In Young's experiment, the pattern that appears on the screen is a result of interference between two sets of waves that are diffracted through two slits.
The location of the bright fringes in the pattern depends on the wavelength of the light used. This means that the path difference between the waves that interfere to produce this fringe is an integer multiple of the red light's wavelength (700 nm).
ΔL = mλ_red = nλ_other
where ΔL is the path difference between the waves, m and n are integers, λ_red is the wavelength of the red light, and λ_other is the wavelength of the second type of visible light.
Solving for λ_other, we get:
λ_other = (m/n) λ_red.
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how fast would a 67 kg person have to run to have that amount of energy? express your answer with the appropriate units.
The 67 kg person has to run at the speed of \(\sqrt{((2 \times KE) / 67)}\) m/s to have that amount of energy.
To calculate the kinetic energy (KE) of a person running, we can use the formula
KE = \(0.5 \times m \times v^2\)
where m is the mass (67 kg) and v is the velocity in meters per second (m/s).
First, we need to determine the desired amount of energy, which is not provided in the question.
Obtain the desired energy value (in joules, J) you want the person to have while running.
Plug the mass (67 kg) and the desired energy value into the KE formula: \(KE = 0.5 \times 67 \times v^2\).
Rearrange the formula to isolate v:
\(v^2 = (2 \times KE) / 67\) m/s
Calculate v by taking the square root
\(v = \sqrt {(2 \times KE) / 67)}\) m/s
The calculated value of v will be the velocity in meters per second (m/s) required for the person to have the desired amount of energy while running.
Remember to replace "KE" with the desired energy value in joules, and you will get the velocity (in m/s) needed for a 67 kg person to have that amount of energy.
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Imagine you inherit a farm and now have to purchase fertilizer for the farm. The farm is 340 acres and had corn planted the previous year. You must add fertilizer to the soil before you plant this year's crop. You go to the local fertilizer store and find SuperPhosphate-brand fertilizer. You read the fertilizer bag and can recognize from your high school chemistry class a molecular formula C*a_{3}*P_{2}*H_{14}*S_{2}*O_{21} (you don't understand anything else written on the bag because it is imported fertilizer from Japan). You must decide how much fertilizer to buy for application to your cornfields. If each bag contains 25 kg of fertilizer and costs $54.73, how many bags of fertilizer must you purchase, and how much will it cost you to add the necessary fertilizer to your fields ?
Total Cost is = $107,380 if The farm is 340 acres and had corn planted add fertilizer to the soil before you plant this years' crop.
What is called fertilizer?A fertiliser is a natural or artificial substance containing chemical elements (such as Nitrogen (N), Phosphorus (P) and Potassium (K)) that improve growth and productiveness of plants. Some synonyms include the terms "enrichment" or "plant nutrient".
Why is fertilizer important?Without fertilizers, nature struggles to replenish the nutrients in the soil. When crops are harvested, important nutrients are removed from the soil, because they follow the crop and end up at the dinner table. If the soil is not replenished with nutrients through fertilizing, crop yields will deteriorate over time.
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The following vectors would carry me how far left or right (x-direction only):
A = 230<15o
B = 120<237o
C = 212<188o
A) 53.1 Left
B) 10.9 Right
C) 70.6 Left
D) 10.9 Left
The same vectors would carry me how far up or down (y-direction only):
A = 230<15o
B = 120<237o
C = 212<188o
A) 53.1 Down
B) 70.6 Up
C) 69.1 Down
D) 70.6 Down
The same vectors would carry me how far away from my starting point and at what angle:
A = 230<15o
B = 120<237o
C = 212<188o
A) 88.3 < 53.1o
B) 88.3 < 143o
C) 124 < 233o
D) 88.3 < 233o
To determine the x- and y-components of each vector, we can use trigonometry.
For vector A:
x-component = 230 cos(15°) ≈ 222.85
y-component = 230 sin(15°) ≈ 59.27
For vector B:
x-component = 120 cos(237°) ≈ -107.75
y-component = 120 sin(237°) ≈ -75.94
For vector C:
x-component = 212 cos(188°) ≈ 112.84
y-component = 212 sin(188°) ≈ -163.63
To determine the direction and magnitude of the resultant vector, we can add up the x- and y-components of each vector.
x-component = 222.85 - 107.75 + 112.84 ≈ 227.94
y-component = 59.27 - 75.94 - 163.63 ≈ -180.3
The magnitude of the resultant vector is given by the Pythagorean theorem:
resultant magnitude = sqrt((227.94)^2 + (-180.3)^2) ≈ 292.9
The direction of the resultant vector is given by the arctangent of the y-component over the x-component:
resultant direction = atan(-180.3/227.94) ≈ -38.5°
Therefore, the answers to the questions are:
To move left or right (x-direction only): A) 53.1 Left
To move up or down (y-direction only): C) 69.1 Down
To move away from starting point and at what angle: D) 88.3 < 233.
What is an angle ?An angle is a geometric figure that is formed by two rays or line segments that share a common endpoint, known as the vertex of the angle. The rays or line segments are referred to as the sides or legs of the angle. The measure of an angle is typically given in degrees, which is a unit of measurement for angles. One complete revolution around a circle corresponds to 360 degrees, while a half revolution corresponds to 180 degrees.
Angles are used in various fields, including mathematics, physics, engineering, and architecture. They are used to measure and describe the orientation and direction of lines, planes, and surfaces.
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Identify the following as electromagnetic (E) or mechanical (M) waves.sound waveswater wavesradio wavesultraviolet waveswaves in a wheat field
The electromagnetic waves are radio waves and ultraviolet, whereas the mechanical waves are sound waves, waves in a wheat field, water waves, and electromagnetic waves.
A disturbance is transmitted from its source, or one location, to another by means of a wave.
Depending on the need for a physical medium, waves can be classed as electromagnetic or mechanical waves.
Sound waves, water waves, and other mechanical waves are those that must travel through a material medium in order to be transmitted. These waves are transmitted via the medium by the medium's particle's vibration.
The waves that may be transmitted without the use of a physical medium are known as electromagnetic waves. They comprise all electromagnetic waves, including radio waves, microwaves, and others.
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Normally, the air in the center of a Low-Pressure system would be warm.
A. Squeeze
C. Reverse direction
B. Evaporate into a liquid D. rise and form clouds
The air in the center of a Low-Pressure system: rises and forms clouds. The correct option is D.
In a low-pressure system, also known as a cyclone, the air in the center rises and forms clouds. Low-pressure systems are characterized by air that is less dense than the surrounding air, causing it to ascend. As the air rises, it expands and cools, leading to the condensation of water vapor and the formation of clouds.
The rising air in a low-pressure system creates an area of low atmospheric pressure at the surface. Air from surrounding areas with higher pressure flows towards the center to fill the void left by the rising air. This results in the convergence of air towards the center of the low-pressure system.
The rising motion and cloud formation in low-pressure systems are associated with unstable atmospheric conditions. These systems are often associated with weather phenomena such as rain, thunderstorms, and cyclones. The warm air rising in the center of a low-pressure system contributes to the development and intensification of these weather events. The correct option is D.
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at what time ABC or D is the writer accelerating upwardwhat is the magnitude of the maximum acceleration experienced by the rider
We will have the following:
From the graph we can see that the point at which it is accelerating upward is at point C. [We can see that where the slope of the function is positive the acceleration will be positive]
We determine the maximum magnitude of the acceleration of the rider by using the maximum force, that is:
\(F=m\cdot a\Rightarrow1.20N=a=\frac{1.20N}{m}\)So, the maixmum magnitude of the acceleration will depend on the mass of the rider. Now, since the mass cannot be 0 kg since that would undetermine the expression we know then that the best approximation is:
\(a=\frac{1.20N}{m}\)Where "m" is the mass of the rider in kg. Since we are not given a mass, then the acceleration can only be expressed as the force divided by the mass of the rider.
A ball hits a wall horizontally at 6m/s and rebounces at 4.4m/s the ball is in contact with wall for 0.04 sec. what is the acceleration.
Answer:
Acceleration (a) = 40 m/s²
Explanation:
Given:
Initial velocity (u) = 6 m/s
Final velocity (v) = 4.4 m/s
Time taken (t) = 0.04sec
Find:
Acceleration (a) = ?
Computation:
We know that,
⇒ v = u + at
⇒ a = (v - u) / t
⇒ Acceleration (a) = (4.4 - 6) / 0.04
⇒ Acceleration (a) = (-1.6) / 0.04
Acceleration (a) = 40 m/s²
If a train travels 80 miles north, 60 miles east, what’s the magnitude of its total displacement? Find the solution by drawing a diagram. ____ miles.
Answer:
100 miles North East.
Explanation:
Please see attached photo for diagram.
In the attached photo, X represents the magnitude of the total displacement of the train.
Thus, we can obtain the value of X by using the pythagoras theory as illustrated below:
X² = 80² + 60²
X² = 6400 + 3600
X² = 10000
Take the square root of both side
X = √10000
X = 100 miles.
Therefore, the magnitude of the total displacement of the train is 100 miles North East.
Hey help me and thanks in advance if you do
P = W / t
2000 = 30000 / t
t = 30000/2000
t = 30/2
t = 15 seconds
Explanation:
work(w)=30000J
power(p)=2000W
time taken(t)=?
now,
p=w/tt=w/pt=30000/2000t=15 sechope it helps.
stay safe healthy and happy.Which substance has a melting point greater than room temperature?
A.
oxygen
B.
aluminum
C.
mercury
D.
water
Answer:
I think the answer is D.)
Explanation:
If it means something needs to melt into liquid i would have gone with B.) or C.) but since it doesn't specifiy. I thought D.) since all you have to do is heat it and it melts or boils.
the box weighing 18 newtons is coated with teflon® and now requires a force of 3 newtons to drag it.the coefficient of friction is .
To determine the coefficient of friction for the box weighing 18 Newtons and requiring a force of 3 Newtons to drag it after being coated with Teflon®, you can use the formula:
Coefficient of friction (μ) = Force of friction (F_ friction) / Normal force (F_ normal)
In this case, the Force of friction (F_ friction) is the force required to drag the box, which is 3 Newtons. The Normal force (F_ normal) is equal to the weight of the box, which is 18 Newtons.
Plug these values into the formula:
μ = 3 N / 18 N
μ = 0.1667
The coefficient of friction for the box coated with Teflon® is approximately 0.1667.
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what was the rule of the sticks on each atom model
Answer:
That they must die
Explanation:
Stick = Die
What is the purpose of the prefixes in the metric system?
a.
They signify the multiples of ten for each unit.
b.
They signify a completely separate unit.
c.
They always make a unit smaller.
d.
They always make a unit larger.
The purpose of the prefixes in the metric system is to signifies the multiples of tens for each unit.
A prefix is a word that precedes a basic unit to indicate the multiple or fraction of that basic unit.
We can assign multiple or subdivisions in the metric system to any unit by simply combining them with their prefix. Some of the common prefixes that are sued in the metric system are kilo, centi, deca, hecto etc. Each prefix has a different meaning assigned to it for example : deci is one-tenth centi is one-hundredth milli is one-thousandth deca is ten. hecto is 100. kilo is 1000.Thus, the prefixes in the metric system are used to signify multiples of ten for each unit.
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Answer: Option A- They signify the multiples of ten for each unit.
Explanation:
Just got it correct on test :)
A sphere with radius 10 cm is filled with a uniform charge distribution. The magnitude of the electric field at a point 5 cm from the center of the sphere is 3014 N/coul. Use this fact to calculate the charge density rho inside the sphere.
Answer:15 cm
Explanation: u had 10cm. them u had another 5cm
A dragster and driver together have mass 948. 8 kg. The dragster, starting from rest, attains a speed of 26. 3 m/s in 0. 63 A dragster and driver together have mass
948. 8 kg. The dragster, starting from rest, attains a speed of 26. 3 m/s in 0. 63 s. Find the average acceleration of the dragster during this time interval. Answer in units of m/s
The average acceleration of the dragster during this time interval is 41.746 m/s².
Average acceleration is the rate of change of velocity over a specific time interval. It is defined as the ratio of the change in velocity to the time interval over which the change occurs
The average acceleration of the dragster can be found using the formula:
average acceleration = (final velocity - initial velocity) / time
where the final velocity is 26.3 m/s, the initial velocity is 0 m/s (since the dragster starts from rest), and the time is 0.63 s.
Substituting the values, we get:
average acceleration = (26.3 m/s - 0 m/s) / 0.63 s
= 41.746 m/s²
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How much force (in Newtons) does a baseball pitcher have to exert on a 250g baseball to make it accelerate to 50 m/s the
Instant that it leaves his hand?
Answer:
Force = 12.5 Newton
Explanation:
Given the following data;
Mass = 250 g to kilograms = 250/1000 = 0.25 kg
Acceleration = 50 m/s²
To find the force;
Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.
Mathematically, it is given by the formula;
\( Acceleration = \frac {Net \; force}{mass} \)
Making force the subject of formula, we have;
\( Force = mass * acceleration \)
Substituting into the formula, we have
\( Force = 0.25 * 50 \)
Force = 12.5 Newton
A gold wire with a circular cross-section has a mass of 1.10 g and a resistance of 0.720 Ω. At 20°C, the resistivity of gold is 2.44 ✕ 10−8 Ω · m and its density is 19,300 kg/m3.
How long (in m) is the wire?
m
What is the diameter (in mm) of the wire?
mm
The diameter of the wire is 0.42 mm. The length of the wire is 1.07 m.
The resistance of the gold wire can be calculated using the formula:
R = (ρL) / A
V = m / ρ
V = 1.10 g / (19,300 kg/m³)
V = 5.70 ✕ \(10^{-8\) m^3
Next, we can calculate the length of the wire:
L = (RA) / ρ
L = (0.720 Ω)(πd²/4) / (2.44 ✕ \(10^{-8\) Ω · m)
L = (0.720 Ω)(πd²/4) / (2.44 ✕ \(10^{-8\) Ω · m)
L = 7.41 ✕ \(10^{-3\) d²
Substituting the value of V into the equation above gives:
7.41 ✕ \(10^{-3\) d² = 5.70 ✕ \(10^{-8\)
Solving for d, we get:
d = 0.42 mm
Finally, we can use the length equation to calculate the length of the wire:
L = 7.41 ✕ \(10^{-3\) d²
L = 7.41 ✕ \(10^{-3\) (0.42 mm)²
L = 1.07 m
Resistance refers to the opposition that occurs when current flows through a conductor. It is an inherent property of a material that opposes the flow of electricity. Resistance is measured in ohms and is represented by the symbol Ω. The resistance of a conductor depends on several factors such as the material, the length of the conductor, its cross-sectional area, and the temperature.
Resistance is an important concept in electrical circuits as it affects the flow of current and voltage across a circuit. A higher resistance means a lower current and a higher voltage drop across the circuit. In electronic devices, resistors are used to control the flow of current and limit the voltage. Different materials have different resistivity, which is a measure of their resistance to the flow of electricity. Materials such as copper, aluminum, and gold have low resistivity and are commonly used in electrical wiring. Resistance plays a crucial role in determining the efficiency and performance of electrical and electronic devices.
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in parallel rlc circuits, the ? is the same and is ? phase across all branches and is used as the main reference for calculations.
In parallel RLC circuits, the voltage is the same and is in-phase across all branches and is used as the main reference for calculations.
In a parallel RLC circuit, the current is determined by the resistance, inductance, and capacitance. The maximum current and the maximum voltage occur simultaneously because the voltage and current through the resistor are in phase. This is so that there is no phase shift between the voltage and the current caused by the resistance.
On the other hand, the voltage is 90 degrees behind the current passing through the capacitor, and the voltage is 90 degrees ahead of the current going through the inductor. As a result, the resistive current and voltage are in phase, which means that when the voltage is at its highest, the resistive current likewise reaches its peak and vice versa.
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How do you compare the mass of proton, neutron, and
electron?
Answer:Explanation:
Protons and neutrons have very similar mass, while electrons are far lighter, approximately 11800 times the mass. Protons are positively charged, neutrons have no electric charge, electrons are negatively charged. The size of the charges is the same, the sign is opposite.
A 10-gram marble has a speed that is 5 times faster than that of a 100-gram marble. Both marbles roll off the table at the same time. Answer the following questions. In your explanations, address the fact that the marbles have different masses and. different speeds. [1] (a) Which marble hits the ground first and why? (b) Which marble travels farther and why?
(a) It can be stated that the 10-gram marble hits the ground first because it has a higher acceleration and travels faster.
(b) Both marbles will travel the same distance since their horizontal components of velocity and initial velocity with respect to the ground are the same.
According to the given statement, a 10-gram marble has a speed that is 5 times faster than that of a 100-gram marble. Both marbles roll off the table at the same time. The questions to answer are as follows:
(a) The acceleration due to gravity is constant at 9.8 m/s², according to Newton's Law of Gravitation.
According to the law of physics, heavier objects fall faster than lighter ones, but since the 10-gram marble has a speed that is five times faster than the 100-gram marble, it implies that the 10-gram marble covers more ground in less time than the 100-gram marble as acceleration is directly proportional to the force applied.
The time taken by both marbles to reach the ground is given byt = √(2h/g)where h is the height from which the marbles were dropped, and g is the acceleration due to gravity.
The height from which the marbles were dropped is the same in both cases, so it can be stated that the 10-gram marble hits the ground first because it has a higher acceleration and travels faster.
(b) The range traveled by both marbles is determined by the horizontal component of their velocity. It's worth noting that the horizontal components of their velocities are identical since they were launched from the same height, so there's no advantage for either marble.
The range of a projectile is determined by the formula:
R = u²sin(2θ)/g where R is the range, u is the velocity of the object, θ is the angle of the initial velocity with the horizontal, and g is the acceleration due to gravity.
Since the angle of the initial velocity with the horizontal is the same for both marbles, and their initial velocity is also the same, it can be stated that both marbles travel the same distance.
Therefore, both marbles will travel the same distance since their horizontal components of velocity and initial velocity with respect to the ground are the same.
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100 POINTS Consider a balloon of mass 0.030kg being inflated with a gas of density 0.54kg/m. What will be the volume of the balloon when it just begins to rise in the air of density 1.29kg/m3. (g=10m/s2) Detailed Explanation Please
Answer: Volume=0.030/0.75
Explanation:
Density= mass/volume ∆density= mass/volume
(1.29- 0.54)= 0.030/volume
0.75 volume= 0.030 Volume=0.030/0.75
A 0.200kg ball is shot out of a toy gun from a height of 3.00m. The gun works by compressing a spring k=175N/m a distance of 0.400m. What is the force applied to the ball?
A 0.200kg ball is shot out of a toy gun from a height of 3.00m. The gun works by compressing a spring k=175N/m a distance of 0.400m. then the force applied to the ball is 70 N.
Simple harmonic motion is a specific kind of periodic motion of a body that arises from a dynamic equilibrium between an inertial force that is proportional to the body's acceleration away from the static equilibrium position and a restoring force on the moving object that is directly proportional to the magnitude of the object's displacement and acts towards the object's equilibrium position. Oscillating spring perform SHM.
Force applied on the spring is spring constant times distance.
F = kx
Given,
mass m = 0.2 kg
height h = 3 m
k = 175 N/m
x = 0.4 m
The force applied to the ball is,
F = kx
F = 175×0.4
F = 70 N
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how far from the base of the cliff would the driver have landed if the driver initially had been moving horizontally with speed 10 m/s?
Answer:
C
Explanation:
y0=100 m
y=0
x0=0
x=?
v0x=10 m/s (moving horizontally)
v0y=0
x=x0+v0xt
x=10t
y=y0+1/2at^2
solve for t
0=y0-1/2gt^2
(a is acceleration which is - gravitational acceleration )
t=\(\sqrt{\frac{2y0}{g} }\)
plug into x equation
x=10(\(\sqrt{\frac{2y0}{g} }\)) where y0=100m and g=9.80 m/s^2
x= 45.2 m
if you check the distance when v0=5 m/s, we get x=22.5 m so the equation is correct. however if the g your class uses is 10.00 m/s^2, then we get x=22.4 for the first velocity and 44.7 for the second velocity
What is the effect of gravity on a falling object?
Answer:
When objects fall to the ground, gravity causes them to accelerate.
Review the following situations and determine whether each is an elastic collision or an inelastic collision. Choose the situations that are elastic collisions. Select all that apply.
A. Momentum is conserved; kinetic energy is not.
B. A moving hockey puck strikes one at rest; the objects exchange velocity.
C. Momentum and kinetic energy are conserved.
D. A collision between a volleyball and a basketball occurs; there is no deformation.
E. After a collision, objects are stuck together, moving together.
Answer:
Your answer would be D.
If an object is not moving, the forces acting upon it are...
A.Balanced
B. Weak
C.Unbalanced
D.Hulk SMASH!
a flute acts like a double open-ended pipe and sounds a note with a fundamental frequency of 310 hz pitch. what is the second harmonic frequency of this pitch?
The second harmonic frequency of this pitch is 620 Hz.
What is frequency?Frequency is the number of occurrences of a repeating event per unit of time. It is also occasionally referred to as temporal frequency for clarity and is distinct from angular frequency.
Frequency is measured in hertz (Hz) which is equal to one event per second.
The fundamental frequency of a pipe is determined by the length of the pipe. The frequency of the second harmonic, also known as the first overtone, is twice the fundamental frequency.
So, if the fundamental frequency of the flute is 310 Hz, the second harmonic frequency would be 2 * 310 Hz = 620 Hz.
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When a force is applied to an object, no work is being preformed on the object unless the object____.
The international Space station was launched on 20 November 1998. It has a mass of 4 197 250 kg. Astronaughts and food are taken to the International Space station with the Soyuz capsule which launches on top of a Soyuz rocket. After the launch, the capsule and the rocket separate. The rocket part of the Soyuz returns to Earth. The Soyuz capsule keeps going to dock onto the Space station. The mass of the Soyus capsule is 2900 kg.
Questions:
(1) Define Newton's Universal Law of Gravity.?
(2) Calculate how many kilometers above the earth's surface the International Space station is if it experiences a net force of 36,99 N to keep it in orbit.? (HINT: do not use scientific notation for this question.)
(3) The Soyus capsule is now approaching the space station. Calculate the force between the Space station and the capsule if it is 200 m apart.?
(4) How does the acceleration of the satellite change? Only answer INCREASE, DECREASE, REMAIN THE SAME Explain your answer in 4.4
Newton's law of gravitation, statement that any particle of matter in the universe attracts any other with a force varying directly as the product of masses and inversely as the square of the distance between them.
Why is the universal rule of gravity referred to as Newton's theory of gravity?
Gravity is a universal force that ALL objects are attracted to in relation to the product of their masses, according to Newton's ground-breaking theory. Everywhere there is gravity. Of course, the majority of gravitational pressures are too small to be felt. Only as an object's bulk increases can gravitational forces be observed.
We can use the following method to determine the International Space Station's (ISS) altitude:
F = GMm / r²
F = mv²/ r
v²= Fr / m
v = √(Fr / m)
Substituting the given values, we get:
v = sqrt((36.99 N)(6,371,000 m) / 419,455 kg) = 7,659 m/s
Now we can use the formula for the altitude of a circular orbit:
r = R + h
where R is the radius of the Earth and h is the altitude of the ISS.
The Earth's circumference is roughly 6,371 km. To find h, we can rearrange the algorithm as follows:
h = r - R = (v²/GM) - R
Substituting the given values, we get:
\(h = [(7,69 m/s)^2 / (6.67430 x 10^-11 m^3/kg/s^2)(5.9722 x 10^24 kg)] - 6,371 km\)
h = 408 km.
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Whenever a force vector is not coincident with an axis in your frame of reference, you must apply what factors to examine the components in your reference frame?
When a force vector is not coincident with an axis in your frame of reference, you need to apply the principles of vector decomposition to analyze its components within your reference frame. Vector decomposition, also known as vector resolution, involves breaking a vector down into its constituent components along the coordinate axes.
In order to do this, you will use trigonometric functions such as sine, cosine, and tangent, depending on the angle between the force vector and the reference axis. For instance, if you know the magnitude of the force and the angle it makes with one of the coordinate axes, you can use the sine and cosine functions to determine the horizontal and vertical components of the force.
These components can then be treated separately to analyze their effects on the system. By examining the components, you can better understand how the force influences the motion or equilibrium of objects in the reference frame.
In summary, when a force vector is not coincident with an axis in your frame of reference, apply vector decomposition and use trigonometric functions to determine the components along the coordinate axes. This allows you to analyze the effects of the force on the system in your reference frame.
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