward velocity is 2.25 m/s is 2.94 s.
We can find the time that takes for the bag to reach the ground with the following equation:
\( y_{f} = y_{i} + v_{i_{y}}t + \frac{1}{2}gt^{2} \) (1)
Where:
\( y_{f} \): is the final height = 35.8 m
\( y_{i} \): is the initial height = 0
\( v_{i_{y}} \): is the initial velocity = 2.25 m/s
t: is the time =?
g: is the acceleration due to gravity = 9.81 m/s²
When the bag is released, it will move upward until it reaches a maximum height and then begins to fall. We can find the time that takes for the bag to reach the maximum height as follows:
\( v_{f} = v_{i} - gt \) (2)
Where:
\( v_{f} \): is the final velocity = 0 (at the maximum height)
\( v_{i} \): is the initial velocity = 2.25 m/s
The time is:
\( t = -\frac{v_{f} - v_{i}}{g} = \frac{2.25 m/s}{9.81 m/s^{2}} = 0.23 s \)
This is the rise time it takes for the bag to reach the maximum height, which is equal to the fall time it takes for the bag to reach the same starting point (35.8 m above the ground), so:
\( t = 0.23 s*2 = 0.46 s \)
Now, from equation (1) we have:
\( 35.8 m = 0 + 2.25 m/s*t + \frac{1}{2}9.81 m/s^{2}*t^{2} \)
By solving the above quadratic equation for t we have:
\( t = 2.48 s \)
Hence, the total time is:
\( t = 2.48 s + 0.46 s = 2.94 s \)
Therefore, the time that it takes for the bag to reach the ground is 2.94 s.
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A fishing boat uses an ultrasound of frequency 4.0×10²Hz to detect a fish blow it. two echo's of the ultrasound are received after 0.09s coming from the shoal of the fish and the other after 0.12s coming from the sea bed .if the sea bed is 64m below the ultrasound transmitter and the receiver, calculate; a. the speed of the ultrasound in water b. the wavelength of ultrasound in water. c. the depth of the fish below the boat.
a. the speed of the ultrasound in water is 1480 m/s
b. the wavelength of the ultrasound in water is 37 m
c. the depth of the fish below the boat is 89.76 m
How to calculate?a.
v = fλ
v = fλ = (4.0 x 10^2 Hz)(λ)
the speed of the ultrasound in water is given as :
v = v_water = 1480 m/s
substitute v_water into the equation above and solve for λ:
λ = v_water / f = (1480 m/s) / (4.0 x 10^2 Hz) = 37 m
Therefore, the speed of the ultrasound in water is 1480 m/s and the wavelength is 37 m.
c. The depth of the fish below the boat ia found using,
d = v_water * t / 2
The first echo came back after 0.09 s:
d = (1480 m/s) * (0.09 s) / 2 = 64.32 m
This is the depth of the sea bed, which is already known to be 64 m. So the fish must be deeper than the sea bed, and the second echo must have come from the fish. The second echo came back after 0.12 s:
d = (1480 m/s) * (0.12 s) / 2 = 89.76 m
So the depth of the fish below the boat is 89.76 m
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Frequency= Wavelength = 502 km Speed= 100 m/s
Answer:
Explanation:
Wavelength = 100m. Speed = V. 2.) Frequency = 20 Hz. Wavelength = 200 m. Speed = ... 2=1.7m. F=Y/2 f=2×10. 5.) Wavelength = 502 km. Speed= 100 m/s.
Suppose you ran 53 km in 67 min. With what speed did you run?
Answer:
47.46 kilometers an hour
Explanation:
hope this helped
0.8 km/h
speed = distance / time
Explain how an electrical current is produced.
Answer:electric current can be generated by moving a metal wire through a magnetic field .electric current can also be produced by batteries
Explanation:
electric current can be generated by moving a metal wire through a magnetic field.this method is applicable in electric generators.
Electric current can also be generated by connecting metal wires to batteries.
A small dog walks 12 meters east
and then 5 meters north. How many
meters is the dog from her starting
position?
[?] m
5 m
12 m
Answer:
13m
Explanation:
North and East are perpendicular so if you illustrate this it will be a right-angle triangle;
One side will be 12 and the another will be 5;
The hypotenuse will be the desired distance;
We can use pythagoras to calculate it:
5² + 12² = x²
25 + 144 = x²
169 = x²
x = 13
In this problem we will consider the collision of two cars initially moving at right angles. We assume that after the collision the cars stick together and travel off as a single unit. The collision is therefore completely inelastic. Two cars of masses m1 and m2 collide at an intersection. Before the collision, car 1 was traveling eastward at a speed of v1, and car 2 was traveling northward at a speed of v2. After the collision, the two cars stick together and travel off in the direction.
Required:
a. Write the momentum conservation equation for the east-west components.
b. Write the momentum conservation equation for the north-south components.
c. Find the tangent of the angle.
Answer:
a) vfₓ = m₁ / (m₁ + m₂) v₁, b) tan θ = m₂ / m₁ v₂ / v₁, c)
Explanation:
Momentum is a vector quantity, so the consideration must be fulfilled in all axes
a) conservation of the moment east-west direction
the system is formed by the two cases, so that the forces during the sackcloth have been internal and therefore the mummer remains
before the crash
p₀ = m₁ v₁
after the crash
\(p_{f}\)= (m1 + m2) vfₓ
p₀ = pf
m₁ v₁ = (m₁ + m₂) vfₓ
vfₓ = m₁ / (m₁ + m₂) v₁
b) conservation of the North-South axis moment
before the shock
p₀ = m₂ v₂
after the crash
p_{f} = ( m₁ +m₂) \(vf_{y}\)
p₀ = p_{f}
me 2 v₂ = (m₁ + m₂) vfy
\(vf_{y}\) = m₂ / (m₁ + m₂) v₂
c) the angle with which the car moves is
tan θ = Vfy / Vfₓ
tan θ = [m₂ / (m₁ + m₂) v] / [m₁ / (m₁ + m₂) v₁]
tan θ = m₂ / m₁ v₂ / v₁
The momentum conservation equation for the north-south components is \(m_1u_1 = v(m_1 + m_2)\)
The momentum conservation equation for the north-south components is \(m_2u_2 = v(m_1 + m_2)\)
The tangent of the angle is 1.
The given parameters;
angle between the initial velocity of the cars, θ = 90Apply the principle of conservation of linear momentum of inelastic collision as shown below;
\(m_1u_1 + m_2u_2 = v(m_1 + m_2)\)
The momentum conservation equation for the east-west components is written as follows;
\(m_1(u_1cos \ 0) + m_2(u_2 cos 90)= v(m_1 + m_2)\\\\m_1u_1 = v(m_1 + m_2)\)
The momentum conservation equation for the north-south components is written as follows;
\(m_1(u_1sin 0) + m_2(u_2sin90) = v(m_1 + m_2)\\\\m_2u_2 = v(m_1 + m_2)\)
The tangent of the angle is calculated as follows;
\(tan \ \theta = \frac{p_y}{p_x} = \frac{v(m_1 + m_2)}{v(m_1 + m_2)} \\\\tan \ \theta = 1\\\\\theta = tan^{-1} (1) \\\\\theta = 45\ ^0\)
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A uniform plane wave with parallel polarization is propagating in a lossless dielectric medium (l is € 1), and is incident obliquely onto a plane boundary with another lossless dielectric medium (u 2, E 2). (30%) (a) Derive the Snell's laws of reflection and refraction in terms of the refractive indices and angles. (b) Derive the general expressions for the reflection and the transmission coefficients of the EM field. Find such expressions in terms of the refractive indices if both media are nonmagnetic, i.e., M F M 240. (c) Derive the general expression for the Brewster angle. Find such an expression in terms of the refractive indices if both media are nonmagnetic. (d) Prove that, under the condition of no reflection, the sum of the Brewster angle and the angle of refraction is 90° if both media are nonmagnetic. (e) For total reflection to occur, find the condition for the medium property and the critical angle.
Transmission coefficients are used in physics and electrical engineering when considering wave propagation in discontinuous media. The snells law is n₁sinθ1 = n₂sinθ2
The transmission coefficient describes the amplitude intensity or total power of the transmitted wave relative to the incident wave. The transmission coefficient is defined as the ratio of the transmitted particle flux to the incident particle flux and depends on the incident energy.
The sum of the reflected and transmitted energy must equal the total incident energy, so the transmission coefficient is calculated simply by subtracting the reflection coefficient. The ratio of the reflected wave amplitude to the incident wave amplitude is called the reflection coefficient.
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Scientists are constantly exploring the universe, looking for new planets that support life similar to the life on
Earth. A new planet that supports life would have all of the following characteristics except -
A. a gaseous atmosphere.
B. an orbiting moon.
C. liquid water.
D. protection from radiation.
A new planet that supports life would have all the following characteristics except an orbiting moon. Hence, option B is correct.
What is a Planet?An enormous, spherical celestial object known as a planet is neither a star nor its remains. The nebular hypothesis, which states how an interstellar cloud falls out of a nebula to produce a young protostar encircled by a protoplanetary disk, is now the best explanation for planet formation.
By gradually accumulating material under the influence of gravity, or accretion, planets develop in this disk.
The rocky planets Mercury, Venus, Earth, and Mars, as well as the giant planets Jupiter, Saturn, Uranus, and Neptune, make up the Solar System's minimum number of eight planets. These planets all revolve around axes that are inclined relative to their respective polar axes.
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A proton and an electron have ...... and ....... charge
Which statement best describes covalent bonding?
A. two nonmetal atoms share electrons between them
B. many atoms give up electrons that can move among the atoms
C. two metal atoms share electrons between them
D. a metal atom transfers electrons to a nonmetal atom
How to solve conservation of momentum
Answer:
Step 1: List the mass and velocity of the object. Step 2: Convert any values into SI units (kg, m, s). Step 3: Multiply the mass and velocity of the object together to get the momentum of the object.
A hot air balloon is rising upward with a constant speed of 3.80m/s. When the balloon is 4.25m above the ground, the balloonist accidentally drops a compass over the side of the balloon. How much time elapses before the compass hits the ground
We can calculate the time taken by the compass to hit the ground by using kinematic equations of motion. The motion of the compass is a free-fall motion since it is only under the influence of gravity. When the compass is dropped, it is initially at rest.
After that, it falls down to the ground with the acceleration due to gravity. Given that the balloon is rising upward with a constant speed of 3.80m/s. Hence, the velocity of the compass when it is dropped will be equal to the velocity of the balloon, which is 3.80m/s. The acceleration due to gravity is 9.81m/s². We can use the following kinematic equation of motion to calculate the time taken by the compass to hit the ground: `y = vi * t + 0.5 * a * t²`, where `y` is the height, `vi` is the initial velocity, `a` is the acceleration, and `t` is the time taken.We know that the initial height of the compass is 4.25m, the initial velocity is 3.80m/s, and the acceleration due to gravity is 9.81m/s². We need to find the time taken by the compass to hit the ground. Using the above kinematic equation, we get:`0 = 3.80t + 0.5 * 9.81 * t²`Simplifying the equation, we get:`4.905t² + 3.80t = 0`Factorizing the equation, we get:`t(4.905t + 3.80) = 0`Solving for `t`, we get:`t = 0` (since time cannot be negative)`t = -3.80/4.905 = -0.776s`We ignore the negative value of time since time cannot be negative. Hence, the time taken by the compass to hit the ground is `t = 0.776s`.Answer: `0.776s`For such more question on acceleration
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A pipe drips at 155 mL/min.
Express this is units of gallons/day.
1. 2.34 gal/day
2. 15.7 gal/day
3. 942 gal/day
4. 58.9 gal/day
5. 223 gal/day
6. 377 gal/day
7. 0.223 gal/day
We have that the total pipe drip of \(X=155 mL/min.\) expressed in gallons/day is
\(X=58.96gal/day\)
From the Question we are told that
Pipe Drip\(=155 mL/min.\)
Generally
We have that for mL to gallons conversion
\(1mL=0.000264172\)
And
A minute to day con version is
\(1min=0.000694444\)
Therefore
\(X=155 mL/min.\)
\(X=155(\frac{0.000264172}{0.000694444})\)
\(X=58.96gal/day\)
In conclusion
The total pipe drip of \(X=155 mL/min.\) expressed in gallons/day is \(X=58.96gal/day\)
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Personal computers are a fixture in most business and in many homes.
true or false
true
Explanation:
computers have become a need in many businesses and homes we now living in a era of technology a computer is now a neccecity
The statement is True.
Personal computers have become an essential fixture in most businesses and households.
They have revolutionized the way we work, communicate, access information, and perform various tasks.
In the business world, personal computers are ubiquitous, serving as indispensable tools for productivity, data management, communication, and decision-making.
From small businesses to large corporations, computers have streamlined operations and enhanced efficiency.
Similarly, in homes, personal computers have become commonplace, enabling individuals and families to connect with the world, pursue online education, engage in entertainment, and manage various aspects of their lives.
With their versatility and functionality, personal computers have become an integral part of modern life, transforming the way we live and work.
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Which of the following statements about treatment for self-injury (SI) is not true?
Answer:
Its true
Explanation:
A body of mass 2.00 kg is pushed straight upward by a 25.0 N vertical force. What is its acceleration
The acceleration on a body of mass 2kg with a force of 25N is 12.5 m/s^2
Mass and AccelerationGiven Data
Mass = 2 kgForce = 25NWe know that the expression for the Relationship between force acceleration and Mass is given as
F = ma----------------1
Substituting our given data into the expression we have
25 = 2*a
Making acceleration the subject of the formula we have
a = 25/2
a = 12.5 m/s^2
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You are going 41 m/s on the highway you travel for 2 hours how far did it go
Given:
Speed = 41 m/s
Time taken, t = 2 hours
Let's find the distance.
To find the distance, apply the formula:
DIstance = speed x time
Convert the speed fro meter per second to meter per hour (m/h).
Where:
1 hour = 3600 seconds
We have:
Speed = 41 x 3600 = 147600 m/h
To find the distance, we have:
DIstance = 147600 x 2 = 295200 meters
Convert the distance from meters to kilometers.
Where:
1 km = 1000 meters
Thus, we have:
\(\frac{295200}{1000}=295.2\operatorname{km}\)Therefore, we can say you travelled 295.2 kilometers.
ANSWER:
295.2 km
Help! Looking for the answers to this question!
The figure below shows three edge views of a square loop with sides of length ℓ = 0.240 m in a magnetic field of magnitude 1.25 T. Calculate the magnetic flux (in Wb) through the loop oriented perpendicular to the magnetic field, 60.0° from the magnetic field, and parallel to the magnetic field.
(a) perpendicular to the magnetic field? _____Wb
(b) 60.0° from the magnetic field? ____Wb
(c) parallel to the magnetic field? _____Wb
Answer:
0.072, 0.062, 0
Explanation:
Flux = magnetic field B * area A * cos(angle between B and normal of A)
= 1.25 * 0.24^2 * cos(angle) = 0.072 * cos(angle)
a) angle = 0°, flux = 0.072 Wb
b) angle = 30°, flux = 0.072*cos(30) = 0.062 Wb.
c) angle = 90°, flux = 0
which statement is true of the temperature of the two substances when they reach thermal equilibrium? (assume no heat loss other than the thermal transfer between the substances.)
The final temperature of both substances is closer to the intital temperature of substance A than the initial temperature of substance B.
What is specific heat capacity?
In thermodynamics, the specific heat capacity of a substance is the heat capacity of a sample of the substance divided by the mass of the sample, also sometimes referred to as massic heat capacity.
Specific Heat Capacity, in physics, is the quantity of heat necessary to increase 1 Kelvin per 1 kilogram of substance, i.e., each substance has its own specific heat capacity.
Substances with different temperatures when in contact with each other reach the same final temperature.
A's specific heat capacity is twice as big as B's specific capacity. This means it is necessary twice as much heat for B to reach its final temperature. Therefore, the final temperature is closer to the initial temperature of substance A.
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a compound having 44 total atoms consists of 11 atoms of element x and 33 atoms of element y find the % element x in the compound
A. 11%
B. 33%
C. 25%
D. 44%
E. 22%
The % element x in the compound is option c.25%.
To find the percentage of element X in the compound, we need to calculate the ratio of the number of atoms of element X to the total number of atoms in the compound and then convert it to a percentage.
Given:
Total number of atoms = 44
Number of atoms of element X = 11
To calculate the percentage, we can use the following formula:
Percentage of element X = (Number of atoms of element X / Total number of atoms) * 100
Substituting the given values, we get:
Percentage of element X = (11 / 44) * 100
Simplifying the equation, we have:
Percentage of element X = 0.25 * 100
Percentage of element X = 25%
Therefore, the percentage of element X in the compound is 25%.
The correct answer is option C. 25%.
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Convert 105oF to Celsius.
apply the formula:
T°C = (T°F-32) x 5/9
T°C = (105 - 32) x 5/9
T°C = 73 x 5/9
T° = 40.56°C
The airport has a new plane that can go from 0 miles per hour to 100 miles per hour in 10 seconds. What is being described about the new plane?
a. acceleration
b. speed
c. velocity
d. magnitude
Answer:
acceleration
Explanation: how fast something can get to a certain speed
,a circular loop carrying a current of 40A produce a field of 3*10^8 T at the center what should be the current in the straight conductor so that it produce the same field at a distance equal to the radius if the loop ?
Hi there!
We can begin by deriving the magnetic field strength for a circular loop at its center.
Using Biot-Savart's Law:
\(dB = \frac{\mu_0}{4\pi }\frac{idl \times \^r}{r^2}\)
μ₀ = Permeability of free space (Tm/A)
dl = Differential length element
r = radius (m)
We can rather use 'ds' to represent a differential arc length since we are finding the magnetic field for a circular loop.
We must begin by dealing with the cross-product. Luckily, this derivation is simple since the radius vector is ALWAYS perpendicular to the path of integration along the loop's circumference. (ONLY if we are finding the field for the direct center.) Thus, since sin(90) = 1, we can get rid of the cross-product.
Therefore:
\(dB = \frac{\mu_0}{4\pi }\frac{ids}{r^2}\)
Now, we can integrate with respect to ds.
\(= \frac{\mu_0}{4\pi }\int\limits^{2\pi r}_0 {\frac{i}{r^2}} \, ds\\\\ = \frac{\mu_0}{4\pi }{\frac{i * 2\pi r}{r^2}} \, ds\)
Simplify:
\(B = \frac{\mu_0 i_{circle}}{2r}\\\)
Now, for a straight conductor (assuming of infinite length), we know the magnetic field strength equation to be:
\(B = \frac{\mu_0 i_{rod}}{2\pi r}\)
Set the two equal.
\(\frac{\mu_0 i_{circle}}{2r}= \frac{\mu_0 i_{rod}}{2\pi r}\)
Cancel out '2', μ₀, and 'r':
\(i_{circle}}= \frac{ i_{rod}}{\pi }\)
Plug in the given values and solve.
\(40\pi = i_{rod}\\\\i_{rod} = \boxed{125.663 A}\)
if the waves are exactly in phase at s1 and s2, a path difference can cause a phase difference between them at the screen.
if the waves are exactly in phase at s1 and s2, a path difference can cause a phase difference between them.
at the screen is zeroIn comparison to the waves coming from S 2, the waves from S 1 have arrived exactly one cycle sooner. As a result, we claim that there is a route difference of about between the two waves (wavelength). The path difference will be 0 if the waves from two disturbances travel the same distance.When waves from two different sources collide, two-point source interference develops. Circular wavefronts will collide within the medium to create a pattern if the wave source generates circular waves. The antinodal lines and nodal lines, which are a collection of nodes and antinodes that lie along roughly straight lines, are what define the pattern. If the frequency of the wave sources is the same
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In Milikan’s experiment, a drop of radius of 1.64 μm and density 0.851 g/cm3 is suspended in the lower chamber when a downward-pointing electric field of 1.92 * 105 N/C is applied.
What is the weight of the drop?
Find the charge on the drop, in terms of e.
How many excess or deficit electrons does it have?
(a) The weight of the drop is 1.54 x 10⁻²⁵ N,
(b) The the charge on the drop, in terms of e is 5 x 10⁻¹²e and
(c) The excess electrons is 5 x 10⁻¹² electron.
Weight of the dropThe weight of the drop is calculated as follows;
Volume of the drop; V = ⁴/₃πr³
V = ⁴/₃π(1.64 x 10⁻⁶)³ = 1.845 x 10⁻¹⁷ m³
mass = density x volume
mass = 0.851 g/cm³ x 1.845 x 10⁻²³ cm³ = 1.572 x 10⁻²³ g = 1.57 x 10⁻²⁶ kg.
Weight = 1.57 x 10⁻²⁶ kg x 9.8 m/s² = 1.54 x 10⁻²⁵ N.
Charge on the dropq = F/E
q = (1.54 x 10⁻²⁵ N)/(1.92 x 10⁵)
q = 8.01 x 10⁻³¹ C
1.6 x 10⁻¹⁹ C = 1e
8.01 x 10⁻³¹ C = ?
= 5 x 10⁻¹²e
Excess electron on the drop1.6 x 10⁻¹⁹ C ------- 1 electron
8.01 x 10⁻³¹ C ------- ?
= 5 x 10⁻¹² electron
Thus, the weight of the drop is 1.54 x 10⁻²⁵ N, the the charge on the drop, in terms of e is 5 x 10⁻¹²e and the excess electrons is 5 x 10⁻¹² electron.
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A 2000 kg car moves at a speed of 30 m/s. To reach this speed, it was necessary to burn 0.1 l of gas. Burning gas provides 30 MJ/l of source energy. Determine the energy efficiency (in %) of this car.
The energy efficiency of the car is approximately 16.7%.
The energy efficiency of a car is the ratio of the useful work output (in this case, the kinetic energy of the car) to the total energy input (in this case, the energy released by burning the gasoline). The equation for energy efficiency is:
Efficiency = Useful work output / Total energy inputThe useful work output can be calculated as the kinetic energy of the car using the equation:
KE = 0.5mv²where m is the mass of the car and v is its velocity.
Substituting the given values:
KE = 0.5 x 2000 kg x (30 m/s)² = 900,000 JThe total energy input is the energy released by burning 0.1 L of gasoline, which is:
Total energy input = 0.1 L x 30 MJ/L = 3 MJ = 3,000,000 JSubstituting these values into the equation for efficiency:
Efficiency = (900,000 J / 3,000,000 J) x 100% = 0.3 x 100% = 16.7%Therefore, the energy efficiency of the car is approximately 16.7%.
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You are an astronomer on planet Nearth, which orbits a distant star. It has recently been accepted that Nearth is spherical in shape, though no one knows its size. One day, while studying in the library of Alectown, you learn that on the equinox your sun is directly overhead in the city of Nyene, located 1200 kilometers due north of you. On the equinox, you go outside in Alectown and observe that the altitude of your sun is 79 ∘.
You know now that 1200 km is 11° of latitude on the planet. So its circumference is roughly approximately around something like about
(360/11) • (1200 km) = 39,273 km
If it was good enough for Eratosthenes, then we can't complain.
pLEASE HURRY !!! ILL GIVE BRAINLIEST!!!!!!!!!!!!!
An object moves from position x = -1.88 m to x = -4.27 m. What is it's displacement?
Answer: Displacement = -2.39 m
Explanation: The displacement of an object is the difference between its final position and its initial position. In this case, the object moved from x = -1.88 m to x = -4.27 m, so its displacement is:
Displacement = Final position - Initial position
Displacement = (-4.27 m) - (-1.88 m)
Displacement = -4.27 m + 1.88 m
Displacement = -2.39 m
Therefore, the displacement of the object is -2.39 m.
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