In your DC experiment, when the capacitor was just beginning to charge the current in the circuit was O maximum between maximum and minimum minimum

The radii of the first five Fresnel zones is 3.6 mm.

Distance from the light source to the wave surface, d₁ = 1 m

Distance from the wave surface to the observation point, d₂ = 1 m.

Wavelength of the light used, λ = 5 x 10⁻⁶m = 5 μm

The expression for the radius of the Fresnel zones is given by,

rₙ = √[nλd₁d₂/(d₁ + d₂)]

Therefore, the radii of the first five Fresnel zones is,

r₅ = √[5 x 5 x 10⁻⁶x 1 x 1/(1 + 1)]

r₅ = √(25 x 10⁻⁶/2)

r₅ = 3.6 x 10⁻³m

r₅ = 3.6 mm

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Answer:

D) 0°

Explanation:

In the drawing, the black and blue vectors are added together resulting in the purple vectors. One can see that when the black and blue vectors point in the same direction (0 angle between them), the magnitude of the purple vector is largest.

The angle between the two fixed magnitude vectors, for the sum of these two has the greatest magnitude, is 180°.

The vector is the vector operation of adding two or more than two vectors for the vector sum.  

The formula for the vector addition of two forces with law of cosine can be given as,

\(F_R=\sqrt{F_1^2+F_2^2+2F_1F_2.\cos\alpha}\)

For the maximum value of the sum of the given two vectors, the value of the angle should be as which gives the greatest value of cosine.

It is known that the maximum value of cos is at the 0 degree and than at 180 degree.

\(\cos(180)=1\)

Thus, the angle between the two fixed magnitude vectors, as the sum of these two has the greatest magnitude, is 180°.

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Answer:

a) 5.143 m/s^2

b) T = 15.43 N

c) Fr = 10.29 N

d) 5.143 m/s^2 , T = 15.43 N

Explanation:

Given:-

- The mass of left most block, m1 = 1.0 kg

- The mass of center block, m2 = 2.0 kg

- The mass of right most block, m3 = 4.0 kg

- A force that acts on the right most block, F = 36 N

Solution:-

a)

- For the first part we will consider the three blocks with masses ( m1 , m2 , and m3 ) as one system on which a force of F = 36 N is acted upon. The masses m1 and m3 are connected with a string with tension ( T ) and the m1 and m2 are in contact.

- We apply the Newton's second law of motion to the system with acceleration ( a ) and the combined mass ( M ) of the three blocks as follows:

                       \(F = M*a\\\\36 = ( 1 + 2 + 4 )*a\\\\a = \frac{36}{7}\\\\a = 5.143 \frac{m}{s^2}\)

Answer: The system moves in the direction of external force ( F ) i.e to the right with an acceleration of 5.143 m/s^2

b)

- The blocks with mass ( m1 and m3 ) are connected with a string with tension ( T ) with a combined acceleration of ( a ).

- We will isolate the massive block ( m3 ) and notice that two opposing forces ( F and T ) act on the block.

- We will again apply the Newton's 2nd law of motion for the block m3 as follows:

                       \(F_n_e_t = m_3 * a\\\\F - T = m_3 * a\\\\36 - T = 4*5.143\\\\T = 36 - 20.5714\\\\T = 15.43 N\)

Answer:- A tension of T = 15.43 Newtons acts on both blocks ( m1 and m3 )

c)

- We will now isolate the left most block ( m1 ) and draw a free body diagram. This block experiences two forces that is due to tension ( T ) and a reaction force ( Fr ) exerted by block ( m2 ) onto ( m3 ).

- Again we will apply the the Newton's 2nd law of motion for the block m3 as follows:

                         \(F_n_e_t = m_1*a\\\\T - F_r = m_1*a\\\\15.43 - F_r = 1*5.143\\\\F_r = 15.43 - 5.143\\\\F_r = 10.29 N\)

- The reaction force ( Fr ) is contact between masses ( m1 and m2 ) exists as a pair of equal magnitude and opposite direction acting on both the masses. ( Newton's Third Law of motion )

Answer: The block m2 experiences a contact force of ( Fr = 10.29 N ) to the right.

d)

- If we were to stack the block ( m2 ) on-top of block ( m1 ) such that block ( m2 ) does not slip we the initial system would remain the same and move with the same acceleration calculated in part a) i.e 5.143 m/s^2

- We will check to see if the tension ( T ) differs or not as the two block ( m1 and m2 ) both experience the same Tension force ( T ) as a sub-system. with a combined mass of ( m1 + m2 ).

- We apply the Newton's 2nd law of motion for the block m3 as follows:

                            \(T = ( m_1 + m_2 ) *a\\\\T = ( 1 + 2 ) * 5.143\\\\T = 15.43 N\)

Answer: The acceleration of the whole system remains the same at a = 5.143 m/s^2 and the tension T = 15.43 N also remains the same.

Explanation:

Elastic string constant (k)

= Slope of the graph F/x

= 15.0N/10.0m = 1.50N/m

Hence,

EPE = 0.5kx² = 0.5(1.50N/m)(3.0m)² = 6.75J.

Answer:

6.8

Explanation:

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Answer:

A is indeed correct

Explanation:

just did the question

The option that correctly matches the chemical formula of a compound with its name is N₂O₃ dinitrogen trioxide.

Dinitrogen trioxide is one of the simple nitrogen oxide. The chemical compound formula of Dinitrogen trioxide N₂O₃.

That is, it consists of 2 molecules of nitrogen, hence the prefix "Di" and 3 molecules of oxygen given the prefix tri.

Thus, the option that correctly matches the chemical formula of a compound with its name is N₂O₃ dinitrogen trioxide.

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Answer:

\(v=0.8m/s\)

Explanation:

From the question we are told that

Distance \(d=1.5m/sm/s\)

Time  \(t_1=60s\)  

Time  \(t_2=90s\)  

Generally the  the equation for the distance traveled is mathematically given as

\(d=vt\)

\(d=1.5*90\)

\(d=138m\)

Generally equation for speed of side walk is mathematically given as

\(d=(v+u)t\)

\(v=\frac{d}{t}-u\)

\(v=\frac{138}{60}-1.5\)

\(v=0.8m/s\)

Answer:

(a) To solve for the initial speed of the rock at launch, we can use the kinematic equation:

v = v0 + at

Where:

v = final velocity (15m/s)

v0 = initial velocity (what we're solving for)

a = acceleration due to gravity (-9.8m/s^2)

t = time (2.0s)

Plugging in the values, we get:

15m/s = v0 - 9.8m/s^2 (2.0s)

v0 = 34.6m/s

Therefore, the initial speed of the rock at launch was approximately 34.6m/s.

(b) To solve for the speed of the rock 5.0s after launch, we can use the same kinematic equation:

v = v0 + at

But this time, we need to add the additional time and distance that the rock traveled after the initial 2.0s. To do this, we'll use the equation:

d = v0t + 1/2at^2

Where:

d = distance traveled

v0 = initial velocity (34.6m/s)

a = acceleration due to gravity (-9.8m/s^2)

t = time (5.0s - 2.0s = 3.0s)

Plugging in the values, we get:

d = (34.6m/s)(3.0s) + 1/2(-9.8m/s^2)(3.0s)^2

d = 103.8m - 44.1m

d = 59.7m

So, the rock traveled 59.7m in the additional 3.0s after the initial 2.0s. Now we can find its speed using the kinematic equation:

v = v0 + at

Where:

v0 = final velocity from before (15m/s)

a = acceleration due to gravity (-9.8m/s^2)

t = time (3.0s)

Plugging in the values, we get:

v = 15m/s - 9.8m/s^2 (3.0s)

v = -12.6m/s

Note that the velocity is negative because the rock is now moving downward. Therefore, the speed of the rock 5.0s after launch is approximately 12.6m/s.

Answer:

A physical change is the change to the physical properties of an object.

Explanation:

As an example if I take a piece of paper and cut it in half that would be a physical change. Water freezing into ice is also a physical change.

According to the given statement:

I) acceleration a=2m/s²

ii) deceleration a=−1  m/s²

iii) the distance travelled =200  m.

Velocity's rate of change with time, in both terms of speed and direction. A point or object moving straight ahead is accelerated when it increases or decelerates. Even if the speed remains constant, motion on the a circle increases because the orientation is always shifting.

Briefing:

You use the standard formulas for distance as a function of speed, acceleration and time:

st = v0t + 0.10at²  for acceleration ( a >0) and deceleration ( a <0), or at constant speed ( a =0).

Now  a  is not given for acceleration and deceleration, so we need to compute this from

vt=v₀+at

Acceleration:  

20=10a⟹a=2m/s²

Distance travelled:  

0.10∗10∗10²=100  m

Distance travelled while at constant speed:

s=vt=20∗20=400  m

Deceleration:  

0=20+20a⟺a=−1  m/s²

Distance travelled:

20∗20+0.1(−1)20²=400−2∗100

=200  m.

So the total distance travelled is  100+400+200=700m

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Answer:

It increases because fg means Force of gravity so When the mass of the two objects  increases with mass and increases the distance between an object

There you go!!!

a) Total momentum before collision is: \(\mathrm{\rho = M \times 3v_0 - M \times v_0 = 2M \times v_0}\)

b) Immediately after the collision, two objects move together with a speed of v₀. The direction of motion is to the right, as A was moving to right before collision.

Momentum may be defined as the product of mass and velocity of any object.

(a) Before the collision, total momentum of the system is :

\(\mathrm{\rho = m_A \times v_A + m_B \times v_B}\)

\(\mathrm{m_A = m_B = M, v_A = 3v_0, \ and \ vB = -v_0}\) (since B is moving to the left).

Therefore, total momentum before the collision is:

\(\mathrm{\rho= M \times 3v_0 - M \times v_0 = 2M \times v_0}\)

(b) Immediately after the collision, the two objects move with the same velocity v. Total momentum of the system is: p' = (mA + mB)  ×  v = 2M  ×  v

As total momentum is conserved: p' = p

\(\mathrm{2M \times v = 2M \times v_0}\)

\(\mathrm{v = v_0}\)

Therefore, immediately after the collision, two objects move together with a speed of v₀. The direction of motion is to the right, since A was moving to the right before collision.

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Answer:

cognitive, humanistic, behavioral, sociocultural

Explanation:

Behavioral, sociocultural, cognitive, and humanistic are approaches to psychological science.

Psychology is a term to refer to the discipline that focuses on the study of various topics related to human thought such as:

Due to the above, several subdisciplines have emerged that focus on the study of each of the topics. For example:

Behavioral psychology: focused on the study of human behavior.

Sociocultural psychology: focused on the study of human behavior and thought in different social situations.

Cognitive psychology: focused on mental processes related to learning.

Humanistic psychology: focused on the study of human thought from a comprehensive approach.

According to the above, options A, E, F, and G are correct because they mention different sub-disciplines of psychology while the other options mention terms that are not related to sub-disciplines or psychological sciences.

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Answer:

it have magnitude and direction is vector

it have magnitude but not direction is scalar

by multiplying ..... is magnitude

ny adding you get another vector

Explanation:

yeah I hope this helpa

Answer:

(B) {u}= [T/(du / dy)] = (F/L^2) / (L/T) / L = FT / L^2

Explanation:

The speed of the car just after the gravel is loaded is 2.8m/s.

An isolated system experiences a change in momentum to zero when the starting and final velocities are equal. The reactions between the particles are separated from the surroundings. Momentum is conserved, so we use the rule of conservation of momentum, which is expressed by the equation

   \(P_{f}\)=\(P_{i}\)(1)

Railway is frictionless due to isolated mechanism. The thing travels at a momentum p-based speed while having mass. m

An object's bulk and velocity v are combined to form a vector.Equation of the form gives the velocity.

\(p=mv\)

Using expression p into equation (1)

\(m_{f}v_{f}\)=\(m_{i}v_{i}\)(2)

The final mass of a car is its original mass plus the mass of the gravel added. A car has an initial mass of.10000Kg  preliminary pace is

\(m_{f}\)=10000Kg+4000Kg=14000Kg

initial speed 4m/s

the final speed should be found after solving the equation(2) for \(v_{f}\)

\(v_{f}\)=\(\frac{m_{i}v_{i} }{m_f} }\)=\(\frac{10000Kg(4m/s)}{1400Kg}\)=2.8m/s

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Infant brain mapping is being used to assess perceptual and cognitive activities including Vision, Hearing, and Language.

The very early offspring of humans are called infants or babies. Infant is a formal or specialized synonym for the phrase baby. It comes from the Latin word infants, which means "unable to talk" or "speechless." Other organisms' young may also be referred to by the names.

In everyday speech, an infant that is only a few hours, days, or even a few weeks old is referred to as a newborn. In medical contexts, an infant in the first 28 days following delivery is referred to as a newborn or neonate (from the Latin neonates, newborn); the word is applicable to premature, full-term, and postmature newborns.

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Answer:

3500N

Explanation:

Given parameters:

Mass of driver  = 50kg

Speed  = 35m/s

Time  = 0.5s

Unknown:

Average force the seat belt exerts on her = ?

Solution:

The average force the seat belt exerts on her can be deduced from Newton's second law of motion.

   F = mass x acceleration

So;

     F  = mass x  \(\frac{change in velocity }{time}\)

  F  = 50 x \(\frac{35}{0.5}\)    = 3500N

Answer:

Answer:

what

Explanation:

what I dont get it??

Answer:

that makes me confused I don't think of pizza the same again LOL

Given:

The mass of the bullet, m=28 g=0.028 kg

The speed of the bullet, v=300 m/s

The mass of the pendulum, M=3.1 kg

The length of the string, l=2.8 m

To find:

The vertical component of the pendulum's maximum displacement.

Explanation:

The law of conservation of energy states that energy can neither be created nor be destroyed. Thus the kinetic energy of the bullet will be transferred into the kinetic energy of the bullet and the pendulum. Which will be converted into its potential energy when it reaches the maximum height, i.e, the vertical component of its maximum displacement.

Thus,

Where g is the acceleration due to gravity and h is the vertical component of the pendulum's maximum displacement.

On rearranging the above equation,

On substituting the known values,

Final answer:

Thus the vertical component of the maximum displacement of the pendulum is 41.1 m

The two analogies in question are:

The strengths of the water analogy are that it is easy to understand and it can be used to explain how current flows through a circuit. The water flows from a high point to a low point, just like current flows from a high voltage to a low voltage. The water can also be blocked by obstacles, just like current can be blocked by resistors.

The limitations of the water analogy are that it is not very accurate. Water is a liquid, while current is a flow of electrons. Electrons are very small and they do not behave like water molecules. For example, electrons can pass through each other, while water molecules cannot.

The strengths of the crowd analogy are that it is more accurate than the water analogy. Crowds of people can be used to explain how current flows through a circuit, how current is blocked by resistors, and how current can be amplified by capacitors.

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Answer:

101.81818    MPH

Explanation:

Answer:

All of then are true

I need brainliest so I can rank up

Explanation:

Answer:

I think all options are true is the right answer

Explanation:

Mark me the brainliest plzzz

Answer: A

Explanation:

Answer:

Because gravity makes you able to stand and move around

Gravity can't fail

it can fail only in astronuts camp and in space

Explanation:

✌❤

Yh....

:)

An electron is moving to the right with an initial speed of vo = 3.5 x 10E7 m/s when it enters a

region of space that is L = 3.3 cm wide with a uniform electric field pointing down of magnitude

E = 8.2E4 N/C. The electron will experience electric field

The electron will experience a force due to the electric field, which is given by the equation F = qE, where q is the charge of the electron (a negative value) and E is the electric field.

The force will cause the electron to accelerate in the direction of the field, which is opposite to its initial direction of motion. The acceleration of the electron can be calculated using the equation a = F/m, where m is the mass of the electron.

The distance the electron will travel before it exits the region of space can be calculated using the equation x = v_0t + 0.5a*t^2, where v_0 is the initial velocity and t is the time it takes for the electron to travel through the region.

Therefore, the correct answer is as given above

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The complete question goes thus:

An electron is moving to the right with an initial speed of vo = 3.5 x 10E7 m/s when it enters a

region of space that is L = 3.3 cm wide with a uniform electric field pointing down of magnitude

E = 8.2E4 N/C. What will happen to the electron?