Instead of getting the baseline power draw from the old lighting manufacturing data sheets, the baseline power draw is measured using power meter. Which M&V option best describe this?

Answer:

0.981

Explanation:

velocity  of cars ( v1 , v2 )  = 55 mi/h

coefficient of adhesion ( u ) = 0.75

Reaction time of driver of car 1 = 2.3 -s

Reaction time of driver of car 2 = 1.9 -s

breaking efficiency of car 2 ( n2 ) = 0.80

Determine the braking efficiency of car 1

First determine the distance travelled during reaction time ( dr )

dr = v * tr ------- ( 1 )

tr ( reaction time )

v = velocity

note : 1 mile = 1609 m ,  I hour = 60 * 60 secs

back to equation 1

for car 1

dr1 =( 55 * 2.3 * 1609 ) / ( 60 * 60 )

    = 56.53 m

for car 2

dr2 = ( 55 * 1.9 * 1609 ) / ( 60 * 60 )

   = 46.70 m

next we calculate the stopping distances  ( d ) using the relation below

ds = d + dr

 d = distance travelled during break

 dr = distance travelled during reaction time

where : d = \(\frac{v^2intial}{2ugn}\)

for car 1

d1 = \(\frac{(55)^2}{2*0.75*9.81* n1} * (\frac{1609}{3600} )^2\)

∴ d1 = \(\frac{41.10}{n1}\)

for car 2

d2 = \(\frac{(55)^2}{2*0.75*9.8*0.8} * (\frac{1609}{3600} )^2\)

∴ d2 = 51.38

since the stopping distance for both cars are the same

d1 + dr1 = d2 + dr2

( 41.10 /n1 ) + 56.53 = 51.38 + 46.70

solve for n1

hence n1 = 0.981 ( braking efficiency of car 1 )

Answer:

..

Explanation:

like this

have you understood

The normal reactions at A and B when the dresser begins to move will be:
Normal Reaction at A = μs * mg = 0.3 * (80 lb) * 32.2 ft/s² = 96.6 lb
Normal Reaction at B = μk * mg = 0.2 * (80 lb) * 32.2 ft/s² = 64.4 lb

What is reaction?
Reaction is an action taken in response to a particular stimulus. It is the way in which people interact with the world around them. Reactions can be physical, mental, or emotional in nature. It is the way in which individuals respond to situations, people, and events. Reactions can range from positive to negative, and can even be neutral. Reactions are affected by a person's past experiences, beliefs, values, and emotional state. It is also influenced by external factors such as the environment, other people, and media. Reactions are an important part of social interaction and communication, as they provide feedback and help build relationships. They also provide insight into a person's personality, character, and values. Reactions are the building blocks of relationships, and it's important to be aware of how one's reactions affect others.

The smallest horizontal force P needed to cause motion is:
P = μs * mg = 0.3 * (80 lb) * 32.2 ft/s² = 96.6 lb

When the force is increased slightly, the acceleration of the dresser will be:
a = (P - μk * mg) / m = (96.6 - 0.2 * (80 lb) * 32.2 ft/s²) / (80 lb) = 7.7 ft/s²

The normal reactions at A and B when the dresser begins to move will be:
Normal Reaction at A = μs * mg = 0.3 * (80 lb) * 32.2 ft/s² = 96.6 lb
Normal Reaction at B = μk * mg = 0.2 * (80 lb) * 32.2 ft/s² = 64.4 lb

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Answer:

mass flow rate = 0.0534 kg/sec

velocity at exit = 29.34 m/sec

Explanation:

From the information given:

Inlet:

Temperature \(T_1 = -16^0\ C\)

Quality \(x_1 = 0.2\)

Outlet:

Temperature \(T_2 = -16^0 C\)

Quality  \(x_2 = 1\)

The following data were obtained at saturation properties of R134a at the temperature of -16° C

\(v_f= 0.7428 \times 10^{-3} \ m^3/kg \\ \\ v_g = 0.1247 \ m^3 /kg\)

\(v_1 = v_f + x_1 ( vg - ( v_f)) \\ \\ v_1 = 0.7428 \times 10^{-3} + 0.2 (0.1247 -(0.7428 \times 10^{-3})) \\ \\ v_1 = 0.0255 \ m^3/kg \\ \\ \\ v_2 = v_g = 0.1247 \ m^3/kg\)

\(m = \rho_1A_1v_1 = \rho_2A_2v_2 \\ \\ m = \dfrac{1}{0.0255} \times \dfrac{\pi}{4}\times (1.7 \times 10^{-2})^2\times 6 \\ \\ \mathbf{m = 0.0534 \ kg/sec}\)

\(\rho_1A_1v_1 = \rho_2A_2v_2 \\ \\ A_1 =A_2 \\ \\ \rho_1v_1 = \rho_2v_2 \\ \\ \implies \dfrac{1}{0.0255} \times6 = \dfrac{1}{0.1247}\times (v_2)\\ \\ \\\mathbf{\\ v_2 = 29.34 \ m/sec}\)

Technician A and Technician B are both correct. Leaf springs are the main suspension component on many vehicles and are composed of multiple components, including the spring eye bushings, the interleaf separators, and the spring itself.

The spring eye bushings are located between the spring and the axle, and when they wear, they can cause squeaking or rattling noises, reduced ride quality, and other handling issues. Interleaf separators, meanwhile, separate the leaves of the spring and also provide insulation from road noise and vibration. When they become worn or move, they can cause the spring to become loose and ride quality to suffer. For this reason, both the spring eye bushings and interleaf separators should be inspected and replaced when needed.  

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"Use a theory that accounts for material yielding" to avoid false answers that use the method of finite elements based on linear elastic material model assumptions.

Thus, "Use a theory that accounts for material yielding" to avoid false answers that use the method of finite elements based on linear elastic material model assumptions.

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Answer:

8×10^-19 seconds

Explanation:

i=∆q/∆t

=> ∆t=∆q/i=50×1.6×10^-19/10=8×10^-19(s)

Answer:

SpaceX

Explanation:

SpaceX successfully launches 60 more Starlink satellites as it continues towards 2020 service debut. SpaceX has launched another big batch of Starlink satellites, the low Earth orbit spacecraft that will provide connectivity for its globe-spanning high-bandwidth broadband internet network.

Value engineering is a systematic approach that aims to improve the value of a product, project, or process by analyzing its functions and identifying opportunities for cost reduction while maintaining or improving its performance and quality. It involves a collaborative effort of cross-functional teams, including engineers, designers, managers, and other stakeholders.

The role of value engineering in target costing is to help achieve the desired cost target for a product or project. Target costing is a cost management approach that sets the desired cost based on market conditions and customer requirements. Value engineering supports target costing by finding ways to optimize the value delivered to customers while controlling costs.

Here's how value engineering contributes to target costing:

Function analysis: Value engineering starts with a thorough analysis of the product's functions and their importance to customers. By understanding the value provided by each function, teams can prioritize them based on customer needs and focus efforts on cost reduction for non-critical functions.

Cost analysis: Value engineering involves a detailed analysis of the costs associated with various components, materials, and processes involved in the product or project. It helps identify areas where costs can be reduced without compromising the essential functions or quality.

Creativity and innovation: Value engineering encourages creativity and innovative thinking to find alternative designs, materials, or processes that can deliver the required functions at a lower cost. It involves brainstorming sessions and idea generation to explore different possibilities.

Trade-off analysis: Value engineering facilitates trade-off analysis between cost, performance, and quality. It helps identify trade-offs that can be made to reduce costs while still meeting customer expectations. By understanding the impact of different design or process changes on cost and performance, informed decisions can be made.

Collaboration and continuous improvement: Value engineering promotes collaboration among cross-functional teams to identify cost-saving opportunities. It encourages open communication and the sharing of ideas to drive continuous improvement in cost management. It also fosters a culture of innovation and cost-consciousness throughout the organization.

Overall, value engineering plays a vital role in target costing by helping teams identify cost reduction opportunities, optimize the value delivered to customers, and achieve the desired cost targets without compromising quality or customer satisfaction. It ensures that the product or project remains competitive in the market while meeting cost objectives.

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The examples of engineering controls is Biohazard waste containers and Spill clean up kits.

An engineering controls is a workplace process that protect workers by removing hazardous conditions or by placing a barrier between the worker and the hazard.

An example of engineering controls is installation of exhaust ventilation to remove airborne emissions to shield the worker.

Hence, the examples of engineering controls is Biohazard waste containers and Spill clean up kits.

Therefore, the Option C and D is correct.

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Answer:

How does electricity produce magnetism?

Explanation:

When the electricity is switched on, the electric magnets create powerful magnetic fields. Coils of wire are mounted around the shaft. As the shaft with the magnets rotates, the coils of wire are exposed to changing magnetic fields, and an electric current is generated in the wires.

Answer:

Explanation:

I am pretty sure it depends but most of the time I think they produce direct current/voltage.

Answer: a filter whose current output depends on past and present inputs.

Explanation:

A nonrecursive filter may best be described as a filter whose current output depends on past and present inputs.

It should be noted that in this case, the output is typically stable. For the non recursive filter, the current output which is denoted as (yn) will have to be calculated from the input values which are for both previous and current values.

The closest equivalent present worth of John's deposits is less than $8,000.

To determine the closest equivalent present worth of John's deposits, we need to calculate the present value of the cash flows he will make.

The deposit of $1000 at the end of the next year can be considered a future value (FV). We need to calculate its present value (PV) using the formula:

PV = FV / (1 + r)^n

Where:

FV = $1000

r = interest rate = 10% = 0.10

n = number of years = 1

PV = $1000 / (1 + 0.10)^1 = $909.09

Next, we calculate the present value of the increasing deposits of $100 per year for 10 years. These cash flows form an arithmetic progression with a common difference of $100.

Using the formula for the sum of an arithmetic progression, we can find the present value of these cash flows:

PV = (n/2) * (2a + (n-1)d)

Where:

n = number of terms = 10

a = first term = $100

d = common difference = $100

PV = (10/2) * (2*100 + (10-1)*100) = 5 * (200 + 9 * 100) = $5,500

Now, we can sum up the present values of both cash flows:

PV = $909.09 + $5,500 = $6,409.09

The closest equivalent present worth is between $8,000 - $8,300. Since the calculated present value is lower than $8,000, the closest equivalent present worth is less than $8,000.

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Answer:

Computer programming is where you learn and see how computers work. People do this for a living as a job, if you get really good at it you will soon be able to program/ create a computer.

Explanation:

Hope dis helps! :)

The initial pressure in the tank can be estimated as approximately 1.356 times the pressure at 150°C.

The initial pressure in the tank can be estimated using the ideal gas law and the given temperature change.

To estimate the initial pressure in the tank, we can use the ideal gas law equation:

PV = nRT

Where:

Given that the tank initially contains water vapor at 300°C (573 K) and is cooled to 150°C (423 K) when the vapor starts condensing, we can assume that the volume and number of moles remain constant.

Using the ideal gas law, we can set up the following equation:

P1V = P2V

Since V is constant, we can simplify the equation to:

P1 = P2(T1 / T2)

Substituting the given temperatures, we have:

P1 = P2(573 K / 423 K)

By evaluating the ratio of temperatures, we find:

P1 ≈ P2(1.356)

Therefore, the initial pressure in the tank can be estimated as approximately 1.356 times the pressure at 150°C.

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String variables are an essential data type in programming languages and find application in various scenarios.

In programming languages, a string variable can indeed hold digits such as account numbers and zip codes. Strings are used to store sequences of characters, including letters, digits, and special characters.

A string can be declared in programming languages by enclosing the characters within single quotes ('...') or double quotes ("..."). For example, in Python, a string can be declared as follows:

```

s = 'Hello World'

```

In this case, the string variable `s` holds the sequence of characters 'Hello World'. Similarly, a string variable can also hold a sequence of digits:

```

s1 = "12345"

```

In this example, the variable `s1` holds the sequence of characters '12345', which consists of digits. It's important to note that even though `s1` contains only digits, it is still considered a string because it is enclosed within quotes.

String variables are commonly used to store text data such as names, addresses, and other information. They are also useful for storing numeric data like account numbers and zip codes, which may contain leading zeros or special characters that cannot be stored in numeric variables.

To summarize, string variables are an essential data type in programming languages and find application in various scenarios.

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The correct answer is b. 26 ch 5 lk and 49 ch 17 lk. Gunter's Chain is precisely 66 feet long; the only change is 0.382 feet for convenience. Two decametres, or 20 metres, make up the 20-metre chain.

Edmund Gunter, a clergyman, invented a low-tech method for precisely measuring property around 1620. He used a chain that became known as Gunter's chain; it was 66 feet long, and the term "chain" eventually came to refer to the actual measurement unit. Edmund Gunter, a polymath, invented a system for precisely measuring land in 1620. He used a surveyor's chain that was 66 feet long and had 100 links. The chain was the term given to the 66 feet unit, which consisted of four perches or rods.Gunter's chain, which was created by English mathematician Edmund Gunter in the early 17th century, is exactly 22 yards (about 20 m) long and has 100 links. Each connection in the gadget is a solid bar.

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RIDs (Relative Identifier) are used in Windows operating systems to uniquely identify objects in a network. They are generated by the Security Account Manager (SAM) and converted into security principals during authentication.

Relative Identifiers (RIDs) are a crucial part of the security model in Windows operating systems. They are used to uniquely identify objects in a network, including users, groups, and computer accounts.

When a new object is created, the Security Account Manager (SAM) generates a RID for that object, which is added to the object's security identifier (SID). The SID is a unique identifier for each object in the network, and the RID helps to ensure that the SID is truly unique across the entire network.

During authentication, the SID is used to determine whether the user has permission to access a resource. The RID is converted into a security principal, which is then used to check the access control list (ACL) for the resource. If the user has permission, the authentication is successful and access is granted.

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Answer:

it's answer B. I took the test

Answer:

nothing will happen

Explanation:

except for whatever that wire feeds will lose power

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An industry discharges 17,520 pounds of BOD5 if it releases a waste of 10 mgd with a BOD5 of 2000 mg/L.

BOD5, or Biological Oxygen Demand, is a measure of the amount of dissolved oxygen required by aerobic microorganisms to decompose organic matter in water over a 5-day period. BOD5 measurements aid in the assessment of water quality and the estimation of the amount of biodegradable organic matter discharged into receiving waters.

The BOD5 of wastewater is usually determined in the laboratory by taking a sample and measuring the quantity of oxygen consumed by aerobic microorganisms over a 5-day period. BOD5 is calculated as the number of milligrams of oxygen consumed per litre of wastewater during this period.

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Answer:

hello the diagram related to your question is missing attached below is the required diagram.

The value of AC = 6m

answer 2.25 N

Explanation:

From the diagram attached below

average intensity of loading = w/2

Total load due to linearly varying load = \(\frac{wL}{2}\)

w = maximum intensity of load , L = span of varying load

since AC = 6m( L )  then

Total load due to linearly varying load  = 3w  ------ ( 1 )

attached below is the detailed solution of the given problem

The model of a certain mass-spring-damper system is given as follows:10x¨+cẋ+20x=f(t)where f(t) is the input force applied to the mass m and x(t) is the displacement of the mass from its equilibrium position at time t.

The resonant frequency of the mass-spring-damper system can be found using the following formula:ωr=ωn√(1-2ζ^2)where,ωn=√(k/m) = natural frequency of the systemζ = damping ratio of the system, and c = 2ζωn m, where m = mass of the system.r = ωn√(1-2ζ^2)Given that ζ=0.1, we can find the resonant frequency as follows:r = ωn√(1-2ζ^2)Let's find the natural frequency of the system first.k = 20, m = 10, andωn=√(k/m)=√(20/10)=√2Thus,ωn=√2c = 2ζωn m = 2(0.1)(√2)(10) = 4√2Thus,c=4√2Substituting the values of ωn and ζ, we get:r = ωn√(1-2ζ^2)r = (√2)√(1-2(0.1)^2)r = 1.38 rad/sThus, the resonant frequency of the mass-spring-damper system is 1.38 rad/s.The peak magnitude M of the mass-spring-damper system can be found using the following formula:M = f0/2ζωnwhere f0 is the amplitude of the input force applied to the mass m.When the system is subjected to an input force of f0 = 1, we can find the peak magnitude of the system as follows:M = f0/2ζωn=1/2(0.1)(√2)(10)=1.78Thus, the peak magnitude of the mass-spring-damper system is 1.78.

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The ultimate BOD (Lo) is given as 570.41 mg/L

we know that BOD(t)=Lo (1-(e^-kt)) where t=time, Lo= ultimate BOD, k= temperature constant(time^-1).

Given BOD(5)=370mg/L

BOD(10)=500 mg/L

assume temperature was same during total procedure so kwill be constant.

so we can write

370=Lo(1-(e^-k * 5)) -----> (1)

and 500=Lo(1-(e- k* 10)) ------>(2)

by dividing equation (1) by equation (2)

\(\frac{1-e^{-5k}}{1-e^{-10k}}= 370/500\) by solving

\(37 e^{-10k}-50e^{-5k}+13=0\)

assume e^{-5k}=t

so equation will become

\(37 t^2 - 50 t +13 =0\)

by solving we get t=1 or .3514

if t=1 then k=0 k can not be zero so

t=.3514 then k=.2092 day ^ -1

so the calculation of ultimate BOD (Lo)

370=Lo(1-e(-5 * .2092))

Lo=370/.6487=570.41 mg/L

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Answer:

Levi Ackerman  is the tritagonist of the anime/manga series Attack on Titan. He is a Captain in the Survey Corps , known to be the strongest soldier alive. He has a harsh and unsocial personality, but is well-regarded by his subordinates and he cares about their lives. Levi Ackerman spent his childhood in the Underground City. It was the slums of the Attack on Titan’s entire world

Explanation:

As this occurs, an armature opens the contacts, allowing the diaphragm to spring back to its original position.

This is  referred to as a simple electromagnetic devices that produce loud, audible sounds to alert people etc.

The movement of the armature flexes the diaphragm which results in the opening of the electrical contacts which is how the horn works.

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Answer:

The main sections included in the bill of quantities are Form of Tender, Information, Requirements, Pricing schedule, Provisional sums, and Day works.

Answer:

  239 mL

Explanation:

The average of any set of data is the sum of the values, divided by their number.

  v = (240 +242 +235)/3 = 717/3 = 239 . . . mL

The average of the three measurements is 239 mL.

Answer: Calendars are important so that; Students know what’s coming up. Adequate time is planned for important events and studying different levels of detail are accounted for students may be organized and prepared for anything.

Explanation:

The reason why it is important for Raul to use the different types of calendars is; So that he can know what is coming up

Calendars are documents that contain dates of all days in a year as classified by that specific calendar.

The most common calendar system types in the world today are Gregorian, Islamic and Chinese. Now, regardless of the type of calendar being used, the one common factor with all of them is that they assist everyone including students to know the events that are coming up.

In conclusion the reason why it is important for Raul to use the different types of calendars is So that he can know what is coming up

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