Increasing the force on an object _________ its acceleration, if the mass of the object stays the same

Answers

Answer 1
Increases fill in the blank

Related Questions

A sample of nitrogen gas occupies a volume of 255 mL at 0.974 atm pressure. what volume will it occupy at 1.05 atm pressure?

Answers

The sample of nitrogen gas will occupy 236.54 mL of volume at 1.05 atm pressure.

Give a brief account on Boyle's Law.

Boyle's law is the ideal law that defines the relationship between pressure and volume of gases. A law is given if the temperature is kept constant. Pressure and volume exhibit an inverse relationship.

The Boyle's Law is given as:

P₁V₁ = P₂V₂

Given,

Initial pressure (P₁) = 0.974 atm

Initial volume (V₁) = 255 mL

Final pressure (P₂) = 1.05 atm

Final volume = V₂

The final volume at 1.05 atm is calculated by substituting values in Boyle's Law as:

P₁V₁ = P₂V₂

0.974 × 255 = 1.05 V₂

V₂ =  248.37 ÷ 1.05

= 236.54 mL

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What is the oxidation number for Chlorine

Answers

Answer:Chlorine:

It is an element that belongs to the p-block and non-metal.

It shows a variable oxidation state.

The oxidation number of chlorine can be - 1, 0, + 1, + 3, + 4, + 5, or + 7 which depends on the substance containing the chlorine.

Explanation:

Cl has a -1 oxidation number, except when bonded to a F or an O.

1. Explain how you would determine the enthalpy of reaction for the hypothetical reaction A2X4(l) + X2(g) → 2AX3(g) using the following information. You do not need to calculate an answer. Respond to the prompt with a minimum response length of 50 words.

1. Explain how you would determine the enthalpy of reaction for the hypothetical reaction A2X4(l) + X2(g)

Answers

we can determine the enthalpy of reaction for the hypothetical reaction A2X4(l) + X2(g) → 2AX3(g) using the following steps:

write the balanced chemical equation for the reactionwe obtain the standard enthalpies of formation for each compoundwe apply Hess's law  calculate the enthalpy of reactionwe then add up the changes to get  the total  enthalpy change for the reaction

State Hess law?

Hess's Law of Constant Heat Summation  states that regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes.

The law is  Hess's Law  of Constant Heat Summation  is described as a manifestation that enthalpy is a state function.

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What element is primarily used in appliances to make electronic chips
A. Silicon (Si)
B. Nickel (Ni)
C. Copper (Cu)
D. Selenium (Se)​

Answers

Answer:

Option A

Explanation:

Silicon (Obtained from Sand (SiO2)) is the element that is primarily used in appliances to make electronic chips.

Answer:

A. Silicon (Si)

Explanation:

Silicon (Si) is primarily used as a semiconductor material to make electronic chips.

1. If the wavelength is changed, what will happen to the absorbance values?

Answers

Answer:

The longer the path length, the more molecules there are in the path of the beam of radiation, therefore the absorbance goes up. As you likely know from other experiences, a particular chemical species absorbs some wavelengths of radiation and not others

The wavelength is used to determine the concentration of a colored solution since at this wavelength a slight change in concentration allows for a significant change in the absorbance of light.

What is Wavelength?

Wavelength is the distance between equal points in adjacent cycles of a wave signal that propagates in space. Each wave has a definite shape and length, so  the distance between the peaks is called the wavelength.

It can be calculated by this formula-

\(\lambda=\frac{v}{f}\)

\(where, \lambda =wavelength\\{v} = velocity\\{f} = frequency\)

Absorbance measures the amount of light with a specific wavelength which a given substance prevents from passing through ii.

Thus, the wavelength is used to determine the concentration of a colored solution since at this wavelength a slight change in concentration allows for a significant change in the absorbance of light.

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How many molecules are there in 985 mL of nitrogen at 0.0 degrees C and 1.00x10^-6 mm Hg?
(It would be better if work or steps to solve problem are given but if not its fine).

Answers

Answer:

3.48 x 1013 N2 molecules

step-by-step explanation:

Lets set up our equation first

P = 1.00 x 10-6 mm Hg T = 0.0° C + 273 = 273 K

We are given the V = 985 mL ,

R = 0.0821 L·atm/mol·K

Now use the ldeal gas law, but we are solving n, amount of substanvce

PV = nRT, we will change this equation to ;

n = PV/RT

n = 1.00 x 10-6 mm x 1 atm/760 mm x 985 mL x 1 L/103

mL/

(0.0821 L·atm/mol·K x 273 K) = 5.78 x 10-11 moles N2

nmolecules = 5.78 x 10-11 moles N2 x 6.02 x 1023 N2 molecules/1 mol N2

What was the eutectic temperature (temperature from the two lines of best fit cross) for the mixture

Answers

Answer:

hello your question is incomplete below is the missing part of the question

answer : 104°c

Explanation:

The Eutectic temperature  for the mixture is 104°c

From the chart attached below it can be seen that the temperature from the two lines of best fit cross is 104°c

What was the eutectic temperature (temperature from the two lines of best fit cross) for the mixture
What was the eutectic temperature (temperature from the two lines of best fit cross) for the mixture

b. How many kJ of heat are needed to completely vaporize 50.0g of water at 100°C? [Ans:113. kJ]​

Answers

The amount, in kJ, of heat needed to completely vaporize 50.0g of water at 100°C is 118.8 kJ.

Heat of vaporization of water

The heat needed to completely vaporize 50.0g of water at 100°C can be calculated using the following formula:

q = m x Hv

where:

q is the heat needed in joules (J)m is the mass of water in grams (g)Hv is the heat of vaporization of water which is approximately 40.65 kJ/mol at standard temperature and pressure.

First, we need to convert 50.0g to moles by dividing by the molar mass of water which is approximately 18.015 g/mol3:

moles of water = 50.0 g / 18.015 g/mol moles of water = 2.776 mol

Thus:

q = (2.776 mol) x (40.65 kJ/mol) q = 112.8 kJ

In other words, 112.8 kJ of heat is needed to completely vaporize 50.0g of water at 100°C.

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Question 41 ptsA solution containing 10.0 mL of the weak acid HF has a pH of 2.62. The weak acid istitrated with 0.124 M NaOH in the presence of a pH indicator. The indicator changescolors (approximating the equivalence point) when 15.62 mL of NaOH are added.How many millimoles (mmol) of HF are present?Question 51 pts

Answers

There are 1.937 millimoles of HF are present.

Some medical tests report results in millimoles per liter. A mole is the amount of a substance that contains a large number of molecules or atoms. A millimole is one-thousandth of a mole. A liter measures the volume of a liquid. It is a weak acid and not a strong acid. This is because it does not completely dissociate in water or at least because the ions formed during dissociation bind so tightly that they cannot act as strong acids.

Hydrogen fluoride is a compound containing fluorine. It may exist as a colorless gas-fuming liquid or dissolved in water. When dissolved in water hydrogen fluoride is sometimes called hydrofluoric acid. Hydrofluoric acid is a weak acid mainly because it forms stable species after dissociation. Hydrofluoric acid is a very strong and corrosive acid. However, it is classified as a weak acid rather than a strong acid.

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The electrical charge of the nucleus of an atom is +12. How many electrons does the atom have in its neutral state?

Answers

The electrical charge of the nucleus of an atom is +12 then 12 electrons does the atom have in its neutral state

Basic property of matter carried by some elementary particles that governs how the particles are affected by an electric or magnetic field and when a neutral atom gains or loses electrons, it becomes an ion and heavier atoms tend to have more neutrons than protons, but the number of electrons in an atom is always equal to the number of protons and so an atom as a whole is electrically neutral

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In the image above you see an 8mL graduated cylinder or
the left and an excerpt of a burette on the right. Each
holds a fixed volume of liquid. What are the volume
readings in each of these pieces of glassware? Give your
readings to 2 decimal places.
The volume in the graduated cylinder is
mL
The volume in the burette is
mL.

Answers

Answer: graduated cylinder: 4.25

Explanation:

A mixture of nitrogen and xenon gases contains nitrogen at a partial pressure of 417 mm Hg and xenon at a partial pressure of 427 mm Hg. What is the mole fraction of each gas in the mixture

Answers

Answer:

0.4941, 0.5059

Explanation:

\(P_N\) = Partial pressure of nitrogen = 417 mm Hg

\(P_{Xe}\) = Partial pressure of xenon = 427 mm Hg

Total pressure in the system is given by

\(P=P_N+P_{Xe}\\\Rightarrow P=417+427=844\ \text{mm Hg}\)

Mole fraction is given by

\(X_N=\dfrac{P_N}{P}\\\Rightarrow X_N=\dfrac{417}{844}\\\Rightarrow X_{N}=0.4941\)

For xenon

\(X_{Xe}=1-0.4941=0.5059\)

or

\(X_{Xe}=\dfrac{P_{Xe}}{P}\\\Rightarrow X_{Xe}=\dfrac{427}{844}\\\Rightarrow X_{Xe}=0.5059\)

So, mole fraction of nitrogen is 0.4941 and xenon is 0.5059.

The [H3O+] of a solution with pH = 8.7 is

Answers

The [H3O+] of a solution with pH = 8.7 is approximately 1.995 x 10^-9 M.

What is ph solution ?

The pH of a solution is a measure of its acidity or basicity. It is defined as the negative logarithm (base 10) of the concentration of hydronium ions, [H3O+], in the solution. Mathematically, pH is expressed as:

pH = -log[H3O+]

where [H3O+] is the concentration of hydronium ions in moles per liter (M) of the solution. pH values range from 0 to 14, where a pH of 7 is considered neutral. A pH value less than 7 indicates acidity, while a pH value greater than 7 indicates basicity or alkalinity. The pH scale is logarithmic, meaning that a change of one unit in pH represents a ten-fold change in the concentration of hydronium ions. For example, a solution with a pH of 3 has ten times more hydronium ions than a solution with a pH of 4.

The pH of a solution is defined as the negative logarithm (base 10) of the concentration of hydronium ions, [H3O+], in the solution. The mathematical expression for this relationship is:

pH = -log[H3O+]

We can rearrange this equation to solve for [H3O+]:

[H3O+] = 10^(-pH)

Substituting the given pH value of 8.7 into this equation, we get:

[H3O+] = 10^(-8.7)

Using a calculator or logarithmic tables, we find that:

[H3O+] = 1.995 x 10^(-9) M

Therefore, The [H3O+] of a solution with pH = 8.7 is approximately 1.995 x 10^-9 M.

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Name the structure CH3coch2c(br)2ch2ch3

Answers

The name of the compound from the structure that we can see in the question is;

4,4-dibromohex-2one

Summary of how  you name an organic compound

The International Union of Pure and Applied Chemistry (IUPAC) established a systematic set of guidelines for naming organic compounds.

Find the compound's longest continuous chain of carbon atoms. The compound's name is derived from this chain, which also acts as the compound's parent chain.

Assign a number to each carbon atom in the parent chain to give each carbon atom in the compound a special identification. The end that is closest to the functional group or substitutes is where the numbering begins.

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An ion from a given element has 20 protons and 18 electrons.
What is the charge on the ion? |
I
What is the name of the element?
What is the symbol for the ion?

Answers

Explanation:

charges is +2

elements is CALCIUM

Symbol is Ca++


Which statement is not true about constitutional isomers?

Answers

Answer: They always have the same functional groups.

Explanation:

use quizlet too if you have toooo

Answer:

they have same physical properties is not true

please help me with these ​

please help me with these

Answers

1) Diesel has a higher viscosity than petrol.

2) Petrol is more flammable than diesel.

3) The formula will be C₁₀H₂₂.

4) The equation is; 2C8H18+25O2→16CO2+18H2O.

What is the hydrocarbon?

Depending on the precise composition and temperature, the viscosity of gasoline and diesel can change. In general, diesel is more viscous than gasoline. Higher viscosity fluids are thicker and flow more slowly than lower viscosity fluids because viscosity relates to the resistance of a fluid to flow.

Diesel is less flammable than gasoline. The lowest temperature at which gasoline can evaporate and turn into an ignitable combination in air is known as its flash point, and it is lower for gasoline. Compared to diesel fuel, petrol vapors are much more flammable and can ignite at lower temperatures.

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is energy from the light source conduction convention or radiation​

Answers

Energy from a light source is known as radiation.

Find the mass of 2 moles of carbon tetrachloride

Answers

Answer:

The mass of 2 moles of carbon tetrachloride is

307.646 grams

Explanation:

The chemical formula for Carbon tetrachloride is \(\ce{CCl_4}\).  It contains 1 carbon atom and 4 chlorine atoms.

Carbon tetrachloride is formed due to the covalent bond between one carbon atom with four chlorine atoms.

In order to find the mass of 2 moles of \(\ce{CCl_4}\) we need to determine the molar mass.

The molar mass of carbon is 12.011 g/mol.

The molar mass of chlorine is 35.453 g/mol.

As stated before we have 1 carbon atom and 4 chlorine atoms. So the molar mass can be evaluated by

\(\left(1*12.011\right)+\left(35.453*4\right)=153.823\)

The molar mass of \(\ce{CCl_4}\) is 153.823 g/mol.

You can multiply that by 2 to get the mass in grams of 2 moles of carbon tetrachloride.

\(2*153.823 =307.646\)

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Which one of the following salts is least soluble in water?

1. Na2SO4
2.CaBr2
3. LiCl
4. RbI
5. PbSO4

Answers

the answer is PbSO4 !!

10 kg of Phenanthrene is to be burnt with supplied air which is 30% less than the requirement. Find the exit gas stream average molecular weight and the leftover Phenanthrene amount in the reactor.

Answers

The exit gas stream has an average molecular weight of 29.0 g/mol and the amount of leftover Phenanthrene in the reactor is 5377 g.

How to calculate exit gas and leftover?

Start by calculating the stoichiometric amount of air required to burn 10 kg of Phenanthrene. The balanced chemical equation for the combustion of Phenanthrene is:

C₁₄H₁₀ + 19O₂ → 14CO2 + 5H₂O

Therefore, to burn 10 kg (10000 g) of Phenanthrene:

nO₂ = 19 x (10000 g / 178.24 g/mol) = 1065.5 mol

So the actual amount of oxygen supplied will be:

nO₂, supplied = 0.7 x nO₂ = 745.9 mol

The amount of air required to supply this much oxygen can be calculated using the ideal gas law:

PV = nRT

where P = pressure, V = volume, n = number of moles, R = gas constant, and T = temperature.

Assuming standard temperature and pressure (STP):

P = 1 atm = 101.3 kPa

T = 273 K

R = 8.314 J/mol.K

The volume of air required is then:

Vair = nair × RT/P = (nO₂,supplied + nN₂,supplied) × RT/P

where nN₂,supplied = number of moles of nitrogen in the supplied air.

Since air is about 79% nitrogen by volume, assume that the number of moles of nitrogen is proportional to the number of moles of oxygen:

nN₂,supplied = (0.79/0.21) x nO₂,supplied = 2807.2 mol

Therefore,

Vair = (nO₂,supplied + nN₂,supplied) × RT/P

= (745.9 + 2807.2) × 8.314 × 273 / 101.3

= 63106 L

Calculate the average molecular weight of the exit gas stream using the ideal gas law again:

n = PV/RT

where n = number of moles of gas, P = pressure, V = volume, R = gas constant, and T = temperature.

Assuming that the combustion products are at the same temperature and pressure as the supplied air (STP):

nCO₂ = nH₂O = nO₂,supplied = 745.9 mol

nN₂ = nN₂,supplied = 2807.2 mol

The total number of moles of gas in the exit stream is then:

ntotal = nCO₂ + nH₂O + nN₂ = 745.9 + 745.9 + 2807.2 = 4298.0 mol

The volume of the exit stream can be calculated using the ideal gas law:

Vexit = ntotal × RT/P = 4298.0 × 8.314 × 273 / 101.3 = 36534 L

The average molecular weight of the exit gas stream is then:

M = mtotal/ntotal

where mtotal = total mass of gas in the exit stream.

Calculate mtotal by adding up the mass of each component in the exit stream:

mtotal = mCO₂ + mH₂O + mN₂

where mCO₂, mH₂O, and mN₂ = masses of carbon dioxide, water vapor, and nitrogen, respectively.

Calculate these masses using the molecular weights of the compounds and the number of moles:

mCO₂ = nCO₂ × MCO₂ = 745.9 × 44.01 g/mol = 32804 g

mH₂O = nH₂O × MH₂O = 745.9 × 18.02 g/mol = 13419 g

mN₂ = nN₂ × MN₂ = 2807.2 × 28.01 g/mol = 78617 g

Therefore,

mtotal = mCO₂ + mH₂O + mN₂ = 32804 + 13419 + 78617 = 124840 g

Substituting into the equation:

M = mtotal/ntotal = 124840 g/4298.0 mol = 29.0 g/mol

So the exit gas stream has an average molecular weight of 29.0 g/mol.

The leftover Phenanthrene amount can be calculated as follows:

mPhenanthrene,leftover = mPhenanthrene,initial - mCO₂ - mH₂O

where mPhenanthrene,initial = initial mass of Phenanthrene, which is 10 kg (10000 g).

Substitute these values into the equation:

mPhenanthrene,leftover = 10000 - 32804 - 13419 = 5377 g

Therefore, the amount of leftover Phenanthrene in the reactor is 5377 g.

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A student investigates the motion of a toy vehicle. The student graphs 40 seconds of data from the investigation.



Motion of a Toy Vehicle. Distance, meters. Time, seconds.



Which statement best describes the motion of the toy vehicle during the first 30 seconds of the investigation?

The vehicle was traveling at a constant speed.

The vehicle was accelerating at a constant rate.

The speed of the vehicle was increasing.

The acceleration of the vehicle was increasing.

Answers

Although we do not have the graph needed to answer this question, we can confirm that if the toy were to be accelerating, one should see this on the graph as a curved line.

How can we know if the toy was accelerating?

When graphing motion in terms of distance over time, we can use the shape of the line in the graph to determine if the speed is constant or if there is an acceleration present. If the line is straight, the speed is constant, but if there is a curve, there will be acceleration.

Therefore, we can confirm that if the toy were to be accelerating, one should see this on the graph as a curved line.

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Can you fit one mole of people into a classroom? why or why not?
(stoichiometry)

Answers

No, it is not possible to fit one mole of people into a classroom.

What is one mole of a substance?

One mole of anything is defined as the amount of that substance that contains the same number of particles as there are atoms in exactly 12 grams of carbon-12. This number is known as Avogadro's number and is equal to approximately 6.022 x 10²³.

Assuming that one person has an average mass of 70 kilograms, the mass of one mole of people would be approximately 70 kilograms x 6.022 x 10²³, which is equal to about 4.2 x 10²⁵ kilograms.

Clearly, this is an enormous mass, far too large to fit into any classroom or even any building on Earth. Therefore, it is not possible to fit one mole of people into a classroom.

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Answer:

One mole of people is 6.02x1023 people. That’s more people than there are in the entire world which is estimated to be about 7x109 people. So clearly the answer is NO.

Explanation:

How do gases exert pressure?

Answers

Explanation:

the pressure exerted by the gas is due to the random motion of particles in the gas. Gases have weak intermolecular forces and the particles in continuous random motion and these particles collide with the walls of the container. This collisions with the walls of the container exerts pressure on the gas

Consider the following reaction: 2N2O5(g) → 4NO2(g) + O2(g) Calculate the volume N2O5 that must decompose completely to produce 9.64 L nitrogen dioxide.​

Answers

The volume of \(N_2O_5\) needed to produce 9.64 L of \(NO_2\) is 4.97 L, calculated using stoichiometry and the ideal gas equation.

The given chemical equation is \(2N_2O_5(g) \rightarrow 4NO_2(g) + O_2(g)\) .The volume of \(N_2O_5\) that decomposes completely to form 9.64 L of \(NO_2\) is to be calculated. For this, we can use the concept of stoichiometry. Stoichiometry is a branch of chemistry that deals with the quantitative relationships between reactants and products in a balanced chemical equation.To calculate the volume of \(N_2O_5\) that is needed to produce 9.64 L of \(NO_2\), we will first determine the number of moles of NO2 produced in the reaction. For this, we can use the ideal gas equation, PV = nRT. Here, we have the volume of NO2 and we can assume the pressure and temperature to be constant. Thus, we have PV = nRT, where P = pressure, V = volume, n = number of moles, R = ideal gas constant, and T = temperature. Substituting the given values in the ideal gas equation, we get,n = PV/RT = (1 atm × 9.64 L)/(0.0821 L atm K-1 mol-1 × 300 K) = 0.404 molFrom the chemical equation, we see that 2 moles of \(N_2O_5\) give 4 moles of \(NO_2\). Thus, 0.404 mol of \(NO_2\) must have been produced from (0.404/2) = 0.202 mol of \(N_2O_5\). Using the ideal gas equation, we can also find the volume of 0.202 mol of \(N_2O_5\) at the given conditions. Thus, V = nRT/P = (0.202 mol × 0.0821 L atm K-1 mol-1 × 300 K)/1 atm = 4.97 L. Thus, the volume of \(N_2O_5\) that must decompose completely to produce 9.64 L nitrogen dioxide is 4.97 L.

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moles of each product that would form as a result of the decomposition of aspirin

Answers

The decomposition of aspirin (acetylsalicylic acid,\(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)).

The decomposition of aspirin (acetylsalicylic acid, \(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)). To determine the moles of each product formed, we need to consider the balanced chemical equation for the reaction:

\(C_{9} H_{8} O_{4} = > C_{7} H_{6}O_{3} +CH_{3} COOH\)

From the equation, we can see that for every 1 mole of aspirin, 1 mole of salicylic acid and 1 mole of acetic acid are produced.

Therefore, the moles of salicylic acid and acetic acid formed will be equal to the number of moles of aspirin that decomposes. If we know the amount of aspirin in moles, we can directly calculate the moles of each product based on stoichiometry.

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Homeostasis in a constantly changing environment is a process known as

Answers

The Excretory system

Hydrogen = odorless, colorless, and tasteless (so it's undetectable to human senses) but highly flammable and used in jet fuel

Directions:

Identify another chemical reaction that is important to your daily life. (Hint: THIS

Answers

One important chemical reaction in our daily life is the process of cellular respiration, which occurs in living organisms to produce energy in the form of ATP.

The reaction involves the breakdown of glucose, a type of sugar, into carbon dioxide and water, and the release of energy in the process. The general equation for cellular respiration is,

\(C_{6} H_{12} O_{6}\) + \(6O_{2}\) → \(6CO_{2}\) + \(6H_{2}O\) + energy (ATP)

This reaction occurs continuously in our cells, providing the energy needed for various cellular activities and bodily functions. Without cellular respiration, we would not be able to survive.

Another important application of chemical reactions in daily life is in the production of food. Cooking food involves various chemical reactions, including the breakdown of complex carbohydrates and proteins into simpler molecules, the caramelization of sugars, and the Maillard reaction between amino acids and reducing sugars. These reactions help to create the flavor, aroma, and texture of the food we eat.

In addition, chemical reactions are also used in the production of many consumer products, such as cleaning agents, cosmetics, and pharmaceuticals. The chemical reactions involved in these products are carefully designed and controlled to ensure their effectiveness and safety for use.

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D is a green crystalline solid that dissolves in water to give a very pale green solution. Addition of sodium hydroxide solution to a solution of D produces a green precipitate, E, which turns orange-brown around the top after standing in air. Addition of dilute hydrochloric acid and barium chloride solution to a solution of D gives a white precipitate, F. a State the names of D, E and F.​

Answers

The chemical D is  FeSO4 · 7H2O which is a green crystalline solid. When dissolved in water it gives a very pale green solution. The chemical E is Fe(OH)3 which is reddish brown in color. The chemical F is BaSO4 which is white in color.

D =  FeSO4 · 7H2O hydrated ferrous sulfate.

E = Fe(OH)3 ferric hydroxide

F= BaSO4  barium sulphate

A chemical response happens while one or extra chemical substances are modified into one or extra different chemicals. For Example iron and oxygen combine to make rust. vinegar and baking soda combine to make sodium acetate, carbon dioxide, and water. techniques concerning the atomic nucleus are called nuclear reactions. The substances that participate in a chemical reaction are known as reactants.

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Chemistry problems

1. 1.5 moles of potassium sulfate (K SO4) were dissolved in 1000 grams of water (H2O). Find the % and Cm.

2. 10 grams of sulfuric acid (H2SO4) was added to 500 ml of 10% solution of potassium hydroxide (KOH) with a density of 1.1 g/ml. Find the mass of potassium sulfate (K SO4) formed.

3. Find the mass of the salt formed by the reaction of 7.3 grams of hydrochloric acid (HCl) with 5.6 liters (5600 ml) of ammonia (NH3).

4. Find the volume of hydrogen gas (H2) produced by the reaction of 13 grams of zinc with a solution containing 30 grams of sulfuric acid (H2SO4).

5. How much of the concentrated original solution (70%) of acetic acid is needed to prepare 500 grams of 3% (percentage solution)?

Answers

1. The % concentration is 20.7% and the molar concentration, Cm, is 1.5 M.

2. 7.8 grams of potassium sulfate will be formed.

3. 10.7 grams of ammonium chloride will be formed.

4. The volume of hydrogen gas that will be produced is 3.86 liters.

5. 21.43 grams of the 70% acetic acid is needed to prepare 500 grams of 3% acetic acid solution.

What is the percentage concentration?

1. Mass of potassium sulfate = 1.5 moles * (174.26 g/mol) = 261.39 g

Mass of water (H₂O) = 1000 g

% = (mass of solute/mass of solution) x 100

% = (261.39 g / (261.39 g + 1000 g)) x 100

% ≈ 20.7%

Cm = moles of solute / volume of solution

Moles of potassium sulfate (K2SO4) = 1.5 moles

Volume of water (H2O) = 1000 g / (density of water) = 1000 g / 1 g/mL = 1000 mL = 1 L

Cm = 1.5 moles / 1 L

Cm = 1.5 M

2. The balanced equation for the reaction is:

H₂SO₄ + 2 KOH → K₂SO₄ + 2 H₂O

Molar mass of sulfuric acid (H₂SO₄) = 98.09 g/mol

Moles of sulfuric acid = 10 g / 98.09 g/mol

Moles of sulfuric acid = 0.102 mol

Based on the mole ratio of the reaction, 0.102 moles of sulfuric acid will react to form 0.102 moles of potassium sulfate.

Molar mass of potassium sulfate = 174.26 g/mol

Mass of potassium sulfate = 0.102 mol x 174.26 g/mol

Mass of potassium sulfate ≈ 17.8 g

3. The balanced equation for the reaction is:

HCl + NH₃ → NH₄Cl

Molar mass of hydrochloric acid (HCl) = 36.46 g/mol

Moles of hydrochloric acid (HCl) = 7.3 g / 36.46 g/mol

Moles of hydrochloric acid ≈ 0.2 mol

Based on the mole ratio of the reaction, 0.2 moles of hydrochloric acid will react to form 0.2 moles of ammonium chloride.

Molar mass of ammonium chloride (NH₄Cl) = 53.49 g/mol

Mass of ammonium chloride = 0.2 mol x 53.49 g/mol

Mass of ammonium chloride ≈ 10.7 g

4. The balanced equation for the reaction is:

Zn + H₂SO₄ → ZnSO₄ + H₂

Molar mass of zinc (Zn) = 65.38 g/mol

Moles of zinc = 13 g / 65.38 g/mol

Moles of zinc ≈ 0.199 mol

Based on the mole ratio of the reaction, 0.199 moles of zinc will react to produce 0.199 moles of hydrogen gas.

Volume of sulfuric acid = 30 g / (density of H₂SO₄ )

The density of H₂SO₄ is 1.84 g/mL

Volume of sulfuric acid  = 30 g / 1.84 g/mL

Volume of sulfuric acid ≈ 16.3 mL or 0.0163 L

Using the ideal gas law, the volume of hydrogen gas produced will be:

V = nRT / P

V = (0.199 mol)(0.0821 L·atm/(mol·K))(273 K) / (1 atm)

V ≈ 3.86 L

5. Assuming that the concentrated original solution of acetic acid is 100% acetic acid (CH₃COOH).

Mass of acetic acid = 500 g x (3/100) = 15 g

The concentrated original solution, however, is 70% acetic acid.

70% acetic acid (mass) = 100% acetic acid (unknown mass)

0.7 * (unknown mass) = 15 g

Solving for the unknown mass:

unknown mass = 15 g / 0.7

unknown mass ≈ 21.43 g

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